机器人学导论(克雷格)第二章作业答案

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2、1

solution:

According to the equation of pure transition transformation,the new point after transition is as follows:

2、3

solution:

According to the constraint equations:

Thus,the matrix should be like this:

2、4

Solution:

= 2、7 Solution:

According to the equation of pure rotation transformation , the new coordinates are as follows: 2、9 Solution:

Acording to the equations for the bined transformations ,the new coordinates are as follows:

010051

05110

0030010310(,90)(5,3,6)(,90)001060

1004900

0110

00111A B

P Rot z Trans Rot x P -⎡⎤⎡⎤⎡⎤⎡⎤⎡⎤⎢⎥⎢⎥⎢⎥⎢⎥⎢⎥-⎢

⎥⎢⎥⎢⎥⎢⎥⎢⎥

=⨯⨯⨯==⎢⎥⎢⎥⎢⎥⎢⎥⎢⎥

⎥⎢⎥⎢⎥⎢⎥⎢⎥

⎣⎦⎣⎦⎣⎦⎣⎦⎣⎦o o

A

B

Transformations relative to the reference frame

Transformations relative to the current frame

2、10

P=Trans(5,3,6)Rot(x,90)Rot(a,90) P

1 0 0 5 1 0 0 0 0 -1 0 0

2 = 0 1 0

3 0 0 -1 0 1 0 0 0 3

0 0 1 6 0 1 0 0 0 0 1 0 5 0 0 0 1 0 0 0 1 0 0 0 1 1 2 = -2 8 1 2、12

0、369 -0、766 -0、601

0、819 0 -2、947 0、439 0、643 -5、38 0 0 0 1 0 -0、39 -3、82

1 0 -6 0 0、9

2 -3、79 0 0 0 1 2、14

a) For spherical coordinates we have (for posihon )

1)r·cos γ·sin β = 3、1375

2)r·sin γ·sin β = 2、195

3)r·cos β = 3、214

I) Assuming sin β is posihve, from a and b →γ=35°

from b and c →β=50°

units

from c → r=5

II) If sin β were negative、Then

units

γ=35°β=50°r=5

Since orientation is not specified, no more information is available to check the results、

b) For case I, substifate corresponding values of sinβ, cosβ, sinγ, cosγ

and r in sperical coordinates to get:

0、5265 -0、5735 0、6275 3、1375

Tsph(r,β,γ)=Tsph(35,50,5)= 0、3687 0、819 0、439 2、195

-0、766 0 0、6428 3、

214

0 0 0 1 2、16

Solution:

According to the equations given in the text book, we can get the Euler angles as follows:

Which lead to :

2、18

Solution:

①Since the hand will be placed on the object, we can obtain this: Thus:

②No,it can’t、

If so,the element at the position of the third row and the second column

should be 0、However, it isn’t、

x=5,y=1,z=0

According to the equations of the euler angles:

2、21

(a)

(b)

# θ d a α0-1 0 0 1-2 0 180 2-H 0 0 (c)

= =

= =

(d)

2、22

(a)

(b)

(c)

= =

= = = (d)

2、23

(a)

(b)

# θ d a α

1 0 0 90

2 0 4 0 1 -90

4 0 90

5 0 0 -90

6 5 0 0

(c)

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