成都石室中学高2019届11月份同步月考
2019-2020学年成都市石室中学北湖校区高三英语月考试题及答案
2019-2020学年成都市石室中学北湖校区高三英语月考试题及答案第一部分阅读（共两节，满分40分）第一节（共15小题；每小题2分，满分30分）阅读下列短文，从每题所给的A、B、C、D四个选项中选出最佳选项ABrecon Beacons YAC has an amazing opportunity for budding (崭露头角的) archaeologists(考古学家) of all ages, in Sunderland in Tyne and Wear. Thanks to funding from the Heritage Lottery Fund, professional archaeologists from Wardell Armstrong will be investigating an archaeological mystery and they need your help. Romans?“The site is a bit of a mystery”, Frank Giecco from Wardell Armstrong said. “There is a very nice cropmark recorded on the site that has got lots of people very excited. Geophysicists(地质物理学家) failed to find anything related to the cropmark. There is anecdotal (传闻的)evidence of Roman material being found, but nothing is officially recorded. We hope to finally answer the question of what is in this field, during the two weeks on site. Is there evidence of any Roman occupation on the site? Can you help us find out?"Get involvedThis is an opportunity for both adults and children to take part in field walking and trial trenching (small hand-dug test pits for children). No experience is necessary, training will be provided by the professional archaeologists from Wardell Armstrong, and all equipment will be provided. Volunteers can attend for as few or as many days as they wish, but they do need to book a place.For more information, and to book your place, please contact Norman Kirtlan at ***********************************.1.Who is the activity probably intended for?A.OfficialsB.ExpertsC.FamiliesD.Romans.2.If you take part in the activity, you ________.A.will be coached by experts in the fieldB.will be charged for using equipmentC.should have worked with archaeologists beforeD.should spare two weeks to stay at the site3.What's the main purpose of the activity?A.To seek funding for archaeological research.B.To appeal for help inproving findings based on anecdotal evidence.C.To find volunteers to help solve an archaeological mystery.D.To organize volunteers to help sort our data on the Roman occupation.BThursday, two Russian submarines(潜艇) dived down 2.5 miles into the Arctic Ocean and planted a national flag onto a piece of continental shelf known as the Lomonosov Ridge. Rising from the center of the Arctic Basin, the flag sent a clear message to the surrounding nations: Russia had just laid claim(权利) to the vast oil and gas reserves contained in this underwater area.AfterRussia, theUnited States,Norway,SwedenandFinlandare all trying to gain profit. Projections show that the area of land and sea that falls within theArctic Circleis home to an estimated 90 billion barrels of oil, an incredible 13% of Earth’s reserves. It’s also estimated to contain almost a quarter of untapped global gas resources. But long before this oil race began, how did theArcticbecome so rich in energy?“The first thing you realize is that theArctic—unlike the Antarctic—is an ocean surrounded by continents”, Alastair Fraser, a geoscientist from Imperial College London, said. Firstly, this means there’s a huge quantity of organic material available, in the form of dead sea creatures such as plankton and algae, which form the basis of what will ultimately become oil and gas. Secondly, the surrounding ring of continents means that the Arctic Basin contains a high proportion of continental crust(大陆地壳), which makes up about 50% of its oceanic area. That’s significant because continental crust typically contains deep depressions called basins, into which organic matter sinks.Here, it gets inserted in rock and preserved in anoxic(缺氧) waters, meaning they contain little oxygen. “Normally, in a shallow sea with lots of oxygen, it would not be preserved. But if the sea is deep enough, the oxygenated waters at the top will be separated from the anoxic conditions at the base,” Fraser explained. Conserved within these oxygen-free basins, the matter maintains compounds that finally make it useful as an energy source for millions of years in the future.4. Why didRussiaplant a national flag onto the Lomonosov Ridge?A. To tell surrounding countries its armed forces.B. To show its advanced technology of submarines.C. To show abundant natural resources in theArcticBasin.D. To claim its privilege to explore for oil and gas in the area.5. What’s the function of the last sentence in paragraph 2?A. Making a comparison.B. Serving as a connecting link.C. Analyzing the cause and effect.D. Drawing the conclusion of the text.6. What can we know from the last paragraph?A. Oxygen only exists in the top part of the ocean.B. Organic materials mostly exist in the basins with oxygen.C. Water containing oxygen turns organic materials into oil and gas.D. Oxygen-free environment counts in the formation of the arctic’s rich energy.7. What can be a suitable title for the text?A. What makes theArcticattractive?B. Why do many nations focus on theArctic?C. Why is there so much oil in theArctic?D. How does theArcticBasincome into being?CThe United Nations Educational, Scientific and Cultural Organization (UNESCO) included on December 17, 2020 China's Tai Chi on the RepresentativeList of the Intangible（无形的）Cultural Heritage of Humanity. The decision was announced during the online meeting of the UNESCO Intergovernmental Committee for the Safeguarding of the Intangible Cultural Heritage held from December 14 to19 inKingston, capital ofJamaica.“Born in the mid-17th century in a small village named Chenjiagou located in Central China's Henan province, Tai Chi is not only a kind of traditional Wushu integrated with slow movements and deep breathing, but is also deeply rooted in many areas of Chinese culture, such as medicine and philosophy,”Zhu Xianghua says, who is the son of the famous Tai Chi master Zhu Tiancai.Although it has spread to more than 150 countries and regions, attracting more than 100 million people to practice, the idea that Tai Chi is for the elderly has stopped many young people practicing the ancient Wushu. They think of it as a slow exercise, which is specially made and better suited for their grandparents. Instead, many young people are turning to the Indian practice of yoga（瑜伽）to relieve stress, which was placed on the UNESCO's List in 2019.In order to promote Tai Chi, joint efforts have been made from individuals and the Chinese government in the last decades. Xi'an Jiaotong University requires students to learn Tai Chi. Wang Yunbing, a professor in the university's sports center, stressed that Tai Chi is not only good physical exercise-researchers from the American College of Rheumatology find that it can help manage several diseases but is also conned ted to ancient Chinese eivilization. Since 2014, the World Tai Chi Championships have been held every two years by the International Wushu Federation. It provides a platform for communication and learning between the Tai Chi masters and Tai Chilovers around the globe. In January 2020, Tai Chi became an official event in the 2026 Dakar Youth Olympic Games.8. What does Zhu Xianghua say about Tai Chi in paragraph 2?A. It originated from fast Kung Fu action.B. It was born around the 1750s in a village.C. It is related to other cultural fields ofChina.D. It integrates Chinese medicine and western philosophy.9. Why do some young people choose to practice yoga instead of Tai Chi?A. They think it easier to practice yoga to keep fit.B. The elderly stop young people practicing Tai Chi.C. They consider Tai Chi is custom-built for old people.D. Yoga was included in the world culture earlier than Tai Chi.10. What is the main purpose of the last paragraph?A. To promote contemporary Chinese civilization.B. To show many efforts made to popularize Tai Chi.C. To stress the importance of Chinese Tai Chi masters.D. To advise people to practise Tai Chi to cure diseases.11.Which of the following is the best title for the passage?A. Tai Chi Steps on the UNESCO's List.B. Tai Chi is Competing against Yoga.C. Tai Chi Has Regained populate Globally.D. Opinions Greatly Differ on Tai Chi and Yoga.DWho is a genius? This question has greatly interested humankind for centuries.Let's state clearly: Einstein was a genius. His face is almost the international symbol for genius. But we want to go beyond one man and explore the nature of genius itself. Why is it that some people are so much more intelligent or creative than the rest of us? And who are they?In the sciences and arts, those praised as geniuses were most often white men, of European origin. Perhaps this is not a surprise. It's said that history is written by the victors, and those victors set the standards for admission to the genius club. When contributions were made by geniuses outside the club—women, or people ofa different color1 or belief—they were unacknowledged and rejected by others.A study recently published bySciencefound that as young as age six, girls are less likely than boys to say that members of their gender(性别)are “really, really smart.” Even worse, the study found thatgirls act on that belief: Around age six they start to avoid activities said to be for children who are “really, really smart.” Can our planet afford to have any great thinkers become discouraged and give up? It doesn't take a genius to know the answer: ly not.Here's the good news. In a wired world with constant global communication, we're all positioned to see flashes of genius wherever they appear. And the more we look, the more we will see that social factors(因素)like gender, race, and class do not determine the appearance of genius. As a writer says, future geniuses come from those with “intelligence, creativity, perseverance(毅力), and simple good fortune, who are able to change the world.”12. What does the author think of victors' standards for joining the genius club?A. They're unfair.B. They're conservative.C. They're objective.D. They're strict.13. What can we infer about girls from the study inScience?A. They think themselves smart.B. They look up to great thinkers.C. They see gender differences earlier than boys.D. They are likely to be influenced by social beliefs14. Why are more geniuses known to the public?A. Improved global communication.B. Less discrimination against women.C. Acceptance of victors' concepts.D. Changes in people's social positions.15. What is the best title for the text?A. Geniuses Think AlikeB. Genius Takes Many FormsC. Genius and IntelligenceD. Genius and Luck第二节（共5小题；每小题2分，满分10分）阅读下面短文，从短文后的选项中选出可以填入空白处的最佳选项。
四川省成都市石室中学2024-2025学年高三上学期11月期中考试数学试题(含解析)
成都石室中学2024～2025学年度上期高2025届十一月月考数学试卷一､单项选择题：本题共8小题，每小题5分，共40分，在每小题给出的四个选项中，只有一项是符合要求的．1.已知集合，集合，则（）A. B. C. D.2.已知为单位圆的内接正三角形，则（ ）A. B.C.1D.3.已知角的终边上一点（ ）A. B. C. D.4.巴黎奥运会期间，旅客人数（万人）为随机变量，且.记一天中旅客人数不少于26万人的概率为，则的值约为（ ）（参考数据：若，有，，）A.0.977B.0.9725C.0.954D.0.6835．已知非零向量，满足，且向量在向量上的投影向量是，则与的夹角是（ ）A ．B ．C ．D ．6.关于的方程在上有（ ）个实数根．A.1B.2C.3D.47.已知，是定义域为R 的函数，且是奇函数，是偶函数，满足，若对任意的，都有成立，则实数a 的取值范围是（ ）(){}ln 1A xy x ==-∣{}xB y y e -==∣A B = ()0,1()1,2()1,+∞()2,+∞ABC V O B B C O ⋅=32-321-α()1,2M -32=⎪⎝⎭22-44-X ()2~30,2X N 0p 0p ()2~,X Nμσ()0.683P X μσμσ-<≤+≈()220.954P X μσμσ-<≤+≈()330.997P X μσμσ-<≤+≈a b ()()22a b a b +⊥- a b 14b a bπ6π3π22π3x 2sin sin2cos cos 222x x xx x =(,)ππ-()f x ()g x ()f x ()g x ()()22f x g x ax x +=++1212x x <<<()()12123g x g x x x ->--A. B. C. D.8.已知，若关于的不等式在上恒成立，则的最小值是（ ）A. B. C. D.二、多项选择题：本题共3小题，每小题6分，共18分．在每小题给出的选项中，有多项符合题目要求．全选对的得6分，部分选对的得部分分，有选错的得0分．9.已知函数的部分图象如图所示，则下列说法正确的是（ ）A.的图象关于直线对称B.在上单调递增C.是奇函数D.将图象上所有点的横坐标变为原来的2倍，得到函数的图象10.已知为函数的一个零点，则（ ）A.的图象关于对称 B.的解集为C.时， D.时，，则的最大值为411.已知函数与及其导函数f ′(x )与的定义域均为.若为奇函数，，，则（ ）A. B.[)0,∞+3,04⎡⎤-⎢⎥⎣⎦3,4∞⎛⎫-+ ⎪⎝⎭3,4∞⎡⎫-+⎪⎢⎣⎭0,a b >∈R x ()()2110ax x bx -+-≥()0,∞+5b a+48()()πsin 0,0,2f x A x A ωϕωϕ⎛⎫=+>><⎪⎝⎭()f x 5π12x =-()f x π,π2⎡⎤⎢⎥⎣⎦2π3f x ⎛⎫-⎪⎝⎭()f x π2sin 3y x ⎛⎫=+ ⎪⎝⎭1-3()3f x x x a =-+()f x (0,2)-()0f x <(,2)-∞(0,1)x ∈()2()f xf x <[,]x m n ∈()[4,0]f x ∈-n m -()f x ()g x ()g x 'R ()f x ()()22f x g x +-=()()12f x g x '+'+=()()264g g -+=()00f '=C.曲线关于点中心对称D.三、填空题：本大题共3小题，每小题5分，共计15分．12.若复数满足，则__________.13.已知某次数学期末试卷中有8道四选一的单选题，学生小万能完整做对其中4道题，在剩下的4道题中，有3道题有思路，还有1道完全没有思路，有思路的题做对的概率为，没有思路的题只能从4个选项中随机选一个答案．若小万从这8个题中任选1题，则他做对的概率为______．14.已知数列{a n }满足，，其中为函数的极值点，则______．四、解答题：共77分．解答应写出文字说明，证明过程或演算步骤．15．（本小题13分）为提高学生的数学应用能力和创造力，石室中学打算开设“数学建模”选修课，为了解学生对“数学建模”的兴趣度是否与性别有关，学校随机抽取该校30名高中学生进行问卷调查，其中认为感兴趣的人数占70%.感兴趣不感兴趣合计男生12女生5合计30(1)根据所给数据，完成下面的2×2列联表，并根据列联表判断，依据小概率值α=0.15的独立性检验，分析学生对“数学建模”选修课的兴趣度与性别是否有关?(2)若感兴趣的女生中恰有4名是高三学生，现从感兴趣的女生中随机选出3名进行二次访谈，记选出高三女生的人数为X ，求X的分布列与数学期望附：，其中.0.150.100.050.0250.0100.0050.0012.0722.7063.8415.0246.6357.87910.82816．（本小题15分）如图所示，在四棱锥中，，，．(1)若平面，，证明：(2)若底面，，，二面角的长．()y f x ='1,12⎛⎫⎪⎝⎭2025120252k k g =⎛⎫= ⎪⎝⎭'∑z 33i1iz -=+1z +=23()1*1e n a n a n ++=∈N 2303aa x +=0x y =()12e 1x x x +->123a a a +-=()()()()()22n ad bc K a b c d a c b d -=++++n a b c d =+++αx αP ABCD -2AC =1BC =AB =//AD PBC AD ⊥PA PB AD ⊥PA ⊥ABCD AD CD ⊥AD =A CP D --PA17．（本小题15分）设的内角，，所对的边分别为，且.(1)求(2)若,求的周长;(3)如图，点是外一点，设且，记的面积，求关于的关系式，并求的取值范围.18．已知抛物线的焦点为，直线过点交于，两点，在，两点的切线相交于点，的中点为，且交于点．当垂直于轴时，长度为4；(1)求的方程；(2)若点的横坐标为4，求；(3)设在点处的切线与，分别交于点，，求四边形面积的最小值．19．（本小题17分）已知函数，.(1)当时，函数恒成立，求实数的最大值；(2)当时，若，且，求证：；(3)求证：对任意，都有.ABC V A B C ,,a b c ()()sin ()(sin sin ),a c B C b c B C -⋅+=-⋅+b =;B 3BA BC +=ABC V D ABC V BAC DAC θ∠=∠=2π3ADC ∠=BCD △S S θS 2:2(0)C x py p =>F l F C A B C A B P AB Q PQ C E AB y AB C P QE C E PA PB M N ABNM ()21ln 2f x x x ax =+-()0a >[)1,x ∈+∞()32f x ≥-a 2a =()()123f x f x +=-12x x ≠122x x +>*N n ∈()2112ln 1ni i n n i =-⎛⎫++> ⎪⎝⎭∑成都石室中学2024-2025学年度上期高2025届11月半期考试数学参考答案双向细目表题号题型分值难度预估内容具体内容1单项选择题50.95集合集合运算2单项选择题50.9向量数量积3单项选择题50.8三角函数诱导公式、倍角公式4单项选择题50.75正态分布正态分布5单项选择题50.7向量投影向量6单项选择题50.7三角函数三角函数图象分析7单项选择题50.5函数性质函数奇偶性及单调性分析8单项选择题50.4不等式不等式9多项选择题60.8三角函数正弦函数图象特点分析10多项选择题60.5函数三次函数图象分析11多项选择题60.3函数性质函数奇偶性、对称、周期性分析12填空题50.8复数复数计算13填空题50.5概率概率计算14填空题50.3函数数列及函数零点15（1）解答题60.8检验15（2）解答题70.7概率统计分布列16（1）解答题30.8线线垂直证明16（2）解答题40.7立体几何二面角17（1）解答题40.7正余弦定理应用17（2）解答题50.6解斜三角形求周长17（3）解答题60.4解斜三角形解斜三角形求面积18（1）解答题50.6抛物线方程18（2）解答题60.6切线问题18（3）解答题60.4解析几何四边形面积19（1）解答题50.7函数恒成立问题19（2）解答题60.5利用函数单调性证明自变量大小19（3）解答题60.3导数数列不等式证明答案及解析1.【参考答案】C【解题思路】由题意可知，，2K (){}ln 1{10}{1}A x y x x x x x ==-=->=>∣∣∣，所以.故选C.2.【参考答案】B【解题思路】如图，延长交于点.因为单位圆半径为，为单位圆的内接正三角形，所以.又因为是正的中心，所以，，所以.设的边长为.由勾股定理，得，即，解得（负值已舍去），所以，易得,的夹角为，所以.故选B.3.【参考答案】C【解题思路】由三角函数定义知，，，所以.故选C.4.【参考答案】A【解题思路】因为，所以，，所以.根据正态曲线的对称性可得，.故选A.5.【参考答案】B【解题思路】因为，所以，所以.因为向量在向量上的投影向量是，所以，即，所以.又因为，所以与的夹角是.故选B.6.【参考答案】C【解题思路】当时，，原方程化为.令{}e{0}xB y y y y-===>∣∣()1,A B=+∞AO BC D O1ABC△O1OA OB OC===O ABC△AD BC⊥1122OD OA==32AD OA OD=+=ABC△a222AB AD BD=+2223122a a⎛⎫⎛⎫=+⎪ ⎪⎝⎭⎝⎭a=1BO=BC=BOBC6π3cos62BO BC BO BCπ⋅=⋅⋅=2tan21α==--cos0α<2sin2tan43cos2ααα===-=-⎪⎝⎭()230,2X N~30μ=2σ=()26340.954P X<≤≈()()()10.954262634340.9540.9772p P X P X P X-=≥=<≤+>≈+=()()22a b a b+⊥-()()222240a b a b a b+⋅-=-=2b a=a b14b1cos,4ba ab bb⋅=11cos,24a b b b⋅=1cos,2a b=[],0,a bπ∈a b3π(),xππ∈-cos02x≠1tan sin2sin2223xx x xπ⎛⎫==-⎪⎝⎭，，则原方程的解的个数即为函数与的图象在上的交点个数.作出函数和的大致图象如图，在上单调递增，，，，由图可知函数和在上有3个交点，即原方程在上有3个实数根.故选C.7.【参考答案】D【解题思路】由题意可得，.因为是奇函数，是偶函数，所以.联立解得.又因为对于任意的，都有成立，所以，即成立.构造，所以在上单调递增.若，则对称轴，解得；若，则在上单调递增，满足题意；若，则对称轴恒成立.综上所述，.故选D.8.【参考答案】A【解题思路】设，.因为，所以在上单调递增.当时，；当时，.因为的图象开口向上，，所以方程有一正根一负根，即函数在上有且仅有一个零点，且为异号零点.由题意可得，，则当时，；当时，，所以是方程的根，则，即，且，所以，当且仅当时等()sin 23f x x π⎛⎫=- ⎪⎝⎭()tan 2x g x =()f x ()g x (),ππ-()f x ()g x ()tan2xg x =(),ππ-tan 124g ππ⎛⎫== ⎪⎝⎭5sin 1122f ππ⎛⎫== ⎪⎝⎭5122ππ<()f x ()g x (),ππ-(),ππ-()()22f x g x ax x -+-=-+()f x ()g x ()()22f x g x ax x -+=-+()()()()222,2,f xg x ax x f x g x ax x ⎧+=++⎪⎨-+=-+⎪⎩()22g x ax =+1212x x <<<()()12123g x g x x x ->--()()121233g x g x x x -<-+()()112233g x x g x x +<+()()2332h x g x x ax x =+=++()232h x ax x =++()1,2x ∈0a <0322x a =-≥304a -≤<0a =()32h x x =+()1,2x ∈0a >0312x a =-≤3,4a ⎡⎫∈-+∞⎪⎢⎣⎭()1f x ax =-()21g x x bx =+-0a >()f x ()0,+∞10x a <<()0f x <1x a>()0f x >()g x ()01g =-()0g x =()g x ()0,+∞()()0f x g x ≥10x a <<()0g x ≤1x a >()0g x ≥1a210x bx +-=2110b a a +-=1b a a=-0a >544b a a a +=+≥=2a =号成立.故选A.9.【参考答案】ACD【解题思路】由图象可得，，，故，代入点，易得，所以.因为，所以当时函数取得最小值，即直线为函数的一条对称轴，故A 正确；由对称性可知，在上单调递减，上单调递增，故B 错误；为奇函数，故C 正确；将的图象上所有点的横坐标变为原来的2倍，得到函数的图象，故D 正确.故选ACD.10.【参考答案】AD【解题思路】因为，即，所以，所以，所以的图象关于（0，-2）对称，故A 正确；当时，且，故B 错误；当时，，而，所以在（0，1）上单调递减，所以，故C 错误；，，所以在区间，上，即单调递增；在区间（-1，1）上，即单调递减，，，，画出的大致图象如图.因为当时，，所以由图可知，的最大值为，故D 正确.故选AD.11.【参考答案】ACD【解题思路】令，得；令，得.因为为奇函数，所以，则，故A 正确；因为为奇函数，所以为偶函数，则求2A =4312T πππ⎛⎫=-=⎪⎝⎭2ω=,212π⎛⎫⎪⎝⎭3πϕ=()2sin 23f x x π⎛⎫=+ ⎪⎝⎭521232πππ⎛⎫⋅-+=- ⎪⎝⎭512x π=-()f x 512x π=-()f x ()f x 7,1212ππ⎡⎤⎢⎥⎣⎦713,1212ππ⎡⎤⎢⎥⎣⎦()22sin 22sin23f x x x ππ⎛⎫-=-=- ⎪⎝⎭()f x 2sin 3y x π⎛⎫=+ ⎪⎝⎭()1130f a -=-++=2a =-()()()233212f x x x x x =--=+-()()4f x f x +-=-()f x ()()()2120f x x x =+-<1x ≠-2x <01x <<201x x <<<()2330f x x =-<'()f x ()()2f x f x >()332f x x x =--()()()233311f x x x x =-=+-'(),1-∞-()1,+∞()0f x '>()f x ()0f x '<()f x ()10f -=()14f =-()24f -=-()f x [],x m n ∈()[]4,0f x ∈-n m -()224--=4x =()()422f g +-=4x =-()()462f g -+=()f x ()()f x f x =--()()264g g -+=()f x ()f x '不出，故B 错误；因为，所以.又，所以，则关于中心对称.因为，所以结合函数图象平移可得，关于点中心对称，故C 正确；由为偶函数，点为对称中心，得的周期为2，且，.又，所以，所以.因为，所以，所以，故D 正确.故选ACD.12.【解题思路】由题意知，，所以.13.【参考答案】【解题思路】设小万从这8道题中任选1道题且作对为事件，选到能完整做对的4道题为事件，选到有思路的3道题为事件，选到完全没有思路的题为事件，则，，.由全概率公式，得.14.【参考答案】【解题思路】因为，所以，.因为，，所以.因为在上单调递增，所以，，，所以.又因为，所以，所以.()00f '=()()22f x g x +-=()()20f x g x '--='()()12f x g x '++='()()122g x g x '++-='()g x '3,12⎛⎫⎪⎝⎭()2(1)f x g x '=-+'()f x '1,12⎛⎫⎪⎝⎭()f x '1,12⎛⎫⎪⎝⎭()f x '()()12f x f x '+-='11122f f ''⎛⎫⎛⎫-== ⎪ ⎪⎝⎭⎝⎭()()12g x f x +='-'()()21g x f x =-'-'2025202520251112140501222k k k k k k g f f ===⎛⎫⎛⎫⎛⎫⎛⎫=--=-- ⎪ ⎪ ⎪ ⎪⎝⎭⎝⎭⎝⎭⎝⎭'''∑∑∑()()41111014222k k f f f f f =⎛⎫⎛⎫⎛⎫-=-+++= ⎪ ⎪ ⎪⎝⎭⎝⎭⎝⎭'''''∑202512025202311450612024202420252222k k f f f f =⎛⎫⎛⎫⎛⎫⎛⎫-=⨯+-=+=+= ⎪ ⎪ ⎪ ⎪⎝⎭⎝⎭''⎭'⎝'⎭⎝∑2025120252k k g =⎛⎫= ⎪'⎝⎭∑()()()()33133333331112i i i i i z i i i i ------====-++-131z i +=-+=2532A B C D ()4182P B ==()38P C =()18P D =()()()()()()()132112512838432P A P B P A B P C P A C P D P A D =++=⨯+⨯+⨯=∣∣∣ln2-1e2x y x +=-'010e 2x x +=01x >11e n a n a ++=2303a a x +=021120000e 32e x a a x x x x +++==+=+1e x y x +=+R 20a x =302a x =120ln 1ln 1a a x =-=-12300ln 1a a a x x +-=--010e 2x x +=0001ln2ln2ln x x x +==+12300ln 1ln2a a a x x +-=--=-15.解：（1）列联表如下：感兴趣不感兴趣合计男生12416女生9514合计21930零假设为：学生对“数学建模”选修课的兴趣度与性别无关，……5分依据小概率值的独立性检验，没有充分证据推断不成立，因此可以认为成立，即学生对“数学建模”选修课的兴趣度与性别无关.……6分（2）由题意可知，的取值可能为0，1，2，3，……7分则，，，，……11分故的分布列如下：0123.……13分16.（1）证明：因为，，，即，所以，即.因为平面，平面，面面，所以，……3分所以.因为，，所以平面，所以.……6分（2）解：因为底面，，底面，所以，.又，所以，以点为原点，以，所在的直线为，轴，过点作的平行线为轴，建立空间直角坐标系如图所示.令，则，，，，，，，.设平面的法向量为，0H ()223012549200.4082 2.072.161421949K⨯⨯-⨯==≈<⨯⨯⨯0.15α=0H 0H X ()35395042CP X C ===()12453910121C C PX C ===()2145395214C C P X C ===()34391321CP X C ===X X P5421021514121()5105140123422114213E X =⨯+⨯+⨯+⨯=2AC =1BC =AB =222BC AB AC +=90ABC ∠=BC AB ⊥AD ∥PBC AD ⊂ABCD ABCD PBC BC =AD BC ∥AD AB ⊥AD PA ⊥PA AB A = AD ⊥PAB PB AD ⊥PA ⊥ABCD CD AD ⊂ABCD PA CD ⊥PA AD ⊥AD CD ⊥CD ==D DA DC x y D PA z PA t =)A)Pt ()0,0,0D ()C ()AC =()0,0,AP t = DC =)DP t =ACP ()1111,,n x y z =所以即令，则，，所以.……9分设平面的法向量为，所以即令，则，，所以.……11分因为二面角，二面角为锐角，，解得，所以.……15分17.解：（1）由正弦定理可知，，所以，所以，即.由余弦定理，所以.……4分（2）因为，所以等号两边同时平方可得，.又由（1）知，所以，即，所以，所以的周长为.……7分（3）由正弦定理可得，，即，110,0,n AC n AP ⎧=⎪⎨=⎪⋅⎩⋅1110,0,tz ⎧=⎪⎨=⎪⎩11x =11y =10z =()11,1,0n =CPD ()2222,,n x y z =220,0,n DP n DC ⎧=⎪⎨=⎪⋅⎩⋅ 2220,0,tz +==2z =2x t =-20y =(2n t =-A CP D --121212cos ,n n n n n n ⋅===2t =2PA =sin sin sin a b cA B C==()()sin sin sin sin sin sin sin sin sin B C A A a b cB CB CB C b c a cπ+--====++++-222a acbc -=-222a cb ac +-=2221cos 222a c b ac B ac ac +-===3B π∠=3BA BC += 229a c ac ++=223a c ac +-=226a c +=3ac =a c ==ABC △a b c ++=2sin sin BC ACABCθ∠===2sin BC θ=，即.因为四边形的内角和为，且，所以，所以.……11分（可以有多种表达形式，化简正确都得分），记，令，则.因为在中，所以，所以，所以当时，恒成立.当，即时，；当，即时，，则……15分18.解：（1）由题意可知，直线的斜率必存在.当垂直于轴时，点，，此时，即，所以抛物线的方程为.……5分（2）设直线的方程为，，.联立得，所以，，则.将代入直线，得，则的中点.因为，所以，则直线的方程为，即.同理可得，直线的方程为，所以，，所以.因为，则，所以，此时，，所以直线的方程为，代入，得，所以，所以2sin sin CD ACADCθ∠===2sin CD θ=ABCD 2πABC ADC ∠∠π+=2BCD πθ∠-=()211sin 2sin 2sin sin 22sin sin222S BC CD BCD ∠θθπθθθ=⋅=⨯⨯⨯-=⨯()22sin sin21cos2sin2sin2sin2cos2S θθθθθθθ=⨯=-=-2x θ=()sin sin cos f x x x x =-()()()()222cos cos sin 2cos cos 12cos 1cos 1f x x x x x x x x =-'-=-++=+-+ACD △03πθ<<203x π<<1cos 12x -<<1cos 12x -<<()0f x '>1cos 2x =-23x π=23f π⎛⎫= ⎪⎝⎭cos 1x =0x =()00f =()0f x <<0S <<l AB y ,2p A p ⎛⎫ ⎪⎝⎭,2p B p ⎛⎫- ⎪⎝⎭24AB p ==2p =C 24x y =l 1y kx =+()11,A x y ()22,B x y 21,4,y kx x y =+⎧⎨=⎩2440x kx --=124x x k +=124x x =-2Q x k =2Q x k =1y kx =+221Q y k =+AB ()22,21Q k k +24x y =2x y '=PA ()1112x y y x x -=-2111124y x x x =-PB 2221124y x x x =-()2212121211442122P x x x x x k x x -+===-21212111112244P x x x x y x x +=⋅-==-()2,1P k -4P x =24k =2k =()4,9Q ()4,1P -PQ 4x =24x y =4y =()4,4E.……10分（3）由（2）知，，，所以直线的方程为，代入，得，所以，所以为的中点.因为抛物线在点处的切线斜率，所以抛物线在点处的切线平行于.又因为为的中点，所以.因为直线的方程为，所以.又到直线的距离.，当且仅当时取“”，所以，所以四边形的面积的最小值为3.……17分19.（1）解：当时，恒成立，即恒成立，只需即可.令，，则.令，，则，当时，恒成立，即在上单调递增，所以，所以在上恒成立，即在上单调递增，所以，945QE =-=()22,21Q k k +()2,1P k -PQ 2x k =24x y =2y k =()22,E k k E PQ C E 22ky k '==C E AB E PQ 34ABP ABNM S S =△四边形AB 1y kx =+()()()2121212112444AB y y p kx kx k x x k =++=++++=++=+()2,1P k -AB h 1122ABP S AB h =⋅=△()()322244414kk +⋅=+≥0k ==334ABP ABNM S S =≥△四边形ABNM 1x ≥213ln 022x x ax +-+≥ln 1322x a x x x ≤++min ln 1322x a x x x ⎛⎫≤++ ⎪⎝⎭()ln 1322x g x x x x =++1x ≥()22221ln 132ln 1222x x x g x x x x -'--=+-=()22ln 1h x x x =--1x ≥()22222x h x x x x-=-='1x ≥()0h x '≥()h x [)1,+∞()()10h x h ≥=()0g x '≥[)1,+∞()g x [)1,+∞()()min 12g x g ==所以，即实数的最大值为2.……5分（2）证明：因为当时，，，所以，即在上单调递增.又，，且，所以不妨设.要证，即证明.因为在上单调递增，即证.因为，即证.设，，令，，则，.因为，所以，即在（0，1）上单调递增，所以，即，所以成立，所以.……11分（3）证明：由（2）可知，当时，在上单调递增，且.由，得，即.令，则，即，所以，，，，，相加得.……17分2a ≤a 2a =()21ln 22f x x x x =+-0x >()()21120x f x x x x-=+-=≥'()f x ()0,+∞()312f =-()()123f x f x +=-12x x ≠1201x x <<<122x x +>212x x >-()f x ()0,+∞()()212f x f x >-()()123f x f x +=-()()1123f x f x +-<-()()()()()()221123ln 2ln 2222322F x f x f x x x x x x x =+-+=+-+-+---+=()()()2ln 221ln 221x x x x x x x x ⎡⎤⎡⎤-+-+=---+⎣⎦⎣⎦01x <<()2t x x =-01t <<()ln 1t t t ϕ=-+()111tt t tϕ-=-='01t <<()0t ϕ'>()t ϕ()()10t ϕϕ<=()()()230F x f x f x =+-+<()()1123f x f x +-<-122x x +>2a =()f x ()1,+∞()()312f x f >=-213ln 2022x x x +-+>22ln 430x x x +-+>()22ln 21x x +->1n x n +=2112ln 21n n n n ++⎛⎫+-> ⎪⎝⎭2112ln 1n n n n +-⎛⎫+> ⎪⎝⎭22112ln 111-⎛⎫+> ⎪⎝⎭23122ln 122-⎛⎫+> ⎪⎝⎭24132ln 133-⎛⎫+> ⎪⎝⎭ 2112ln 1n n n n +-⎛⎫+> ⎪⎝⎭()2112ln 1ni i n n i =-⎛⎫++> ⎪⎝⎭∑。
成都石室中学高2019届10月份同步月考-化学试卷(解析版)
成都石室中学高2019届10月份同步月考化学试卷解析7．化学与生产、生活、社会密切相关。
下列有关说法中不正确的是A．航天服材质是主要由碳化硅、陶瓷和碳纤维复合而成，它是一种新型无机合成材料B．石油裂解、煤的气化、粮食酿酒、蛋白质的变性都是化学变化C．“地沟油”禁止食用，但可用来制取肥皂D．纳米铁粉有较强的物理吸附作用，可去除水体中的Cu2＋、Cd2＋、Hg2＋等重金属离子答案：D解析：纳米铁粉可除去水体中的Cu2+、Cd2＋、Hg2＋等重金属离子，是由于铁将其单质置换出来，而不是由于较强的物理吸附作用，故D错。
8．N A代表阿伏加德罗常数的值。
下列叙述正确的是A．标准状况下，2.24 L NO与1.12 L O2充分反应后的气体分子数为0.1N AB．向FeI2溶液中通入适量Cl2，当有1 mol Fe2＋被氧化时，共转移的电子的数目为N A C．1 mol K2S与K2S2的混合物中含离子总数为3N AD．25 ℃时，1 L pH＝12的Ba(OH)2溶液中含有的OH－数目为0.02N A答案：C解析：二氧化氮与四氧化二氮存在平衡，反应后的气体分子数无法准确计算，故A错；I-还原性强于Fe2+，I-优先反应，I-量不确定，转移的电子数无法计算，故B错；K2S2中过硫根是整体，K2S与K2S2阴阳离子个数比均是1:2，C正确；pH=12时，c(OH-)=0.01mol/L，考虑水的电离，则N(OH-)≥0.01N A，故D错。
9．下列说法正确的是A．乙烷、乙醇、乙酸、乙酸乙酯都能发生取代反应B．按系统命名法，化合物的名称是2,2,3,4,4-五甲基丁烷C．氯苯分子中苯环上的一个氢原子被丁基原子团取代形成的同分异构体共有4种D．乙烯和苯加入溴水中，都能观察到褪色现象，原因是都发生了加成反应答案：A解析：该结构的名称应为2,2,3,4-四甲基戊烷，故B错；丁基有4种，丁基和氯原子在苯环上的位置异构有3种，则4×3=12种，故C错；乙烯与溴发生加成反应而褪色，苯因为萃取溴水中的溴单质使溴水褪色，故D错。
成都石室中学2019级2019学年度上学期月考-高考模拟
成都石室中学2019级2019学年度上学期月考-高考模拟本文从网络收集而来，上传到平台为了帮到更多的人，如果您需要使用本文档，请点击下载按钮下载本文档（有偿下载），另外祝您生活愉快，工作顺利，万事如意！第I卷（选择题，共45分）一、（18分，每小题3分）1．下列加点的注音全对的一组是（）A．前仆（pū）后继潸（shān）然泪下荫（yìn）庇青冢（zhǒng）B．衣（yī）锦还乡针砭（biān）时弊埋（mán）怨绵亘（gèng）c．人心叵（pǒ）测箪食壶浆（sì）慰藉（jì）投奔（bèn）D．爱憎（zēng）分明淆（xiáo）乱乾坤梦魇（yǎn）熨（yùn）帖2．下面词语字形全对的一组是（）A．沐猴而冠头晕目眩闲情逸志死有余辜B．响誉中外鞭辟入里一筹莫展殒身不恤c．锲而不舍历经苍桑罄竹难书声名鹊起D．出神入化矫揉造作仓皇失措锱铢必较3．依次填入下列各横线处的词语恰当的一组是（）（1）北京大学作为我国重要的教育学术文化，为祖国培养了一代又一代优秀人士。
（2）鲁迅先生后期杂文，几乎都是讽刺文学的，他的谈话，也往往表现了同样的风格。
（3）小说中的典型形象虽然有生活，但仍属于虚构的现象。
A．领域典型原形B．阵地典范原型c．阵地典型原型D．领域典范原形4．下列各句中加点的词语，使用正确的一项是（）A．23日傍晚，小城澳门万人空巷，市民信众早早来到湄洲妈祖金身巡游澳门的拟定道路两旁，翘首企盼一睹仙容，膜拜这位在海内外中华儿女心目中享有盛誉的海上女神。
B．在这个厂里，他是敢于摔了铁饭碗，而干个体的始作俑者，在他之后，不少人或辞职，或停职，投入到下海的潮流中。
c．园丁康居工程，确定抓到了点子上，消息一传出，广大教师奔走相告，弹冠相庆，称赞为他们办了实事。
D．个人利益要服从集体利益，局部利益要服从整体利益，不能目无全牛，本末倒置。
5．下列各句中，没有语病的一句是（）A．作为一个共产党员，党的领导干部，办事、想问题，都要从党和人民的根本利益为出发点。
2019-2020学年成都市石室中学北湖校区高三英语月考试题及答案解析
2019-2020学年成都市石室中学北湖校区高三英语月考试题及答案解析第一部分阅读（共两节，满分40分）第一节（共15小题；每小题2分，满分30分）阅读下列短文，从每题所给的A、B、C、D四个选项中选出最佳选项ATry one of these amazing destinations on your next vacation.MallorcaOn the popular Spanish island of Mallorca, farmhouse inns focus more on providing isolation and quietness than offering hands-on farming experiences. With millions of visitors staying on the beaches of Mallorca and the other Balearic Islands each summer, a little bit of isolation is a good thing for aloneness-seeking travelers. Mainly located in the hills of inland Mallorca, these inns range from rustic century-old farmhouses to luxury(奢侈的) villas with spas and swimming pools.HawaiiPeople who don't want to dig out their passport but still want their farm adventure can head to the island of Hawaii. The 50th state talks much about the well-developed farm tourism industry that can hold people with different interests. Agritourism choices range from visiting coffee plantations(种植园) in the Big Island's Kona region to exploring the plantations on Maui to staying on farms on the easily reachable island of Oahu. CaliforniaCalifornia is one ofthe best places in the U. S. to enjoy a farm-stay, thanks to the diversity of crops and farms. Small family farms and large farms offer a more hands-on approach to agritourism. Many of them teach small-scale farming techniques and even offer strategies for organic growing. The University of California system, one of the largest state-run higher education systems in the U.S., has a small-farm program that helps growers create agritourism businesses.Philippine IslandsWith diverse conditions on different islands, the Philippine Islands are ideal places for visiting multiple agritourism sites or focusing on one product. Tourists can visit a huge pineapple plantation for a taste of large-scale agriculture, or they could focus on smaller operations such as bee farms, and even small plantations that specialize in growing tropical produce such as dragon fruit.1. What kind of people will choose to go to Mallorca?A. Those who prefer peace of mind.B. Those who like lying on the beach.C. Those who enjoy the luxury of tourism.D. Those who want to experience farming.2. What can people do on the Philippine Islands?A. Live in farmhouses.B. Visit plantations.C. Learn farming techniques.D Take part in a farm program.3. What are the four places in the text famous for?A. Locations.B. Environments.C. Local products.D. Tourism features.BShanghairesidents passing through the city’s eastern Huangpu district in Octobermight have astonished at an unusual sight: a “walking” building. An 85-year-old primary school has been lifted off the ground in its entirety and relocated using new technology named the “walking” machine.In the city’s latest effort to preserve historic structures, engineers used nearly 200 mobile supports under the five-story building. The supports act like robotic legs. They’re split into two groups which in turns rise up and down, imitating the human step. Attached sensors help control how the building moves forward.TheLagenaPrimary School, which weighs 7,600 tons, faced a new challenge — it’s T-shaped, while previously relocated structures were square or rectangular. Experts and technicians met to discuss possibilities and test a number of different technologies before deciding on the “walking machine”.Over the course of 18 days, the building was rotated 21degrees and moved 62 meters away to its new location. The old school building is set to become a center for heritage protection and cultural protection. The project marks the first time this “walking machine” method has been used inShanghaito relocate a historical building.In recent years,China’s rapid modernization has seen many historic buildingsrazedto clear land for skyscrapers and office buildings. But there has been growing concern about the architectural heritage loss as a result ofdestruction across the country.Shanghaihas beenChina’s most progressive city when it comes to heritage preservation. The survival of a number of 1930s buildings in the famous Bund district and 19th-century “Shikumen” houses in the repaired Xintiandi neighborhood has offered examples of how to give old buildings new life. The city also has a track record of relocating old buildings. In 2018, the city relocated a 90-year-old building in Hongkou district, which was then considered to beShanghai’s most complex relocation project to date.4. How did the primary school get moved?A. By reducing the weight of it.B. By using movable supports.C. By dividing it into several parts.D. By using robotic legs.5. What does the underlined word “razed” probably mean in Paragraph 5?A. Replaced.B. Burnt.C. Protected.D. Destroyed.6. What can we infer about the heritage preservation inChina?A. The use of advanced technology leads to growing concern.B. Shanghai is the pioneer in preserving architectural heritage.C.A number of old buildings have been given new life.D. Many historic buildings will be relocated.7. What is the passage mainly about?A. New preservation campaigns are launched inChina.B. New technology gives new life to historic buildings.C. A building inShanghai“walks” to a new location.D. “Walking machine” makes heritage protection simpler.CClara Daly was seated on an Alaska Airlines flight from Boston to Los Angeles when a flight attendant asked an urgent(紧急的) question over the loudspeaker: “Does anyone on board know American Body Language?” She knew she needed to help.Clara, 15 at the time, pressed the call button. The flight attendant came by and explained the situation. “We have a passenger on the plane who’s blind and deaf,” she said. The passenger seemed to want something, but he was traveling alone and the flight attendants couldn’t understand what he needed, according to PEOPLE magazine.Clara had been studying ASL for the past year to help with her dyslexia (阅读障碍) and knew she’d be able to spell on the man’s palm(手掌) by finger. So she unbuckled her seat belt, walked toward the front of the plane, and knelt by the aisle seat of Tim Cook, then 64. Gently taking his hand, she wrote, “How are you? Are you OK?” Cook asked for some water. When it arrived, Clara returned to her seat. She came by again a bit later because he wanted to know the time. On her third visit, she stopped and stayed for a while.“He didn’t need anything. He was lonely and wanted to talk,” Clara said. So for the next hour, that was what they did. She talked about her family and her plans for the future (she wants to be a politician). Cook told Clara how he had gradually become blind over time and shared stories of his days as a traveling salesman. Even though he couldn’t see her, she “looked attentively at his face with such kindness”, a passenger reported.“Clara was amazing,” a flight attendant told Alaska Airlines in a blog interview. “You could tell Cook was very excited to have someone he could speak to, and she was such a warm-hearted girl.” Cook’s reaction: “Best trip I’ve ever had.”Looking for ways to offer help? Start with this random(随时的) act of kindness that can change someone’s life right now.8. The flight attendant asked an urgent question because ________.A. the passenger was traveling aloneB. the plane was in a dangerous situationC. the passenger asked for something suddenlyD. none of the flight attendants could communicate with the passenger9. Why did Clara talk about her plans for the future?A. Because the flight attendant asked her to do so.B. Because she needed topics to go on talking with Cook.C. Because Cook hoped to understand teenagers better.D. Because she wanted to show her dream for the future.10. Which of the following words can best describe Clara?A. Kind and caring.B. Warm-hearted and brave.C. careful and calm.D. opened-minded and confident.11. The passage is mainly written to ________.A. tell a touching story of an amazing girlB. show the great importance of American Body LanguageC. encourage readers to give a hand kindly and randomlyD. show how kind the flight attendant was to help CookDHundreds of millions of people watched on television on July 20, 1969, when American astronauts Neil Armstrong and Buzz Aldrin became the first humans to land on the moon. Back then, businesses sold many products connected to the event and many such products are now on sales again — in celebration of the moon landing’s 50th anniversary.A limited number of Omega’s gold Speedmaster watches — the same kind that Buzz Aldrin wore on the moon — will be sold at $34,600. Omega Speedmaster watches have been an important part of space travel since NASA chose them for its moon landing in 1965. Other watches had failed required tests. Omega gave its gold Speedmasters to the astronauts at a dinner in 1969 before the landing. Another less costly type of silver Speedmasters will be sold at $ 9,650. It carries a picture of Aldrin stepping down from the moon lander.Something for children-as well as adults — is the NASA Apollo 11 moon lander set. Made by Lego, it is a group of small pieces to put together to make a model of the moon lander.Other things for sale include the anti-gravity Fisher Space Pens,developed just for the Apollo 11 mission. They work even when writing upside down. Now Fisher Space Pen Company has a limited-edition pen for sale at anout-of this-worldprice: $700, with real material from the Apollo 11 spacecraft.Back in 1969, companies were quick to show their Apollo 11 connections with media and advertisements. The food company Stouffer’s made sure consumers knew it provided food for Apollo 11 astronauts once they returned to Earth. It started the ad campaign “Everybody who’s been to the moon is eating Stouffer’s”. Fifty years later, the company is celebrating with a media campaign to share some recipes from 1969.Marketing experts David Meerman Scott says, “Since 1972,we’ve gone around and around the earth many times, and it is not interesting to people any more. I’m not sure whether they can accept such crazy prices. Now NASA has had plans to go to Mars in the 2030s and marketing efforts for a NASA Mars mission should be in development.”12. What can we learn about the gold Speedmaster watch?A. It will be sold at $34,600.B. NASA bought itats9,650.C. It has Aldrin’s picture inside.D. It was chosen by NASA in 1969.13. What does the underlined word “out-of-this-world” in paragraph 4 mean?A. Extremely fair.B. Surprisingly high.C. Really low.D. Truly worthwhile.14. What does David Meerman Scott mean?A. It is a waste of money to go around and around the moon.B. People will be interested in the products connected to Apollo.C. Since 1972,governments have lost interest in moon explorations.D. The event of going to Mars will be another good chance to advertise.15. What is the author’s main purpose in writing the text?A. To show how to design the best advertisement.B. To forecast the sales of the products in the text.C. To introduce some of the products connected to Apollo 11.D. To celebrate the 50th anniversary of the first moon landing.第二节（共5小题；每小题2分，满分10分）阅读下面短文，从短文后的选项中选出可以填入空白处的最佳选项。
四川省成都石室中学2018-2019学年高一数学10月月考试题
四川省成都石室中学2018-2019学年高一数学10月月考试题说明：考试时间120分钟，总分150分 一、选择题（共12小题；共60分）1. 集合{},,,,M a b c d e =，集合{},,N b d e =，则A. N M ∈B. MN M =C. MN M = D. M N >2. 下列各组函数中，表示同一函数的是A. ()1f x t =+ 与 2()x xg x x+=B. ()()22x f x =与 ()g x x =C.()f x x = 与()g x =D.()f x x =与 32()1t tg t t +=+3. 函数 24313x x y --+⎛⎫= ⎪⎝⎭的单调递增区间是A. (],2-∞-B. [)2,+∞C. [)2,-+∞D. (],2-∞4. 某工厂年来生产某种产品的情况是：前三年年产量的增长速度越来越快，后三年年产量保持不变，则该厂年来这种产品的总产量与时间（年）的函数关系图象最有可能是A. B.C. D.5. 关于 不等式0(0)ax b b +>≠的解集不可能是A. ,b a ⎛⎫+∞⎪⎝⎭B. ,b a ⎛⎫-∞-⎪⎝⎭C. ∅D. R6. 已知()f x 是R 上的偶函数，且当0x >时 ()()1f x x x =-，则当0x <时()f x 的解析式是()f x =（ ）A. ()1x x --B. ()1x x -C. ()1x x -+D. ()1x x +7. 比较 212333222,,335⎛⎫⎛⎫⎛⎫ ⎪ ⎪ ⎪⎝⎭⎝⎭⎝⎭的大小关系正确的是A. 122333222335⎛⎫⎛⎫⎛⎫>> ⎪ ⎪ ⎪⎝⎭⎝⎭⎝⎭B. 122333222353⎛⎫⎛⎫⎛⎫>> ⎪ ⎪ ⎪⎝⎭⎝⎭⎝⎭C. 212333222533⎛⎫⎛⎫⎛⎫>> ⎪ ⎪ ⎪⎝⎭⎝⎭⎝⎭D. 212333222335⎛⎫⎛⎫⎛⎫>> ⎪ ⎪ ⎪⎝⎭⎝⎭⎝⎭8. 若关于x 的不等式230ax bx ++> 的解集为11,2⎛⎫- ⎪⎝⎭，其中,a b 为常数，则不等式230x bx a ++< 的解集是A. ()2,1-B. ()1,2-C. 1,12⎛⎫- ⎪⎝⎭D. 11,2⎛⎫- ⎪⎝⎭9. 已知集合 403x A x x -⎧⎫=≤⎨⎬+⎩⎭，{}211B x m x m =-<<+，且 A B B ⋂=，则实数的取值范围为A. [)1,2-B. []1,3-C. [)2,+∞D.[)1,-+∞10. 函数()()2,211,22x a x x f x x -≥⎧⎪=⎨⎛⎫-<⎪ ⎪⎝⎭⎩ 值域为R ，则实数a 的取值范围是A. (),2-∞B. 13(,]8-∞ C. (0,2) D. 13[,2)811. 已知()223,03,0x x x f x x x x ⎧+≥⎪=⎨-+<⎪⎩，则不等式()()2240f x f x -+-< 的解集为A. ()1,6-B. ()6,1-C. ()3,2-D. ()2,3-12. 设函数 ()f x 与()g x 的定义域为R ，且()f x 单调递增，()()()F x f x g x =+，()()()G x f x g x =-．若对任意()1212,x x R x x ∈≠ ，不等式()()()()221212f x f x g x g x ->-⎡⎤⎡⎤⎣⎦⎣⎦ 恒成立．则A. ()(),F x G x 都是增函数B. ()(),F x G x 都是减函数C. ()F x 是增函数，()G x 是减函数D. ()F x 是减函数，()G x 是增函数二、填空题（共4小题；共20分） 13.若函数()131x f x a =++ 是奇函数，则实数 的值为 ．14. 已知函数()y f x =的定义域是 ，则函数1f x y +=的定义域是 ．15.若直线y ＝a 与函数13x y a +=- (a >0且a ≠1)的图象有两个公共点，则a 的取值范围是________________．16. 已知定义在R 上的函数()y f x =，满足()20f =，函数()1y f x =+的图象关于点()1,0-中心对称，且对任意的负数12,x x ()12x x ≠，()()201720171122120x f x x f x x x -<-恒成立，则不等式()0f x <的解集为____________. 三、解答题（共6小题；共70分）17.已知集合2{450}A x x x =--≤，{124}xB x =<<，}{C x x m =<.(1)求R A (C B)；(2)若A C A ≠且B C ≠∅，求实数m 的取值范围.18.（1）计算：()1120.7502370.064()2168π--⎡⎤--+-+⎣⎦；（2）求二次函数()()2410f x x ax a =-++> 在区间[]0,2的最大值.19.某工厂生产甲、乙两种产品所得利润分别为P 和Q （万元），它们与投入资金m （万元）的关系有如下公式：160,702P m Q =+=+今将200万元资金投入生产甲、乙两种产品，并要求对甲、乙两种产品的投入资金都不低于25万元.（1）设对乙种产品投入资金x （万元），求总利润y （万元）关于x 的函数关系式及其定义域；（2）如何分配投入资金，才能使总利润最大，并求出最大总利润.20. 设函数()21f x ax x=+()a R ∈其中. （1）讨论函数()f x 的奇偶性，并说明理由. （2）若12a >，试判断函数()f x 在区间[)1,+∞上的单调性，并用函数单调性定义给出证明.21．设函数 ()f x x a x =-+，其中 0a >． （1）当 3a = 时，求不等式 ()4f x x ≥+ 的解集；（2）若不等式 ()22f x x a ≥+ 在[1,3]x ∈恒成立，求实数a 的取值范围．22. 定义域为R 的函数()f x 满足：对于任意的实数,x y 都有()()()f x y f x f y +=+成立，且当0x < 时，()0f x > 恒成立，且()()nf x f nx = ．（n 是一个给定的正整数）． （1）判断函数 ()f x 的奇偶性，并证明你的结论；（2）证明()f x 为减函数；若函数()f x 在 []2,5- 上总有 ()10f x ≤ 成立，试确定 ()1f 应满足的条件；（3）当0a <时，解关于x 的不等式()()()()2211f ax nf x f a x nf a n n->- .成都石室中学2018—2019学年度上期高2021届10月月考数学参考答案一、选择题1－5：BDCAA 6－10：CABDD 11、12：CA二、填空题：13： 14： 15： 16：三、解答题：17：解：（1）………………………2′………………………3′………………………5′（2）由A∩C≠A，则………………………7′由C∩B≠∅，则………………………9′综上：………………………10′18：（1）解：原式==；………………………6′（2）解：对称轴………………………7′当，即时，……………………9′当，即时，……………………11′综上：………………………12′19. 解：(1) ………………………3′由，解得,即定义域为……………………5′（2）令，,则……………………7′,……………………8′所以当即时，…………………… 10′答：当甲种产品投入资金164万元，乙种产品投入资金36万元时，总利润最大. 最大总利润是248万元. …………………… 12′20：解：（Ⅰ） --------- 1分当时，，，为奇函数；--------- 3分当时，，，不是偶函数；--------- 4分，不是奇函数；--------- 5分故当时，是非奇非偶函数. ---------6分(2)任取，， ---------7分---------9分，，且,，. 于是，从而，即---------11分所以函数在区间上单调递增. ---------12分21：解：（1）当时，不等式，即，即，------1分或 ------5分故不等式的解集为． ------6分（2）由题意可得：在x恒成立（用公式法或函数法对应给分） ------12分22：解：（1）为奇函数，证明如下；由已知对于任意，， ------1分恒成立．令，得，所以． ------2分令，得．所以对于任意，都有．所以是奇函数． ------4分（2）设任意且，则，由已知，又，由得，根据函数单调性的定义知在上是减函数． ------6分所以在上的最大值为．要使恒成立，当且仅当，又因为所以．又，，所以． ------8分（3），所以．所以，所以，因为在上是减函数，所以．即， ------10分因为，所以．讨论：①当，即时，原不等式的解集为；②当，即时，原不等式的解集为；③当，即时，原不等式的解集为．---12分。
四川省成都市石室中学北湖校区高一上学期物理11月月考考试( Word版含答案)
四川省成都市石室中学北湖校区高一上学期物理11月月考考试（ Word 版含答案）一、选择题1．某航母跑道长200m 飞机在航母上滑行的最大加速度为6m/s 2，起飞需要的最低速度为50m/s ．那么，飞机在滑行前，需要借助弹射系统获得的最小初速度为A ．5m/sB ．10m/sC ．15m/sD ．20m/s2．如图所示，一物块置于水平地面上．当用与水平方向成060角的力1F 拉物块时，物块做匀速直线运动；当改用与水平方向成030角的力2F 推物块时，物块仍做匀速直线运动．若1F 和2F 的大小相等，则物块与地面之间的动摩擦因数为A ．31-B ．23-C ．312-D ．1-323．短跑运动员在100m 竞赛中，测得7s 末的速度是9m/s ，10s 末到达终点的速度是10.2m/s ，则运动员在全程内的平均速度为（ ）A ．9m/sB ．10m/sC ．9.6m/sD ．10.2m/s4．小刚同学看新闻时发现：自从我国采取调控房价政策以来，曾经有一段时间，全国部分城市的房价上涨出现减缓趋势。
小刚同学将房价的“上涨”类比成运动中的“加速”，将房价的“下降”类比成运动中的“减速”，据此类比方法，你觉得“房价上涨出现减缓趋势”可以类比成运动中的（ ）A ．速度增大，加速度减小B ．速度增大，加速度增大C ．速度减小，加速度减小D ．速度减小，加速度增大5．某同学用如图所示方法做共点力平衡实验．M 、N 为摩擦不计的定滑轮，O 点是轻质细绳OA 、OB 和OC 的结点，桌上有若干相同的钩码，他已经在A 点和C 点分别挂了3个和4个钩码，为使O 点在两滑轮间某位置受力平衡，在B 点挂的钩码数可能是（ ）A ．1个B ．3个C ．5个D ．7个6．下列说法正确的是 A ．竖直上抛物体到达最高点时，速度为零，物体处于平衡状态B ．人站在电梯中随电梯一起运动时，当电梯减速下降时，电梯对人的支持力大于人的重力C．跳水运动员踩压跳板弯曲到最低点时，运动员对跳板的压力由跳板发生形变而产生D．惯性是由物体的速度和质量共同决定的7．拿一个长约1.5m的玻璃筒，一端封闭，另一端有开关，把金属片和小羽毛放到玻璃筒里．把玻璃筒倒立过来，观察它们下落的情况，然后把玻璃筒里的空气抽出，再把玻璃筒倒立过来，再次观察它们下落的情况，下列说法正确的是A．玻璃筒充满空气时，金属片和小羽毛下落一样快B．玻璃筒充满空气时，金属片和小羽毛均做自由落体运动C．玻璃筒抽出空气后，金属片和小羽毛下落一样快D．玻璃筒抽出空气后，金属片比小羽毛下落快8．汽车A在红绿灯前停住，绿灯亮起时起动，以0.4 m/s2的加速度做匀加速运动，经过30 s后以该时刻的速度做匀速直线运动．设在绿灯亮的同时，汽车B以8 m/s的速度从A 车旁边驶过，且一直以相同速度做匀速直线运动，运动方向与A车相同，则从绿灯亮时开始( )A．A车在加速过程中与B车相遇B．A、B相遇时速度相同C．相遇时A车做匀速运动D．两车不可能再次相遇9．如图所示，物体B叠放在物体A上，A、B的质量均为m，且上、下表面均与斜面平行，它们以共同速度沿倾角为θ的固定斜面C匀速下滑，则()A．A、B间没有静摩擦力B．A受到B的静摩擦力方向沿斜面向上C．A受到斜面的滑动摩擦力大小为2mgsin θD．A与B间的动摩擦因数μ＝tan θ10．从发现情况到采取相应行动经过的时间叫反应时间。
成都石室中学高2019届10月份同步月考数学(文科)参考答案
1 1 S∆ADE ⋅ OP ＝ × 4 × 2 3 ， 3 3
……..9 分
且 VD − PAE =
1 1 S∆PAE ⋅ h = ⋅ 4 ⋅ h ， 3 3
从而由 VP − ADE = VD − PAE 得， h = 2 3 ， 所以点 D 到平面 PAE 的距离为 2 3 ． 20． （12 分） 解析：(1)依题意，直线 AB 的斜率存在，设直线 AB： = y k ( x + 1) ， A( x1 , y1 ), B( x2 , y2 ) ，
所以没有 95%的把握认为 2017 年个人移动支付比例达到 80%与该用户是城市用户还是农村 用户有关 ……….12 分 19． （12 分） 解析：(1)因为 PA＝PD＝AD＝4，O 为 AC 的中点，所以 OP ⊥ AD ，且 OP = 2 3 . 连结 OB. 因为 AB = 2 AO ，∠DAB＝45°，所以 △ABO 为等腰直角三角形， 且 OB ⊥ AD ， OB = 2 . 而 PB＝4，从而 OP 2 + OB 2 = PB 2 知 OP ⊥ OB ， 结合 OP ⊥ AD ，AD∩OB＝O，知 OP⊥平面 ABCD． ……….2 分 ……..4 分 …….6 分
1 ；14．0.5；15．－6；16． [5 − 2 5,5 + 2 5] ． 2
25 + 9 − 49 1 法 2：在△ACD 中，由余弦定理可得 cos ∠ADC = = − ，即∠ADC＝120°， 2 × 3× 5 2
在△ABC 中，由正弦定理可得
AB AC ACsin C 5 3 ＝ ，则 AB＝ ＝ 2×7× ＝5 3 ……6 分 sin C sin B sin B 14
= y k ( x + 1), 0， 则 2 ，整理得 (2k 2 + 1) x 2 + 4k 2 x + 2k 2 − 6 = 2 + = x 2 y 6
四川省成都市石室中学2024-2025学年高三上学期期中考试政治答案
成都石室中学2024-2025学年度上期高2025届十一月月考政治参考答案1.【答案】D【详解】①：奴隶社会取代原始社会是人类进入文明时代的开始，故①错误。
②：马克思认为，社会进步不是一帆风顺的，而是在矛盾和对抗中发展起来的，“生产建立在阶级的对抗上”表明生产关系状况制约生产发展，故②正确。
③：直接劳动是劳动者直接参与生产过程，创造价值的劳动形式，而积累劳动是资本家通过剥削工人的剩余价值，“积累的劳动”与“直接的劳动”的对抗意味着阶级的对立。
但资本主义社会一切矛盾和冲突的总根源是生产社会化与生产资料资本主义私人占有之间的矛盾，故③错误。
④：“没有对抗就没有进步”揭示了阶级斗争是推动社会发展的直接动力，故④正确。
故本题选D。
2.【答案】A【详解】材料主旨是发展新质生产力需要深化劳动力市场改革。
新质生产力的显著特点是创新,创新驱动本质上是人才驱动,习近平总书记强调按照发展新质生产力要求,完善人才培养,这表明习近平新时代中国特色社会主义思想为发展新质生产力提供了根本遵循，①正确。
发展新质生产力包括管理和制度层面的创新,这要求中国共产党坚持解放思想、实事求是、与时俱进、求真务实,扎实推进新质生产力发展的体制机制创新,②正确。
改革开放是坚持和发展中国特色社会主义的必由之路，③错误。
发展新质生产力应推动新型生产关系与生产力相适应，④错误。
故本题选A。
3.【答案】B【详解】①中国人民银行实施逆回购政策，有利于增加市场资金，保持银行体系流动性合理充裕，①排第一位。
③：银行体系流动性合理充裕，能够增强商业银行信贷投放能力，③排第二位。
②：商业银行信贷投放能力增强有利于缓解企业融资难题，②排第三位。
④：企业融资难题缓解，有利于实体经济发展，改善市场预期，④排第四位。
⑤：央行的做法是为了调节资金流动，推动经济持续健康发展，而不是为了提高金融机构的经济效益，⑤说法错误。
⑥：逆回购政策属于稳健的货币政策，⑥说法错误。
故本题选B。
成都石室中学文庙校区2019届高一下期月考语文试题 附答案
第Ⅰ卷阅读题（74分）一、现代文阅读（23分）（一）论述类文本阅读（9分，每小题3分）阅读下面的文字，完成1～3题。
漫谈李白诗歌中的夸张林庚李白有一首《长相思》诗中说：“忆君迢迢隔青天！昔时横波目，今作流泪泉；不信妾肠断，归来看取明镜前。
”这是一首闺人思念征夫的诗，相思之苦，以至于到了“昔时横波目，今作流泪泉”的程度。
美妙的眼睛竟成了一口泉眼，这当然是有些夸张；却还不能说就怎么不合理，还可以算在合理的夸张之列；但也有其不合理处，这不合理处在于她还要证明原来是秋波横生的眼睛，真的变成了一口泉眼；并要求那面镜子到时候为她作证。
因为如果真到那征夫回来的时候，她即使还很憔悴，即使是当时快乐得又哭了起来——那神情毕竟会大不相同——要证明她真正肠断的情形，只有那面镜子才最清楚。
可是除非那面镜子是面魔镜，又怎能重现她那已经成为过去的容颜呢？也许今天有了录像可以做到这一点，可是如果真有一位妻子录好了像专等她丈夫回来时证明这一切，恐怕她的丈夫反而更不相信；何况古代并无录像这种先进技术呢？假定真能录像，也许看来是合理的，却反而近于荒唐；假定镜子可以证明过去，看来好像是不合理的，却反而更近于真实。
艺术的魔力竟然真能把一面普通的镜子变成了魔镜吗？反正我们读这首诗，读到这里时早已忘记了那不合理性，而只感到分外亲切，分外动人。
从日常的尺度来说乃是不合理的，从艺术的尺度来说却是更为合理的；那么所谓合理的夸张到底该怎样来理解呢？“白发三千丈”，这是人们谈到李白诗中夸张时最爱引的名句，在这首《秋浦歌》中乃是轮到李白自己面对着一面镜子了。
所以说：“不知明镜里，何处得秋霜。
”从日常的尺度来说，这个“三千丈”简直是违背常识；从夸张的尺度来说，也未免无边无际；如果这样的夸张起来也算合理，那么究竟夸张到什么程度才算不合理呢？李白有一首经常为人们所称道的《望庐山瀑布》，诗中说“飞流直下三千尺，疑是银河落九天！”这瀑布仿佛是一道银河自天而降，也不过才夸张到三千尺，而白发从头上算起，却竟能达到三千丈；艺术的魔力似乎正是通过战胜那日常尺度认为的不合理而变得更为合理，这能不令人为之惊异叹服吗！有些人认为夸张似乎是浪漫主义的主要特征，这可能有些道理，可也并不尽然。
2024-2025学年四川省成都市石室中学高一(上)月考物理试卷(10月份)(含答案)
2024-2025学年四川省成都市石室中学高一（上）月考物理试卷（10月份）一、单选题：本大题共8小题，共24分。
1.关于重心，下列说法正确的是( )A. 重心可能在物体的外部B. 重心一定在物体的几何中心C. 重心不会随物体几何形状的改变而改变D. 物体除重心受重力之外，其他部分不受重力作用2.深中通道是国家重大工程和世界级跨海集群工程，全长约24千米，北距虎门大桥约30千米。
小明计划周末从家坐车去深圳宝安机场，他事先用导航软件搜索路线，若选择走A路线，经过虎门大桥，路程约103千米，耗时约1小时50分钟；若选择走B路线，经过深中通道，路程约53千米，耗时约1小时10分钟。
假设汽车实际行驶路程和时间与导航软件预计的相同，则下列说法正确的是( )A. 汽车通过两条路线的平均速度相同B. 汽车通过A路线的平均速度更大C. 汽车通过A路线的位移更大D. 汽车通过A路线的平均速率更大3.如图所示，在粗糙水平面上有两个质量分别为m1和m2的木块1和2，中间用一原长为l、劲度系数为k的轻弹簧连接，木块与地面之间的动摩擦因数为μ.现用一水平力向右拉木块1，当两木块一起匀速运动时，两木块之间的距离为( )A. l+μm1gk B. l+μ(m1+m2)gkC. l+μm2gkD. l+μm1m2gk(m1+m2)4.如图所示为一个时钟，下列说法正确的是( )A. 一秒钟之内，时针针尖的位移最小B. 一分钟之内，时针针尖的位移最小C. 一小时之内，秒针针尖的位移最大D. 永远不可能存在一段时间，在这段时间内时针、分针、秒针针尖的位移相等5.2024年6月2日，嫦娥六号成功着陆月球背面南极——艾特肯盆地。
嫦娥六号利用向下喷射气体产生的反作用力，有效地控制了探测器着陆过程中的运动状态。
其中一段着陆过程中，探测器减速的加速度大小a 随时间t变化的关系如图所示，3t0时刻探测器的速度恰好为零。
下列说法中正确的是( )A. 0～t时间内，探测器做匀速直线运动B. 探测器在t0时刻的速度大小是2t0时刻的4倍C. 0～t0时间内，探测器的位移大小为52a0t20D. 0～t0探测器的速度变化量是t0～3t0的两倍6.成昆复线米易到昆明段已于2020年正式通车，标志着攀西地区发展进入了快车道。
2019-2020学年成都石室佳兴外国语学校高三英语月考试卷及参考答案
2019-2020学年成都石室佳兴外国语学校高三英语月考试卷及参考答案第一部分阅读（共两节，满分40分）第一节（共15小题；每小题2分，满分30分）阅读下列短文，从每题所给的A、B、C、D四个选项中选出最佳选项AThree Things to Do Before You Are 18Are you bored with your daily life? Here are some things you should try before you are 18.★Learn to swimSeriously, this is so important that it can save your life. If you can’t swim well, you won’t be able to dowater sports like waterskiing, surfing and diving. Even taking a boat trip will be dangerous for you. Make sure you do it.★Try at least one kind of team sportsBeing a good team player is an important skill in life. You can’t just think of yourself, but have to work well with other people. Other advantages of team sports like basketball, football and baseball are that they keep you fit and healthy, and they are also great fun. Teams usually have a good social life too—you’ll go to lots of parties and make many friends.★Collect somethingOne of the best hobbies for under-18s is collecting things. You could collect kinds of stamps, or you could collect things that make you remember what you have done, like cinema tickets for films you have seen or letters from friends. The best way to collect is to have a special album to put your collection in and to write what each thing means to you. That way you won’t forget.1. The most important reason for learning to swim is that ________.A. you might feel wellB. it can make you healthyC. you might easily do lots of thingsD. it can save your life2. The writer tells us that one of the best hobbies is to ________ .A. collect somethingB. do some water sportsC. send letters to your friendsD. play basketball with your friends23. The passage is mainly about ________before you are 18.A. good habits to keepB. skills to haveC. things to doD. sports to playBIn a recent survey of 2000 Americans, housecleaning was shown to have some mood-boosting effects — but that doesn't mean everybody is willing to do it.The majority of respondents (受访者) said cleaning gave them a sense of accomplishment (65%) and helped them clear their mind (63%). Half of these adults said they are most often motivated to clean when they're happy. In fact, 63% of those surveyed find the experience of cleaning to be relaxing - even more so than getting fresh air (61%).But that's not the only reason people clean. A big 70% admitted that tidying their home was a way of putting off having to do other things, with the average procrastinator (拖延者) using that trick four times a week. The survey showed that 86% of respondents do feel on top of their housework, but the last deep clean of their kitchen happened over a week and a half ago. That's no surprise because the kitchen is most terrible of all.Conducted by OnePoll on behalf of DishFish, the survey investigated people's attitudes toward dirty dishes and how they get through tricky task. More than two-thirds of people (69%) let their dishes pile up between washings with 20% saying “always” letting them be placed in the sink, which left them feeling stressed. More than any other room, the kitchen was rated as “very difficult” to cope with. And most people enjoy cleaning their toilet or taking out the garbage more than washing dishes by hand.How do they get through it? 66% listen to music while they clean. 72% have a best-loved song that they sounded while tidying up their home, with “Uptown Funk,”“Read All About It” and “Work” being the three favorite tunes on America's cleaning playlist.4. What is the result of the survey?A. Housecleaning may contribute to a good mood to some extent.B. Housecleaning may strengthen people's willingness to volunteer.C. Housecleaning may cause anxiety and concern for some people.D. Housecleaning may improve people's motivation to other housework.5. What is the top reason why people undertake housecleaning?A. They can entertain themselves.B. They can take in fresh air.C. They get a sense of achievement.D. They can delay other things.6. What are respondents' attitudes to dirty dishes?A. Many would rather wash dishes than throw out the rubbish.B. Half are under pressure with dirty dishes lying in the sink.C. A quarter will let dirty dishes pile up after their meals.D. Most prefer cleaning their toiletto washing dishes by hand.7. What column does the text belong to?A. Feature Story.B. Family Life.C. Scientific Hotspot.D. Finance Focus.CIs renting clothes greener than buying them? Sustainable (可持续的) fashion expert Elizabeth Cline isn’t sure. Clothing renting is a hot new industry and businessmen are trying to attract shoppers who care about the environment. Last summer alone,Urban Outfitters, Macy’s, Bloomingdale’s American EagleandBanana Republicall announced renting services – a sure sign of changing times.But is renting fashion actually more environmentally-friendly than buying it? And if so, how much more? Journalist and author Elizabeth Cline researched this question in a feature article for Elle, and she concluded that it’s not as sustainable as it seems.Take shipping for example, which has to go two ways if an item is rented – receiving and returning. Cline writes that consumer transportation has the second largest carbon footprint of our collective fashion habit after manufacturing.Then there’s the burden of washing, which has to happen for every item when it’s returned, regardless of whether or not it was worn. For most renting services, this usually means dry-cleaning, which is a polluting process. All the renting services that Cline looked into have replaced perchloroethylene, a carcinogenic (致癌的) air pollutants that’s still used by 70 percent of US dry cleaners, with hydrocarbon (碳氢化合物) alternatives, although these aren’t great either. They can produce harmful waste and air pollution if not handled correctly.Lastly, Cline fears that renting services will increase our appetite for fast fashion, simply because it’s so easily accessible. There’s something called “share-washing” that makes people have more wasteful behaviors because a product or service is shared and thus is considered more eco-friendly. Uber is one example of this: advertised as a way to share rides and reduce car ownership, and yet it has been proven to discourage walking, bicycling and public transportation use.Renting clothes is still preferable to buying them cheap and throwing them into the bin after wearing them a few times, but we shouldn’t let the availability of these services make us self-satisfied. There’s an even better step – and that’s wearing what we already have.8. What do we know about Elizabeth Cline from the passage?A. She is trying to attract shoppers.B. She is an expert and journalist.C. She has created “share-washing”.D. She never rents clothes.9. Why does renting services increase people’s appetite for fast fashion?A. Because it is handled correctly.B. Because it is transported easily.C. Because it is fairly eco-friendly.D. Because it is easily accessible.10. What can we infer from the passage?A. Clothing renting became popular ten years ago.B. Consumer transportation has the largest carbon footprint.C. Renting clothes deserves further consideration.D. Uber is a good example of sharing rides.11. Which section of a newspaper does the text probably come from?A. Environment.B. Technology.C. Travel.D. Medicine.D“Snowplow(扫雪机) parenting” is the newest parenting style that can include parents booking their adult children haircuts, calling their college kids to wake them up so that they don’t sleep through a test, and even calling their kids’ employers.“‘Helicopter (直升机) parenting’ means monitoring their kids’ every activity,which is out of date.” Claire Cain Miller and Jonah Engel Bromwich wrote in The New York Times. “Some rich mothers and fathers now are more like snowplows: clearing any problems in their children’s path to success so that they don’t have to meet failure or lose opportunities.”There is a mother who started a charity in her son’s name to try to raise his chances of being accepted to the college. Another parents spent years helping their daughter avoid foods with sauce, which she didn’t like. Once she got to college, she had problems with the food in her school because it was all covered in sauce.A survey says that three-quarters of parents of children between the ages of 18 and 28 ask for doctor visits or haircuts for their children, and 11% say they would call their kids’ bosses whether their children are having anissue at work.As reported, wealthy parents try to get their children into top colleges by giving a large amount of money to a school, such as paying for a building. This parenting has become the most popular way to raise children, whatever the income, education, or race is.Julie, a teacher at Stanford, told the Times that “snowplow parenting” is not a reasonable approach. “The parents should prepare the kid for the road, instead of preparing the road for the kid,” she said.12. How does Julie like “snowplow parenting”?A. It is unreasonable.B. It is advanced.C. It is accepted by teachers.D. It is refused by rich people.13. What is the character of “helicopter parenting”?A. Parents make kids popular.B. Parents provide little money for kids.C. Parents ask kids to care for themselves.D. Parents watch over kids’ every activity.14. What should parents do according to Julie?A. Do as wealthy parents do.B. Make kids be prepared.C. Make roads be prepared.D. Do as little as possible.15. What’s the best title for the text?A. Helicopter Parenting.B. The Similarity in Parenting.C. A Research on Parenting.D. A New Kind of Parenting.第二节（共5小题；每小题2分，满分10分）阅读下面短文，从短文后的选项中选出可以填入空白处的最佳选项。
2019-2020学年成都市石室中学北湖校区高三英语月考试卷及参考答案
2019-2020学年成都市石室中学北湖校区高三英语月考试卷及参考答案第一部分阅读（共两节，满分40分）第一节（共15小题；每小题2分，满分30分）阅读下列短文，从每题所给的A、B、C、D四个选项中选出最佳选项AFilms to watch in MarchGretaA lonely young waitress finds a handbag on aNew Yorksubway train. Luckily, the address is inside, so she returns it to the piano teacher who left it there. She then discovers that the piano teacher makes a habit of dropping bags around the city on purpose to make new friends. Directed by Neil Jordan, the actors are attractive. Grace Moretz is the waitress and Isabelle Huppert is the one who admires her. Thanks to them, Greta winds up being far more enjoyable than it has any right to be.The AftermathThe Aftermath is one of the few World WarⅡ-related films. Based on Rhidian Brook’s novel,this touching romantic movie is starred by Keira Knightley, who is the wife of a British officer. She hates the Germans because her son was killed in an air raid. But is there a chance that a tall, dark andhandsome man might persuade her to overcome her hate?Captain MarvelIt took Marvel Studios a decade to finally make a female superhero. It’s also the first Marvel film to be directed by a woman, who has directed Half Nelson and Missisippi Grind. Captain Marvel is set in the 1990s. The Oscar-winning Brie Larson stars as Carol Danvers, a US Air Force fighter pilot, while Samuel L Jackson, as usual, plays Nick Fury.DumboDumbo is a classic Disney cartoon, who has big ears and there have been plenty of those kind of movies in recent years.Burtonalways has inspirations to direct such kind of movies from Edward Scissorhands to Miss Peregrine’s Home for Peculiar Children. Magical figures have always been his favorite characters.1. What makes Captain Marvel special?A. Winning Oscar.B. Its female director.C. Time setting.D. A woman pilot.2. Which film is better for a 7-year-old kid to watch?A. The AftermathB. Captain MarvelC. GreteD. Dumbo3. Where can you most probably read the text?A. Reader’s DigestB. NatureC. Scientific AmericanD. National GeographicBMasks that helped save lives during the Covid-19 pandemic（疫情）are proving a deadly risk for wildlife, with birds and sea creatures trapped in many facial coverings in animal habitats.Single-use masks have been found on the ground, waterways and beaches worldwide since countries required（heir use in public places to slow the pandemic's spread. Worn once, the thin protective materials can take hundreds of years to break down. "Face masks aren't going away any time soon-but when we throw them away, these items can harm the environment and the animals who share our planet," Ashley from anima! rights group PETA said.Monkeys have been found playing with used masks in the hills outsideMalaysia's capitalKuala Lumpur. And in an incident inBritain, a seagull was saved inChelmsfordafter its legs got caught in an abandoned mask for a week.However, the biggest influence is in the water. More than 1.5 billion masks made their way into the world's oceans last year, accounting for around 6200 extra tons of ocean plastic pollution, according to environmental group OceansAsia. “Masks and gloves are particularlyproblematicfor sea creatures," says George Leonard, chief scientist from NGO. "When those plastics break down in the environment, they form smaller and smaller particles （颗粒）.Those particles then enter the food chain and influence the entire ecosystem,“ he added.Campaigners have urged people to deal with masks properly after using them. OceansAsia has also called on governments to increase punishment for littering and encourage the use of washable masks.4. What bring（s）a great danger to wildlife now?A. Waste masks.B. Covid-19.C. Polluted water.D. Damaged habitats.5. What does the underlined word “problematic”in paragraph 4 mean?A. Important.B. Attractive.C. Common.D. Troubling.6. What can we infer from the text?A. Monkeys learned to wear masks from humans.B. Plastics are less harmful after becoming particles.C. Used masks have a worse effect on sea creatures.D. Waste masks arc the main ocean plastic pollution.7. How should we solve the problem from the last paragraph?A. Keep masks after they' re used.B. Call on governments to stop littering.C. Punish those who wear single-use masks.D. Put used masks in the recycling box.CThe mass death of flying foxes in extreme heat in North Queensland last month underlines the importance ofUniversityofQueenslandwildliferesearch released today.The UQ research sheds light on how various species have responded to major climate events.A study led by UQ School of Earth and Environmental Science researcher Dr Sean Maxwell has spent more than 70 years quantifying the responses of various species.“The growing frequency and intensity of extreme weather events such as cyclones, droughts and floods is causing unpredictable and immediate changes to ecosystems and blocking existing management efforts,” Dr Maxwell said.“Some of the negative responses we found were quite concerning, including more than 100 cases of dramatic population declines and 31 cases of local population extinction following an extreme event.”"Populations of critically endangered bird species inHawaii, such as the palia, have been annihilated due to drought, leaving none of its kind, and populations of lizard species have been wiped out due to cyclones in theBahamas."Cyclones were the most common extreme event for birds, fish, plants and reptiles, while mammals and amphibians were most responsive to drought events, with drought leading to 12 cases of major population decline in mammals.Drought also led to 13 cases of breeding declines in bird populations and 12 cases of changes in the composition of invertebrate communities.UQ Centre for Biodiversity and Conservation Science director Professor James Watson said the detailed information would help inform ecosystem management.“The research clearly shows species will respond, often negatively, to extreme events,” Professor Watson said.“As climate change continues to ensure extreme climate and weather events are more and more common,we now need to act to ensure species have the best chance to survive.Wherever possible, high quality and intacthabitat areas should be retained, as these are the places where species are most resilient(易恢复的) to increasing exposure to extreme events.”8. How was the UQ researchconducted?A. By observing extreme weather events.B. By protecting the endangered species.C. By recording reactions of animals to extreme climate.D. By analyzing the reason whymass animal death happened.9. What does the underlined word “annihilated” in paragraph 4 probably mean?A. destroyedB. defeatedC. decreasedD. disappeared10. Which of the following sentences is true about extreme weather events?A. Drought caused 13 cases of distinctionin bird populations.B. Drought caused 12 cases of population decline in mammals.C. Birds and mammals are most responsive to cyclones.D. Cyclones wiped out populations of lizard.11. What can we infer from Professor Watson’s words?A. Animals often show negative responses to extreme events.B. The existing management ways for wildlife protection are limited.C. Different methods should be adopted to ensure the survival of different species.D. Complete and undamaged habitats are of great importance to species’ survival.DI was at the hardware store the other day and overheard a woman tell Ed., the manager, that fall was her favorite time of year. Ed., because he liked to keep his customers happy, agreed that fall was a wonderful season, but I could tell he was lying.I was going through my mind recently, trying to find sweet memories of fall. I failed. I met my wife in the summer and married her two summers later. My sons were born in the winter and summer, my granddaughter in the winter. I’ve been fried twice in my life, both in fall. One October, a truck carrying tofu ran a red light and hit me, destroying my favorite car, combining the three things I most hate - trucks, tofu and October.I'm not saying fall is without its attractions. The leavesare beautiful. But fall's vacillation (立场摇摆)is troubling, its effort (努力)to please everyone, its continuous search for the middle ground to be all things to allpeople. Say what you will about summer and winter, at least they have the courage to keep their opinions strong, even if they kill us with extreme heat or cold.I recently read a story of a man coming out of a three-month coma (昏迷). It started in early fall and ended just as winter came. I hope if I were ever in a coma I would be just as lucky as the man.Upon my awakening, one of my families who stood around my bed would ask. "Don't you remember anything from the past three months?""Not the first thing," I would happily report.If I ever have enough money. I'm going to buy a second home inAustralia, so that when fall starts here, I can move there for three months, just when spring is starting.12. What did Ed think of the customers words according to the author?A. Ed understood them and supported the customer completely.B. Ed might hold a different opinion on the topic.C. Ed believed the customer wasn't telling the truth.D. Ed thought they stood for most peoples' opinion.13. What can we infer from Paragraph 2?A.The author has a big and loving family.B. The author is having a hard time at work.C. It is important to follow the rules of the road.D. Nothing good has happened to the author in fall.14. Why does the author say the man in Paragraph 4 was lucky?A. Because he slept fall away.B. Because he ho sweet memories of fall.C. Because hedreamed of fill many times.D. Because he was met by his family when waking up.15. Which of the following does the author most want to do?A. Drivetracks.B. Eat tofu dishes.C. Watch leaves falling in fall.D. Move toAustraliain October.第二节（共5小题；每小题2分，满分10分）阅读下面短文，从短文后的选项中选出可以填入空白处的最佳选项。
四川省成都市青羊区石室中学2019-2020学年高三上学期10月月考数学(理)试题(解析版)
论都要否。属于基础题。
4. 已知
an
是公差为
1
的等差数列，
Sn 为 an
的前 n 项和 . 若 a2， a6 ， a14 成等比数列，则
S5
（
）
2
35
A.
2
B. 35
25
C.
2
D. 25
【答案】 C
【解析】 【分析】
根据条件求首项，再根据等差数列求和公式得结果
,
【详解】因为 a2 ， a6 ， a14 成等比数列，所以
【答案】 B
【解析】
【分析】
根据命题的否定：全称变特称，只否结论；否命题：条件结论都要否。即可选出答案。
【详解】 p 的否定为“ x ( ,0) ， 2x2 3x 1 0 ”， q的否命题为“若 x 0 ，则 2x2 3 x 1 0 ”
故选： B 【点睛】本题考查命题的否定与否命题，注意区分命题的否定：全称变特称，只否结论；否命题：条件结
a
2 6
a2a14 ,( a1
5)2
( a1
1
13
)( a1 )
a1
3
，
2
2
2
2
31
1 25
因此 S5 5
54
,选 C.
22
22
B. p 的否定为“ x ( ,0) ， 2x2 3x 1 0 ”， q的否命题为“若 x 0 ，则 2x2 3x 1 0 ”
C. p 的否定为“ x [0, ) ， 2x2 3x 1 0 ”， q的否命题为“若 x 0 ,0) ， 2x2 3x 1 0 ”， q的否命题为“若 x 0 ，则 2 x2 3x 1 0 ”
B. M N
2019-2020学年成都石室中学北湖校区高三英语月考试题及参考答案
2019-2020学年成都石室中学北湖校区高三英语月考试题及参考答案第一部分阅读（共两节，满分40分）第一节（共15小题；每小题2分，满分30分）阅读下列短文，从每题所给的A、B、C、D四个选项中选出最佳选项A4 Best Drive--In Movie Theaters in the USColorado: Holiday Twin Drive--InAddress: 2206 S Overland Trail, Fort Collins, CO 80526, USAPhone: +1 970-221-1244The theater, open since 1968 and currently the most popular drive-in in the US, provides various special foods. The menu there even amazes meat-free customers. But please remember the outside food is forbidden here. Besides, the Rocky Mountains provide a pastoral (田园式的) backdrop to screenings, and sunsets usually don’t disappoint either. It also offers lots of unique events that go beyond the big screen.North Carolina: Hound’s Drive--InAddress: 114 Raven Cir, Kings Mountain, NC 28086, USAPhone: +1 704-739-4424Having only opened in 2016, it’s one of the newest theaters on the block. The drive-in features newer equipment and digital projection. People can bring their animal friends along.Florida: Fort Lauderdale Swap ShopAddress: 3291 W Sunrise Blvd, Fort Lauderdale, FL 33311, USAPhone: +1 954-791-7927The Florida favorite offers plenty ofways to have fun. With 14 screens, the self-proclaimed (自称的) world’s largest drive-in equals any indoor cinema in terms of capacity and programming. It also includes an 88-acre flea (跳蚤) market and a free Ferrari museum. It’s best to book tickets on the Internet ahead of time if you don’t want to wait in line.California: Mission Tiki Drive -InAddress: 10798 Ramona Ave, Montclair, CA 91763, USAPhone: +1 909-628-0511Let’s have fun in the old-school outdoor cinema in Montclair, California. Remember tickets are available at the ticket office only. It alternates (交替) up to eight new releases on four screens and hosts almost daily swapmeets where people can exchange things they no longer need. It also organizes classic car and lowrider meet-ups.1.What can people do in Holiday Twin Drive-In?A.Participate in somespecial activities.B.Enjoy the film with the latest equipment.C.Learn about the benefits of being meat free.D.Share home-made cookies while watching the film.2.Which of the following theaters is friendly to visitors with pets?A.Hound’s Drive- In.B.Mission Tiki Drive-In.C.Holiday Twin Drive-In.D.Fort Lauderdale Swap Shop.3.What do Fort Lauderdale Swap Shop and Mission Tiki Drive-In have in common?A.Both feature old-fashioned styles.B.Both allow booking tickets online.C.Both provide free museum exhibitions.D.Both offer chances to trade second-hand goods.BIn the northern part ofAustin there once lived an honest family by the name of Smothers. The family had John Smothers, his wife and their five-year-old daughter.One night after supper the little girl was ill with a serious stomachache, and John Smothers hurried downtown to get some medicine. He never came back. The mother was very sad over her husband's disappearance, and it was nearly three months before she married again, and moved to San Antonio. The little girl recovered and in time grew up to womanhood. After a few years had rolled around, the little girl also married in time, and she also had a little girl of five years. She still lived in the same house where theydweltwhen her father had left and never returned.By an unbelievable coincidence her little girl was taken with the same stomachache on the same night of the disappearance of John Smothers, who would now have been her grandfather if he had been alive. “I will go downtown and get some medicine for her,” said John Smith(for it was he whom she had married). “No, no, dear John,” cried his wife. “You, too, might disappear forever, and then forget to come back.” So John Smith did not go, and together they sat by the bedside of little Pansy. After a little while Pansy seemed to grow worse, and John Smith again wanted to go for medicine, but his wife would not let him.Just then, the door suddenly opened and an old man with long white hair entered the room. “Hello, here isgrandpa,” said Pansy. She had recognized him before any of the others. The old man drew a bottle of medicine from his pocket and gave Pansy a spoonful. She got well immediately. “I was a little late,” said John Smothers, “as I waited for a street car.”4. What happened after John Smothers disappeared?A. His daughter took some medicine.B. His wife left for San Antonio.C. Pansy immediately had a stomachache.D. John Smith went for medicine.5. What does the underlined word “dwelt” in paragraph 2 probably mean?A. Lived.B. Left.C. Returned.D. Married.6. What is the relationship between John Smothersand Pansy?A. Husband and wife.B. Father and daughter.C. Grandfather and granddaughter.D. Father and son.7. How could Pansy's mother feel when she saw John Smothers?A. Worried.B. Sad.C. Uninterested.D. Surprised.CScientists often compare coral reefs(珊瑚礁) to underwater rainforests, yet unlike the leafy plant base of a forest, corals are animals. The soft creatures are naturally half-transparent and get their brilliant color1 from algae(藻类) living inside them. When corals experience stress from hot temperatures or pollution, theyhaltthe interdependent relationship with algae, typically pushing them out and turning white. Corals are still alive when they are white, but they're at risk and many eventually die, turning dark brown.Scientists around the world are looking for means to protect and maybe increase corals. One common option is to create more protected areas — essentially national parks in the ocean. Beyond nature preserves, some conservationists are looking to more hands-on methods. One research center in the Florida Keys is exploring a form of natural selection to keep corals remaining. The reef system in the Keys has been hit hard by climate change and pollution, which is especially tough, because corals there help support fisheries worth $ 100 million every year.To keep the wild ecosystem alive, Erinn Muller, the center's director, and her team are harvesting samples of the corals that survived the environmental stress naturally, keeping them to make them reproduce, and then reattaching them to the reef. They have 46,000 corals on plastic frames under the sea. So far, the center has regrown over 70,000 corals from five different species on damaged reefs.In The Bahamas, Ross Cunning, a research biologist at Chicago's Shedd Aquarium, focuses on corals withgenes that could make them natural candidates for restoration projects. He published a study of two Bahamian reefs, one that survived an extreme 2015 heat wave, and one that didn't. "We think their ability to deal with these higher temperatures is built into their genes," says Cunning. There's evidence of corals evolving more quickly to resist rapidly warming climate. The big question scientists need investigate, adds Gunning, is how much more heat corals can adapt to.8. What does the underlined word "halt" in the first paragraph mean?A. End.B. Develop.C. Strengthen.D. Weaken.9. What do Muller and her team do to save corals?A. Restore the damaged reefs.B. Grow corals by hand underwater.C. Create more protected areas.D. Move corals to unpolluted areas.10. What do Gunning's words suggest?A. Many corals have been genetically improved.B. Cooling down the waters is key to rescuing corals.C. Reasons for corals surviving heat waves are shocking.D. The highest temperature corals can survive is unclear.11. Which can be a suitable title for the text?A. Relationship between corals and algaeB. Efforts made to save coralsC. Impact of climate warming on coralsD. Survival crisis faced by coral reefsDMy first week working in a restaurant, one of the servers said something that stuck with me: Everyone should work in a restaurant for at least a year. At the time, I didn't get it, but I took the advice to heart and worked in restaurants on and off for the next eight years. Before realizing it, I mastered many important skills, one of which is communication skill.When I was little, I was so shy that I used to hide behind my mom whenever someone spoke to me. And when I first started in restaurants, I had two personalities: Restaurant Lizzy and Home Lizzy. It was easier to pretend to be a different person while at work, since it was so different from who I actually was. But gradually, the skills I learned working in restaurants helped Home Lizzy come out of her shell in the real world.When you work in a restaurant, you don't have the luxury of hiding behind your parents to avoid talking to people. I'm still 110% an introvert, but restaurant work helped me communicate. Working in a restaurant not only helped me speak clearly, deliberately and directly but also taught me how to talk about almost everything. Someguests don't want their servers to interact too much with them, and that's fine. But some sit at the bar simply to chat with you. You learn how to judge your guests' level of interest in communicating with you, and how to exit a conversation at the appropriate time.My restaurant work is something that I'm most proud of and I know I wouldn't be the person I am today without those eight years of experience. If you're still on the fence about working in a restaurant for that long, start with one year. I doubt that you'll look back.12. What did the writer think of the server's words?A. Impressive.B. Ridiculous.C. Amusing.D. Logical.13. What do we infer from Paragraph 2?A. The writer tried different jobs.B. The writer became more sociable.C. The writer used an invented name.D. The writer had a hard time at work.14. Which of the following best describes the writer's restaurant work?A. Boring.B. Relaxing.C. Worthwhile.D. Unchallenging.15. What message does the writer try to convey in this passage?A. A strong-willed soul can reach his goal.B. Things are difficult before they are easy.C. Communication skills advance your career.D. Restaurantwork helps to achieve a better self.第二节（共5小题；每小题2分，满分10分）阅读下面短文，从短文后的选项中选出可以填入空白处的最佳选项。
成都石室中学月考试卷调研
Ａ ．向上 平移 两个单 位 Ｃ ．向左平 移两 个单位
Ｂ ．向下 平移 两个单位 Ｄ ．向右平 移两个 单位
函数 奇偶 性来 比较 函数值 的大小 ； 文 理 科 第 １ 题都 涉 及 关于 函数 的 新 定 ６ 义 ， 查 抽 象概 括 能 力 、 辑 推理 能 考 逻 力 和 运 算 求解 能 力 ， 解 题 意 、 关 理 抓
键 点是解 信 息类试题 的常用 方法 ．本 套试 卷注 重在知识 交汇处命 题 ， 函
５“ ． 函数 ）似２Ｉ＋ ∈ 是偶函数” ｂ ０的（ ＝ ＋ ｃ Ｒ） Ｊ 是“－ ”
Ａ ．充分 不必要 条件 Ｃ 充 要条 件 ．
）
Ｂ ．必要 不充分 条件 Ｄ ．既不充 分也不 必要条 件
ａ
Ｃ Ｏ ｘ 一 ＜＜１
．
Ｄ
．
Ｏｘ— ＜＜ Ｌ
ｌ —
ａ
罴 掰 祭
（ ） 文 已知 ） 是定 义 在Ｒ上 的奇 函数 ， ＞ 时 当 ０ ） ＝ ∈（ ，］ ≠ ）有 一 ｏ （。 ，
２ １ —
＜， （ ０则
ｘ ， 不等 厂 ） 解 － 那么 式（＜ ２ ÷的 集是（ ）
厂ｃ ， 映 Ｊ Ⅳ （）则 ］ Ｉ 的个数 为 （
Ａ．１ Ｂ．２
）
Ｃ．３ Ｄ．４
本套试卷严格按照《 考试大纲》 和
课程标准 的 内容 、 围与要 求设置 ， 范 注 重对基础 知识 、 基本 方法 的考 查 ， 持 坚 对 数 学思 想 方法 的考 查 ， 同时体 现 了 能力 立意 的原则 ． 套试 卷涵 盖九 月 本
考 卷 硼 试 调
（ 明： 说 本套试卷满分１吩 ． ５ 考试时间１ ０ ２ 分钟）
四川省成都石室中学2018-2019学年高一数学10月月考试题(含解析)
四川省成都石室中学2018-2019学年高一10月月考数学试题一、选择题（本大题共12小题，共60.0分）1.集合M={a，b，c，d，e}，集合N={b，d，e}，则（）【答案】B【解析】【分析】由集合M,N直接进行交集、并集的运算即可．【详解】∵M={a，b，c，d，e}，N={b，d，e}；∪N=M．故选：B．【点睛】考查列举法的定义，元素与集合的关系，交集、并集的运算，集合间的关系．2.下列各组函数中，表示同一函数的是（）与【答案】D【解析】【分析】通过求定义域，可以判断选项A，B的两函数都不是同一函数，通过看解析式可以判断选项C 的两函数不是同一函数，从而只能选D．【详解】A．f（x）=x+1的定义域为R，是同一函数；0，+∞），g（x）=x的定义域为R，定义域不同，不是同一函数；C．f（x）=|x|，解析式不同，不是同一函数；D．f（x）=x的定义域为R R，定义域和解析式都相同，是同一函数．故选：D．【点睛】考查函数的定义，判断两函数是否为同一函数的方法：看定义域和解析式是否都相同．3.函数y=）【答案】C【解析】【分析】利用换元法结合复合函数单调性之间的关系进行求解即可．【详解】t=x2+4x-3，则y=3t是增函数，求函数y的单调递增区间，等价为求函数设t=x2+4x-3的单调递增区间，函数t=x2+4x-3的对称轴为x=-2，则[-2，+∞）上是增函数，则[-2，+∞），故选：C．【点睛】本题主要考查函数单调递增区间的求解，利用换元法结合指数函数，一元二次函数的单调性关系是解决本题的关键．4.某工厂6年来生产某种产品的情况是：前3年年产量的增长速度越来越快，后3年年产量保持不变，则该厂6年来这种产品的总产量C与时间t（年）的函数关系图象正确的是（）A. B. C. D.【解析】【分析】根据已知，分析函数的单调性和凸凹性，进而得到函数的图象．【详解】∵前3年年产量的增长速度越来越快，故函数为增函数，且为凹函数；又∵后3年年产量保持不变，故函数图象为平行于x轴的线段，故选：C．【点睛】本题考查的知识点是函数的图象，难度不大，属于基础题．5.关于x不等式ax+b＞0（b≠0）的解集不可能是（）D. R【答案】A【解析】【分析】结合a，b的符号，以及一元一次不等式的解法进行判断即可．【详解】若a=0，则不等式等价为b＞0，当b＜0时，不等式不成立，此时解集为∅，当a=0，b＞0时，不等式恒成立，解集为R，当a＞0时，不等式等价为ax，即x，当a＜0时，不等式等价为ax，即x-∞，，故不可能的是A，故选：A．【点睛】本题主要考查不等关系与不等式的解法，结合一元一次不等式的解法是解决本题的关键．6.已知f（x）是R上的偶函数，且当x＞0时f（x）=x（1-x），则当x＜0时f（x）的解析式是f（x）=（）【答案】C【解析】根据f（x）是R上的偶函数，从而得出f（-x）=f（x），可设x＜0，从而-x＞0，又代入解析式即可得解．【详解】∵f（x）是R上的偶函数；∴f（-x）=f（x）；设x＜0，-x＞0，则：f（-x）=-x（1+x）=f（x）；∴x＜0时f（x）的解析式是f（x）=-x（1+x）．故选：C．【点睛】考查偶函数的定义，求偶函数对称区间上解析式的方法．）A.【答案】A【解析】【分析】先利用指数函数y=x的单调性，比较前两个数的大小，再利用幂函数的大小，最后将三个数从大到小排列即可【详解】∵y=x在R∵0，∴故选：A．【点睛】本题考查了利用函数的单调性比较大小的方法，指数函数的单调性、幂函数的单调性，转化化归的思想方法8.若关于x的不等式ax2+bx+3＞0的解集为a，b为常数，则不等式3x2+bx+a ＜0的解集是（）【答案】B【解析】【分析】根据题意利用根与系数的关系求出a、b的值，再化简不等式3x2+bx+a＜0并求出它的解集．【详解】关于x的不等式ax2+bx+3＞0则方程ax2+bx+3=0的两实数根为-1a＜0；由根与系数的a=-6，b=-3，所以不等式3x2+bx+a＜0可化为3x2-3x-6＜0，即x2-x-2＜0，解得-1＜x＜2，所以所求不等式的解集是（-1，2）．故选：B．【点睛】本题考查了一元二次不等式的解法与应用问题，是基础题．9.已知集合B={x|2m-1＜x＜m+1}且A∩B=B，则实数m的取值范围为（）D.【答案】D【解析】【分析】解不等式可求出A，然后由A∩B=B，可知B⊆A，分B=∅，及B≠∅两种情况进行讨论即可求解【详解】-3＜x≤4}，∵A∩B=B，∴B⊆A，若B=∅，则2m-1≥m+1，解可得m≥2，若B≠∅-1≤m＜2则实数m的取值范围为[-1，+∞）故选：D．【点睛】本题主要考查了集合之间的包含关系的应用，体现了分类讨论思想的应用．10.R，则实数a的取值范围是（）B.【答案】B【解析】,则有： B.点睛：本题考查分段函数的单调性，解决本题的关键是熟悉指数函数，一次函数的单调性，确定了两端函数在区间上单调以外，仍需考虑分界点两侧的单调性，需要列出分界点出的不等关系.11.f（x-2）+f（x2-4）＜0的解集为（）B.【答案】C【解析】【分析】先判断函数的奇偶性和单调性，进而得f（x-2）+f（x2-4）＜0⇒f（x-2）＜f（4-x2）⇒x-2＜4-x2，解不等式即可得解.当x＞0，则f（-x）=（-x）2+3（-x）=-x2-3x=-f（x），当f（-x）=（-x）2+3（-x）=x2-3x=-f（x），函数f（x）为奇函数，易知函数f（x）在R上为增函数；f（x-2）+f（x2-4）＜0⇒f（x-2）＜-f（x2-4）⇒f（x-2）＜f（4-x2）⇒x-2＜4-x2，则有x2+x-6＜0，解可得：-3＜x＜2，即不等式的解集为（-3，2）；故选：C．【点睛】本题主要考查了分段函数的奇偶性和单调性的判断及应用，属于基础题.12.设函数f（x）与g（x）的定义域为R，且f（x）单调递增，F（x）=f（x）+g（x），G（x）=f（x）-g（x）．若对任意x1，x2∈R（x1≠x2），不等式[f（x1）-f（x2）]2＞[g（x1）-g（x2）]2恒成立．则（）【答案】A【解析】试题分析：由，，可得.又对于任意，不等式恒成立，即恒成立.即恒成立.可知与具有相同的单调性，同为增函数或同为减函数，由可知，若同为减函数，则为减函数，这与条件中位增函数相矛盾.因而与同为增函数. 故选A.考点：函数单调性的理解和应用，弄清这四个函数之间的关系，理解透彻题目中的条件的含义.【方法点晴】本题主要考查的是抽象函数的单调性问题，首先要从条件中理清四个函数之间的关系，由,可得.将题中的条件,对于任意不等式恒成立，作一定的变形，更要注意有直接的单调性，的单调性要从条件中自己想办法去得出.此题要注重对条件的挖掘，力争正确理解题意.二、填空题（本大题共4小题，共20.0分）13.a=______．【解析】则14.已知函数y=f（x）的定义域是[0，4]______．【答案】（1，3]【解析】【分析】根据f（x）的定义域为[0，4]需满足，x的范围即可．【详解】∵y=f（x）的定义域是[0，4]需满足：解得1＜x≤3；∴该函数的定义域为：（1，3]．故答案为：（1，3]．【点睛】考查函数定义域的概念及求法，已知f（x）定义域求f[g（x）]定义域的方法．15.若直线y=a与函数y=|a x+1-3|（a＞0且a≠1）的图象有两个公共点，则a的取值范围是______．【答案】（0，1）∪（1，3）【解析】【分析】分类讨论：①当0＜a＜1时，②当a＞1时，作出两函数的图象，结合图象由数形结合思想可得解【详解】①当0＜a＜1时，y=|a x+1-3|的图象如图（1）所示,由已知得0＜a＜1，∴0＜a＜1，②当a＞1时，y=|a x+1-3|的图象如图（2）所示，由图可得0＜a＜3，又a＞1，可得1＜a＜3，综合①②得：实数a的取值范围为：（0，1）∪（1，3）．故答案为：（0，1）∪（1，3）【点睛】本题考查函数图象的交点个数，数形结合是解决问题的关键，属中档题．16.已知定义在R上的函数y=f（x），满足f（2）=0，函数y=f（x+1）的图象关于点（-1，0）中心对称，且对任意的负数x1，x2（x1≠x2），则不等式f（x）＜0的解集为____．【答案】（-∞，-2）∪（0，2）【解析】【分析】根据条件判断函数f（x）是奇函数，结合不等式的性质，构造函数h（x）=x2107f（x），研究函数h（x）的奇偶性和取值情况，进行求解即可．【详解】∵函数y=f（x+1）的图象关于点（-1，0）中心对称，∴函数y=f（x）的图象关于点（0，0）中心对称，即函数f（x）是奇函数，对对任意的负数x1，x2（x1≠x2）不妨设x1＜x2，则x12107f（x1）-x22107f（x2）＞0，设h（x）=x2107f（x），则不等式等价为h（x1）＞h（x2），且函数h（x）是偶函数，即h（x）在（-∞，0）上为减函数，∵f（2）=0，∴h（2）=22107f（2）=0，则当x＞0时，不等式f（x）＜0等价为不等式x2107f（x）＜0，即h（x）＜0当x＜0时，不等式f（x）＜0等价为不等式x2107f（x）＞0，即h（x）＞0，当x＞0时，由h（x）＜0得0＜x＜2，当x＜0时，由h（x）＞0得x＜-2，即f（x）＜0的解集为（-∞，-2）∪（0，2），故答案为：（-∞，-2）∪（0，2）．【点睛】本题考查的是函数单调性，奇偶性的综合应用，解题中构造函数h（x）=x2107f（x）是解决本题的关键，属于中档题.三、解答题（本大题共6小题，共70.0分）17.已知集合A={x|x2-4x-C={x|x＜m}．（1）求A∩（∁R B）；（2）若A∩C≠A且B∩C≠∅，求实数m的取值范围．【答案】（1）{x|-1≤x≤0或2≤x≤5}；（2）0＜m≤5【解析】【分析】（1）解不等式求出集合，结合交集补集的定义进行计算即可．（2）根据集合交集关系确定m的范围即可．【详解】（1）∁R B={x|x≥2或x≤0}∴A∩（∁R B）={x|-1≤x≤0或2≤x≤5}（2）由A∩C≠A，则m≤5由C∩B≠∅，则m＞0 ，综上：0＜m≤5【点睛】本题主要考查集合的基本运算，求出集合的等价条件是解决本题的关键．比较基础．18.（1（2）求二次函数f（x）=-x2+4ax+1（a＞0）在区间[0，2]的最大值．【答案】（1）π（2）f（x）max【解析】【分析】（1）根据题意，由指数幂的运算性质可得原式π（2）根据题意，分析函数f（x）的对称轴，据此讨论a的取值范围，求出函数的最值，分析即可得答案．【详解】（1（2）根据题意，对于函数f（x）=-x2+4ax+1，其对称轴x=2a＞0，开口向下.当0＜2a＜2即0＜a＜1时，f（x）max=f（2a）=4a2+1，当2a≥2即a≥1时，f（x）max=f（2）=8a-3，综合可得：f（x）max【点睛】本题考查二次函数的性质以及指数幂的计算，（2）中注意讨论a的范围，属于基础题．19.某工厂生产甲、乙两种产品所得利润分别为P和Q（万元），它们与投入资金m（万元）的关系有如下公式：200万元资金投入生产甲、乙两种产品，并要求对甲、乙两种产品的投入资金都不低于25万元．（Ⅰ）设对乙种产品投入资金x（万元），求总利润y（万元）关于x的函数关系式及其定义域；（Ⅱ）如何分配投入资金，才能使总利润最大，并求出最大总利润．【答案】(Ⅰ)答案见解析；(Ⅱ)答案见解析.【解析】分析：，结合题方法结合二次函数的性质可求总利润y的最大值．详解：,由，解得所以函数的定义域为因，所以，.点睛：本题考查利用数学知识解决实际问题，考查函数的最值，正确建立函数解析式是关键．20.a∈R）．（1）讨论函数f（x）的奇偶性，并说明理由．（2f（x）在区间[1，+∞）上的单调性，并用函数单调性定义给出证明．【答案】（1）见解析；（2）见解析【解析】分析】（1）根据题意，求出函数的定义域，分a=0与a≠0两种情况讨论函数的奇偶性，即可得答案；（2）根据题意，设1≤x1＜x2，由作差法分析可得结论．【详解】（1{x|x≠0}，当a=0时，f（x）=，有f（-x）=-f（x），则函数f（x）为奇函数；当a≠0f（-x）=ax2有f（x）≠f（-x）且f（-x）≠-f（x），则函数f（x）是非奇非偶函数；（2）根据题意，函数f（x）在[1，+∞）上为增函数；证明：设1≤x1＜x2，则f（x1）-f（x2）=（ax12-（ax22=（x1-x2）[a（x1+x2，又由1≤x1＜x2，则（x1-x2）＜0，[a（x1+x2）＞11，则有f（x1）-f（x2）＜0，则函数f（x）在[1，+∞）上为增函数．【点睛】本题考查函数的奇偶性与单调性的判断与证明，注意分析a的取值范围，属于基础题．21.设函数f（x）=|x-a|+x，其中a＞0．（1）当a=3时，求不等式f（x）≥x+4的解集；（2）若不等式f（x）≥x+2a2在x∈[1，3]恒成立，求实数a的取值范围．【答案】（1）{x|x≤-1或x≥7}；（2）【解析】【分析】（1）分情况去绝对值解不等式可得；（2）由题意可得：|x-a|≥2a2在x∈[1，3]恒成立，再按照a与区间[1，3]的关系分3种情况讨论．【详解】（1）当a=3 时，不等式f（x）≥x+4，即|x-3|+x≥x+4，即|x-3|≥4，x≥7x≤-1故不等式f（x）≥x+4 的解集为{x|x≤-1或x≥7}（2）由题意可得：|x-a|≥2a2在x∈[1，3]恒成立，①当a＜1时，则x-a＞0，∵x-a≥2a2在x∈[1，3]上恒成立，∴1-a≥2a2，解得②当1≤a≤3时，∵|x-a|≥2a2在x∈[1，3]上恒成立，∴当x=a时，0≥2a2，解得a=0舍去；③当a≥3时，则x-a＜0，∴-x+a≥2a2在[1，3]上恒成立，∴-3+a≥2a2，此不等式无解；综上，【点睛】本题考查了绝对值不等式的解法，考查了分类讨论的思想，属中档题．22.定义域为R的函数f（x）满足：对于任意的实数x，y都有f（x+y）=f（x）+f（y）成立，且当x＜0时，f（x）＞0恒成立，且nf（x）=f（nx）．（n是一个给定的正整数）．（1）判断函数f（x）的奇偶性，并证明你的结论；（2）证明f（x）为减函数；若函数f（x）在[-2，5]上总有f（x）≤10成立，试确定f（1）应满足的条件；（3）当a＜0时，解关于x【答案】（1）见解析；（2）f（1[-5，0）；（3）见解析【解析】【分析】（1）利用函数奇偶性的定义，结合抽象函数关系，利用赋值法进行证明（2）结合函数单调性的定义以及最值函数成立问题进行证明即可（3）利用抽象函数关系，结合函数奇偶性和单调性定义转化为一元二次不等式，讨论参数的范围进行求解即可【详解】（1）f（x）为奇函数，证明如下；由已知对于任意实数x，y都有f（x+y）=f（x）+f（y）恒成立．令x=y=0，得f（0+0）=f（0）+f（0），所以f（0）=0．令y=-x，得f（x-x）=f（x）+f（-x）=0．所以对于任意x，都有f（-x）=-f（x）．所以f（x）是奇函数．（2）设任意x1，x2且x1＜x2，则x2-x1＞0，由已知f（x2-x1）＜0，又f（x2-x1）=f（x2）+f（-x1）=f（x2）-f（x1）＜0，得f（x2）＜f（x1），根据函数单调性的定义和奇函数的性质知f（x）在（-∞，+∞）上是减函数．所以f（x）在[-2，5]上的最大值为f（-2）．要使f（x）≤10恒成立，当且仅当f（-2）≤10，又因为f（-2）=-f（2）=-f（1+1）=-2f（1）,所以f（1）≥-5．又x＞1，f（x）＜0，所以f（1）∈[-5，0）．（3，∴f（ax2）-f（a2x）＞n2[f（x）-f（a）]．所以f（ax2-a2x）＞n2f（x-a），所以f（ax2-a2x）＞f[n2（x-a）]，因为f（x）在（-∞，+∞）上是减函数，所以ax2-a2x＜n2（x-a）．即（x-a）（ax-n2）＜0，因为a＜0，所以（x-a）（0．讨论：0，即a＜-n时，原不等式的解集为{x|x x＜a}；，即a=-n时，原不等式的解集为{x|x≠-n}；＜a0，即-n＜a＜0 时，原不等式的解集为{x|x＞a或x．【点睛】本题主要考查抽象函数的应用，利用函数奇偶性和单调性的定义，利用赋值法是解决本题的关键．考查学生的转化能力，综合性较强，有一定的难度．。
- 1、下载文档前请自行甄别文档内容的完整性，平台不提供额外的编辑、内容补充、找答案等附加服务。
- 2、"仅部分预览"的文档,不可在线预览部分如存在完整性等问题,可反馈申请退款(可完整预览的文档不适用该条件!)。
- 3、如文档侵犯您的权益，请联系客服反馈,我们会尽快为您处理(人工客服工作时间：9:00-18:30)。
成都石室中学高2019届文科班2018年11月月考试卷“石桥古纸”属唐代造纸工艺，它以普通的构树皮为原料，利用丰富的地下水，在天然岩洞里设槽造纸。
它精选生长三年的常绿构树，通过剥皮、选料、漂洗、抄纸等十多道手工工序方可出纸。
目前，我国手工纸生产以青藏区的狼毒纸、四川夹江的竹纸、安徽泾县的宣纸等地为中心，逐渐沦为一个个孤岛。
据上述材料，完成1-3题。
1.造成目前我国手工纸业生产逐渐沦为一个个孤岛的主要影响因素是A.互联网等信息化的迅速发展对无纸化的冲击B.手工造纸工序复杂、劳动强度大、经济效益差C.传统古建筑的修缮及珍藏古典书籍的修补D.手工纸在特种印刷、特殊包装等方面广泛应用【解析】互联网等信息化的发展对机制纸的冲击最大，故A错误；手工纸在书画创作、文物修复、特种印刷、特殊包装方面仍有不可替代的用途，有稳定的市场需求，故C和D错误；纯手工造纸工序复杂、劳动强度大、经济效益差导致手工纸的生产缓慢、产量小，且部分纸张有明显的地域特征，导致我国手工纸业生产逐渐沦为一个个孤岛，故B对。
2. “石桥古纸”的传统工作作坊，保存最多的地区最可能在A.黄土高原B. 内蒙古高原C. 云贵高原D.华北平原【解析】古法造纸“利用丰富的地下水，在天然岩洞里设槽造纸”，说明这里地下水源充足，多天然洞穴；“它精选生长三年的常绿构树”，说明这里林木较多，以常绿植被为主，故云贵高原符合，C对。
（云贵高原为南方地区，天然植被以常绿阔叶林为主；为喀斯特地区，地形崎岖，多天然岩洞；地表水容易渗漏，地下水资源丰富等）。
3.藏区的经书在寺庙往往能保存很久，其主要原因有①海拔高，太阳紫外线强烈②高原气候干燥，氧气缺乏③所采用的手工纸张毒性强④存放地点人迹罕至A.①②B. ③④C. ②③D. ①④【解析】藏区的手工纸主要是狼毒纸，用狼毒根制成的纸，虽经过漂洗加工，传统制法仍含有毒性，有利于防虫蛀和鼠咬等生物破坏，故③对；高原干燥，有利于防止纸张潮湿腐坏，氧气含量较低，有利于防止文物氧化带来的损害，故②对；太阳紫外线强烈，会导致经书老化、变形、字迹模糊等，故①错；经书均收藏在寺庙里，保存条件一致，故④错。
2018年7月6日我国对美关税反制措施正式实施，对进口自美国的大豆加征25%关税，美国大豆进口价格大幅上涨，此后，我国对优质巴西豆的进口量同比大幅增长。
大豆为每年春季播种，当年秋季收获。
下图为巴西大豆通过海运到我国的线路图，据上述材料，完成4-6题。
4. 为监测大豆生长状况，宜采用的地理信息技术是A.数字地球B.地理信息技术C.全球定位系统D. 遥感技术【解析】地理信息技术主要用于分析、解读地理信息，全球定位系统在于获得经纬度、海拔高度，实现空间定位；遥感技术用于获取信息，“监测”即为信息的获取环节，故D对。
5.研究发现，巴西大豆的平均蛋白质含量普遍高于美国，其原因可能是A.昼夜温差更大B.大豆的生长周期更长C.大豆在成熟期间气温较高D.气候湿热，病虫害较少【解析】美国大豆产区以温带大陆性气候为主（巴西大豆产区以热带草原气候为主），气候较巴西干旱，故昼夜温差更大，A错误；农作物生长周期的长短跟作物品种和气温有关，气温越低，生长周期越长，越有利于有机质积累，B错误；巴西纬度低，大豆在成熟期间气温较高，有利于农作物进行光合作用，合成有机质，故C正确；气候湿热，有利于病虫类动物的生长和产卵，病虫危害更多，故D错误。
6.巴西大豆在运输过程中，沿途不可能出现A.在①处船只顺风顺水B.在②处停靠，附近林木高大C.在③处看到火山喷发D.在④处停靠，附近海鸟成群【解析】①位于东北信风带和北赤道暖流流经区域，且航行为自东向西，故顺风顺水，A对；②位于南半球盛行西风带，冬半年南北温差更大，风大浪高，为适应环境，房屋、林木大多矮小，B错；③位于美洲板块和南极洲板块交界处，多火山地震，C对；④位于索马里半岛夏半年盛行离岸风，形成季节性渔场，鱼类繁多，海鸟食物足，D对。
“一带一路”是中国与世界各国互联互通互利共赢的大战略，是中国优秀文化传统的继承和弘扬。
2016年“十三五规划”提出将建设北京到台湾间的高铁。
其中台海通道是一项连接大陆与台湾的工程重要设想，它将可以打开“一带一路”的东方门户。
早在1998年两岸学者对其进行可行性探讨、预测和论证后，提出了北线、中线、南线的台海通道三方案，有不少专家提出了桥梁、隧道结合的方式。
据此完成7-8题。
7.大陆专家多倾向于三方案中的北线方案，原因最可能是北线A．台风影响小B．线路较短C．洋流较弱D．气温较高【解析】7.原因最可能是北线线路较短(通过图可以看出)，B对。
建设海底隧道，洋流、台风、气温主要影响海面区域，不是主要影响因素A、C、D错。
8.台海通道中采用桥隧结合方式，如右图中段采用海底隧道的原因可能是A．建设成本低、难度小B．保证台湾海峡的通航能力C．便于旅客欣赏风景D．缩短通行距离和时间【解析】隧道的优势在于位于海底，保证主航道的通行能力D对。
建设成本较高、难度较大，A错。
在隧道中，不便于旅客欣赏风景，C错。
对通行距离不会缩短，D 错。
一队登山运动爱好者5月1日从秘鲁古城库斯科(图b)出发，乘车沿崎岖山路到达威尼坎加国家公园，然后开始徒步登山，约10公里后到达海拔5050米的彩虹山(图a)，附近可见高耸雪山。
一名队员站在蓝天白云下享受被“彩虹”包围的感动，且面向正北拍照留念，据此完成9-11题。
9.彩虹山地貌景观近年来才被人们发现，其主要原因不可信的是A．位置偏僻，交通不便B．高山深处，人类活动较少C．受气候变暖影响，冰雪消融加快D．海拔高，物理风化作用强【解析】9.据图中经纬度判断可知，彩虹山地处南美洲安第斯山脉区，地处低纬度的热带地区，位置偏僻，交通不便，人类活动较少，不易被发现；且据材料可知海拔5050米高，曾被冰雪覆盖，后受气候变暖影响，近年来冰雪融化后才被发现；此处海拔高，风化作用强，则易被侵蚀而容易发现，所以D不正确。
10.彩虹山地貌景观形成的主要过程最可能是A．外力侵蚀一水平挤压一地壳下沉一外力沉积B．地壳抬升一外力侵蚀一水平挤压一外力沉积C．外力沉积一水平挤压一地壳抬升一外力侵蚀D．水平挤压一地壳下沉一外力沉积一外力侵蚀【解析】10.据图可知，沉积岩层上拱，可判断为背斜部位，据图可知为砂岩，属于沉积岩，说明当地早期为沉积环境，长时期堆积了较厚的不同颜色的砂岩；后受内力作用挤压形成褶皱并抬升为山地；后受外力作用剥蚀出露地表，所以C正确。
11.登山队员拍照时，当地的时间大约为A．9时B．12时 C. 15时D．18时【解析】11.据材料可知，该队员面向正北拍照留念，据图中影子的方向位于东南方向，则可确定太阳方位为西北方向照射；材料中提到拍照日期为5月1日，太阳直射北半球，全球除极昼极夜区外各地均东北日出西北日落,正午太阳位于正北方，据图可知此时影子较短(太阳高度较大18时太阳高度较小)且太阳位于西北方向，因此可判断时刻大约为下午15时左右较为合理。
36.(24分)阅读下列图文材料，回答问题。
材料一近年来，云南省七彩高原特色农业发展十分迅速。
昆明郊区一些乡村由以粮食、蔬菜种植为主已逐渐转变为专门的花卉种植，使云南成为我国最大的鲜切花生产基地，所产鲜花供给全国各地。
材料二世界某咖啡连锁企业的原料实行全球化采购，我国云南省普洱市的小粒种咖啡也是其原料之一。
普洱市小粒种咖啡正在迅速“膨胀”，全省种植面积占全国面积的70%，确立了云南咖啡在国内的主导地位。
小粒种咖啡为多年生常绿灌木或小乔木，适宜生长在海拔800-1800米、土壤排水良好、年均温19-20℃的温暖环境中.材料三图1为云南省部分地区等高线地形图和普洱市辖区范围示意图，图2为某城区用地示意图。
(1)分析昆明市郊区种植农作物品种变化的主要原因及条件。
（4分）【参考答案】（1）生活水平不断提高，花卉市场需求量不断增大（2分）；交通运输条件得到改善（或航空、高速公路得到发展）（2分）；花卉保鲜技术不断提高（2分）。
【解析】（1）本题考查农业区位因素的变化。
市场决定了农业生产的类型和规模。
随着生活水平不断提高，花卉市场需求量不断增大；交通运输条件得到改善和花卉保鲜技术不断提高，使昆明市郊区种植农作物品种发生变化。
(2)分析该区域地势起伏、地势高低及变化对普洱市小粒种咖啡树生长的有利影响。
（6分）【参考答案】地势起伏较大，土壤排水良好（2分）；海拔（地势）较高（或多在800-1800米之间），满足咖啡树生长对海拔的要求（2分）；北部高大山地阻挡冬季寒冷气流南下，气温较高，少低温冻害（2分）。
【解析】根据材料二提示“小粒种咖啡树适宜生长在海拔800-1800m、年均温19-20℃、土壤排水良好等环境中”,再从图1所示区域地形起伏、地势高低及变化来分析，对对咖啡树生长的具体有利影响，根据图例信息，可知该区域地形起伏大，有利于排水；纬度较低，海拔较高，能够满足年均温19-20℃的条件；地势北高南低，阻挡冬季寒冷气流南下，受低温冻害影响小。
(3)该企业拟将图2中A、B两处作为咖啡店的备选地，请分别说出A、B处的两点区位优势。
(要求：两处回答的区位优势不重复，每处回答超过两点的按前两点计分)(8分)【参考答案】A处：位于道路交叉点（主要交通干道），交通便利；位于商业用地中心（街角十字路口），人流量大(消费市场广阔)；位于城市中心附近，居民消费能力强。
B处：距离市中心较远，租金便宜；靠近绿化用地，环境优美；位于主要道路的一侧，交通便利。
(8分) 【解析】此题注意审题，对比A、B两地的位置，说出A、B处的两点区位优势，同时不能重复，A处位于市中心，B处为城市边缘地区，企业布局的区位条件主要从交通、地租、市场、环境、劳动力等方面来分析，结合两地地理位置不同，对照找出各自优势。
(4)你是否赞成在普洱市大规模种植小粒种咖啡？请表明态度，并说明理由。
（6分）【参考答案】赞同。
该地种植小粒咖啡的自然环境优越（2分）；与世界某咖啡连锁企业合作，国内国际消费市场广阔（2分）；能带动与咖啡相关产业的发展；能促进地区经济发展，增加农民收入，提高农民生活水平。
（咖啡种植带来的好处，任答1点得2分，共计6分）不赞同。
该地为喀斯特地貌，土层浅薄，土壤肥力低（2分）；地处西南山区，交通运输不便（2分）；地处偏远山区，距离主要消费市场远（2分）（有利区位条件，任意2点得4分）；种植使用农药、化肥，会导致土壤、地下水污染加重；大量垦殖，导致植被破坏，水土流失加剧；破坏地表原生植被，导致生物多样性减少。
（咖啡种植带来的不利影响，任答1点得2分，共计6分）【解析】本题主要考查种植小粒咖啡对当地的影响，为开放性试题，可自选角度作答。
若赞同，从当地有利于种植咖啡的农业区位因素（自然条件、市场前景）以及种植该种农作物对当地带来的有利影响（带动产业、增加收入等）入手分析。