深圳市罗湖区翠园中学(高中部)2018-2019学年高三上学期第三次月考试卷数学含答案
高考专题翠园中学高三第三次模拟考试.docx
侧视图h5高中数学学习材料马鸣风萧萧*整理制作2015届翠园中学高三第三次模拟考试文科数学一、选择题：本大题共10小题，每小题5分，满分50分．在每小题给出的四个选项中，只有一项是符合题目要求的．1．已知{|31,}A x x k k Z ==-∈，则下列表示正确的是A.1A -∉B.11A -∈C. 231k A -∈ D.34A -∉2．已知复数1z i =+，则2(1)z z -=A. 2B. －2C. 22i -D. 22i --3．命题P ：“对2,12x R x x ∀∈+≥”的否定P ⌝为A. 2,12x R x x ∃∈+>B.2,12x R x x ∃∈+≥C. 2,12x R x x ∀∈+<D.2,12x R x x ∃∈+<4．已知1sin()3πα+=，则cos2α= A.79 B.89 C. 79- D.4295. 若01x y <<<，则下列不等式正确的是A ．44y x <B ．33>x y C ．44log log x y < D ．11()()44x y <6．设向量(12)(23)==，，，a b ，若向量λ-a b 与向量(56)=--，c 共线，则λ的值为 A ．43 B ．413 C ．49- D ．4 7．图1中的三个直角三角形是一个体积为330cm 的几何体的三视图，图2否是a i ≥90？n=n+1n=0,i=1否输入a 1，a 2，……，a 12i=i+1开始结束输出n i ≤12？是则侧视图中的h 为A. 5 cmB.6 cmC.7 cmD.8 cm 图18．已知变量,x y 满足约束条件⎪⎩⎪⎨⎧≥-≤+-≤-+0101205x y x y x ，则y x 的最小值是A.1B. 4C.23D.09．下表记录了某学生进入高三以来各次数学考试的成绩 考试第次123456789101112成绩（分） 65 78 85 87 88 99 90 94 93 102 105 116将第1次到第12次的考试成绩依次记为1212,,,a a a L .图2是统计上表中成绩在一定范围内考试次数的一个算法流程图,那么算法流程图输出的结果是A.8B.7C.6D.5 10．已知{1,2,3,4},{1,2,3}a b ∈∈，则关于x 的不等式222(1)0x a x b --+≥的解集为R 的概率为A.14B.12C. 23D. 34二、填空题：本大题共5小题，考生作答4小题，每小题5分，满分20分． （一）必做题（11－13题）11．已知幂函数()y f x =的图象过点1(3,)3，则2log (2)f 的值为 ．12．以点(2,1)-为圆心且与直线3470x y +-=相切的圆的标准方程是 ．13．在△ABC 中，已知角C B A ,,所对的边分别为c b a ,,，且2(cos cos )c a B b A b -=，则s i n s i n AB= ． （二）选做题（14－15题，考生只能从中选做一题）14. (坐标系与参数方程选做题) 在极坐标系(,)ρθ (02)θπ≤<中，曲线(2cos sin )3ρθθ-=与(cos 2sin )1ρθθ+=-的交点的极坐标为 ．15．（几何证明选讲选做题）如图3，点P 在圆O 的直径AB 的 延长线上，且PB=OB=3,PC 切圆O 于C 点，CD ⊥AB 于D 点，N M Po yx则CD 的长为 ． 图3三．解答题：本大题共6小题，满分80分．解答须写出文字说明、证明过程和演算步骤． 16．(本小题满分12分)已知函数()sin()6f x A x πω=+(00)A ω>>，的部分图象如图4示，其中M 1(,0)6-为图象与x 轴的交点，1(,2)3P 为图象的最高点．(1)求A 、ω的值；(2)若2()3f απ=，(,0)3πα∈-，求cos()3πα+的值． 图417．(本小题满分12分)某校为了调查“学业水平考试”学生的数学成绩，随机地抽取该校甲、乙两班各10名同学，获得的数据如下：（单位：分）甲：132，108，112，121，113，121，118，127，118，129； 乙：133，107，120，113，121，116，126，109，129，127.（1）以百位和十位为茎，个位为叶，在图5中作出以上抽取的甲、乙两班学生数学成绩的茎叶图，求出这20个数据的众数，并判断哪个班的平均水平较高；（2）将这20名同学的成绩按下表分组，现从第一、二、三组中，采用分层抽样的方法抽取6名同学成绩作进一步的分析，求应从这三组中各抽取的人数．18．(本小题满分14分)组别 第一 第二 第三 第四分值区间 [100,110) [110,120) [120,130) [130,140]已知等比数列{}n a 满足：0n a >，15a =，n S 为其前n 项和，且13220S S S ，，7成等差数列． （1）求数列{n a }的通项公式； （2）设51525log log log n n b a a a =+++，求数列{1nb }的前n 项和n T ．19．（本小题满分14分）如图6，在三棱锥S ABC -中，侧面SAB 与侧面SAC 均 为等边三角形，2AB =，90BAC ∠=°． （1）证明：SA BC ⊥；（2）求三棱锥S ABC -的体积．图620．(本小题满分14分)已知椭圆C :22221(0)x y a b a b+=>>的焦点分别为1(3,0)F -、2(3,0)F ，P 为椭圆C 上任一点，12PF PF ⋅uuu r uuu r的最大值为1.（1）求椭圆C 的方程；（2）已知点(1,0)A ，试探究是否存在直线:l y kx m =+与椭圆C 交于D 、E 两点，且使得||||AD AE =？若存在，求出k 的取值范围；若不存在，请说明理由.21．(本小题满分14分)已知函数()321(21)3(2)13f x x k x k k x =-++++，其中k 为实数.（1）当1k =-时，求函数()f x 在[0,6]上的最大值和最小值； （2）求函数()f x 的单调区间；（3）若函数()f x 的导函数'()f x 在(0,6)上有唯一的零点，求k 的取值范围.数学(文科)参考答案一、选择题：CADAC ABCBD二、填空题：11. 1-；12.22(2)(1)1x y -++=；13.2；14. 7(2,)4π；15.332. 三、解答题：16．解：（1）由1(,2)3P 为图象的最高点知2A =，---------------------1分又点M 1(,0)6-知函数()f x 的最小正周期114()236T =+=，-----------------------3分 ∵2T πω=∴ωπ=,-------------------------------------------------5分(2)由（1）知，()2sin()6f x x ππ=+由2()3f απ=得1sin()63πα+=，----------------------------------------6分 ∵(,0)3πα∈-∴666πππα-<+<----------------------------------------7分∴2122cos()1sin ()16693ππαα+=-+=-=-------------------------9分 ∵cos()cos()366πππαα+=++cos()cos sin()sin 6666ππππαα=+-+-------------11分∴cos()3πα+2231126132326-=⨯-⨯=------------------------------------------------12分 17．解：（1）甲、乙两班学生数学成绩的茎叶图如右图示：----4分这20个数据的众数为121，----------------------------------5分 乙班的平均水平较高；----------------------------------------7分 （2）由上数据知，这20人中分值落在第一组的有3人，落在第二组的有6人，落在第三组的有9人，-------------9分故应从第一组中抽取的人数为：631369⨯=++，-------10分应从第二组中抽取的人数为：662369⨯=++，--------------------------------11分应从第三组中抽取的人数为：693369⨯=++.-----------------------------------12分18．解：（1）设数列{}n a 的公比为q ，∵13220,,7S S S 成等差数列，3122207.S S S ∴=+-----------------------------------2分即21111112()207()a a q a q a a a q ++=++，化简得225250q q --=，------4分解得：5q =或52q =-------------------------------------------------------------------6分 ∵0n a >，∴52q =-不合舍去，∴111555n n nn a a q --==⨯=.-----------------------------------------7分(2)∵ 51525log log log n n b a a a =+++=1235125log ()log 5123nn a a a n ++++==++++---------------------9分(1)2n n +=，----------------------------------------------------------------------------10分 ∴1n b =211=2()(+11n n n n -+）----------------------------------------------------------------12分 ∴12111n n T b b b =+++111112[(1)()()]2231n n =-+-++-+ 122(1)11nn n =-=++.------------------------------------------14分 19．解：（1）证明：取BC 中点D ，连结SD 、AD ，-----2分 ∵△SAB 与△SAC 均为等边三角形∴SB=SC=AB=AC=SA=2，∴SD BC ⊥,AD BC ⊥-----4分 又SDAD D =∴BC ⊥平面SAD ----------------------5分 ∵SA ⊂平面SAD∴SA BC ⊥-------------------------------------------------7分 （2）∵90BAC ∠=°，AB=AC ， ∴222BC AB ==，------------------------------------8分∵SB=AB ，SC=AC ，BC=BC ，∴△SBC ≌△ABC ，∴90BSC ∠=，-------------------------9分 ∴122SD AD BC === ∵2224SD AD SA +== ∴SD AD ⊥---------------------11分 又SD BC ⊥,BCAD D =∴SD ⊥平面ABC ,------------------------------------------12分 ∴13P ABC ABC V S SD -∆=1122222323=⨯⨯⨯⨯=.----------------14分 其它解法请参照给分.20.解：(1)设(,)P x y ,由1(3,0)F -、2(3,0)F 得1(3,)PF x y =---uuu r , 2(3,)PF x y =--uuu r.∴212(3)(3)PF PF x x y ⋅=-+-+uuu r uuu r 223x y =+-，---------------------2分由22221x y a b +=得2222(1)x y b a=- ∴222122(1)3x PF PF x b a ⋅=+--uuu r uuu r 22233x b a=+-，------------------------4分∵220x a ≤≤，∴当22x a =，即x a =±时，12PF PF ⋅uuu r uuu r有最大值，即212max ()331PF PF b ⋅=+-=uuu r uuu r ，---------------------------------------6分∴21b =，2224a c b =+=，∴所求椭圆C 的方程为2214x y +=.------------------------------------7分 其它解法请参照给分.（2）假设存在直线l 满足题设，设1122(,),(,)D x y E x y ，将y kx m =+代入2214x y +=并整理得 222(14)8440k x kmx m +++-=，------------------------------------------------------------8分由222222644(14)(44)16(41)0k m k m m k ∆=-+-=--->，得2241k m +>-----------①又122814kmx x k+=-+--------------------10分 由||||AD AE =可得2222112212121212(1)(1)()(2)()()0x y x y x x x x y y y y -+=-+⇒-+-+-+=121212122()0y y x x y y x x -⇒+-++=-212(1)()220k x x km ⇒+++-=228(1)22014kmk km k⇒-++-=+ 化简得2143k m k+=-------------②------------------------------------------12分将②代入①得2221441()3k k k++> 化简得42222010(41)(51)0k k k k +->⇒+->，解得55k >或55k <- 所以存在直线l ，使得||||AD AE =，此时k 的取值范围为55(,)(,)55-∞-⋃+∞．-------14分 21.解：（1）当1k =-时，321()313f x x x x =+-+，---------------------------1分 则2'()23f x x x =+-(1)(3)x x =-+，令'()0f x =，∵[0,6]x ∈ 得1,x =----------------------------------2分 且()f x 在[0,1]上单调递减，在[1,6]上单调递增， ∵2(0)1,(1),(6)973f f f ==-=， ∴()f x 在[0,6]上的最大值为97，最小值为23-.------------------------4分 （2） ∵()2'2(21)3(2)f x x k x k k =-+++=(3)[(2)]x k x k --+，----------------5分当1k =时，2'()(3)0f x x =-≥，∴函数()f x 的单调递增区间为(,)-∞+∞；---6分当1k >时，32k k >+，由'()0f x >解得3x k >或2x k <+，由'()0f x <得23k x k +<<， ∴函数()f x 的单调递增区间为(3,)k +∞和(,2)k -∞+，递减区间为(2,3)k k +；----7分 当1k <时，32k k <+，由'()0f x >解得2x k >+或3x k <，由'()0f x <得32k x k <<+， ∴函数()f x 的单调递增区间为(3,)k +∞和(,2)k -∞+；递减区间为(3,2)k k +.-----9分 （3）由()'(3)[(2)]0f x x k x k =--+=得122,3x k x k =+=，--------------------------------------------------10分 ①当12x x =时，有231k k k +=⇒=，此时123(0,6)x x ==∈，函数'()f x 在(0,6)上有唯一的零点，∴1k =为所求；----------------------11分 ②当12x x >时，有231k k k +>⇒<，此时213x x <<，∵函数'()f x 在(0,6)上有唯一的零点，得2103x x ≤<<，即3023k k ≤<+<，解得20k -<≤，-----------------12分 ③当12x x <时，有231k k k +<⇒>，此时213x x >>， ∵函数'()f x 在(0,6)上有唯一的零点，得1236x x <<≤，即3263k k <+<≤，解得24k ≤<，------------------13分 综上得实数k 的取值范围为是：20k -<≤或1k =或24k ≤<.----------------14分。
深圳市翠园中学高三9月月考语文试题 (答案)
2018－2019学年第一学期高三综合测试高三语文试题答案2018年9月5日1．［内容理解］（3分）C（中国逻辑中的对象语言也是汉语自然语言。
）2．［论证分析］（3分）A（文章是以中国逻辑为研究对象，引用名家等各派学说，论证中国逻辑的独创性。
）3．［分析推断］（3分）A（B项，西方逻辑并非一直采用形式化的人工语言。
C项，“意以象尽，象以言著”意思是语言可以塑造形象，表达思想情意。
D项，关系错置，“有助于我们更谁确深刻地理解中华文化的内涵和意蕴”的是“对中国逻辑特质的理解和再认识”。
“理解中华文化的内涵和意蕴”，在此基础上“树立文化自信”。
）4．［分析鉴赏］（3分）B（“对杀鸡的不解”，错。
双喜是理解红影杀鸡的行为的，虽然是“皱着眉”。
5．小说叙述双喜一次又一次成鸡汤送人，这样的情节安排有什么作用，请结合作品简要分析①双喜将鸡汤送给爹、媳妇，他们都没有喝而是“指了指村外”，突出表现了老百姓对解放军的尊敬、爱戴与感激之情。
②类似的情节重复出现，形成层次分明的叙述节奏，强化了小说的主旨；③重复中的变化，又给读者带来新鲜的阅读感受。
［6分。
每点2分。
意思对即可。
注意小说的五个要点：人物、情节、环境、主题、读者。
］6．答案示例一：“陈官庄的枪声”。
①题目点明了故事发生的背景，小说中多处出现的陈官庄的枪炮声，揭示了战争给民众带来的深重灾难；②从而说明了双喜、红影等普通民众支持解放军的根本原因。
③“陈官庄的枪声”比较醒目，带有悬念，能吸引读者阅读。
答案示例二：“1948年的鸡汤”。
①该题目概括了小说的主要情节，突出小说中双喜炖鸡汤送解放军的中心内容；②凸显了民众支持解放军这一主题。
③“1948年”又有怀旧的意味，“鸡汤”给人温暖的感觉，让读者遐想。
［6分。
表明观点，1分；答出一点理由2分，两点4分，三点5分。
若仅从反面分析，如：“1948年的鸡汤”中的“1948年”指向不明，容易让人联想为贫穷年代，而“鸡汤”又理解为贫寒时代的温暖，不能够鲜明地体现小说中的军民鱼水深情这一主旨。
广东省深圳市翠园中学高三英语第三次模拟考试试题
2015届翠园中学高三第三次模拟考试英语时间：120分钟满分：135分I.语言知识及应用（共两节，满分45分）第一节完型填空（共15小题；每小题2分，满分30分）阅读下面短文，掌握其大意，然后从1~15各题所给的A、B、C和D中，选出最佳选项，并在答题卡上将该项涂黑。
A seven-year-old boy, with his family, was inspecting a new car, one with a metal strip (条纹) looking like woo d. “Dad,” the boy whispered, “don’t 1 this because wood rot.” He was surprised when his father started laughing. Then, when the father 2 the boy’s remark with the salesman, and the salesman laughed, the boy felt ashamed. Some 30 years later, now a father himself, the man often thinks of this 3 whenever his own children say something that is unintentionally (无心的) funny.Most parents are 4 by such reactions because they don’t understand how deeply a child fears shame. “All too often we don’t see or hear what is really 5 our children,” says Kaoru Yamamoto, a psychologist at the University of Colorado at Denver.Yamamoto’s surveys show that children are afraid of losing 6 : being thought of as unattractive, stupid or dishonest. It is more troubling to wet their pants in class, get a poor score or 7 a grade than it is to be faced with a competitive baby brother or sister—situations a parent might 8 to be most disturbing. For a child, a blow (打击) to self-esteem, the sense of being worthy, is a 9 thing to bear.The fear comes from the experience of being lost in a(n) 10 place, or of seeing their parents fight, 11 when there is violence. Between two thirds and three quarters of the children surveyed have experienced the 12 of parental fighting, and it 13 them afraid that their mother and father are going to get divorced and just the noise of the quarrel can be frightening.“In listening to children, it is14 not to be touched by their sense of vulnerability(脆弱),” says Yamamoto. “They are afraid of being left alone, fearful of what lies ahead and uncertain of what they can do. They are fundamentally dependent on 15 in the face of upsetting and unpredictable events.”1. A. buy B. believe C. accept D. mind2. A. started B. spared C. shared D. replaced3. A. occasion B. fun C. accident D. event4. A. delighted B. puzzled C. frightened D. challenged5. A. interesting B. spoiling C. inspiring D. troubling6. A. love B. courage C. faceD. freedom7. A. repeat B. stay C. leave D. change8. A. arrange B. intend C. expect D.imagine9. A. simple B. pleasant C. terribleD. hopeless10. A. strange B. familiar C. open D. remote11. A. mostly B. naturally C. basically D. especially12. A. result B. pain C. trouble D. noise13. A. leaves B. warns C. finds D. keeps14. A. funny B. difficult C. true D. possible15. A. teachers B. neighbors C. friends D.adults第二节语法填空（共10小题；每小题1.5分，满分15分）阅读下面短文，按照句子结构的语法性和上下文连贯的要求，在空格处填入一个适当的词或使用括号中词语的正确形式填空，并将答案填写在答题卡标号为16~25的相应位置上。
深圳市罗湖区翠园中学(高中部)2018-2019学年上学期期中高考数学模拟题
深圳市罗湖区翠园中学（高中部）2018-2019学年上学期期中高考数学模拟题班级__________ 座号_____ 姓名__________ 分数__________一、选择题（本大题共12小题，每小题5分，共60分.每小题给出的四个选项中，只有一项是符合题目要求的.）1． “”是“”的（ ）24x ππ-<≤tan 1x ≤A.充分不必要条件 B.必要不充分条件C.充要条件D.既不充分也不必要条件【命题意图】本题主要考查充分必要条件的概念与判定方法，正切函数的性质和图象，重点是单调性.2． 已知全集，，，则有（ ）U R ={|239}xA x =<≤1{|2}2B y y =<≤A ．B ．C ．D ．A ØB A B B = ()R A B ≠∅ ð()R A B R= ð3． 为了解决低收入家庭的住房问题，某城市修建了首批108套住房，已知三个社区分别有低收入家C B A ,,庭360户，270户，180户，现采用分层抽样的方法决定各社区所分配首批经济住房的户数，则应从社C 区抽取低收入家庭的户数为（ ）A ．48B ．36C ．24D ．18【命题意图】本题考查分层抽样的概念及其应用，在抽样考查中突出在实际中的应用，属于容易题．4． 如右图，在长方体中，=11，=7，=12，一质点从顶点A 射向点，遇长方体的面反射（反射服从光的反射原理），将次到第次反射点之间的线段记为，，将线段竖直放置在同一水平线上，则大致的图形是（ ）AB CD5． 满足下列条件的函数中，为偶函数的是（ ）)(x f )(x f A.B.C. D.()||xf e x =2()x xf e e =2(ln )ln f x x =1(ln )f x x x=+【命题意图】本题考查函数的解析式与奇偶性等基础知识，意在考查分析求解能力.6． 某三棱锥的三视图如图所示，该三棱锥的体积是（ ）A ． 2B ．4C ．D ．3438【命题意图】本题考查三视图的还原以及特殊几何体的体积度量，重点考查空间想象能力及对基本体积公式的运用，难度中等.7． 已知向量，，若，则实数（ ）(,1)a t = (2,1)b t =+ ||||a b a b +=-t =A.B. C. D. 2-1-12【命题意图】本题考查向量的概念，向量垂直的充要条件，简单的基本运算能力．8． 函数是周期为4的奇函数，且在上的解析式为，则()()f x x R Î02[,](1),01()sin ,12x x x f x x x ì-££ï=íp <£ïî（ ）1741()()46f f +=A ．B ．C ．D ．71691611161316【命题意图】本题考查函数的奇偶性和周期性、分段函数等基础知识，意在考查转化和化归思想和基本运算能力．9． 已知全集，集合，集合，则集合为R U ={|||1,}A x x x R =≤∈{|21,}xB x x R =≤∈U AC B （ ） A.B.C.D.]1,1[-]1,0[]1,0()0,1[-【命题意图】本题考查集合的运算等基础知识，意在考查运算求解能力.10．已知函数f （x ）＝若f （－6）＋f （log 26）＝9，则a 的值为（ ）{log 2（a －x ），x ＜12x ，x ≥1)A ．4B ．3C ．2D ．111．已知，，则“”是“”的（）α[,]βππ∈-||||βα>βαβαcos cos ||||->-A. 充分必要条件 B. 充分不必要条件 C. 必要不充分条件D. 既不充分也不必要条件【命题意图】本题考查三角函数的性质与充分必要条件等基础知识，意在考查构造函数的思想与运算求解能力.12．某大学的名同学准备拼车去旅游，其中大一、大二、大三、大四每个年级各两名，分乘甲、乙两辆汽8车，每车限坐名同学（乘同一辆车的名同学不考虑位置），其中大一的孪生姐妹需乘同一辆车，则乘44坐甲车的名同学中恰有名同学是来自同一年级的乘坐方式共有（ ）种.42A ．B ．C ．D ．24184836【命题意图】本题考查排列与组合的基础知识，考查学生分类讨论，运算能力以及逻辑推理能力．所示的框图，输入，则输出的数等于14．设α为锐角， =（cos α，sin α），=（1，﹣1）且•=，则sin （α+）= ．15．设向量a ＝（1，－1），b ＝（0，t ），若（2a ＋b ）·a ＝2，则t ＝________．16．自圆：外一点引该圆的一条切线，切点为，切线的长度等于点到C 22(3)(4)4x y -++=(,)P x y Q P 原点的长，则的最小值为（ ）O PQ A ．B ．3C ．4D ．13102110【命题意图】本题考查直线与圆的位置关系、点到直线的距离，意在考查逻辑思维能力、转化能力、运算求解能力、数形结合的思想．三、解答题（本大共6小题，共70分。
【考试必备】2018-2019年深圳市翠园中学高中部初升高自主招生模拟考试英语试题及答案【精品试卷】
深圳市翠园中学高中部2018-2019年自主招生考试英语模拟试卷本试题分试题卷和答题卡两部分。
试题卷共8页。
满分150分，考试时间100分钟。
注意事项：1．答题前，考生务必将自己的姓名、考号、用0.5毫米的黑色墨水签字笔填写在答题卡上，并认真核对。
2．1-50题使用2B铅笔填涂在答题卡对应题目标号的位置上，非选择题用0.5毫米的黑色墨水签字笔书写在答题卡的对应位置。
在草稿纸、试题卷上答题无效。
3．考试结束后，将试题卷，答题卡一并交回。
第Ⅰ卷（选择题，共100 分）第一部分：英语知识运用（共两节，满分60分）第一节：单项填空（共15小题，每小题2分，满分30分）从（ A、B、C、D)四个选项中选出一个可以填入空白处的最佳选项，并在答题卡上将该项涂黑。
1. He was told that ____10:00 bus would take him to Mianyang in time toreach ____Nanshan High school.A. the; /B. the; aC. a; theD. /; the2. Mother was so angry at all I was doing ____she walked out.A. whichB. whatC. thatD. as3. ---Who is late for class again?--- ____you ask? Tim, of course.A. CanB. WouldC. CouldD. Need4. The traffic in the city was ____today, so as you guess, Mary got homefar earlier than usual.A. heavyB. lightC. weakD. scare5. When she was awake, she found that she was standing on____seemed tobe a piece of stone.A. thatB. whichC. whatD. it6. It is difficult for most of us to eat better, exercise more, and sleepenough, ____we know we should.A. as ifB. even thoughC. unlessD. before7. Starting a business is one thing, while keeping it running smoothlyis quite____.A. the otherB. anotherC. neitherD. others8. Let’s learn to use the problem we are facing____a stepping stone tofuture success.A. toB. forC. asD. by9. Grandma found it increasingly difficult to read, for her eyesight wasbeginning to____.A. disappearB. fallC. failD. damage10.---I hear you are working at the Smith’s.---Yes, I _____ there for about three months.A. workedB. have been workingC. was workingD. amworking11.On the wall ____many pictures Mary drew during her childhood.A. hangB. hangsC. is hungD. are hung12.While walking along the bank, he fell into the river but fortunatelyhe was____by a passing boat.A. taken upB. picked upC.turned upD. made up13.Eyes are known ____a powerful part of human body, known as the windowof the heart.A. beingB. having beenC. to beD. to have beenually John would be late for meetings. But this time, ____to mysurprise, he arrived on time.A. littleB. muchC. greatD. even15.---Excuse me, Mum, but I am going to the club to meet my friends inthe football team.---OK. ____________.A. Good luckB. CongratulationsC. You’re welcomeD. Havefun第二节：完形填空（共15小题，每小题2分，满分30分）阅读下列短文，从短文后各题所给的( A、B、C、D)四个选项中选出能填入相应空白的最佳选项，并在答题卡上将该项涂黑。
深圳市罗湖区笋岗中学2018-2019学年高三上学期第三次月考试卷数学含答案
深圳市罗湖区笋岗中学2018-2019学年高三上学期第三次月考试卷数学含答案班级__________ 座号_____ 姓名__________ 分数__________一、选择题（本大题共12小题，每小题5分，共60分.每小题给出的四个选项中，只有一项是符合题目要求的.）1． 下列正方体或四面体中，P 、Q 、R 、S 分别是所在棱的中点，这四个点不共面的一个图形是 （ ）2． 在正方体1111ABCD A B C D -中，M 是线段11A C 的中点，若四面体M ABD -的外接球体积为36p ， 则正方体棱长为（ ）A ．2B ．3C ．4D ．5【命题意图】本题考查以正方体为载体考查四面体的外接球半径问题，意在考查空间想象能力和基本运算能力．3． 已知函数f （x ）＝⎩⎨⎧a x －1，x ≤1log a1x ＋1，x ＞1（a ＞0且a ≠1），若f （1）＝1，f （b ）＝－3，则f （5－b ）＝（ ） A ．－14B ．－12C ．－34D ．－544． 已知函数，函数，其中b ∈R ，若函数y=f （x ）﹣g （x ）恰有4个零点，则b 的取值范围是（ ）A ．B ．C ．D ．5． 棱台的两底面面积为1S 、2S ，中截面（过各棱中点的面积）面积为0S ，那么（ ） A ．0122S S S = B ．012S S S = C ．0122S S S =+ D ．20122S S S =6． 由两个1，两个2，两个3组成的6位数的个数为（ ）A ．45B ．90C ．120D ．3607． 若P 是以F 1，F 2为焦点的椭圆=1（a ＞b ＞0）上的一点，且=0，tan ∠PF 1F 2=，则此椭圆的离心率为（ ）A ．B ．C ．D ．8． 已知向量=（﹣1，3），=（x ，2），且，则x=（ ）A ．B ．C ．D ．9． 以的焦点为顶点，顶点为焦点的椭圆方程为（ ）A ．B ．C ．D ．10．如图甲所示， 三棱锥P ABC - 的高8,3,30PO AC BC ACB ===∠= ，,M N 分别在BC 和PO 上，且(),203CM x PN x x ==∈（，，图乙的四个图象大致描绘了三棱锥N AMC -的体积y 与 的变化关系，其中正确的是（ ）A ．B ． C. D ．1111] 11．若复数满足71i i z+=（为虚数单位），则复数的虚部为（ ） A ．1 B ．1- C ． D ．i -12．设0＜a ＜1，实数x ，y 满足，则y 关于x 的函数的图象形状大致是（ ）A ．B ．C ．D ．二、填空题（本大题共4小题，每小题5分，共20分.把答案填写在横线上）13．在直角坐标系xOy 中，已知点A （0，1）和点B （﹣3，4），若点C 在∠AOB 的平分线上且||=2，则= ．14．数列{ a n }中，a 1＝2，a n ＋1＝a n ＋c （c 为常数），{a n }的前10项和为S 10＝200，则c ＝________．15．函数1()lg(1)1f x x x=++-的定义域是 ▲ ．16．若正方形P 1P 2P 3P 4的边长为1，集合M={x|x=且i ，j ∈{1，2，3，4}}，则对于下列命题： ①当i=1，j=3时，x=2； ②当i=3，j=1时，x=0；③当x=1时，（i ，j ）有4种不同取值； ④当x=﹣1时，（i ，j ）有2种不同取值； ⑤M 中的元素之和为0．其中正确的结论序号为 ．（填上所有正确结论的序号）三、解答题（本大共6小题，共70分。
深圳市罗湖外语学校2018-2019学年高三上学期第三次月考试卷数学含答案
深圳市罗湖外语学校2018-2019学年高三上学期第三次月考试卷数学含答案班级__________ 座号_____ 姓名__________ 分数__________一、选择题（本大题共12小题，每小题5分，共60分.每小题给出的四个选项中，只有一项是符合题目要求的.）1． 已知2a =3b =m ，ab ≠0且a ，ab ，b 成等差数列，则m=（ ）A ．B ．C ．D ．62． 在ABC ∆中，角A ，B ，C 的对边分别是，，，BH 为AC 边上的高，5BH =，若2015120aBC bCA cAB ++=，则H 到AB 边的距离为（ ）A ．2B ．3 C.1 D ．43． 某工厂产生的废气经过过虑后排放，过虑过程中废气的污染物数量P （单位：毫克/升）与时间t （单位： 小时）间的关系为0e ktP P -=（0P ，k 均为正常数）．如果前5个小时消除了10%的污染物，为了消除27.1% 的污染物，则需要（ ）小时.A.8B.10C. 15D. 18【命题意图】本题考指数函数的简单应用，考查函数思想，方程思想的灵活运用，体现“数学是有用的”的新课标的这一重要思想.4． 下列说法正确的是（ ） A.圆锥的侧面展开图是一个等腰三角形；B.棱柱即是两个底面全等且其余各面都是矩形的多面体；C.任何一个棱台都可以补一个棱锥使他们组成一个新的棱锥；D.通过圆台侧面上的一点，有无数条母线.5． 某几何体的三视图如图所示，则此几何体不可能是（ ）A ．B ．C ．D ．6． 设函数()log |1|a f x x =-在(,1)-∞上单调递增，则(2)f a +与(3)f 的大小关系是（ ）A ．(2)(3)f a f +>B ．(2)(3)f a f +< C. (2)(3)f a f += D ．不能确定7． 已知数列{}n a 是各项为正数的等比数列，点22(2,log )M a 、25(5,log )N a 都在直线1y x =-上，则数列{}n a 的前n 项和为（ ）A ．22n -B ．122n +-C ．21n -D ．121n +-8． 下列函数中，与函数()3x xe ef x --=的奇偶性、单调性相同的是（ ）A ．(ln y x =B ．2y x =C ．tan y x =D ．xy e = 9． 已知d 为常数，p ：对于任意n ∈N *，a n+2﹣a n+1=d ；q ：数列 {a n }是公差为d 的等差数列，则￢p 是￢q 的（ ）A ．充分不必要条件B ．必要不充分条件C ．充要条件D ．既不充分也不必要条件10．复数满足2＋2z 1－i＝i z ，则z 等于（ ） A ．1＋iB ．－1＋iC ．1－iD ．－1－i 11．已知函数f(x)是定义在R 上的奇函数，当x ≥0时，.若,f(x-1)≤f(x),则实数a 的取值范围为A[] B[] C[]D[] 12．一个空间几何体的三视图如图所示，其中正视图为等腰直角三角形，侧视图与俯视图为正方形， 则该几何体的体积为（ ）A ．64B ．32C ．643D ．323二、填空题（本大题共4小题，每小题5分，共20分.把答案填写在横线上）13．计算121(lg lg 25)1004--÷= ▲ ． 14．设()x x f x e=，在区间[0,3]上任取一个实数0x ，曲线()f x 在点()00,()x f x 处的切线斜率为k ，则随机事件“0k <”的概率为_________. 15．已知数列{}n a 中，11a =，函数3212()3432n n a f x x x a x -=-+-+在1x =处取得极值，则 n a =_________.16．在ABC ∆中，已知角C B A ,,的对边分别为c b a ,,，且B c C b a sin cos +=，则角B为 .三、解答题（本大共6小题，共70分。
深圳市翠园中学2018届高三上学期第三次月考(理数)
深圳市翠园中学2018届高三上学期第三次月考数学（理科）第I 卷一、选择题：本大题共12小题，每小题5分，在每小题给出的四个选项中，只有一项是符合题目要求的。
1．已知集合{||2,}A x x x R =≤∈},{|4,}B x x x Z =≤∈,则A B ⋂=(A)(0,2) (B)[0,2] (C){0,2] (D){0,1,2} 2．已知复数23(13)iz i +=-，z 是z 的共轭复数，则z z •= A.14 B.12C.1D.2 3．曲线2xy x =+在点（-1，-1）处的切线方程为（A ）y=2x+1 (B)y=2x-1 C y=-2x-3 D.y=-2x-24．如图，质点P 在半径为2的圆周上逆时针运动，其初始位置为P 0（2，-2），角速度为1，那么点P 到x 轴距离d 关于时间t 的函数图像大致为5．已知命题1p ：函数22xxy -=-在R 为增函数；2p ：函数22xxy -=+在R 为减函数，则在命题1q ：12p p ∨，2q ：12p p ∧，3q ：()12p p ⌝∨和4q ：()12p p ∧⌝中，真命题是（A ）1q ，3q （B ）2q ，3q （C ）1q ，4q （D ）2q ，4q6．某种种子每粒发芽的概率都为0.9，现播种了1000粒，对于没有发芽的种子，每粒需再补种2粒，补种的种子数记为X ，则X 的数学期望为（A ）100 （B ）200 （C ）300 （D ）400 7．如果执行右面的框图，输入5N =，则输出的数等于（A ）54 （B ）45（C ）65（D ）568．设偶函数()f x 满足3()8(0)f x x x =-≥，则{|(2)0}x f x ->=(A) {|24}x x x <->或 (B) {|04}x x x <>或 (C) {|06}x x x <>或 (D) {|22}x x x <->或9．若4cos 5α=-，α是第三象限的角，则1tan21tan 2αα+=- (A) 12- (B) 12(C) 2 (D) -210．设三棱柱的侧棱垂直于底面，所有棱长都为a ，顶点都在一个球面上，则该球的表面积为(A) 2a π (B)273a π (C)2113a π (D) 25a π 11．已知函数|lg |,010,()16,10.2x x f x x x <≤⎧⎪=⎨-+>⎪⎩若,,a b c 互不相等，且()()(),f a f b f c ==则abc的取值范围是(A) (1,10) (B) (5,6)(C) (10,12)(D) (20,24)12．已知双曲线E 的中心为原点，(3,0)P 是E 的焦点，过F 的直线l 与E 相交于A ，B 两点，且AB 的中点为(12,15)N --,则E 的方程式为(A)22136x y -= (B) 22145x y -= (C) 22163x y -= (D) 22154x y -= 第Ⅱ卷二、填空题：本大题共4小题，每小题5分。
深圳市罗湖中学2018-2019学年高三上学期第三次月考试卷数学含答案
深圳市罗湖中学2018-2019学年高三上学期第三次月考试卷数学含答案 班级__________ 座号_____ 姓名__________ 分数__________一、选择题（本大题共12小题，每小题5分，共60分.每小题给出的四个选项中，只有一项是符合题目要求的.）1． 高考临近，学校为丰富学生生活，缓解高考压力，特举办一场高三学生队与学校校队的男子篮球比赛．由于爱好者众多，高三学生队队员指定由5班的6人、16班的8人、33班的10人按分层抽样构成一个12人的篮球队．首发要求每个班至少1人，至多2人，则首发方案数为（ ） A ．720 B ．270 C ．390 D ．3002． 已知实数a ，b ，c 满足不等式0＜a ＜b ＜c ＜1，且M=2a ，N=5﹣b ，P=（）c ，则M 、N 、P 的大小关系为（ ）A ．M ＞N ＞PB ．P ＜M ＜NC ．N ＞P ＞M3． 在等差数列{}n a 中，已知4816a a +=，则210a a +=（ ）A ．12B ．16C ．20D ．24 4． 已知全集I={1，2，3，4，5，6}，A={1，2，3，4}，B={3，4，5，6}，那么∁I （A ∩B ）等于（ ） A ．{3，4} B ．{1，2，5，6} C ．{1，2，3，4，5，6} D ．∅5． 已知f （x ）在R 上是奇函数，且f （x+4）=f （x ），当x ∈（0，2）时，f （x ）=2x 2，则f （7）=（ ） A ．﹣2 B ．2 C ．﹣98 D ．986． 设函数()()21xf x e x ax a =--+，其中1a <，若存在唯一的整数，使得()0f t <，则的 取值范围是（ ）A ．3,12e ⎡⎫-⎪⎢⎣⎭ B ．33,24e ⎡⎫-⎪⎢⎣⎭ C ．33,24e ⎡⎫⎪⎢⎣⎭ D ．3,12e ⎡⎫⎪⎢⎣⎭1111] 7． 已知i z 311-=，i z +=32，其中i 是虚数单位，则21z z的虚部为（ ）A ．1-B ．54C ．i -D ．i 54【命题意图】本题考查复数及共轭复数的概念，复数除法的运算法则，主要突出对知识的基础性考查，属于容易题.8． 已知2,0()2, 0ax x x f x x x ⎧+>=⎨-≤⎩，若不等式(2)()f x f x -≥对一切x R ∈恒成立，则a 的最大值为（ ）A ．716-B ．916-C ．12-D ．14-9． 已知命题p ：存在x 0＞0，使2＜1，则￢p 是（ ）A ．对任意x ＞0，都有2x ≥1B ．对任意x ≤0，都有2x ＜1C ．存在x 0＞0，使2≥1D ．存在x 0≤0，使2＜110．已知，，那么夹角的余弦值（ ）A ．B ．C ．﹣2D ．﹣11．已知命题1:0,2p x x x∀>+≥，则p ⌝为（ ） A ．10,2x x x ∀>+< B ．10,2x x x ∀≤+< C ．10,2x x x ∃≤+< D ．10,2x x x∃>+<12．由两个1，两个2，两个3组成的6位数的个数为（ ） A ．45B ．90C ．120D ．360二、填空题（本大题共4小题，每小题5分，共20分.把答案填写在横线上）13．在等差数列{}n a 中，17a =，公差为d ，前项和为n S ，当且仅当8n =时n S 取得最大值，则d 的取值范围为__________.14．已知过双曲线22221(0,0)x y a b a b-=>>的右焦点2F 的直线交双曲线于,A B 两点，连结11,AF BF ，若1||||AB BF =，且190ABF ∠=︒，则双曲线的离心率为（ ）A ．5-BC ．6- D【命题意图】本题考查双曲线定义与几何性质，意要考查逻辑思维能力、运算求解能力，以及考查数形结合思想、方程思想、转化思想．15．如果实数,x y 满足等式()2223x y -+=，那么yx的最大值是 ． 16．（本小题满分12分）点M （2pt ，2pt 2）（t 为常数，且t ≠0）是拋物线C ：x 2＝2py （p ＞0）上一点，过M 作倾斜角互补的两直线l 1与l 2与C 的另外交点分别为P 、Q .（1）求证：直线PQ 的斜率为－2t ；（2）记拋物线的准线与y 轴的交点为T ，若拋物线在M 处的切线过点T ，求t 的值．三、解答题（本大共6小题，共70分。
广东省深圳市翠园中学高三化学月考试题含解析
广东省深圳市翠园中学高三化学月考试题含解析一、单选题（本大题共15个小题，每小题4分。
在每小题给出的四个选项中，只有一项符合题目要求，共60分。
）1. 用滴定法测定Na2CO3(含NaCl杂质)的质量分数，下列操作会引起测定值偏高的是A．试样中加入酚酞作指示剂，用标准酸液进行滴定B．滴定管用蒸馏水洗涤后，直接注入标准酸液进行滴定C．锥形瓶用蒸馏水洗涤后，壹接加入待测溶液进行滴定D．滴定管用蒸馏水洗涤后，直接注入待测液，取20.00 mL进行滴定参考答案：B本题考查滴定实验操作，意在考查考生实验能力和误差分析能力。
A项、C项操作对测定结果无影响、B项操作导致标准液变稀，消耗体积变大，使测得结果偏高、D项操作导致待测液浓度变小，因此测定结果偏低，故答案为：B。
2. 下列物质中其电子式可用表示的是A．HClO B．NaHS C．KOH D．KClO参考答案：D略3. 为提升电池循环效率和稳定性，科学家近期利用三维多孔海绵状Zn（3D?Zn）可以高效沉积ZnO 的特点，设计了采用强碱性电解质的3D?Zn—NiOOH二次电池，结构如下图所示。
电池反应为Zn(s)+2NiOOH(s)+H2O(l) ZnO(s)+2Ni(OH)2(s)。
下列说法错误的是A. 三维多孔海绵状Zn具有较高的表面积，所沉积的ZnO分散度高B. 充电时阳极反应为Ni(OH)2(s)+OH?(aq)?e?=NiOOH(s)+H2O(l)C. 放电时负极反应为Zn(s)+2OH?(aq)?2e?=ZnO(s)+H2O(l)D. 放电过程中OH?通过隔膜从负极区移向正极区参考答案：D【详解】A、三维多孔海绵状Zn具有较高的表面积，吸附能力强，所沉积的ZnO分散度高，A正确；B、充电相当于是电解池，阳极发生失去电子的氧化反应，根据总反应式可知阳极是Ni(OH)2失去电子转化为NiOOH，电极反应式为Ni(OH)2(s)＋OH－(aq)－e－＝NiOOH(s)＋H2O(l)，B正确；C、放电时相当于是原电池，负极发生失去电子的氧化反应，根据总反应式可知负极反应式为Zn(s)＋2OH－(aq)－2e－＝ZnO(s)＋H2O(l)，C正确；D、原电池中阳离子向正极移动，阴离子向负极移动，则放电过程中OH－通过隔膜从正极区移向负极区，D错误。
深圳市高三上学期语文第三次月考试卷
深圳市高三上学期语文第三次月考试卷姓名:________ 班级:________ 成绩:________一、选择题 (共1题；共6分)1. （6分） (2019高二下·集宁期中) 阅读下面的文字，完成下列小题①我非常喜欢读林语堂先生的《苏东坡传》，前后读过多少遍都记不清了，（）。
语堂先生酷爱苏东坡的黄州诗文，因此由诗文渲染开去，由酷爱渲染开去，渲染得通体风雅、圣洁。
其实，就我所知，苏东坡在黄州还是很凄苦的，优美的诗文，是对凄苦的挣扎和超越。
②日常生活，在家人接来之前，大多是白天睡觉，晚上一个人出去溜达，见到淡淡的土酒也喝一杯，但绝不喝多，怕醉后失言。
他真的害怕了吗？也是也不是。
他怕的是麻烦，而绝不怕大义凛然地为道义、为百姓，甚至为朝廷、为皇帝捐躯。
他经过“乌台诗案”已经明白，一个人蒙受了诬陷即便是死也死不出一个道理来，你找不到的目标，你抓不住的理由。
你想做个的英雄，不知怎么一来把你打扮成了小丑；你想做个的烈士，闹来闹去却成了一个深深忏悔的俘虏。
无法洗刷，无处辩解，更不知如何来提出自己的抗议，发表自己的宣言。
③这是一种真正精神上的孤独无告，正是这种难言的孤独，使他彻底洗去了人生的喧闹，去寻找无言的山水，去寻找远逝的古人。
现在他即便写诗作文，也不会追求社会轰动了。
他在寂寞中反省过去，觉得自己以前最大的毛病是才华外露，缺少自知之明。
苏东坡的这种自省的原因，是一种走向乖巧的心理调整，是一种极其诚恳的自我剖析，目的是想找回一个真正的自己。
他在无情地剥除自己身上每一点异己的成分，哪怕这些成分曾为他带来过官职、荣誉和名声。
他渐渐回归于清纯和空灵，在这一过程中，佛教帮了他大忙，使他习惯于淡泊和静定。
艰苦的物质生活，又使他不得不亲自垦荒种地，体味着自然和生命的原始意味。
（1）下列在文中第一段括号内补写的语句，最恰当的一是（）A . 总觉得语堂先生生动逼真地再现了苏东坡在黄州的境遇和心态B . 总觉得语堂先生真正解读了苏东坡在黄州的境遇和心态C . 但每次总觉得语堂先生把苏东坡在黄州的境遇和心态写得太理想了D . 但每次总觉得语堂先生把苏东坡在黄州的境遇和心态写得失真了（2）依次填入文中第二段横线上的成语，全都恰当的一项是（）A . 从容赴死慷慨陈词坚贞不屈义无反顾B . 慷慨陈词从容赴死义无反顾坚贞不屈C . 慷慨淋漓从容不迫视死如归临危不惧D . 从容不迫慷慨淋漓临危不惧视死如归（3）文中第三段文字横线部分有语病，下列修改最恰当的一项是（）A . 苏东坡的这种自省的原因，不是一种走向乖巧的心理调整，而是一种极其诚恳的自我剖析，目的是想找回一个真正的自己。
2019-2020学年深圳市翠园中学高中部高三英语月考试卷及答案解析
2019-2020学年深圳市翠园中学高中部高三英语月考试卷及答案解析第一部分阅读（共两节，满分40分）第一节（共15小题；每小题2分，满分30分）阅读下列短文，从每题所给的A、B、C、D四个选项中选出最佳选项ASome young people win attention because of their good looks or their singing ability. A much smaller number gain fame because they have done something important and worthwhile with their abilities. Rishab Jain is among the latter. In 2018, 13-year-oldRishab developed a way to use AI technology to help pancreatic(胰腺的) cancer patients and won the3MYoung Scientist Challenge, a nationwide middle-school science competition, and its $25,000 prize.In the last stage of the contest, Rishab competed againstnine other finalists at the 3M Innovation Center(创新中心) in St.Paul,Minnesota. Leading up to the big meet, each finalist had partnered with a scientist to further develop their inventions.Rishab explains what led him to create his invention. First,a family friend died of cancer. Then Rishab learned about how deadly pancreatic cancer is, and that its low survival rate is due to how difficult it is to treat. "I'm also into programming, so I was learning about AI technology. I decided to try to solve a real-world problem using it."His winnings have been put in further research and in his nonprofit Samyak Science Society, which helps poor children enter the STEM (science, technology, engineering and math) education. Rishab is also raising awareness about pancreatic cancer. These efforts make him quite different from teenagers of his age. Considering becoming a biomedical engineer or a doctor一or both, he has also put some money aside to further his own learning. Almost certainly the doors of higher education will open wide to him before he even knocks.That's an outstanding outlook for one so young. Rashib is committed to helping very sick people in need. He is also providing teenagers of his age with a much-needed model of what kinds of things youth can achieve.1. What can we learn about the 3M Young Scientist Challenge in 2018?A. It was intended to solve medical problems.B. It was a nationwide AI competition for teenagers.C. It offered the finalists an opportunity to work with scientists.D. It allowed the finalists to learn AI technology in the 3M center.2. How did Rishab win the 3M Young Scientist Challenge?A.He showed excellent programming ability.B. He figured out the survival rate of pancreatic cancer.C. He introduced poor children to STEM education.D. He applied AI technology to treating pancreatic cancer.3. Which of the following best describes Rishab?A. Talented and caring.B. Independent and humorous.C. Responsible and patient.D. Polite and inspiring.BThe relationship between humans and the Amazon Rainforest has not always been a harmonious one. However, recent research suggests that the native peoples ofthe Putumayo region helped to protect the rainforest, leaving it unchanged for 5,000 years. Perhaps humans’ coexisting with nature is possible after all.The study, published in PNAS, looked at soil samples in the Putumayo region of the Amazon in Peru to find how humans influenced the land. The researchers found that the trees still growing in the region today have been growing there for the last 5,000 years — evidence that the area has not been home to cities and farmland in that time. Traces of charcoal(木炭) found in the, soil, however, indicate that people did live there; they just did so in a way that had minimum influence on their environment.To come to these conclusions the team dug a 0.6-0.9 meter deep column into the ground, taking samples of soilfrom different heights along the column. Back in the lab, samples were carbon- dated to determine their age and then sorted under a microscope to look for microscopic mineral particles, known as phytoliths (植硅体). Phytoliths are essential evidence of plants— they remained in the soil thousands of years after the plant died. So researchers can use them to tell which plants have grown in an area in the past.Over 5,000 years’ worth of samples, no species loss was detected. These findings suggest that contrary to common belief, the Amazon is not untouched by humans, but rather has been protected by them for thousands of years. The management of the rainforest by native peoples appears to have been vital in preserving its biodiversity and will continue to be important in the fight to prevent it from acollapse.As Nigel Pitman, a co-author on the paper, said: “Since this particular forest is still being protected by native peoples, I hope this study reminds us all how important it is to support their work.”4. How did native peoples deal with the rainforest in the region of Putumayo?A. They always destroyed the rainforest.B. They had a side effect on the rainforest.C. They never lived in the area of the forest.D. They had been in harmony with the forest.5. What did the researchers try to find in the Amazon forest in Peru?A. The diversity of the plants in the rainforest.B. The evidence of human influence on the forest.C. The nutrition of the soil samples in the rainforest.D. The survival age of growing trees in the rainforest.6. What does the underlined word “collapse” mean in Paragraph 4?A. Sudden decrease.B. Bad management.C. Poor preservation.D. Over development.7. What can be inferred from Nigel Pitman's words?A. Native peoples should protectthe rainforest.B. We should help protect the Amazon Rainforest.C. More science research should be done on rainforest.D We should make good use of the Amazon Rainforest.CWith their tiny brains and excellent ability to memorize nectar locations, honeybees are a favorite model organism for studying learning and memory. Such research has indicated that to form long-term memories—ones that last a day or more—the insects need to repeat a training experience at least three times. By contrast, short-and mid-term memories that last seconds to minutes and minutes to hours, respectively, need only a single learning experience.Exceptions to this rule have been observed, however. For example, in some studies, bees formed long-lasting memories after a single learning event. Such results are often regarded as circumstantial anomalies, says Martin Giurfa of the University of Toulouse. But the anomalous findings, together with research showing that fruit flies and ants can form long-term memories after single experiences, aroused Giurfa’s curiosity. Was it possible that honeybees could reliably do the same? Giurfa reasoned that the ability to form long-term memories might depend on the particular type of bee and the experience. Within a honeybee colony, there are nurses, who clean the hive and feed the young; guards, who patrol and protect the hive; and foragers, who search for nectar.While previous studies have tested bees as a whole, Ciurfa and his colleagues focused on foragers, tasking them with remembering an experience relevant to their role: an odor associated with a sugary reward.The researchers observed that a single exposure to a reward-paired odor was enough for most forager beesto remember that specific odor the following day. Many foragers could even remember the odor three day later.The results do not mean that all prior research was wrong, says André Fiala of the University of Göttingen. “People have done the experiments in a different way.” Still, the new results do show that “the commonly held belief that one needs multiple training trials to achieve long-term memory is not always true,” he says, and this “really advances the field.”8. What does the author want to tell us through Paragraph 1?A. A model for memory research.B. The classification of memories.C. New research on learning and memory.D. Previous findings on memory formation.9. Which factor might influence a bee’s memory of an experience, according to Giurfa’s research?A. Whether the bee's role is related.B. Whether the bee is introduced or native.C. How often the bee repeats the experience.D. How long the bee is exposed to the reward.10. What is Andre Fiala’s attitude towards the new results?A. Doubtful.B. Favorable.C. Intolerant.D. Unclear.11. Which of the following is a suitable title for the text?A. Learning and Memory: How Honeybees RememberB. Honeybee Memory: Honeybee Knows What to DoC. Honeybees Remember after Just One LessonD. Honeybees Use Memory for CommunicationDGrowing up as kids we are told to share our toys and notto be selfish. We also live in an age when discussing our feelings is encouraged. But when does it all become too much? With new crazes trending all the time, such as dance challenges and wearing a carpet as a dress, the question is: when can sharing become oversharing on social media?“Oversharing” has become associated with social media, but it isn'texclusiveto this platform. Imagine you head to a party and meet x k w someone. Within five minutes they have revealed private details about their life. While some of us may try to escape these people, according to marriage advisor Carolyn Cole, this form of oversharing could come from a strong desire to connect with someone. But how does this translate to social media?Dr. Christopher Hand, a lecturer in cyberpsychology (网络心理学），says the more details people disclose, the less sympathy we express when things go wrong. It seems that searching for sympathy by oversharing is generallyconsidered as negative rather than the cry for help it could really be.However, Dr. Hand's research also seems to suggest that the more we post on a platform, the more socially attractive we become-provided that the posts that we bang out are positive. Even back in 2015, Gwendolyn Seidman PhD said that we should avoid complaining and being negative online. We should also avoid showing off, especially about our love lives. It makes sense-if your date is going “that well", would you really have time to share a photo with text?So, how can you know if you are oversharing? Well, why not ask your friends in real life. They would probably be happy to tell you if your posts about your breakfast or your complaints about your lack of money really are too much.12. What does the underlined word “exclusive" in paragraph 2 mean?A. Unique.B. Similar.C. Relevant.D. Fundamental.13. Why do some people prefer oversharing at parties?A. To draw others' attention.B. To satisfy others' curiosity.C. To remove negative feelings.D. To develop good relationships.14. Which of the following may Dr. Hand agree with?A. Sharing more details online can attract more sympathy.B. Oversharing negative experiences is equal to crying for help.C. Sharing negative posts can't help one become socially attractive.D. Oversharing isn't likely to happen online when things go wrong.15. According to the text, what should be avoided for online sharing?A. Reflecting on past bad manners.B. Showing a great many expensive goods.C. Writing a recipe for a balanced breakfast.D. Recording unforgettable moments with friends.第二节（共5小题；每小题2分，满分10分）阅读下面短文，从短文后的选项中选出可以填入空白处的最佳选项。
高考专题翠园中学高三第三次模拟考试
侧视图正视图h65高中数学学习材料金戈铁骑整理制作2015届翠园中学高三第三次模拟考试文科数学一、选择题：本大题共10小题，每小题5分，满分50分．在每小题给出的四个选项中，只有一项是符合题目要求的．1．已知{|31,}A x x k k Z ==-∈，则下列表示正确的是A.1A -∉B.11A -∈C. 231k A -∈ D.34A -∉2．已知复数1z i =+，则2(1)z z -=A. 2B. －2C. 22i -D. 22i --3．命题P ：“对2,12x R x x ∀∈+≥”的否定P ⌝为A. 2,12x R x x ∃∈+>B.2,12x R x x ∃∈+≥C. 2,12x R x x ∀∈+<D.2,12x R x x ∃∈+<4．已知1sin()3πα+=，则cos2α= A.79 B.89 C. 79- D.4295. 若01x y <<<，则下列不等式正确的是A ．44y x <B ．33>x y C ．44log log x y < D ．11()()44x y <6．设向量(12)(23)==，，，a b ，若向量λ-a b 与向量(56)=--，c 共线，则λ的值为 A ．43 B ．413 C ．49- D ．4 7．图1中的三个直角三角形是一个体积为330cm 的几何体的三视图，图2否是a i ≥90？n=n+1n=0,i=1否输入a 1，a 2，……，a 12i=i+1开始结束输出n i ≤12？是则侧视图中的h 为A. 5 cmB.6 cmC.7 cmD.8 cm 图18．已知变量,x y 满足约束条件⎪⎩⎪⎨⎧≥-≤+-≤-+0101205x y x y x ，则y x 的最小值是A.1B. 4C.23D.09．下表记录了某学生进入高三以来各次数学考试的成绩 考试第次123456789101112成绩（分） 65 78 85 87 88 99 90 94 93 102 105 116将第1次到第12次的考试成绩依次记为1212,,,a a a L .图2是统计上表中成绩在一定范围内考试次数的一个算法流程图,那么算法流程图输出的结果是A.8B.7C.6D.5 10．已知{1,2,3,4},{1,2,3}a b ∈∈，则关于x 的不等式222(1)0x a x b --+≥的解集为R 的概率为A.14B.12C. 23D. 34二、填空题：本大题共5小题，考生作答4小题，每小题5分，满分20分． （一）必做题（11－13题）11．已知幂函数()y f x =的图象过点1(3,)3，则2log (2)f 的值为 ．12．以点(2,1)-为圆心且与直线3470x y +-=相切的圆的标准方程是 ．13．在△ABC 中，已知角C B A ,,所对的边分别为c b a ,,，且2(cos cos )c a B b A b -=，则s i n s i n AB= ． （二）选做题（14－15题，考生只能从中选做一题）14. (坐标系与参数方程选做题) 在极坐标系(,)ρθ (02)θπ≤<中，曲线(2cos sin )3ρθθ-=与(cos 2sin )1ρθθ+=-的交点的极坐标为 ．15．（几何证明选讲选做题）如图3，点P 在圆O 的直径AB 的 延长线上，且PB=OB=3,PC 切圆O 于C 点，CD ⊥AB 于D 点，N M Po yx则CD 的长为 ． 图3三．解答题：本大题共6小题，满分80分．解答须写出文字说明、证明过程和演算步骤． 16．(本小题满分12分)已知函数()sin()6f x A x πω=+(00)A ω>>，的部分图象如图4示，其中M 1(,0)6-为图象与x 轴的交点，1(,2)3P 为图象的最高点．(1)求A 、ω的值；(2)若2()3f απ=，(,0)3πα∈-，求cos()3πα+的值． 图417．(本小题满分12分)某校为了调查“学业水平考试”学生的数学成绩，随机地抽取该校甲、乙两班各10名同学，获得的数据如下：（单位：分）甲：132，108，112，121，113，121，118，127，118，129； 乙：133，107，120，113，121，116，126，109，129，127.（1）以百位和十位为茎，个位为叶，在图5中作出以上抽取的甲、乙两班学生数学成绩的茎叶图，求出这20个数据的众数，并判断哪个班的平均水平较高；（2）将这20名同学的成绩按下表分组，现从第一、二、三组中，采用分层抽样的方法抽取6名同学成绩作进一步的分析，求应从这三组中各抽取的人数．18．(本小题满分14分)组别 第一 第二 第三 第四分值区间 [100,110) [110,120) [120,130) [130,140]已知等比数列{}n a 满足：0n a >，15a =，n S 为其前n 项和，且13220S S S ，，7成等差数列． （1）求数列{n a }的通项公式； （2）设51525log log log n n b a a a =+++，求数列{1nb }的前n 项和n T ．19．（本小题满分14分）如图6，在三棱锥S ABC -中，侧面SAB 与侧面SAC 均 为等边三角形，2AB =，90BAC ∠=°． （1）证明：SA BC ⊥；（2）求三棱锥S ABC -的体积．图620．(本小题满分14分)已知椭圆C :22221(0)x y a b a b+=>>的焦点分别为1(3,0)F -、2(3,0)F ，P 为椭圆C 上任一点，12PF PF ⋅uuu r uuu r的最大值为1.（1）求椭圆C 的方程；（2）已知点(1,0)A ，试探究是否存在直线:l y kx m =+与椭圆C 交于D 、E 两点，且使得||||AD AE =？若存在，求出k 的取值范围；若不存在，请说明理由.21．(本小题满分14分)已知函数()321(21)3(2)13f x x k x k k x =-++++，其中k 为实数.（1）当1k =-时，求函数()f x 在[0,6]上的最大值和最小值； （2）求函数()f x 的单调区间；（3）若函数()f x 的导函数'()f x 在(0,6)上有唯一的零点，求k 的取值范围.数学(文科)参考答案一、选择题：CADAC ABCBD二、填空题：11. 1-；12.22(2)(1)1x y -++=；13.2；14. 7(2,)4π；15.332. 三、解答题：16．解：（1）由1(,2)3P 为图象的最高点知2A =，---------------------1分又点M 1(,0)6-知函数()f x 的最小正周期114()236T =+=，-----------------------3分 ∵2T πω=∴ωπ=,-------------------------------------------------5分(2)由（1）知，()2sin()6f x x ππ=+由2()3f απ=得1sin()63πα+=，----------------------------------------6分 ∵(,0)3πα∈-∴666πππα-<+<----------------------------------------7分∴2122cos()1sin ()16693ππαα+=-+=-=-------------------------9分 ∵cos()cos()366πππαα+=++cos()cos sin()sin 6666ππππαα=+-+-------------11分∴cos()3πα+2231126132326-=⨯-⨯=------------------------------------------------12分 17．解：（1）甲、乙两班学生数学成绩的茎叶图如右图示：----4分这20个数据的众数为121，----------------------------------5分 乙班的平均水平较高；----------------------------------------7分 （2）由上数据知，这20人中分值落在第一组的有3人，落在第二组的有6人，落在第三组的有9人，-------------9分故应从第一组中抽取的人数为：631369⨯=++，-------10分应从第二组中抽取的人数为：662369⨯=++，--------------------------------11分应从第三组中抽取的人数为：693369⨯=++.-----------------------------------12分18．解：（1）设数列{}n a 的公比为q ，∵13220,,7S S S 成等差数列，3122207.S S S ∴=+-----------------------------------2分即21111112()207()a a q a q a a a q ++=++，化简得225250q q --=，------4分解得：5q =或52q =-------------------------------------------------------------------6分 ∵0n a >，∴52q =-不合舍去，∴111555n n nn a a q --==⨯=.-----------------------------------------7分(2)∵ 51525log log log n n b a a a =+++=1235125log ()log 5123nn a a a n ++++==++++---------------------9分(1)2n n +=，----------------------------------------------------------------------------10分 ∴1n b =211=2()(+11n n n n -+）----------------------------------------------------------------12分 ∴12111n n T b b b =+++111112[(1)()()]2231n n =-+-++-+ 122(1)11nn n =-=++.------------------------------------------14分 19．解：（1）证明：取BC 中点D ，连结SD 、AD ，-----2分 ∵△SAB 与△SAC 均为等边三角形∴SB=SC=AB=AC=SA=2，∴SD BC ⊥,AD BC ⊥-----4分 又SDAD D =∴BC ⊥平面SAD ----------------------5分 ∵SA ⊂平面SAD∴SA BC ⊥-------------------------------------------------7分 （2）∵90BAC ∠=°，AB=AC ， ∴222BC AB ==，------------------------------------8分∵SB=AB ，SC=AC ，BC=BC ，∴△SBC ≌△ABC ，∴90BSC ∠=，-------------------------9分 ∴122SD AD BC === ∵2224SD AD SA +== ∴SD AD ⊥---------------------11分 又SD BC ⊥,BCAD D =∴SD ⊥平面ABC ,------------------------------------------12分 ∴13P ABC ABC V S SD -∆=1122222323=⨯⨯⨯⨯=.----------------14分 其它解法请参照给分.20.解：(1)设(,)P x y ,由1(3,0)F -、2(3,0)F 得1(3,)PF x y =---uuu r , 2(3,)PF x y =--uuu r.∴212(3)(3)PF PF x x y ⋅=-+-+uuu r uuu r 223x y =+-，---------------------2分由22221x y a b +=得2222(1)x y b a=- ∴222122(1)3x PF PF x b a ⋅=+--uuu r uuu r 22233x b a=+-，------------------------4分∵220x a ≤≤，∴当22x a =，即x a =±时，12PF PF ⋅uuu r uuu r有最大值，即212max ()331PF PF b ⋅=+-=uuu r uuu r ，---------------------------------------6分∴21b =，2224a c b =+=，∴所求椭圆C 的方程为2214x y +=.------------------------------------7分 其它解法请参照给分.（2）假设存在直线l 满足题设，设1122(,),(,)D x y E x y ，将y kx m =+代入2214x y +=并整理得 222(14)8440k x kmx m +++-=，------------------------------------------------------------8分由222222644(14)(44)16(41)0k m k m m k ∆=-+-=--->，得2241k m +>-----------①又122814kmx x k+=-+--------------------10分 由||||AD AE =可得2222112212121212(1)(1)()(2)()()0x y x y x x x x y y y y -+=-+⇒-+-+-+=121212122()0y y x x y y x x -⇒+-++=-212(1)()220k x x km ⇒+++-=228(1)22014kmk km k⇒-++-=+ 化简得2143k m k+=-------------②------------------------------------------12分将②代入①得2221441()3k k k++> 化简得42222010(41)(51)0k k k k +->⇒+->，解得55k >或55k <- 所以存在直线l ，使得||||AD AE =，此时k 的取值范围为55(,)(,)55-∞-⋃+∞．-------14分 21.解：（1）当1k =-时，321()313f x x x x =+-+，---------------------------1分 则2'()23f x x x =+-(1)(3)x x =-+，令'()0f x =，∵[0,6]x ∈ 得1,x =----------------------------------2分 且()f x 在[0,1]上单调递减，在[1,6]上单调递增， ∵2(0)1,(1),(6)973f f f ==-=， ∴()f x 在[0,6]上的最大值为97，最小值为23-.------------------------4分 （2） ∵()2'2(21)3(2)f x x k x k k =-+++=(3)[(2)]x k x k --+，----------------5分当1k =时，2'()(3)0f x x =-≥，∴函数()f x 的单调递增区间为(,)-∞+∞；---6分当1k >时，32k k >+，由'()0f x >解得3x k >或2x k <+，由'()0f x <得23k x k +<<， ∴函数()f x 的单调递增区间为(3,)k +∞和(,2)k -∞+，递减区间为(2,3)k k +；----7分 当1k <时，32k k <+，由'()0f x >解得2x k >+或3x k <，由'()0f x <得32k x k <<+， ∴函数()f x 的单调递增区间为(3,)k +∞和(,2)k -∞+；递减区间为(3,2)k k +.-----9分 （3）由()'(3)[(2)]0f x x k x k =--+=得122,3x k x k =+=，--------------------------------------------------10分 ①当12x x =时，有231k k k +=⇒=，此时123(0,6)x x ==∈，函数'()f x 在(0,6)上有唯一的零点，∴1k =为所求；----------------------11分 ②当12x x >时，有231k k k +>⇒<，此时213x x <<，∵函数'()f x 在(0,6)上有唯一的零点，得2103x x ≤<<，即3023k k ≤<+<，解得20k -<≤，-----------------12分 ③当12x x <时，有231k k k +<⇒>，此时213x x >>， ∵函数'()f x 在(0,6)上有唯一的零点，得1236x x <<≤，即3263k k <+<≤，解得24k ≤<，------------------13分 综上得实数k 的取值范围为是：20k -<≤或1k =或24k ≤<.----------------14分。
2019-2020学年深圳市翠园中学东晓校区高三英语第三次联考试题及答案解析
2019-2020学年深圳市翠园中学东晓校区高三英语第三次联考试题及答案解析第一部分阅读（共两节，满分40分）第一节（共15小题；每小题2分，满分30分）阅读下列短文，从每题所给的A、B、C、D四个选项中选出最佳选项ABob and Sue Harvey spent nine years as resident fellows in a dormitory at Sanford and in their bookVirtual Reality and The College Freshman, they write “The Freshman oftenfaces an identity problem during the first semester.” College is a more pressured environment than it used to be, in part because the academic gap between high school and college has increased. Many college freshmen have never had to make independent decisions about sex, drugs and alcohol. Most don’t know how to manage their time or money. They often feel lonely and overwhelmed, resulting in anxiety and depression.Nancy Corbin, director of clinical service for student-counseling (咨询) services at Iowa State University, says her office is seeing a significant increase in requests for counseling from freshmen who are having trouble making the adjustment to college life. She says older teenagers increasingly lack the skills to deal with personal problems that aren’t easily defined or fixed. And they get homesick but have a hard time admitting it.Parents and high schools can make things easier on freshmen by preparing them differently. For example, by teaching them to budget their hours and dollars. The Harveys think high schools should offer a college-life course. “Parents need to focus more on relationship and personal issues and less on how many sheets and towels to take,” they say. Many homesick freshmen think they’ll be regarded as failures if they come home before Thanksgiving. So parents can help by letting them know they’re welcome to return if they feel the need. In the meantime, parents have to find new ways to keep in touch with their college kids. One of the best ways is e-mail. It’s less unpleasant and less expensive than constant phone calls and is more likely to be answered than a handwritten letter.1. Why is the first semester difficult for freshmen in college?A. Because they often fail in exams.B. Because they lack time and money.C. Because they are too homesick to make new friends.D. Because they have to settle personal issues on their own.2. In the last paragraph, it is suggested that ________.A. parents should stop buying anything for their kidsB. parents should develop a good relationship with their kidsC. parents should be taught how to send e-mails to their kidsD. parents should work with high schools in college-life courses3. Which of the following might be the best title for the passage?A. Hard Life of College FreshmenB. Approaches to Trouble in CollegeC. Freshmen’s Adaptation ProblemsD. A Strange Phenomenon in CollegeBIn order to help discover spoilage and reduce food waste for supermarkets and consumers, researchers have developed new low-cost, smart phone-linked, eco-friendly spoilage sensors for meat and fish packaging.One in threeUKconsumers throw away food just because it reaches the use-by date, but 60% of the £12.5 billion-worth of food we throw away each year is safe to eat.The researchers, whose findings were published in ACS Sensors, say the sensors could also eventually replace the use-by date—a widely used indicator of being fresh and eatable.The sensors cost two US cents each to make. Known as “paper-based electrical gas sensors (PEGS)”, they detect spoilage gases like ammonia (a poisonous gas with a strong unpleasant smell) in meat and fish products. The information provided by the electronic nose is received by a smart phone, and then you can know whether the food is fresh and safe to eat.The Imperial College London researchers who developed PEGS made the sensors by printing carbon electrodes onto a special type of paper. The materials are eco-friendly and harmless, so they don’t damage the environment and are safe to use in food packaging. The sensors, combined with a tiny electronic system, then inform nearby mobile devices, which identify and understand the data about spoilage gases.Lead author Dr Firat Guder of Imperial’s Department of Bioengineering, said, “Although they’re designed to keep us safe, use-by dates can lead to eatable food being thrown away. They don’t always reflect its actual freshness. In fact, people often get sick from food-borne diseases due to poor storage, even when an item is within its use-by date.”“These sensors are cheap enough so we hope to see supermarkets using them within three years. Our goal is to use PEGS in food packaging to reduce unnecessary food waste.”The authors hope that PEGS could have applications beyond food processing, like sensing chemicals in agriculture, air quality, and detecting disease markers in breath like those involved in kidney disease.4. What is the function of PEGS according to the text?A. To improve the taste of foods.B. To improve the service of stores.C. To help supermarkets store foods.D. To help people test food freshness.5. What role does the smartphone play while PEGS are functioning?A. It acts as an electronic nose.B. It reads the data collected by PEGS.C. It helps print the gas sensors onto paper.D. It discovers the spoilage gases from foods.6. What does Dr. Firat Guder say about use-by dates?A. They are not completely reliable.B. They can help reduce food waste.C. They are based on scientific research.D. They are not accepted by the consumers.7. What does the author mainly talk about in the text?A. The process of researching spoilage sensors.B. A new technology in packaging to reduce food waste.C. The application of spoilage sensors beyond food processing.D. The influence of use-by dates on supermarkets and consumers.CIt was once a shoreline buried by enough garbage to make it invisible (看不见的), thus, given the unfortunate nickname "toilet bowl" . Now the Philippines' Manila Bay beach is totally different, compared with a few months ago. It happened so suddenly and extremely that it brought tears to the eyes of the local people.The cleanup started on 27 January, when 5, 000 volunteers descended on Manila Bay to remove over 45 tons (公吨) of garbage, marking the beginning of a nation-wide environmental campaign. But some two months before this great movement began, a quiet revolution was already underway.During the first week of December 2018, Brooklyn- based Bounties Network collectedthree tons of garbage from Manila Bay aver two days through a project that paid a small group of people, mostly fishermen, with a digital currency (数字货币) based on the Ethereum system.For the mostly non-bank -using Filipino fishermen, this was a first-ever experience with a digital currency. It's one that proves decisive in enabling poor communities around the world to take up arms in the fight againsthumanity's waste.There are signs that this recycling-for-digital payment industry may be just about to take off. Earlier in September 2018, Plastic Bank, a Vancouver -based company powered by IBM technology, also started a similar project. They set up a project in Naga, a town in southern Luzon, the country's largest island, building a collection point to let people exchange plastic and recyclable materials for digital payouts through a system.That both these pioneers have chosen the Philippines as their first location is not surprising considering the country's contribution to ocean waste. A Wall Street Journal study in 2015 revealed that the Philippines make the third-largest amount of plastic waste into global oceans.8. Why did people call Manila Bay beach“toilet bowl” ?A. It looked like a huge bowl.B. There were plenty of toilets.C. It was covered by rubbish.D. People loved the toilets here.9. What does the underlined phrase“descended on”in paragraph 2 mean?A. Completely depended on.B. Suddenly arrived at.C. Occasionally decreased to.D. Gradually disappeared from.10. What made poor communities willing to fight against waste?A. The benefits to their homeland.B. The desire to make a difference.C. The chance to escape ocean pollution.D. The experience with a digital currency.11. What is the best title for the text?A. Online system helps endocean pollution.B. Manila Bay beach is suddenly removed.C. Plastic Bank is powerful in recycling waste.D. Philippines make a great amount of waste.DHardware in general,and smartphones in particular,have become a huge environmental and health problem in the Global South's landfill sites(垃圾填埋场).Electronic waste(e-waste) currently takes up 5 percent of all global waste,and it is set to increase rapidly as more of us own more than one smartphone,laptop and power bank They end up in places like Agbogbloshie on theoutskirts of Ghana's capital,Accra. It is the biggest e-waste dump in the world,where 10,000 informal workers walk through tons of abandoned goods as part of an informal recycling process.They risk their health searching for the precious metals that are found in abandoned smartphones.But Agbogbloshie should not exist.The Basel Convention,a 1989 treaty,aims to prevent developed nations from unauthorized dumping of e-waste in less developed countries.The e-waste industry,however,circumventsregulations by exporting e-waste labelled as "secondhand goods' to poor countries like Ghana,knowing full well hat it is heading for a landfill site.A recent report found Agbogbloshie contained some of the most dangerous chemicals.This is not surprising: smartphones contain chemicals like mercury（水银）,lead and even arsenic(砷).Reportedly, one egg from a free-range chicken in Agbogbloshie contained a certainchemical which can cause cancer and damage the immune system at a level that's about 220 times greater than a limit set by the European Food Safety Authority(EFSA).Most worryingly,these poisonous chemicals are free to pollute the broader soil and water system.This should concern us all, since some ofGhana's top exports are cocoa and nuts.Some governments have started to take responsibility for their consumers' waste.For example,Germanyhas started a project that includes a sustainable recycling system at Agbogbloshie,along with a health clinic for workers.However,governments cannot solve the problem alone, as there is an almost limitless consumer demand for hardware,especially when governments' green policies are focused on issues like climate change.Only the manufacturers can fix this.A more economically sustainable and politically possible solution is through encouraging hardware manufacturers to make the repair, reuse and recycling of hardware profitable,or at least cost-neutral12. What can we infer from Paragraph 2?A. Electronic waste requires more landfill sites acrossGhana.B. Electronic waste is too complex to get fully recycleC. Electronic products need to be improved urgentlyD. Electronic pollution is a burning question in Agbogbloshie13. What does the underlined word "circumvents"in Paragraph 3 mean?A. AbolishesB. TightensC. Brings inD. Gets around14. What should be the best concern according to the text?A. The thread of polluted food around the worldB. The damage of chicken’s immune systemC. The lack of diversity inGhana's exportsD. The violation of EFSA's standards15. What does the author think is the best solution to the e-waste problem?A. Manufacturers' developing a sustainable hardware economyB. Governments’ adjusting their green policies about e-waste.C. Reducing customers' demands for electronic productsD. Manufacturers’ urging the government to make effective policies to ensure more profit.第二节（共5小题；每小题2分，满分10分）阅读下面短文，从短文后的选项中选出可以填入空白处的最佳选项。
2020年深圳市翠园中学高中部高三英语三模试卷及答案
2020年深圳市翠园中学高中部高三英语三模试卷及答案第一部分阅读（共两节，满分40分）第一节（共15小题；每小题2分，满分30分）阅读下列短文，从每题所给的A、B、C、D四个选项中选出最佳选项AMust-see MusicalsReady to get back to the theater and enjoy some toe-tapping show tunes? Whether you're a Londoner or just visiting the capital for a day, you're sure to find a good night out from our selection of must-see musicals. Book your ticketsin advance to catch the hottest shows!●TINA- The Tina Turner MusicalFrom humble beginnings in Nutbush, Tennessee, to her transformation into global Queen of Rock n' Roll, Tina Turner didn't just break the rules, she rewrote them. This new stage musicalreveals the story of a woman who dared to defy the bounds of her age, gender and race. TINA—The Tina Turner Musical is written by Oliver Award-winning playwright Katori Hall and directed by Phyllida Lloyd.Performance times: Monday 7 pm; From June 3, 2021 until June 26, 2022Venue: Aldwych Theater, 49 Aldwych, London, WC2B 4DF●The Lion KingTaking the famous story of Simba and his ascension to king, the stage show is a one-way ticket to Pride Lands. With fascinating scenery drawing you in, you'll almost feel like you're part of the action as you journey through Simba's world. To bring The Lion King to life, the show's original director, Julie Taymor, combined live performers and creative props. Creating a visual feast that's since redefined how musicals could and should look, The Lion King really is an all singing, all-dancing affair.Performance times: Tuesday—Saturday 7: 30 pm; From June 1, 2021 until April 3, 2022Venue: Lyceuwm Theater, 21 Wellington Street, London WC2E 7RQ●The Prince of EgyptJourney through the wonders of Ancient Egypt as two young men, raised together as brothers in a kingdom of privilege, find themselves suddenly divided by a secret past. One must rule as Pharaoh, but the other must rise up and free histrue people; both face a destiny that will change history forever.With a huge cast and orchestra of almost 60 artists, this “truly phenomenal production” is based on the classic Dream Works Animation film and features the international best-selling, Academy Award-winning songWhen You Believe.Performance times: Monday—Saturday 7: 30 pm; From July 1, 2021 until January 8, 2022Venue: Dominion Theater, 268—269 Tottenham Court Rd, Fitzrovia, London W1T 7AQ1. Who is the author of TINA—The Tina Turner Musical?A. Oliver Award.B. Katori Hall.C. Phyllida Lloyd.D. Tina Turner.2. What is special for The Lion King?A. It is written by a famous director.B. It reveals a conflict between two brothers.C. It offers a lifelike feast for eyes.D. It shows the importance of protecting lions.3. If you prefer the songWhen You Believe, which theater should you go to?A. Dominion Theater.B. Lyceuwm Theater.C. Aldwych Theater.D. Egypt Theater.BEarthquakes are a natural disaster—except when they're man-made. The oil and gas industry has forcefully used the technique known as hydraulic fracturing (水力压裂法) to destroy sub-surface rock and liberate the oil and gas hiding there. But the process results in large amounts of chemical-filled waste water. Horizontal drilling (水平钻孔) for oil can also produce large amount of natural, unwanted salt water. The industry deals with this waste water by pumping it into deep wells.On Monday, the US Geological Survey published for the first time an earthquake disaster map covering both natural and “induced” quakes. The map and a report show that parts of the central United States now face a ground-shaking disaster equal to the famously unstable terrain (不稳定地形) of California.Some 7 million people live in places easily attacked by these man-made quakes, the USGS said The list of places at highest risk of man-made earthquakes includes Oklahoma, Kansas, Texas, Arkansas, Colorado, New Mexico, Ohio and Alabama. Most of these earthquakes are ly small, in the range of magnitude (震级) 3, but some have been more powerful, including a magnitude 5.6 earthquake in 2011 in Oklahoma that was connected to waste water filling.Scientists said they do not know ifthere is an upper limit on the magnitude of man-made earthquakes; this is an area of active research Oklahoma has had prehistoric earthquakes as powerful as magnitude 7.It's not immediately clear whether this new research will change industry practices, or even whether it will surprise anyone in the areas of newly supposed danger. In Oklahoma, for example, the natural rate of earthquakes is only one or two a year, but there have been hundreds since hydraulic fracturing and horizontal drilling, with thewaste water filling, became common in the last ten years.4. What kind of human activities can cause earthquakes?A. The man-made produced waste water in the factories.B. The process of digging deep wells in those poor areas.C. The advanced techniques used to deal with waste water.D. The oil or gas industry's work connected with the earth.5. What does the underlined word “induced” in paragraph 2 mean?A. Man-made.B. Reduced.C. Newly-built.D. Controlled.6. How much magnitude can man-made earthquakes reach?A. It's been said as small as magnitude 3.B. It has been said as high as magnitude 7.C. It's being studied without a final conclusion.D. It has risen by an average of magnitude 5. 6.7. What is the best title for the text?A. Natural Earthquakes in America Are Disappearing NowB. 7 Million Americans at Risk of Man-Made EarthquakesC. Time for Oil and Gas Industry Change Their Working PracticeD. More Often Earthquakes as Powerful as Magnitude 7 in AmericaCNot long after the first fitness magazine was published, a list probably followed soon after, ranking the best fitness equipment. This tradition has continued, with the implied message: usethisand exercise willbe yours.And that's part of the problem, says Dr. Lieberman, a professor of Harvard University. There isn't one “best” anything to achieve fitness. Besides, people understand exercise is good for them. Knowledge about exercise still doesn't motivate.Before you can answer why, it helps to look at history. Before the Industrial Revolution, people fetched water and walked up stairs because they had to. But then technology made life and work easier. Exercise has become something that people have to carve out time for. “It's a fundamental instinct to avoid physical activity when it's neither necessary nor rewarding,” he says.It would seem like being healthy would qualify as necessary, but a doctor's prescription to exercise “can makeit like taking cod liver oil,” Lieberman says. “Sometimes it works, but more often than not, it doesn't. And it's still coming across as an order, and “not having a heart attack in five years is not an immediate reward,” says Dr. Beth Frates, assistant professor at Harvard Medical School.People might not want to exercise because it's never been enjoyable. Most of us probably have memories of gym class, not being picked for a team, or being in a fitness center that's filled with in-shape people. The majority don't feel excited. They feel that exercise isn't for them, but it can be. Coaching people in an empowering and motivating way can work much better than ordering someone to exercise. It starts with an expanded definition of what counts as exercise, and an injection of what's rarely used to describe exercise, but is certainly allowed: namely, fun.8. What does the underlined “this” in paragraph 1 refer to?A. The magazine.B. The tradition.C. The equipment.D. The message.9. What can we infer about technology?A. It improves life quality.B. It saves people's time.C. It drives social progress.D. It makes exercise less likely.10. Why does the author mention “cod liver oil” in paragraph 4?A. To attach importance to health.B. To present a doctor's prescription.C. To explain exercise is considered inessential.D. To introduce the latest medical application.11. What is the main idea of the last paragraph?A. Exercise should be made more joyful.B. It's more fun to work out with others.C. We may encounter bad workout experiences.D. Orders work well to motivate people to exercise.DThe year 2020 will mark the beginning of the decade of the yold, or the “young old”, as the Japanese call people aged between 65 and 75. The traditional retirement age is 65. One might therefore expect peak retirement. By continuing to work, and staying socially engaged, the yold will change the world, as they have done several times before at different stages of their lives.The yold are more numerous, healthier and wealthier than previous generations of seniors. The yold are busier, too. In short, the yold are not just any group of old people. They are challenging the traditional expectations of the retired as people who wear slippers and look after the grandchildren. That will influence consumer, service and financial markets.The over-60s are one of the fastest-growing groups of customers of the airline business. The yold are vital to the tourism industry because they spend much more, when taking a foreign holiday, than younger adults.But for all this to happen,three big things will have to change, under pressure from the yold themselves. The most important is public attitudes towards older people, and in particular the expectation that the old ought to be putting their feet up and quietly retiring into the background. Then, government policies will have to change, too. The retirement age in many rich countries is still below the age to which many people want to work. The effective retirement age (the age at which people actually leave the workforce) is usually even lower. Third, higher numbers of healthy yold people will require drastic changes in health spending. Most diseases of ageing are bestmetwith prevention and lifestyle changes. But only about 2%~3% of most countries’ health-care spending goes on prevention. That will have to rise, because although the yold will constitute a bulge of comparative health and activity over the next decade, by 2030 they will hit 75 and enter a long period of decline for which few rich countries are ready.12. What kind of people are the yold exactly?A. They are workaholics.B. They are full of energy.C. They enjoy being focused on.D. They like staying socially engaged.13. Why do the yold contribute to tourist industry?A. They like traveling more.B. They have more money.C. They consume more on travel.D. They have much free time.14. What’s the author’s attitude toward health-care spending on prevention?A. Unsatisfied.B. Subjective.C. Neutral.D. Active.15. What does the underlined word “met” in the fourth paragraph mean?A. dealt withB. come acrossC. satisfiedD. experienced.第二节（共5小题；每小题2分，满分10分）阅读下面短文，从短文后的选项中选出可以填入空白处的最佳选项。
广东省深圳市普通高中学校高三数学3月月考模拟试题02
2018高考高三数学3月月考模拟试题02共150分.时间120分钟．第Ⅰ卷（选择题 共60分）一、选择题：本大题共12小题．每小题5分，共60分．在每小题给出的四个选项中，只有一项是符合题目要求的．1. i 是虚数单位，复数ii+12的实部为 A ．2 B ．2- C ．1 D ．1-2. 设全集R U =，集合{}2|lg(1)M x y x ==-，{}|02N x x =<<，则()U NM =A ．{}|21x x -≤<B ．{}|01x x <≤C ．{}|11x x -≤≤D ．{}|1x x < 3. 下列函数中周期为π且为偶函数的是 A ．)22sin(π-=x y B. )22cos(π-=x y C. )2sin(π+=x y D ．)2cos(π+=x y4. 设n S 是等差数列{}n a 的前n 项和，1532,3a a a ==,则9S = A ．90 B ．54C ．54-D ．72-5. 已知m 、n 为两条不同的直线，α、β为两个不同的平面，则下列命题中正确的是A ．若l m ⊥,l n ⊥,且,m n α⊂,则l α⊥B ．若平面α内有不共线的三点到平面β的距离相等，则βα//C ．若n m m ⊥⊥,α，则α//nD ．若α⊥n n m ,//，则α⊥m6. 一个几何体的三视图如图所示，其中俯视图与左视图均为半径是2的圆，则这个几何体的表面积是A ．16πB ．14πC ．12πD ．8π7. 已知抛物线x y 42=的焦点为F ，准线为l ，点P 为抛物线上一点，且在第一象限，l PA ⊥，垂足为A ，4PF =，则直线AF 的倾斜角等于正视图 俯视图左视图A ．712π B.23π C ．34π D. 56π 8. 若两个非零向量a ，b 满足||2||||a b a b a=-=+，则向量a b +与b a -的夹角为A ．6πB ．3πC ．32πD ．65π9. 已知函数2, 0(), 0x x f x x x x ≤⎧=⎨->⎩，若函数()()g x f x m =-有三个不同的零点，则实数m 的取值范围为 A ．1[,1]2-B ．1[,1)2-C ．1(,0)4-D ．1(,0]4- 10. 已知()|2||4|f x x x =++-的最小值为n ，则二项式1()nx x-展开式中2x 项的系数为 A ．15 B ．15- C ．30 D ．30-11. 已知函数()f x 对定义域R 内的任意x 都有()f x =(4)f x -，且当2x ≠时其导函数()f x '满足()2(),xf x f x ''>若24a <<则A ．2(2)(3)(log )af f f a << B ．2(3)(log )(2)af f a f << C ．2(log )(3)(2)af a f f <<D ．2(log )(2)(3)af a f f <<12. 定义区间(, )a b ，[, )a b ，(, ]a b ，[, ]a b 的长度均为d b a =-，多个区间并集的长度为各区间长度之和，例如, (1, 2)[3, 5)的长度(21)(53)3d =-+-=. 用[]x 表示不超过x 的最大整数，记{}[]x x x =-，其中R x ∈.设()[]{}f x x x =⋅，()1gx x =-，当0x k ≤≤时,不等式()()f x gx <解集区间的长度为5，则k 的值为 A ．6 B ．7 C ．8 D ．9第Ⅱ卷（非选择题 共90分） 二、填空题：本大题共4小题，每小题4分，共16分． 13. 某程序框图如右图所示，若3a =,则该程序运行后，输出的x 值为 ; 14. 若11(2)3ln 2(1)ax dx a x+=+>⎰，则a 的值 是 ;15. 已知,x y 满足约束条件224200x y x y y ⎧+≤⎪-+≥⎨⎪≥⎩,则目标函数2z x y =+的最大值是 ;16．给出以下命题：① 双曲线2212y x -=的渐近线方程为y =； ② 命题:p “+R x ∀∈，1sin 2sin x x+≥”是真命题； ③ 已知线性回归方程为ˆ32yx =+，当变量x 增加2个单位，其预报值平均增加4个单位； ④ 设随机变量ξ服从正态分布(0,1)N ，若(1)0.2P ξ>=，则(10)0.6P ξ-<<=； ⑤ 已知2622464+=--，5325434+=--，7127414+=--，102210424-+=---，依照以上各式的规律，得到一般性的等式为824(8)4n nn n -+=---，（4n ≠） 则正确命题的序号为 （写出所有正确命题的序号）．三、解答题：本大题共6小题,共74分,解答时应写出必要的文字说明、证明过程或演算步骤. 17. （本小题满分12分）已知函数()sin f x x ω= (0)ω>在区间[0,]3π上单调递增,在区间2[,]33ππ上单调递减;如图,四边形OACB中,a ,b ,c 为ABC △的内角A B C ，，的对边，且满足ACB AC B cos cos cos 34sin sin sin --=+ω. （Ⅰ）证明：a c b 2=+；（Ⅱ）若c b =，设θ=∠AOB ，(0)θπ<<,22OA OB ==， 求四边形OACB 面积的最大值. 18．（本小题满分12分）现有长分别为1m 、2m 、3m 的钢管各3根（每根钢管质地均匀、粗细相同且附有不同的编号），从中随机抽取n 根（假设各钢管被抽取的可能性是均等的,19n ≤≤），再将抽取的钢管相接焊成笔直的一根．（Ⅰ）当3n =时,记事件A ={抽取的3根钢管中恰有2根长度相等}，求()P A ； （Ⅱ）当2n =时,若用ξ表示新焊成的钢管的长度（焊接误差不计）,①求ξ的分布列； ②令21ηλξλ=-++，()1E η>，求实数λ的取值范围．如图，几何体111ABCD B C D -中，四边形ABCD 为菱形，60BAD ∠=，AB a =， 面111B C D ∥面ABCD ,1BB 、1CC 、1DD 都垂直于面ABCD ,且1BB =，E 为1CC 的中点，F 为AB 的中点.（Ⅰ）求证：1DB E ∆为等腰直角三角形； （Ⅱ）求二面角1B DE F --的余弦值.20．（本小题满分12分）已知N n *∈,数列{}n d 满足2)1(3n n d -+=,数列{}n a 满足1232n n a d d d d =+++⋅⋅⋅+；又知数列{}n b 中，21=b ，且对任意正整数n m ,，nm m n b b =.（Ⅰ）求数列{}n a 和数列{}n b 的通项公式；（Ⅱ）将数列{}n b 中的第．1a 项，第．2a 项，第．3a 项，……，第．n a 项，……删去后，剩余的项按从小到大的顺序排成新数列{}n c ，求数列{}n c 的前2013项和. 21．（本小题满分13分）已知向量(,ln )xm e x k =+，(1,())n f x =，//m n （k 为常数， e 是自然对数的底数），曲线()y f x =在点(1,(1))f 处的切线与y 轴垂直,()()xF x xe f x '=． （Ⅰ）求k 的值及()F x 的单调区间；（Ⅱ）已知函数2()2g x x ax =-+(a 为正实数),若对于任意2[0,1]x ∈，总存在1(0,)x ∈+∞， 使得21()()g x F x <，求实数a 的取值范围．1已知椭圆C :22221(0)x y a b a b+=>>的焦距为,离心率为2,其右焦点为F ,过点(0,)B b 作直线交椭圆于另一点A .(Ⅰ)若6AB BF ⋅=-,求ABF ∆外接圆的方程;(Ⅱ)若过点(2,0)M 的直线与椭圆:N 222213x y a b +=相交于两点G 、H ，设P 为N 上一点，且满足OG OH tOP +=（O 为坐标原点），当253PG PH -<时，求实数t 的取值范围.参考答案一、选择题：本大题共12小题．每小题5分，共60分． C B A C D A B B C A C B二、填空题：本大题共4小题，每小题4分，共16分．13. 31 14. 2 15. ．①③⑤三、解答题：本大题共6小题，共74分，解答时应写出必要的文字说明、证明过程或演算步骤．17. （本小题满分12分）解：（Ⅰ）由题意知：243ππω=，解得：32ω=， ……………………………2分ACB AC B cos cos -cos -2sin sin sin =+ A C A B A A C A B sin cos -sin cos -sin 2cos sin cos sin =+∴ A A C A C A B A B sin 2sin cos cos sin sin cos cos sin =+++∴A C AB A sin 2)(sin )(sin =+++∴………………………………………………………4分a cb A B C 2sin 2sin sin =+⇒∴=+∴…………………………………………………6分（Ⅱ）因为2b c a b c +==，，所以a b c ==，所以ABC △为等边三角形21sin 24OACB OAB ABC S S S OA OB AB θ∆∆=+=⋅+ ……………………………8分22sin -2cos )4OA OB OA OB θθ=++⋅ ……………………………………………9分435cos 3-sin +=θθ2sin (-)3πθ=， ………………………………………10分 (0)θπ∈，,2--333πππθ∴∈(，)，当且仅当-32ππθ=，即56πθ=时取最大值,OACB S 的最大值为24+………………12分18．（本小题满分12分）解：(Ⅰ)事件A 为随机事件，121336399()14C C C P A C ==………………………………………4分 （Ⅱ）①ξ可能的取值为2,3,4,5,623291(2)12C P C ξ=== 1133291(3)4C C P C ξ===211333291(4)3C C C P C ξ+=== 1133291(5)4C C P C ξ===23291(6)12C P C ξ===∴ξ的分布列为：……………………………………………………9分 ②11111()2345641243412E ξ=⨯+⨯+⨯+⨯+⨯= ………………………………10分 21ηλξλ=-++，2()()1E E ηλξλ∴=-++241λλ=-++()1E η>，2141104λλλ∴-++>⇒<<…………………………………………12分 19．（本小题满分12分）解：（I ）连接BD ，交AC 于O ，因为四边形ABCD 为菱形，60BAD ∠=，所以BD a = 因为1BB 、1CC 都垂直于面ABCD ,∴11//BB CC ，又面111B C D ∥面ABCD ,11//BC B C ∴1所以四边形11BCC B 为平行四边形 ,则11B C BC a ==……………………………2分 因为1BB 、1CC 、1DD 都垂直于面ABCD ,则1DB ===2DE ===12B E ===…4分 所以222222116634a a DE B E a DB ++=== 所以1DB E ∆为等腰直角三角形 ………………………………………………5分 （II ）取1DB 的中点H ，因为,O H 分别为1,DB DB 的中点，所以OH ∥1BB 以,,OA OB OH 分别为,,x y z 轴建立坐标系，则1(0,,0),(,0,),(0,),,,0)2224a a a D E a B F -所以13233(0,,2),(,,),(,,0)24a DB a a DE a a DF a a ==-= ………………7分 设面1DB E 的法向量为1111(,,)n x y z =，则1110,0n DB n DE ⋅=⋅=，即110ay =且11102a y += 令11z =，则1(0,n = ………………………………………………………………9分 设面DFE 的法向量为2222(,,)n x y z =， 则220,0n DF n DE⋅=⋅=22304ay +=且222022a y az ++= 令21x=，则2(1,)33n =-……………………………………………………11分则12cos ,2n n +==,则二面角1B DE F --的余弦值为2 …12分20．（本小题满分12分）解：2)1(3n n d -+= ,∴1232n n a d d d d =+++⋅⋅⋅+3232n n ⨯== …………………3分又由题知：令1m = ，则22212b b ==,33312b b ==12n n n b b == ………………5分若2n n b =，则2m nm n b =，2n mn m b =，所以m nn m b b =恒成立若2n n b ≠,当1m =,m nn m b b =不成立,所以2n n b = ……………………………………6分（Ⅱ）由题知将数列{}n b 中的第3项、第6项、第9项……删去后构成的新数列{}n c 中的奇数列与偶数列仍成等比数列，首项分别是12b =，24b =公比均是,8 …………9分201313520132462012()()T c c c c c c c c =+++⋅⋅⋅+++++⋅⋅⋅+1007100610062(18)4(18)208618187⨯-⨯-⨯-=+=--…………………………………………12分21．（本小题满分13分）解：（I ）由已知可得：()f x =1xnx k e+1ln ()x x k x f x e --'∴=， 由已知，1(1)0kf e-'==，∴1k = …………………………………………………………2分 ∴()()x F x xe f x '=1(ln 1)1ln x x x x x x=--=--所以()ln 2F x x '=-- …………3分由21()ln 200F x x x e'=--≥⇒<≤， 由21()ln 20F x x x e '=--≤⇒≥()F x ∴的增区间为21(0,]e ，减区间为21[,)e +∞ ………………………………………5分 （II ）对于任意2[0,1]x ∈，总存在1(0,)x ∈+∞， 使得21()()g x F x <，∴max max ()()g x F x < ……………………………………………………………………6分由（I ）知，当21x e =时，()F x 取得最大值2211()1F e e=+.………………………………8分 对于2()2g x x ax =-+，其对称轴为x a = 当01a <≤时，2max ()()g x g a a ==， ∴2211a e<+，从而01a <≤………………10分 当1a >时，max ()(1)21g x g a ==-， ∴21211a e -<+，从而21112a e <<+……12分综上可知： 21012a e<<+………………………………………………………………13分22．（本小题满分13分）解：(Ⅰ)由题意知：c =2c e a ==，又222a b c -=，解得：a b ==椭圆C 的方程为：22163x y += …………………………2分 可得：(0,3)B，F,设00(,)A x y ，则00()AB x y =-，(3,BF =，6AB BF ⋅=-，00)6y =-，即00y x =由220000163xy y x ⎧+=⎪⎨⎪=-⎩000x y =⎧⎪⇒⎨=⎪⎩0x y ⎧=⎪⎪⎨⎪=⎪⎩即(0,A，或A …………………………………………………………4分 ①当A 的坐标为(0,时，OA OB OF ===∴ABF∆外接圆是以O为半径的圆，即223x y +=……………………………………………………………5分 ②当A的坐标为时，1AF k =，1BF k =-，所以ABF ∆为直角三角形，其外接圆是以线段AB 为直径的圆，圆心坐标为，半径为12AB =， ABF ∴∆外接圆的方程为225((333x y -+-= 综上可知：ABF ∆外接圆方程是223x y +=，或225((333x y -+-= ……7分 (Ⅱ)由题意可知直线GH 的斜率存在.设:(2)GH y k x =-，11(,)G x y ，22(,)H x y ，(,)P x y由22(2)12y k x x y =-⎧⎪⎨+=⎪⎩得：2222(12)8820k x k x k +-+-= 由422644(21)(82)0k k k ∆=-+->得：212k <（*） ………………………9分 22121222882,1212k k x x x x k k -+==++253PG PH -<，253HG ∴<123x -<422222648220(1)[4](12)129k k k k k -∴+-⨯<++ 214k ∴>，结合（*）得：21142k << ………………………………………………11分 OG OH tOP +=，1212(,)(,)x x y y t x y ∴++=从而21228(12)x x k x t t k +==+，1212214[()4](12)y y ky k x x k t t t k +-==+-=+ 点P 在椭圆上，2222284[]2[]2(12)(12)k k t k t k -∴+=++，整理得：22216(12)k t k =+即228812t k=-+，23t ∴-<<-，或23t <<………………………………13分。
2020年深圳市翠园中学高中部高三英语第三次联考试题及答案
2020年深圳市翠园中学高中部高三英语第三次联考试题及答案第一部分阅读（共两节，满分40分）第一节（共15小题；每小题2分，满分30分）阅读下列短文，从每题所给的A、B、C、D四个选项中选出最佳选项AThough online ordering is popular in the UK today，handson experience still attracts many buyers' attention.Oxford StreetLondon is a shoppers' paradise，and most visitors head for Oxford Street.Halfway along is Selfridges，one of the world's first department stores where the architecture and window dressing impress you even before you go in.There are at least four other major stores on this street，plus Europe's largest music shop.In December the atmosphere is especially festive because of the Christmaslights which are always lighted by a politician，a great sportsman，or a super star.Kensington High StreetA fashionable area for shopping is Kensington High Street.One of its department stores even has a roof garden—good for relaxing between purchases.There's also an organic food superstore.Borough MarketYou can't visit London without going to a supermarketOne of the oldest and best for food is probably Borough Market on the south bank of the Thames.Get off the underground at London Bridge and wander among fresh fish stalls，bakeries，and fruit and vegetable sellers.You can also buy specialities to take away，like cheeses，pork pies，mustard and chutney.More places for bargainsPortobello Road Market on a Saturday is your best choice for jewelry or collector's items.It's a shortwalk from the underground station at Notting Hill Gate and you never know what you will find.For clothes，Camden Market is the place.It gets a little crowded at the weekends，though.Convent Garden Market offers great experience for the simple pleasure of looking at jewelry and gifts.1.Oxford Street becomes special in December for ________.A.the wonderful window dressingB.the Europe's largest music shopC.the lights lighted by a famous personD.many bargains to choose from2.To enjoy food，you can goto ________.A.Camden MarketB.Borough MarketC.Kensington High StreetD.Portobello Road Market3.Where is this passage probably taken from?AA science book. B.A traveler's journal.C.A news report.D.A trip guide.BTeens who have good, supportive relationships with their teachers enjoy better healthas adults, according to research published by an American research center.“This research suggests that improving students' relationships with teachers could have positive and long-lasting effects beyond just academic success," said Jinho Kim, a professor atKoreaUniversityand author of the study."Itcould also bring about healthimplicationsin the long run.”Previous research has suggested that teens' social relationships might be linked to health outcomes in adulthood. However, it is not clear whether the link between teen relationships and lifetime health is causal（因果的）-it could be that other factors, such as different family backgrounds, might contribute to both relationship problems in adolescence and to poor health in adulthood. Also, most research has focused on teens' relationships with their peers（同龄人）, rather than on their relationships with teachers.To explore those questions further, Kim analyzed data on nearly 20,000 participants from the Add Health study, a national study in theU.S.that followed participants from seventh grade into early adulthood. The participant pool included more than 3,400 pairs of siblings（兄弟姐妹）. As teens, participants answered questions, like “How often have you had trouble getting along with other students and your teachers?" As adults, participants were asked about their physical and mental health.Kim found that participants who had reported better relationships with both their peers and teachers in middle and high school also reported better physical and mental health in their mid-20s. However, when he controlled for family background by looking at pairs of siblings together, only the link between good teacher relationships and adult health remained significant.The results suggest teacher relationships are more important than previously realized and that schools should invest in training teachers on how to build warm and supportive relationships with their students. "This is notsomething that most teachers receive much training in," Kim said, “but it should be.”4. What does the underlined word “implications" in Paragraph 2 refer to?A. Recipes.B. Habits.C. Benefits.D. Risks.5. What is Paragraph 3 mainly about?A. Poor health in adolescence.B. Limitations of the previous research.C. Teens' relationships with their peers.D. Factors affecting health in adulthood.6. What does Kim's research show?A. Good adult health depends on teens' good teachers.B. Good family background promises long-term adult health.C. Healthy peer relationships leads to students' academic success.D. Positive student-teacher relationship helps students' adult health.7. Where does this text probably come from?A. A health magazine.B. A medical report.C. A term paper.D. A family survey.CPreparations for the Tokyo Olympics have suffered another challenge after a survey found that 60% of people in Japan want them to be cancelled,less than three months before the Games are scheduled to open.Japan has extended a state of emergency in Tokyo and several other regions until the end of May as it struggles to control a fast increase in COVID-19 cases caused by new, more catching variants（变异体）with medical staff warning that health services in some areas are on the edge of breaking down.The Olympics, which were delayed by a year due to the pandemic, are set to open on 23 July, with the International Olympic Committee（IOC）and organizers insisting that measures will be put in place to ensure the safety of athletes and other visitors, as well as a nervous Japanese public.The survey, conducted between 7 and 9 May by the conservative Yomiuri Shimbun, showed 60% wanted the Games cancelled as opposed to 39% who said they should be held. “Postponement” — an option abandoned by the IOC — was not offered as a choice.Of those who said the Olympics should go ahead, 23% said they should take place without audience. Foreign audience have been banned but a final decision on native attendance will be made in June.Another poll conducted at the weekend by TBS News found 65% wanted the Games cancelled or postponed again, with 37% voting to give up the event altogether and 28% calling for another delay. A similar poll in April conducted by Kyodo news agency found 70% wanted the Olympics cancelled or postponed.The IOC's vice president, John Coates, said that while Japanese sentiment about the Games “was a concern”, he could foresee no situation under which the sporting events would not go ahead.8. How many Japanese wish the Olympics would not be held in Tokyo according to the survey?A. 60%.B. 28%.C. 37%.D. 70%.9. What should be put into consideration if the Olympics open?A. The economic crisis.B. The urban transport.C. The safety of athletes.D. The health condition of citizens.10. What is some people's attitude towards foreign spectators in Paragraph 5?A. Welcome.B. Unfriendly.C. Cold.D. Unsupported.11. What can we conclude from John Coates'words?A. The Olympics will be stopped this year.B. The Olympics will be put off.C. The Olympics will be held normally.D. The Olympics will take place in other place.DImagine the feeling of swinging at a baseball going 100 miles per hour—without leaving your living room, or being in race car as it roars down the track, while you are sitting on the couch.These are just some of the ways that sports business leaders say virtual reality (VR) will revolutionize how people train for and experience sports. Virtual and augmented（增强的）realities are together known as mixed reality (MR). “American footballers are already using VR to better train their minds andread the field,” Ludden said. “This can allow players to perfect their skills without risking injury.”Canadian company D-BOX Technologies designs and produces moving seats found in cinema and theme parks. It is now moving into sports, and shows its Formula One (F1) racing simulator（模拟器）. The seats stimulate the force of gravity, speed and every shaking as Fl champion Lewis Hamilton zips around city streets.A simulation seat uses pre-programed data now. Someday, though, it could use real-time information sent by the car. “They couldbroadcast live content through a network in pop-up theaters around the world,” Ludden said. Say you want to experience the true stress of a batter being up against major-league baseball pitcher. “You canhave a heartbeat added to the sensation on the seat and then you can feel it, boom, boom,” Maheu explained. “When he swings and hits the ball, you can have an impact.”One day, fans around the world could physically experience every game from their favorite player in real time. Ludden said that current and near-future technology could create “augmented stadiums” for live audiences. Panasonic launched its “Smart Venue” plans which included the overlaying of graphics, advertisements, player statistics and replays on the field of play at a pro football game. “If you are seated in the cheap seats, you can see this really useful.” “Fans may someday join in stadium wide games, using the field as a virtual gaming platform,” Ludden added.12. What does the underlined phrase “read the field” in paragraph 2 mean?A. Get off the playing field.B. Build up a football court.C. Judge the situation on the field.D. Ask players to play on the spot.13. What does Maheu think audiences can do in the future baseball game?A. Enjoy live content in any theater.B. Program the simulation seats in advance.C. Control the force and speed of the baseball.D. Experience the real time game with the player.14. What does Ludden mainly describe in the last paragraph?A. The origin of VR.B. A future stadium.C. An advertisement platform.D. The expectations of audiences.15. What is the main idea of the text?A. VR can improve players' skills for sports.B. VR increases fans' joy in the baseball game.C. VR can improve sports experience for players and fans.D. VR promises a new future for football players and games.第二节（共5小题；每小题2分，满分10分）阅读下面短文，从短文后的选项中选出可以填入空白处的最佳选项。
2020年深圳市翠园中学高中部高三英语三模试卷及答案解析
2020年深圳市翠园中学高中部高三英语三模试卷及答案解析第一部分阅读（共两节，满分40分）第一节（共15小题；每小题2分，满分30分）阅读下列短文，从每题所给的A、B、C、D四个选项中选出最佳选项AThis is a list of places to spend the 2020 Olympics if you aren't going to Japan.AustraliaThe fact that the summer Olympics fall during Australia's winter season is worth keeping in mind for two reasons: it makes traveling there cheaper, and it's still not too cold. As far as the Olympics are concerned, there will be no shortage of opportunities to watch the Games in between your various explorations of the country and its limitless activities.ThailandThailand is a breathtaking place 10 spend some time during any summer, and provides a perfect setting for Olympie viewing: You can go scuba diving one morning before watching sports all afternoon, or simply duck out for world-famous street food in between events. But Thai sports fans may also be taking extra interest in the Olympics these days.United StatesThe U.S. is likely to be as interested in the Olympics as any other nation, given is collection of athletes who will be taking center stage. You can rest assured it won't be difficult to watch the Games no matter where you're visiting specifically. This leaves you with all sorts of fun options. You can visit a luxury ski resort town like Aspen, which turns into a gorgeous hiking destination in the summer.Great BritainNot unlike the U, s. Britain will make for a fun place to spend the 2020 Olympics because there's a great deal of national interest in a number of different sports, and the local athletes are expected to be competitive. Summer can also be a good time to be in Britain in general," with ly mild temperatures allowing for full exploration of the country. That means you can stay in the beautiful Lake District if you like, hiking or kayaking when you're not watching the Games.1.What is special about Australia as a destination in an Olympic summer?A.Its season.B.Its activities.C.Its sports.D.Its scenery,2.Which country can you go to if you are a street food lover?A.Australia.B.Thailand.C.United States.D.Great Britain.3.What do the U. S. and Britain have in common as fun places to spend the 2020 Olympics?A.They both have a pleasant temperature.B.They are both interested in the Games.CThey both own lots of sports centers. D.They are both English-speaking countries.BWith their tiny brains and excellent ability to memorize nectar locations, honeybees are a favorite model organism for studying learning and memory. Such research has indicated that to form long-term memories—ones that last a day or more—the insects need to repeat a training experience at least three times. By contrast, short-and mid-term memories that last seconds to minutes and minutes to hours, respectively, need only a single learning experience.Exceptions to this rule have been observed, however. For example, in some studies, bees formed long-lasting memories after a single learning event. Such results are often regarded as circumstantial anomalies, says Martin Giurfa of the University of Toulouse. But the anomalous findings, together with research showing that fruit flies and ants can form long-term memories after single experiences, aroused Giurfa’s curiosity. Was it possible that honeybees could reliably do the same? Giurfa reasoned that the ability to form long-term memories might depend on the particular type of bee and the experience. Within a honeybee colony, there are nurses, who clean the hive and feed the young; guards, who patrol and protect the hive; and foragers, who search for nectar.While previous studies have tested bees as a whole, Ciurfa and his colleagues focused on foragers, tasking them with remembering an experience relevant to their role: an odor associated with a sugary reward.The researchers observed that a single exposure to a reward-paired odor was enough for most forager bees to remember that specific odor the following day. Many foragers could even remember the odor three day later.The results do not mean that all prior research was wrong, says André Fiala of the University of Göttingen. “People have done the experiments in a different way.” Still, the new results do show that “the commonly held belief that one needs multiple training trials to achieve long-term memory is not always true,” he says, and this “really advances the field.”4. What does the author want to tell us through Paragraph 1?A. A model for memory research.B. The classification of memories.C. New research on learning and memory.D. Previous findings on memory formation.5. Which factor might influence a bee’s memory of an experience, according to Giurfa’s research?A. Whether the bee's role is related.B. Whether the bee is introduced or native.C. How often the bee repeats the experience.D. How long the bee is exposed to the reward.6. What is Andre Fiala’s attitude towards the new results?A. Doubtful.B. Favorable.C. Intolerant.D. Unclear.7. Which of the following is a suitable title for the text?A. Learning and Memory: How Honeybees RememberB. Honeybee Memory: Honeybee Knows What to DoC. Honeybees Remember after Just One LessonD. Honeybees Use Memory for CommunicationCJapan has announced emergency Covid measures in Tokyo and three other areas in order to control rising infections (传染病), just three months before the country is set to host the Olympics. The government said the state of emergency — set to last for about two weeks— would be “short and powerful”. Under the measures, bars will be required to close and big sporting events will be held without audience. The government has insisted that the Olympics will go ahead in July.Prime minister Yoshihide Suga announced the measures on Friday, saying they would begin on Sunday and remain in place until 11 May. In addition to to Tokyo, Osaka, Kyoto and Hyogo will be affected. It has marked the third state of emergency in japan since the pandemic began. “I sincerely apologize for causing trouble for many people again,” he said. “It is feared that infection in major cities will spread across the whole country if we take no measures.”Under the rules, major facilities like department stores will close, as well as restaurants, bars, and KTV rooms serving alcohol. Restaurants that do not serve alcohol are being told to close early, and companies are being asked to make arrangements for people to work remotely. Schools will remain open. Besides, the emergency measurescoincide withthe country’s “Golden Week” holiday, which runs from late April to the first week of May and is the busiest travel period of the year. Tokyo governor Yuriko Koike urged residents to start taking precautions immediately. In an effort to discourage people from going out at night. She said neon signs (霓虹灯) would be turned off.The coronavirus toll in Japan has been much lower than that in many other countries, with about 558,000 cases and fewer than 10,000 deaths, according to figures collected by Johns Hopkins University. But there areconcerns over the latest rise in infections, with reports of hospital bed shortages in some areas.Tokyo 2020 president Seiko Hashimoto said at a news conference on Friday that organizers were not considering canceling the event. “I hope the coronavirus situation improves with the prevention measures the government, Tokyo, and other regional governments have put into place,” she said. “We, as Tokyo 2020, continue to wish for the swift return to normal and will continue to work closely to make sure a safe and secure Olympics can happen.”8. According to the passage, what does Japanese government advise people to do?A. To watch a live game.B. To work at home.C. To hang out in the evening.D. To study at home.9. What is the aim of bringing in emergency Covid measures?A. To relieve people's fear of the the pandemic.B. To settle the problem of hospital bed shortages.C. To test government’s management of emergency.D. To ensure the smooth running of the upcoming Olympics.10. Which words can best describe the government’s action?A. generous and brilliant.B. costly but useless.C. positive and considerate.D. accidental but efficient.11. What does the underlined phrase “coincide with” in Paragraph 3 mean?A. meet withB. deal withC. make upD. set upDIn the old days, when you had to drive to a movie theater to get some entertainment, it was easy to see how your actions could have an impact（影响）on the environment. After all, you were jumping into your car, driving across town, coughing out emissions（产生排放）and using gas all the way. But now that we're used to staying at home and streaming movies, we might get a littleproud. After all, we're just picking up our phones and maybe turning on the TV. You're welcome. Mother Nature.Not so fast, says a recent report from the French-based Shift Project. According to "Climate Crisis: The Unsustainable Use of Online Video", digital technologies are responsible for 4% of greenhouse gas emissions, and that energy use is increasing by 9% a year. Watching a half-hour show would cause 1. 6 kilograms of carbon dioxide emissions. That's like driving 6. 28 kilometers. And in the European Union, the Eureca project found that data centers（where videos are stored）there used 25% more energy in 2017 compared to just three years earlier,reports the BBC.Streaming is only expected to increase as webecome more enamored ofour digital devices（设备）and the possibility of enjoying entertainment where and when we want it increases. Online video use is expected to increase by four times from 2017 to 2022 and account for 80% of all Internet traffic by 2022. By then, about 60% of the world's population will be online.You're probably not going to give up your streaming services, but there're things you can do to help lessen the impact of your online use, experts say. For example, according to Lutz Stobbe, a researcher from the Fraunhofer Institute in Berlin, we have no need to upload 25 pictures of the same thing to the cloud because it consumes energy every time. If instead you delete a few things here and there, you can save energy. Moreover, it's also a good idea to stream over Wi-Fi, watch on the smallest screen you can, and turn off your Wi-Fi in your home if you're not using your devices.12. What topic is the first paragraph intended to lead in?A. The environmental effects of driving private cars.B. The improvements on environmental awareness.C. The change in the way people seek entertainment.D The environmental impacts of screaming services.13. What does the underlined phrase become more enamored of" in paragraph 3 probably mean?A. Get more skeptical of.B. Become more aware of.C. Feel much crazier about.D. Get more worried about.14. What can we infer about the use of streaming services?A. It is being reduced to protect the planet.B. Its environmental effects are worsening.C. It is easily available to almost everyone.D. Its side effects have drawn global attention.15. Which of the following is the most environmentally-friendly?A. Watching downloaded movies on a mobile phone.B. Downloading music on a personal computer.C. Uploading a lot of images of the same thing.D. Playing online games over mobile networks.第二节（共5小题；每小题2分，满分10分）阅读下面短文，从短文后的选项中选出可以填入空白处的最佳选项。
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深圳市罗湖区翠园中学（高中部）2018-2019学年高三上学期第三次月考试卷数学含答案班级__________ 座号_____ 姓名__________ 分数__________一、选择题（本大题共12小题，每小题5分，共60分.每小题给出的四个选项中，只有一项是符合题目要求的.）1． 设集合A ＝{1,2,3}，B ＝{4,5}，M ＝{x|x ＝a ＋b ，a ∈A ，b ∈B}，则M 中元素的个数为( )。
A3 B4 C5 D62． 已知集合23111{1,(),,}122i A i i i i -=-+-+（其中为虚数单位），2{1}B x x =<，则A B =（ ） A ．{1}- B ．{1} C ．{1,}2- D ．{}23． 已知点P 是双曲线C ：22221(0,0)x y a b a b-=>>左支上一点，1F ，2F 是双曲线的左、右两个焦点，且12PF PF ⊥，2PF 与两条渐近线相交于M ，N 两点（如图），点N 恰好平分线段2PF ，则双曲线的离心率是（ ）A.5B.2 D.2【命题意图】本题考查双曲线的标准方程及其性质等基础知识知识，意在考查运算求解能力. 4． 已知集合{}2|10A x x =-=，则下列式子表示正确的有（ ） ①1A ∈；②{}1A -∈；③A ∅⊆；④{}1,1A -⊆．A ．1个B ．2个C ．3个D ．4个 5． 已知函数22()32f x x ax a =+-，其中(0,3]a ∈，()0f x ≤对任意的[]1,1x ∈-都成立，在1和两数间插入2015个数，使之与1，构成等比数列，设插入的这2015个数的成绩为T ，则T =（ ） A ．20152B ．20153C ．201523D ．2015226． 如图在圆O 中，AB ，CD 是圆O 互相垂直的两条直径，现分别以OA ，OB ，OC ，OD 为直径作四个 圆，在圆O 内随机取一点，则此点取自阴影部分的概率是（ ）A ．π1B ．π21C ．π121-D ．π2141-【命题意图】本题考查几何概型概率的求法，借助圆这个载体，突出了几何概型的基本运算能力，因用到圆的几何性质及面积的割补思想，属于中等难度． 7． 若a=ln2，b=5，c=xdx ，则a ，b ，c 的大小关系（ ）A ．a ＜b ＜cB B ．b ＜a ＜cC C ．b ＜c ＜aD ．c ＜b ＜a8． 已知函数211,[0,)22()13,[,1]2x x f x x x ⎧+∈⎪⎪=⎨⎪∈⎪⎩，若存在常数使得方程()f x t =有两个不等的实根12,x x（12x x <），那么12()x f x ∙的取值范围为（ ）A ．3[,1)4 B．1[,86 C ．31[,)162 D ．3[,3)89． 已知x ，y满足时，z=x ﹣y 的最大值为（ ） A ．4B ．﹣4C ．0D ．210．如图，在棱长为1的正方体1111ABCD A B C D -中，P 为棱11A B 中点，点Q 在侧面11DCC D 内运动，若1PBQ PBD ∠=∠，则动点Q 的轨迹所在曲线为（ ）A.直线B.圆C.双曲线D.抛物线【命题意图】本题考查立体几何中的动态问题等基础知识，意在考查空间想象能力.DABCO11．已知命题1:0,2p x x x∀>+≥，则p ⌝为（ ） A ．10,2x x x ∀>+< B ．10,2x x x ∀≤+< C ．10,2x x x ∃≤+< D ．10,2x x x∃>+<12．已知函数()sin()(,0)4f x x x R πωω=+∈>的最小正周期为π，为了得到函数()cos g x x ω=的图象，只要将()y f x =的图象（ ）A ．向左平移8π个单位长度 B ．向右平移8π个单位长度 C ．向左平移4π个单位长度 D ．向右平移4π个单位长度二、填空题（本大题共4小题，每小题5分，共20分.把答案填写在横线上）13．已知x ，y 为实数，代数式2222)3(9)2(1y x x y ++-++-+的最小值是 . 【命题意图】本题考查两点之间距离公式的运用基础知识，意在考查构造的数学思想与运算求解能力.14．设某双曲线与椭圆1362722=+y x 有共同的焦点，且与椭圆相交，其中一个交点的坐标为 )4,15(，则此双曲线的标准方程是 .15．将一张坐标纸折叠一次，使点()0,2与点()4,0重合，且点()7,3与点(),m n 重合，则m n +的 值是 ．16．设向量a ＝（1，－1），b ＝（0，t ），若（2a ＋b ）·a ＝2，则t ＝________．三、解答题（本大共6小题，共70分。
解答应写出文字说明、证明过程或演算步骤。
）17．（本小题满分12分）如图，多面体ABCDEF 中，四边形ABCD 为菱形，且60DAB ∠=，//EFAC ，2AD =，EA ED EF ===.（1）求证：AD BE ⊥；（2）若BE =-F BCD 的体积.18．（本小题满分12分）某媒体对“男女延迟退休”这一公众关注的问题进行名意调查，下表是在某单位（Ⅱ）从赞同“男女延迟退休”的80人中，利用分层抽样的方法抽出8人，然后从中选出2人进行陈述 发言，求事件“选出的2人中，至少有一名女士”的概率．参考公式：22()K ()()()()n ad bc a b c d a c b d -=++++，()n a b c d =+++【命题意图】本题考查统计案例、抽样方法、古典概型等基础知识，意在考查统计的思想和基本运算能力19．如图，在四边形ABCD 中,,,3,2,45AD DC AD BC AD CD AB DAB ⊥===∠=, 四 边形绕着直线AD 旋转一周.（1）求所成的封闭几何体的表面积； （2）求所成的封闭几何体的体积.20．（本题10分）解关于的不等式2(1)10ax a x -++>.21．（本题满分12分）在长方体1111D C B A ABCD -中，a AD AA ==1，E 是棱CD 上的一点，P 是棱1AA 上的一点.（1）求证：⊥1AD 平面D B A 11； （2）求证：11AD E B ⊥；（3）若E 是棱CD 的中点，P 是棱1AA 的中点，求证：//DP 平面AE B 1.22．（本小题满分12分）1111]已知函数()()1ln 0f x a x a a x=+≠∈R ，．（1）若1a =，求函数()f x 的极值和单调区间；（2）若在区间(0]e ，上至少存在一点0x ，使得()00f x <成立，求实数的取值范围．深圳市罗湖区翠园中学（高中部）2018-2019学年高三上学期第三次月考试卷数学含答案（参考答案）一、选择题（本大题共12小题，每小题5分，共60分.每小题给出的四个选项中，只有一项是符合题目要求的.）1． 【答案】B【解析】由题意知x ＝a ＋b ，a ∈A ，b ∈B ，则x 的可能取值为5,6,7,8.因此集合M 共有4个元素，故选B 2．【答案】D 【解析】考点：1.复数的相关概念；2.集合的运算 3． 【答案】A.【解析】4． 【答案】C 【解析】试题分析：{}1,1A =-，所以①③④正确.故选C. 考点：元素与集合关系，集合与集合关系． 5． 【答案】C 【解析】试题分析：因为函数22()32f x x ax a =+-，()0f x ≤对任意的[]1,1x ∈-都成立，所以()()1010f f -≤⎧⎪⎨≤⎪⎩，解得3a ≥或1a ≤-，又因为(0,3]a ∈，所以3a =，在和两数间插入122015,...a a a 共2015个数，使之与，构成等比数列，T 122015...a a a =，201521...T a a a =，两式相乘，根据等比数列的性质得()()2015201521201513T a a ==⨯，T=201523，故选C.考点：1、不等式恒成立问题；2、等比数列的性质及倒序相乘的应用.6．【答案】C【解析】设圆O的半径为2，根据图形的对称性，可以选择在扇形OAC中研究问题，过两个半圆的交点分别向OA，OC作垂线，则此时构成一个以1为边长的正方形，则这个正方形内的阴影部分面积为12-π，扇形OAC的面积为π，所求概率为πππ12112-=-=P．7．【答案】C【解析】解：∵a=ln2＜lne即，b=5=，c=xdx=，∴a，b，c的大小关系为：b＜c＜a．故选：C．【点评】本题考查了不等式大小的比较，关键是求出它们的取值范围，是基础题．8．【答案】C【解析】试题分析：由图可知存在常数，使得方程()f x t=有两上不等的实根，则314t<<，由1324x+=，可得14x=，由213x=，可得33x=（负舍），即有121113,4223x x≤<≤≤，即221143x≤≤，则()212123133,162x f x x x⎡⎫=⋅∈⎪⎢⎣⎭.故本题答案选C.考点：数形结合．【规律点睛】本题主要考查函数的图象与性质,及数形结合的数学思想方法.方程解的个数问题一般转化为两个常见的函数图象的交点个数问题来解决.要能熟练掌握几种基本函数图象,如二次函数,反比例函数,指数函数,对数函数,幂函数等.掌握平移变换,伸缩变换,对称变换,翻折变换,周期变换等常用的方法技巧来快速处理图象.9． 【答案】A【解析】解：由约束条件作出可行域如图，联立，得A （6，2），化目标函数z=x ﹣y 为y=x ﹣z ，由图可知，当直线y=x ﹣z 过点A 时，直线在y 轴上的截距最小，z 有最大值为4． 故选：A ．【点评】本题考查简单的线性规划，考查了数形结合的解题思想方法，是中档题．10．【答案】C.【解析】易得//BP 平面11CC D D ，所有满足1PBD PBX ∠=∠的所有点X 在以BP 为轴线，以1BD 所在直线为母线的圆锥面上，∴点Q 的轨迹为该圆锥面与平面11CC D D 的交线，而已知平行于圆锥面轴线的平面截圆锥面得到的图形是双曲线，∴点Q 的轨迹是双曲线，故选C. 11．【答案】D 【解析】考点：全称命题的否定. 12．【答案】A【解析】试题分析：由()f x 的最小正周期是π，得2ω=，即()sin(2)4f x x π=+sin 2()8x π=+，因此它的图象可由()sin 2g x x =的图象向左平移8π个单位得到．故选A ． 考点：函数()sin()f x A x ωϕ=+的图象与性质． 【名师点睛】三角函数图象变换方法：二、填空题（本大题共4小题，每小题5分，共20分.把答案填写在横线上）13． 【解析】14．【答案】15422=-x y 【解析】试题分析：由题意可知椭圆1362722=+y x 的焦点在y 轴上，且927362=-=c ，故焦点坐标为()3,0±由双曲线的定义可得()()()()4340153401522222=++---+-=a ,故2=a ，5492=-=b ，故所求双曲线的标准方程为15422=-x y ．故答案为：15422=-x y ． 考点：双曲线的简单性质；椭圆的简单性质． 15．【答案】345【解析】考点：点关于直线对称；直线的点斜式方程. 16．【答案】【解析】（2a ＋b ）·a ＝（2，－2＋t ）·（1，－1） ＝2×1＋（－2＋t ）·（－1） ＝4－t ＝2，∴t ＝2. 答案：2三、解答题（本大共6小题，共70分。