机械厂装配车间输送带传动装置设计新版D9
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机械
课
程设
计说
明书
课程名称: 机械设计机械厂装配车间输送带传动装置设计: 题目名称
学生学院: 材料学院材料
专业班级: 10-3班学: 14105417
号 : 学生姓名尹圣楠
目录
机械设计任务书
机械课程设计任务书1························································································
机械课程设计第一阶段
1.1、确定传动方案2·····························································································
1.2、电动机选择 3·······························································································
1.3、传动件的设计5····························································································
机械课程设计第二阶段
2.1装配草图设计第一阶段说明17·········································································2.2轴的设计及校核17·························································································
2.3滚动轴承的选择21·························································································
2.4键和联轴器的选择22······················································································
机械课程设计第三阶段
3.1、减速器箱体及附件的设计23·········································································3.2、润滑方式、润滑剂及密封装置的选择24·························································
机械课程设计小结
4.1、机械课程设计小结 25·················································································
附1:参考文献
机械课程设计任务书一、课程设计的内容机械厂装配车间输送带传动装置设计(新版).题目D9为参考传动方案。。图2 图1)设计一带式运输机传动装
置(见
D
vF动力及传动装置图1 带式运输机传动装置图2 参考传动方案
二、课程设计的要求与数据1、设计条件:由输送带传送机器的零、部件;1)机器功用
℃;352)工作情况单向运输、轻度振动、环境温度不超过
输送带运动速度误差不超过5%;3)运动要求
小时;16 10年,每年350天,每天4)使用寿命一年小修;两年大修;5 )检修周期
6 )生产批量单件小批量生产;- 1 -
7)生产厂型中型机械厂
、设计任务 2 1)设计内容1、电动机选型;2、带传动设计;3、减速器设计;4、联轴器选型设计;5、其他。
2)设计工作量1、传动系统安装图1张;2、减速器装配图1张;3、设计计算说明书一份。
3、原始数据
主动滚筒扭矩(N·m):1000
0.6 :)主动滚筒速度(m/s 主动滚筒直径(mm):340-2 -
- 3 -
'n T=1000 N·m,卷筒转速:上式中:工作机的扭矩'n=33.72
?minr//(3.14?/340)D?60?1000?0.6?n'?6?1000v
= 0.96 η1.V带传动效率: 1 44
=0.99η4对深沟球轴承传动效率:2.222 = 0.97η级圆柱齿轮传动效率:对3.28 3
= 0.99 η联轴器的传动效率:4. 4
= 0.96
η滚筒传动效率:5. 5 24???????。
51423?=0.82
把上述值代入后得:
33.72?1000?P=4.31KW
??P=4.31kW
0.829550?
2、电动机的输入功率P的计算:
1.2k?,故本题中起动系数d?4.31?1.2kP??P?d
1500r/min
得,Y系列查表16-2P=5.172KW Y132S4-2-B3型电动机的具体牌号为:2.2
/额定转矩:5.5kW; 额定转矩:2.2; 最大转矩额定功率为:、计算总传动比并确定传动比3、计算总传动比1)i =1440r/min 在上面已经确定了电机满载转速为n i为传动装置的总传动比
n42.70 ?i?i?1440/33.72 'n
)、传动比的分配2 i?i?i10总取带传动比为i i?ii? =2 而023112ii(而
2312
?? kWP?4.72????kW4.91?0.99?0.97?P?P4.72?23221
?? kW4.53P?????kW4.534.72??0.99?0.97?PP?33223
、各个轴扭矩的计算4)??m65.127NT???m65.127720?NnT?9550P/?9550?4.91/
1111
??mTN?329.94??m?329.94N/136.62/T?9550Pn?9550?4.722
222
??mN?T1151.18??m/1151.18?N?n?95504.53/37.589550T?P3
333