寒假作业2

合集下载

寒假作业2

寒假作业2
2
A
B
C
D 单位:cm
E
16
34 54 76 图2
12
物理(60 分钟) A.它们都是一种计时仪器
腊月十七上午
B.它们都使用 10V 以下交流电压 运动的描述 2 1.如图所示,一物体沿三条不同的路径由 A 运动 到 B,下列关于它们的位移 的大小说法正确的是( A.沿Ⅰ较大 B.沿Ⅱ较大 C.沿Ⅲ较大 D.一样大 2.路程和位移的关系正确的是( ) 9. 一物体以 5 m/s 的速度垂直于墙壁碰撞后, 又以 5m/s 的速度反弹回来.若物体与墙壁作用时间 为 0.2 s,取碰撞前初速度的方向为正方向,那 么物体与墙壁碰撞的过程中,物体的加速度为 ( ) ))
11 .在匀速直线运动中,一个物体的平均速度是 10m/s, 他在各段的平均速度大小是______ m/s, 瞬时速度是______ m/s. 12. 一辆汽车在一条直线上行驶, 第 1 s 内通过 8m, 第 2s 内通过 20m,第 3s 内通过 30m,第 4s 内通过 10m,则此汽车最初 2 s 内的平均速度 是______ m/s, 中间 2 s 内的平均速度是______ m/s,全部时间内的平均速度是______ m/s. 13.如图所示是一个物体向东运动的速度图象.由 图 可 知 在 0 ~ 10s 内 物 体的 加 速 度大 小 为 ________,方向是________,在 10 s~40 s 内 物体的加速度为________; 在 40s~60s 内物体 的 加 速 度 大 小 是 ________ , 方 向 是 ________.
2 2
C.它们都使用 220V 交流电压 D.它们分别使用 10V 以下和 220V 交流电压 8.打点计时器打点的周期,决定于( A.交流电压的高低 B. 交流电的频率 C.永久磁铁的磁性强弱 D. 振针与复写纸间的距离. )

钦州二中高三寒假作业2

钦州二中高三寒假作业2

钦州二中2013年秋季学期高三语文寒假作业(二)出题人:黎廷宪审题人:刘凝思一、基础题。

(12分,每小题3分)1.下列词语中加点的字,每对读音都不相同....的一组是A.肄.业/肆.扰懈.怠/亵.渎押解./浑身解.数B.聒.躁/恬.静咯.血/炮烙.中.肯/一语中.的C.戳.穿/杀戮.希冀./契.约咀嚼./咬文嚼.字D.国粹./荟萃.悭.吝/信笺.拓.本/落拓.不羁2.下列各句中,加点词语使用正确的一句是A.下半年,部分银行严格控制甚至暂时停止购房贷款的发放,“房贷荒”开始在各地不同程度地出现,并有逐步漫延..的趋势。

B.基层法院的工作人员深入乡村,与村干部一起耐心调解村中的赡养纠纷、宅基地纠纷等,消融..了村民问的矛盾、嫌怨,受到村民的欢迎。

C.美国“监控门”事件不断升级,这边中国、俄罗斯等国的批评之声未落,那边英、德等美国铁杆盟友又发表声明谴责,这令美国“老大哥”左支右绌....,狼狈不堪。

D.广西南宁“科技·时尚”产品展上,“全景LED灯”“电子鱼”“钻石U盘”等一系列时尚感十足的科技产品纷纷亮相,着实让观众应接不暇....。

3.下列各句中,没有语病的一句是A.搞清楚工人和企业主这些微观个体在劳动力市场上搜寻和匹配的行为,对于了解失业率的决定因素,解释工资的形成机制,制定降低失业率的政策都十分重要。

B.谁都知道,民主与法治是一个长期的过程,但在经济攻坚之后,现在确实已经到向新目标攻坚的时候了。

C.开征房产税,提高房产持有的成本,现阶段更是可以起到打击投机、打击囤积居奇作用,把市场上种种非真实需求的泡沫挤掉,从而对平抑房价起到立竿见影的效果。

D.在部分舆论看来,本属于全民娱乐、全民福利的春晚,用广告践踏公众眼球给公众添堵,使春晚这台公共节目丧失了“公共性”,挑战的是国家电视台的职业操守。

4.下列各句中,,标点符号使用正确的一句是A.阿拉法特是否因中毒而死?如果是的话,投毒者是以色列情报人员?这是巴勒斯坦反对派人士?有的疑问可通过尸检解答,而有的则可能成为永远的谜。

部编版九年级上册语文寒假作业2(含答案解析)

部编版九年级上册语文寒假作业2(含答案解析)

部编版九年级上册语文寒假作业21.下列句子中没有语病的一项是()A.著名作家吴伯箫的籍贯是山东莱芜人,他的散文大多以小见大,善于从平凡中挖掘出深刻的内涵。

B.党的十九大会议上,众代表积极讨论并认真听取了李克强总理作的政府工作报告。

C.通过《经典咏流传》节目的播出,让观众在一众唱作歌手的演绎中领略诗词之美。

D.莲花台风景区成为我省继崆峒山、麦积山、敦煌鸣沙山风景区后第四个国家级风景名胜区。

2.下列句中没有语病的一项是()A.中国不仅是“一带一路”建设的倡议者,更是负责任的参与者、有担当的行动者。

B.通过参加这次活动,使我对中国博大精深的书法艺术产生了浓厚的兴趣。

C.《红海行动》在影片质感和人物情节方面突破了一大步的跨越。

D.防止校车安全事故不再发生是个系统工程,需要多方面、多领域齐心协力完成。

3.下列句子中,没有语病的一项是()A.《奔跑吧,兄弟》综艺节目深受欢迎的主要原因是其形式新颖、内容丰富造成的。

B.读书切忌不能偷懒,只有勤奋好学,脚踏实地,才能获取知识。

C.经探索发现,火星上不仅有四季、大气和重力,还有水、冰、河道的痕迹。

D.这次大赛掀起了我校同学们书写汉字,激发了他们对汉字、书法等传统文化的兴趣。

4.下列句子没有语病的一项是()A.感动中国人物钱伟长不仅是当代科技工作者的典范,乐于帮助其他人,因此我们要向他学习。

B.“最美妈妈”吴菊萍,奋不顾身托住小生命,是近年来涌现出的英雄模范人物之一。

C.日本能否在短时间内消除核泄漏带来的严重污染,依赖于科学技术及政府的重视。

D.通过音乐名人高晓松案醉驾入刑的宣判执行,使酒后驾车的人越来越少了。

5.下列各句中有语病的一项是()A.我并不是否认你学习的进步,而是说你应该制定更合理的学习计划。

B.通过自我风采展示活动,同学们了解了你,你对自己和同学也有了更深入的认识。

C.在中华文明悠久的历史中,爱国主义精神一直是中华民族得以发展、生存和凝聚的动力。

D.优化能源结构是推动我国能源革命的本质要求和经济社会转型发展的迫切需要。

七年级英语冀教版 寒假作业(2)

七年级英语冀教版 寒假作业(2)

寒假作业(2)一、单选题1.—_____is your mum?—She is fine. Thank you.A. WhereB. HowC. WhatD. Who2.—Is her name Kate?—_____.A. Yes, she isB. No, she isn'tC. Yes, it'sD. No, it isn't3.I have _____ eraser and five _____ in my pencil box.A. a; pencilsB. a; pencilC. an; pencilsD. an; pencil4.—_____ that an English girl?—_____, she's a Chinese girl.A. Is; YesB. Is; NoC. Are; NoD. Are; Yes5.—Sandy, is Mr. Li in the teachers' office now?—I am not sure. He _____ be there.A. mustB. can'tC. mustn'tD. may6.The students do experiments(实验) in the _____. They learn a lot there.A. playgroundB. labC. libraryD. office7.The boy is from _____. He's _____.A. Chinese; ChinaB. China; ChineseC. Chinese; ChineseD. China; China8.—______ going shopping tomorrow?—Good idea.A.How aboutB.WhatC. What'sD.How9.Six and four is _______.A. nineB.tenC. elevenD. twelve10.—Sally, what about going to the classroom?—_________.A. You're welcomeB. Nice to meet youC. Have a good dayD. That sounds good二、连词成句1.is, classmate, my, Nick______________________________________.2.to, welcome, class, our______________________________________3.she, from, is, Japan, not______________________________________4.very, thank, much, you______________________________________!5.from, are, Shanghai, you____________________________________________?三、完形填空Hello! 1 name is Li Ying. I'm twelve. I'm from Kunming. Now I'm in Beijing No.14 Middle School. I'm 2 Class Five, Grade Seven. Miss Gao 3 my English teacher. She is 4 old teacher. I have a pen, a ruler and two 5 in my pencil box. Liu Ping is in Grade Seven, too. 6 is from Guangzhou. She is my good 7 . We are in 8 same class. Now she can 9 English well. I think she is a good girl. Look! 10 is that? She is Liu Ping.1.A.I B.My C.Your D.Me2.A.from B.to C.not D.in3.A.is B.are C.am D.be4.A.a B.an C.good D./5.A.buses B.desks C.schoolbags D.pencils6.A.He B.His C.She D.Her7.A. friend B. teacher C. student D.mom8.A.these B.the C.an D.a9.A. spell B. speak C.help D.see10.A. How B.What C.Where D.Who四、阅读理解Tom and Tony are classmates. Tom is 12 and Tony is 13 years old. They are in Class 3, Grade 7 in No.33 Middle School.One day, they can't write their names well. Their English teacher Mr. Green is angry(生气的) with them. He asks them to write their names a hundred times(一百遍). Tony cries(哭). The teacher says, "Why are you crying?"Tony says, "Tom's name is Tom Hill. He can finish writing his name1.How old is Tom?A.10.B.11.C.12.D.13.2.Which class is Tony in?A.Class One.B.Class Two.C.Class Three.D.Class Seven.3.Why is their English teacher angry with them?A.They are late for class.B.They can't do their homework.C.They can't write their names well.D.They can't read their names well.4.What does Tony do after Mr. Green asks him to write his name a hundred times?A.He is happy.B.He cries.C.He goes home.D.He writes well.A.I am slow.B.Tom is fast.C.His name is too long.D.But my name is too long.五、写作假如你是Peter,你很想用英文给你的网友Jack写一封信来介绍你的初中生活,请根据思维导图完成信件。

高三数学寒假作业(2)及答案

高三数学寒假作业(2)及答案

有一项是符合题目要求的)1.已知集合(){}|30M x x x =-<,{}|2N x x =<,则MN =( )A .()0,2-B .()2,0C .()3,2D .()3,2- 2.已知命题2:,210,p x R x ∀∈+>则( ) A .2:,210p x R x ⌝∃∈+≤ B .2:,210p x R x ⌝∀∈+≤ C .2:,210p x R x ⌝∃∈+<D .2:,210p x R x ⌝∀∈+<3.向量a =(1,-2),b =(6,3),则a 与b 的夹角为( ) A .60︒ B .90︒ C .120︒ D .150︒ 4.在△ABC 中,角A 、B 、C 的对边分别为a 、b 、c , 已知A =3π, a =3, b =1,则c = ( )A .1B .2C .3—1D .3 5.已知两条直线,m n ,两个平面,αβ,给出下面四个命题: ①//,m n m n αα⊥⇒⊥ ②//,,//m n m n αβαβ⊂⊂⇒ ③//,////m n m n αα⇒ ④//,//,m n m n αβαβ⊥⇒⊥其中正确命题的序号是( ) A .①③ B .②④ C .①④ D .②③6.函数)sin()(ϕω+=x x f (,0,02)x R ωϕπ∈>≤<的部分图象如图,则 ( )A .ω=2π,ϕ=4πB .ω=3π,ϕ=6πC .ω=4π,ϕ=4πD .ω=4π,ϕ=45π131oy x7.三个学校分别有1名、2名、3 名学生获奖,这6名学生排成一排合影,要求同校的任两名学生不能相邻,那么不同的排法有( ) A .36种B .72种C .108种D .120种8.如图,设点P 为△ABC 内一点,且AP →= 25 AB → + 15AC → ,则△ABP 的面积与△ABC 的面积之比是( ) A .2:5 B . 1:5C . 1:4D . 1:39.已知{(,)|6,0,0}x y x y x y Ω=+≤≥≥,{(,)|4,0,20}A x y x y x y =≤≥-≥,若向区域Ω上随机投一点P , 则点P 落入区域A 的概率为( ) A .31 B .32 C .91 D .92 10.已知双曲线12222=-y ax 的一条准线与抛物线x y 42-=的准线重合,则该双曲线的离心率为 ( ) A.22B.2C.2D.21二、填空题:本大题共7个小题,把答案填在题中横线上.11.若a =)1,8(-,b =)4,3(,则a 在b 方向上的投影是 ; 12.复数ii++12的共轭复数是 . 13.已知x 、y 满足y x z k y x x y x 420,305+=⎪⎩⎪⎨⎧≥++≤≥+-且的最小值为-6,则常数k= . 14.若)2,0(,135)4sin(πααπ∈=-且,则)4cos(2cos αα+值为 .15.如图,函数)(x f y =的图象在点P 处的切线方程是8+-=x y ,则)5()5(f f '+= .16.若1)2(33)(23++++=x a ax x x f 有极大值和极小值,则a 的取值 范围是____________17.下列程序执行后输出的结果是 . i =11 s=1 DO s=s* i i = i -1 LOOP UNTIL i <9 PRINTs END三、解答题:本大题共4小题,解答应写出文字说明、证明过程或推演步骤.18.已知函数f(x)=2cosx(sinx-cosx)+1,x ∈R. (1)求函数f(x)的最小正周期T ; (2)求函数f(x)的单调增区间;(3)求函数f(x)在区间⎥⎦⎤⎢⎣⎡43,8ππ上的最小值和最大值.19.已知函数)1(log )()()1(>==+a x f x g y x a与的图象关于原点对称.(1)写出)(x g y =的解析式;(2)若函数m x g x f x F ++=)()()(为奇函数,试确定实数m 的值; (3)当)1,0[∈x 时,总有n x g x f ≥+)()(成立,求实数n 的取值范围.21.如图,在正方体1111D C B A ABCD -中,E 、F 分别是BB 1的中点. (1)证明F D AD 1⊥; (2)求AE 与F D 1所成的角; (3)证明:面⊥AED 面11FD AA 1寒假作业3答案一、选择题1-5 BABBC 6-10 CDBDB二、填空题11.-4 12.2123+i 13.0 14.132415.211 16.12-<>a a 或 17.990 三、解答题18(1)T=π (2))(83,8Z k k k ∈⎥⎦⎤⎢⎣⎡++-ππππ(3)最小值-1…,最大值2…19.解:(1)设M (x ,y )是函数)(x g y =图象上任意一点, 则M (x ,y )关于原点的对称点为N (-x ,-y )N 在函数)1(log )(+=x x f a 的图象上,)1(log +-=-∴x y a)1(log x y a --=∴ (2)m x F x ax a+-=-+)1()1(log log )( 为奇函数.mm x F x F x ax ax ax a-+-=+-∴-=-∴-++-)1()1()1()1(log log log log )()(00log log log 211111=∴==+=∴+--+m m a xx a xxa(3)由n n x g x f xx a ≥≥+-+11log ,)()(得设)1,0[,11log )(∈-+=x x xa x Q ,即可只要由题意知n ≥min Q(x),,)121(log )(xax F -+-= 在[0,1)上是增函数.0)0()(min ==∴Q x Q 即0≤n 即为所求.20.解:(I)将事件“第一次、第三次均抽到白球”记作A ,则P (A ) = 16 ⨯16 =136A1(II)设 ξ 是三次抽取中抽到白球的次数,则 ξ~ B (3,16 )ξ 的分布列为E ξ = 3·P (A ) = 3·16 = 1221.(1)证明:因为AC 1是正方体,所以AD ⊥面DC 1。

小学四年级语文上册寒假作业2

小学四年级语文上册寒假作业2

一、成语填空。

若()若()()首东()风平()()水天()()()()江面()头()进()天()地人声()()二、把下面句子改为把字句。

院中的花草被小花猫折腾得枝折花落。

三、把下面句子改为被字句它没有把我放在眼里。

四、把下面句子改为反问句功课没做完,不能去看电影。

五、把下面句子改为陈述句。

这位小姑娘天真美好的心灵,不正像一朵含苞欲放的花蕾吗?六、缩句。

鱼贯而入的孩子们对这阴森神秘的山洞心生好奇。

七、看拼音写词语。

fān yìchūn gēng bōzhǒng hútúlièwù( ) () ( ) ( ) ( )huāgūduǒāi āi jǐjǐjīng miào juélún( ) () ( ) hàn zāi gān kūdìqiúxīn xiān kūzhī( ) () ( ) ( ) ( )八、修改病句。

我有勇气做一名优秀的少先队员。

_____________________________________我们要做到讲卫生的习惯。

____________________________________中国的人口是世界上最多的国家。

_____________________________________宽敞的草原是牛马的乐园。

_____________________________________南京的夏天是全国最热的城市之一。

_____________________________________刘老师香港回归写了四个大字。

_____________________________________经过治疗,小明的病已经恢复了健康。

_____________________________________九、找出成语中的错别字,再在括号里填上正确的字。

金壁辉煌()荒荒张张()是而不见()风双雨雪()十、填一填。

高一上学期数学寒假作业二

高一上学期数学寒假作业二

启明班寒假作业二学校:___________姓名:___________班级:___________考号:___________一、单选题1.若函数2(0)3y x πωω⎛⎫=-> ⎪⎝⎭两零点间的最小距离为2π,则ω=( )A .1B .2C .3D .42.已知函数()2sin()0,||2f x x πωϕωϕ⎛⎫=+>< ⎪⎝⎭,其图象与直线1y =的相邻两个交点的距离分别为3π和23π,若13 f π⎛⎫= ⎪⎝⎭,则ϕ的值为( )A .6π B .6π- C .3π- D .3π3.设函数())f x x ωϕ=-,x ∈R ,其中0ω>,||ϕπ<.若08f π⎛⎫-= ⎪⎝⎭,58f π⎛⎫= ⎪⎝⎭()f x 的最小正周期大于2π,则( )A .13ω=,1124πϕ=B .13ω=,712πϕ=-C .23ω=,1112πϕ=D .23ω=,12πϕ=-4.已知函数()()sin 06f x x πωω⎛⎫=+> ⎪⎝⎭在区间,2ππ⎡⎤⎢⎥⎣⎦内单调递减,则实数ω的取值范围是( )A .2,13⎡⎤⎢⎥⎣⎦B .24,33⎡⎤⎢⎥⎣⎦C .[)1,2D .3,22⎡⎫⎪⎢⎣⎭5.已知函数()()sin f x x α=+在,43x ππ⎛⎫∈- ⎪⎝⎭上单调递增,则α的值可以是( )A .3π-B .4π-C .4π D .3π 6.若函数()()()sin πf x x ϕϕ=+<在π2π,33-⎡⎤⎢⎥⎣⎦上单调,则ϕ的值为( )A .2π3-或π3B .π3-或2π3C .5π6-或6π D .π6-或5π6 7.若函数()πsin 23f x x ⎛⎫=- ⎪⎝⎭与()πcos 4g x x ⎛⎫=+ ⎪⎝⎭都在区间()(),0πa b a b <<<上单调递减,则b a -的最大值为( )A .π3B .π2C .6πD .π 8.若函数()2sin 23f x x πϕ⎛⎫=-+ ⎪⎝⎭是奇函数,则ϕ的值可以是( )A .56π B .2π C .23π-D .2π-9.函数()sin 23f x x πϕ⎛⎫=++ ⎪⎝⎭为偶函数的一个充分条件( )A .6πϕ=B .6πϕ=-C .3πϕ=D .3πϕ=-10.已知函数()sin 22f x x x =,若函数()y f x ϕ=-为奇函数,则||ϕ的最小值是( ) A .12π B .6π C .3π D .712π 11.已知函数()sin(2)f x x ϕ=+的图象关于点π,06⎛⎫⎪⎝⎭中心对称,则||ϕ的最小值为( )A .π6B .π3C .2π3D .4π312.将函数2sin()3y x π=+的图象向左平移()0m m >个单位长度后,所得到的图象关于y 轴对称,则m 的最小值是( ) A .12π B .6π C .3π D .23π13.已知函数()21cos cos (0,)2f x x x x a x R ωωω=+->∈在[]0,π内有且仅有三条对称轴,则ω的取值范围是( ) A .27,36⎛⎫ ⎪⎝⎭B .75[,)63C .513,36⎫⎡⎪⎢⎣⎭D .138,63⎛⎫ ⎪⎝⎭14.已知函数π()sin (0)3f x x ωω⎛⎫=-> ⎪⎝⎭在(π,2π)内不存在对称中心,则ω的取值范围为( ).A .12,33⎡⎤⎢⎥⎣⎦B .20,3⎛⎤ ⎥⎝⎦C .10,6⎛⎤⎥⎝⎦ D .1120,,633⎛⎤⎡⎤⋃ ⎥⎢⎥⎝⎦⎣⎦15.若函数()sin (0)3f x x πωω⎛⎫=+> ⎪⎝⎭在区间(),2ππ内没有最值,则ω的取值范围是( )A .1120,,1233⎛⎤⎡⎤⋃ ⎥⎢⎥⎝⎦⎣⎦B .1170,,12612⎛⎤⎡⎤ ⎥⎢⎥⎝⎦⎣⎦C .70,12⎛⎤ ⎥⎝⎦D .12,33⎡⎤⎢⎥⎣⎦ 16.若函数()sin 6f x x πω⎛⎫=+ ⎪⎝⎭(0ω>)在,44ππ⎛⎫- ⎪⎝⎭有最大值无最小值,则ω的取值范围是( )A .48,33⎛⎫ ⎪⎝⎭B .48,33⎛⎤ ⎥⎝⎦C .416,33⎛⎫ ⎪⎝⎭D .416,33⎛⎤ ⎥⎝⎦17.已知函数()()sin cos 0f x x a x a =+>的最大值为2,若方程()f x b =在区间13π0,6⎛⎫⎪⎝⎭内有三个实数根123,,x x x ,且123x x x <<,则1232x x x ++等于( )A .8π3 B .10π3C .4πD .25π618.已知函数()()22cos 10,2xf x x x ωωω=->∈R ,若函数()f x 在区间(),2ππ上没有零点,则ω的取值范围是( ) A .55110,,12612⎛⎤⎡⎤⎥⎢⎥⎝⎦⎣⎦ B .211,312⎡⎤⎢⎥⎣⎦ C .511,612⎛⎫⎪⎝⎭D .250,,1211312⎛⎫ ⎪⎝⎝⎛⎤ ⎥⎦⎭19.已知函数()()1sin 0f x x x ωωω=+>在()0,π上有且只有3个零点,则实数ω的取值范围是( ) A .1137,26⎛⎤ ⎥⎝⎦B .137,62⎛⎤ ⎥⎝⎦C .725,26⎛⎤ ⎥⎝⎦D .2511,62⎛⎤ ⎥⎝⎦20.已知函数()()sin 0,2f x x πωϕωϕ⎛⎫=+>< ⎪⎝⎭图象的两相邻对称轴之间的距离为2π,且3f x π⎛⎫+ ⎪⎝⎭为偶函数,则ϕ=( )A .6π B .6π- C .3π- D .3π21.若直线12x π=是曲线()sin 04y x πωω⎛⎫=-> ⎪⎝⎭的一条对称轴,且函数sin 4y x πω⎛⎫=- ⎪⎝⎭在区间0,12π⎡⎤⎢⎥⎣⎦上不单调,则ω的最小值为( )A .9B .15C .21D .3322.已知函数()()sin 06f x x πωω⎛⎫=-> ⎪⎝⎭在区间3,34ππ⎡⎤-⎢⎥⎣⎦上单调递增,且在区间[]0,π上只取得一次最大值,则ω的取值范围是( )A .30,4⎡⎤⎢⎥⎣⎦ B .80,9⎛⎤ ⎥⎝⎦ C .28,39⎡⎤⎢⎥⎣⎦ D .38,49⎡⎤⎢⎥⎣⎦23.已知函数()()sin 0,0,2f x A x A πωϕωϕ⎛⎫=+>>< ⎪⎝⎭,若函数()f x 的一个零点为6π.其图像的一条对称轴为直线512x π=,且()f x 在,64ππ⎛⎫ ⎪⎝⎭上单调,则ω的最大值为( )A .2B .6C .10D .1424.已知函数()sin()(0,0)f x A x ωϕωϕπ=+><<为偶函数,在0,3π⎡⎫⎪⎢⎣⎭单调递减,且在该区间上没有零点,则ω的取值范围为( ) A .30,2⎛⎫ ⎪⎝⎭B .31,2⎡⎤⎢⎥⎣⎦C .35,22⎡⎤⎢⎥⎣⎦D .30,2⎛⎤ ⎥⎝⎦二、填空题25.已知函数()cos f x x x ωω-(0)ω>的最小正周期为π,则ω=___.26.已知函数()()sin f x x ω=(0ω>)在区间ππ,123⎛⎤- ⎥⎝⎦上单调递增,在区间π5π,312⎡⎫⎪⎢⎣⎭上单调递减,则ω的值是______.27.已知函数()sin 2062f x x ππϕϕ⎛⎫⎛⎫=++<< ⎪ ⎪⎝⎭⎝⎭在,32ππ⎛⎫ ⎪⎝⎭上单调递增,则ϕ的取值范围为_________.28.将函数()sin (0)6f x x πωω⎛⎫=+> ⎪⎝⎭图像上所有点的横坐标伸长到原来的2倍,再向右平移6π个单位长度,得到函数()y g x =的图像,若函数()y g x =为偶函数,则ω的最小值为_________.29.已知函数()()()sin 0,0f x x ωϕωϕπ=+><<,且()f x 与()3f x π+均为偶函数,则ω的最小值是______.30.已知函数()()ππsin 22f x x ϕϕ⎛⎫=+-<< ⎪⎝⎭的图像关于直线π4x =对称,则ϕ=__________.31.若函数sin y x ω=(0ω>)在区间[]0,2上恰好取到3次最小值,请写出一个符合题意的ω的值:___________. 32.已知函数()π2sin 6f x x ω⎛⎫=+ ⎪⎝⎭中x 在任意的15个单位长度的距离内能同时取得最大值和最小值,那么正实数ω的取值范围是________.33.设函数()()sin 03f x x πωω⎛⎫=-> ⎪⎝⎭,若()f x 在0,2π⎛⎫ ⎪⎝⎭上有且仅有2个零点,则实数ω的取值范围为______.34.已知函数()sin (0)f x x x ωωω=>,若函数()f x 的图像在区间π()0,x ∈上恰有2个零点,则实数ω的取值范围为__________. 35.函数()()4sin 6f x x πωω*⎛⎫=+∈ ⎪⎝⎭N ,若,06π⎛⎫- ⎪⎝⎭是()f x 的一个对称中心,且()f x 在52,369ππ⎛⎫ ⎪⎝⎭上单调,则ω的最小值为_________.36.已知函数π()sin (0)6f x x ωω⎛⎫=+> ⎪⎝⎭,若π3f x ⎛⎫+ ⎪⎝⎭为偶函数,()f x 在区间π7π,312⎛⎫ ⎪⎝⎭内单调,则ω的最大值为_________.37.已知函数()2sin f x x ω=(0ω>)在区间3,43ππ⎡⎤-⎢⎥⎣⎦上单调递增,且函数()2sin 2g x x ω=+在[]2,0π-上有且仅有一个零点,则实数ω的取值范围是_______. 38.已知函数()()sin f x x ωϕ=+(其中0ω>,2πϕ<),若()0f T =(T 为周期),4x π=是函数()f x 图像的一条对称轴,()f x 在区间3,816ππ⎛⎫⎪⎝⎭上单调,则ω的值为______.。

人教版 高一 必修一 寒假作业(2)物质的分类(带答案)

人教版 高一 必修一  寒假作业(2)物质的分类(带答案)

寒假作业(2)物质的分类一、单选题1.下列说法不正确的是()①只含有一种元素的物质一定是纯净物②生石灰做干燥剂涉及化学变化③酸性氧化物都能与水反应生成酸④碱性氧化物一定是金属氧化物⑤用鸡蛋壳膜和蒸馏水除去淀粉胶体中的食盐不涉及化学变化⑥两种盐反应一定生成两种新盐A. ①③⑥B. ①②③④⑤C. ②④⑥D. ②④⑤2.下图所表示的一些物质或概念间的从属关系不正确的是()A. AB. BC. CD. D3.下列分类或归类正确的是①液氯、氨水、干冰、碘化银均为纯净物②CaCl2、NaOH、HCl、IBr均为化合物③明矾、水银、烧碱、硫酸均为电解质④火碱、纯碱、碳酸钙都是电解质⑤碘酒、淀粉、水雾、纳米材料均为胶体A. ①③④B. ②③C. ②④D. ②③④⑤4.下列有关分类的说法正确的是()A. 胶体的本质特征是具有丁达尔效应B. 阳离子、阴离子中均分别只含有一种元素,则由这样的阴、阳离子组成的物质一定是纯净物C. 白磷转化为红磷是物理变化D. 碱性氧化物一定是金属氧化物,酸性氧化物不一定是非金属氧化物5.下列说法不正确的是()①只含有一种元素的物质一定是纯净物②生石灰做干燥剂涉及化学变化③酸性氧化物都能与水反应生成酸④碱性氧化物一定是金属氧化物⑤用鸡蛋壳膜和蒸馏水除去淀粉胶体中的食盐不涉及化学变化⑥两种盐反应一定生成两种新盐A. ①③⑥B. ①②③④⑤C. ②④⑥D. ②④⑤6.分类法在化学学科的发展中起到了非常重要的作用,下列分类标准合理的是()A. 根据是否具有丁达尔效应,将分散系分为溶液、浊液和胶体B. 依据分子组成中是否含有氧元素,将酸分为含氧酸和无氧酸C. 根据水溶液是否能够导电,将物质分为电解质和非电解质D. 依据组成元素的种类,将物质分为单质和化合物7.下列说法正确的是()①Na2O、Fe2O3、Al2O3属于碱性氧化物,CO2、SiO2、NO2都能和碱溶液发生反应属于酸性氧化物②碳酸钠、氢氧化钡、氯化铵、过氧化钠都属于离子化合物③混合物:漂白粉、水玻璃、Fe(OH)3胶体、冰水混合物④醋酸、烧碱、纯碱和生石灰分别属于酸、碱、盐和氧化物⑤硅导电,铝在浓硫酸中钝化均属于物理变化⑥盐酸属于混合物,而液氯、冰醋酸均属于纯净物。

_高中英语寒假作业2Unit2Onwardsandupwards含解析外研版选择性必修第一册

_高中英语寒假作业2Unit2Onwardsandupwards含解析外研版选择性必修第一册

寒假作业第一部分阅读理解(共两节,满分50分)第一节(共15小题;每小题2.5分,满分37.5分)阅读下列短文,从每题所给的A、B、C和D四个选项中,选出最佳选项。

AThe Lake District Attractions GuideDalemain Mansion & Historic GardensHistory, Culture & Landscape (景观). Discover and enjoy 4 centuries of history, 5 acres of celebrated and award-winning gardens with parkland walk. Owned by the Hasell family since 1679, home to the International Marmalade Festival. Gifts and antiques, plant sales, museums & Mediaeval Hall Tearoom.Open:29 Mar—29 Oct, Sun to Thurs.Tearoom, Gardens & Gift Shop: 10.30—17.00 (16.00 in Oct).House: 11.15—16.00(15.00 in Oct).Town:Pooley Bridge & PenrithAbbot Hall Art Gallery & MuseumThose viewing the quality of Abbot Hall's temporary exhibitions may be forgiven for thinking they are in a city gallery. The impressive permanent collection includes Turners and Romneys and the temporary exhibition programme has Canaletto and the artists from St Ives.Open:Mon to Sat and Summer Sundays. 10.30—17.00 Summer. 10.一16.00 Winter. Town: KendalTullie House Museum & Art GalleryDiscover, explore and enjoy award-winning Tullie House, where historic collections, contemporary art and family fun are brought together in one impressive museum and art gallery. There are four fantastic galleries to visit from fine art to interactive fun,so there's something for everyone!Open:High Season 1 Apr—31 Oct: Mon to Sat 10.00— 17.00, Sun 11.00—17.00.Low Season 1 Nov一31 Mar: Mon to Sat 10.00— 16.30, Sun 12.00—16.30.Town: CarlisleDove Cottage & The Wordsworth MuseumDiscover William Wordsworth's inspirational home. Take a tour of his Lakeland cottage, walk through his hillside garden and explore the riches of the collection in the Museum. Visit the shop and relax in the cafe. Exhibitions, events and family activities throughout the year.Open: Daily, 09.30—17.30( last admission 17.00).Town: Grasmere1. When is the House at Dalemain Mansion & Historic Gardens open on Sundays in July?A. 09. 30—17. 30.B. 10. 30—16. 00.C. 11. 15—16. 00.D. 12. 00—16. 30.2. What can visitors do at Abbot Hall Art Gallery &Museum?A. Enjoy Romney's works.B. Have some interactive fun.C. Attend a famous festival.D. Learn the history of a family.3. Where should visitors go if they want to explore Wordsworth's life?A. Penrith.B. Kendal.C. Carlisle.D. Grasmere.BChildren are excited to find brightly wrapped(包装的) presents under the tree on Christmas morning. They can't wait to open the wrapping and get the toys that were on their wish lists,such as toy cars. But after the excitement wears off, those toys are usually left to the corner of the toy box and the kids are searching for something else to do. But it doesn't have to be that way.A study from the University of Toronto found that giving your child experiences as a gift, instead of toys, improves your child's intelligence and makes stronger parent-child bonds. "Often the focus is only on whether someone likes a gift rather than focusing on a fundamental purpose of gift giving. Knowing that will foster(培养) relationships between the giver and the receiver,'' said lead researcher Cindy Chan.Chan suggested that when you are buying a holiday gift or birthday gift, you should buy something that kids can experience with you. This can be movie or concert tickets, a CD from a performance you already saw to keep the memory alive. For example,for kids, a trip to a museum, going ice-skating or a book that the family can read together over and over again are valuable gifts.It is found that giving your kids too many toys can be counterproductive(适得其反) and make kids at a loss. The best way to make kids happy is to spend time together.So, if you want happy and intelligent kids, spending time with them and making memories are the best gifts you can give them. That's not to say that there shouldn't be any toys but change the focus from getting things to making lasting memories.1.How do children usually deal with toys after the excitement disappears?A. They put them aside.B.They give them to their friends.C.They add them to the wish lists.D.They throw them into the rubbish bin.2.What should people focus on when buying gifts according to Cindy Chan?A. The advantage of giving toys.B.The purpose of giving gifts.C. The excitement caused by toys.D.The gift receiver's hobby.3.What did Cindy Chan advise parents to do in Paragraph 3?A.Do something together with kids.B.Give kids well-wrapped presents.C.Buy kids as many toys as possible.D.Encourage kids to do sport in school.4.What is the best title for the text?A. A lesson from kids at ChristmasB.The pleasure of giving and receivingC.Valuable gifts: popular among kidsD.Move over toys, and make room for memoriesCBee see, bee do. At least that's the conclusion of research published earlier this month in the journal PLOS Biology, showing that bumblebees learn to solve problems by watching each other.In the first study of its kind in insects,scientists constructed experiments that challenged bees to pull strings in order to access rewards of nectar(花蜜).The scientists hoped their study would throw light on a bigger picture: howsocial learning spreads through a population.In the study, Lars Chittka from Queen Mary University of London and his team made artificial flowers and filled them with artificial nectar made of sugar water. They put the flowers under a clear type of plastic and attached a string.Then they added bees. While most of the insects failed to reach the nectar, a few eventually figured out how to access it, by pulling the string.The team discovered that they could greatly increase the success rate of the bees by first placing them inside a transparent(透明的) box where they could observe an experienced bee pull the string. Then, when the boxed bees were released, they often knew what to do and successfully pulled the string to obtain nectar.Next, the researchers added a bee that was experienced in string pulling to each of three new groups that had never seen the experiment before. Within a short time, about half of all those bees were soon pulling the strings. That result suggests the learned behavior could spread from bee to bee, similar to the way cultural ideas spread in other animals, including people.The experiment suggests that social learning may be more widespread in the animal kingdom than people previously thought.1.What happened after the bee pulled the string?A. It joined others.B.It saw flowers.C. It found water.D.It got nectar.2.What did the boxed bees do after being set free?A.They watched the experienced bee work.B.They imitated the experienced bee.C.They flew directly to the rewards.D.They flew back to the box.3.Why was an experienced bee added to new bee groups?A.To reduce the difficulty of the experiment.B.To watch the process of string pulling.C.To carry the experiment further.D.To keep the bees' interest.4.What does the study find?A.Most animals create their own cultures.B.Strings are particularly attractive to bees.C.Animals may have good social learning ability.D.Bumblebees may be smarter than other bee species.DOne day, when Albert Einstein was a small boy, his father bought him a composs(指南针). It was a small toy to entertain him. Einstein was very pleased as he looked at the "magic," thing turning towards north. For him, the compass was not a toy but a new world.He was a curious child and would often daydream. His father was annoyed with him for the bad reports from his teachers. They told him that the boy was not interested in his studies. He was blamed by his father for being lost in his foolish dreams.On leaving school, his father wanted him to study electrical engineering. But he disliked becoming an engineer. He entered the Zurich Polytechnic Academy to prepare himself for a teaching position in mathematics and physics. Though he finished his studies, he was unable to get a job.Finally, he got a job in an office. In his spare time, he filled his notepaper with difficult mathematical formulas(公式). Some of these later led to great scientific discoveries. When they were published, he became a famous scientist. He could not take his daily walk without being surrounded by reporters. He would only smile at them, and went on with his work in his quiet way.In 1921, Einstein was awarded the Nobel Prize. The Queen of Belgium invited him to pay her a visit. He got off the train and walked to the palace. He wasn't willing to take the car sent to pick him up. When the Queen asked him, he looked at her with a smile and answered, "It was a very pleasant walk." Einstein disliked wealth. Peace, he said, was what the world needed, and that could not be bought with money.1.Why did Einstein's father buy him a compass?A. To satisfy his curiosity.B.To let him play with it.C.To develop his interest in science.D.To help him create a dream world.2.What does the underlined word "annoyed" in Paragraph 2 mean?A. Familiar.B. Strict.C. Angry.D.Content.3.What can we learn about Einstein from Paragraph 4?A. He cared little for fame.B.He was not good at talking.C.He was praised by the Queen.D.He didn't work as an officer for long.4.What is the author's purpose in writing the text?A. To introduce a new theory.B.To contribute to world peace.C. To remember a great scientist.D.To share some incidents about Einstein. 第二节(共5小题;每小题2.5分,满分12.5分)根据短文内容,从短文后的选项中选出能填入空白处的最佳选项。

高一寒假作业2(必修1和必修2)

高一寒假作业2(必修1和必修2)

B.若 a ∥ , b ∥ , ∥ ,则 a ∥ b D.若 a , b , ,则 a b
6.、函数 f ( x) lg
A. (1, 4)
2 2
1 x 的定义域为( x4
B. [1, 4)
) D. (, 1] (4, )
C. (, 1) (4, )
2
A. EF 与 BB1 垂直 C. EF 与 CD 异面
4、 .若直线 ax 2 y 6 0 和直线 x a (a 1) y (a 1) 0 垂直,则 a 的 值为 ( )
A.
3 2
B.0
3 C. 或0 2
D. 3

5、设 a,b 为两条直线, , 为两个平面,下列四 个命题中,正确的命题是( A.若 a,b 与 所成的角相等,则 a ∥ b C.若 a , b , a ∥ b ,则 ∥
(1)求证:EF∥平面 CB1D1; (2)求证:平面 CAA1C1⊥平面 CB1D1
第 3 页(共 9 页)
19、(本题满分 12 分)
已知直线 l1 : 3 x y 1 0 , l2 : x y 3 0 ,求: (1)直线 l1 与 l2 的交点 P 的坐标;(2)过点 P 且与 l1 垂直的直线方程.
10、若直线 y kx 1 与圆 x 2 y 2 1 相交于 P,Q 两点,且 POQ 120 (其中 O 为原点),则 k 的 值为( ) B. 3 C. 2 或 2 D. 2
A. 3 或 3
11.已知点 A(2,3) 、 B (3,2) 直线 l 过点 P (1,1) ,且与线段 AB 相交,则直线 l 的斜率的取值 k 范围是 ( )

2021-2022学年八年级物理人教版寒假作业(2)

2021-2022学年八年级物理人教版寒假作业(2)

(2)——2021-2022学年八年级物理人教版寒假作业一、单选题1.2020年11月24日,中国再次发生了一件轰动全球的大事,嫦娥五号探测器在中国文昌航天发射场发射成功,这是我国探月工程“绕、落、回”三步走中,第三步的首次任务。

在探测器升空的过程中,以下列哪个物体为参照物,探测器是静止的( )A.太阳B.地球C.运载火箭D.发射架2.下列是牛牛同学的四个活动现象,其中属于机械运动的是( )A.思考物理问题B.听英语听力C.认真听讲D.跑步锻炼3.用刻度尺测量物体长度,下列情况会引起测量误差的是( )A.刻度尺的刻度不完全均匀B.刻度尺的刻度没紧贴被测物体C.读数时视线与刻度尺不垂直D.未能估读到分度值的下一位4.甲、乙、丙三只小兔分别以4 m/s 、180 m/min 、18 km/h 的速度从同一起跑线同时出发进行百米赛跑,它们以恒定不变的速度跑完全程,则下列说法正确的是( )A.甲先到达终点B.乙先到达终点C.丙先到达终点D.它们同时到达终点5.某小车从甲地到乙地,前半段路程的速度为1v ,后半段路程的速度为2v 。

那么该小车在整段路程内的平均速度是( ) A.122v v + B.12122v v v v + C.12122v v v v + D.1212v v v v + 6.如图所示,图甲是小车甲运动的s t -图像,图乙是小车乙运动的v t -图像,由图像可知( )A.甲车速度大于乙车速度B.甲车速度小于乙车速度C.甲、乙两车都以10 m/s 匀速运动D.甲、乙两车经过5 s 通过的路程都是10 m二、填空题7.我国古书《套买曜》上记载有:“人在舟中闭牖(门窗)而坐,舟行而人不觉。

”这是_____的生动描述,其中“舟行”是以 为参照物,“人不觉”是以 为参照物。

8.如图所示是小明某次步行后手机“微信运动”功能记录的数据.如果小明此次步行的时间是50 min ,一步的长度是0.5 m ,则他总共走了______m ,他步行的速度是______m/s.9.蜻蜓点水是指雌蜻蜓将卵直接产入水中。

苏教版小学语文六年级上册寒假作业(2)

苏教版小学语文六年级上册寒假作业(2)

苏教版小学语文六年级上册寒假作业(2)一、按课文内容填空。

1、《草原》的作者是(),原名(),字(),他是我国现代著名作家。

他的主要作品有()、()等。

2、那些小丘的线条(),就像(),不用墨线勾勒的(),到处(),轻轻()。

这种境界,既(),又(),既(),又()。

3、《草原》中最能反映蒙汉两族人民情深的句子是:()4、读了《草原》,我们头脑中马上会浮现这些与“草原”相关的成语:()、()、()、();还会想到与草原相关的古诗句:()。

5、“渲”字用音序查字法应查(),用部首查字法应查()部。

6、用“_”在选段中的括号里选择恰当的词。

(1)空气是那么(新鲜清新)(2)天空是那么(晴朗明朗)(3)小丘的线条是那么(柔美柔软)(4)这种境界,既使人(惊叹惊讶),又叫人舒服。

7、《草原》一文中有两个表示“绿”的词语,分别是()和()我还从课外积累了两个,它们是()和()。

8、《草原》一文中“翠色欲流”的“欲”字在字典里有四种解释:①欲望;②想要;③需要;④将要在这里应该是第()种解释。

9、看到草原,“我”感触很深,请用一个词来形容此时作者的心情,然后再用这个词造句。

词:();造句:()。

10、在《草原》中找一个拟人句:()11、“像给无边的绿毯绣上了白色的大花”中的“绣”字用得好,你能说说好在哪里吗?()12、“天色微明,晨雾如轻纱般飘浮在黄海滩涂上。

”这句话把晨雾比作(),写出了晨雾()的特点.13、糜鹿是()的一种。

它的外形很奇特:(),(),(),(),所以又被称作“()”。

14、阅读课文第3自然段,这段话从()、()、()、()等方面具体描述了服鹿的特点;“”这句话写出了糜鹿与众不同的生活习性。

15、仿照例子,写任一动物的某一特点。

例。

糜鹿的尾巴是鹿科动物中最长的。

长尾巴用来驱赶蚊蝇,以适应沼泽环境中的生活。

()16、写两句保护动物的宣传标语:();()。

17、《麋鹿》是一篇说明文,介绍了糜鹿的()、()和()。

2020年长沙县职业中专学校寒假作业(2)

2020年长沙县职业中专学校寒假作业(2)

2020年长沙县职业中专学校寒假作业(2)1. 计算机病毒不可能具有( )。

[单选题]A、可触发性和传染性B、潜伏性和隐蔽性C、传染性和破坏性D、自行痊愈性和天生免疫性(正确答案)答案解析:解释:计算机病毒不具有自行痊愈性和天生免疫性。

2. 计算机病毒通常会依附于其它文件而存在,是指计算机病毒具有( )。

[单选题]A、触发性B、传染性C、寄生性(正确答案)D、破坏性答案解析:解释:计算机病毒通常会依附于其它文件而存在,是指计算机病毒具有寄生性。

3. 计算机病毒侵入系统后,一般不立即发作,而是等待“时机”一到才发作,这种特性叫作 ( )。

[单选题]A、传染性B、寄生性C、潜伏性(正确答案)D、隐蔽性答案解析:解释:计算机病毒侵入系统后,一般不立即发作,而是等待“时机”一到才发作,这种特性叫作潜伏性。

4. 一种病毒的出现,使得人们对计算机病毒只破坏计算机软件的认识发生了改变,这种计算机病毒是 ( )。

[单选题]A、冲击波B、木马病毒C、backdoorD、CIH(正确答案)答案解析:解释:在CIH病毒之前,计算机病毒只破坏计算机的软件系统,但是CIH病毒且能破坏计算机的硬件。

5. 电子邮件的发件人利用某些特殊的电子邮件软件,在短时间内不断重复地将电子邮件发送给同一个接收者,这种破坏方式叫做( )。

[单选题]A、邮件病毒B、邮件炸弹(正确答案)C、木马D、蠕虫答案解析:解释:电子邮件的发件人利用某些特殊的电子邮件软件,在短时间内不断重复地将电子邮件发送给同一个接收者,这种破坏方式叫做邮件炸弹。

6. 以下肯定不是计算机感染病毒的迹象的是( )。

[单选题]A、计算机运行程序异常,反应迟缓B、没有操作情况下,磁盘自动读写C、软驱弹不出软盘(正确答案)D、设备有异常现象,如显示怪字符,磁盘读不出来等答案解析:解释:软驱弹不出软盘属性硬件故障,不是计算机病毒所能破坏的。

7. 有关计算机病毒描述正确的( )。

七年级数学寒假作业(二)

七年级数学寒假作业(二)

七年级数学寒假作业(二)一、选择题1.方程23x -=-的解是 ( ) A .5x =- B .5x = C .1x =- D .1x =2.解方程1124x x+-=,去分母,去括号得( ) A .122x x -+= B .122x x --= C .422x x -+= D .422x x --= 3.下列等式变形正确的是 ( ) A .若42x =,则2x =B .若4223x x -=-,则4322x x +=-C .若4(1)32(1)x x +-=+,则4(1)2(1)3x x +++=D .若3112123x x+--=,则3(31)2(12)6x x +--=4.若1x =是方程20x a +=的解,则a= ( ) A .1 B .2 C .1- D .2- 5.已知关于x 的方程250x a -+=的解是2x =-,则a 的值为 ( ) A .2- B .1- C .1 D .26.一艘轮船在甲、乙两地之间航行,已知水流速度是5千米时,顺水航行需要3小时,逆水航行需要4小时,则甲乙两地间的距离是 ( ) A .120千米 B .110千米 C .130千米 D .175千米7.如图,学校实验室需要向某工厂定制一批三条腿的桌子,已知该工厂有24名工人,每人每天可以生产20块桌面或300条桌腿,1块桌面需要配3条桌腿,为使每天生产的桌面和桌腿刚好配套,设安排x 名工人生产桌面,则下面所列方程正确的是 ( ) A .203300(24)x x =⨯- B .300320(24)x x =⨯- C .320300(24)x x ⨯=- D .20300(24)x x =-8.古埃及人的“纸草书”中记载了一个数学问题:一个数,它的三分之二,它的一半,它的七分之一,它的全部,加起来总共是33.若设这个数是x ,则所列方程为 ( )A .213337x x x ++=B .21133327x x x ++=C .21133327x x x x +++=D .21133372x x x x ++-=9.规定一种新运算:22a b a b =-⊗,若2[1()]6x -=⊗⊗,则x 的值为 ( ) A .1- B .1 C .2 D .2-10.代数式25ax b +的值会随x 的取值不同而不同,如表是当x 取不同值时对应的代数式的值,则关于x 的方程254ax b +=-的解是 ( )x4- 3-2- 1- 025ax b +1284 04-A .12B .4C .2-D .0 二、填空题11.已知方程240x -=,则x = .12.关于x 的方程253x a +=的解与方程220x +=的解相同,则a 的值是 .13.某下水管道工程由甲、乙两个工程队单独铺设分别需要10天,15天完成.如果甲队先单独施工5天,然后由甲、乙两队共同施工完成整个工程,则还需多少天?若设还需天数为x 天,则可列方程为 . 14.姐姐比弟弟大3岁,若5年前姐姐的年龄是弟弟的2倍,则姐姐现在的年龄是 岁.15. 如果10.20.3x y+=,那么101023x y += . 16.已知1x =是关于x 的方程(26)20m x --=的解,则m = .17.假设“▲、●、■”分别表示三种不同的物体.如图,前两架天平保持平衡,如果要使第三架天平也保持平衡,那么“?”处应放 个■.18.一列方程如下排列:1142x x -+=的解是2x =; 2162x x -+=的解是3x =; 3182x x -+=的解是4x =; ⋯根据观察得到的规律,写出其中解是2020x =的方程: . 三、解答题19.解方程:(1)33(21)x x x +=--; (2)3210123x x --=-.20.小明解方程121224x x+--=+的过程如图,请指出他解答过程中所有错误步骤的序号,并写出正确的解答过程.21.已知方程30x +=与关于x 的方程63()12x x k x -+=-的解相同(1)求k 的值; (2)若|5|(1)0k m n ++-=求m n +的值.22.快车以200/km h的速度由甲地开往乙地再返回甲地,慢车以75/km h的速度同时从乙地出发开往甲地.已知当快车回到甲地时,慢车距离甲地还有225km,则(1)甲乙两地相距多少千米?(2)从出发开始,经过多长时间两车相遇?(3)几小时后两车相距100千米?23.某商场从厂家购进了A、B两种品牌足球共100个,已知购买A品牌足球比购买B品牌足球少花2800元,其中A品牌足球每个进价是50元,B品牌足球每个进价是80元.(1)求购进A、B两种品牌足球各多少个?(2)在销售过程中,A品牌足球每个售价是80元,很快全部售出;B品牌足球每个按进价加价25%销售,售出一部分后,出现滞销,商场决定打九折出售剩余的B品牌足球,两种品牌足球全部售出后共获利2200元,有多少个B品牌足球打九折出售?24.某水果销售店用1000元购进甲、乙两种水果共140千克,这两种水果的进价、售价如下表所示:进价(元/千克)售价(元/千克)甲种水果58乙种水果913(1)这两种水果各购进多少千克?(2)若该水果店把这两种水果全部售完,则可获利多少元.25.下表为某市居民每月用水收费标准.用水量x(立方米)水费到户价单价(元/立方米)低于或等于17的部分0.8a+高于17低于或等于31的部分 2.72a+(1)某户用水10立方米,共缴水费32元,求a的值;(2)在(1)的前提下,该用户5月份缴水费80元,请问该用户5月份用水多少立方米?26.综合与实践在数学综合与实践课上,老师以“出行方式的选择“为主题,请同学们发现和提出问题并分断和解决问题.问题情境随着互联网的普及和城市交通的多样化,人们出行的时间与方式有了更多的选择.某市有出租车.滴滴快车和神州专车三种网约车,收费标准见下图(该市规定网约车行驶的平均速度为40公里/时)问题一“奋进小组”提出的问题是:如果乘坐这三种网约车的里程数都是10公里.他们发现乘坐出租车最节省钱.费用为元;问题二“质疑小组”提出了两个问题,请从A,B两个问题中任选一问作答,A.从甲地到乙地,乘坐出租车比滴滴快车节省13.6元,求甲.乙两地间的里程数.B.神州专车和滴滴快车对第一次下单的乘客有如下优惠活动:神州专车收费打八折,另外加5.3元的空车费;滴滴快车超过8公里收费立减6.5元.如果两位顾客都是第一次下单.分别乘坐神州专车、滴滴快车且收费相同,求这两位顾客乘车的里程数.七年级数学寒假作业(二)参考答案一、选择题1.方程23x -=-的解是( ) A .5x =- B .5x = C .1x =- D .1x = 【分析】移项、合并同类项即可求解. 【解析】23x -=-, 32x =-+, 1x =-. 故选:C .2.解方程1124x x+-=,去分母,去括号得( )A .122x x -+=B .122x x --=C .422x x -+=D .422x x --= 【分析】方程两边乘以4去分母得到结果,即可作出判断.【解析】解方程1124x x+-=,去分母,去括号得42(1)x x -+=,即422x x --=.故选:D .3.下列等式变形正确的是( ) A .若42x =,则2x =B .若4223x x -=-,则4322x x +=-C .若4(1)32(1)x x +-=+,则4(1)2(1)3x x +++=D .若3112123x x +--=,则3(31)2(12)6x x +--=【分析】根据等式的性质即可解决.【解析】A 、若42x =,则12x =,原变形错误,故这个选项不符合题意;B 、若4223x x -=-,则4322x x +=+,原变形错误,故这个选项不符合题意;C 、若4(1)32(1)x x +-=+,则4(1)2(1)3x x +-+=,原变形错误,故这个选项不符合题意;D 、若3112123x x+--=,则3(31)2(12)6x x +--=,原变形正确,故这个选项符合题意; 故选:D .4.若1x =是方程20x a +=的解,则(a = ) A .1 B .2 C .1- D .2- 【分析】将1x =代入20x a +=即可求出a 的值. 【解析】将1x =代入20x a +=, 20a ∴+=, 2a ∴=-, 故选:D .5.已知关于x 的方程250x a -+=的解是2x =-,则a 的值为( ) A .2- B .1- C .1 D .2【分析】由2x =-是方程的解,故将2x =-代入原方程中,得到关于a 的方程,求出方程的解得到a 的值即可.【解析】由方程250x a -+=的解是2x =-, 故将2x =-代入方程得:2(2)50a ⨯--+=, 解得:1a =. 故选:C .6.一艘轮船在甲、乙两地之间航行,已知水流速度是5千米时,顺水航行需要3小时,逆水航行需要4小时,则甲乙两地间的距离是( ) A .120千米 B .110千米 C .130千米 D .175千米【分析】可根据船在静水中的速度来得到等量关系为:航程÷顺水时间-水流速度=航程÷逆水时间+水流速度,把相关数值代入即可求得航程. 【解析】设A 、B 两码头之间的航程是x 千米. 5534x x-=+, 解得120x =, 故选:A .7.如图,学校实验室需要向某工厂定制一批三条腿的桌子,已知该工厂有24名工人,每人每天可以生产20块桌面或300条桌腿,1块桌面需要配3条桌腿,为使每天生产的桌面和桌腿刚好配套,设安排x 名工人生产桌面,则下面所列方程正确的是( ) A .203300(24)x x =⨯- B .300320(24)x x =⨯- C .320300(24)x x ⨯=- D .20300(24)x x =-【分析】设安排x 名工人生产桌面,则安排(24)x -名工人生产桌腿,根据生产的桌腿数量是桌面数量的3倍,即可得出关于x 的一元一次方程,此题得解.【解析】设安排x 名工人生产桌面,则安排(24)x -名工人生产桌腿, 依题意,得:320300(24)x x ⨯=-. 故选:C .8.古埃及人的“纸草书”中记载了一个数学问题:一个数,它的三分之二,它的一半,它的七分之一,它的全部,加起来总共是33.若设这个数是x ,则所列方程为( )A .213337x x x ++=B .21133327x x x ++=C .21133327x x x x +++=D .21133372x x x x ++-=【分析】根据题意列方程21133327x x x x +++=.【解析】由题意可得21133327x x x x +++=.故选:C .9.规定一种新运算:22a b a b =-⊗,若2[1()]6x -=⊗⊗,则x 的值为( ) A .1- B .1 C .2 D .2-【分析】首先根据题意,可得:21()12()12x x x -=-⨯-=+⊗,所以2(12)6x +=⊗,所以222(12)6x -+=;然后根据解一元一次方程的方法,求出x 的值为多少即可. 【解析】22a b a b =-⊗,21()12()12x x x ∴-=-⨯-=+⊗, 2[1()]6x -=⊗⊗, 2(12)6x ∴+=⊗,222(12)6x ∴-+=,去括号,可得:4246x --=, 移项,可得:4642x -=-+, 合并同类项,可得:44x -=, 系数化为1,可得:1x =-. 故选:A .10.代数式25ax b +的值会随x 的取值不同而不同,如表是当x 取不同值时对应的代数式的值,则关于x 的方程254ax b +=-的解是( )x 4- 3- 2- 1-0 25ax b + 12 8 4 0 4-A .12B .4C .2-D .0 【分析】根据表格中的数据确定出a 与b 的值,代入方程计算即可求出解. 【解析】根据题意得:250a b -+=,54b =-,解得:2a =-,45b =-,代入方程得:444x --=-, 解得:0x =, 故选:D . 二、填空题11.已知方程240x -=,则x = . 【分析】直接移项、系数化为1即可. 【解析】240x -=, 24x =, 2x =,故答案为:2.12.关于x 的方程253x a +=的解与方程220x +=的解相同,则a 的值是 . 【分析】利用一元一次方程的解法解出方程220x +=,根据同解方程的定义解答. 【解析】解方程220x +=, 得1x =-,由题意得,253a -+=, 解得,1a =, 故答案为:1.13.某下水管道工程由甲、乙两个工程队单独铺设分别需要10天,15天完成.如果甲队先单独施工5天,然后由甲、乙两队共同施工完成整个工程,则还需多少天?若设还需天数为x 天,则可列方程为 .【分析】由甲、乙两队共同施工,设还需x 天完成,题中的等量关系是:甲工程队5天完成的工作量+甲、乙两队工程队x 天完成的工作量1=,依此列出方程即可.【解析】甲队完成所有工程需要10天,所以甲队先施工5天完成了所有工程的一半,所以111()10152x +=,所以111()121015x ++=.故答案是:111()121015x ++=.14.姐姐比弟弟大3岁,若5年前姐姐的年龄是弟弟的2倍,则姐姐现在的年龄是 岁. 【分析】设姐姐现在的年龄是x 岁,则弟弟现在的年龄是(3)x -岁,根据5年前姐姐的年龄是弟弟的2倍,即可得出关于x 的一元一次方程,解之即可得出结论.【解析】设姐姐现在的年龄是x 岁,则弟弟现在的年龄是(3)x -岁, 依题意得:52(35)x x -=--, 解得:11x =. 故答案为:11.15.如果10.20.3x y+=,那么101023x y += . 【分析】根据等式的性质解决此题.【解析】10.20.3x y +=, ∴1010()10.20.31010x y +⨯=⨯. ∴1010123x y +=.故答案为:1.16.已知1x =是关于x 的方程(26)20m x --=的解,则m = . 【分析】把1x =代入(26)20m x --=,求出m 的值. 【解析】把1x =代入(26)20m x --=, 得2620m --=, 262m =+, 解得4m =. 故答案为:4.17.假设“▲、●、■”分别表示三种不同的物体.如图,前两架天平保持平衡,如果要使第三架天平也保持平衡,那么“?”处应放 个■.【分析】根据等式的性质解决此题.【解析】设“▲、●、■”的质量分别是x 、y 、z . 由题意得:x y z =+,2x z y +=. 22y z y ∴+=. 2y z ∴=. 36y z ∴=.∴要使第三架天平也保持平衡,那么“?”处应放6个■. 故答案为:6.18.一列方程如下排列: 1142x x -+=的解是2x =; 2162x x -+=的解是3x =; 3182x x -+=的解是4x =; ⋯根据观察得到的规律,写出其中解是2020x =的方程: . 【分析】先根据已知方程得出规律,再根据得出的规律得出即可. 【解析】一列方程如下排列: 1142x x -+=的解是2x =; 2162x x -+=的解是3x =; 3182x x -+=的解是4x =; ∴一列方程如下排列: 11222x x -+=⨯的解是2x =;21232x x -+=⨯的解是3x =; 31242x x -+=⨯的解是4x =; ⋯∴20191220202x x -+=⨯, ∴方程为2019140402x x -+=,故答案为:2019140402x x -+=.三、解答题 19.解方程:(1)33(21)x x x +=--;(2)3210123x x --=-. 【分析】(1)(2)按解一元一次方程的一般步骤,求解即可. 【解析】(1)去括号,得3321x x x +=-+, 移项,得3213x x x -+=-, 合并同类项,得42x =-,系数化为1,得12x =-;(2)去分母,的3(3)62(210)x x -=--, 去括号,得396420x x -=-+, 移项,得346209x x +=++ 合并,得735x =, 系数化为1,得5x =.20.小明解方程121224x x+--=+的过程如图,请指出他解答过程中所有错误步骤的序号,并写出正确的解答过程.【分析】根据解一元一次方程的方法和步骤进行解答即可得解. 【解析】错误步骤的序号为:①、②、③. 正确解答过程如下: 121224x x+--=+2(1)14242x x +-⨯=⨯+- 22482x x +-=+- 28224x x +=+-+ 312x = 4x =.21.已知方程30x +=与关于x 的方程63()12x x k x -+=-的解相同(1)求k 的值;(2)若|5|(1)0k m n ++-=求m n +的值. 【分析】(1)解方程30x +=,得x 的值,把x 的值代入方程63()12x x k x -+=-,求出k 的值; (2)把k 的值代入,根据非负数的和为0,先求出m 、n 的值,再求m n +. 【解析】(1)由30x +=,得3x =-, 把3x =-代入63()12x x k x -+=-, 得6(3)3(3)312k ⨯---+=--, 整理,得36k =, 解得2k =. (2)2k =, 2|5|(1)0m n ∴++-=|5|0m +,2(1)0n - 50m ∴+=,10n -=. 5m ∴=-,1n =. 514m n +=-+=-.22.快车以200/km h 的速度由甲地开往乙地再返回甲地,慢车以75/km h 的速度同时从乙地出发开往甲地.已知当快车回到甲地时,慢车距离甲地还有225km ,则 (1)甲乙两地相距多少千米?(2)从出发开始,经过多长时间两车相遇? (3)几小时后两车相距100千米? 【分析】(1)设甲、乙两地相距x 千米,根据时间=路程÷速度结合两车相同时间内行驶的路程间的关系,即可得出关于x 的一元一次方程,解之即可得出结论; (2)设经过y 小时两车相遇,分两车第一次相遇及两车第二次相遇两种情况考虑,根据路程=速度⨯时间,即可得出关于y 的一元一次方程,解之即可得出结论;(3)设t 小时后两车相距100千米,分两车第一次相距100千米、第二次相距100千米、第三次相距100千米、第四次相距100千米及第五次相距100千米五种情况考虑,根据两车行驶的路程之间的关系,即可得出关于t 的一元一次方程,解之即可得出结论. 【解析】(1)设甲、乙两地相距x 千米,依题意,得:222520075x x -=, 解得:900x =.答:甲、乙两地相距900千米. (2)设经过y 小时两车相遇. 第一次相遇,(20075)900y +=,解得:3611y =;第二次相遇,20075900y y -=,解得:365y =.答:从出发开始,经过3611或365小时两车相遇.(3)设t 小时后两车相距100千米.第一次相距100千米时,20075900100t t +=-,解得:3211t =;第二次相距100千米时,20075900100t t +=+,解得:4011t =; 第三次相距100千米时,20075900100t t -=-,解得:325t =;第四次相距100千米时,20075900100t t -=+, 解得:8t =; 第五次相距100千米时,75900100t =-,解得:323t =. 答:经过3211,4011,325,8或323小时后两车相距100千米. 23.某商场从厂家购进了A 、B 两种品牌足球共100个,已知购买A 品牌足球比购买B 品牌足球少花2800元,其中A 品牌足球每个进价是50元,B 品牌足球每个进价是80元. (1)求购进A 、B 两种品牌足球各多少个? (2)在销售过程中,A 品牌足球每个售价是80元,很快全部售出;B 品牌足球每个按进价加价25%销售,售出一部分后,出现滞销,商场决定打九折出售剩余的B 品牌足球,两种品牌足球全部售出后共获利2200元,有多少个B 品牌足球打九折出售? 【分析】(1)设购进A 品牌足球x 个,则购进B 品牌足球(100)x -个,根据“购买A 品牌足球比购买B 品牌足球少花2800元”可列出方程求解即可.(2)设有y 个B 品牌足球打九折出售,根据题意列出方程解决问题. 【解析】(1)设购进A 品牌足球x 个,则购进B 品牌足球(100)x -个, 根据题意,得80(100)502800x x ⨯--=,解得40x =.10060x -=. 答:购进A 品牌足球40个,则购进B 品牌足球60个; (2)设有y 个B 品牌足球打九折出售,根据题意,得(8050)408025%(60)[80(125%)90%80]2200y y -⨯+⨯⨯-+⨯+⨯-=. 解得20y =.答:有20个B 品牌足球打九折出售.24.某水果销售店用1000元购进甲、乙两种水果共140千克,这两种水果的进价、售价如下表所示:进价(元/千克) 售价(元/千克)甲种水果5 8 乙种水果9 13 (1)这两种水果各购进多少千克?(2)若该水果店把这两种水果全部售完,则可获利多少元. 【分析】(1)设购进甲种水果x 千克,则购进乙种水果(140)x -千克,根据表格中的数据和意义列出方程并解答;(2)总利润=甲的利润+乙的利润. 【解析】(1)设购进甲种水果x 千克,则购进乙种水果(140)x -千克,根据题意得:59(140)1000x x +-=,解得:65x =,14075x ∴-=.答:购进甲种水果65千克,乙种水果75千克; (2)(85)65(139)75495-⨯+-⨯=(元) 答:利润为495元.25.下表为某市居民每月用水收费标准.用水量x (立方米) 水费到户价单价(元/立方米)低于或等于17的部分0.8a + 高于17低于或等于31的部分2.72a + (1)某户用水10立方米,共缴水费32元,求a 的值;(2)在(1)的前提下,该用户5月份缴水费80元,请问该用户5月份用水多少立方米? 【分析】(1)根据题意列出方程10(0.8)32a +=,进而求出即可; (2)首先判断得出17x >,进而表示出总水费,进而得出即可. 【解析】(1)10(0.8)32a +=,解得 2.4a =; (2)17(2.40.8)54.480⨯+=<,设该用户5月份用水x 米3,依题意有17(2.40.8)(17)(2.4 2.72)80x ⨯++-⨯+=,解得22x =. 答:该用户5月份用水22立方米. 26.综合与实践在数学综合与实践课上,老师以“出行方式的选择“为主题,请同学们发现和提出问题并分断和解决问题. 问题情境随着互联网的普及和城市交通的多样化,人们出行的时间与方式有了更多的选择.某市有出租车.滴滴快车和神州专车三种网约车,收费标准见下图(该市规定网约车行驶的平均速度为40公里/时)问题一“奋进小组”提出的问题是:如果乘坐这三种网约车的里程数都是10公里.他们发现乘坐出租车最节省钱.费用为 元; 问题二“质疑小组”提出了两个问题,请从A ,B 两个问题中任选一问作答,A .从甲地到乙地,乘坐出租车比滴滴快车节省13.6元,求甲.乙两地间的里程数.B .神州专车和滴滴快车对第一次下单的乘客有如下优惠活动:神州专车收费打八折,另外加5.3元的空车费;滴滴快车超过8公里收费立减6.5元.如果两位顾客都是第一次下单.分别乘坐神州专车、滴滴快车且收费相同,求这两位顾客乘车的里程数. 【分析】问题一:根据出租车的收费标准解答;问题二:A 、设甲、乙两地间里程数为x 公里,分3x 和3x >两种情况列出方程并解答; B 、设两位顾客的里程数为x 公里,分8x 和8x >两种情况,分别列出方程并解答. 【解析】问题一:14 2.4(103)30.8+⨯-=(元) 问题二:A 解:设甲、乙两地间里程数为x 公里①若603,12 2.50.41413.640x x x ++⨯=+ 解得:15631x =(舍) ②若3x >,6012 2.50.414 2.4(3)13.640xx x ++⨯=+-+解得:12x =答:甲、乙两地间里程数为12公里B . B 解:设两位顾客的里程数为x 公里①若8x ,60600.8(10 2.80.5) 5.312 2.50.44040x xx x ++⨯+=++⨯解得:5x = ②60608,0.8(10 2.80.5) 5.312 2.50.4 6.54040x xx x x >++⨯+=++⨯-解得:30x =答:两位顾客的里程数为5或30公里.。

寒假作业(2)Welcome Unit -2021-2022学年高一英语人教版(2019)必修第一册

寒假作业(2)Welcome Unit -2021-2022学年高一英语人教版(2019)必修第一册

(2)Welcome Unit ——2021-2022学年高一英语人教版(2019)寒假作业一、阅读理解1.Chinese students always complain that they're under great pressure and don't get enough sleep. But they may be surprised to learn that they're much luckier than their peers (同龄人) in South Korea and Japan, according to a recently published report, conducted by Shanghai Academy of Social Sciences on the physical and mental health of senior high school students in the three Asian countries.According to the study, among nearly 6,000 high school students in the three countries, Chinese students are the tallest but poorest in physical fitness. Chinese students are on average 168.17cm, compared with 167.61cm for South Korean students and 164.70cm for Japanese students. Chinese students have asked for sick leave more than students in other countries. About 72 percent of South Korean students have never asked for sick and injury leave during high school, compared to 53 percent for Japanese students and 45 percent for Chinese students. Moreover, Chinese students drink alcohol and smoke earlier than South Korean and Japanese students. Around 70 percent of Chinese students have drunk alcohol, compared to 50 percent for South Korean and Japanese students.According to the survey, Japanese and South Korean students suffer more pressure than their Chinese peers. Statistics show 16 percent of students in China said they experienced mental pressure often over the past year, while the numbers in Japan and South Korea are 33 percent and 47 percent respectively (分别). Their worries come from "study", "future after graduation", "friendships" and "relationships with their parents". To go with stress, 57.9 percent of South Korean students sleep the least, less than six hours a day, compared with 46.6 percent of Japanese students and 30 percent of Chinese students.More Chinese students were satisfied with their physical appearance, double that of students in the survey from Japan and South Korea. The report said that over ha lf of students in South Korea had tried to lose weight in the past year, while in China the figure was only 22 percent. In measures of self-worth, such as "I think I am valuable", "I think I am successful", "I can complete many things" and "I won't give up to failure", Chinese students showed greater self-confidencethan students in Japan and South Korea.1.What's the main idea of the second paragraph?A.Chinese teenagers are the tallest, but most unhealthy.B.Chinese students drink the most alcohol and smoke earliest.C.Japanese students ask for the least sick leave.D.Chinese students ask for sick leave most often.2.It can be inferred from the passage that_________.A.Chinese stud ents are luckiest, yet most unsuccessfulB.Chinese students are confident in themselves and luckierC.Japanese students are most stressedD.South Korean students sleep the least3.The worries that c ause students to be stressed come from the following factors EXCEPT __________.A.study and careerB.physical appearanceC.friendshipsD.family relationships2.You may not know a lot of people when you start senior high school. Maybe your friends from junior high school are going to a different senior high school. Even if you know other freshmen(—年级学生), you still feel anxious that you don't know any upperclassmen. How are you going to make friends among this sea of unknown faces?Most senior high schools hold the freshman orientation(迎新会) before school actually starts. It is helpful because you not only learn your way around the building but also get to meet some of your teachers and fellow freshmen. That way, when you show up on your first day of school, you may already recognize a few familiar faces.When you talk to people at orientation, you'll probably find that a lot of them are feeling just like you are. They're all new to the school and don't know what to expect. Talking about a common concern with your classmates can help you develop friendships.The work in senior high school is something freshmen are probably worried about. It builds on what you learned in junior high school, giving you a more advanced(高深的) knowledge of many subjects. So you may find you have more work to do or that it's a bit more challenging. If you ever find your work too difficult, teachers can give you extra help.Senior high school also has more after-school activities than junior high school, such as clubs,music and theater groups a nd sports teams. This is a good time to explore your interests and try new things.Junior high school taught you the basics of time management and social skills while providing you with a little extra support and guidance. Senior high school gives you the chance to learn how to be more independent and responsible.1. How do the freshmen usually feel on their first day of senior high school?A. Proud.B. Nervous.C. Excited.D. Curious.2. What are freshmen probably worried about?A. The learning task.B. The ability to make friends.C. The freshman orientation.D. The relationship with teachers.3. What do after-school activities mainly help students to do?A. Develop friendships.B. Develop their interests.C. Build up their strength.D. Improve their learning ability.4. What is the last paragraph mainly about?A. What you'll learn in senior high school.B. What you learned in junior high school.C. The difference between junior high school and senior high school.D. The importance of being more independent and responsible.3.It's school time again! You're probably feeling excited and maybe a little sad that summer is over. Some kids feel nervous or a little frightened on the first day of school because of all the new things: new teachers, new friends, and even a new school. Luckily, these "new" worries only stick around for a little while. Let's find out more about going to a new school.Most teachers kick off the new school year by introducing themselves and talking about all the stuff you'll be doing that year. Some teachers give students a chance to tell something about themselves to the rest of the class, too. When teachers do the talking on the first day, they often read classroom rules and school rules to you so you'll know what's allowed and what's not. Please pay close attention.You might already know a lot of people in your class on the first day, but it's a great day to make a new friend, so try to say hello to kids you know and new ones that you don't know. Make the first move and you'll be glad you did, and so will your new friends!Seeing friends you haven't seen for some time can make the first day a good one. You can make the day feel special by wearing clothes that you really like. Maybe you got a great T-shirt on one of your vacations, or a pair of sneakers. It also can make you feel good to be prepared and have all the things you need, such as pencils, folders, and whatever else you'll need. But make sure that you pack them the night before in case you don't have time in the morning.1.What does the underlined phrase "kick off" in the second paragraph probably mean?A.Start.B.Study.C.Find.D.Teach.2.What does the last paragraph mainly tell us about?A.What to know about a new school.B.How to prepare for a new school.C.What to do on your first day of school.D.How to spend your first day of school.3.According to the passage, you usually do the following things on the first day of school except _________.A.introduce yourselfB.learn about the school rulesC.make new friendsD.go over your new lessons4.If you happen to see an old friend on the first day of school, what will you feel from the passage we know?A.Nervous.B.Sad.C.Happy.D.Worried.4.To most of us, school means classes, teachers, schedules, grades and tests. But for the children at Sudbury Valley School, Massachusetts, school is very different.Firstly, there are no lessons. All the children, aged between 4 and 19, do whatever they want to. There are no teachers —only "staff members". The idea behind this is that you do not need to make children learn, because children want to learn anyway. "You do not need to say to a three-year-old, 'Go to explore your environment.' You can't stop them!" says Daniel Greenberg, a founder of the school. "But if you make children do what you want all day, they will lose all taste for learning."At Sudbury Valley School, you will permit children to talk, read, paint, cook, work on computers, study French, play the piano, climb trees, or just run around. Two boys spent three years just fishing!The other way that Sudbury Valley School is different is that the children can decide the rules. Every week, there is a school meeting where both children and staff have one vote each—even thefour-year-olds. They decide the school rules, how to spend the school budget, and even which staff they want and do not want any more.When the school first opened i n 1968, people said it would never work. But today, the school has 200 students, and 80% of its students go on to college. Even the two boys who went fishing all the time have successful careers today. One of them is a musician and the other is a computer scientist.1.What is the main topi c of the article?A.An unusual school.B.Children's hobbies.C.A school without rules.cation in the US.2.What does the school believe?A.Teachers cannot teach children well.B.Children learn best when they do what they want to do.C.Learning is for adults—children should only play.D.Children should only learn about one thing at a time.3.What does Daniel Greenberg say about three-year-olds?A.They love learning.B.They are very naughty.C.They want to be outside all the time.D.They are too young to learn anything.4.Who has the most power in the school meetings?A.The older children have more power than the younger children.B.A child has more power than an adult.C.The younger children have more power than the older children.D.Everybody has equal power.二、七选五5.Just Go to UniversityFor any student, going to university is one of the most important stages of their lives. It is a time when a young person will move out of their home to be independent. ①_______ Are youready for such an exploration? The following information may be helpful.· Why should you go to university?Learning is a lifelong process. University is the right place where you can learn both academically and socially. At university, you will be taught by leading lecturers in their fields of study. ②_______Meanwhile, you will meet people with different backgrounds at university. This offers you the chance to learn to look after yourself, to develop your own values and to accept those who may be different.·③_______Once you have decided that you do want to go to university, how can you choose a dream one?④_______ Your interest, the major and the course to be taken are all the concerns. Many universities have open days or send tutors out to talk to the students on what they offer. This also gives you a chance to ask questions. Finding out what their predicted exam grades will also help students determine which university may be the most suitable.· What can you learn at university?In many universities, each student begins with a general knowledge base in the first year. Students can have more time to explore their interests before committing to a specific subject. Apart from the academic achievements, various societies, where freshmen can meet like-minded friends, offer you chances to develop the extra-curricular interests in many fields. ⑤_______A. How can you choose a university?B. You have to first think of various aspects.C. What should you prepare before going to university?D. You can thus equip yourself with enough academic knowledge.E. Besides, it is a great honor to be admitted into such a university.F. In one sense, the university can be a completely new world to explore.G. University provides the all-important stepping stone for your future life.三、完形填空6.My nephew's 10-year-old son came for a visit one hot July weekend. I persuaded him to1inside and joined him in a game. After playing for an hour, I suggested that we relax for a while. I 2 my favorite chair to let my neck relax. He left the room and I was catching a fewenjoyable 3 of peace."Look, Alice," he said excitedly as he 4 over to the chair where I was sitting. "I found a kite. Could we go outside and 5 it?" Looking out of a nearby window, I noticed it was still outside. "I'm sorry. Tripper," I said, sad to see his 6 expression. "The wind is not blowing today. The kite won't fly."The7 10-year-old boy replied, "I think it's windy enough. I can get it to fly," he answered8 he hurried out to the back door.He ran back and forth, as9 as his ten-year-old legs would carry him, looking back 10 at the kite behind. After about ten minutes of unsuccessful trying, he came back in.I asked, "How did it 11?" "Fine," he said, not wanting to admit (承认) the failure. "I got it to fly some." However, I heard him say secretly, "I guess I'll have to wait for the 12 ."At that moment I heard another voice speak to my 13 ," Alice, sometimes you are jus t like that. You want to do it your way 14 waiting for the wind."And the voice was right. We usually want to use our own efforts to 15 what we want to do. We must learn how to make use of "the wind" in the first place!1.A.live B.lie C.study D.stay2.A.fell into B.jumped off C.cleaned up D.went through3.A.times B.hours C.moments D.periods4.A.sent B.climbed C.left D.ran5.A.decorate B.fly C.hang D.drop6.A.bright B.satisfied C.dull D.unhappy7.A.determined B.talented C.clever D.generous8.A.as B.unless C.after D.until9.A.hard B.hardly C.actively D.gradually10.A.angrily B.hopefully C.doubtfully D.nervously11.A.make e C.go D.settle12.A.news B.order C.wind D.sunshine13.A.dream B.memory C.heart D.world14.A.because of B.instead of C.except for D.as for15.A.imagine plete C.fancy D.decide四、语法填空7.阅读下面短文,在空白处填入1个适当的单词或括号内单词的正确形式。

  1. 1、下载文档前请自行甄别文档内容的完整性,平台不提供额外的编辑、内容补充、找答案等附加服务。
  2. 2、"仅部分预览"的文档,不可在线预览部分如存在完整性等问题,可反馈申请退款(可完整预览的文档不适用该条件!)。
  3. 3、如文档侵犯您的权益,请联系客服反馈,我们会尽快为您处理(人工客服工作时间:9:00-18:30)。

必修3检测题(08-9-20)1.在人体内环境中可以发生的生理过程是A.抗体与相应的抗原发生特异性的结合B.合成生长激素、胰高血糖素C.丙酮酸的氧化分解D.食物中的淀粉经消化分解成葡萄糖2.下列关于人体内环境和稳态的叙述不正确的是A.葡萄糖、生长激素、抗体属于人体内环境的成分B.内环境稳态不能维持,机体的生命活动就会受到威胁C.青蛙从25℃的室温中被转移到5℃的环境中,其耗氧量将减少D.胰岛素和胰高血糖素的协同作用使血糖浓度维持相对稳定3.下列关于体温调节的叙述,正确的是A.大脑皮层是调节体温的主要中枢B.温觉感受器只分布于皮肤C.人在剧烈运动时主要产热方式是骨骼肌的收缩D.降低新陈代谢是人在炎热环境中散热的主要方式4.科学家发现过渡肥胖往往造成血中葡萄糖浓度(简称血糖)过高,且血中胰岛素浓度也偏高。

某研究室对过度肥胖的老鼠进行实验,发现阿斯匹林(一种消炎止痛药)可矫正肥胖老鼠的生理缺失,肥胖老鼠服用阿斯匹林三周后注射胰岛素,120分钟内的血中葡萄糖浓度变化如下图所示,则下列叙述正确的是(对照组老鼠未服用阿斯匹林)甲:时间为零时服用阿斯匹林的老鼠血糖浓度显著低于对照组乙:注射胰岛素使对照组及实验组的血糖浓度在60分钟内明显下降丙:肥胖老鼠的细胞对胰岛素不起反应,使胰岛素无法调节血糖浓度丁:服用阿斯匹林使老鼠细胞恢复对胰岛素的反应,使胰岛素得以降低血糖浓度A.甲、乙B.乙、丙C.甲、丁D.丙、丁5.乙酰胆碱是可引起突触后膜兴奋的递质,若病人血清中含有对抗乙酰胆碱受体的抗体,该病人所患疾病及表现为A.自身免疫病,肌无力B.自身免疫病,痉挛C.过敏反应,肌无力D.过敏反应,痉挛6.人体在剧烈运动状态下,不可能发生的是A.[H]减少B.贮存的糖元减少C.乳酸积累增加D.肾上腺素含量增加7.人在寒冷环境中的即时反应之一是皮肤起“鸡皮疙瘩”。

该反应属于A.神经—体液调节B.大脑皮层控制的反应C.条件反射D.应激反应8.下列关于体温调节的叙述中,正确的是A.体温调节的主要中枢位于下丘脑,是形成冷觉和温觉的部位B.冷觉感受器分布在皮肤,温觉感受器分布在内脏器官C.肾上腺素与甲状腺激素在体温调节中起协同作用D.寒冷环境中出现“寒战”的行为属于条件反射9 、丝瓜为雌雄同株异花植物,将刚萌发的该植物种子先在下表5种物质一定浓度的溶液泡24小时,然后种植。

比较最初lO节的雌花与雄花平均数,求出性别比,结果如下表。

分析上表数据,其中表述不正确的是A.外源植物生长调节剂或激素打破了内源激素比例的平衡,从而影响雌雄花的性别分化B.该实验浓度下的乙烯利对丝瓜性别分化影响不大,对其他植物也是如此C.花器官的性别分化是各种激素和内外环境因子对基因表达调控的结果D.该实验浓度下的赤霉素、CP有利雌花的形成,整形素有利雄花的形成10.被切除某一内分泌器官的褐色家鼠会很快死亡,若补充大量食盐水可维持生存。

切除的这一内分泌器官最可能是A.甲状腺B.胰腺C.肾上腺D.脑垂体11.当人所处的环境温度从25 ℃降至5 ℃,耗氧量、尿量、抗利尿激素及体内酶活性的变化依次为A.减少、减少、增加、不变B.增加、增加、减少、不变C.增加、减少、增加、不变D.增加、增加、减少、降低12.给家兔注入20%葡萄糖溶液10mL,引起尿量增加,其主要原因是A.肾小管液溶质浓度升高而减少水的重吸收B.肾小球滤过率增加C.抗利尿激素分泌增加D.醛固酮分泌增加13.如图为动物的某组织,其中1一毛细血管壁、2一红细胞、3一血浆、4一细胞内液、5一组织液,据图判断下列说法中正确的是A.过敏反应的抗体主要分布在3和5中,3和5的成分是有区别的B.葡萄糖由3经1和5到达4的过程,依靠自由扩散来完成C.图中二氧化碳浓度最高的部位是5D.2中的氧气进入4需要经过4层膜,2处的氧气浓度高于4处14.右图A表示流进肾脏的血管,B表示流出肾脏的血管,C表示输尿管,对于健康人A、B、C中液体成分的比较,正确的是A.A中有大分子蛋白质,B中无蛋白质,C中无蛋白质B.B中无尿素,A中有尿素,C中有尿素C.A、B、C中均有尿素,且C尿素浓度最大D.A中蛋白质含量最高,B中尿素最低,C中尿素含量最高15.水和无机盐的平衡对内环境稳定具有重要意义,下列关于人体内水盐平衡调节的叙述,正确的是A.Na+来自饮食,主要通过汗腺排出B.K+排出的特点是多吃多排,少吃少排,不吃不排C.调节水盐平衡的主要激素是抗利尿激素和醛固铜D.寒冷环境中人体内多余的水分只从肾、肺和消化道排出D.寒冷环境中出现“寒战”是立毛肌收缩的结果16.下图为人体内环境示意图。

图中A、B、C、D表示结构,①、②、③、④表示液体,下列有关叙述不正确的是A.一般情况下,②中的CO2不能向③中扩散B.B结构呼吸作用的终产物是乳酸C.①中血糖浓度的调节与垂体有关D.①②④均参与了体温的调节17.下面关于下丘脑功能的叙述正确的是①大量出汗后,下丘脑分泌的抗利尿激素增加,肾上腺分泌的醛固酮也增加②寒冷刺激使下丘脑分泌促甲状腺激素,促进甲状腺的活动来调节体温③下丘脑是体温调节的高级中枢,在下丘脑产生冷觉和热觉④血糖低时下丘脑通过有关神经的作用,可以促进肾上腺和胰岛A细胞的分泌活动⑤内环境渗透压的增高,使下丘脑某部位产生的神经冲动传至大脑皮层产生渴觉A.①②③B.②③④C.②④⑤D.①④⑤18.已知每克淀粉和脂肪完全氧化分解时产生水的量分别是0.55g和1.05g。

现有A、B两种小型哺乳动物体重和年龄都相似,将它们分成数量相等的2组,每天每只消耗100g 大麦种子(含60%淀粉和40%脂肪),两者在相同环境下持续实验10天,数据如下表所示:A.物种A为2g,B为47gB.物种A为4g,B为7gC.物种A为2g,B为7gD.物种A为12g,B为47g19.下图为人体细胞及其内环境之间物质交换的示意图①②③④分别表示人体内不同部位的液体。

据图判断下列说法正确的是A.人体的内环境是由①、②、③组成的B.体液①中含有激素、血红蛋白、尿素、CO2等物质C.效应B细胞分泌的抗体通过②进入①④内,再经循环运输到发炎部位D.细胞无氧呼吸产生的乳酸进入①中,①中NaHCO3与之发生作用使pH基本稳定20.据2006年8月25日出版的《科学》报道,来自美国哈佛公共健康学院的一个研究组提出了两种分别叫做PBA和TUDCA的化合物有助于糖尿病治疗,其机理是:这两种药物可以缓解“内质网压力”(指过多的物质如脂肪积累到内质网中使其出错的状态)和抑制JNK基因 (一个能干扰胰岛素敏感性的基因)活动,以恢复2型糖尿病患者的正常血糖平衡,并已用2型糖尿病小鼠进行实验并获得成功。

下列对此分析错.误.的是A.肥胖与2型糖尿病的病因有关B.内质网功能出错影响了胰岛素的合成C.JNK基因活动受到抑制是2型糖尿病的另一重要病因D.2型糖尿病小鼠胰岛B细胞中的高尔基体和线粒体也参与了胰岛素的合成和分泌21.人体在剧烈运动状态下,不可能发生的是A.[H]减少B.贮存的糖元减少C.乳酸积累增加D.肾上腺素含量增加22.哮喘是世界性顽症,最新研究发现哮喘的生化接触点潜伏在淋巴细胞中。

下图为人的淋巴细胞的体液免疫图解,下列说法中正确的是A.细胞②为B细胞B.细胞⑤产生的物质为蛋白质C.细胞⑤为靶细胞D.细胞④是浆细胞23.下图为动物的某组织,其中1—毛细血管壁、2—红细胞、3—血浆、4—细胞内液、5—组织液。

下列说法中正确的是A.氧气通过3及1而运输到5过程,需要ATPB.葡萄糖由3经1和5到达4过程,依靠主动运输来完成C.图中二氧化碳浓度最高的部位是5D.由4产生的热量可由2的运输而散失到体外24.生态系统结构越复杂,其调节能力就越大,原因是①处于同一营养级的生物种类多②能量可通过不同的食物链传递到顶级③某营养级的部分生物减少或消失,可由该营养级的其他生物代替④能量流经各营养级时,是逐级递减的A.①②③④B.①②③C.①③④D.③④25.当人体饮水不足、体内失水过多或吃的食物过咸时,都会引起细胞外液渗透压升高(浓度升高),下丘脑感受到这种刺激A.在下丘脑部位产生渴觉,进而调节对水的摄入量B.垂体后叶分泌并释放的抗利尿激素增加C.下丘脑分泌,并由垂体后叶释放的抗利尿激素增加D.在下丘脑的调节下,肾上腺分泌的醛固酮量增加26.神经冲动在神经元与神经元之间的传递方向是A.树突→轴突B.树突→细胞体C.轴突→轴突D.轴突→树突或细胞体27.下列关于下丘脑在机体稳定态调节中的作用的叙述中,错误..的是A.下丘脑的渗透压感受器可感受机体渗透压升高B.下丘脑是体温调节中枢、血糖调节中枢、渗透压调节中枢C.下丘脑分泌抗利尿激素;在外界环境温度低时分泌促甲状激素D.下丘脑可传导渗透压感受器产生的兴奋至大脑皮层,使人产生渴觉28.图为人体内体温与水平衡调节的示意图,下列叙述正确的是:①当受到寒冷刺激时,a、b、c、d激素的分泌均会增加②c、d激素分泌增多,可促进骨骼肌与内脏代谢活动增强,产热量增加③下丘脑是感觉体温变化的主要中枢,是形成冷觉、热觉的部位④下丘脑具有渗透压感受器功能,同时能合成、分泌e激素⑤寒冷刺激使下丘脑分泌促甲状腺激素释放激素,通过促进甲状腺的活动来调节体温。

⑥上图所示的神经调节过程中,肾上腺、皮肤均为效应器A.①②③B.①②④C.③④⑤D.④⑤⑥29、在决定鲸的捕捞量时,需研究右图。

该图表示了生殖数量、死亡数量与种群大小的关系。

图中哪条线表示生殖的数量,P点代表什么A. 曲线1表示生殖数量,P代表各种群的最大数量B. 曲线2表示生殖数量,P代表各种群的最大数量C. 曲线1表示生殖数量,P代表环境的负载能力D. 曲线2表示生殖数量,P代表环境的负载能力30、下列组合中,依次属于种群、群落和生态系统的一组是①生活在人大肠内的细菌②某一池塘中的全部鱼类③肺炎患者肺部的肺炎双球菌④一根枯木及枯木上所有生物A. ①②④B. ②③④C. ③②①D. ③①④31、右图是一温带地区在初生演替过程中2种量值的变化曲线,这两条曲线分别表示A. A表示草本植物的种类数量,B表示整个植被的生物量B. A表示整个种群的生物量,B表示草本植物的种类数量C. A表示土壤中腐殖质总量,B表示整个植被中的种类数量D. A表示食肉类的种类数量,B表示食肉类的生物32、锄足蟾蝌蚪、雨蛙蝌蚪和蟾蜍蝌蚪均以浮游生物为食。

在条件相同的四个池塘中,每池放养等量的三种蝌蚪,各池蝌蚪总数相同。

再分别在四个池塘中放入不同数量的捕食者水螈。

一段时间后,三种蝌蚪数量变化结果如图。

下列分析,错误的是A. 无水螈的池塘中,锄足蟾蝌蚪数量为J型增长B. 三种蝌蚪之间为竞争关系C. 水螈更喜捕食锄足蟾蝌蚪D. 水螈改变了三种蝌蚪间相互作用的结果33、右图中三条曲线分别代表了动物物种多样性程度、动物数量易变程度及冬眠动物比例在不同类型生态系统中的变化趋势。

相关文档
最新文档