人教八上期中测试

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人教版八年级英语上册期中试卷(含答案)

人教版八年级英语上册期中试卷(含答案)

人教版八年级上册期中测试英语I . 听力 (共两节, 满分20分)第一节 (共5小题;每小题1分,满分5分)听下面5段对话。

每段对话后有一个小题,从题中所给的A、B、C三个选项中选出最佳选项。

听完每段对话后,你都有10秒钟的时间来回答有关小题和阅读下一小题。

每段对话读两遍。

1.Where did Tina go on vacation?A. Tianlang MountainB. The beach.C. The park.2. How often does Lily go swimming?A Usually. B. Often. C. Never.3. Who is the taller, Bob or Tom?A. Tom.B. Bob.C. Not mentioned(未提及).4. What makes the restaurant so popular near here?A. The best music.B. The worst service.C. The best service.5. What do they plan to do tonight?A. Watch a movie.B. Watch TV.C. Watch a video.第二节 (共15小题;每小题1分,满分15分)听下面6段对话或独白。

每段对话或独白后有几个小题,从题中所给的A、B、C三个选项中选出最佳选项。

听每段对话或独白前,你将有时间阅读各个小题,每小题5秒钟;听完后,各小题将给出5秒钟的作答时间。

每段对话或独白读两遍。

听第六段材料,回答第6、7题。

6. What's the relationship between the two speakers?A. Mother and son.B. Father and son.C. Teacher and student.7. What do Jack and David do after school?A Play sports. B. Read books. C. Play basketball.听第七段材料,回答第8、9题。

人教版数学八年级上学期《期中测试卷》含答案解析

人教版数学八年级上学期《期中测试卷》含答案解析
【答案】D
【解析】
【分析】
要熟悉三角形中的概念及其分类方法和三角形的内角和定理及其推论.
【详解】A、正确,符合线段的定义;
B、正确,符合三角形内角和定理;
C、正确;三角形的分类;
D、三角形的一个外角大于任何一个和它不相邻的内角,错误.
故选D.
【点睛】考查了三角形的高、中线、角平分线的概念;三角形的内角和定理及其推论;三角形的分类方法.
B. AOB、 BOC、 COA都是等腰三角形
C. OAB+ OBC+ OCA=
D.点O到AB、BC、CA的距离相等
8.如图 中, ,且 为 上一点.今打算在 上找一点 ,在 上找一点 ,使得 与 全等,以下是甲、乙两人的作法:
(甲)连接 ,作 的中垂线分别交 、 于 点、 点,则 、 两点即为所求
(乙)过 作与 平行的直线交 于 点,过 作与 平行的直线交 于 点,则 、 两点即为所求
对于甲、乙两人的作法,下列判断何者正确?( )
A. 两人皆正确B. 两人皆错误
C. 甲正确,乙错误D. 甲错误,乙正确
9.如图,己知在 中, ,点 是 边的中点,分别以 , 为圆心,大于线段 长度一半的长为半径作弧,两弧在直线 上方的交点为 ,直线 交 于点 ,连接 ,则下列结论:① ;② ;③ 平分 .其中一定正确的是()
1.现实世界中,对称现象无处不在,中国的方块字中有些也具有对称性,下列美术字是轴对称图形的是()
A.诚B.信C.友D.善
【答案】D
【解析】
【分析】
根据轴对称图形的概念逐一进行分析即可得.
【详解】A.不是轴对称图形,故不符合题意;
B.不是轴对称图形,故不符合题意;
C.不是轴对称图形,故不符合题意;

人教版八年级英语上册期中水平测试卷含答案

人教版八年级英语上册期中水平测试卷含答案

人教版八年级英语上册期中水平测试卷第一卷听力部分(共20分)一、情景反应(每小题1分,共5分)本题共5个小题,每小题你将听到一组对话。

请你从每小题所给的A、B、C三幅图片中,选出与你所听到的信息相关联的一项。

二、对话理解(每小题1分,共5分)本题共5个小题,每小题你将听到一组对话和一个问题。

请你从每小题所给的A、B、C三个选项中,选出一个最佳选项。

()6. A. Two. B. Three. C. Four.()7. A. B. C.()8. A. Once a week. B. Twice a week.C. Five times a week.()9. A. The best restaurant. B. The best clothes store.C. The best movie theater.()10. A. He can't stand the movie.B. He didn't see the movie.C. He loves the movie.三、语篇理解(每小题1分,共5分)本题你将听到一篇短文。

请你根据短文内容和所提出的5个问题,从每小题所给的A、B、C三个选项中,选出一个最佳选项。

()11. When did they make the survey?A. Last term.B. Last month.C. Last week. ()12. What's the topic of the survey?A. Ways of relaxing on weekends.B. Ways of learning English.C. Ways of relaxing after class.()13. What's the percentage of students who like reading?A. 10%.B. 20%.C. 30%.()14. How does Tony like to relax?A. By swimming.B. By reading and doing sports.C. By doing housework.()15. Why don't some students relax themselves?A. Because they are too lazy.B. Because they have no time.C. Because they have no money.四、听力填空(每小题1分,共5分)本题你将听到一篇短文。

人教版数学八年级上册期中测试题及答案

人教版数学八年级上册期中测试题及答案

人教版数学八年级上册期中测试题(时间:120分钟分值:150分)一、选择题(共9小题)1.(3分)如图,一面小红旗,其中∠A=60°,∠B=30°,则∠BCA=90°.求解的直接依据是()A.三角形内角和定理B.三角形外角和定理C.多边形内角和公式D.多边形外角和公式2.(3分)如图,在直角三角形ABC中,AC≠AB,AD是斜边上的高,DE⊥AC,DF⊥AB,垂足分别为E、F,则图中与∠C(∠C除外)相等的角的个数是()A.3个 B.4个 C.5个 D.6个3.(3分)如图,在△ABC中,∠C=90°,点D,E分别在边AC,AB上.若∠B=∠ADE,则下列结论正确的是()A.∠A和∠B互为补角 B.∠B和∠ADE互为补角C.∠A和∠ADE互为余角D.∠AED和∠DEB互为余角4.(3分)已知△ABC中,AB=6,BC=4,那么边AC的长可能是下列哪个值()A.11 B.5 C.2 D.15.如图,▱ABCD中,E,F是对角线BD上的两点,如果添加一个条件,使△ABE ≌△CDF,则添加的条件不能为()A.BE=DF B.BF=DE C.AE=CF D.∠1=∠26.如图,在方格纸中,以AB为一边作△ABP,使之与△ABC全等,从P1,P2,P3,P4四个点中找出符合条件的点P,则点P有()A.1个 B.2个 C.3个 D.4个7.如图,△ABC中,AB=AC,D是BC的中点,AC的垂直平分线分别交AC、AD、AB于点E、O、F,则图中全等三角形的对数是()A.1对 B.2对 C.3对 D.4对8.如图,已知∠ABC=∠DCB,下列所给条件不能证明△ABC≌△DCB的是()A.∠A=∠D B.AB=DC C.∠ACB=∠DBC D.AC=BD9.如图,在△ABC中,AB>AC,点D、E分别是边AB、AC的中点,点F在BC 边上,连接DE、DF、EF,则添加下列哪一个条件后,仍无法判断△FCE与△EDF 全等()。

完整版)人教版八年级英语上册期中测试题及答案

完整版)人教版八年级英语上册期中测试题及答案

完整版)人教版八年级英语上册期中测试题及答案人教版八年级英语上册期中测试题一、单项选择(15%)1.There is an “u” and a “s” in the word “bus”.2.It’s quite hot today。

Would you like to go swimming with me?3.How often do you visit your grandpa。

XXX.4.XXX.5.I find it easy to work out the problem.6.Although he isn’t tall。

he is strong.7.Could you tell us what to do next week?8.Kate was born on the night of November 11th.9.XXX.10.How long did it take them to go there by bus?11.Ted has a small number of interesting books.12.Thank you for inviting us to your birthday party.A。

MondayB。

XXXC。

XXXD。

XXX改写:Mr。

and Mrs。

Wang have a XXX instance。

XXX Sundays。

mistaking XXX。

XXX。

2.A。

driveB。

flyC。

walkD。

sail改写:During their summer n。

Mr。

and Mrs。

Wang planned to fly to New York。

3.A。

beforeB。

afterC。

whenD。

while改写:They arrived at the airport only ten minutes before the plane was led to take off。

人教版八年级语文上册期中试卷【含答案】

人教版八年级语文上册期中试卷【含答案】

人教版八年级语文上册期中试卷【含答案】专业课原理概述部分一、选择题1. 下列词语中,加点字的读音全都正确的一项是()A. 应和(hè)枯藤(téng)蓑衣(suō)镜匣(xiá)B. 狡黠(xiá)感慨(kǎi)哺育(bǔ)水泵(bèng)C. 拘束(jū)蜷缩(quán)摩挲(mā)静谧(mì)D. 侍候(shì)惬意(qiè)棱锥(léng)狡辩(biàn)()2. 下列句子中,加点成语使用不正确的一项是()A. 这篇文章生动形象,读来引人入胜,真是妙笔生花。

B. 桂花盛开,香飘十里,形容桂花的香气浓郁,是夸张的说法。

C. 他做事不拘小节,为人宽宏大量,从不斤斤计较。

D. 他的作品富有想象力,常常天马行空,让人难以捉摸。

()3. 下列句子中,没有语病的一项是()A. 通过这次活动,使我对语文产生了浓厚的兴趣。

B. 他穿着一件灰色上衣,戴着一顶蓝色帽子。

C. 这部电影讲述了一个关于勇气和友谊的故事。

D. 老师告诉我们,努力学习是取得好成绩的关键。

()4. 下列句子中,加点词语的感情色彩不正确的一项是()A. 他勤奋好学,品学兼优,深受老师和同学们的喜爱。

B. 他粗心大意,做事马虎,让人十分头疼。

C. 他聪明机智,思维敏捷,是大家学习的榜样。

D. 他自私自利,从不考虑别人的感受,让人十分讨厌。

()5. 下列句子中,加点词语的用法不正确的一项是()A. 雪花飘落在地上,像一层薄薄的绒毯。

B. 他的笑声如同春风,让人感到温暖。

C. 那座山高耸入云,宛如巨人屹立。

D. 他的眼睛像星星一样闪烁,充满了智慧。

()二、判断题1. 《背影》的作者是朱自清。

()2. “落霞与孤鹜齐飞,秋水共长天一色”出自王勃的《滕王阁序》。

()3. “不以规矩,不能成方圆”出自《论语》。

()4. 《骆驼祥子》是老舍的代表作之一。

人教版八年级英语上册期中综合测试卷含答案

人教版八年级英语上册期中综合测试卷含答案

人教版八年级英语上册期中综合测试卷(限时:120分钟满分:120分)第一部分听力(共四大题, 满分20 分)I. 短对话理解(共5 小题;每小题1 分,满分5 分)你将听到五段对话, 每段对话后有一个小题。

请在每小题所给的A、B、C 三个选项中选出一个最佳选项。

每段对话读两遍。

( )1. What subject is Mark good at?A. B. C.( )2. What does the boy plan to do tonight?A. B. C.( )3. What will Tony wear to the beach?A. Pants.B. Jeans.C. Shorts.( )4. Where is the Chinese restaurant?A. In front of the office.B. Behind the office.C. Near the post office.( )5. What is Peter like?A. He’s funny.B. He’s qui et.C. He’s smart.II. 长对话理解(共5 小题;每小题1 分,满分5 分)你将听到两段对话, 每段对话后有几个小题。

请在每小题所给的A、B、C 三个选项中选出一个最佳选项。

每段对话读两遍。

听下面一段对话, 回答第6、7 题。

( )6. What did Wang Hongxiang do in a TV show?A. He sang a Chinese song.B. He performed swing dance.C. He performed Beijing Opera.( )7. Where does Wang live now?A. In Australia.B. In Canada.C. In China.听下面一段对话,回答第8 至10 题。

( )8. How old is Grace?A. 14.B. 15.C. 16.( )9. What’s the difference between Grace and Alice?A. Grace is thinner than Alice.B. Grace is smarter than Alice.C. Grace is more hard-working than Alice.( )10. What sport does Alice like?A. Swimming.B. Basketball.C. Baseball.III. 短文理解(共5 小题;每小题1 分,满分5 分)你将听到一篇短文, 短文后有五个小题。

人教版八年级上学期期中考试数学试卷及答案解析(共六套)

人教版八年级上学期期中考试数学试卷及答案解析(共六套)

人教版八年级上学期期中考试数学试卷(一)一、选择题(本题共30分,每小题3分,下列各题均有四个选项,其中只有一个是符合题意的)1.图中的两个三角形全等,则∠α=()A.72°B.60°C.58°D.50°2.下列条件中,不能判定三角形全等的是()A.三条边对应相等B.两边和其中一角对应相等C.两边和夹角对应相等D.两角和它们的夹边对应相等3.下列各式从左到右的变形中,是因式分解的为()A.x(a﹣b)=ax﹣bx B.x2﹣1+y2=(x﹣1)(x+1)+y2C.x2﹣1=(x+1)(x﹣1) D.ax+bx+c=x(a+b)+c4.下列各式中,正确的是()A.B.C. =D.5.若分式的值为0,则x应满足的条件是()A.x=﹣2 B.x=2 C.x≠﹣2 D.x=±26.下列各分式中,最简分式是()A.B.C.D.7.若x2﹣2(m﹣3)x+16是完全平方式,则m的值等于()A.﹣1 B.7 C.7或﹣7 D.7或﹣18.如图,P是∠BAC的平分线AD上一点,PE⊥AB于E,PF⊥AC于F,下列结论中不正确的是()A.PE=PF B.AE=AF C.△APE≌△APF D.AP=PE+PF9.已知:三角形的两边长分别为3和7,则第三边的中线长x的取值范围是()A.2<x<5 B.4<x<10 C.3<x<7 D.无法确定10.如图,在△ABC中,AD是它的角平分线,AB=8cm,AC=6cm,则S△ABD :S△ACD=()A.3:4 B.4:3 C.16:9 D.9:16二、填空题(本题共16分,每小题2分)11.计算:3﹣2= .12.若(x﹣2)0有意义,则x的取值范围是.13.分解因式:x2+x﹣2= .14.如图,亮亮书上的三角形被墨迹污染了一部分,他根据所学的知识很快就画出了一个与书上完全一样的三角形,那么亮亮画图的依据是.15.如图,AC、BD相交于点O,∠A=∠D,请你再补充一个条件,使得△AOB≌△DOC,你补充的条件是.16.在△ABC中,∠C=90°,BC=4cm,∠BAC的平分线交BC于D,且BD:DC=5:3,则D到AB的距离为 cm.17.若x2+4x+1=0,则x2+= .18.请同学们观察 22﹣2=2(2﹣1)=2,23﹣22=22(2﹣1)=22,24﹣23=23(2﹣1)=23…(1)写出表示一般规律的第n个等式;(2)根据所总结的规律计算210﹣29﹣28﹣…﹣22﹣2= .三、解答题(本题共54分)19.(5分)请你阅读下列计算过程,再回答所提出的问题:解:=(A)=(B)=x﹣3﹣3(x+1)(C)=﹣2x﹣6(D)(1)上述计算过程中,从哪一步开始出现错误:;(2)从B到C是否正确,若不正确,错误的原因是;(3)请你正确解答.20.(2分)尺规画图(不用写作法,要保留作图痕迹)如图1,在一次军事演习中,红方侦察员发现蓝方指挥部在A区内,到铁路与到公路的距离相等,且离铁路与公路交叉处B点400米,如果你是红方的指挥员,请你在图2所示的作战图上标出蓝方指挥部的位置点P.21.(6分)分解下列因式:(1)9a2﹣1(2)p3﹣16p2+64p.22.(7分)计算(1)﹣.(2)()﹣1+(﹣1)+(2﹣)0+|﹣3|.23.(5分)先化简,再求值:,其中x=5.24.(5分)解分式方程:.25.(4分)已知:如图,AB=AC,AD=AE,∠1=∠2.求证:△ABD≌△ACE.26.(4分)已知:如图,AB⊥BD,CD⊥BD,AD=BC.求证:(1)AB=DC.(2)AD∥BC.27.(4分)在△AFD和△BEC中,点A、E、F、C在同一直线上,有下面四个论断:(1)AD=CB;(2)AE=CF;(3)∠B=∠D;(4)AD∥BC.请用其中三个作为条件,余下一个作为结论,编一道数学问题,并写出证明过程.28.(4分)若x2+y2﹣4x+2y+5=0,求()2010+y2010的值.29.(4分)已知:正方形ABCD中,∠MAN=45°,∠MAN绕点A顺时针旋转,它的两边分别交CB、DC(或它们的延长线)于点M、N.(1)如图1,当∠MAN绕点A旋转到BM=DN时,有BM+DN=MN.当∠MAN绕点A 旋转到BM≠DN时,如图2,请问图1中的结论还是否成立?如果成立,请给予证明,如果不成立,请说明理由;(2)当∠MAN绕点A旋转到如图3的位置时,线段BM,DN和MN之间有怎样的等量关系?请写出你的猜想,并证明.30.(4分)已知:在△ABC中,∠ABC=100°,∠C的平分线交AB边于点E,在AC边上取点D,使得∠CBD=20°,连结DE.求∠CED的度数.参考答案与试题解析一、选择题(本题共30分,每小题3分,下列各题均有四个选项,其中只有一个是符合题意的)1.图中的两个三角形全等,则∠α=()A.72°B.60°C.58°D.50°【考点】KA:全等三角形的性质.【分析】根据全等三角形对应角相等解答即可.【解答】解:∵两个三角形全等,∴α=58°.故选C.【点评】本题考查了全等三角形的性质,熟记性质并准确识图,确定出对应角是解题的关键.2.下列条件中,不能判定三角形全等的是()A.三条边对应相等B.两边和其中一角对应相等C.两边和夹角对应相等D.两角和它们的夹边对应相等【考点】KB:全等三角形的判定.【分析】根据全等三角形的判定定理逐个判断即可.【解答】解:A、符合全等三角形的判定定理SSS,能推出两三角形全等,故本选项不符合题意;B、不符合全等三角形的判定定理,不能推出两三角形全等,故本选项符合题意;C、符合全等三角形的判定定理SAS,能推出两三角形全等,故本选项不符合题意;D、符合全等三角形的判定定理ASA,能推出两三角形全等,故本选项不符合;故选B.【点评】本题考查了全等三角形的判定定理,能熟记全等三角形的判定定理是解此题的关键,注意:全等三角形的判定定理有SAS,ASA,AAS,SSS.3.下列各式从左到右的变形中,是因式分解的为()A.x(a﹣b)=ax﹣bx B.x2﹣1+y2=(x﹣1)(x+1)+y2C.x2﹣1=(x+1)(x﹣1) D.ax+bx+c=x(a+b)+c【考点】51:因式分解的意义.【分析】根据因式分解的定义作答.把一个多项式化成几个整式的积的形式,叫做把这个多项式因式分解,也叫做把这个多项式分解因式.【解答】解:A、是整式的乘法运算,故选项错误;B、结果不是积的形式,故选项错误;C、x2﹣1=(x+1)(x﹣1),正确;D、结果不是积的形式,故选项错误.故选:C.【点评】熟练地掌握因式分解的定义,明确因式分解的结果应是整式的积的形式.4.下列各式中,正确的是()A.B.C. =D.【考点】65:分式的基本性质.【分析】利用分式的基本性质对各式进行化简即可.【解答】解:A、已经是最简分式,故本选项错误;B、,故本选项错误;C、=,故本选项错误;D、利用分式的基本性质在分式的分子与分母上同时乘以x+y即可得到,故本选项正确;故选D.【点评】本题考查了分式的基本性质,解题的关键是在进行分式的运算时要同时乘除.5.若分式的值为0,则x应满足的条件是()A.x=﹣2 B.x=2 C.x≠﹣2 D.x=±2【考点】63:分式的值为零的条件.【分析】根据分式值为0的条件可得x2﹣4=0且x+2≠0,再解出x的值即可.【解答】解:由题意得:x2﹣4=0且x+2≠0,解得:x=2.故选:B.【点评】此题主要考查了分式的值为零的条件,分式值为零的条件是分子等于零且分母不等于零.6.下列各分式中,最简分式是()A.B.C.D.【考点】68:最简分式.【分析】最简分式是指分子和分母没有公因式.【解答】解:(A)原式=,故A不是最简分式;(B)原式==,故B不是最简分式;(C)原式=,故C是最简分式;(D)原式==,故D不是最简分式;故选(C)【点评】本题考查考查最简分式,要注意将分子分母先分解后,约去公因式.7.若x2﹣2(m﹣3)x+16是完全平方式,则m的值等于()A.﹣1 B.7 C.7或﹣7 D.7或﹣1【考点】4E:完全平方式.【分析】这里首末两项是x和4这两个数的平方,那么中间一项为加上或减去x 和4积的2倍.【解答】解:依题意,得m﹣3=±4,解得m=7或﹣1.故选D.【点评】本题是完全平方公式的应用;两数的平方和,再加上或减去它们积的2倍,就构成了一个完全平方式.注意积的2倍的符号,避免漏解.8.如图,P是∠BAC的平分线AD上一点,PE⊥AB于E,PF⊥AC于F,下列结论中不正确的是()A.PE=PF B.AE=AF C.△APE≌△APF D.AP=PE+PF【考点】KF:角平分线的性质.【分析】题目的已知条件比较充分,满足了角平分线的性质要求的条件,可直接应用性质得到结论,与各选项进行比对,得出答案.【解答】解:∵P是∠BAC的平分线AD上一点,PE⊥AB于E,PF⊥AC于F,∴PE=PF,又有AD=AD∴△APE≌△APF(HL∴AE=AF故选D.【点评】本题主要考查平分线的性质,由已知证明△APE≌△APF是解题的关键.9.已知:三角形的两边长分别为3和7,则第三边的中线长x的取值范围是()A.2<x<5 B.4<x<10 C.3<x<7 D.无法确定【考点】K6:三角形三边关系;K2:三角形的角平分线、中线和高.【分析】根据三角形的三边关系:两边之和大于第三边,两边之差小于第三边.倍长中线,构造一个新的三角形.根据三角形的三边关系就可以求解.【解答】解:7﹣3<2x<7+3,即2<x<5.故选A.【点评】本题主要考查了三角形的三边关系,注意此题构造了一条常见的辅助线:倍长中线.10.如图,在△ABC中,AD是它的角平分线,AB=8cm,AC=6cm,则S△ABD :S△ACD=()A.3:4 B.4:3 C.16:9 D.9:16【考点】K3:三角形的面积.【分析】利用角平分线的性质,可得出△ABD的边AB上的高与△ACD的AC上的高相等,估计三角形的面积公式,即可得出△ABD与△ACD的面积之比等于对应边之比.【解答】解:∵AD是△ABC的角平分线,∴设△ABD的边AB上的高与△ACD的AC上的高分别为h1,h2,∴h1=h2,∴△ABD与△ACD的面积之比=AB:AC=8:6=4:3,故选:B.【点评】本题考查了角平分线的性质,以及三角形的面积公式,熟练掌握三角形角平分线的性质是解题的关键.二、填空题(本题共16分,每小题2分)11.计算:3﹣2= .【考点】6F:负整数指数幂.【分析】根据负整数指数为正整数指数的倒数计算.【解答】解:3﹣2=.故答案为.【点评】本题主要考查了负指数幂的运算,比较简单.12.若(x﹣2)0有意义,则x的取值范围是x≠2 .【考点】6E:零指数幂.【分析】根据非零的零次幂等于1,可得答案.【解答】解:由题意,得x﹣2≠0,解得x≠2,故答案为:x≠2.【点评】本题考查了零指数幂,利用非零的零次幂等于1是解题关键.13.分解因式:x2+x﹣2= (x﹣1)(x+2).【考点】57:因式分解﹣十字相乘法等.【分析】因为(﹣1)×2=﹣2,2﹣1=1,所以利用十字相乘法分解因式即可.【解答】解:∵(﹣1)×2=﹣2,2﹣1=1,∴x2+x﹣2=(x﹣1)(x+2).故答案为:(x﹣1)(x+2).【点评】本题考查的是十字相乘法分解因式,运用十字相乘法分解因式时,要注意观察,尝试,并体会它实质是二项式乘法的逆过程.14.如图,亮亮书上的三角形被墨迹污染了一部分,他根据所学的知识很快就画出了一个与书上完全一样的三角形,那么亮亮画图的依据是两角和它们的夹边分别相等的两个三角形全等.【考点】KE:全等三角形的应用.【分析】根据图象,三角形有两角和它们的夹边是完整的,所以可以根据“角边角”画出即可.【解答】解:根据题意,三角形的两角和它们的夹边是完整的,所以可以利用“角边角”定理作出完全一样的三角形.故答案为:两角和它们的夹边分别相等的两个三角形全等.【点评】本题考查了三角形全等的判定的实际运用,熟练掌握判定定理:两角及其夹边分别对应相等的两个三角形全等是解题的关键.15.如图,AC、BD相交于点O,∠A=∠D,请你再补充一个条件,使得△AOB≌△DOC,你补充的条件是AO=DO或AB=DC或BO=CO .【考点】KB:全等三角形的判定.【分析】本题要判定△AOB≌△DOC,已知∠A=∠D,∠AOB=∠DOC,则可以添加AO=DO或AB=DC或BO=CO从而利用ASA或AAS判定其全等.【解答】解:添加AO=DO或AB=DC或BO=CO后可分别根据ASA、AAS、AAS判定△AOB≌△DOC.故填AO=DO或AB=DC或BO=CO.【点评】本题考查三角形全等的判定方法,判定两个三角形全等的一般方法有:SSS、SAS、ASA、AAS、HL.添加时注意:AAA、SSA不能判定两个三角形全等,判定两个三角形全等时,必须有边的参与,若有两边一角对应相等时,角必须是两边的夹角.16.在△ABC中,∠C=90°,BC=4cm,∠BAC的平分线交BC于D,且BD:DC=5:3,则D到AB的距离为 1.5 cm.【考点】KF:角平分线的性质.【分析】作出图形,过点D作DE⊥AB于E,先求出CD的长,再根据角平分线上的点到角的两边的距离相等可得DE=CD解答.【解答】解:如图,过点D作DE⊥AB于E,∵BC=4cm,BD:DC=5:3,∴CD=×4=1.5cm,∵AD是∠BAC的平分线,∴DE=CD=1.5cm.故答案为:1.5.【点评】本题考查了角平分线上的点到角的两边的距离相等的性质,熟记性质是解题的关键,作出图形更形象直观.17.若x2+4x+1=0,则x2+= 14 .【考点】4C:完全平方公式.【分析】由x2+4x+1=0可得x≠0,两边除以x可得到x+=﹣4,再两边平方,根据完全平方公式展开即可得到x2+的值.【解答】解:∵x2+4x+1=0,∴x+4+=0,即x+=﹣4,∴(x+)2=(﹣4)2,∴x2+2+=16,∴x2+=14.故答案为14.【点评】本题考查了完全平方公式:(a±b)2=a2±2ab+b2.也考查了代数式的变形能力.18.请同学们观察 22﹣2=2(2﹣1)=2,23﹣22=22(2﹣1)=22,24﹣23=23(2﹣1)=23…(1)写出表示一般规律的第n个等式2n+1﹣2n=2n;(2)根据所总结的规律计算210﹣29﹣28﹣…﹣22﹣2= 2 .【考点】37:规律型:数字的变化类.【分析】(1)根据等式的变化找出变化规律“第n个等式为2n+1﹣2n=2n”,此题得解;(2)根据2n=2n+1﹣2n将算式210﹣29﹣28﹣…﹣22﹣2进行拆项,合并同类项即可得出结论.【解答】解:(1)观察,发现规律:22﹣2=2(2﹣1)=2,23﹣22=22(2﹣1)=22,24﹣23=23(2﹣1)=23,…,∴第n个等式为2n+1﹣2n=2n.故答案为:2n+1﹣2n=2n.(2)∵2n=2n+1﹣2n,∴210﹣29﹣28﹣…﹣22﹣2=210﹣210+29﹣29+28﹣28+27﹣…﹣23+22﹣2=22﹣2=2.故答案为:2.【点评】本题考查了规律型中数字的变化类,根据等式的变化找出变化规律是解题的关键.三、解答题(本题共54分)19.请你阅读下列计算过程,再回答所提出的问题:解:=(A)=(B)=x﹣3﹣3(x+1)(C)=﹣2x﹣6(D)(1)上述计算过程中,从哪一步开始出现错误: A ;(2)从B到C是否正确,若不正确,错误的原因是不能去分母;(3)请你正确解答.【考点】6B:分式的加减法.【分析】异分母分式相加减,先化为同分母分式,再加减.【解答】解:===,(1)故可知从A开始出现错误;(2)不正确,不能去分母;(3)===.【点评】本题考查异分母分式相加减.应先通分,化为同分母分式,再加减.本题需注意应先把能因式分解的分母因式分解,在计算过程中,分母不变,只把分子相加减.20.尺规画图(不用写作法,要保留作图痕迹)如图1,在一次军事演习中,红方侦察员发现蓝方指挥部在A区内,到铁路与到公路的距离相等,且离铁路与公路交叉处B点400米,如果你是红方的指挥员,请你在图2所示的作战图上标出蓝方指挥部的位置点P.【考点】N4:作图—应用与设计作图;KF:角平分线的性质.【分析】作出角平分线,进而截取PB=400进而得出答案.【解答】解:如图所示:P点即为所求.【点评】此题主要考查了应用设计与作图,正确掌握角平分线的性质是解题关键.21.分解下列因式:(1)9a2﹣1(2)p3﹣16p2+64p.【考点】55:提公因式法与公式法的综合运用.【分析】(1)原式利用平方差公式分解即可;(2)原式提取公因式,再利用完全平方公式分解即可.【解答】解:(1)原式=(3a+1)(3a﹣1);(2)原式=p(p2﹣16p+64)=p(p﹣8)2.【点评】此题考查了提公因式法与公式法的综合运用,熟练掌握因式分解的方法是解本题的关键.22.计算(1)﹣.(2)()﹣1+(﹣1)+(2﹣)0+|﹣3|.【考点】6B:分式的加减法;2C:实数的运算;6E:零指数幂;6F:负整数指数幂.【分析】(1)直接利用分式加减运算法则化简求出答案;(2)直接利用负指数幂的性质以及零指数幂的性质以及绝对值的性质分别化简求出答案.【解答】解:(1)原式===;(2)原式=2﹣1+1+3=5.【点评】此题主要考查了分式得加减运算以及实数运算,正确掌握运算法则是解题关键.23.先化简,再求值:,其中x=5.【考点】6D:分式的化简求值.【分析】把原式的第二项被除式分母及除式分母都分解因式,然后利用除以一个数等于乘以这个数的倒数把除法运算化为乘法运算,约分后,再与第一项通分,利用同分母分式的减法运算计算,可化为最简,最后把x的值代入化简的式子中即可求出值.【解答】解:==﹣=﹣===,(4分)当x=5时,原式==.(5分)【点评】此题考查了分式的化简求值,分式的化简求值时,加减的关键是通分,通分的关键是找出各分母的最简公分母,分式的乘除关键是约分,约分的关键是找出公因式,本题属于化简求值题,解答此类题要先将原式化为最简,再代值,同时注意有时计算后还能约分,比如本题倒数第二步约去公因式x+1.24.解分式方程:.【考点】B3:解分式方程;86:解一元一次方程.【分析】方程的两边都乘以5(x+1),把分式方程转化成整式方程,求出方程的解,再代入方程进行检验即可.【解答】解:方程的两边都乘以5(x+1)、去分母得:5x=2x+5x+5,移项、合并同类项得:2x=﹣5,∴系数化成1得:x=﹣,经检验x=﹣是原方程的解,∴原方程的解是x=﹣.【点评】本题考查了分式方程的解法,关键是把分式方程转化成整式方程,注意一定要检验.25.已知:如图,AB=AC,AD=AE,∠1=∠2.求证:△ABD≌△ACE.【考点】KB:全等三角形的判定.【分析】首先得出∠EAC=∠BAD,进而利用全等三角形的判定方法(SAS)得出即可.【解答】证明:∵∠1=∠2,∴∠EAC=∠BAD,在△DAB和△EAC中,∴△ABD≌△ACE(SAS)【点评】此题主要考查了全等三角形的判定,正确应用全等三角形的判定方法是解题关键.26.已知:如图,AB⊥BD,CD⊥BD,AD=BC.求证:(1)AB=DC.(2)AD∥BC.【考点】KD:全等三角形的判定与性质.【分析】(1)易证△ABD≌△CDB,根据全等三角形的对应边相等知AB=DC;(2)因为△ABD≌△CDB,所以全等三角形的对应角∠ADB=∠CBD.然后由平行线的判定定理知AD∥BC.【解答】证明:(1)∵AB⊥BD,CD⊥BD,∴∠ABD=∠CDB=90°,∴在Rt△ABD和Rt△CDB中,,∴Rt△ABD≌Rt△CDB(HL),∴AB=DC(全等三角形的对应边相等);(2)∵Rt△ABD≌Rt△CDB[由(1)知],∴∠ADB=∠CBD(全等三角形的对应角相等),∴AD∥BC(内错角相等,两直线平行).【点评】本题考查了全等三角形的判定与性质.判定两个三角形全等的一般方法有:SSS、SAS、ASA、AAS、HL.以及三角形全等的性质:全等三角形的对应边、对应角相等.27.在△AFD和△BEC中,点A、E、F、C在同一直线上,有下面四个论断:(1)AD=CB;(2)AE=CF;(3)∠B=∠D;(4)AD∥BC.请用其中三个作为条件,余下一个作为结论,编一道数学问题,并写出证明过程.【考点】KD:全等三角形的判定与性质.【分析】只要以其中三个作为条件,能够得出另一个结论正确即可,下边以(1)、(2)、(4)为条件,(3)为结论为例.【解答】解:以(1)、(2)、(4)为条件,(3)为结论.证明:∵AE=CF,∴AF=CE,∵AD∥BC,∴∠A=∠C,又AD=BC,∴△ADF≌△CBE(SAS),∴∠B=∠D.【点评】本题与命题联系在一起,归根到底主要还是考查了全等三角形的判定及性质问题,应熟练掌握.28.若x2+y2﹣4x+2y+5=0,求()2010+y2010的值.【考点】AE:配方法的应用;1F:非负数的性质:偶次方.【分析】根据x2+y2﹣4x+2y+5=0,可以求得x、y的值,从而可以求得所求式子的值.【解答】解:∵x2+y2﹣4x+2y+5=0,∴x2﹣4x+4+y2+2y+1=0,∴(x﹣2)2+(y+1)2=0,∴x﹣2=0,y+1=0,解得,x=2,y=﹣1,∴()2010+y2010==1+1=2.【点评】本题考查配方法的应用、非负数的性质,解题的关键是明确题意,找出所求问题需要的条件.29.已知:正方形ABCD中,∠MAN=45°,∠MAN绕点A顺时针旋转,它的两边分别交CB、DC(或它们的延长线)于点M、N.(1)如图1,当∠MAN绕点A旋转到BM=DN时,有BM+DN=MN.当∠MAN绕点A旋转到BM≠DN时,如图2,请问图1中的结论还是否成立?如果成立,请给予证明,如果不成立,请说明理由;(2)当∠MAN绕点A旋转到如图3的位置时,线段BM,DN和MN之间有怎样的等量关系?请写出你的猜想,并证明.【考点】LE:正方形的性质;KD:全等三角形的判定与性质;R2:旋转的性质.【分析】(1)在MB的延长线上截取BE=DN,连接AE,根据正方形性质得出AD=AB,∠D=∠DAB=∠ABC=∠ABE=90°,证△ABE≌△ADN推出AE=AN;∠EAB=∠NAD,求出∠EAM=∠MAN,根据SAS证△AEM≌△ANM,推出ME=MN即可;(2)在DN上截取DE=MB,连接AE,证△ABM≌△ADE,推出AM=AE;∠MAB=∠EAD,求出∠EAN=∠MAN,根据SAS证△AMN≌△AEN,推出MN=EN即可.【解答】解:(1)图1中的结论仍然成立,即BM+DN=MN,理由为:如图2,在MB的延长线上截取BE=DN,连接AE,∵四边形ABCD是正方形,∴AD=AB,∠D=∠DAB=∠ABC=∠ABE=90°,∵在△ABE和△ADN中,∴△ABE≌△ADN(SAS).∴AE=AN;∠EAB=∠NAD,∵∠DAB=90°,∠MAN=45°,∴∠DAN+∠BAM=45°,∴∠EAM=∠BAM+∠EAB=45°=∠MAN,∵在△AEM和△ANM中,∴△AEM≌△ANM(SAS),∴ME=MN,∴MN=ME=BE+BM=DN+BM,即DN+BM=MN;(2)猜想:线段BM,DN和MN之间的等量关系为:DN﹣BM=MN.证明:如图3,在DN上截取DE=MB,连接AE,∵由(1)知:AD=AB,∠D=∠ABM=90°,BM=DE,∴△ABM≌△ADE(SAS).∴AM=AE;∠MAB=∠EAD,∵∠MAN=45°=∠MAB+∠BAN,∴∠DAE+∠BAN=45°,∴∠EAN=90°﹣45°=45°=∠MAN,∵在△AMN和△AEN中,∴△AMN≌△AEN(SAS),∴MN=EN,∵DN﹣DE=EN,∴DN﹣BM=MN.【点评】本题考查了正方形性质和全等三角形的性质和判定的应用,题目具有一定的代表性,是一道比较好的题目,证明过程类似,培养了学生的猜想能力和分析归纳能力.30.已知:在△ABC中,∠ABC=100°,∠C的平分线交AB边于点E,在AC边上取点D,使得∠CBD=20°,连结DE.求∠CED的度数.【考点】KD:全等三角形的判定与性质;KF:角平分线的性质.【分析】分别作EF⊥CB的延长线于F,EH⊥AC于H,EG⊥BD于G.利用CE是角平分线,角平分线的性质定理,得EF=EH,再证明∠ABD=∠EBF,同理可证:EF=EG,根据HL证明Rt△EDH≌Rt△EDG,根据全等三角形的性质和角的和差关系可求∠CED.【解答】解:分别作EF⊥CB的延长线于F,EH⊥AC于H,EG⊥BD于G.∵CE是角平分线,∴EF=EH.∠ABC=100°,∠DBC=20°,∴∠ABD=80°,又∵∠EBF=80°,∴∠ABD=∠EBF,∴EF=EG,∴EH=EG,在Rt△EDH与Rt△EDG中,,∴Rt△EDH≌Rt△EDG(HL),∴∠EDH=∠EDG,∴∠CED=∠EDH﹣∠ECD=(∠BDH﹣∠BCA)=×20°=10°.【点评】本题考查了全等三角形的判定与性质,角的平分线的性质定理和逆定理,本题的关键是作出辅助线,以及角的平分线性质定理的应用.人教版八年级上学期期中考试数学试卷(二)一、精心选一选(每小题3分,共30分)1.计算(﹣)﹣3的结果是()A.﹣B.﹣C.﹣343 D.﹣212.将,(﹣2)0,(﹣3)2这三个数按从小到大的顺序排列,正确的结果是()A.(﹣2)0<<(﹣3)2B.<(﹣2)0<(﹣3)2C.(﹣3)2<(﹣2)0<D.(﹣2)0<(﹣3)2<3.下列各式中,从左到右的变形是因式分解的是()A.a2﹣4ab+4b2=(a﹣2b)2 B.x2﹣xy2﹣1=xy(x﹣y)﹣1C.(x+2y)(x﹣2y)=x2﹣4y2D.ax+ay+a=a(x+y)4.如图所示,AB=AC,要说明△ADC≌△AEB,需添加的条件不能是()A.∠B=∠C B.AD=AE C.∠ADC=∠AEB D.DC=BE5.在下列图案中,不是轴对称图形的是()A.B.C.D.6.如图,若OP平分∠AOB,PC⊥OA,PD⊥OB,垂足分别是C、D,则下列结论中错误的是()A.PC=PD B.OC=PC C.∠CPO=∠DPO D.OC=OD7.下列等式成立的是()A.B.C.D.8.如图,△ABC≌△BAD,点A和点B,点C和点D是对应点,如果AB=6cm,BD=5cm,AD=4cm,那么BC的长是()A.4 B.5 C.6 D.无法确定9.如图,正方形ABCD的边长为4,将一个足够大的直角三角板的直角顶点放于点A处,该三角形板的两条直角边与CD交于点F,与CB延长线交于点E,四边形AECF的面积是()A.16 B.12 C.8 D.410.如图,将一张正方形纸片经两次对折,并剪出一个菱形小洞后展开铺平,得到的图形是()A.B.C.D.二.细心填一填(每小题2分,共20分)11.一种细菌的半径为0.000407m,用科学记数法表示为m.12.当x= 时,分式没有意义;当x= 时,分式的值为0.13.计算(﹣)3÷(﹣)2的结果是.14.计算+的结果是.15.若x2+mx+16是完全平方式,则m= .16.如图,在△ABC和△DEF 中,AB=DE,AC=DF.请再添加一个条件,使△ABC 和△DFE全等.添加的条件是(填写一个即可):,理由是.17.如图,把△ABC绕C点顺时针旋转30°,得到△A′B′C,A′B′交AC于点D,若∠A′DC=80°,则∠A=°.18.如图,在△ABC中,∠C=90°,AD平分∠CAB,BC=8cm,BD=5cm,那么点D 到线段AB的距离是cm.19.如图,△ABC中,AB=AC,AB的垂直平分线交AC于P点.(1)若∠A=35°,则∠BPC=;(2)若AB=5cm,BC=3cm,则△PBC的周长= .20.探究:观察下列各式,,,…请你根据以上式子的规律填写: = ;= .三.精心解一解:(21,22每小题2分,23,24,25每小题2分,共16分)21.因式分解:2mx2﹣4mx+2m= .22.因式分解:x2y﹣9y= .23.化简:﹣+.24.先化简,再求值:(1﹣)÷,其中x=2.25.解分式方程:四.耐心想一想:(本小题4分)26.四川5.12特大地震受灾地区急需大量赈灾帐篷,某帐篷生产企业接到生产任务后,加大生产投入,提高生产效率,实际每天生产帐篷比原计划多200顶,已知现在生产3000顶帐篷所用的时间与原计划生产2000顶的时间相同.现在该企业每天能生产多少顶帐篷?五.精确作一作:作图题(本小题4分)27.某地区要在区域S内(即∠COD内部)建一个超市M,如图所示,按照要求,超市M到两个新建的居民小区A,B的距离相等,到两条公路OC,OD的距离也相等.这个超市应该建在何处?(要求:尺规作图,不写作法,保留作图痕迹)六.耐心看一看(每小题6分)28.如图,△ABC中A(﹣2,3),B(﹣31),C(﹣1,2).(1)画出△ABC关于x轴对称的△A1B1C1;并写出△A1B1C1三个顶点坐标:,,.(2)画出△ABC关于y轴对称的△A2B2C2;并写出△A2B2C2三个顶点坐标:,,.七.严密推一推(每小题4分,共20分)29.已知:如图,AB=DE,AC=DF,BE=CF.求证:∠A=∠D.30.如图,已知AB=AD,AC=AE,∠1=∠2,求证:BC=DE.31.已知:AC⊥BC,BD⊥AD,AC与BD交于O,AC=BD.求证:(1)BC=AD;(2)AO=BO.32.如图,在四边形ABCD中,AD∥BC,E为CD的中点,连接AE、BE,BE⊥AE,延长AE交BC的延长线于点F.求证:(1)FC=AD;(2)AB=BC+AD.33.已知:如图,在△ABC中,∠ACB=90°,CD⊥AB于点D,点E在AC上,CE=BC,过E点作AC的垂线,交CD的延长线于点F.求证:AB=FC.八.挑战自我(选做本题4分)34.如图,在四边形ABCD中,对角线AC平分∠BAD,AB>AD,试判断AB﹣AD 与CD﹣CB的大小关系,并证明你的结论.解:结论:证明:参考答案与试题解析一、精心选一选(每小题3分,共30分)1.计算(﹣)﹣3的结果是()A.﹣B.﹣C.﹣343 D.﹣21【考点】负整数指数幂.【分析】根据负整数指数为正整数指数的倒数进行计算即可.【解答】解:原式=(﹣7)3=﹣343.故选:C.【点评】此题主要考查了负整数指数幂、乘方,关键是掌握负整数指数为正整数指数的倒数.2.将,(﹣2)0,(﹣3)2这三个数按从小到大的顺序排列,正确的结果是()A.(﹣2)0<<(﹣3)2B.<(﹣2)0<(﹣3)2 C.(﹣3)2<(﹣2)0<D.(﹣2)0<(﹣3)2<【考点】负整数指数幂;有理数的乘方;零指数幂.【分析】分别根据零指数幂,负整数指数幂和平方的运法则进行计算,再比较大小即可.【解答】解:∵=6,(﹣2)0=1,(﹣3)2=9,又∵1<6<9,∴(﹣2)0<<(﹣3)2.故选A.【点评】主要考查了零指数幂,负整数指数幂和平方的运算.负整数指数幂为相应的正整数指数幂的倒数;任何非0数的0次幂等于1.3.下列各式中,从左到右的变形是因式分解的是()A.a2﹣4ab+4b2=(a﹣2b)2 B.x2﹣xy2﹣1=xy(x﹣y)﹣1C.(x+2y)(x﹣2y)=x2﹣4y2D.ax+ay+a=a(x+y)【考点】因式分解的意义.【分析】根据因式分解是把一个多项式转化成几个整式积的形式,可得答案.【解答】解:A、把一个多项式转化成几个整式积的形式,故A正确;B、每把一个多项式转化成几个整式积的形式,故B错误;C、是整式的乘法,故C错误;D、把一个多项式转化成几个整式积的形式,故D正确;故选:D.【点评】本题考查了因式分解的意义,利用了因式分解的意义.4.如图所示,AB=AC,要说明△ADC≌△AEB,需添加的条件不能是()A.∠B=∠C B.AD=AE C.∠ADC=∠AEB D.DC=BE【考点】全等三角形的判定.【分析】△ADC和△AEB中,已知的条件有AB=AC,∠A=∠A;要判定两三角形全等只需条件:一组对应角相等,或AD=AE即可.可据此进行判断,两边及一边的对角相等是不能判定两个三角形全等的.【解答】解:A、当∠B=∠C时,符合ASA的判定条件,故A正确;B、当AD=AE时,符合SAS的判定条件,故B正确;C、当∠ADC=∠AEB时,符合AAS的判定条件,故C正确;D、当DC=BE时,给出的条件是SSA,不能判定两个三角形全等,故D错误;故选:D.【点评】本题主要考查的是全等三角形的判定方法,需注意的是SSA和AAA不能作为判定两个三角形全等的依据.5.在下列图案中,不是轴对称图形的是()A.B.C.D.【考点】轴对称图形.【分析】根据轴对称图形的概念:如果一个图形沿一条直线折叠,直线两旁的部分能够互相重合,这个图形叫做轴对称图形,这条直线叫做对称轴进行分析即可.【解答】解:A、B、C都是轴对称图形,D不是轴对称图形,故选:D.【点评】此题主要考查了轴对称图形,关键是正确找出对称轴的位置.6.如图,若OP平分∠AOB,PC⊥OA,PD⊥OB,垂足分别是C、D,则下列结论中错误的是()A.PC=PD B.OC=PC C.∠CPO=∠DPO D.OC=OD【考点】角平分线的性质.。

人教版英语八年级上册期中测试卷(含答案)

人教版英语八年级上册期中测试卷(含答案)

人教版英语八年级上册期中测试卷(含答案)一、单项选择1. The boy didn't find much ________ about the topic on that website.A. reportB. articleC. informationD. story2. There is ________ in the program, so ________ is interested in it.A. nothing interesting; no oneB. something interested; anyoneC. interesting anything; someoneD. nothing interesting; someone3. —China is over 5, 000 years old. It's one of ______ countries in the world.—Yes. It has much ________ history than the USA.A. old; longB. older; longerC. older; the longestD. the oldest; longer4. —________ does Tom go to the swimming club?—Once a week.A. How oftenB. How longC. How soonD. How much5. My mother expects ________ around the world.A. to goB. goingC. goesD. went6. It was raining too ________, so we could ________ see anything below.A. hard; hardB. hard; hardlyC. hardly; hardlyD. hardly; hard7. Amanda read the article ________, and found something important in it.A. enough carefulB. carefully enoughC. enough carefullyD. careful enough8. ________ exciting news it is!Beijing will hold 2022 Winter Olympic Games.A. What anB. WhatC. HowD. How an9. ________ it rained a lot, we enjoyed our holiday.A. AlthoughB. BecauseC. UnlessD. However10. —I got an “A” in my math test.—________A. Long time no see.B. You did a good job.C. Thank you.D. It doesn't matter.二、完形填空A lot of people play sports, but very________11people become sports professionals. If sports aren't going to be your future, then why should you play them? Why should you train every day? Why should you work hard and feel sore the next day? Wouldn't it be________12to forget sports and only pay attention to your lessons?There are actually a lot of good________13to play sports. First of all, sports are a great way to exercise. Exercising keeps you________14and strong. It also helps you stay in a good state. When you exercise, your body produces endorphins. Endorphins give you more energy and make you feel happier.Sports are important to everyone, but they are________15important to young people. They teach young people about winning and losing. ________16, they teach young people how to communicate and work as a team. ________17, when you play football, you must learn________18to communicate with your teammates and work together. Sports teach young people to respect their coaches, teammates, and people they fight against as well.Many reports say that sports help young people stay out of trouble. If a young person plays sports, he or she is________19likely to have problems. This is because sports teach people rules. They also teach people that if they work hard, they might________20.Sports will help you become a better and happier person. Sports will help you make friends and stay healthy. Here is another good reason to play sports: Sports are fun.11. A. a few B. few C. a little D. little12. A. better B. best C. worse D. worst13. A. results B. ways C. reasons D. differences14. A. healthy B. tall C. necessary D. simple15. A. especially B. seriously C. exactly D. finally16. A. Too B. Nearly C. Also D. Only17. A. Such as B. At all C. As well D. For example18. A. when B. how C. what D. why19. A. less B. least C. more D. most20. A. drop B. succeed C. pass D. miss三、阅读理解ARecently I had a trip to Sydney with my parents. We visited the Wildlife Park.The Wildlife Park has lots of different animals. Some are native to Australia and can only be found there. There are more than 500 animals there, including kangaroos, koala and crocodiles. They are kept in their natural environment. I like the Wildlife Park better than a zoo. In zoos, most of the animals are in cages.We first spent some time with the kangaroos. We could touch and feed them. It was very exciting to be so close to them. There were koalas there too. They looked very cuddly. Although we couldn't carry koalas, I could take a photo with one. It is a wonderful souvenir of my holiday in Sydney.The Wildlife Park has plenty of freshwater and saltwater crocodiles. Some of them are really big and scary with huge teeth! I did not want to get too close to them.There was also a bird show. The keepers showed us different species of birds. I saw an ol d parrot. It could “talk” and made a great impression on me.I enjoyed the trip very much. There was so much to see.21. The Wildlife Park is ________.A. in SydneyB. in CairoC. in AthensD. in Rome22. What is a wonderful souvenir of the writer's holiday?A. A parrot that could talk.B. A chance to feed a koala.C. A photo with a koala.D. Food for the kangaroos.23. Why didn't the writer want to get very close to the crocodiles?A. Because they lived in water.B. Because the writer was afraid of them.C. Because the writer did not want to feed them.D. Because the writer did not like the smell of saltwater.24. Which of the following is true?A. The kangaroos are kept in cages in the Wildlife Park.B. The writer traveled to the Wildlife Park alone.C. The writer went to see koalas first.D. The writer watched a bird show.25. After visiting the Wildlife Park, the writer felt.A. boredB. unhappyC. excitedD. hopelessBThe Wandering Earth(《流浪地球》), China's first successful movie whose background is space, was shown on February 5. It is based on a short play of the same name by Liu Cixin, China's top science-fiction writer.1. Capsule(太空舱) —a core (核心) element(要素)The space capsule used in the film has made the audience inte rested. “This was the first time anything like that was done,” said Wang Hong, the producer of the movie. At first, the production team planned to use a small space capsule that had appeared in an earlier film, but found that it could not meet their needs for filming.2. Giant Vehicles(巨大的车辆) —key to the filmGiant vehicles are the key element in the film. Famous actors, Ng Man-tat and Wu Jing, said they could not even imagine what these vehicles would be like before filming, because the idea was far ahead of our time. The production team made about 10, 000 props to show the space better, including the giant vehicles.3. Saving planet itselfIn the film, the earth itself is pushed forward by 10, 000 giant thrusters. It carries 3. 5 billion people about 4. 2 light years through space in order to avoid destruction by the dying sun. In Liu's story, each thruster is 11, 000 meters in height.4. Amazing openingAt the beginning of the film, it shows the environment and life in an underground city—a big tree growing upside down, busy bookstores and snack bars and so on. There are also many snow scenes throughout the whole film.26. The story The Wandering Earth was written by ________.A. Wu JingB. Ng Man-tatC. Wang HongD. Liu Cixin27. The core element is ________.A. the space capsuleB. giant vehiclesC. saving the planet itselfD. an amazing opening28. Why did the production team give up using a small space capsule?A. Because of the audience's needs.B. Because the producer wanted to cut down the cost.C. Because of the production team's needs.D. Because the small capsule was broken in an earlier film.29. People must push the earth forward with 10, 000 giant thrusters because _______.A. each thruster is too highB. people want to save the earthC. people want to move to the sunD. 3. 5 billion people want to go through space30. What can we know about The Wandering Earth from the passage?A. Liu Cixin is the director of the film.B. It is made from a story of the same name.C. The capsule used in the film had appeared before.D. Snow scenes are shown only at the beginning of the film.CChina and Western countries have something different in cultures about certain animals, but when it comes to pigs, we have the same idea—pigs are ugly, lazy and stupid.Just look at some Chinese sayings such as “Boiling a dead pig.” and “A pig looking in the mirror is still a pig.” And in English, there are some expressions like “Eating like a pig.” and “Pigs might fly.” None of them are complimentary.However, pigs have some good qualities. They are even as smart as dogs and elephants. They have good memories. And they know whether people treat them well or not.A UK cartoon, Peppa Pig is a most popular cartoon. The four members in the pig family teach children from all around the world about love, friendship and the value of family. And a Chinese cartoon film, the Adventures of Mcdull, is also very famous. In the cartoon, the little pig, Mcdull, has a heart of gold and always works hard towards his dreams. Most people want quick success, but Mcdull is slow and patient, and not afraid of failing again and again.Maybe when we talk about pigs next time, we should think of their good qualities.31. China and Western countries have ________ in cultures according to the passage.A. the same idea towards pigsB. different ideas towards pigsC. the same idea towards all the animalsD. different ideas towards all the animals32. What does the underlined word “complimentary” mean in Chinese?A. 固执的B. 赞美的C. 负面的D. 组成的33. From the third paragraph, we can learn that ________.A. pigs have bad memories.B. pigs don't know who treats them well.C. pigs are as clever as dogs and elephants.D. pigs aren't clever at all.34. The writer gives the two examples of cartoons in the passage to show ________.A. pigs have good qualitiesB. the two cartoons are well-knownC. both Chinese and English children like pigsD. pigs have good memories35. What's the best title of the passage?A. Opinions on PigsB. Opinions on AnimalsC. Opinions on CartoonsD. Opinions on Cartoon Characters四、词汇运用A)用所给词的正确形式填空36. Mo Yan is a ________(write). He is the first to win the Nobel Prize in China.37. In the singing competition, he didn't sing so ________(clear) as Bob.38. Yang Jiang, a famous writer, ________(die) at the age of 105.39. Elsa is ________(talent) than her twin sister Anna. She is often praised by theteacher.40. ________(build) like the Palace Museum are famous around the world.B)根据汉语提示填空41. My sister plays sports ________ (两次) a week.42. Tom is a ________(有创造力的) student and he can solve the problems quickly.43. Tom and Peter are good friends. They can talk about and ________(分享)everything.44. In the 1930s, Walt Disney made 87 cartoons________(成功地).45. We had a ____________(讨论)about our picnic yesterday.五、补全对话M: Hi, I'm a reporter from the radio station. I'm conducting a survey. ________46 W: Sure.M: Do you like watching movies?W: ________47M: So which do you think is the best cinema in the town?W: Rose Cinema, I think.M: ________48W: Because Rose Cinema has the biggest screens and the most comfortable seats. M: ________49W: Yes, it is far from my home. But it is convenient(方便的)to take the subway(地铁).M: OK, that's all. Thank you.W: _______50十、综合填空根据短文内容, 从方框中选出合适的单词填入文中, 完成文章___________51 GreetingIn the main ______52, say “thank you” and tell the reasons. Closing and your name.参考答案1. C2. A3. D4. A5. A6. B7. B8. B9. A10. B11. B12. A13. C14. A15. A16. C17. D18. B19. A20. B21. A22. C23. B24. D25. C26. D27. A28. C29. B30. B31. A32. B33. C34. A35. A36. writer37. clearly38. died39. more talented40. Buildings 41. twice42. creative43. share44. successfully 45. discussion 46. F47. C48. B49. G50. A51. Date52. body53. tired54. inviting55. will56. kind57. especially58. seen59. bought60. forget。

人教版数学八年级(上)期中考试测试卷(1)

人教版数学八年级(上)期中考试测试卷(1)

人教版数学八年级(上)期中考试测试卷(1)一.选择题(本大题共12小题,每小题3分,共36分)1.(3分)下列长度的三条线段能组成三角形的是()A.6,2,3B.3,3,3C.4,3,8D.4,3,72.(3分)一个多边形的内角和是它的外角和的2倍,则这个多边形是()A.五边形B.六边形C.七边形D.八边形3.(3分)如图,△ABC中,∠ACB=90°,D为BC上一点,DE⊥AB于点E,下列说法中,错误的是()A.△ABC中,AC是BC上的高B.△ABD中,DE是AB上的高C.△ABD中,AC是BD上的高D.△ADE中,AE是AD上的高4.(3分)两根木棒的长分别为5cm和7cm,要选择第三根木棒,将它们钉成一个三角形.如果第三根木棒长为偶数,则满足条件的三角形的个数为()A.3个B.4个C.5个D.6个5.(3分)若△ABC≌△DEF,且∠A=60°,∠E=70°,则∠C的度数为()A.50°B.60°C.70°D.50°或80°6.(3分)如图,点A,E,C在同一直线上,△ABC≌△DEC,BC=5,CD=8,则AE的长为()A.2B.3C.4D.57.(3分)如图,已知∠1=∠2,则不一定能使△ABD≌△ACD的条件是()A.BD=CD B.AB=AC C.∠B=∠C D.∠BDA=∠CDA 8.(3分)如图,点B在CD上,△ABO≌△CDO,当AO∥CD,∠BOD=30°时,∠A的度数为()A.20°B.30°C.40°D.35°9.(3分)把一个多边形纸片沿一条直线截下一个三角形后,变成一个四边形,则原多边形纸片的边数不可能是()A.3B.4C.5D.610.(3分)如图,射线OC平分∠AOB,点D、Q分别在射线OC、OB上,若OQ=4,△ODQ的面积为10,过点D作DP⊥OA于点P,则DP的长为()A.10B.5C.4D.311.(3分)到三角形各顶点距离相等的点是()A.三条边垂直平分线交点B.三个内角平分线交点C.三条中线交点D.三条高交点12.(3分)如图,在Rt△ABC中,∠ABC=90°,以AC为边,作△ACD,满足AD=AC,E为BC上一点,连接AE,2∠BAE=∠CAD,连接DE,下列结论中正确的有()①AC⊥DE;②∠ADE=∠ACB;③若CD∥AB,则AE⊥AD;④DE=CE+2BE.A.①②③B.②③④C.②③D.①②④二.填空题(本大题共4小题,每小题3分,共12分)13.(3分)在直角三角形中,有一个锐角是另外一个锐角的5倍,则这个锐角的度数为度.14.(3分)已知AD是△ABC的中线,若△ABD与△ACD的周长分别是17和15,△ABC 的周长是22,则AD的长为.15.(3分)如图,∠C=90°,AD是△ABC的角平分线,DE⊥AB,垂足为E,若BC=8,BD=5,则DE的长为.16.(3分)如图,AB=7cm,AC=5cm,∠CAB=∠DBA=60°,点P在线段AB上以2cm/s 的速度由点A向点B运动,同时,点Q在射线BD上运动速度为xcm/s,它们运动的时间为t(s)(当点P运动结束时,点Q运动随之结束),当点P,Q运动到某处时,有△ACP与△BPQ全等,此时t=.三.解答题(本大题共8小题,共72分)17.(8分)已知a,b,c是△ABC的三边长.(1)若a,b,c满足|a﹣b|+|b﹣c|=0,试判断△ABC的形状;(2)化简:|a﹣b﹣c|+|b﹣c﹣a|+|c﹣a﹣b|.18.(8分)(1)根据图中的相关数据,求出x的值.(2)一个多边形的内角和是1260°,求这个多边形的边数.19.(8分)在△ABC中,BC=8,AB=1.(1)若AC是整数,求AC的长;(2)已知BD是△ABC的中线,若△ABD的周长为17,求△BCD的周长.20.(8分)在△ABC中,CD平分∠ACB交AB于点D,AH是△ABC边BC上的高,且∠ACB=70°,∠ADC=80°,求∠BAH的度数.21.(8分)已知一个正多边形的边数为n.(1)若这个多边形的内角和为其外角和的4倍,求n的值;(2)若这个正多边形的一个内角为135°,求n的值.22.(10分)如图,AB=CD,AH=CG,DG⊥AC于G,BH⊥AC于H,BD交AC于点M.(1)求证:Rt△ABH≌Rt△CDG;(2)求证:MB=MD.23.(10分)如图,点D,E分别在AB,AC上,∠ADC=∠AEB=90°,BE,CD相交于点O,OB=OC.求证:∠1=∠2.小虎同学的证明过程如下:证明:∵∠ADC=∠AEB=90°,∴∠DOB+∠B=∠EOC+∠C=90°.∵∠DOB=∠EOC,∴∠B=∠C.……第一步又OA=OA,OB=OC,∴△ABO≌△ACO.……第二步∴∠1=∠2.……第三步(1)小虎同学的证明过程中,第步出现错误;(2)请写出正确的证明过程.24.(12分)(1)如图1,∠MAN=90°,射线AE在这个角的内部,点B、C分别在∠MAN 的边AM、AN上,且AB=AC,CF⊥AE于点F,BD⊥AE于点D.求证:△ABD≌△CAF;(2)如图2,点B、C分别在∠MAN的边AM、AN上,点E、F都在∠MAN内部的射线AD上,∠1、∠2分别是△ABE、△CAF的外角.已知AB=AC,且∠1=∠2=∠BAC.求证:△ABE≌△CAF;(3)如图3,在△ABC中,AB=AC,AB>BC.点D在边BC上,CD=2BD,点E、F 在线段AD上,∠1=∠2=∠BAC.若△ABC的面积为15,求△ACF与△BDE的面积之和.。

2024-2025学年人教版八年级上册数学期中测试卷

2024-2025学年人教版八年级上册数学期中测试卷

2024-2025学年人教版八年级上册数学期中测试卷一、单选题1.下列图案中,不是轴对称图形的是( )A .B .C .D . 2.下列长度的三条线段能组成三角形的是( )A .1,2,3B .2,2,2C .2,2,4D .1,3,5 3.如图,AB CD ∥, 80C ∠=︒,A ∠比M ∠大40︒,则A ∠=( )A .10︒B .20︒C .30︒D .60︒4.已知三角形的两边长分别为4,6.则第三边长的取值范围在数轴上表示正确的是( ) A . B .C .D .5.如图,已知CBE DAE △≌△,连接AB ,若35,30C B E B A D ∠=︒∠=︒,则BAE ∠等于()A .25︒B .30︒C .35︒D .65︒6.如图,点C 在BE 上,B E ACF ∠=∠=∠,AC CF =,4AB =,6EF =,则BE 的长是()A .8B .10C .12D .137.如图,OP 平分MON ∠,PE OM ⊥于点E ,PF ON ⊥于点F ,OA OB =,则图中全等三角形有( )A .1对B .2对C .3对D .4对8.在平面直角坐标系中,点()3,2A -,(),B m n 关于x 轴对称,将点B 向左平移3个单位长度得到点C ,则点C 的坐标为( )A .()3,2-B .()3,2C .()0,2-D .()0,29.如图,ABC V 中,90C =o ∠,AC BC =,AD 平分CAB ∠交BC 于D ,DE AB ⊥于E 且6cm AB =,则AC CD +的长为( )A .12cmB .10cmC .8cmD .6cm10.如图,在ABC V 中,AD 平分BAC ∠交边BC 于点D ,DE AB ∥交边AC 于点E .若48B ∠=︒,26C ∠=︒,则ADE ∠的大小为( )A .42︒B .52︒C .53︒D .54︒11.如图,等腰ABC V 的底边BC 长为3,面积是12,腰AC 的垂直平分线EF 分别交边AC ,AB 于点E ,F .若D 为BC 边的中点,M 为线段EF 上的一动点,则CDM V 周长的最小值为( )A .4B .9.5C .12.5D .1612.如图,已知25AOB ∠=︒,55CPD ∠=︒,分别以O ,P 为圆心,以同样长为半径作弧,交OA ,OB 于点E ,F ,交PC ,PD 于点M ,N ;以点N 为圆心,以EF 的长为半径作弧,交弧MN 于点G ,作射线PG ,则CPG ∠的度数是( )A .25︒B .30︒C .35︒D .45︒二、填空题13.已知一个多边形的内角和是2520︒,则这个多边形是边形.14.点(),4A a ,点()3,B b 关于x 轴对称,则()2023a b +=.15.如果,60,40ABC DEC B C ∠=︒∠=︒V V ≌,那么E ∠=︒16.在平面直角坐标系中,点(,1)A a 与点(2,)B b -关于x 轴对称,则a b +的值为.三、解答题17.已知点23P a -(,)与点8,2P b '+(). (1)若点P 与点P '关于x 轴对称,求a ,b 的值;(2)若点P 与点P '关于y 轴对称,求a ,b 的值.18.如图,已知BC DF ∥,B D ∠=∠,A 、F 、B 三点共线,连接AC 交DF 于点E .(1)求证:A ACD ∠=∠;(2)若FG AC P ,106A B ∠+∠=︒,求EFG ∠的度数.19.已知:a 、b 、c 为ABC V 的三边长,且a 、b 满足()22280a b a b -+++-=.(1)求c 的取值范围;(2)在(1)的条件下,若21x c -=,求x 的取值范围.20.在平面直角坐标系中,O 是坐标原点,定义点A 和点B 的关联值[,]A B 如下: I.若O ,A ,B 在一条直线上[,]0A B =;II.若O ,A ,B 不在一条直线上[,]AOB A B S =V ;已知点A 坐标为(4,0)点B 坐标为(0,4),回答下列问题:(1)[]A B =,_______;(2)若[]0P A =,,[]1P B =,,则点P 坐标为_______.21.如图,已知点B E G D 、、、在同一条直线上,AC EF ∥,A F ∠=∠,AB DC =.(1)求证:AB CD ∥;(2)求证:ABG CDG △≌△;(3)若16BD =,3GE =,求BE 的长是多少?22.如图,在平面直角坐标系中,()2,1A -,()1,3B -,()3,4E ,将线段AB 平移得到线段CD(点A 、B 的对应点分别是C 、D ),若点(),2C m (2m ≠,且32m ≠-),连接EB 、ED ,(1)点D 的坐标为(用含m 的式子表示)(2)探究CDE ∠,ABE ∠,DEB ∠之间的数量关系(3)若三角形ABE 的面积是三角形ECD 的面积的2倍,求m 的值.23.已知:如图,ABC V 、CDE V 都是等边三角形,AD 、BE 相交于点O ,点M 、N 分别是线段AD 、BE 的中点.(1)求证:AD BE =;(2)求DOE ∠的度数;(3)求证:MNC V 是等边三角形.24.已知(1,0),(,),(1,4)A B a b C -,其中2(2)0a -=.(1)求点B 的坐标.(2)在x 轴正半轴上找一点P ,使以A ,C ,P 三点为顶点的三角形的面积为10.(3)在(2)的条件下,连接PB ,在直线PB 上,是否存在点D ,使得三角形ABD 的面积是三角形ACP 面积的2倍?若存在,直接写出点D 的坐标;若不存在,请说明理由.(提示:可用坐标的平移来求点D 的坐标)25.已知ON GM ⊥于点O ,直线CD 交ON 于点B ,点A 在射线OM 上.(1)如图1,若CD AB ⊥于点B ,AE 平分OAB ∠,交CD 于点E ,交ON 于点F ,求证:BEF BFE ∠=∠;(2)如图2,若CD 平分NBA ∠,OE 平分BOG ∠交CD 于点E ,58OAB ∠=︒,则O E B ∠的度数为________.(3)如图3,若CD 平分NBA ∠,OE 平分BOG ∠交CD 于点E ,BF 平分OBA ∠交OE 反向延长线于点F ,在BEF △中,如果一个角是另一个角的3倍,请求出BAO ∠的度数.。

人教版八年级上册数学《期中》测试卷及答案【完美版】

人教版八年级上册数学《期中》测试卷及答案【完美版】

人教版八年级上册数学《期中》测试卷及答案【完美版】 班级: 姓名: 一、选择题(本大题共10小题,每题3分,共30分)1.下列说法中正确的是( )A .若0a <,则20a <B .x 是实数,且2x a =,则0a >C .x -有意义时,0x ≤D .0.1的平方根是0.01±2.在平面直角坐标系的第二象限内有一点M ,点M 到x 轴的距离为3,到y 轴的距离为4,则点M 的坐标是( )A .(3,4)-B .(4,3)-C .(4,3)-D .()3,4-3.下列运算正确的是( )A .4=±2B .(4)2=4C .2(4)-=﹣4D .(﹣4)2=﹣44.若点1(3,)A y -,2(2,)B y -,3(1,)C y 都在反比例函数12y x=-的图象上,则1y ,2y ,3y 的大小关系是( )A .213y y y <<B .312y y y <<C .123y y y <<D .321y y y <<5.在平面直角坐标系中,将点A (1,﹣2)向上平移3个单位长度,再向左平移2个单位长度,得到点A ′,则点A ′的坐标是( )A .(﹣1,1)B .(﹣1,﹣2)C .(﹣1,2)D .(1,2)6.菱形不具备的性质是( )A .四条边都相等B .对角线一定相等C .是轴对称图形D .是中心对称图形7.下列各图中a 、b 、c 为三角形的边长,则甲、乙、丙三个三角形和左侧△ABC 全等的是( )A .甲和乙B .乙和丙C .甲和丙D .只有丙8.如图,在△ABC 中,∠C=90°,AC=BC=2,将△ABC 绕点A 顺时针方向旋转60°到△AB ′C ′的位置,连接C ′B ,则C ′B 的长为( ).A .1B .31-C .2D .222-9.如图1,点F 从菱形ABCD 的顶点A 出发,沿A →D →B 以1cm/s 的速度匀速运动到点B ,图2是点F 运动时,△FBC 的面积y (cm 2)随时间x (s )变化的关系图象,则a 的值为( )A .5B .2C .52D .2510.如图,AD ,CE 分别是△ABC 的中线和角平分线.若AB=AC ,∠CAD=20°,则∠ACE 的度数是( )A .20°B .35°C .40°D .70°二、填空题(本大题共6小题,每小题3分,共18分)1.因式分解:3222x x y xy +=﹣__________. 2.已知菱形ABCD 的面积是12cm 2,对角线AC =4cm ,则菱形的边长是______cm .3.若m+1m =3,则m 2+21m=________. 4.如图,点A 在双曲线1y=x 上,点B 在双曲线3y=x上,且AB ∥x 轴,C 、D 在x 轴上,若四边形ABCD 为矩形,则它的面积为________.5.正方形111A B C O 、2221A B C C 、3332A B C C 、…按如图所示的方式放置.点1A 、2A 、3A 、…和点1C 、2C 、3C 、…分别在直线1y x =+和x 轴上,则点n B 的坐标是__________.(n 为正整数)6.如图△ABC 中,分别延长边AB 、BC 、CA ,使得BD=AB ,CE=2BC ,AF=3CA ,若△ABC 的面积为1,则△DEF 的面积为________.三、解答题(本大题共6小题,共72分)1.解方程:223124x x x --=+-2.先化简2728333x x x x x -⎛⎫+-÷ ⎪--⎝⎭,再从04x ≤≤中选一个适合的整数代入求值.3.已知关于x 的一元二次方程()22x 2k 1x k k 0-+++=(1)求证:方程有两个不相等的实数根;(2)若△ABC 的两边AB 、AC 的长是方程的两个实数根,第三边BC 的长为5.当△ABC 是等腰三角形时,求k 的值4.如图,△ABC 中,AB=AC ,点E ,F 在边BC 上,BE=CF ,点D 在AF 的延长线上,AD=AC ,(1)求证:△ABE ≌△ACF ;(2)若∠BAE=30°,则∠ADC= °.5.如图,分别以Rt △ABC 的直角边AC 及斜边AB 向外作等边△ACD ,等边△ABE ,已知∠BAC=30°,EF ⊥AB ,垂足为F ,连接DF(1)试说明AC=EF ;(2)求证:四边形ADFE 是平行四边形.6.学校需要添置教师办公桌椅A 、B 两型共200套,已知2套A 型桌椅和1套B 型桌椅共需2000元,1套A 型桌椅和3套B 型桌椅共需3000元.(1)求A,B两型桌椅的单价;(2)若需要A型桌椅不少于120套,B型桌椅不少于70套,平均每套桌椅需要运费10元.设购买A型桌椅x套时,总费用为y元,求y与x的函数关系式,并直接写出x的取值范围;(3)求出总费用最少的购置方案.参考答案一、选择题(本大题共10小题,每题3分,共30分)1、C2、C3、B4、B5、A6、B7、B8、B9、C10、B二、填空题(本大题共6小题,每小题3分,共18分)1、()2x x y -23、74、25、1(21,2)n n --6、18三、解答题(本大题共6小题,共72分)1、54x = 2、42x x +;1x =时,原式52=(或当2x =时,原式32=.)3、(1)详见解析(2)k 4=或k 5=4、(1)略;(2)75.5、略.6、(1)A ,B 两型桌椅的单价分别为600元,800元;(2)y=﹣200x+162000(120≤x ≤130);(3)购买A 型桌椅130套,购买B 型桌椅70套,总费用最少,最少费用为136000元.。

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笔试部分(85分)二、完形填空(15分)Jon Hunt is a __16__ writer. Lots of people like him and his works. Jon Hunt is different __17__ many other writers. Although he needs to work at home and likes reading and watching different __18__ of TV shows, he doesn't always stay at home. He likes going outside and exercising. __19__,he often runs, swims and goes skateboarding(滑滑板). __20__ he also goes camping(野营) with his friends. He has many good habits so he is very happy. And he is always in good __21__. How can he keep healthy? He __22__ us some advice(建议). Let's have a look together. First, keep __23__ every day. He gets up at 6:00 a.m. and __24__ for one hour every morning. And he walks to mountains three times a week. So don't be lazy. Second, remember to have __25__. It's very important. He always has a lot of porridge, bread or milk __26__ doing morning exercises. Then __27__ after working. Don't __28__ too much about your work. It isn't __29__ for your health. You can try listening to music or walking with friends if you have time. He's sure it will __30__ you have a healthy body.()16.A.commonB.luckyC.famousD.fresh()17.A.inB.fromC.ofD.with()18.A.kindsB.culturesC.reasonsD.roles()19.A.Because ofB.For exampleC.So farD.In fact()uallyB.FinallyC.SometimesD.Luckily()21.A.lifeB.interestC.mindD.health()22.A.plansB.givesC.findsD.teaches()23.A.workingB.writingC.exercisingD.reading()24.A.runsB.watchesC.drivesD.jumps()25.A.mealB.dinnerC.breakfastD.lunch()26.A.whenB.ifC.afterD.as()27.A.relaxB.talkC.practiceD.leave()28.A.talkB.worryC.thinkD.expect()29.A.badB.goodC.niceD.cool()30.A.makeB.tryC.hopeD.decide三、阅读理解(30分)AWhen spring comes, what do you do? Do you still stay at home or watch boring TV programs? Why not go out to bathe in the warm sunshine and enjoy the flowers? Here are three places for you to visit to see the most beautiful sights(风景).Our first stop is Lijiang, Yunnan Province(省). From mid­March to late April, the spring air in Lijiang is sweet with the perfume(芳香) of cherries. Cherries are one of the first fruits to be sold at the market each year. The lovely bright red cherries will get you in a spring mood.Next, from late March to April, Wuyuan, Jiangxi Province, is one of the best places to enjoy thefascination of bright yellow rape flowers(油菜花). Walking along the stone roads, over bridges, seeing the waves of flowers, you will feel you are returning to nature.Last, from midApril to early May, you can visit Qingdao in Shandong Province. A sea of sakura(樱花) waits for you. People say that sakura trees here are planted more densely than in any other place in the world except(除了) Hokkaido, Japan. In a park in Qingdao, there are more than 20,000 sakura trees.These beautiful sights are worth(值得) a weekend or two of anyone's time. Visit them when next spring comes.()31.How many places where you can enjoy springtime are talked about in the passage?A.One.B.Two.C.Three.D.Four.()32.If it's early May now, where can you visit?A.Lijiang, Yunnan Province.B.Wuyuan, Jiangxi Province.C.Qingdao, Shandong Province.D.Nowhere.()33.What do people think of the sakura trees in Qingdao?A.They are the most densely planted in the world.B.They are the most densely planted in China.C.They are more densely planted than those in Japan.D.They are more densely planted than those in Wuyuan.()34.If you have a fiveday holiday in April, you can go to visit ________.A.LijiangB.WuyuanC.QingdaoD.all of the above()35.What channel does the passage probably come from?A.Travel Channel.B.Game Channel.C.News Channel.D.Music Channel.BWithout(没有) changes(改变), our lives would be very boring. It would be like listening to the same song on your MP3 player over and over again.Some people don't like changes. They want to do the same things and see the same people every day. When something changes, it makes them feel uncomfortable. It is like some children, and they can't go to sleep unless(除非) all their toys are in their places. But the change is a big part oflife and we all change in small ways every day. The young get stronger and the old get weaker. We meet new friends or get new hobbies.You will go through many changes in your lifetime. In America, some people change jobs ten times during their lives. Some change their homes eleven times. They like changing because they think it improves their lives.China has seen many changes in recent years and they are living longer. People have more money, more food and they have a better education. Children are growing taller and the children in Shanghai are now the tallest in China. Changes have been good for China and they will be good for you.()36.The writer thinks that without changes our lives would ________.A.not be boringB.not be interestingC.be more comfortableD.be much healthier()37.People who don't like changes want to ________.A.change in small ways every dayB.buy many toys for their children every dayC.meet new friends or get new hobbies all the timeD.do the same things and see the same people every day()38.Americans like changes because they think ________.A.these changes improve their livesB.they can't do the same things every dayC.they can meet many new friendsD.they can often get new hobbies()39.What can we learn from the passage?A.People are less healthy and they are living a shorter life in China.B.The children in Shanghai are now the tallest in the world.C.Many good changes have taken place in recent years in China.D.People have less money, but they have a better education in China.()40.What does the passage tell us?A.What changes are.B.How to change.C.Changes are good.D.How to live better.CDo you want to be in good health?Try to do the following things!You can become stronger.Drink eight cups of water every day. Water helps your body in many ways. If you feel thirsty, just have a cup of water.Don't forget to eat your breakfast. Breakfast gives you everything your body needs for the morning, so do not forget your breakfast.Get enough calcium(钙). Your bones(骨头) need it. Milk has more calcium. You may also drink orange juice with calcium in it.Go for a walk every day after meals. Walking is good exercise, and people need exercise for good health. It's better to walk after meals.Stretch for five minutes after sitting for one or two hours. Stretching your arms and legs is good for your body.Use your brain every day. For example, you can do crossword puzzles or read a new book.Have a rest for about twenty minutes when you are tired. You may do something different to have a break. For example, get up and walk. Or sit down to listen to music.()41.How many things does this passage mention for you to do if you want to keep healthy?A.Five.B.Six.C.Seven.D.Eight.()42.Which meal can provide what your body needs for the morning?A.Breakfast.B.Lunch.C.Dessert.D.Dinner.()43.It's better to take a walk after meals, isn't it?A.No, it isn't.B.Yes, it is.C.No, it doesn't.D.Yes, it was.()44.What does the underlined word “Stretch”mean in Chinese?A.锻炼B.跳跃C.跑步D.伸展()45.What is the best title for this passage?A.It's Important to Keep HealthyB.Ways to Keep HealthyC.Why People Do ExerciseD.Take Care of Yourself四、词汇运用(15分)A)用方框中所给单词的适当形式填空。

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