【考试必备】2018-2019年最新成都树德中学(外国语校区)初升高自主招生考试英语模拟试卷【解析】【4套】
2018年成都外国语学校自主招生考试化学卷(直升卷)

成都外国语学校高中自主招生化学真卷(考试时间:60分钟满分:100 分)可能用到的相对原子质量:H-1C-12O-16 C1-35.5S- 32 Ca- 40 Fe- 56第一卷(选择题,共30分)一、选择题(本题包括15个小题,每小题2分,共30分。
每小题至少有1个选项符合题意。
)1.下列选项中属于化学变化的是A.云变成雨B.酒精挥发C.大米酿酒D.石蜡熔化成液态2.下列对空气的成分描述正确的是A.空气是纯净物B.氧气支持呼吸和燃烧C.氮气的化学性质很活泼D.空气中只含有氧气和氮气3.我国“化学”一词最早出于《化学鉴原》(1871年)。
该书把一种元素翻译为“矽(xi)”。
在地壳里,“矽”的含量在所有元素含量中占第二位,现代把这种“矽”元素命名为A.锡B.硒C.氧D.硅4.下列粒子表示2个氧分子的是A.2O2B.2SO2C.2O2D.2H2O5.用右图装置可以探究二氧化碳的制取和性质。
下列关于该实验的叙述正确的是A.浸有紫色石蕊试液的棉花会变蓝B.粗铜丝能控制反应的发生和停止C.产生的二氧化碳可用生石灰干燥D.能验证二氧化碳的密度比空气大6.在10克SO 2与5克SO 3中氧原子的个数比是A.10:5B.4:3C.5:3D.3:57. 是某原子的结构示意图,以下说法正确的是:()A.该原子的元素符号为xB.该原子核外电子总数为4C.该种元素属于金属元素D.金刚石中含有该原子8.人们可从铁钛矿(主要成分FeTiO 3) 制取金属钛(Ti),其在一定条件下的主要反应有:①3222FeTiO H Fe TiO H O +=++;②224TiO 2C 2Cl TiCl 2CO ++=+;③42TiCl 2Mg 2MgCl Ti +=+下列叙述正确的是A.反应①中的H 2被氧化B.反应②中钛元素的化合价升高C.反应②Cl 2中的“CI ”失去电子D.反应③是复分解反应9.下列物质中既存在离子又存在分子的是A.氯化钠晶体B.金刚石C.氯化钠溶液D.液氧10.下列图①~④分别与相应的操作过程相对应,其中正确的是①②③④A.①在恒温的条件下,将足量的氯化钠饱和溶液蒸发适量的水分B.②向露置在空气中部分变质的氢氧化钠溶液中加入稀盐酸C.③向氢氧化钠溶液中不断加入水稀释D.④相同质量的且过量的锌粉和铁粉,分别与质量和质量分数相同的稀盐酸反应11.下列有关物质的燃烧现象的叙述中,正确的是A.铁丝在氧气中燃烧:火星四射,生成红色固体B.镁条在空气中燃烧:发出耀眼的白光,只生成一种黑色固体C.硫粉在空气中燃烧:产生淡蓝色火焰,生成一种刺激性气味的气体D.红磷在空气中燃烧:发出白光,生成大量的白色烟雾12.已知甲、乙、丙、丁四种溶液分别是K2CO3溶液、Na2SO4溶液、BaCl2溶液和稀HCl中的一种。
成都市外国语国际学校2019年初升高入学考试(含自主招生考)英语试题及答案

成都市外国语国际学校2019年初升高入学考试(含自主招生考)英语试题及答案(答卷时间:90分钟满分:100 分)本试卷分第Ⅰ卷和第Ⅱ卷。
第Ⅰ卷为选择题,请考生把第Ⅰ卷各题答案填在题后答题卡上;第Ⅱ卷为非选择题。
第Ⅰ卷(选择题共65 分)一.单项填空(本大题共15小题,每小题1分,共15分)1. When he was there, he ______ go to that coffee shop at the corner after work every day.A. wouldB. shouldC. had betterD. might2. Shirley ______ a book about China last year but I don’t know whether she has finished it.A. has writtenB. wroteC. had writtenD. was writing3. She ______ his number in the phone book to make sure that she had got it right.A. looked forB. looked upC. looked afterD. looked like4. ---I called you just now, but you weren’t in.---Sorry, I ______ the reading room.A. was inB. have gone toC. studiedD. had been to5. He’s n ever stolen anything before, ______ he?______. It’s his third time to be taken to police station.A. hasn’t; YesB. is; YesC. has; YesD. has; No6. ______ you the truth, she knows nothing about it.A. To tellB. TellingC. TellD. Told7.The old man walked in the street, ______.A. followed by his sonB. followed his sonC. and following his sonD. and followed by his son8.I am going to Qingdao and stay there for a week.______ you are there, would you please buy some books for me?A .If B. While C. Since D. As soon as9.Could you give me ______ second chance please?A. anB./C. theD. a10.Is that book ______ he borrowed on Friday?A. thatB. whichC. the oneD. who11.The train ______ she was traveling was five minutes late.A. thatB. on thatC. by whichD. on which12.There are four pairs of socks to ______, but the woman doesn’t know ______ to buy.A. choose from; whichB. choose from; whatC. choose; whichD. choose; what13. --Would you like some coffee?--Yes, please. By the way, do you have any milk? I prefer coffee ______ milk.A. fromB. withC. toD. for 14.John plays football ______, if not better than David.A. as wellB. as well asC. so wellD. so well as15. ---where did you meet you girlfriend?---It was in the store she workedA. thatB. whereC. oneD. which二.完型填空(20小题,每小题1分,共20分)阅读下面短文,掌握其大意,然后从16~35各题所给的四个选项(A、B、C和D)中,选出最佳选项。
【考试必备】2018-2019年最新成都外国语学校初升高自主招生化学模拟精品试卷【含解析】【4套试卷】

2018-2019年最新成都外国语学校初升高自主招生化学模拟精品试卷(第一套)一、选择题(共12小题,每小题3分,满分18分)1.(3分)甲、乙两烧杯中分别盛有等体积、等溶质质量分数的H2SO4溶液.现向甲杯中加入m克Mg,向乙杯中加入m克Zn,充分反应后,有一只烧杯中仍有金属未溶解,则甲、乙烧杯中原有H2SO4的溶质质量x应为()A.g≤x<g B.g>x≥g C.x=g D.x<g2.(3分)某白色粉末可能含有NaOH、Na2CO3、Na2SO4、NaCl中的一种或几种.为探究白色粉末的性质,将该粉末放入足量水中,充分搅拌后,把所得溶液分为三份进行实验:(1)第一份溶液中滴加酚酞后,溶液呈红色;(2)第二份溶液中滴加稀盐酸后,开始无明显现象,随着盐酸的滴入逐渐有气泡产生;(3)第三份溶液中滴加BaCl2后有白色沉淀生成,过滤,所得沉淀全部溶于稀盐酸,分析实验得出的以下结论,合理的是()A.一定含有Na2CO3,一定没有Na2SO4、NaCl,可能含有NaOHB.一定含有Na2CO3,一定没有Na2SO4、NaOHC.一定含有Na2CO3、NaCl,一定没有Na2SO4,可能含有NaOHD.一定含有Na2CO3,一定没有Na2SO43.(3分)小婧做探究性实验:用称量法测定铁在O2中燃烧的产物.发现5.6g铁在足量的O2中燃烧得到7.82g固体.小婧排除了其他因素可能产生的误差,则她得到的固体产物可能是()A.Fe3O4和Fe的混合物B.Fe3O4和FeO的混合物C.Fe3O4、FeO和Fe的混合物D.Fe3O4和Fe2O3的混合物4.(3分)有Na、S、O、H四种元素中的二种或三种元素组成四种常见的化合物.甲能跟氯化钡反应生成一种硫酸盐和另﹣种盐,乙能跟氢氧化钠反应生成盐和水,丙能跟盐酸反应生成盐和水,丁呈中性,且可以分别跟氧化钙或二氧化碳发生化合反应,生成相应的碱或酸,其中下列推断:①甲﹣定是硫酸钠;②乙可能是硫酸;③丙﹣定是氢氧化钠;④丁﹣定是水.其中正确的一组是()A.①②③B.②③④C.①③④D.①②④5.(3分)下列各物质无论以何种比例混合,其氯元素的质量分数不变的是()A.HClO4、KClO3B.NaClO、KCl C.KClO、KCl D.NaCl、KCl6.(3分)(2014•南海区二模)已知所含元素化合价发生变化的反应是氧化还原反应,其中被还原的元素化合价降低,被氧化的元素化合价升高.海洋中有丰富的资源,如图所示利用海水可获得许多化工产品.下列有关说法正确的是()A.第①步中除去粗盐中的SO42﹣、Ca2+、Mg2+等杂质,加入的试剂顺序为:Na2CO3溶液、NaOH溶液、BaCl2溶液,过滤后加盐酸B.第②步中加入的试剂为CaCl2溶液C.第③步中发生分解反应D.在第④步中溴元素被还原8.有一包不纯的Na2CO3样品,其中只含一种杂质,现取该样品5.3g与足量稀盐酸反应生成2.4g CO2,则所混杂质可能是()A.BaCO3B.K2CO3C.CaCO3D.MgCO310.无色溶液可能由K2CO3、MgCl2、NaHCO3、BaCl2溶液中的一种或几种组成.向溶液中加入烧碱溶液出现白色沉淀,加入稀硫酸也出现白色沉淀并放出气体.据此分析,下列判断中正确的是()①肯定有BaCl2;②肯定有MgCl2;③肯定有NaHCO3;④肯定有Na2CO3或NaHCO3⑤肯定没有MgCl2.A.①②③B.②④C.①③D.①③⑤11.(2010•常州模拟)Fe、Mg、Al 三种金属分别跟稀盐酸充分反应,得到相同质量的氢气,其原因是:①Fe、Mg、Al的质量相等,盐酸足量;②Fe、Mg、Al的质量比是56:24:27,盐酸足量;③Fe、Mg、Al的质量比是28:12:9,盐酸足量;④Fe、Mg、Al均为过量,所用盐酸的质量分数和质量都相同.你认为可能的原因是()A.③④B.①②C.①③D.②③14.t℃时,Na2CO3溶解度为Ag,现有饱和Na2CO3溶液(100+A)g,溶质质量分数为a%;向该溶液中投入无水碳酸钠Ag,静置后析出碳酸钠晶体(Na2CO3•10H2O)Bg;加水使晶体全部溶解,所得溶液质量分数为a%,则加入水的质量为()A.(100+A)g B.100g C.g D.(100﹣A•a%)g16.(2012•新乡模拟)由Mg(OH)2和MgO组成的混合物,测得其中含镁元素的质量分数为48%.取该混合物10g,将其投入110g的稀硫酸中恰好完全反应,所得溶液中溶质的质量分数为()A.12% B.24% C.20% D.30%17.(2011•平房区二模)已知将氯酸钾加热到较高温度时,氯酸钾可以发生分解放出氧气.现有氯酸钾和氯化钾的固体混合物共319.5克,在较高温度下将其加热至固体质量不再减少为止.而后将所得固体加入足量的水中充分溶解后,再向其中加入足量的硝酸银溶液,充分反应后得沉淀的质量为430.5克.则原固体混合物中氯酸钾的质量分数为()A.35% B.50% C.76.7% D.82.14%二、解答题(共6小题,满分0分)7.(2011•西城区二模)工业上用CaSO4、NH3、CO2制备硫酸铵晶体(NH4)2SO4,过程如图所示.(1)硫酸铵在农业生产上的一种用途是_________ ,它属于_________ (填“酸”、“碱”或“盐”).(2)操作①中需要使用的玻璃仪器有_________ ;从滤液中得到硫酸铵晶体,正确操作顺序是_________ →_________ →_________ (填序号).a.过滤 b.加热浓缩 c.冷却结晶(3)用CaSO4、NH3、CO2制备硫酸铵的化学方程式是_________ .12.(2010•青岛)某气体可能含有氢气、一氧化碳、二氧化碳、水蒸气和氯化氢中的一种或几种,为了确定其成分,将该气体依次进行如下实验(假设各步均完全反应):①通过浓硫酸,浓硫酸质量增加;②通过澄清石灰水,石灰水不变浑浊;③先通过浓硫酸,再通过灼热的氧化铜,固体由黑色变成红色;④通过无水硫酸铜,固体不变色(无水硫酸铜具有遇水变蓝的性质);⑤通过澄清石灰水,石灰水变浑浊.请根据上述实验现象推断,并用化学式填空:该气体中一定有_________ ,一定没有_________ ,无法确定的是_________ .13.某一种气体可能是氮气、水蒸气、二氧化碳、氢气和一氧化碳中的一种或几种,某学生设计了如下实验来分析研究该气体的成分.该学生观察到如下化学现象:装置A中澄清的石灰水变白色浑浊,装置B中白色无水硫酸铜变蓝,装置C中浓硫酸无明显变化,装置D中黑色的氧化铜变为一种亮红色物质,装置E中澄清的石灰水变白色浑浊,装置F中白色的无水硫酸铜变蓝色.该学生从上述实验现象中得出如下结论:气体中①肯定不含二氧化碳,②肯定含一氧化碳,③肯定含水蒸气,④肯定含氢气,⑤可能含氮气.请你分析:(1)上述不正确的结论是(填代号)_________ ,你认为不正确的原因是_________ .(2)上述正确的结论是(填代号)_________ .(3)当使本实验有可能得出更多的正确结论,可将各实验仪器重新连接,你认为的连接次序是(从左到右填写仪器代号)_________ .15.某校的化学学习小组根据下面给出的药品和实验装置,设计一个实验,粗略测定由铜和锌两种金属组成的合金﹣黄铜中锌的质量分数(黄铜已加工成粉末).实验装置如图(另有托盘天平可用):【药品】稀硫酸、浓硫酸、氧化铜【分析与思考】同学们通过充分“交流﹣分析﹣讨论”后一致认为,设计以下三种实验方案可测出黄铜中锌的质量分数.C装置中,提供热源的仪器名称是酒精灯酒精灯,三种方案都必需选用的药品是稀硫酸稀硫酸.同学们用过量该药品与称取的ag黄铜粉样品进行充分反的体积bL(已知氢气的密度);应后,实验中测定了以下数据:①测定生成H2②过滤、洗涤、烘干后,测定漏斗中剩余固体的纯净质量为Cg;③充分反应后,测定A装置中仪器和药品总质量减少了d克.【方案一】小悦同学仅选用一个实验装置_________ 进行实验,用测定数据_________ ,通过计算可求出黄铜中锌的质量分数为(写计算结果)_________ 装置A 中发生反应的化学方程式为_________【方案二】小华同学选用两个装置_________ (填装置编号,以下同)进行实验,并用测定数据_________ (填数据编号,以下同),通过计算也求出了黄铜中锌的质量分数.【方案三】小琳同学选用三个实验装置进行实验,装置连接的顺序是(用装置接口处的编号表示)_________ ,并用测定的数据_________ ,通过计算也求出了黄铜中锌的质量分数.【反思与评价】同学们对上述三种实验方案进行了综合评价,一致认为方案一一简单易行.18.某实验小组欲测定某白色粉末(已知是碳酸钠与碳酸氢钠的混合物)的组成,取三份质量不同的样品甲、乙、丙分别与30g稀盐酸充分反应,得到的常温常压下气体体积关系如下表,试求:(1)样品中碳酸钠的质量分数?(2)稀盐酸的质量分数?(已知二氧化碳常温常压下的密度是1.97g/L)(计算过程中保留两位小数)甲乙丙混合物质量/g 3.80 7.60 11.4二氧化碳的体积/L 0.893 1.786 1.78619.(2010•扬州)叠氮化钠(NaN3)被广泛应用于汽车安全气囊,某兴趣小组对其进行下列研究.应用研究:(1)汽车经撞击后,30毫秒内引发NaN3,迅速分解为Na、N2,反应方程式为_________ .制备研究:(2)将金属钠与液态氨反应得NaNH2,再将NaNH2与N2O反应可生成NaN3、NaOH和气体X,该反应的化学方程式为2NaNH2+N2O=NaN3+NaOH+X,实验室检验X气体使用的试纸是湿润的_________ .Na2CO3质量分数测定:工业级NaN3中常含有少量的Na2CO3,为测定样品中Na2CO3的质量分数设计如图装置(已知H2SO4溶液与NaN3,反应不生成气体).(3)装置A的作用是_________ .设计的实验步骤为:①精确称量样品,检查装置气密性;②打开弹簧夹,鼓入空气,称量装置C;③关闭弹簧夹,打开分液漏斗活塞;④再打开弹簧夹,_________ ;⑤再次称量装置C.计算碳酸钠含量至少需要测定_________ (填数字)个数据.根据制备反应,分析工业级NaN3中含有Na2CO3的可能原因_________ .NaN3纯度测定:精确称量0.140g NaN3样品,设计如图装置,测定其纯度.已知2NaN3→3N2(NaN3中的N全部转化为N2,其他产物略),反应中放出大量的热.(4)检查该装置气密性的方法是连接好装置,从水准瓶注水,量气管中液面与右边液面形成高度差,做好标记,一段时间后,两边高度差_________ (填“变大”、“变小”或“不变”),说明气密性良好.(5)使小试管中的NaN3样品与M溶液接触的操作是_________ .(6)使用冷水冷凝的目的是_________ .反应前应将液面调节到量气管的“0”刻度,并使两边液面相平,反应后读数时,还需要进行的操作是_________ .的密度为1.25g/L),则实验中选用的量气管规格(7)常温下测得量气管读数为67.2mL(N2合适的是_________ (填字母序号).A.100mLB.1LC.2L(8)计算NaN样品的纯度(写出计算过程).32018-2019年最新成都外国语学校初升高自主招生化学模拟精品试卷(第一套)参考答案与试题解析一、选择题(共12小题,每小题3分,满分18分)1.(3分)甲、乙两烧杯中分别盛有等体积、等溶质质量分数的H2SO4溶液.现向甲杯中加入m克Mg,向乙杯中加入m克Zn,充分反应后,有一只烧杯中仍有金属未溶解,则甲、乙烧杯中原有H2SO4的溶质质量x应为()A.g≤x<g B.g>x≥gC.x=gD.x<g考点:根据化学反应方程式的计算.专题:有关化学方程式的计算.分析:根据题干提供的数据,首先计算出是哪种金属剩余,然后根据反应的化学方程式计算出硫酸质量的取值范围即可.解答:解:设与mg镁反应消耗硫酸的质量为x,与mg锌反应消耗硫酸的质量为y,H 2SO4+Mg═MgSO4+H2↑98 24x mg=,x=gH 2SO4+Zn═ZnSO4+H2↑98 65y mg=,y=g,由此可以得出相同质量的镁和锌,镁可以消耗更多质量的硫酸,所以剩余金属一定是镁,那么要使镁有剩余而锌完全反应,则原来硫酸质量x的取值范围为:g≤x<g.故选:B.点评:本题考查了金属与酸反应的质量关系,完成此题,可以依据有关反应的化学方程式进行.2.(3分)某白色粉末可能含有NaOH、Na2CO3、Na2SO4、NaCl中的一种或几种.为探究白色粉末的性质,将该粉末放入足量水中,充分搅拌后,把所得溶液分为三份进行实验:(1)第一份溶液中滴加酚酞后,溶液呈红色;(2)第二份溶液中滴加稀盐酸后,开始无明显现象,随着盐酸的滴入逐渐有气泡产生;(3)第三份溶液中滴加BaCl2后有白色沉淀生成,过滤,所得沉淀全部溶于稀盐酸,分析实验得出的以下结论,合理的是()A.一定含有Na2CO3,一定没有Na2SO4、NaCl,可能含有NaOHB.一定含有Na2CO3,一定没有Na2SO4、NaOHC.一定含有Na2CO3、NaCl,一定没有Na2SO4,可能含有NaOHD.一定含有Na2CO3,一定没有Na2SO4考点:物质的鉴别、推断;碱的化学性质;盐的化学性质.专题:混合物组成的推断题.分析:根据物质的性质结合有关的实验现象进行分析解答,(1)第一份溶液中滴加酚酞后,溶液呈红色,说明溶液呈碱性,可能含有氢氧化钠或碳酸钠;(2)第二份溶液中滴加稀盐酸后,开始无明显现象,随着盐酸的滴入逐渐有气泡产生,说明一定有氢氧化钠和碳酸钠;(3)第三份溶液中滴加BaCl2后有白色沉淀生成,过滤,所得沉淀全部溶于稀盐酸,由于硫酸钡沉淀不溶于稀盐酸,故一定不含有硫酸钠,据此解答.解答:解:(1)第一份溶液中滴加酚酞后,溶液呈红色,说明溶液呈碱性,可能含有氢氧化钠或碳酸钠;(2)第二份溶液中滴加稀盐酸后,开始无明显现象,随着盐酸的滴入逐渐有气泡产生,说明一定有氢氧化钠和碳酸钠;(3)第三份溶液中滴加BaCl2后有白色沉淀生成,过滤,所得沉淀全部溶于稀盐酸,由于硫酸钡沉淀不溶于稀盐酸,故一定不含有硫酸钠,无法确定氯化钠是否存在;A、氢氧化钠一定存在,氯化钠可能存在,故A错误;B、氢氧化钠一定存在,故B错误;C、氯化钠不一定含有,故C错误;D、一定含有Na2CO3,一定没有Na2SO4,故D正确;故选D,点评:本题考查了常见混合物成分的推断,完成此题,可以依据已有的知识结合物质的性质和物质间反应的实验现象进行.3.(3分)小婧做探究性实验:用称量法测定铁在O2中燃烧的产物.发现5.6g铁在足量的O2中燃烧得到7.82g固体.小婧排除了其他因素可能产生的误差,则她得到的固体产物可能是()A.F e3O4和Fe的混合物B.F e3O4和FeO的混合物C.F e3O4、FeO和Fe的混合物D.F e3O4和Fe2O3的混合物考点:金属的化学性质;物质组成的综合计算;根据化学反应方程式的计算.专题:压轴实验题;有关化学方程式的计算.分析:铁在氧气中燃烧能生成四氧化三铁,可先计算5.6g铁在足量的O2中燃烧生成四氧化三铁的质量,然后进行比较,得出合理的答案.解答:解:设5.6g铁完全燃烧生成四氧化三铁的质量为x,则有:3Fe+2O2Fe3O4168 2325.6g x=x≈7.7g而实际上得到的固体质量为7.82g>7.7g,说明生成的另一物质的含氧量比四氧化三铁的含氧量高.Fe3O4、FeO、Fe2O3含氧量比较大小,可根据铁原子个数相等将化学式变形,即Fe6O8、Fe6O6、Fe6O9由此可见,Fe2O3含氧量高于四氧化三铁.故选D.点评:本题考查了金属铁的化学性质,完成此题可以依据已有的铁的性质进行.4.(3分)有Na、S、O、H四种元素中的二种或三种元素组成四种常见的化合物.甲能跟氯化钡反应生成一种硫酸盐和另﹣种盐,乙能跟氢氧化钠反应生成盐和水,丙能跟盐酸反应生成盐和水,丁呈中性,且可以分别跟氧化钙或二氧化碳发生化合反应,生成相应的碱或酸,其中下列推断:①甲﹣定是硫酸钠;②乙可能是硫酸;③丙﹣定是氢氧化钠;④丁﹣定是水.其中正确的一组是()A.①②③B.②③④C.①③④D.①②④考点:复分解反应的条件与实质;物质的鉴别、推断.专题:常见物质的推断题.分析:盐是由金属离子和酸根离子组成的化合物.酸性氧化物能与碱溶液反应生成盐和水,碱性氧化物能与酸反应生成盐和水.解答:甲能跟氯化钡反应生成一种硫酸盐和另一种盐,说明甲中含有硫酸根离子和一种金属离子;乙能跟氢氧化钠反应生成盐和水,说明乙是一种酸或酸性氧化物;丙能跟盐酸反应生成盐和水,说明丙是金属氧化物或碱;丁呈中性,且可以分别跟氧化钙或二氧化碳发生化合反应,生成相应的碱或酸,说明丁是水.故选D点评:此题考查了酸的化学性质、碱的化学性质等多方面的知识,要真正的掌握所学的知识,才能得心应手的做题.5.(3分)下列各物质无论以何种比例混合,其氯元素的质量分数不变的是()A.H ClO4、KClO3B.N aClO、KCl C.K ClO、KCl D.N aCl、KCl考点:元素的质量分数计算.专题:化学式的计算.分析:根据物质中某元素的质量分数=×100%,分别计算选项中氯元素的质量分数,氯元素的质量分数相同的符合题意.解答:解:A.HClO4中氯元素的质量分数为:×100%=35.32%;KClO3中氯元素的质量分数为:×100%=28.98%;B.NaClO中氯元素的质量分数为:×100%=47.65%;KCl中氯元素的质量分数为:×100%=47.65%;C.KClO中氯元素的质量分数为:×100%=39.23%;KCl中氯元素的质量分数为:×100%=47.65%;D.NaCl中氯元素的质量分数为:×100%=60.68%;KCl中氯元素的质量分数为:×100%=47.65%;由此可知,选项B符合题意;故选B.点评:本题考查学生对物质中某元素的质量分数计算方法的掌握与应用的能力.6.(3分)(2014•南海区二模)已知所含元素化合价发生变化的反应是氧化还原反应,其中被还原的元素化合价降低,被氧化的元素化合价升高.海洋中有丰富的资源,如图所示利用海水可获得许多化工产品.下列有关说法正确的是()A.第①步中除去粗盐中的SO42﹣、Ca2+、Mg2+等杂质,加入的试剂顺序为:Na2CO3溶液、NaOH溶液、BaCl2溶液,过滤后加盐酸B.第②步中加入的试剂为CaCl2溶液C.第③步中发生分解反应D.在第④步中溴元素被还原考点:对海洋资源的合理开发与利用;氯化钠与粗盐提纯;分解反应及其应用.专题:压轴实验题;物质的分离、除杂、提纯与共存问题.分析:根据转化图可知,①为粗盐提纯,利用物质之间的发生及除杂的原则来分析;②为物质的转化,根据反应物与生成物的组成来选择试液;③为结晶水合物失去结晶水的反应;④为制备溴单质的反应,利用反应中溴元素的化合价来分析.解答:解:A、除去粗盐中的SO42﹣、Ca2+、Mg2+等杂质,先除硫酸根离子,需要BaCl2溶液,再除镁离子,需要NaOH溶液,最后除钙离子,加入Na2CO3溶液,故A错误;B、由②中物质的组成可知,要与氢氧化镁反应应选择盐酸,故B错误;C、由③的转化可知,结晶水合物失去结晶水并生成氯化镁,是一种物质反应生成两种物质,则属于分解反应,故C正确;D、由④可知NaBr→Br2,NaBr中溴元素的化合价为﹣1价,单质中溴元素的化合价为0,则在反应中溴元素的化合价升高,由信息可知溴元素被氧化,故D错误;故选C.点评:本题较难,考查海水资源的利用,学生应熟悉粗盐提纯及物质转化中的化学反应并利用信息来综合解答,在物质转化中应学会利用组成的差异来选择合适的试剂.8.有一包不纯的Na2CO3样品,其中只含一种杂质,现取该样品5.3g与足量稀盐酸反应生成2.4g CO2,则所混杂质可能是()A.B aCO3B.K2CO3C.C aCO3D.M gCO3考点:证明碳酸盐;酸的化学性质;盐的化学性质;根据化学反应方程式的计算.专题:压轴实验题;有关化学方程式的计算;推断混合物的可能组成;常见的酸酸的通性;常见的盐化学肥料.分析:要计算含有的另一种杂质,可以根据归一法求混合物的相对分子质量,之后分析给定物质的相对分子质量解答:解:设该盐为纯净的+2价碳酸盐,设该金属为M,对应的碳酸盐的相对分子质量为x.MCO3+2HCl=MCl2+CO2↑+H2Ox 445.3g 2.4g=解得:x≈97;由于碳酸钠的相对分子质量为106,所以所含杂质的相对分子质量必须小于97,给定物质中只有碳酸镁的相对分子质量为84,小于97.故选D.故选D.点评:本题考查了混合碳酸盐与酸反应生成二氧化碳质量,完成此题,需使用极值法和平均值法.10.无色溶液可能由K2CO3、MgCl2、NaHCO3、BaCl2溶液中的一种或几种组成.向溶液中加入烧碱溶液出现白色沉淀,加入稀硫酸也出现白色沉淀并放出气体.据此分析,下列判断中正确的是()①肯定有BaCl2;②肯定有MgCl2;③肯定有NaHCO3;④肯定有Na2CO3或NaHCO3⑤肯定没有MgCl2.A.①②③B.②④C.①③D.①③⑤考点:物质的鉴别、推断;酸的化学性质;盐的化学性质.专题:混合物组成的推断题.分析:根据向溶液中加入烧碱溶液出现白色沉淀,说明含有MgCl2或含有NaHCO3、BaCl2或MgCl2、NaHCO3,另取溶液加入稀硫酸也出现白色沉淀并放出气体证明一定含有NaHCO3、BaCl2溶液,依据离子共存分析确定,氯化钡和碳酸钾会生成白色的碳酸钡沉淀,不能共存,所以溶液中一定不含K2CO3,可能含有MgCl2.解答:解:某无色溶液可能由K2CO3、MgCl2、NaHCO3、BaCl2溶液中的一种或几种组成,向溶液中加入烧碱溶液出现白色沉淀,说明含有MgCl2或含有NaHCO3、BaCl2或MgCl2、NaHCO3,另取溶液加入稀硫酸也出现白色沉淀并放出气体证明一定含有NaHCO3、BaCl2溶液,依据离子共存分析确定,氯化钡和碳酸钾会生成白色的碳酸钡沉淀,不能共存,所以溶液中一定不含K2CO3,可能含有MgCl2.综上所述:一定含有NaHCO3、BaCl2溶液,一定不含K2CO3,可能含有MgCl2.所以判断正确的是①③.故选:C.点评:本题考查了离子检验方法,明确物质性质的分析判断、离子反应的现象和离子共存是解题关键.11.(2010•常州模拟)Fe、Mg、Al 三种金属分别跟稀盐酸充分反应,得到相同质量的氢气,其原因是:①Fe、Mg、Al的质量相等,盐酸足量;②Fe、Mg、Al的质量比是56:24:27,盐酸足量;③Fe、Mg、Al的质量比是28:12:9,盐酸足量;④Fe、Mg、Al均为过量,所用盐酸的质量分数和质量都相同.你认为可能的原因是()A.③④B.①②C.①③D.②③考点:根据化学反应方程式的计算.专题:有关化学方程式的计算.分析:F e、Mg、Al 三种金属分别跟稀盐酸反应的化学方程式为:Fe+2HCl═FeCl2+H2↑,Mg+2HCl═MgCl2+H2↑,2Al+6HCl═2AlCl3+3H2↑,由此可知,产生氢气的是盐酸中的氢离子,故要得到相同质量的氢气有两种情况:①参与反应的HCl的质量相等;②参与反应的Fe、Mg、Al的质量符合得到相同质量的氢气的条件.解答:解:①因为产生氢气的是盐酸中的氢离子,故参与反应的HCl的质量相等,产生的氢气的质量就相等.故④符合;②假设Fe、Mg、Al 三种金属分别跟稀盐酸充分反应,得到氢气的质量都是2g,设参与反应的Fe的质量为x,Mg的质量为y,Al的质量为z,Fe+2HCl═FeCl2+H2↑,Mg+2HCl═MgCl2+H2↑,2Al+6HCl═2AlCl3+3H2↑,56 2 24 2 54 6x 2g y 2g z 2g∴=,,,解之得:x=56g,y=24g,z=18g,故Fe、Mg、Al的质量比为:56g:24g:18g=28:12:9.故③符合;①②不符合;故选A.点评:本题主要利用化学方程式和假设法解答问题.在利用化学方程式解答问题时,运用假设法,对解题有很大作用.14.t℃时,Na2CO3溶解度为Ag,现有饱和Na2CO3溶液(100+A)g,溶质质量分数为a%;向该溶液中投入无水碳酸钠Ag,静置后析出碳酸钠晶体(Na2CO3•10H2O)Bg;加水使晶体全部溶解,所得溶液质量分数为a%,则加入水的质量为()A.(100+A)g B.100g C.gD.(100﹣A•a%)g考点:溶质的质量分数、溶解性和溶解度的关系.专题:溶液、浊液与溶解度.分析:根据固体溶解度的概念和同一温度下同种物质的饱和溶液溶质质量分数=×100%解答.解答:解:t℃时,Na2CO3溶解度为Ag,现有饱和Na2CO3溶液(100+A)g,溶质质量分数为a%;向该溶液中投入无水碳酸钠Ag,静置后析出碳酸钠晶体(Na2CO3•10H2O)Bg;加水使晶体全部溶解,所得溶液质量分数为a%,说明所得溶液还是该温度下的饱和溶液,所以就相当于计算该温度下溶解Ag无水碳酸钠所需要的水的质量,该温度下,Na2CO3溶解度为Ag,说明100g水该温度下正好饱和;所以加入水的质量为100g,故答案选B.点评:同一温度下同种物质的饱和溶液溶质质量分数=×100%.16.(2012•新乡模拟)由Mg(OH)2和MgO组成的混合物,测得其中含镁元素的质量分数为48%.取该混合物10g,将其投入110g的稀硫酸中恰好完全反应,所得溶液中溶质的质量分数为()A.12% B.24% C.20% D.30%考点:有关溶质质量分数的简单计算;质量守恒定律及其应用.专题:元素质量守恒.分析:根据镁元素的质量分数可计算镁元素的质量,利用反应后的溶质为硫酸镁,根据镁原子守恒来计算硫酸镁的质量,混合物与酸的质量和为溶液质量,最后计算溶质的质量分数.解答:解:混合物中镁元素的质量为10g×48%=4.8g,设恰好完全反应后溶液中硫酸镁的质量为xg,由镁元素守恒可知,Mg~MgSO424 1204.8g x解得x=24g,反应后溶液质量为10g+110g=120g,则溶液中溶质的质量分数为×100%=20%,故选:C.点评:本题考查溶液中溶质质量分数的计算,学生应能利用元素守恒的方法来计算溶质的质量是解答中的关键,不可盲目利用化学方程式来计算溶质质量.17.(2011•平房区二模)已知将氯酸钾加热到较高温度时,氯酸钾可以发生分解放出氧气.现有氯酸钾和氯化钾的固体混合物共319.5克,在较高温度下将其加热至固体质量不再减少为止.而后将所得固体加入足量的水中充分溶解后,再向其中加入足量的硝酸银溶液,充分反应后得沉淀的质量为430.5克.则原固体混合物中氯酸钾的质量分数为()A.35% B.50% C.76.7% D.82.14%考点:根据化学反应方程式的计算.专题:有关化学方程式的计算.分析:根据氯化钾和硝酸银反应的化学方程式,利用沉淀的质量可求出氯化钾的质量;根据质量守恒定律,原固体混合物的质量和氯化钾的质量之差就是氯酸钾分解放出氧气的质量;然后根据氯。
成都市外国语国际学校2019年初升高入学考试(含自主招生考)物理试题及答案

成都市外国语国际学校2019年初升高入学考试(含自主招生考)物理试题及答案(答卷时间:45分钟满分:50分)一、选择题(每小题2分,共16分)在每个小题的选项中,只有一个选项符合题目要求,请将其序....。
号填入下面的答案栏中..........1、如图所示的四种现象中,属于光的直线传播的是()2、根据分子运动论,下列说法中错误的是()A.温度升高,液体蒸发加快B.温度升高,大量分子无规则运动加快C.温度升高,气体、液体、固体的扩散加快D.温度升高,物体的动能越大3、在下列事例中,属于内能转化为机械能的是()A.钻木取火B.厚玻璃筒里的空气被压缩,温度升高C.水壶中的水沸腾后,壶盖被水蒸气顶起D.把热的工件放到冷水中,使冷水变热4、甲、乙两同学沿平直路面步行,他们运动的路程随时间变化的规律如图所示,下面说法中错误的是()A.甲同学比乙同学晚出发4sB.4s~8s内,甲、乙两同学都做匀速直线运动C.0s~8s内,甲、乙两同学通过的路程相等D.8s末甲、乙两同学速度相等5、妙趣横生的动物世界蕴涵着丰富的物理知识,下列说法中错误的是( ) A .骆驼的脚掌较大,可以减小压力,从而使其在沙漠中行走自如 B .鱼要下沉时就吐出鱼鳔内的空气,减小排开的水的体积而使浮力变小C .壁虎的脚掌上有许多“吸盘”,从而利用大气压使其在天花板上也不会掉下来D .蝙蝠靠主动发射并接收自障碍物反射回来的超声波准确定位6、小明在洗苹果时,发现有一个苹果悬浮在盆里的水中,他拿起这个苹果,用小刀把苹果削了一小块下来,又发现这一小块苹果会沉于水底,因此他基于上述现象做出下列判断,正确的是( ) A .大块苹果的平均密度与完整苹果的平均密度相同 B .大块苹果的平均密度小于水的密度C .如果把大块苹果放入水中,大块苹果仍然会悬浮于水中D .如果把大块苹果放入水中,大块苹果也会在水中下沉7、在如图所示电路中,电源电压保持不变,当滑动变阻器的滑片P 由中点滑向最右端时,安培表和伏特表示数的变化是( )A .安培表示数变大,伏特表示数变大B .安培表示数变小,伏特表示数变大C .安培表示数变小,伏特表示数不变D .安培表示数变大,伏特表示数不变8、如图所示,定滑轮重2N ,动滑轮重1N 。
【考试必备】2018-2019年最新成都市实验外国语学校初升高自主招生语文模拟精品试卷【含解析】【4套试卷】

2018-2019年最新四川成都市实验外国语学校自主招生语文模拟精品试卷(第一套)(满分:100分考试时间:90分钟)一、语文基础知识(18分,每小题3分)1.下列词语中加点的字,读音全都正确的一组是()A.连累(lěi) 角(juã)色河间相(xiàng) 冠冕(miǎn)堂皇B专横(hâng) 忖(cǔn)度涮(shuàn) 羊肉妄加揣(chuāi)测C.笑靥(yâ) 顷(qīng)刻汗涔(cãn)涔休戚(qì)相关D慨叹(kǎi) 俨(yǎn)然刽子手(kuàì) 刎(wěn)颈之交2、下列各项中字形全对的是()A、橘子州偌大急躁光阴荏苒B、蒙敝犄角慰籍书生意气C、敷衍磕绊笔竿艰难跋涉D、翱翔斑斓屏蔽自怨自艾3、依次填入下列各句横线上的词语,最恰当..的一项是()⑴虽然他尽了最大的努力,还是没能住对方凌厉的攻势,痛失奖杯。
⑵那些见利忘义,损人利己的人,不仅为正人君子所,还很可能滑向犯罪的深渊。
⑶我认为,真正的阅读有灵魂的参与,它是一种个人化的精神行为。
A.遏制不耻必需B.遏止不耻必需C.遏制不齿必须D.遏止不齿必须4、下列句中加点的成语,使用恰当的一句是()A、故宫博物院的珍宝馆里,陈列着各种奇珍异宝、古玩文物,令人应接不暇。
B、任何研究工作都必须从积累资料做起,如果不掌握第一手资料,研究工作只能是空中楼阁....。
C、电影中几处看来是闲笔,实际上却是独树一帜之处。
D、这部精彩的电视剧播出时,几乎万人空巷,人们在家里守着荧屏,街上显得静悄悄的。
5、下列句子中,没有语病的一项是()A 大学毕业选择工作那年,我瞒着父母和姑姑毅然去了西藏支援边疆教育。
B北京奥运会火炬接力的主题是‚和谐之旅‛,它向世界表达了中国人民对内致力于构建和谐社会,对外努力建设和平繁荣的美好世界。
C他不仅是社会的一员,同时还是宇宙的一员。
2019年成都树德中学自主招生考试物理试卷(含答案)

2019年四川省成都市树德中学自主招生考试物理试卷一、不定项选择题(本题共12 小题,每小题 3 分,共36 分,在每小题给出的四个选项中,有的只有一个选项是正确的,有的有多个选项正确,全部选对的得 3 分,选对但不全的得2 分,有选错的得0 分。
)1、小明得眼睛近视了,他到医院配眼镜,经仪器检测左眼应配戴焦距为0.5m 的透镜,右眼应佩戴焦距为1m 的透镜,下列说法正确的()A.光线进入正常眼睛,在视网膜上呈倒立缩小的虚像B.他应佩戴凸透镜作眼镜C.他佩戴眼镜度数为左眼镜片200 度,右眼镜片100 度D.小明有一望远镜是由两组凸透镜组成的,其中物镜作用是成正立,放大,虚像2、如图所示,某种物质熔化时温度随时间变化的图像,根据图像的特征和信息,以下说法中错误的是()A.该物质是晶体B.该物质的熔点是80℃C.该物质从开始熔化到完全熔化大约持续了15 分钟的时间D.该物质在熔化过程中是放热3、如右上图所示,小明在做模拟“蹦极”的小实验,一根橡皮筋一端系一个小石块,另一端固定在A 点,B 点是橡皮筋不系小石块自然下垂时下端所在的位置,C 点是小石块从A 点自由释放后所能达到的最低点,关于小石块从 A 点到 C 点运动过程的说法,正确的是()A.小石块减少的重力势能全部转化为动能B.从A 点下落到B 点的过程中,小石块受到重力和弹力的作用C.从B 点下落到C 点的过程中,小石块的速度先增大后减小D.小石块在C 点时,受到平衡力的作用4、某同学制作了一个会“发光的二极管”,器电路简图如图所示,二极管具有单向导电性,电流只能从二极管的正极流入,负极流出,演示时,左右摇动塑料管,这时会看见发光二极管发光,以下说法中,正确的是()A.制作发光二极管的主要材料是半导体B.两个发光二极管可以同时发光C.二极管发光时,图中的条形磁体相当于电源D.在该现象中,将机械能转化为电能5、如右上图所示,整个装置处于静止状态,重力和摩擦力不计,弹簧测力计A,B,C 的示数分别为F A.F B.F C;其中F B=2N.以下有关弹簧测力计的关系正确的是:()A. A 弹簧秤对墙壁的拉力大于A 弹簧秤的示数B. B 弹簧秤对墙壁的拉力为1NC. F A=2N F C=6ND. F A=1N F C=3N6、如图所示,在两个平面镜之间的夹角为60°,在两镜面夹角的角平分线上有一个点光源S,它在两平面镜中所成的象个数为()A.5B.6C.4D.77.粗细均匀、密度为ρρ蜡的蜡烛底部沾有一块质量为m 的铁块,蜡烛竖直漂浮在密度为ρ水的水中,蜡烛露出水面的高度为H,如图所示,点燃蜡烛,直至蜡烛与水面相平、蜡烛熄灭(假定蜡烛油不流下来),设燃烧掉的蜡烛长为L,则L/H 的关系是()8、下列有关说法中正确的是()A.设想从某一天起,地球的引力减小一半,那么对于漂浮在水面上的船来说,则船受到的重力将减小,船的吃水深度也减小B.磁感线越密集的地方磁场越强,发电机是利用电磁感应原理工作的,地磁场的N 极在地球的南极附近C.秋千摆动的幅度越小,惯性也越小D.用钢尺压在桌面上,改变钢尺伸出桌面的长度,是探究声音的音调与频率的关系9、如图,一重为mg,长度为的均匀柔软细绳PQ 数值悬挂,用外力将绳的下端Q 缓慢地竖直向上拉起至M 点,M 点与绳的上端P 相距1\3L,在此过程中,外力做的功为()10.如右上图所示的电路中电源电压保持不变 R1. R2为定值电阻,当滑动变阻器R 的滑动触头P由左向右运动时( )A.电流表A1的示数始终在增大,电流表A2示数先减小后增大B.电流表A2的示数始终在增大,电流表1示数先减小后增大C.电流表A1示数先减小后增大,电流表A2示数先减小后增大D.电流表2示数先增大后减小,电流表1示数先减小后增大11、在两个完全相同的容器中分别导入甲和乙两种不同的液体,如图所示,下列分析正确的是()A.若甲和乙对容器底部的压强相等,则甲的质量小于乙的质量B.若甲和乙的质量相等,则甲的密度大于乙的密度C.若甲和乙对容器底部的压强相等,则甲的密度小于乙的密度D.若甲和乙的质量相等,则甲对容器底部的压强大于乙对容器底部的压强12、用滑轮组分别以不同速度匀速提升物重为G 的物体A,作用在滑轮组绳子自由端的拉力均为F,如图所示,不计绳重和摩擦,当拉力 F 的功率为P1时,重物 A 以速度v1匀速上升h 所用的时间为t1,当拉力F 的功率为P2时,重物 A 以速度v2匀速上升h 所用时间为t2,则( )A.该滑轮组的机械效率为B.该滑轮组的动滑轮的重为2F-GC.当拉力F的功率为P1 + 1\2 P2时,重物A以速度v3匀速上升h所用的时间为.D.当拉力F的功率为P1 + 1\2 P2时,重物A以速度v3匀速上升h所用的时间为.二、填空题(每空2 分,共8 分)13、物理学中将物体在单位时间内速度的增加量定义为加速度。
2018年树德中学(外国语校区)初、高中艺体特长生

2018年树德中学(外国语校区)初、高中艺体特长生招生简章根据成招考委[2018]23号文件精神,结合我校实际情况,特制定成都树德中学(外国语校区)2018年初、高中艺体特长生招生简章。
一、报考条件1.报考初中艺体特长生的学生必须是应届小学毕业生,且具有中心城区户籍(或是已在中心城区就读的符合条件的进城务工人员随迁子女)。
报考高中艺体特长生的考生必须具有中心城区户籍并参加中心城区中考。
备注:“中心城区”是指成都天府新区(纳入中心城区招生范围的区域)、成都高新区(不含成都天府空港国际新城)、锦江区、青羊区、金牛区、武侯区、成华区、龙泉驿区、青白江区、新都区、温江区、双流区、郫都区。
2.报考艺术特长生必须具有某项艺术专长且达到一定水平,在就读初中、小学或教育行政部门批准举办的艺术比赛活动中取得一定成绩,艺术考级不得作为报考条件。
3.报考体育特长生必须具有某项体育专长且达到一定水平,在就读初中、小学或教育行政部门批准举办的体育比赛活动中取得一定成绩。
4.考生所持的艺术、体育证书专业项目须与报考学校的专业项目相同。
报考高中艺体特长生的必须具备初中阶段的相应证书;报考初中艺体特长生的必须具备小学阶段的相应证书。
5.初中毕业生中考成绩必须符合招生要求。
二、报名及资格审查(一)报名2018年中心城区初中、高中艺体特长生网上报名的时间为2018年6月17日上午8:00—6月20日下午15:00。
报考初中艺体特长生的小学毕业生应在此期间访问网址或,点击“小升初网络应用服务平台”,进入“艺体特长生网上报名”进行填报。
报考高中艺体特长生的考生应在此期间访问网址或,点击“中考网络应用服务平台”,进入“艺体特长生网上报名”进行填报。
(二)资格审查网上报名后,考生本人应于6月19—20日到我校进行现场资格审查,未在规定时间内到现场进行资格审查的考生视为放弃志愿。
现场资格审查具体时间:上午9:00—11:30;下午14:30—17:00。
树德中学国际部自主招生样题及答案(初三考生版-1202-完整版)

英语样题(针对初三学生)Ⅰ.选择题1.—How soon will you be?--three days’time.My air ticker is on March10.A.at;InB.away;ForC.off;ForD.off;In2.Kate will learn swimming,no matter how much it.A.costsB.takesC.spendsD.Pays3.I advised my father to smoking to keep healthy.But he didn’t listen to me.A.open upB.put upC.give upD.make up4.I’m sorry you the last bus.It left ten minutes ago.A.have lostB.lostC.missedD.have missed5.Liu Xiang,21,is an Olympic winner in the hurdles(跨栏).We are proud of him.A.110-metreB.110-metresC.110metreD.110metresⅡ.完形填空When I was16years old,I made my first visit to the United States.It wasn’t the first time I had been21.Like most English children I learned French22school and I had often been to French,so I23speaking a foreign language to people who didn’t understand24.But when I went to America I was really looking forward to25a nice easy holiday without any26 problems.21.A.out B.away C.outside D.abroad22.A.from B.during C.at D.after23.A.get used to B.was used to ed to ed24.A.English B.French C.Russian tin25.A.buying B.having C.giving D.receivingⅢ.阅读理解(A)Without plants,people could not live.We eat plants.We breathe the oxygen(呼吸氧气)that plants produce.And we need plants because they make our cities and our life beautiful and colourful.That’s why even in big modern cities,we have parks full of trees,green grass and flowers.Also you are sure to find some green house plants and flowers in the rooms in every city.But do you talk to your plants?Do you give them love and attention(注意)?The book The Secret Life of Plant by Peter Tomkins and Christopher Bird says that you should talk to them and give them love.The book tells a very interesting test.Two seeds(种子)were planted in different places.While the plants were growing,one plant was given love and positive(积极的)ideas.The other plant was given only negative ideas.After six months,the loved plant was bigger.Under theearth,it had more and longer roots(根),above it had a thicker stem(树干)and more leaves.41.Plants produce___________.A.oxygenB.clear airC.flowersD.wind42.The word negative means___________.A.疲倦的B.腐朽的C.消极的D.向上的43.The passage mainly(主要)tells us that___________.A.People love plantsB.People can’t live without plantsC.Plants need love and attentionD.Plants become more and more important in people’s lifeⅣ.单词拼写(共10小题,每小题1分,满分10分)61.The students were all very____________(激动)when they heard the good news that theirteam had won.62.Yan Ming is one of the best basketball____________(队员)in China.63.As time goes on,there are more people____________(想要)to buy cars.Ⅴ.短文改错(共10小题,每小题1分,满分10分)此题要求改正所给短文中的错误。
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2018-2019年最新四川成都树德中学(外国语校区)自主招生考试英语模拟精品试卷(第一套)考试时间:120分钟总分:150分第I卷(选择题,共100分)第一节:单项填空(共25小题,每小题1分,满分25分)1. —When did the terrible earthquake in YaNan happen?—It happened ________ the morning of April 20, 2013.A. onB. atC. inD. /2. Our teacher told us ________ too much noise in class.A. to makeB. makeC. not to makeD. not make3. Here is your hat. Don’t forget______ when you __________.A. to put it on, leaveB. to wear it, leaveC. to wear it, will leaveD. putting it on, will leave4. The baby is sleeping. You _____ make so much noise.A. won’tB. mustn’tC. may notD. needn’t5. Since you are _____ trouble, why not ask _________ help?A. in, forB. in, toC. with, forD. with, to6. It’s about___________kilometers from Nanchong to Chengdu.A. two hundredsB. two hundreds ofC. two hundredD. two hundred of7. It is six years since my dear uncle ________China.A. leftB. has leftC. is leftD. had left8. —How long _______ you _______ the bicycle?—About two weeks.A. have, hadB. have, boughtC. did, buyD. have, have9. The Yellow River is not so ________ as the Yangtze River.A. longerB. longC. longestD. a long10. Mrs.Green usually goes shopping with ________ umbrella in ________ summer.A. a;theB. an; /C. the; aD. /;/11. At first, I was not too sure if he could answer the question. However, ____,he worked it out at last with the help of his friend.A. to my angerB. to my surpriseC. in other wordsD. ina word12. —Must I stay here with you?—No, you ______.You may go home, but you _____ go to the net bar (网吧).A. mustn't; needn'tB. needn't; mustn'tC. must; needD. need; must13. I ______ the newspaper while my mother _____TV plays yesterday evening.A. was reading; was watchingB. was reading; watchedC. read; was watchingD. read; would watch14. It's a rule in my class that our classroom ________ before 6:00 p. m.every day.A. be able to cleanB. should be cleaningC. must cleanD. must be cleaned15. —Tom wants to know if you ________ a picnic next Sunday.—Yes. But if it ________, we'll visit the museum instead.A. will have; will rainB. have; rainsC. have; will rainD. will have; rains16.—Would you mind looking after my dog while I'm on holiday?—________.A. Of course notB. Yes. I'd be happy toC. Not at all. I've no timeD. Yes, please17. Many students didn’t realize the importance of study _______they left school.A. whenB. untilC. afterD. unless18. My father _______ to Shanghai. He _______ for over 2 months.A. has been, has leftB. has gone, has goneC. has gone, has been awayD. has been, has gone19. They are your skirts. Please __________.A. put it awayB. put out itC. put them awayD. put them out20. —Please read every sentence carefully. you are, mistakes you’ll make.—Thank you for your advice.A. The more carefully; the fewerB. The more careful; the lessC. The more carefully; the lessD. The more careful; the fewer21. My friend is coming today but he didn’t tell me _______.A. when did the train arriveB. how did the train arriveC. when the train arrivedD. how the train arrived22. I felt it hard to keep up with my classmate s. But whenever I wantto _______, my teacher always encourages me to work harder.A. go onB. give upC. run awayD. give back23. —________ fine weather it is today!—Let's go for a picnic.A. WhatB. HowC. What aD. How a24. — Mary, you’re going to buy an apartment here, aren’t you?—Yes, but I can’t_______an expensive one.A. spendB. costC. payD. afford25. —Would you like to drink coffee or milk?—_________. Please give me some tea.A. NeitherB. BothC. EitherD. None第二节:完形填空(共20小题,每小题1分,满分20分)(A)Big schoolbags have been a serious problem for students for a long time.Maybe your schoolbag is too __26__ to carry, and it troubles you a lot __27__ you want to find a book out to read. Now an etextbook will __28__ you.It is said that etextbooks are going to be __29__ in Chinese middle schools.An etextbook, in fact, is a small __30__ for students.It is much __31__ than a usual schoolbag and easy to carry. Though it is as small as a book, it can __32__ all the materials (材料) for study.The students can read the text page by page on the __33__, take notes with the pointer (屏写笔). Or even “__34__” their homework to their teachers by sending emails. All they have to do is to press a button.Some people say etextbooks are good, but some say they may be __35__for the students' eyes. What do you think of it?26.A.light B. heavy C. useful D. comfortable27.A.till B. after C. before D. when28.A.trouble B. prevent C. help D. understanded B. kept C. invented D. lent B. radio C. pen D. computer31.A.heavier B. lighter C. cheaper D. brighter32.A.hold B. build C. discover D. practice33.A.blackboard B. desk C. screen D. card34.A.find out B. hand in C. get back D. give back35.A.helpful B. famous C. good D. bad(B)Food is very important. Everyone needs to _36_ _well if he/she wants to have a strong body. Our minds also need a kind of food. This kind of food is__ 37 __.We begin to get a knowledge even when we are very young. Small children are __38__ in everything around them. They learn __39 __while they are watching and listening. When they are getting older, they begin to ___ 40__ story books, science books…anything they like. When they find something new, they have to ask questions and__41___ to find out the answers.What is the best ___42___to get knowledge? If we learn___43___ourselves, we will get the most knowledge, If we are__44___getting answers from others and don’t ask why, we will never learn more and understand___45_.36. A. sleep B. read C. drink D. eat37. A. sport B. exercise C. knowledge D. meat38. A. interested B. interesting C. weak D. meat39. A. everybody B. something C. nothing D. anything40. A. lend B. write C. think D. read41. A. try B. wait C. think D. need42. A. place B. school C. way D. road43. A. in B. always C. to D. by44. A. seldom B. always C. certainly D. sometimes45.A.harder B. much C. well D. better第三节:阅读理解(共25小题,每小题2分,满分50分)AFamous Museums_______ .A. BeijingB. LondonC. New YorkD. The USA47. New York Museum is America’s largest museum on American__________.A. areaB. historyC. collectionsD. buildings48. The Palace Museum. Which is in the center of Beijing, is also called“Forbidden City(紫禁城)” in China. It lies in __________.A.Chang’an StreetB. New Oxford StreetC. BerlingD. Chestnut Street49. According to the form, if you want to see ancient Chinese collections,you can visit ____ at most.A. one museumB. two museumsC. three museumsD. four museums50. Which of the following is TRUE according to the information above?A. Each ticket for the Palace Museum costs the same in the whole year.B. You don’t have to pay for tickets if you visit New York Museum on Monday.C. British Museum lies in Chestnut street, London.D. New York Museum is the largest in the world.BIn recent years, more and more people like to keep pets such as a dog, a cat, a monkey and other animals. But usually people would accept tame(温顺的) and loyal(忠诚的) animals as pets rather than dangerous ones such as a lion,a tiger or a snake.People love pets and take good care of them. The owners usually regard pets as good friends and some even consider them as members of the family. Although they are not human beings(人类), their behavior sometimes is better than human beings, for they are always loyal to their owners. There are always many stories about brave and smart pets. We often hear that a pet dog saved the owner's life or traveled thousands of miles to return home. Such stories often make pets more lovely.Some pets can also be trained to help people with some special work. For example, trained dogs can help the blind to walk and trained dogs and pigs can even help police to find where drugs are easily.But pets are sometimes trouble-makers. Some pets like dogs or snakes may hurt people without any warning. Some people may become ill after being hurt because of the virus carried by the pets. If they are not taken good care of, they will become very dirty and easily get ill. So pets are helpful to us but keeping pets is not an easy job.51. What animals are thought to be dangerous as pets?A. Cats.B. Dogs.C. Snakes.D. Monkeys52. Which of the following statements is TRUE about pets?A. All the pets are considered as family members.B. Pets always behave better than human beings.C. Sometimes some pets can protect their owners.D. Pets like traveling far away from home.53. Why do people train pets according to the passage?A. To make them more clever.B. To make them more lovely.C. To find drugs for the blind.D. To do some special work.54. What can we learn from the last paragraph?A. Pets often hurt strange people.B. Pets can live well with the virus.C. Pets are dirty and dangerous.D. Pets should be looked after well.55. What is the best title for the passage?A. Training Pets.B. Keeping Pets.C. Cleaning Pets.D.Loving Pets.CFrom Feb. 8 to Mar. 1 is our winter holiday. I think everybody did a lot in the holiday. But it seems that I did nothing and it was my most unlucky holiday.I spent a lot of time on my homework. Every morning my mother woke me up early and I had breakfast in a hurry. Then I had to do my homework almost the whole day! I’m not a very slow person but the homework was too heavy!I was also unlucky when playing. During the Spring Festival, I played fireworks but my finger was hurt because I was careless to light the fireworks. I began to fear playing with fireworks from then.I was still unlucky on my friend’s party. On my friend’s birthday, unusually I woke up at 10:50 because my parents went to visit my grandmother early in the morning. The party would start in 10 minutes! So I hurried to my friend’s home without breakfast. I returned very late that day and when I got home, my parents were very angry with me.Another worrying thing was my weight. Last term, I was 46 kg but nowI am 51 kg! I have to consider losing weight!56. How long did the winter holiday last?A. two monthsB. one monthC. 4 weeksD. 22 days57. The writer got up early every day during the holiday because ______.A. he had to finish homeworkB. he had to have breakfastC. he was a very slow personD. his mother was in a hurry58. He hurt his finger because of ________.A. the Spring FestivalB. his carelessnessC. the light of fireworksD. his fear of playing59. Why were the writer’s parents angry with him?A. Because he got up too late.B. Because he missed breakfast.C. Because he was late for the party.D. Because he came back home too late.60. What did the writer want to tell us in the passage?A. He had an unlucky holiday.B. He had too much homework.C. His parents were very strict.D. He planned to lose weight.DSteven Jobs, the designer of Apple Computer, was not clever when he was in school.At that time, he was not a good student and he always made troubles with his schoolmates.When he went into college, he didn't change a lot.Then he dropped out.But he was full of new ideas.After he left college, Steven Jobs worked as a video game designer.He worked there for only several months and then he went to India.He hoped that the trip would give him some new ideas and give him a change in life.Steven Jobs lived on a farm in California for a year after he returned from India.In 1975, he began to make a new type of computer.He designed the Apple Computer with his friend in his garage.He chose the name “Apple” just because it could help him to remember a happy summer he once spent in an apple tree garden.His Apple Computer was such a great success that Steven Jobs soon became famous all over the world.61.Steven Jobs was not a good student in school because he ________.A. never did his lessonsB. was full of new ideasC. always made troubles with his schoolmatesD. dropped out62.Did Steven Jobs finish college?A. Yes, he did.B. No, he didn't.C. No, he didn't go into college.D. We don't know.63.Steven Jobs designed his new computer ______.A. in IndiaB. with his friendC. in a pear tree gardenD. by himself64.Steven Jobs is famous for his ________ all over the world.A. new ideasB. appleC. Apple ComputerD. video games65.From this passage we know ________.A. Steven Jobs didn't finish his studies in the college because he hatedhis schoolmatesB. Steven Jobs liked traveling in India and CaliforniaC. Steven Jobs liked trying new things and making new ideas become trueD. Steven Jobs could only design video gamesEIf you go into the forest with friends, stay with them. If you don't, you may get lost. If you get lost, this is what you should do. Sit down and stay where you are. Don't try to find your friends. Let them find you. You can help them find you by staying in one place. There is another way to help your friends or other people to find you. You can shout or whistle (吹口哨) three times. Stop. Then shout or whistle three times again. Any signal given three times is a call for help.Keep up shouting or whistling. Always three times together. When people hear you, they will know that you are not just making a noise for fun. They will let you know that they have heard your signal. They will give you two shouts or two whistles. When a signal is given twice, it is an answer to a call for help.If you don't think that you will get help before night comes, try to make a little house with branches .Make yourself a bed with leaves and grass.When you need some water, you have to leave your little branch house to look for it. Don't just walk away .Pick off small branches and drop them as you walk in order to go back again easily.66.If you get lost in the forest, you should ________.A. walk around the forest to find your friendsB. stay in one place and give signalsC. climb up a tree and wait for your friends quietlyD. shout as loudly as possible67.Which signal is a call for help?A. Shouting one time as loudly as you can.B. Crying twice.C. Shouting or whistling three times together.D. Whistling everywhere in the forest.68.When you hear two shouts or two whistles, you know that ________.A. someone finds something interestingB. people will come and help youC. someone needs helpD. something terrible will happen69.Before night comes, you should try to make a little house with ________.A. stoneB. earthC. leaves and grassD. branches70.Which of the following is the best title?A. Getting Water in the ForestB. Spending the Night in the ForestC. Surviving (生存) in the ForestD. Calling for Help in the Forest 第四节:补全对话,从方框内7个选项中选择恰当的5个句子完成此对话(共5分)John: Hi, Karl. You were not here, in your class yesterday afternoon. What was wrong?Karl: 71________John: Sorry to hear that.72Karl: Much better. The fever is gone. But I still cough and I feel weak. John: 73Karl: Yes, I have. I went to the doctor’s yesterday afternoon. The doctor gave me some medicine and asked me to stay in bed for a few days. John: 74Karl: Because I’m afraid I’ll miss more lessons and I’ll be left behind. John: Don’t worry. Take care of yourself. 75第Ⅱ卷(非选择题,共50分)一、根据句意及所给提示,补全单词或用单词、固定短语、固定搭配的正确形式填空(10分)76. Many athletes won gold medals in the Olympics, they are our national h_____.77. Tom didn’t finish _____________( write) his test because he ran out of the time.78. The girl is making a model doll ___________ (care).79. The boy felt __________(困倦的) in class because he stayed up late last night.80. So Terrible! The airplane ______________(起飞) five minutes ago.81.I don't think students should be (允许)to bring mobile phones to school.82.I find it useless to spend much time (解释)it to him.83. She prefers keeping silent to (争吵)with others.84. It is important for us to be (有信心的)of doing everything.85. The doctor operated on the patient (成功)yesterday.二、汉译英, 一空一词(共5小题,每小题2分,计10分)86. 他默默地在雨中行走,浑身上下都被淋湿。