湖南省长沙市雅礼中学高三第六次月考
2022-2023学年湖南省长沙市雅礼中学高三下学期月考卷(六)地理试题(解析版)

17.阅读图文材料,回答下列问题。
通用航空是指使用民用航空器从事公共航空运输以外的民用航空活动,如农林业作业飞行、低空旅游飞行等。黑龙江省通过制定通用机场布局规划,将已有的65个农用机场、14个护林机场改建为通用机场。下图为黑龙江省通用机场布局规划图。通用航空产业是以通用航空飞行活动为核心的战略性新兴产业体系。目前,黑龙江省通用航空相关企业和机场数量位居全国前列,通用航空产业发展潜力巨大。
【点睛】人口老龄化是指人口生育率降低和人均寿命延长导致 总人口中因年轻人口数量减少、年长人口数量增加而导致的老年人口比例相应增长的动态。两个含义:一是指老年人口相对增多,在总人口中所占比例不断上升的过程;二是指社会人口结构呈现老年状态,进入老龄化社会。国际上通常看法是,当一个国家或地区60岁以上老年人口占人口总数的10%,或65岁以上老年人口占人口总数的7%,即意味着这个国家或地区的人口处于老龄化社会。
7.促进宁波舟山港成为国际油品储运加工基地的主导因素是( )
A.原料B.市场C.交通D.劳动力
8.2020年新冠肺炎疫情期间世界石油消费疲软,对舟山新投产石化基地的影响是( )
A.扩大消费市场B.提高接卸能力C.降低原料成本D.降低仓储成本
蒙古族将靠近山林的优质草原称为杭盖草原。杭盖草原地形和缓,多由缓丘和河谷组成。缓丘上牧草葱郁,河谷中的牧草更加繁茂。通常鼠类打洞、啃食等对草原多有破坏,而杭盖草原的河谷中鼠害却很轻。杭盖草原是古时游牧民族最喜爱的牧场。据此完成下面小题。
【2题详解】
根据材料可知,15分钟养老圈的建设与专业养老中心建设的主要目的都在于改善老年人的生活品质,对老龄化的速度无明显影响,①错误。15分钟养老服务圈的建设更能联动社区服务等机构和产业,为社会提供了大量就业岗位,也为养老创造了更好的环境,②④正确。养老服务圈虽提供了多项养老服务,但与专业养老中心相比,成本较低,养老的支出减少,③正确。康乐产品、医养结合和营养饮食虽可提高老年人的生活水平和生活质量,提高老年人平均寿命,但与专业养老中心比较,专业养老中心更有优势,⑤错误。D正确、ABC错误。故选D。
文言翻译与断句

文言翻译与断句1.(广东省中山市2010届高三上学期期末考试)用“/”给下面的文字断句一幅数千言不加点窜当时学者翕然宗之而博览强记尤长典章制度喜诲诱后进以成名者甚众答案精密有规裁/善细字起草/一幅数千言/不加点窜/当时学者/翕然宗之/而博览强记/尤长典章制度/喜诲诱后进/以成名者甚众2.(浙江省金华十校2010届高三上学期期末考试)把下面文言文阅读材料中划线的句子译成现代汉语。
客有问陈季方:“足下家君太丘,有何功德而荷天下重名?”季方曰:“吾家君譬如桂树生泰山之阿,上有万仞之高,下有不测之深;上为甘露所沾,下为渊泉所润。
当斯之时,桂树焉知泰山之高,渊泉之深,不知有功德与无也!”注:太丘:陈寔,字仲弓,东汉颍川许(现在河南许昌)人,做过太丘县令。
(1)足下家君太丘,有何功德而荷天下重名?(2)当斯之时,桂树焉知泰山之高,渊泉之深,不知有功德与无也!答案(1)您的父亲太丘先生,有何功德而负天下盛名?(2)这时候桂树哪知道泰山有多高,渊泉有多深呢!所以我不知道我爸爸有什么功德。
【参考译文】有客人问陈季方(陈谌):“您的父亲太丘先生,有何功德而负天下盛名?”季方回答说:“我爸爸就像生在泰山角落的桂树,上有万仞高峰,下有万丈深渊;上承甘露浸湿,下被渊泉滋润。
这时候桂树哪知道泰山有多高,渊泉有多深呢!所以我不知道我爸爸有什么功德。
”3.(广东省佛山市2010届高三一模)用/给下面的句子断句。
论曰朱穆见偏党毁俗志抑朋游之私遂著《绝交》之论蔡邕以为穆贞而孤穆徒以友分少全因绝同志之求党侠生敝而忘得朋之义蔡氏贞孤之言其为然也!答案论曰 / 朱穆见偏党毁俗 / 志抑朋游之私/ 遂著《绝交》之论 / 蔡邕以为穆贞而孤/ 穆徒以友分少全/ 因绝同志之求 / 党侠生敝 / 而忘得朋之义 / 蔡氏贞孤之言 / 其为然也!4.(广东省深圳高级中学2010届高三一模)用“/”给文言文阅读材料中划波浪线的部分断句。
古人有言一夫不耕或受其饥一妇不织或受其寒况数万之众其所损废亦以多矣推之于古验之于今必然之效也答案(1)古人有言/一夫不耕/或受其饥/一妇不织/或受其寒/况数万之众/其所损废/亦以多矣/推之于古/验之于今/必然之效也5.(浙江省杭州外国语2010届高三上学期第三次月考)用斜线(/)给下列文字断句。
湖南省长沙市雅礼中学2014届高三第六次月考试题 英语 Word版含答案

雅礼中学2014年上学期期高三英语第六次月考试卷本试卷分为四个部分,包括听力理解、语言知识运用、阅读和书面表达。
考试结束后,将答题卷和答题卡一并交回。
时量120分钟。
满分150分。
PARTⅠLISTENING COMPREHENSION (30 marks)Section A(22.5 marks)Directions:In this section, you’ll hear six conversations between two speake rs. For each conversation, there are several questions and each question is followed by three choices marked A, B and C. Listen carefully and then choose the best answer for each question.You will hear the short passage TWICE.EXAMPLE:When will the magazine probably arrive?A. WednesdayB. ThursdayC. FridayThe answer is B.略PARTⅡLAGUAGE KNOWLEDGE (45 marks)Section A (15 marks)Directions: For each of the following unfinished sentences there are four choices marked A, B, C and D. Choose the one that best completes the sentence.21. Peter has gone to Beijing, but I’m wondering why he ________ in such a hurry.A. leftB. has leftC. leavesD. was leaving一、________ Mr. Smith was the last man I wanted to see, I did all in my power to help him.A. BecauseB. Now thatC. WhileD. As23. In this victory speech ________ before a huge crowd of his supporters, Obama declared that“Change has come to America”.A. deliveredB. to be deliveredC. having deliveredD. delivering24. ________ matters much ________ our headmaster supports our plan.A. As; thatB. It; whetherC. That; ifD. What; whether25. ---- Jack, you ________ the window quickly, will you?---- Ok! Oh! The window ________ broken.A. are shutting; wasB. shut; isC. have shut; hasD. will shut; has been26.----Will you take up teaching as a career after graduation?---- Hard to say. I ________ go abroad for higher education instead, but it depends.A. mustB. shouldC. mightD. shall27.________ the kids had when they experienced the first snowfall--in the South.A. How funB. What funC. How funnyD. What a fun28. Now there is just one point ________ I wish you to make quite clear.A. whereB. whichC. whatD. when29. No one really knows for sure ________ makes a person become right-handed rather thanleft-handed.A. whateverB. whoC. whatD. whoever30. It’s reported that many a house ________ by the heavy snow so far in New York.A. have been destroyedB. has been destroyedC. was destroyedD. were destroyed31.----Why does Jane always ask you for help?---- There is no one else ________, is there?A. who to turn toB. she can turn toC. for whom to turnD. for her to turn32.People laugh at jokes, but seldom ________ about how they work.A. they thinkB. think theyC. they do thinkD. do they think33.It is the only time in history that two Nobel Prizes ________ to the same person.A. have been givenB. had been givenC. have givenD. will give34.---- How is the man injured in the accident?---- The doctor said if ________ in a proper way, he was likely to be saved.A. treatedB. treatingC. is treatedD. to be treated35.---- What happened to you?---- I ________ in the street when someone patted me on the shoulder, which frightened me.A. was about to walkB. was walkingC. had walkedD. walkSection B (18 marks)Directions: For each blank in the following passage there are four words or phrases marked A, B, C and D. Fill in the blank with the word or phrase that best fits the context.I have a cousin who’s a farmer. If you saw him on market day with his old boots and worn hat, you might think he was a tramp (流浪汉). But he’s either buying or selling 36 for thousands of pounds. He doesn’t have a luxurious lifestyle, but the farmhouse, dozens of acres of land, machinery, cattle, chicken and crops must be worth a fortune. You might describe him as a 37 man, but he doesn’t look like that.My father owned a shop selling newspapers, cigarettes, birthday cards, toys, books and magazines. The shop 38 a comfortable life for us, but we weren’t rich. The only luxury was that my father owned a car when most people in our town couldn’t afford one, 39professionals such as doctors and lawyers.My point is that 40 can be misleading. You often can’t 41 the rich from the way they look.I once met Richard Branson, the Virgin Airlines tycoon (巨头).He’d 42 a hot balloon across the Atlantic and landed in the Irish sea. When he was rescued, he was wearing jeans, a T-shirt and a sneaker. You’d 43 have guessed he was a multimillionaire.Andrew Bruce, the 11th Earl (伯爵) of Elgin, 44 a group of press people to his luxurious home in Fife, Scotland. His 45 , the 7th Earl of Elgin was famous for removing and transporting to Britain priceless sculptures from the Parthenon, a very famous temple in Greece. The so-called Elgin Marbles can be seen in the British Museum. The Earl’s castle was 46 cold, despite a fire burning in the hearth (壁炉). He explained to us,“I’m sorry it’s so cold, but you should know that a gentleman’s house is always cold.”There you have it: 47 doesn’t always bring comfort.36. A. eggs B. foods C. cattle D. fruits37. A. wealthy B. poor C. good D. successful38. A. offered B. provided C. supplied D. gave39. A. besides B. including C. as well as D. apart from40. A. things B. facts C. appearances D. faces41. A. say B. tell C. recognize D. judge42. A. made B. driven C. bought D. flown43. A. perhaps B. neither C. never D. rather44. A. allowed B. permitted C. demanded D. invited45. A. forefather B. father C. grandfather D. father-in-law46. A. frozen B. freezing C. surprising D. surprised47. A health B. wealth C. luck D. povertySection C (12 marks)Directions: Complete the following passage by filling in each blank with one word that best fits the context.Lazy people are often seen as useless. However, are they really being lazy 48 are they acting lazy? There is a huge difference between saying you act lazy sometimes and you are a lazy person.So 49 causes a person to be inactive? The answer is 50 lack of goals and purpose. If you give someone a good enough reason to do something, they will do it. People 51 don’t seem to do anyt hing just haven’t found a good enough reason to do anything. Lazy students don’t study because they don’t see the point in studying. If you give them a reason, a strong enough reason that is, they will take action. For example, if you are 52 lazy to go to the gym, would you go if someone offered you a million dollars to go? If you are too lazy to clean out the garage,would someone pointing a gun to your head help you take action? The reason can be positive or negative as long as 53 is strong enough to induce(引起) action.Action will lead to success while inaction will lead to failure. 54 you take action though, you need a compelling reason to do so. 55 motivate someone who is lazy, what you need to do is help them find purpose and enough reasons to work towards a certain goal.PART ⅢREADI NG COMPREHENTION (30 marks) Directions: Read the following three passages. Each passage is followed by several questions or unfinished statements. For each of them there are four choices marked A, B, C and D. Choose the one that fits best according to the information given in the passage.AI remember the first time that I was extremely happy. I was about 8 years old when for the first time, there was a computer in the classroom. I remember that my teacher allowed each student to take turns to play various educational games on the computer. One day, I found the source code(编码)for one of these games. Without knowing or being taught any programming language, I was able to figure out some of the BASIC code. I just gave myself an infinite number of lives in the game, so I could continue playing it forever. This was also my first introduction to algebra, and I didn't even know it at the time. This was a decisive moment in my life. I was quite excited because of what I was learning and what I was able to do. As a result, I was enthusiastic for the rest of my life about self learning and computers, and I was quite happy doing them too.I've noticed that people who are truly content with life are enthusiastic about what they do. This enthusiasm, along with good health, is the key to being happy. It also leads to self-confidence and content in life too. It may also lead to success, wealth, and achievements.Success, wealth, or achievements can also bring some people happiness, yet I know plenty of rich people who are unhappy. I know many people with successful businesses that are not happy with what they are doing. I know people who continuously buy themselves new toys, such as cars, computers, and televisions, yet never seem content for too long. Please remember, happiness is the journey of life, not the destination.56. What can we know from Paragraph 1?A. The author has a great talent for algebra.B. Creative thinking is necessary for every child.C. The BASIC code of the computer is not difficult.D. The author's experience in his childhood changed his life.57. The underlined word "infinite" meansA. bigB. limitlessC. normalD. small58. The author wants to tell us through his experience in the school that ________.A. interest is the best teacherB. children are the hope of the futureC. young people are fearlessD. where there’s a will, there’s a way59. What is the secret of happiness in the author's opinion?A. Success and wealth.B. Gifts and self-confidence.C. Enthusiasm and good health.D. Knowledge and achievements.60. We can infer from the last paragraph that ________.A. people who are rich and successful in career generally feel unhappyB. wealth can’t bring people any happiness and comfortC. one will feel unhappy once he has gained all the things that he wantsD. being enthusiastic about what you do is more important than wealthBParents are fuelling bad behavior among their children by attempting to "buy" their love with expensive gifts nowadays.Over recent decades we seem to have created a "must have" culture among our young people. Many mothers and fathers believe they are "failing as parents" if they are unable to ensure that their children have the latest toy, electronic devices (the lap-top, cellphones, Game Boy, etc.) along with their friends. In many cases, families also feel pressured to enroll (使加入) children in "'every interest club or after-school activity that is available" to fill up their time like most of the other children.But experts warned that the move might affect "precious family time" negatively. Graham Gorton, chairman of the Independent Schools Association, said that parents spent too much time filling their children's lives, which had a series of negative effects on "the very precious family time that exists"."It seems that those times when a whole weekend without planned work was seen as a luxury (奢侈) and a perfect opportunity to spend time together and share those valuable moments of childhood are long gone," Mr. Gorton said. "As a child I only once said that phrase that parents feared 'I'm bored'. Immediately my mother took action and produced a list of jobs and then insisted that I complete every one of them. Though l didn't think cleaning all the floors could really get rid of my boredom, I enjoyed the feeling of staying at home with my mother and brothers."Earlier this year, some researchers suggested that relatively wealthy parents were sometimes guilty of failing to teach basic social skills to children. "Often, it’s the rich middle classes that buy off their children through the computer and the TV. That then sets them apart from their family, and then the parents are surprised when their child isn’ t coming to school."61. The second paragraph mainly tells us that ________.A. today’s children have little time to playB. today’s children depend on electronic tools too muchC. today’s parents feel pressured by the "'must have" cultureD. being qualified parents becomes harder for today's young people62. What does the "must have" phenomenon refer to based on the passage?A. That children must have what other children have.B. That children must have proper pressure to work hard.C. That children must have special skills to ensure a better future.D. That parents must have patience to know their children better.63. Which of the following is the best advice you could give to parents based on Gorton’s statement?A. Plan fewer activities for their children to improve family time.B. Buy their children fewer things that they are fond of.C. Give their children more housework to do.D. Leave their children alone when the kids feel bored.64. Mr. Gorton tended to think that in the past ________.A. children enjoyed doing houseworkB. children never thought life was boringC. children liked to spend time with their familyD. children often had some planned work after school65. From the passage we can infer that ________.A. wealthy parents don’t like teaching basic social skills to childrenB. parents should be much more strict with their children at homeC. children should not be brought up in a wealthy and pleasant environmentD. only satisfying children’s material needs is not a good way of parentingCThere is some unwelcome news for students preparing for exams and officers putting in long hours-----you don't need the break as much as you may think that makes you feel less tired.Scientists have long assumed that willpower (意志力) is a limited resource, which is why you feel the need to have a rest, have a snack and come back to a task when you're feeling better. They argued that the only way to restore willpower was by rest, food or entertainment.But psychologists have challenged this theory, saying weak willpower is all in your head. They found that people's beliefs in willpower determine how long and how well they'll be able to work on a tough mental exercise. "If you think of willpower as something that's limited, you're more likely to be tired when you perform a difficult task," said Prof.Veronika Job. "'But if you think of willpower as something that is not easily used up, you can go on and on."The researchers designed four experiments to test students'-beliefs in willpower. After a tiring task, those, who believed or were led to believe that willpower is a limited resource, performed worse on standard concentration tests than those who thought of willpower as something they had more control over. They also found that leading up to final exam week, students who believed the limited resource theory ate junk food 24 percent more often than those who believed they hadmore control in resisting temptation (诱惑).Mr. Job said. "The theory that willpower is a limited resource is interesting, but it has had unintended consequences. Students who may already have trouble studying are being told that their power of concentration is limited, and they need to take frequent breaks. But a belief in willpower as a non-limited resource makes people stronger in their ability to work through challenges.'"The findings could help people who are" battling temptation. Willpower isn't driven by a biologically based process as much as we used to think. The belief in it is what influences your behavior.66. The theory that willpower is limited supports that _________.A. people must eat snacks when they feel tiredB. people do need a break to restore their willpowerC. t here’s no way to strengthen people’s willpowerD. weak willpower doesn’t affect people’s life much67. What have the scientists long believed regarding willpower?A. It is in the charge of people.B. It is a limited resource.C. There is no way to restore willpower.D. It doesn’t easily run out.68. Which of the following best helps the students to prepare better for their exams?A. Push themselves even if they want to take a break.B. Don’t eat fast food while studying.C. Remind themselves willpower is not limited.D. Stay in a comfortable and quiet place.69. The following groups can benefit from the findings exceptA. patients following strict dietsB. children liking to watch TVC. smokers trying to give up smokingD. employees facing a new but well-paid task70. What’s the best title for the passage?A. A new theory about willpowerB. How to build strong willpowerC. The great influence of willpowerD. Willpower doesn’t last longPART ⅣWRITING (45 marks)Section A (10 marks)Directions: Read the following passage. Fill in the numbered blankets by using the information from the passage. Write NO MORE THAN THREE WORDS for each answer.Before the 1850’s, the United States had a numbe r of small colleges, most of them dating from colonial(殖民的)days. They were small, church connected institutions whose primary concern was to shape the moral character of their students.Throughout Europe, institutions of higher learning had developed, bearing the ancient name of university. In German university was concerned primarily with creating and spreadingknowledge, not morals. Between mid-century and the end of the 1800’s, more than nine thousand young Americans, dissatisfied with their training at home, went to Germany for advanced study. Some of them return to become presidents of admired colleges-Harvard, Yale, Columbia-and transform them into modern universities. The new presidents broke all ties with the churches and brought in a new kind of faculty. Professors were hired for their knowledge of a subject, not because they were of the proper faith and had a strong arm for disciplining students. The new principle was that a university was to create knowledge as well as pass it on, and this called for a faculty made up of teacher-scholars. Drilling and learning by memorization were replaced by the G erman method of lecturing, in which the professor’s own research was presented in class. Graduate training leading to the Ph.D., an ancient German degree representing the highest level of advanced scholarly achievement, was introduced. With the establishment of the seminar system, graduate student learned to question, analyze, and conduct their own research.At the same time, the new university greatly expanded in size and course offerings, breaking completely out of the old, restricted curriculum of mathematics, classics, rhetoric, and music. The president of Harvard pioneered the elective system, by which students were able to choose their own course of study. The new goal was to make the university relevant(相关的) to the real pursuits(追求)of the world.Title The development of the 71 in the USASection B (10 marks)Directions: Read the following passage. Answer the questions according to the information given in the passage and required words limit. Write your answers on your answer sheet.A 10-year-old boy decided to study judo despite the fact that he had lost his left arm in a terrible car accident.The boy began lessons with an old Japanese judo master. The boy was doing well, so he couldn't understand why, after three months of training, the master had taught him only one move. "Sensei," the boy finally said, "shouldn't I be learning more moves?" "This is the only move you know, but this is the only move you'll ever need to know," the sensei replied. Not quite understanding, but believing in his teacher, the boy kept training.Several months later, the sensei took the boy to his first tournament.Surprising himself, the boy easily won his first two matches. The third match proved to be more difficult, but after some time, his opponent became impatient and charged; the boy deftly used his one move to win the match. Still amazed by his success, the boy was now in the finals.This time, his opponent was bigger, stronger, and more experienced. For a while, the boy appeared to be overmatched. Concerned that the boy might get hurt, the referee called a timeout. He was about to stop the match when the sensei intervened."No," the sensei insisted, "let him continue." Soon after the match resumed, his opponent made a big mistake: he dropped his guard. Instantly, the boy had won the match and the tournament. He was the champion.On the way home, the boy and sensei reviewed every move in each and every match.Then the boy gathered the courage to ask what was really on his mind. "Sensei, how did I win the tournament with only one move?" You won for two reasons," the sensei answered. "First, you've almost mastered one of the most difficult throws in all of judo. Second, the only known defense for that move is for your opponent to grab your left arm."81. How did the judo master teach the boy? (no more than 8 words)__________________________________________________________________________ 82. Why did the referee call a timeout? (no more than 9 words)__________________________________________________________________________ 83. What were the reasons for the boy’s winning the champion? (no more than 20 words)__________________________________________________________________________ 84. What can we learn from the short story? (no more than 8 words)__________________________________________________________________________Section C (25 marks)Directions: Write an English composition according to the instructions given below inChinese.请仔细观察图片,描述图片内容,并以生活中发生的一件事情说明图片所说明的内涵。
湖南省长沙市雅礼中学2023届高三下学期月考(六)数学试题含答案

湖南省长沙市雅礼中学2023届高三下学期月考(六)数学试题含答案湖南省长沙市雅礼中学2023届高三下学期月考(六)数学试题含答案1. 选择题1.1. 单选题1. 下列四个不等式中,正确的是:A. |x + 2| > 3B. |2x - 4| ≥ 0C. |3x - 1| ≤ -1D. |4x + 2| < 22. 解答题2.1. 简答题(1)解方程x² + 5x + 6 = 0。
解:首先,我们可以尝试因式分解,将方程进行因式分解,得到:x² + 3x + 2x + 6 = 0(x + 3)(x + 2) = 0由此可知,方程的解为x = -3或x = -2。
(2)已知集合A = {2, 3, 4},集合B = {3, 4, 5},求A和B的交集与并集。
解:集合A和B的交集为A∩B = {3, 4},即A和B共有的元素是3和4。
集合A和B的并集为A∪B = {2, 3, 4, 5},即A和B的所有元素的集合。
2.2. 计算题铁路物流公司欲购买一辆装货能力为200t的货车,现有两种型号的货车可供选择:型号A的装货能力为50t,每辆售价200万元;型号B的装货能力为40t,每辆售价160万元。
为了降低成本,铁路物流公司希望选择装载能力和价格成比例的货车。
那么,应选择购买多少辆型号A和多少辆型号B的货车?解:设购买型号A的货车辆数为x,购买型号B的货车辆数为y,则有以下两个约束条件:50x + 40y = 200200x + 160y = C由第一个等式可得:x = (200 - 40y)/50将x的表达式代入第二个等式中,得到:200(200 - 40y)/50 + 160y = C根据题意,装载能力和价格成比例,可以得到比例关系:(200 - 40y)/50 = 0.4y求解得到:200 - 40y = 0.4y * 50200 - 40y = 20y200 = 60yy = 200/60 = 10/3 ≈ 3.33将y的值代入x的表达式中,得到:x = (200 - 40 * 3.33)/50 ≈ 1.34所以,应选择购买1辆型号A和3辆型号B的货车,以满足装载能力与价格成比例的要求。
湖南省长沙市雅礼中学2009届高三第六次月考试卷文科数学

湖南省长沙市雅礼中学2009届高三月考试卷数学(文史类)命题:高三数学组 审卷:高三数学组本试卷分第Ⅰ卷(选择题)和第Ⅱ卷(非选择题)两部分.满分150分,考试时间120分钟. 参考公式: 正棱锥、圆锥的侧面积公式 如果事件A 、B 互斥,那么 cl S 21=锥侧 P (A+B )=P (A )+P (B )如果事件A 、B 相互独立,那么 其中,c 表示底面周长、l 表示斜高或 P (A ·B )=P (A )·P (B ) 母线长如果事件A 在1次实验中发生的概率是 球的体积公式 P ,那么n 次独立重复实验中恰好发生k 334R V π=球 次的概率k n kk n n P P C k P --=)1()( 其中R 表示球的半径第I 卷(共40分)一.选择题:本大题共8小题,每小题5分,共40分,在每小题给出的四个选项中,只有一项是符合要求的. 1.已知全集U ={1,2,3,4,5},集合M ={1,2,3},N ={3,4,5},则M ∩(U C N )=A.{1,2} B.{4,5} C.{3} D.{1,2,3,4,5}2.()()811x x -+的展开式中含7x 项的系数是A.-21 B.21 C.28- D.283.已知a ,b ∈R ,且a >b ,则下列不等式中恒成立的是A.a 2>b 2B.ba>1 C.lg(a -b)>0 4:已知⎩⎨⎧>+-≤=0,1)2(0,sin )(x x f x x x f π,则)61()61(--f f 的值为A .2-B .1-C .1D .25.给出下面四个命题:①“直线a 、b 为异面直线”的充分非必要条件是:直线a 、b 不相交; ②“直线l 垂直于平面α内所有直线”的充要条件是:l ⊥平面α; ③“直线a ⊥b ”的充分非必要条件是“a 垂直于b 在平面α内的射影”;④“直线a ∥平面β”的必要非充分条件是“直线a 至少平行于平面β内的一条直线”. 其中正确命题的个数是 A.1个 B.2个C.3个 D.4个6.北京2008年第29届奥运会开幕式上举行升旗仪式,在坡度15°的看台上,同一列上的第一排和最后一排测得旗杆顶部的仰角分别为60°和30°, 第一排和最后一排的距离 为610米(如图所示),旗杆底部与第一 排在一个水平面上.已知国歌长度约为50 秒,升旗手匀速升旗的速度为 A.51(米/秒) B.53(米/秒) C.56(米/秒)7.已知P 是椭圆13422=+y x 上的一点,21,F F 是该椭圆的两个焦点,若21F PF ∆的内切圆半径为21,则21PF PF ⋅的值为 A.23C.49- D.08.若二次函数)(4)(2R x c x ax x f ∈+-=的值域为(]0,∞-,则ac c a 44-+-的最小值为 A 4B.C .6D.第II 卷二.填空题:本大题共7小题,每小题5分(第14题第一空2分,第二空3分,第15题第一空3分,第二空2分),共35分.把答案填在答题卡...中对应题号后的横线上. 9.0sin15010.若向量()12,23a λλ=+-与()4,1b =共线,则λ11.已知,x y 满足约束条件50,0,3,x y x y x -+≥⎧⎪+≥⎨⎪≤⎩则y x z +=21213.某商贸公司为了解员工对工资福利的满意度,用分层抽样的方法从销售、财务、人事三个部门的员工中抽取一个容量为20的样本。
湖南省长沙市雅礼中学2024-2025学年高三上学期月考卷(一) 语文试卷(含解析)

炎德·英才大联考雅礼中学2025届高三月考试卷(一)语文本试卷共四道大题,23道小题,满分150分。
时量150分钟。
一、现代文阅读(35分)(一)现代文阅读Ⅰ(本题共5小题,19分)阅读下面的文字,完成1~5题。
材料一:积极情绪(Positive Emotion)可以定义为正面的情绪或者具有正面向上价值的情绪。
情绪的认知理论认为,“积极情绪就是在目标实现过程中取得进步或得到他人积极评价时所产生的感受。
”由此可见,积极情绪就是经历了内在、外在的刺激,正确地解决了问题,达到某种成功与满意度,满足了个体的需求,感觉到个体的存在价值伴有随之而来的愉悦的心情与感受。
积极情绪并不是消极接受、坦然享受、乐不思蜀的感觉。
这些只是浅薄的感受,即时地享乐。
积极情绪拓展到更深的层面——从欣赏到热爱。
它并不是简单的迷恋,而是一种真心喜欢、经过努力而获得的欢愉、欣喜。
“积极情绪”这个词,指向了重要的人性瞬间。
那些轻微而短暂的愉悦状态,其实要比你想象的强大得多。
作为人类,生来就能够体验到微弱短促却愉悦舒畅的积极情绪。
它有着不同的形态和滋味。
回想一下,当感到与他人或与所爱的人心灵相通时;当感到有趣、有创意或忍俊不禁时;当感到自己的灵魂被蕴含在生命中的纯粹的美所打动时;或者当因一个新颖的主意或爱好而感到活力无限、兴致勃勃时,你都会不由自主地产生爱、喜悦、感激、宁静、兴趣和激励这样的积极情绪,它们会打开你的心扉。
然而,无论是迷恋、欢笑还是爱,你由衷的积极情绪总是无法持续很长的时间。
良好的感觉来了又去,就如同好天气一样,这是人类的本性。
积极情绪会逐渐消退,如果它长盛不衰,人们会很难适应变化,无法觉察到好消息和坏消息之间的差异,或是邀请与冒犯之间的差异。
如果你想重塑生活,让它变得更美好,秘诀就是不要把积极情绪抓得太紧,也不要抗拒它稍纵即逝的本性,而是将它更多地植入生活——久而久之,你就会提高积极情绪的分量。
我们发现,在这一秘诀中最重要的是积极率,这是用来描述积极情绪与消极情绪的数量关系的一种方法。
【维叶试卷】2024届湖南省长沙市雅礼中学高三月考语文试卷(五)(含答案)

雅礼中学2024届高三月考试卷(五)语文本试卷共四道大题,23道小题,满分150分。
时量150分钟。
一、现代文阅读(35分)(一)现代文阅读I(本题共5小题,19分)阅读下面的文字,完成1~5题。
材料一:通过天气预报了解天气变化,为出行活动提供参考,这已成为人们日常生活中重要的一部分。
在漫长的没有现代技术与文明的时代里,人们又是怎样进行天气预报的呢?我国的天气预报最早可追溯到商代。
祭祀、农业生产、战争等重大活动都需要预知天气。
有人曾对殷墟出土的317片甲骨文进行统计,发现其中卜雨93片,卜晴4片,卜暴雨5片,卜雪、卜雹各1片。
但仅依靠龟壳灼烧后的裂纹形状进行占卜预测天气,其准确程度值得怀疑。
千年来,人们通过看云、辨风、识星象来观察天气,积累一定经验后,可知一地某些天气变化规律,从而进行预测。
秦汉时总结出的二十四节气、流传至今的天气谚语都反映了早期人们对天气预报的关注。
20世纪,科学家发明并应用气象仪器定量测量大气状态变量,汇总各地气象观测数据绘成天气图,天气预报开始变为应用科学。
在20世纪50年代末之前,所有的天气图都是手工绘制的,气象专家利用各种技术,从天气图表显示的天气类型出发,将现在和过去类似的天气类型作对比,预测出当前的天气系统在几小时或几天后可能发生的变化。
随着计算机技术的发展,数值天气预报诞生,预报准确率也得到大幅提升。
数值天气预报是指根据大气实际情况,在一定的初始和边界条件下,通过大型高速计算机作数值计算,求解描写天气演变过程的流体力学和热力学方程组,以此预测未来一定时段的大气运动状态和天气现象的方法。
但伴随而来的问题是依赖确定性物理规律的数值计算能否彻底解决天气预报的准确性呢?答案并不那么乐观。
大气运动包含了极大的不确定性,其初始场的偏差难以避免,如果初始偏差在处理过程中保持稳定,对大气系统的预测也可能得到相对稳定或确定的结果,遗憾的是在大气这一非线性复杂系统演变过程中做不到这一点,偏差会被迅速放大,导致初始有效信息最终会全部消失,预测结果将出现重大错误。
湖南省长沙市雅礼中学2014届高三第六次月考试题 历史 Word版含答案

雅礼中学2014届高三第六次月考试卷历史第Ⅰ卷选择题(48分)一、选择题(本大题共24小题,每小题2分,共计48分。
在每小题给出的四个选项中,只有一项是符合题目要求的。
)1.陈苏镇在《汉代政治与〈春秋〉学》说:“一方面必须“承秦”,包括承秦之制,另一方面又必须尊重东方社会之习俗,特别是楚、齐、赵人之俗。
这是历史对刘邦的苛刻要求,也是汉初实行郡国并行制的深层背景。
”材料说明西汉初年实行郡国并行是基于A.为了打败刘邦的需要B.吸取秦朝灭亡的原因C.东西方文化的差异D.刘邦的中庸思想【解析】C 这是新的学术观点,根据材料可以得出。
2.《晋书·王询传》记载:“魏氏给公卿以下租牛客户数各有差(不同)。
白后小人惮(害怕)役(服劳役),多乐为之,贵势之门,动有百数。
又太原诸部亦以匈奴胡人为田客,多者数千。
”这主要表明A.两晋民族对峙严重,民族关系紧张B.晋代农民与地主的租佃关系得到发展C.魏国实行赋税制度减轻了农民的负担D.两晋察举选拔逐渐以士族门阀为依据【解析】B A项不正确,材料中只有“以匈奴胡人为田客”的表述,没有反映出民族关系对峙严重的信息。
B项正确,从材料第一句话“租牛客户数”、“以匈奴胡人为田客”,都反映了租佃关系的存在和发展。
C项不正确,材料中反映的是民众害怕“服劳役”,所以愿意到地主贵族的租田佃户。
D项在材料中没有体现。
3.唐太宗时,全国分为十个道,每个道包括若干个州,以便于皇帝派官员视察各州的行政工作。
与“道”职能相当的是A.秦朝的郡B.西汉的州C.宋朝的谏院D.元朝的中书省【解析】B 职掌规谏朝政缺失,西汉的州开始和唐朝的道一样,开始是监察地方的机构,后来才演变为行政区。
4.一位正担任中央大臣者,回忆其早年入仕过程,虽顺利通过礼部考试,因未能通过吏部测试,不得派任官职,只好暂时接受地方政府首长聘任,担任僚佐。
根据你的历史知识,这个官僚可能身处那个时期?A汉代B唐代C元代D清代【解析】B 唐代科举采用资格考试与任官考试分途的方法,考生州、县试合格后,再到礼部按科别参加考试,及格后仅能取得任官资格,考生还要再通过吏部考试,才能分配任官.5. 法国学者加奈隆说:“民众支配雅典,演说支配民众。
湖南省长沙市雅礼中学2023届高三月考英语免费试题带答案和解析

Have a wonderful summer in Italy! Teach English to children at our summer camps and get paid.Job DescriptionEach summer, EDUCO sends hundreds of mother tongue English speakers to over 200 summer camps across Italy, from the Alps, to Sicily. Our camps offer a unique experience for Italian children as they do not stick firmly to traditional teaching methods; instead, they employ the use of drama, songs and games to help learn English gradually and easily. Camps run form 9 am to 5pm, from Monday to Friday, and the children are completely involved in this mode of learning from start to finish. Each camp runs for either one or two weeks, before sending tutors off to a new location.Join us for a rewarding summer experience in one of the most beautiful countries in the world. We’re looking for enthusiastic, responsible and reliable tutors who love working with children and are prepared to teach English in fun and creative ways. Previous teaching experience and Italian language skills are NOT necessary for this role.A five-day course in Bologna(an Italian city) will provide all tutors with the training they need for our camps. Working in small guided groups, you’ll be taught some skills to help you successfully run camps. EDUCO will also provide you with a number of necessary materials to take to camp. The course dates for summer 2021 are:June 11th-16thJune 18th -23rdAugust 13th -18thWhat we offerPaid financial aid.A chance to spend the summer in Italy!The chance to take on a challenging but extremely rewarding role that will prove to be invaluable in your future career.You get to discover various beautiful places in Italy while touring in groups to perform shows.We ask thatYou should be a university student or graduate.Previous teaching experience is NOT necessary.Italian language skills are NOT necessary.Your mother tongue is English.You enjoy working with children.【1】What can we learn about the camps from the text?A.The tutors in the camps are native English speakers.B.The camps are for adults.C.The teaching methods are different among the camps.D.Each camp lasts for two weeks.【2】Who may be the right person for the camps?A.A person who is outgoing and likes children.B.A person who is a native Italian speaker.C.A person who has experience in teaching Italian.D.A person who has just graduated from high school.【3】Where may this text come from?A.A popular magazine.B.A job advertisement.C.World news section of a newspaper.D.Entertainment section of a newspaper.【答案】【1】A【2】A【3】B【解析】这是一篇应用文。
湖南省长沙市雅礼中学2022-2023学年高三下学期月考卷(六)生物试题含答案

雅礼中学2023届高三月考试卷(六)生物学本试题卷包括选择题、非选择题两部分,共10页。
时量75分钟,满分100分。
一、单项选择题(本题共 12小题,每小题2分,共24分。
每小题只有一个选项符合题目要求。
)1.3NO -和NH 4+是植物利用的主要无机氮源,转运机制如下图所示,图中AMTs 、NRT1.1、SLAH3为根细胞膜上的三种转运蛋白。
过量施用NH 4+会加剧土壤的酸化,引起植物生长受到严重抑制,这一现象被称为铵毒。
研究发现当3NO -存在时,植物可以通过减轻土壤酸化来缓解铵毒症状,NRT1.1和SLAH3参与缓解铵毒的过程。
以下分析错误的是A .根细胞膜对物质的吸收具有选择透过性,这与细胞膜上的蛋白质种类不同有关B . AMTs 运输NH 4+的方式与NRT1.1运输3NO -的方式均为协助扩散C .推测植物通过调用NRT1. 1来加速对胞外3NO -/H +的同向转运从而降低了胞外H +浓度,缓解了铵毒D .外源施加3NO -或者由SLAH3外排3NO -均可能缓解植物的铵毒症状2.生物学实验设计中应遵循单一变量原则和对照原则,在对照实验中可以采用加法原理或减法原理实现对自变量的控制。
下列有关实验的叙述中正确的是A .在“比较过氧化氢在不同条件下的分解”实验中利用了减法原理来控制自变量B .在探索生长素类调节剂促进插条生根的最适浓度”实验中,预实验和正式实验均需要设置空白对照C .在“观察紫色洋葱鳞片叶外表皮细胞质璧分离与复原”的实验中不存在对照D .在“探究唾液淀粉酶的最适pH ”的实验中,先将每一组温度控制在37°C 属于对无关变量的控制3.细胞中几乎所有的化学反应都是由酶催化的,酶的活性受到多种因素的影响。
酶的作用原理如图一所示,酶促反应速率与影响因素的关系如图二所示。
下列叙述错误的是A.图一中有酶催化时反应进行所需要的活化能是BC段B.如果将酶催化改为无机催化剂催化,则图一的纵坐标轴上B点对应的虚线应上移C.图二中曲线②和③分别表示pH和温度对酶促反应速率的影响D.图二中若横轴表示反应物浓度,曲线①的BC段对应数值保持不变的原因主要是酶的数量有限4.某昆虫体色有灰体和黄体,分别由等位基因B、b控制,腿型有粗腿和细腿,分别由等位基因D、d控制,其中B、b基因位于常染色体上(D、d基因不位于Y染色体上)。
雅礼中学高三月考作文

雅礼中学高三月考作文咱雅礼中学这高三月考啊,可真是让我又爱又恨!就说这次月考写作文的时候吧,那真是一场“惊心动魄”的经历。
那天,考试铃声一响,我拿到试卷就赶紧瞄了眼作文题目。
哎呀妈呀,这题目看着有点绕,我心里“咯噔”一下,感觉有点不妙。
但咱也不能慌不是?我深吸一口气,告诉自己:“稳住,能赢!”我开始构思,脑子像个飞速旋转的陀螺。
想着想着,突然灵光一闪,有了个大概的思路。
于是,我迫不及待地拿起笔,准备在这作文的战场上“大杀四方”。
我写的是关于友谊的话题,这让我一下子就想起了我和我那好哥们儿的事儿。
我俩啊,从穿开裆裤的时候就认识了,一起调皮捣蛋,一起被家长追着打。
记得有一次,学校组织春游,我们去了一个有山有水的好地方。
那风景,美得就像画儿一样。
到了中午,大家都开始分享自己带的好吃的。
我这马大哈,光顾着玩儿,带的零食少得可怜。
我那哥们儿一看,二话不说就把他的零食往我怀里塞,还笑着说:“咱哥俩谁跟谁啊,你多吃点,别饿着!”就这么一句话,当时我心里那叫一个暖哟,感觉比吃了蜜还甜。
后来我们一起爬山,那山可真陡啊!我这人平时就缺乏锻炼,没爬几步就累得气喘吁吁。
我那哥们儿呢,走在前面还时不时地回头拉我一把,嘴里不停地给我打气:“加油,马上就到山顶啦,到了山顶风景更美!”在他的鼓励下,我咬着牙,一步一步地往上爬。
终于到了山顶,那景色,真的是绝了!连绵起伏的山峦,在阳光的照耀下,像是披上了一层金色的纱衣。
远处的湖水波光粼粼,就像一面巨大的镜子。
我们俩站在山顶,开心得大喊大叫,仿佛整个世界都是我们的。
想着想着,我笔下的文字就像流水一样,哗哗地往外淌。
我写得那叫一个投入啊,完全忘记了周围的一切。
就在我写得正起劲儿的时候,突然听到监考老师说:“还有半个小时交卷。
”我一听,心里一紧,妈呀,时间咋过得这么快?我赶紧加快速度,可越着急越容易出错,有几个字都写得歪歪扭扭的。
我一边写一边瞟着试卷上的字数,心里默默祈祷:“老天保佑,让我写够字数吧!”终于,在考试结束的前几分钟,我写完了最后一个字。
2023-2024学年湖南省长沙市雅礼中学高三上学期月考试卷(六)化学试题

2023-2024学年湖南省长沙市雅礼中学高三上学期月考试卷(六)化学试题1. 2023年中国航天大会的主题是“格物致知,叩问苍穹”。
下列关于航天飞船上所用材料说法正确的是A.航天飞船上太阳能电池板的材料主要成分为SiO 2B.航天飞船制作发动机喷管套筒的碳纤维属于有机高分子材料C.发射航天飞船的新一代运载火箭成功应用液氧煤油发动机,煤油是烃的混合物D.航天飞船上用于燃气管路隔热层的纳米二氧化硅是胶体2.下列说法错误的是A.反-2-丁烯的结构简式:B.基态的价电子轨道表示式:C.的空间填充模型:D.和在光照下充分反应,反应前后的分子总数不变3.设N A为阿伏加德罗常数的值。
下列有关叙述正确的是A.的盐酸中含HCl分子的数目为N AB.通入水中发生反应,转移的电子数为N AC.标准状况下,中含有的硫原子数为N AD.中含有共用电子对的总数为1.5 N A4.下列指定反应的离子方程式正确的是A.饱和氯水中通入至溶液颜色褪去:B.溶液中加入过量浓氨水:C.向滴有酚酞的溶液中滴入盐酸至红色恰好褪去:D.溶液中加入足量石灰乳:5.高氯酸钾是一种强氧化剂,易溶于水。
以氯化钠为原料制备高氯酸钾的一种流程如图:下列说法错误的是A.“电解”生成气体的主要成分为H 2B.“高温分解”反应中氧化剂和还原剂的物质的量之比为1∶3 C.本实验条件下,KClO 4在水中的溶解度比NaClO 4大D.母液经分离、提纯可制得食盐6.如图所示装置能达到实验目的的是A.制取B.制取C.利用此装置可较长时间看到白色絮状沉淀D.该改进装置可用于性质的探究实验7.探究汽车尾气中NO的无害化处理,催化剂作用下在容积均为1L的两个容器中发生反应2NO(g)⇌N2(g)+O2(g) △H1,有CO存在时发生反应2NO(g)+2CO(g)⇌N2(g)+2CO2(g) △H2。
容器①充入0.1molNO,容器②0.1molNO和0.1molCO。
湖南省长沙市雅礼中学2024-2025学年高三上学期月考卷(一)化学试题+答案

大联考雅礼中学2025届高三月考试卷(一)化学本试题卷分选择题和非选择题两部分,共8页。
时量75分钟,满分100分。
可能用到的相对原子质量:H~1 C~12 N~14 O~16 Na~23 Al~27 Si~28 P~31第Ⅰ卷(选择题 共42分)一、选择题(本题共14小题,每小题3分,共42分,每小题只有一个选项符合题意。
)1.下列有关叙述错误的是( )A .放电影时,放映机到银幕间光柱的形成是因为丁达尔效应B .工业上一般可以采用电解饱和食盐水的方法制取NaOHC .FeO 在空气中受热,能迅速被氧化成23Fe OD .硬铝是一种铝合金,密度小、强度高,具有较强的抗腐蚀能力,是制造飞机和宇宙飞船的理想材料 2.设A N 为阿伏加德罗常数的值,下列叙述正确的是( ) A .40gSiC 晶体中含有的Si C −的数目为A 2NB .100g 质量分数为46%的25C H OH 的水溶液中含有的氧原子数目为A 4N C .标准状况下,11.2L 3NH 与11.2LHF 均含有A 5N 个质子D .1mol 614C H 中含有的σ键的数目为A 20N3.下列关于23Na CO 和3NaHCO 的说法中,错误的是( ) A .两种物质的溶液中,所含微粒的种类相同 B .可用NaOH 溶液使3NaHCO 转化为23Na COC .利用二者热稳定性差异,可从它们的固体混合物中除去3NaHCOD .室温下,二者饱和溶液的pH 差约为4,主要是因为它们的溶解度差异 4.在给定条件下,下列制备过程涉及的物质转化均可实现的是( )A .制备22HCl :NaCl H Cl HCl → →电解点燃溶液和B .制备金属()22Mg :Mg OH MgCl Mg → →盐酸电解溶液C .纯碱工业:2CO 323NaCl NaHCO Na CO →→△溶液D .硫酸工业:22O H O2224FeS SO H SO → →高温5.下列过程中,对应的反应方程式错误的是( ) A 草酸溶液与酸性高锰酸钾溶液反应 22424222MnO 16H 5C O 2Mn 10CO 8H O −+−+++=+↑+ B NaH 用作野外生氢剂22NaH H ONaOH H +=+↑ C 工业制备高铁酸钠()24Na FeO32423ClO 2Fe 10OH 2FeO 3Cl 5H O −+−−−++=++D绿矾()42FeSO 7H O ⋅处理酸性工业废水中的227Cr O −22332726Fe Cr O 14H 6Fe 2Cr 7H O +−+++++=++6.下列实验装置正确的是( )A .制备()2Fe OHB .制取少量2OC .3NaHCO 受热分解D .铝热反应7.下列实验操作和现象、结论或目的均正确的是( ) 选项 操作和现象结论或目的A将新制的()3Al OH 沉淀分装在两支试管中,向一支试管中滴加2mol/L 盐酸,另一支试管中滴加2mol/L 氨水,沉淀均溶解 ()3Al OH 是两性氢氧化物B将镁条点燃后迅速伸入充满2CO 的集气瓶,瓶中产生浓烟并有2CO 能支持镁条燃烧黑色颗粒生成 C取2FeCl 溶液置于试管中,加入几滴酸性高锰酸钾溶液,酸性高锰酸钾溶液的紫色褪去2Fe +具有还原性D各取23Na CO 溶液与3NaHCO 溶液少许于试管中,加入澄清石灰水,仅23Na CO 溶液中出现白色沉淀鉴别23Na CO 溶液与3NaHCO 溶液8.已知电对的标准电极电势()0E越高,其电对中氧化剂的氧化性越强。
雅礼中学2010届高三月考试卷(六)

雅礼中学2010届高三月考试卷(六)化学试卷考生须知:1.本试卷考查内容:选修5占30%,其他内容占70%。
2.本试卷共5页(含答卷),共21小题,满分为100分,考试时量90分钟。
3.本卷可能用到的相对原子质量:H-1 N-14 O-16 Cl—35.5 C—12 Si—28 Na-23 Fe—56 Mg—24 Al—27 Cu—64第Ⅰ卷(本卷包含16个小题,共48分)一.选择题(每小题只有一个符合题意的选项,每小题3分,共48分):1.下列说法中不正确的是()①三聚氰胺(C3N6H6)俗称“蛋白精”,加入到奶粉中的目的是提高含氮量,以提高蛋白质的含量,增加奶粉的营养,对身体有益;②医疗上可用碳酸钡作X射线透视肠胃的内服药;③用新制备的Cu(OH)2悬浊液与病人尿液共热,可检验病人尿液中是否含有葡萄糖;④铝和铜具有良好的导电性,所以电工操作时,可以把铜线和铝线绞接在一起;⑤明矾可以用于净水,主要是由于铝离子可以水解得到氢氧化铝;⑥“水滴石穿”主要是溶解了CO2的雨水与CaCO3长期作用生成了可溶性的Ca(HCO3)2的缘故。
A. ②③⑤B. ①②④C.③④⑥D. ③④⑤【答案】B 2.某炔烃经催化加氢后可得到2-甲基丁烷,则该炔烃的名称是()A.2-甲基-1-丁炔B.2-甲基-3-丁炔C.3-甲基-1-丁炔D.3-甲基-2-丁炔【答案】C 3.设N A为阿伏加德罗常数的数值,则下列说法正确的是()A.1mol甲基(CH3-)所含有的电子总数为10N AB. 铁、铜和稀硫酸构成原电池,当转移N A个电子,产生的气体体积一定为11.2 LC. 足量的单质铁与1mol氯气充分反应后转移的电子总数为3N AD.对于反应:C2H2 (g)+5/2O2(g) == 2CO2(g)+H2O(l) △H=-1300 kJ·mol-1,若有4N A个碳氧双键形成时,则可放出1300 kJ的能量【答案】D 4.某酯的结构可表示为:C m H2m+1COOC n H2n+1,其中m+n=5,若该酯在酸性条件下水解得到的一种水解产物经催化氧化可最终转化成它的另一种水解产物,则原来的酯是()A.乙酸丙酯B.乙酸乙酯C. 丙酸丙酯D. 丙酸异丙酯【答案】C 5.下列各组离子在指定溶液中一定能够大量共存的是()A.pH=12的溶液中:K+,Na+,AlO2—,S2—,SO32—B.无色溶液中:K+,Cl—,MnO4—,PO43—,SO42—C.水电离的H+浓度C(H+)=10—12mol·L—1的溶液中:ClO-,SO42-,NO3-,NH4+,Na+D.某强酸性溶液中:Fe2+,Al3+,NO3—,I—,Cl—【答案】A6.把固体Ca(OH)2放入适量的蒸馏水中,一段时间后达到溶解平衡:Ca(OH)2(s)Ca2+ (aq)+ 2OH-(aq),则下列说法中正确的是()A.给溶液加热,溶液中的Ca2+浓度一定增大B.恒温条件下向溶液中加入少量CaO,溶液的pH升高C.向溶液中加入少量CH3COONa晶体,则Ca(OH)2固体的质量增多D.向溶液中加入少量冰醋酸,溶液中的OH-浓度增大【答案】C 7.已知某有机物结构简式为:若将Na、NaOH、NaHCO3分别与等物质的量的该有机物恰好完全反应时,则消耗Na、NaOH、NaHCO3的物质的量之比为()A.3∶3∶2 B.3∶2∶1 C.3∶2∶2 D.3∶1∶1 【答案】B 8.一定量的甲烷燃烧后产物为CO、CO2和H2O(g),共重144 g,此混合气体缓慢通过浓H2SO4后,浓H2SO4增重72 g,则燃烧产物中CO2的质量为()A. 72gB. 66 gC. 48 gD. 44 g 【答案】D 9.现有在固定容积的密闭容器中进行的可逆反应:4L(g)2M(g)+N(g)△H>0,下图表示温度,则图中Y轴可以表示的涵义是()和压强对该平衡状态的影响,同时已知有:p p12A. 体系中物质L的百分含量B. 体系中总的气体分子数目C. 气体混合物的平均相对分子质量D. 气体混合物的平均密度【答案】C10.右图中为直流电源,为浸透饱和氯化钠溶液和酚酞试液的滤纸,为电镀槽,通电后发现上的c点附近显红色,则下列叙述中正确的是()A.e极上发生还原反应B.a为直流电源的负极C.若要实现铁上镀锌,则f电极为锌板D.c极上发生的反应:2H+ +2e-=H2↑【答案】D11.将CO2持续通入下列八种饱和溶液:①Na2CO3②K2SiO3 ③NaAlO2 ④C6H5ONa ⑤Ca(ClO)2⑥BaCl2⑦NH3和NaCl ⑧Ca(OH)2,最终能够得到沉淀或析出晶体的是()A.②⑤⑥⑧B.③④⑤⑧C.①④⑥⑦D.①②③⑦【答案】D 12.现有1.0 mol/L的NaOH溶液0.2L,若通入4.48L(标准状况)SO2气体使其充分反应后,则所得溶液中各粒子浓度大小关系正确的是()A.c(SO32―) + c( OH―) = c(H+) + c(H2SO3)B.c(Na+) = c(H2SO3) + c(HSO3―) + c ( H+)C.c(Na+)+c(H+) = c(HSO3―) +c(SO32―) + c( OH―)D.c(Na+)>c(HSO3―)>c( OH―)>c(H2SO3)>c(SO32―)>c(H+) 【答案】A 13.霉酚酸酯(MMF)是器官移植中抑制细胞增殖最常用的药物,下列关于MMF的说法正确的是( )A.MMF所有碳原子一定处在同一平面B.1molMMF能与含3molNaOH溶液完全反应C.MMF的分子式为C24H31O7N D.MMF能发生取代、氧化、加成和消去反应【答案】B 14.在浓度为C mol/L的AgNO3溶液VmL中,加入一定量的pH=1的盐酸时恰好沉淀完全,此时得到pH=2的溶液100mL,则C约为(设反应前后溶液体积变化忽略不计)()A、0.011B、0.022C、0.01D、0.1 【答案】A 15.分子式为C4H7Cl的属于链状化合物的可能结构共有(包含顺反异构和对映异构)()A.14种B.12种C.11种D.8种【答案】B 16.现有一定量的铁粉和铜粉的混合物,将其平均分成四等份,分别加入同浓度不同体积的稀硝酸,充分反一种):根据上表中的数据计算分析,下列推断正确的是( )A.①中溶解了5.6 g Fe B.②中溶解了9.6 g CuC.硝酸的浓度为4 mol/L D.④中V = 6720 【答案】C第Ⅱ卷(本卷包括5小题,共52分)二、填空题(每空2分,共52分):17.(8分)已知:氨水的电离程度与醋酸的电离程度在同条件下几乎相等。
湖南省长沙市雅礼中学2023-2024学年高三下学期月考试卷(六)英语试题

International Summer Job
Hi, I’m an ESL student in China. I’m 20, quiet and polite, and I speak reasonable English. I’m looking for a summer job in an Englishspeaking country. I can teach Chinese or do house and garden work and cook Chinesedishes. Can anybody offer me a job? I don’t need to earn much, just enough in two months(JulyAugust)to pay for my return ticket to China. My goal is to improve my English and see a bit more of the world.
C. He plays the piano well.
听第9段材料,回答第13至16题。
13. When was the World Wild Fund for Nature set up?
A. In 1916. B. In 1961. C. In 1969.
14. What does the Audubon Society work to protect?
C. Shop assistant and manager.
4. Where are the speakers?
A. In a restaurant. B. In a bank. C. In a hotel.
湖南省长沙市雅礼中学2022-2023学年高三下学期月考卷(六)物理试卷

雅礼中学2023届高三月考试卷(六)本试题卷分选择题和非选择题两部分,共8页。
时量75分钟,满分100分。
一、单选题(本题共7小题,每小题4分,共28分,在每小题给出的四个选项中,只有一项是符合题目要求的)1.下列说法不正确的是A.原子核结合能越大,原子核越稳定B.汤姆孙通过对阴极射线的研究发现了电子,从而揭示了原子有复杂结构C.卢瑟福的原子核式结构模型解释了α粒子散射实验D.贝克勒尔发现的天然放射现象说明原子核具有复杂的结构2.水下一固定点光源,发出a、b两单色光。
人在水面上方向下看,水面中心Ⅰ区域有a光b 光射出,Ⅱ区域只有a光射出,如图所示。
下列判断不正确的是A.水对a光折射率比水对b光折射率小B利用同一双缝干涉实验装置在相同介质进行光的干涉实验,b光干涉条纹间距比a光大C.a光在水中的传播速度大于b光D.若用a光照射某种金属可发生光电效应,则用b光照射此金属同样可发生光电效应3.如图所示,长木板上固定有一根“L”形木杆,木杆右端边缘的O点用轻质细绳悬挂一个质量为m的小球,长木板与木杆的总质量为7m。
若给长木板施加大小为14mg的水平推力,长木板开始向右运动,稳定时,细绳偏离至OA位置。
经过一段时间,撤去水平推力,长木板继续向右运动,稳定时,细绳偏离至OB位置(图中没有作出,此时木板速度不为0)。
已知重力加速度为g,长木板与地面之间的动摩擦因数为3,则∠AOB等于4A.82°B.90°C.60°D.75°4.一质点从坐标原点沿着x轴正方向做直线运动﹐质点运动速度v与位移x的关系如图所示,下列说法正确的是A.质点做匀减速直线运动B质点做加速度增大的减速直线运动C.质点所受合外力与位移成线性关系D.质点通过连续相等位移所用时间变小5.用质量分布均匀的长方形光滑玻璃板AB做成的跷跷板置于O点上,左右两侧等高。
被轻质细绳锁定的C、D小车之间放置一压缩轻质弹簧,已知轻质弹簧与小车不拴接,将连有轻弹簧的C、D小车静置于跷跷板上,左右两侧仍等高。
湖南省长沙市雅礼中学2022-2023学年高三下学期月考卷(六)化学试题

2023届 雅礼中学化学试卷(六)时量:75分钟满分:100分可能用到的相对原子质量:H ~1C ~12N ~14O ~16F ~19Na ~23Al ~27Si ~28S ~32Cl ~35.5Ca ~40Fe ~56Ba ~137第Ⅰ卷(选择题共42分)一、选择题(本题共14小题,每小题3分,共42分,每小题只有一个选项符合题意。
)1.成语、古诗词、谚语等都是我国传统文化的瑰宝。
下列有关解读错误的是()A.“水滴石穿”过程中发生了化学变化B.“雨过天晴云破处,这般颜色做将来”所描述的瓷器青色,不是来自氧化铁C.“三月打雷麦谷堆”是指在雷电作用下,N 2最终转化成被作物吸收的化合态氮D.“日照香炉生紫烟”描述的是碘的升华2.N A 为阿伏加德罗常数的值,下列说法错误的是()A.已知1141521B He R H +→+,14g R 含有的中子数为8N AB.0.4mol 联氨(N 2H 4)中含有共价键数目为2N AC.138g NO 2与H 2O 完全反应时转移的电子数为3N AD.常温下,1L pH=12的CH 3COONa 溶液中,H 2O 电离出的OH -数为0.01N A3.周期表中第ⅥA 族元素及其化合物应用广泛。
用硫黄熏蒸中药材的传统由来已久;H 2S 是一种易燃的有毒气体(燃烧热为1562.2kJ mol -⋅),可制取各种硫化物;硫酸、硫酸盐是重要化工原料;硫酰氯(SO 2Cl 2)是重要的化工试剂,常作氯化剂或氯磺化剂。
硒(34Se )和碲(52Te )的单质及其化合物在电子、冶金、材料等领域有广阔的发展前景,工业上以精炼铜的阳极泥(含CuSe )为原料回收Se ,以电解强碱性Na 2TeO 3溶液制备Te 。
下列化学反应表示正确的是()A.H 2S 的燃烧:122222H S(g)3O (g)2SO (g)2H O(g)1124.4kJ mol H -+===+∆=-⋅B.SO 2Cl 2遇水强烈水解生成两种强酸:22223SO Cl 2H O 4H SO 2Cl +--+===++C.电解强碱性Na 2TeO 3溶液的阴极反应:232TeO 4e 3H O Te 6OH ---++===+D.CuSe 和浓硝酸反应:3322CuSe 2HNO Cu(NO )H Se +===+↑4.某100mL 溶液可能含有Na +、4NH +、Fe 3+、23CO -、42SO -、Cl -中的若干种,取该溶液进行连续实验,实验过程如图(所加试剂均过量,气体全部逸出)。
湖南省长沙市雅礼中学2020届高三月考(六)数学(理)试题及答案

湖南省长沙市雅礼中学2020届高三月考(六)数学(理)试题一、选择题:本大题共12个小题,每小题5分,共60分.在每小题给出的四个选项中,只有一个选项是符合题目要求的.1.已知集合A ={x ∈N |x ≤3},B ={x |﹣1≤x ≤5},则A ∩B =( ) A .{1,2,3}B .{0,1,2}C .{0,1,2,3}D .{﹣1,0,1,2,3}2.若复数z 满足|z +1|+|z ﹣1|=4,则|z|的最小值为( ) A .1B .√2C .√3D .23.已知a →=(−2,−1),b →=(λ,1),则λ>−12是“a →与b →的夹角为钝角”的( )条件 A .充分不必要 B .必要不充分 C .充分必要D .既不充分也不必要4.函数y =xlnx 的图象大致是( )A .B .C .D .5.在等差数列{a n }中,其公差d ≠0,若S 7=S 12,现有以下四个命题:①S 19=0;②S 10=S 9;③若d >0,则S n 有最大值;④若d >0,则S n 有最小值. 则关于这四个命题,正确的是( ) A .①②③B .①②④C .①④D .②③.6.甲、乙、丙、丁四位同学站成一排照相,则甲.乙两人中至少有一人站在两端的概率为( ) A .56B .12C .13D .237.在空间中,a 、b 、c 是三条不同的直线,α、β是两个不同的平面,则下列说法正确的是( ) A .若a ⊥c ,b ⊥c ,则a ∥b B .若a ⊂α,b ⊂β,则a ⊥bC .若a ∥α,b ∥β,α∥β,则a ∥bD .若α∥β,a ⊂α,则a ∥β8.已知变量x ,y 之间的线性回归方程为y =−0.7x +10.3,且变量x ,y 之间的一组相关数据如表所示,则下列说法错误的是( ) x 6 8 10 12 y6m32A .变量x ,y 之间呈现负相关关系B .可以预测,当x =20时,y =﹣3.7C .m =4D .该回归直线必过点(9,4) 9.cos10°sin10°−4cos10°=( ) A .1B .√2C .√3D .210.设a =log 23,b =log 45,c =212,则a ,b ,c 的大小关系为( ) A .a >c >bB .a >b >cC .c >a >bD .b >c >>a11.在数列{a n }中,a 1=a ,a n +1=2a n ﹣1,若a n 为递增数列,则a 的取值范围为( ) A .a >0B .a >1C .a >2D .a >312.双曲线C :x 2a 2−y 2b 2=1(a >0,b >0)上存在一点P ,使sin∠PF 2F1sin∠PF 1F 2=ca ,则双曲线C 的离心率的取值范围为( ) A .(1,1+√2)B .(1,2]C .(1+√2,+∞)D .[2,+∞)二、填空题:本大题共4小题,每小题5分,共20分.13.若x ,y 满足约束条件{x −y +1≥0x +y −3≥0x −3≤0,则z =x ﹣2y 的最小值为 .14.点P 为椭圆C :x 2a 2+y 2a 2−1=1(a >1)上的任意﹣一点,AB 为圆M :(x ﹣1)2+y 2=1的任意一条直径,若PA →⋅PB →的最大值为15,则a = .15.在(x +y +z )6的展开式中,所有形如x 3y a z b (a ∈N ,B ∈N )的项的系数之和为 . 16.函数f (x )=1sinx+8cosx(0<x <π2)的最小值为 .三、解答题:本大题共70分.解答应写出文字说明、证明过程或演算步骤.17.(12分)△ABC 中,角A 、B 、C 的对边分别为a 、b 、c ,已知(a +b )(sin A ﹣sin B )=(c ﹣b )sin C . (1)求角A 的大小; (2)求b+c a的取值范围.18.(12分)在平行六面体ABCD ﹣A 1B 1C 1D 1中,所有棱长均为2,∠AA 1D 1=∠AA 1B 1=60°,∠D 1A 1B 1=90°. (1)求证:A 1C ⊥B 1D 1; (2)求对角线AC 1的长;(3)求二面角C 1﹣AB 1﹣D 1的平面角的余弦值的大小.19.(12分)已知中心在原点的双曲线C 的渐近线方程为y =±2x ,且该双曲线过点(2,2). (1)求双曲线C 的标准方程;(2)点A 为双曲线C 上任一点,F 1、F 2分别为双曲线的左、右焦点,过其中的一个焦点作∠F 1AF 2的角平分线的垂线,垂足为点P ,求点P 的轨迹方程. 20.(12分)已知函数f (x )=lnx ﹣ax +a ,a ∈R . (1)求f (x )的单调区间;(2)当x ≥1时,恒有g (x )=(x +1)f (x )﹣lnx ≤0恒成立,求a 的取值范围..21.(12分)现有甲、乙、丙、丁四个人相互之间传球,从甲开始传球,甲等可能地把球传给乙、丙、丁中的任何一个人,依此类推.(1)通过三次传球后,球经过乙的次数为ξ,求ξ的分布列和期望; (2)设经过n 次传球后,球落在甲手上的概率为a n , (i )求a 1,a 2,a n ;(ii )探究:随着传球的次数足够多,球落在甲、乙、丙、丁每个人手上的概率是否相等,并简单说明理由.请考生在第22、23两题中任选一题作答.注意:只能做所选定的题目.如果多做,则按所做的第一个题目计分.[选修4-4:坐标系与参数方程]22.(10分)已知直线l 的参数方程为{x =1+t y =3+2t (t 为参数),曲线C 的极坐标方程为ρ2=91+8sin 2θ.(1)求直线l 的普通方程和曲线C 的直角坐标方程; (2)直线l 与曲线C 交于A 、B 两点,P (1,3),求1|PA|+1|PB|的值.[选修4-5:不等式选讲]23.已知函数f (x )=|x ﹣1|+|2x ﹣6|(x ∈R ),记f (x )的最小值为c . (1)求c 的值;(2)若实数a 、b 满足a >0,b >0,a +b =c ,求a 2a+1+b 2b+1的最小值.一、选择题:本大题共12个小题,每小题5分,共60分.在每小题给出的四个选项中,只有一个选项是符合题目要求的.1.【详解详析】∵集合A ={x ∈N |x ≤3}={0,1,2,3}, B ={x |﹣1≤x ≤5}, ∴A ∩B ={0,1,2,3}. 故选:C .2.【详解详析】设z 对应的点为(x ,y ),则x 24+y 23=1,所以 |z|最小值=√3. 故选:C .3.【详解详析】∵a →=(−2,−1),b →=(λ,1), ∴a →与b →的夹角为钝角⇔﹣2λ﹣1<0且﹣2+λ≠0, 即λ>−12且λ≠2.∴λ>−12是“a →与b →的夹角为钝角”的必要不充分条件.故选:B .4.【详解详析】当x →0+时,lnx →﹣∞,∴xlnx <0,排除A 、B 选项, 当x →+∞时,xlnx →+∞,排除C 选项, 故选:D .5.【详解详析】在等差数列{a n }中,其公差d ≠0,若S 7=S 12, 则:a 8+a 9+a 10+a 11+a 12=0,整理得5a 10=0, 所以a 10=0, 所以A :S 19=19(a 1+a 19)2=19a 10=0.B :由S 10=S 9;整理得a 10=0,C :若d >0,则S n 有=na 1+n(n−1)2d =d 2n 2+(a 1−d2)n ,所以S n 有最小值. 故;①②④正确. 故选:B .6.【详解详析】∵甲、乙、丙、丁四位同学站成一排照相,基本事件总数n=A44=24,甲、乙两人中至少有一人站在两端包含的基本事件个数m=A44−A22A22=20,∴甲.乙两人中至少有一人站在两端的概率为:P=mn =2024=56.故选:A.7.【详解详析】对于选项A:若a⊥c,b⊥c,则a和b可能是异面直线,故错误.对于选项B:若a⊂α,b⊂β,则a和b不能判定有垂直和平行的关系,故错误.对于选项C:若a∥α,b∥β,α∥β,则a和b可能异面,故错误.对于选项D:若α∥β,a⊂α,则a∥β,正确.故选:D.8.【详解详析】对于A:根据b的正负即可判断正负相关关系.线性回归方程为y=−0.7x+10.3,b=﹣0.7<0,负相关.对于B,当x=20时,代入可得y=﹣3.7.对于C:根据表中数据:x=14(6+8+10+12)=9.可得y=−0.7×9+10.3=4.即14(6+m+3+2)=4,解得:m=5.对于D:由线性回归方程一定过(x,y),即(9,4).故选:C.9.【详解详析】原式=cos10°−2sin20°sin10°=cos10°−2sin(30°−10°)sin10°=√3sin10°sin10°=√3.故选:C.10.【详解详析】log23>log2232>log2√5=log45,∴a>32>b,又log45<log4443=43<212<32,∴a>c>b.故选:A.11.【详解详析】∴a n+1=2a n﹣1,∴a n+1﹣1=2(a n﹣1),∴a n+1−1a n−1=2,又∵a1﹣1=a﹣1,∴数列{a n﹣1}是首项为a﹣1,公比为2的等比数列,∴a n−1=(a−1)2n−1,∴a n =(a −1)2n−1+1, 又∵{a n }为递增数列,∴a n+1−a n =(a −1)2n −(a −1)2n−1=12(a −1)2n >0, ∴a ﹣1>0,∴a >1, 故选:B .12.【详解详析】设P 在右支上,设|PF 1|=m ,|PF 2|=n ,则m ﹣n =2a , 又因为sin∠PF 2F 1sin∠PF 1F 2=c a =m n ,可得c−a a=m−n n,所以2a n =c−a a,所以n =2a 2c−a >c ﹣a ,即c 2﹣2ac ﹣a 2<0,即e 2﹣2e ﹣1<0,解得1−√2<e <1+√2, 由于e >1,所以可得1<e <1+√2, 故选:A .二、填空题:本大题共4小题,每小题5分,共20分. 13.【详解详析】由约束条件{x −y +1≥0x +y −3≥0x −3≤0作出可行域如图,联立{x =3x −y +1=0,解得B (3,4).化目标函数z =x ﹣2y 为y =12x −12z ,由图可知,当直线y =12x −12z 过B (3,4)时,直线在y 轴上的截距最大,z 有最小值为:3﹣2×4=﹣5.故答案为:﹣5.14.【详解详析】圆M :(x ﹣1)2+y 2=1的圆心M (1,0),半径为1, AB 为圆M 的直径,可得MB →=−MA →, 椭圆C :x 2a 2+y 2a 2−1=1(a >1)的焦点为(﹣1,0),(1,0),则PA →⋅PB →=(PM →+MA →)•(PM →+MB →)=(PM →+MA →)•(PM →−MA →)=|PM →|2﹣|MA →|2=|PM →|2﹣1,又P 为椭圆上一点,M为椭圆的右焦点,可得|PM →|2﹣|MA →|2≤(a +c )2﹣1=15,当P 为椭圆的左顶点(﹣a ,0),上式取得等号, 则a +c =4,又c =1,可得a =3. 故答案为:3.15.【详解详析】(x +y +z )6表示6个因式(x +y +z )的乘积,其中有3个因式都取x ,得C 63⋅x 3,另外的三个因式取y 或z ,即可得到形如x 3y a z b (a ∈N ,B ∈N )的项. 而(y +z )3的各项系数和为23,故所有形如x 3y a z b (a ∈N ,B ∈N )的项的系数之和为C 63•23=160,故答案为:160. 16.【详解详析】f′(x)=−cosx sin 2x+8sinx cos 2x=8sin 3x−cos 3x (sinxcosx)2=(2sinx−cosx)(4sin 2x+2sinxcosx+cos 2x)(sinxcosx)2,由f ′(x )=0可得cos x =2sin x 即tan x =12, 又因为0<x <12π,根据导数与单调性的关系可知,当tan x =12时,函数取得最小值,此时sin x =5cos x =5,故f (x )min =5√5.故答案为:5√5.三、解答题:本大题共70分.解答应写出文字说明、证明过程或演算步骤. 17.【详解详析】(1)∵(a +b )(sin A ﹣sin B )=(c ﹣b )sin C . 由正弦定理可得:(a +b )(a ﹣b )=(c ﹣b )c . 化为b 2+c 2﹣a 2=bc , 由余弦定理可得:cos A =b 2+c 2−a 22bc=12,∵A ∈(0,π), ∴A =π3. (2)∵A =π3, ∴a 2=b 2+c 2﹣bc ≥(b+c)22−(b+c 2)2=(b+c)24,∴(b+c a)2≤4,∴b+c a≤2,可得b+c a的最大值为2,又b +c >a , ∴b+c a的取值范围为(1,2].18.【详解详析】(1)证明:(1)∵在平行六面体ABCD ﹣A 1B 1C 1D 1中,所有棱长均为2, ∴AD 1=AB 1=2,连结A 1C 1,B 1D 1,交于点O ,连结AO , ∵∠AA 1D 1=∠AA 1B 1=60°,∠D 1A 1B 1=90°.∴AO ⊥B 1D 1, ∵四边形A 1B 1C 1D 1为正方形,∴B 1D 1⊥A 1C 1, ∴B 1D 1⊥平面A 1ACC 1,∵A 1C ⊂平面A 1ACC 1,∴B 1D 1⊥A 1C .(2)解:在△AB 1D 1中,AO =√2,A 1O =√2,AA 1=2, ∴AO 2+A 1O 2=A 1A 2,∴AO ⊥A 1O , ∵AO ⊥B 1D 1,∴AO ⊥平面A 1B 1C 1D 1, ∴AO ⊥OC 1,∴AC 1=√AO 2+OC 12=2. (3)解:由(2)知AO ⊥平面A 1B 1C 1D 1,以点O 为原点,OA 1为x 轴,OB 1为y 轴,OA 为z 轴,建立空间直角坐标系, A (0,0,√2),B 1(0,√2,0),C 1(−√2,0,0), AB 1→=(0,√2,−√2),AC 1→=(−√2,0,−√2),设平面AB 1C 1的法向量m →=(x ,y ,z ),则{m →⋅AB 1→=√2y −√2z =0m →⋅AC 1→=−√2x −√2z =0,取x =1,得m →=(1,﹣1,﹣1), 平面AB 1D 1的法向量n →=(1,0,0), 设二面角C 1﹣AB 1﹣D 1的平面角为θ, 则cosθ=|m →⋅n →||m →|⋅|n →|=√3=√33, ∴二面角C 1﹣AB 1﹣D 1的平面角的余弦值为√33.19.【详解详析】(1)根据题意,双曲线的渐近线方程是y =±2x ,则设双曲线方程为:4x 2﹣y 2=λ,(λ≠0), 点(2,2)代入得:λ=12, 则双曲线方程为:4x 2﹣y 2=12, 即x 23−y 212=1,(2)∵F 1,F 2是双曲线x 23−y 212=1的左右焦点,过F 2作角的平分线AB 的垂线,垂足为P ,并且交AF 1于Q ,连接OP ,则OP =∥12F 1Q ,由角的平分线定理可得:|AQ |=|AF 2|,∴|F 1Q |=|AF 1|﹣|AQ |=|AF 1|﹣|AF 2|=2a ,∴|OP |=a =√3,由圆的定义可知,点P 的轨迹是以点O 为圆心,√3为半径的圆,所以P 的轨迹方程为:x 2+y 2=3.20.【详解详析】(1)函数的定义域(0,+∞),f′(x)=1x −a =1−ax x,(i )当a ≤0时,f ′(x )>0恒成立,f (x )在(0,+∞)上单调递增,(ii )当a >0时,由f ′(x )>0可得,0<x <1a ,此时函数单调递增,由f ′(x )<0可得,x >1a ,此时函数单调递减,(2)当x ≥1时,g (x )=(x +1)(lnx ﹣ax +a )﹣lnx =xlnx ﹣ax 2+a ,g ′(x )=lnx +1﹣2ax , 令h (x )=lnx +1﹣2ax ,则h ′(x )=1x −2a ,(i )当a ≤0时,h ′(x )>0恒成立,h (x )在[1,+∞)上单调递增,h (x )≥h (1)=1﹣2a >0, 即g ′(x )》0,故g (x )在[1,+∞)上单调递增,g (x )≥g (1)=0,不合题意;(ii )当0<a <12时,h (x )在[1,12a ]上单调递增,h (x )≥h (1)=1﹣2a >0,此时g (x )在[1,12a ]上单调递增,所以g (12a )>g (1)=0,不合题意;(iii )当a ≥12时,h ′(x )≤0,h (x )在[1,+∞)上单调递减,所以h (x )≤h (1)=1﹣2a <0,故g ′(x )≤0, 所以g (x )在[1,+∞)上单调递减,所以g (x )≤g (1)=0,所以g (x )≤0恒成立. 21.【详解详析】(1)由题意得ξ的取值为0,1,2, P (ξ=0)=23×23×23=827,P (ξ=1)=13×1×23+23×13×1+23×23×13=1627,P (ξ=2)=13×1×13=19, ∴ξ的分布列为: ξ 0 1 2 P827162719∴E (ξ)=0×827+1×1627+2×19=2227. (2)(i )由题意可知,a 1=0,a 2=13,a n =13(1−a n−1),n ≥2,∴a n −14=−13(a n−1−14),(n ≥2), ∴a n −14=(a 1−14)×(−13)n ﹣1, ∴a n =14−14×(−13)n−1.11 (ii )由(i )可知,当n →+∞时,a n →14, ∴当传球次数足够多时,球落在甲手上的概率趋向于一个常数14,又第一次从甲开始传球,而且每一次都是等可能地把球传给任何一个人,∴球落在每个人手上的概率都相等,∴球落在乙、丙、丁手上的概率为(1−14)÷3=14,∴随着传球的次数足够多,球落在甲、乙、丙、丁每个人手上的概率相等,都是14. 请考生在第22、23两题中任选一题作答.注意:只能做所选定的题目.如果多做,则按所做的第一个题目计分.[选修4-4:坐标系与参数方程]22.【详解详析】(1)直线l 的参数方程为 {x =1+t y =3+2t(t 为参数),消去参数,可得直线l 的普通方程y =2x +1,曲线C 的极坐标方程为ρ2=91+8sin 2θ,即8ρ2sin 2θ+ρ2=9,∴x 2+y 2+8y 2=9,∴曲线C 的直角坐标方程为x 29+y 2=1;(2)直线的参数方程改写为 {x =1+√55t y =3+2√55t(t 为参数), 代入x 29+y 2=1,375t 2√5t +73=0,t 1+t 2=−√5375,t 1t 2=73375, 1|PA|+1|PB|=|t 1−t 2t 1t 2|=√5×73=22√573. ∴当直线l 与曲线C 相交时,1|PA|+1|PB|=22√573. [选修4-5:不等式选讲]23.【详解详析】(1)f (x )=|x ﹣1|+|2x ﹣6=|x ﹣1|+|x ﹣3|+|x ﹣3|,f (x )表示数轴上的点到数轴上1,3,3对应点的距离之和.∴f (x )min =f (3)=2,∴c =2.(2)∵a +b =2,∴a 2a+1+b 2b+1=14[(a +1)+(b +1)](a 2a+1+b 2b+1); =14[a 2+b 2+(b+1)a 2a+1+(a+1)b 2b+1]≥14(a 2+b 2+2ab )=14(a +b )2=1;当且仅当{a +b =2(b+1)a 2a+1=(a+1)b 2b+1,即{a =1b =1时,有最小值1.。
湖南省雅礼中学2025届高三10月 月考语文试卷及答案

湖南省雅礼中学2025届高三10月月考语文试卷及答案一、现代文阅读(35分)(一)现代文阅读I(本题共5小题,19分)阅读下面的文字,完成下面小题。
自改革开放以来我国处于高速工业化进程之中,至今已完成向工业经济大国的转变。
新一轮科技革命和产业变革深入发展,在此形势之下,为扭转我国过早去工业化的倾向,推动新型工业化、信息化、城镇化和农业现代化协同发展是必由之路。
党的二十届三中全会指出,要加快推进新型工业化,培育壮大先进制造业集群,推动制造业高端化、智能化、绿色化发展。
不同于低效能传统工业化道路,新型工业化是以数字化和智能化为特征的工业化,是紧密结合中国实际发展情况与世界整体局势后所提出的概念。
新型工业化以高科技含量、优良经济效益、低资源消耗和环境污染为特点,充分发挥人力资源优势,为我国发展开辟出一条新的道路。
创新是引领发展的主要动力,数字战略则是构建新发展格局和推动我国经济高质量发展的重要手段。
“十二五”和“十三五”国家战略性新兴产业发展规划不断强调发展云计算、人工智能、大数据等新一代创新工程的重要作用。
数据作为新型生产要素,对传统生产方式的改革产生深远影响,数字资产价值将变得可量化、评估、交互,成为工业企业数字化转型的重要推动力。
随着技术应用场景的扩展,数字技术创新将继续深化,在中国特色社会主义工业化道路上产生多维度的影响。
以大数据、人工智能为代表的数字技术正在重塑甚至推翻原有的工业生产方式和组织形式,中高技术产业利润实现超高速增长,并且数字技术创新能够促进多个产业融合发展,有助于全要素生产率的提升。
数字技术概念首次提出时被定义为利用数字化技术和信息通信技术来高效处理、传输、储存和管理数据的一种技术。
数字技术创新具有智能化、高效化和可持续化的特点,是企业在数字经济时代的一种创新方式,其表现形式为利用或创造现有产品、服务、流程或企业商业模式,从而获得固有、无线和增值的新型事物,也有学者将其称为制造新产品或形成新服务,将数字化能力嵌入纯物理组件的活动,结合新型工业化的特征,数字技术创新通过三条路径赋能新型工业化发展。
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2021届湖南省长沙市雅礼中学高三第六次月考
文科综合试卷地理部分
(试题共39题;时量150分钟;分值300分)
(第一卷选择题部分共140分)
一.选择题(每题4分共140分)
某学校地理小组对地球某区域进行考察,(如图,其中AD线为晨昏线圈的某一段)他们在D点某日发现太阳从正北升起,据此完成1-3题。
1.此时,太阳直射点的地理坐标为
A.115ºW 、0º B.115ºW、23º26´N
C.0º 0º D.115ºE、23º26´S
2.此时与北京处于同一日期的范围占全球的
A.大于二分之一 B.小于二分之一
C.等于四分之三 D.等于三分之二
3.当C地与D地昼夜长短相同时,下列现象可能发生的是 A.华北平原正值小麦的种植期
B.巴西高原一片枯黄
C.莱茵河水量大增
D.长城站正处于极夜期
下图为某地等压线分布图,读图回答4—6题。
4.该图表示的时间可能是
A.1月 B.4月 C.7月D.10月
5.此时,图中P盛行
A.西南风 B.东南风
C.西北风D.东北风
6.下列关于此时P盛行风成因的叙述,正确的是
A.沿岸洋流的影响
B.气压带和风带位置的季节移动
C.城市人口集中产生的“热岛效应”
20ºE
C
B
D
0º
D.海陆热力性质的差异
下图是a,b,c,d 4种农产品产值百分比的扇面示意图,读图回答7一9题。
7.如果a,b,c,d分别代表我国某自然村的4种农产品(依次为乳产品、玉米、蔬菜、苹果)占该村农业总产值的比重,那么,影响该村农业地域类型的主要因素是
A.政策
B.市场
C.交通
D.气候
8.该自然村的位置可能在
A.杭州市附近
B.长春市附近
C.昆明市附近
D.西安市附近声
9.和该自然村距离较近的旅游景观是
A.浙江千岛湖
B.吉林雾淞
C.昆明世博园
D.西安秦陵兵马俑
读下列资料,回答10~11题。
为了加速我国繁荣的长江三角洲地区经济和社会的一体化进程,跨越整个杭州湾、全长36千米、6车道公路的我国内地第一座跨海斜拉大桥正在建设。
而奔涌了千百年、“壮观天下无”的钱江潮将不会因为世界第一跨海长桥的建设而受到影响。
大桥连接杭州湾南岸的宁波慈溪和北岸的嘉兴平湖,使宁波到上海的路程缩短120公里。
专家认为这将加速以上海为龙头的长三角国际级都市圈成形。
10.杭州湾跨海大桥的修建的要区位优势有
A.合理布局杭州湾地区的交通网,缓解杭州湾地区的运输紧张状况,促进“长三角”的发展
B.自然因素已不是现代交通运输线建设需考虑的因素
C.海域风浪小,海水对大桥的影响小
D.杭州湾水文地质条件单一
11.宋代时,杭州西湖上漂浮的架田(人们做成木架浮在水面,将木架里填满带泥的水草根,让水草生长纠结填满框架而成为人造耕地)。
一度使湖面越来越小,灌溉能力越来越小,甚至连市民生活用水也成问题。
因此,文学家苏东坡任杭州通判时,将架田挖起,堆积成今天的苏堤。
但是,开挖西湖并没有阻止架田在江南地区的发展,到了南宋时期,架田在江南已较为普遍。
原因是:
A.架田可以“随坡逐流”,便于人口迁徙
B.江南地区丘陵低山广,地形起伏大。
C.江南农业开发较早,水域面积广,人多地少,人地矛盾突出
D.为了开发西湖和“苏堤”样的旅游景观
(第二卷非选择题部分共160分)
二、非选择题部分(共160分)
36.读图,回答下列问题。
(I)图示①平原地区发展农业生产应注意的哪些问题,并分析
原因。
8分
(2)图中A是该地区特大城市之一,其名称是_。
试分析其发展
成为交通枢纽的原因和城市建设中面临的地质环境问题。
10分
(3)图示区域,水能资源十分丰富。
其中,甲、乙两阴影区被
称为水电的“富矿”。
乙地区与甲地区相比,发展水电的条件有何
差异?9分
(4)“天府”一词最早见于《周礼》,本是一种官名,其职责是“掌祖庙之守藏,与其禁令。
凡国之玉镇、大宝藏器焉,若有大祭大丧,则出而陈之,既事而藏之”。
可见,“天府”是专门保管国家珍宝、库藏的一种官吏,后人用以来比喻自然条件优越,形势险固,物产富饶的地方。
图②地所在地形区有“天府之国”的美誉,试从自然条件方面分析其形成的原因。
9分
39.阅读材料并回答问题。
材料三:区域图
(5)N河所在国南部新兴工业区是,与我国东部同纬度的河流比较,图中N河最突出的水文特征是什么?(8分)
(6)旅游业是A国重要的经济支柱之一,试分析该国旅游业发达的原因。
(12分)。