人教课标必修一选专项同步训练

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人教版高中英语选择性必修第一册同步训练UNIT5 Section Ⅲ 含答案

课后·训练提升一、单词拼写.We need to get to the r of the problem before we can solve it.2.Nowadays people prefer o food and vegetables because they are free of3.Introduced as a “less-harmful” a to smoking,“vaping” has gained increasing4.No other technological development has had as great an impact as the growth of electronics on so many a of social,economic,and cultural development.5.It is an area at a d of about 1,000 metres below the surface where light does not6.Individuals can reduce their contribution by creating less waste at the start—for7.N is necessary for life,so it is not surprising that food is such an important part of(admit) their mistakes.’t looked at the report in (deep) yet.(entire) female.(grocery) annually?(bacterium) are actually good for you.turn..What would you do,instance,if you found a member of staff stealing?long way to go before China achieves modernisation..There is,addition,one further point to make.10.It is important to introduce children to healthy (nutrition) foods from when they1.这种颜色跟我找的那种差远了。

人教版高中英语选择性必修第一册同步训练UNIT3 Section Ⅱ 含答案

SectionⅡLearning About Language课后·训练提升一、单句语法填空(think) about the past or being worried about the future.(quarrel) about it.We are all in the same boat.(read) without understanding.7.(communicate) on Internet is a common phenomenon,and more people(learn) English well.10.(recognise) wherever you go is the price you pay for being二、完成句子1.看电视过多对你的眼睛有害。

2.赶紧行动起来吧。

抱怨是没有用的。

’s .3.对我来说,玩电脑游戏不再有乐趣。

For me,computer games.4.没有调查就讨论这个计划是浪费时间。

5.每天早晨朗读英语有助于提高你的口语能力。

improve your spoken English.三、阅读理解We all know that theme parks are places to have fun and amuse ourselves,but among so many exciting rides there are also some dangers.Make sure you know what the safety standards are for all the attractions at the park.If you do that,you will be safe and have fun.Drink water.Believe it or not,dehydration—when your body doesn’t have enough water—is the commonest cause of injuries at theme parks.Drinking water while you are at the park is not enough.You must make sure that you drink enough water before your visit.Use your“common sense”.There are lots of people around,so make sure where your friends or family are.Also,if you are walking and want to stop,make sure nobody is walking behind you.First step aside,then look behind and if you aren’t in anybody’s way,then stop.It might sound exaggerated(夸张的),but crashes between people can cause accidents.Follow the instructions.The majority of theme parks have instructions for each ride.Some rides only allow people of a certain height.So make sure you are not too tall or too short before boarding any ride.Also,people with certain diseases or conditions are advised not to go on some rides.Do remember:If you are told not to go on a ride,then DON’T.Do not ride with a bad stomach or if you’ve just eaten.Rides can make you ill because of their violent changes of direction and your lunch may end up on someone else’s head:surely not a very pleasant experience.Have fun,relax,and be a little brave!1.What is the leading reason for injuries at theme parks?A.Snow.B.Dehydration.D.Crashes.“...dehydration—when your body doesn’t have enough water—is the commonest cause of injuries at theme parks.”可知,脱水——当你的身体没有足够的水时——是主题公园里最常见的受伤原因,也就是说脱水是在主题公园里受伤的主要原因。

人教版高中英语必修第一册同步训练WELCOME UNIT Section Ⅳ 含答案

SectionⅣListening and Talking&Reading for Writing课后·训练提升一、根据句意及首字母提示写出单词1.I spent the weekend r for my exam.答案:revising2.The new houses have been built in a traditional s.答案:style3.You just have to keep working towards your g.答案:goal4.Learning s are important in your senior high school.答案:strategies5.He isn’t my business p now.答案:partner二、阅读理解Michael has a better understanding of the sentence “Where there is a will,there is a way.”Now he is 22 years old and ha s become an example of young people because of his story of success.Michael was born in a very poor family.His parents worked in Vietnam before they moved to Britain in 1980.They couldn’t find jobs in Britain because they spoke little English.The whole family had to live on benefits(救济金) and they lived in a small house in Hackney,a poor area in East London.Growing up is not easy for Michael,but he never gave up.At the age of ten,he made up his mind to go to Cambridge University.It was not easy,either.Mich ael studied at a school,which used to be called “the worst school in Britain”.However,young Michael made his mind to try his best,no matter what kind of school he was studying at.The smart boy studied very hard and did well in every subject at school.Once he made a bet with his friend to learn further maths.As a result,after just spending four months teaching himself from a textbook,he got an A in AS-level further maths.Now Michael is the star medical student in St John’s College,Cambridge and has just won an award for his excellent grades.He hopes he will be an example for other young people from poor families.1.What do we know about Michael’s family according to the passage?A.His family was very poor and lived on benefits.B.They made a living with the help of the government in Vietnam.C.Michael’s parents had no jobs because of their little experience.D.They lived in a poor area without any help.答案:A解析:细节理解题。

2023人教版新教材高中地理选择性必修第一册同步练习--全书综合测评

2023人教版新教材高中地理选择性必修第一册全书综合测评(全卷满分100分,考试用时75分钟)一、单项选择题(本题共15小题,每小题3分,共45分。

在每小题给出的四个选项中,只有一项是符合题目要求的。

)日晷是我国古代根据晷针日影位置来确定时辰的一种仪器,按晷面的摆放角度可分为地平式、垂直式和赤道式。

位于清华大学校礼堂前的日晷(图1)为典型的赤道式日晷,其下部底座上镌刻着“行胜于言”。

图2为“赤道式日晷示意图”。

读图完成下面两题。

图1图21.山东某地安装赤道式日晷时,下列做法及原因描述合理的是()A.精确测定当地经度,用于调整晷面与水平面之间夹角B.精确测定当地纬度,用于计算当地与北京时间的时差C.使用罗盘精准调节,保证当地正午时晷针针影朝向正南D.使用角度测量仪,保证晷针与地平面夹角等于当地纬度2.北半球夏至日清华日晷的晷针在晷面上形成的针影()A.呈逆时针方向移动B.正午时落在朝南的一面上C.划过角度小于180°D.长度先变短再变长大湖效应指的是冷气团遇到大面积未结冰的水面(通常是湖泊)从中得到水汽和热能,然后在湖泊迎风岸形成雨、雪、雾的现象。

北美洲五大湖区是全球大湖效应最典型的地区。

下图为五大湖区东岸附近一年中气温与水温变化示意图。

据此完成下面两题。

3.与大湖效应产生的降雪过程原理类似的天气系统是()A.暖锋B.冷锋C.气旋D.反气旋4.由大湖效应产生降雪的主要时期是()A.①B.②C.③D.④下图为四地气温和降水量图。

读图完成下面两题。

5.①地气候的形成原因为()A.海陆热力差异B.受西风带控制C.受赤道低压带控制D.受副热带高压带控制6.①②③④四地气候成因最相近的是()A.①②B.①④C.③④D.②④下图为某地地质剖面示意图。

据此完成下面两题。

7.图中地质作用由早到晚依次发生的是()A.岩浆侵入、褶皱、断层、堆积、侵蚀B.断层、褶皱、岩浆侵入、堆积、侵蚀C.断层、褶皱、侵蚀、堆积、岩浆侵入D.褶皱、断层、侵蚀、堆积、岩浆侵入8.图中()A.甲处景观在高温、高压条件下形成B.地质演化过程中发生过两次褶皱C.形成花岗岩的物质主要来自地壳D.乙处岩石经历变质作用可成为板岩海岸是海陆相互作用地带,贝壳堤是由海洋里大量甲壳生物的遗骸经过多种地质作用形成的,它是古海岸的遗迹。

人教版高中英语必修第一册同步训练UNIT4 Section Ⅲ 含答案

SectionⅢDiscovering Useful Structures课后·训练提升一、单句语法填空1.Kate,brother I shared an apartment with,has come to my rescue.答案:whose2.The soldiers are busy looking for (survive) in the ruins.答案:survivors3.You should not do anything will make others upset.答案:that4.Those want to attend the party should sign your name here.答案:who5.He has written two novels,the first of is a best-seller.答案:which6.Do you know the man is talking with your mother?答案:who/that7.I like those books topics are about history.答案:whose8.The girl,graduated from Cambridge University,is called Amanda.答案:who9.This is the person you should thank for helping your son.答案:who/whom10.Look,here are some people I want you to meet.答案:who/whom/that11.Do you still remember the chicken farm we visited three months ago?答案:that/which二、用适当的关系代词填空The shopping mall,1. atmosphere many people enjoyed,was on fire last week because the gas pipes 2.were used too long cracked.Those 3.were shopping in it were trapped.It was such a big fire that it seemed as if the world came to an end.Many goods 4.were on sale were destroyed.This was the biggest fire 5. people had everseen.Luckily,the firefighters 6. received the emergency call came at once.They did 7.they could to put out the fire.To our relief,no one was injured or dead.答案:1.whose 2.which/that 3.who 4.which/that 5.that 6.who/that7.what 三、阅读理解The earthquake is one of the most common natural disasters.It may cause great damage.So it is wise to learn some simple safety tips to protect yourself or your family members.Fragile items like those made of glass are easily broken and should usually be placed on a lower surface,near the ground instead of being placed on the cupboards higher up.Never place them near your bed,sofas and other furniture where you would be sitting or lying down.When there is a strong movement,these pieces will fall on the floor directly and not on you.There is a strong chance of short circuits(短路) and fire during an earthquake.Make sure you turn off electrical connections and gas immediately when an earthquake happens.During an earthquake,lie beneath an object that is not easily damaged.Do not go near objects that could directly fall on you.Never use the elevator to go down.Stay inside until the shaking stops and it is safe to go outside.Research has shown that most injuries happen when people inside buildings try to go e the staircases at all times.If you are outdoors,do not take shelter under a tree,streetlights,electric poles or tall buildings.If you are driving,stop your car and stay in a safe place.Do not park your car under a tree or any tall object.If trapped in debris(瓦砾堆),cover your mouth with a handkerchief or clothing.Tap on a pipe or the wall so that rescuers can find e a whistle if one is available.Never shout for help.Shouting can cause you to breathe in dangerous amounts of dust.Do not light a match because you may burn yourself.Do not move about or kick up dust.1.The purpose of the passage is to tell readers .A.the damage caused by earthquakesB.the rescue work after earthquakesC.how to prevent earthquakesD.what to do about earthquakes答案:D解析:写作意图题。

人教版高中英语选择性必修第一册同步训练UNIT1 Section Ⅲ 含答案

SectionⅢUsing Language,Assessing Your Progress&Video Time课后·训练提升一、单词拼写.Peter got a large s of money from his uncle..Mrs White is a quiet and g lady who likes reading in spare time.one of my old friends on the way to school this morning..Sue decided to apply for a p on her new invention of a practical item.(political).’s theory of (relative) is now generally accepted.a position at The New York Times.the circumstances we may say that man can conquer nature.the high standard of entries for the competition.1.我的老师看起来好像完全知道这件事了。

My teacher looked the thing2.据报道,这种产品已投入使用。

that the product has been put into use.3.我进去时发现一个陌生的女孩坐在角落里。

in the corner.4.这次会议总结了你们的经验。

your experience.5.音乐占广播节目的30%。

thirty percent of the broadcasting programmes.The journey my daughter Cathy has had with her swimming is as long as it is beautiful.Cathy suffered some terrible 1in her early childhood.After years of regular treatment,she finally became healthy.Two years ago,while Cathy was watching television,a dream came into her sweet little head—to be a st summer,she wanted to 2our local swim team.She practised hard and finally 3it.The team practice,however,was a rough start.She coughed and choked and could hardly 4her first few weeks.Hearing her coughing bitterly one night,I decided to pull her from it all.But Cathy woke me up early next morning,wearing her swimsuit 5to go!I told her she shouldn’t swim after a whole night’s coughing,but she refused to 6and insisted she go.From that day on,Cathy kept swimming and didn’t 7 a single practice.She had a 8 intention within herself to be the best she could be.My ten-year-old daughter was growing and changing right before my eyes,into this 9human being with a passion and a mission.There were moments of 10of course:often she would be the last swimmer in the race.It was difficult for Cathy to accept that she wasn’t a 11—ever.But that didn’t stop her from trying.Then came the final awards ceremony at the end of the year.Cathy didn’t expect any award but was still there to 12her friends and praise their accomplishments.As the ceremony was nearing the end,I suddenly heard the head coach 13,“The highest honour goes to Cathy!”Looking around,he continued,“Cathy has inspired us with her will and enthusiasm.14skills and talents bring great success,the most valuable asset(财富) one can hold is the heart.”It was the greatest 15of my daughter’s life.With all she had been through in her ten years,this was the hour of true triumph(成功).1.A.failure B.pressureD.illness“After years of regular treatment, she finally became healthy.”可知,Cathy在童年的时候患有某种严重的疾病。

人教版高中英语选择性必修第一册同步训练UNIT1 Section Ⅱ含答案

SectionⅡLearning About Language课后·训练提升一、单句语法填空.The engineer,leg was badly hurt,was quickly sent to hospital..The city,is far away,is very beautiful..Tom has made rapid progress,makes me very happy.5.We will be shown around the city:schools museums and some other places,other1.It is widely known that the moon is closer to Earth than the sun.,the moon is closer to Earth than the sun.2.The factory has over 8,000 workers and eighty percent of them are women.→The factory has over 8,000 workers,3.He said that he had never seen her before.It was not true.→He said that he had never seen herbefore,.4.Bob’s father spent four years in Egypt.He worked on the project.→Bob’s father,,spent5.He went to America;there he was noticed by an important film director.→He went to America,by anJennifer Mauer has needed more willpower than the typical college student to pursue her goal of earning a nursing degree.That willpower bore fruit when Jennifer graduated from University of Wisconsin-Eau Claire and became the first in her large family to earn a bachelor’s degree.Mauer,of Edgar,Wisconsin,grew up on a farm in a family of 10 children.Her dad worked at a job away from the farm,and her mother ran the farm with the kids.After high school,Jennifer attended a local technical college,working to pay her tuition(学费),because there was no extramoney set aside for a college education.After graduation,she worked to help her sisters and brothers pay for their schooling.Jennifer now is married and has three children of her own.She decided to go back to college to advance her career and to be able to better support her family while doing something she loves:nursing.She chose the UW-Eau Claire programme at Ministry Saint Joseph’s Hospital in Marshfield because she was able to pursue her four-year degree close to home.She could drive to class and be home in the evening to help with her kids.Jennifer received great support from her family as she worked to earn her degree:Her husband worked two jobs to cover the bills,and her 68-year-old mother helped take care of the children at times.Through it all,she remained in good academic standing and graduated with honours.Jennifer sacrificed(牺牲) to achieve her goal,giving up many nights with her kids and missing important events to study.“Some nights my heart was breaking to have to pick between my kids and studying for exams or papers,”she says.However,her children have learnt an important lesson witnessing their mother earn her degree.Jennifer is a first-generation graduate and an inspiration to her family—and that’s pretty powerful.1.What did Jennifer do after high school?A.She helped her dad with his work.B.She ran the family farm on her own.C.She supported herself through college.“After high school,Jennifer attended a local technical college,working to pay her tuition,because...for a college education.”可知,高中毕业后,詹尼弗到当地的技术学院上学,由于家里没有额外的钱供应她的大学教育,她边打工边上学。

人教版高中英语必修第一册同步训练UNIT 1 Section Ⅰ 含答案

UNIT 1TEENAGE LIFESectionⅠListening and Speaking课后·训练提升一、根据句意及首字母提示写出单词1.T are often warned of the danger of drugs.答案:Teenagers2.We must d the question with the rest of the workers.答案:debate3.We haven’t found a s place for the picnic yet.答案:suitable4.There was a sudden m behind the door.答案:movement5.Susan gave up her well-paid job and was working as a v in the neighbourhood when I visited her.答案:volunteer6.I’ve a visited many countries in Europe.答案:actually7.They said they like the c of your article,but the style wasn’t quite right for the magazine.答案:content8.I p studying English at home to watching the match.答案:prefer二、完成句子1.我拿不定主意要选哪一个。

I ca n’t .答案:decide which one to choose2.我宁愿外出钓鱼也不愿在家看电视。

I to watching TV at home. 答案:would prefer going fishing3.他们正在琢磨如何去栽这棵苹果树。

They to plant the apple tree.答案:are wondering how4.你觉得哪个俱乐部适合亚当?Which club do you think Adam?答案:is suitable for5.事实上,我更喜欢表演,但我的朋友们去芭蕾舞俱乐部,我想和他们在一起。

人教版高中数学选择性必修第一册1.1.1空间向量及其线性运算精讲精练同步训练

人教版高中数学选择性必修第一册1.1.1空间向量及其线性运算精讲精练同步训练【考点梳理】考点一空间向量的概念1．定义：在空间，具有大小和方向的量叫做空间向量．2．长度或模：向量的大小．3．表示方法：①几何表示法：空间向量用有向线段表示；②字母表示法：用字母a ，b ，c ，…表示；若向量a 的起点是A ，终点是B ，也可记作AB →，其模记为|a |或|AB →|.4．几类特殊的空间向量名称定义及表示零向量长度为0的向量叫做零向量，记为0单位向量模为1的向量称为单位向量相反向量与向量a 长度相等而方向相反的向量，称为a 的相反向量，记为－a 共线向量(平行向量)如果表示若干空间向量的有向线段所在的直线互相平行或重合，那么这些向量叫做共线向量或平行向量．规定：对于任意向量a ，都有0∥a相等向量方向相同且模相等的向量称为相等向量考点二空间向量的线性运算空间向加法a ＋b ＝OA →＋AB →＝OB→量的线性运算减法a －b ＝OA →－OC →＝CA →数乘当λ>0时，λa ＝λOA →＝PQ →；当λ<0时，λa ＝λOA →＝MN →；当λ＝0时，λa ＝0运算律交换律：a ＋b ＝b ＋a ；结合律：a ＋(b ＋c)＝(a ＋b )＋c ，λ(μa )＝(λμ)a ；分配律：(λ＋μ)a ＝λa ＋μa ，λ(a ＋b )＝λa ＋λb .考点三共线向量1．空间两个向量共线的充要条件对于空间任意两个向量a ，b (b ≠0)，a ∥b 的充要条件是存在实数λ，使a ＝λb .2．直线的方向向量在直线l 上取非零向量a ，我们把与向量a 平行的非零向量称为直线l 的方向向量．考点四共面向量1．共面向量如图，如果表示向量a 的有向线段OA →所在的直线OA 与直线l 平行或重合，那么称向量a 平行于直线l .如果直线OA 平行于平面α或在平面α内，那么称向量a 平行于平面α.平行于同一个平面的向量，叫做共面向量．2．向量共面的充要条件如果两个向量a ，b 不共线，那么向量p 与向量a ，b 共面的充要条件是存在唯一的有序实数对(x ，y )，使p ＝x a ＋y b .【题型归纳】题型一：空间向量的有关概念1．给出下列命题：①空间向量就是空间中的一条有向线段；②在正方体1111ABCD A B C D -中，必有11=AC AC ；③a b =是向量a b =的必要不充分条件；④若空间向量,,m n p 满足,∥∥m n n p ，则∥m p ．其中正确的命题的个数是A ．1B ．2C ．3D ．02．给出下列命题①空间中所有的单位向量都相等；②方向相反的两个向量是相反向量；③若,a b 满足a b >，且,a b 同向，则a b >；④零向量没有方向；⑤对于任意向量,a b ，必有a b a b +≤+．其中正确命题的序号为（）A ．①②③B ．⑤C ．④⑤D ．①⑤3．下列关于空间向量的说法中正确的是（）A ．若向量a ，b 平行，则a ，b 所在直线平行B ．若||||a b =，则a ，b 的长度相等而方向相同或相反C ．若向量AB ，CD 满足AB CD >，则AB CD >D ．相等向量其方向必相同题型二：空间向量的线性运算（加减法）4．如图，在正方体1111ABCD A B C D -中，点M ，N 分别是面对角线1A B 与11B D 的中点，若DA a =，DC b =，1DD c =，则MN =（）A ．()12c b a +-B ．()12a b c +-C ．()12a c -D ．()12c a -5．空间四边形ABCD 各边及对角线长均为2，E ，F ，G 分别是AB ，AD ，DC 的中点，则GE GF ⋅=（）A ．12B ．1C ．2D ．226．空间四边形OABC 中，,,OA a OB b OC c ===.点M 在OA 上，且2OM MA =，N 为BC 的中点，则MN 等于（）A ．12a -2132b c+B ．-211322a b c++C ．12a 12b +-23cD ．2233a b +-12c题型三：空间两个向量共线的有关问题7．已知空间向量a ，b ，且2AB a b =+，56BC a b =-+，72CD a b =-，则一定共线的三点是（）.A ．A ､B ､DB ．A ､B ､CC ．B ､C ､DD ．A ､C ､D8．已知空间中两条不同的直线,m n ，其方向向量分别为,a b →→，则“,R a b λλ→→∀∈≠”是“直线,m n 相交”的（）A ．.充分而不必要条件B ．必要而不充分条件C ．充分必要条件D ．既不充分也不必要条件9．下列命题中正确的是（）.A ．若a 与b 共线，b 与c 共线，则a 与c 共线.B ．向量a ，b ，c 共面，即它们所在的直线共面C ．若两个非零空间向量AB 与CD 满足0AB CD +=，则//C B D A D ．若//a b ，则存在唯一的实数λ，使a bλ=题型四：空间共面向量定理10．已知A 、B 、C 三点不共线，点O 是平面ABC 外一点，则在下列各条件中，能得到点M 与A 、B 、C 一定共面的是（）A ．111222OM OA OB OC =++B ．1313O OB OCM OA =-+C ．OM OA OB OC =++D ．2OM O OB OCA =--11．下列结论错误的是（）.A ．三个非零向量能构成空间的一个基底，则它们不共面B ．两个非零向量与任何一个向量都不能构成空间的一个基底，则这两个向量共线C ．若a ､b 是两个不共线的向量，且c a b λμ=+r r r(R λμ∈、且0λμ⋅≠)，则{}a b c ，，构成空间的一个基底D ．若OA ､OB ､OC 不能构成空间的一个基底，则O ､A ､B ､C 四点共面12．在下列结论中：①若向量,a b 共线，则向量,a b 所在的直线平行；②若向量,a b 所在的直线为异面直线，则向量,a b 一定不共面；③若三个向量,,a b c r v v 两两共面，则向量,,a b c rv v 共面；④已知空间的三个向量,,a b c rv v ，则对于空间的任意一个向量p 总存在实数x ，y ，z 使得p xa yb zc =++u r rv v ．其中正确结论的个数是（）A ．0B ．1C ．2D ．3【双基达标】一、单选题13．在正方体ABCD —A 1B 1C 1D 1中，已知下列各式：①()1AB BC CC ++；②()11111AA A D D C ++；③()111AB BB B C ++；④()11111AA A B B C ++.其中运算的结果为向量1AC uuu r的有（）A ．1个B ．2个C ．3个D ．4个14．①若A ､B ､C ､D 是空间任意四点，则有0AB BC CD DA +++=；②a b a b -=+是a ､b 共线的充要条件；③若a ､b 共线，则a 与b 所在直线平行；④对空间任意一点O 与不共线的三点A ､B ､C ，若OP xOA yOB zOC =++uu u r uu r uu u r uuu r（其中x ､y ､z ∈R ），则P ､A ､B ､C 四点共面.其中不正确命题的个数是（）A ．1B ．2C ．3D ．415．若空间中任意四点O ，A ，B ，P 满足OP ＝m OA ＋n OB ，其中m ＋n ＝1，则（）A ．P ∈直线AB B ．P ∉直线ABC ．点P 可能在直线AB 上，也可能不在直线AB 上D ．以上都不对16．在正方体1111ABCD A B C D -中，点P 满足113AP AB AA λ=+（[]0,1λ∈）若平面//BDP 平面11B CD ，则实数λ的值为（）A ．14B ．13C ．12D ．2317．如图，在平行六面体ABCD -A ′B ′C ′D ′中，设AB a →=，AD b →=r ，AA c →'=，则下列与向量A C →'相等的表达式是（）A ．a b c -++B ．a b c--+C ．a b c --D ．a b c+-r r r 18．如图，在四面体OABC 中，M ，N 分别是OA ，BC 的中点，则MN =（）A ．111222OB OC OA+-B ．111222OA OC OB--C ．111222OB OC OA++D ．111222OA OC OB+-19．已知空间四边形ABCD 中，AB a =，CB b =，AD c =uuu r r，则CD 等于（）A ．a b c +-B ．a b c --+C ．a b c -++D ．a b c-+-20．下列说法：①若两个空间向量相等，则表示它们有向线段的起点相同，终点也相同；②若向量AB →，CD →满足AB CD →→>，且AB →与CD →同向，则AB CD →→>；③若两个非零向量AB →与CD →满足0AB CD →→→+=，则AB →，CD →为相反向量；④AB CD →→=的充要条件是A 与C 重合，B 与D 重合.其中错误的个数为（）A ．1B ．2C ．3D ．421．在空间四边形OABC 中，,,OA a OB b OC c ===，点M 在OB 上，且3OM MB =，N 为AC 的中点，则NM =（）A ．131242a b c-+-B ．121232a b c-++C ．131242a b c++D ．121232a b c-+22．如图，在平行六面体1111ABCD A B C D -中，1AA a =，AB b =，AD c =uuu r r点P 在1AC 上，且1:2:3A P PC =，则AP =（）．A ．233555a b c++B ．322555a b c++C ．223555a b c-++D ．322555a b c--【高分突破】一：单选题23．四棱锥P ABCD -中，底面ABCD 是平行四边形，点E 为棱PC 的中点，若23AE x AB yBC z AP =++，则x y z ++等于（）A ．1B ．1112C ．116D ．224．已知正方体1111ABCD A B C D -中，11114AE A C =，若1()AE x AA y AB AD =++，则（）A ．1x =，12y =B ．12x =，y =1C ．1x =，13y =D ．1x =，14y =25．如图，在平行六面体1111ABCD A B C D -中，M 在AC 上，且12AM MC =，N 在1A D 上，且12A N ND =．设AB a =，AD b =，1AA c =，则MN =A ．111333a b c-++B ．1133a b c+-C ．112333a b c--D ．1133a b c-++26．在四面体OABC 中，空间的一点M 满足1146OM OA OB OC λ=++，若M ，A ，B ，C 共面，则λ=（）A ．712B ．13C ．512D ．1227．在正方体1111ABCD A B C D -中，若点M 是侧面11CDD C 的中心，且1AM x AA y AD z AB =-+，则,,x y z 的值分别为（）A ．12，1，12-B ．12，1-，12-C ．12-，1，12D ．12，1-，1228．已知点P 为三棱O -ABC 的底面ABC 所在平面内的一点，且()12OP OA mOB nOC m n R =+-∈，，则m n ，的值可能为（）A ．112m n ==-，B ．112m n ==，C ．112m n =-=-，D ．312m n =-=-，29．如图，在三棱柱111ABC A B C -中，M 为11AC 的中点，设1,,AB a AA c BC b ===，则下列向量与BM 相等的是（）A ．1122-++a b cB ．1122a b c++C ．1122a b c--+D ．1122a b c-+30．空间A 、B 、C 、D 四点共面，但任意三点不共线，若P 为该平面外一点且5133PA PB xPC AD =--，则实数x的值为()A ．13B ．13-C ．23D ．23-31．在平行六面体1111ABCD A B C D -中，M 为AC 与BD 的交点，若11A B a =，11A D b =，1A A c =，则下列向量中与1B M 相等的向量是（）A ．1122-++a b cB ．1122a b c++C ．1122a b c-+D ．1122a b c--+32．如图，在空间四边形OABC 中，OA a =，OB b =，OC c =．点M 在OA 上，且2OM MA =，N 是BC 的中点，则MN =（）A ．121232a b c-+B ．211322a b c-++C ．112223a b c+-D ．221332a b c+-二、多选题33．如图所示，M 是四面体OABC 的棱BC 的中点，点N 在线段OM 上，点P 在线段AN 上，且3AP PN =，23ON OM =，设OA a =，OB b =，OC c =，则下列等式成立的是（）A ．1122OM b c =-B ．1133AN b c a=+-C ．113444AP b c a=--D ．111444OP a b c=++34．已知正方体1111ABCD A B C D -的中心为O ，则下列结论中正确的有（）A ．OA OD +与11OB OC +是一对相反向量B ．OB OC -与11OA OD -是一对相反向量C ．OA OB OC OD +++与1111OA OB OC OD +++是一对相反向量D ．1OA OA -与1OC OC -是一对相反向量35．如图，在正方体1111ABCD A B C D -中，下列各式中运算的结果为1AC uuu r的有A ．AB BC CD++B ．11111AA B C D C ++C ．111AB C C B C -+D ．111AA DC B C ++36．已知A ，B ，C 三点不共线，O 为平面ABC 外的任一点，则“点M 与点A ，B ，C 共面”的充分条件的是（）A ．2OM OA OB OC=--B ．OM OA OB OC =+-C ．1123OM OA OB OC =++D ．111236OM OA OB OC =++三、填空题37．如果两个向量,a b 不共线，则p 与,a b 共面的充要条件是___________.38．已知非零向量1e ，2e 不共线，则使12ke e +与12e ke +共线的k 的值是________．39．在三棱锥A -BCD 中，若△BCD 是正三角形，E 为其中心，则AB ＋12BC －32DE －AD 化简的结果为________.40．已知点M 在平面ABC 内，并且对不在平面ABC 内的任意一点O ，都有1133AM xOA OB OC =++，则x 的值为_______．41．如图，M 是四面体OABC 的棱BC 的中点，点N 在线段OM 上，点P 在线段AN 上，且12MN ON =，34AP AN =，用向量OA ，OB ，OC 表示OP ，则OP =_______．四、解答题42．在空间四边形ABCD 中，连结AC ､BD ，BCD 的重心为G ，化简1322AB BC DG AD +--.43．如图所示，在三棱柱111ABC A B C -中，M 是1BB 的中点，化简下列各式：（1）1AB BA +；（2）111AB B C C C ++；（3）AM BM CB --；（4）112AA AB AM +-．44．如图，在正方体ABCD -A 1B 1C 1D 1中，E 在A 1D 1上，且112A E ED =，F 在对角线A 1C 上，且123A F FC =，求证：E ，F ，B 三点共线.45．如图，已知,,,,,,,,O A B C D E F G H 为空间的9个点，且,,OE kOA OF kOB OH kOD ===，,,0,0AC AD m AB EG EH mEF k m =+=+≠≠，求证：（1）,,,A B C D 四点共面，,,,E F G H 四点共面；（2）AC EG ∥；（3）OG kOC =.【答案详解】1．B【详解】有向线段可以表示向量，但不是向量，故①不正确；根据正方体1111ABCD A B C D -中，向量AC 与11AC 的方向相同，模也相等，则11AC AC=，故②正确；命题③显然正确；命题④不正确，向量的平行不具有传递性，比如当n 为零向量时，零向量与任何向量都平行，则,m n 不一定平行．故选B ．2．B【详解】对于①，长度相等，方向也相同的向量才是相等的向量，两个单位向量，方向不同时，不相等，故①错误；对于②，长度相等且方向相反的两个向量是相反向量，仅仅方向相反不是相反向量，故②错误；对于③，向量是既有大小有有方向的量，向量的长度(模)能够比较大小，但向量不能比较大小的，故③错误；对于④，根据规定，零向量与任意向量都平行，故零向量是有方向的，只是没有确定的方向，故④错误；对于⑤，a b a b +≤+为向量模的不等式，由向量的加法的几何意义可知是正确的，故⑤正确．综上，正确的命题只有⑤，故选：B .3．D【详解】A 中，对于非零向量a ，b 平行，则a ，b 所在的直线平行或重合；B 中，||||a b =只能说明a ，b 的长度相等而方向不确定；C 中，向量作为矢量不能比较大小；D 中，由相等向量的定义知：方向必相同；故选：D.4．D【详解】因为点M ，N 分别是面对角线1A B 与11B D 的中点，DA a =，DC b =，1DD c =，所以11MN MB BB B N=++111111 22A B BB B D =++()()111122A A AB BB BC CD =++++()()1122c b c a b =-+++--()12c a =-故选:D.5．A【详解】空间四边形ABCD 各边及对角线长均为2，所以四边形ABCD 构成的四面体ABCD 是正四面体，四个面是等边三角形，因为E ，F ，G 分别是AB ，AD ，DC 的中点，所以//AC FG ，1//2AC FG ，()1122GE GB BE BC BD BA =+=-++，12GF CA =，所以()()1144GE GF BC BD BA CA BC CA BD CA BA CA ⋅=-+-⋅=-⋅+⋅-⋅()14BC CA BD BA BC BA CA ⎡⎤=-⋅+⋅--⋅⎣⎦()14BC CA BD BA BD BC BA CA =-⋅+⋅-⋅-⋅()1cos120cos 60cos 60cos 604BC CA BD BA BD BC BA CA =-⋅+⋅-⋅-⋅1111112222422222⎛⎫=--⨯+⨯-⨯-⨯= ⎪⎝⎭.故选：A.6．B解：因为2OM MA =，所以2233OM OA a ==,N 为BC 的中点，则()111222ON OB OC b c =+=+，()2121132322MN MO ON OA OB OC a b c =+=-++=-++.故选：B.7．A【详解】因为242BD BC CD a b AB =+=+=，所以//BD AB ，又,BD AB 有公共点B ，所以A ､B ､D 三点共线，故选项A 正确；显然,AB BC 不共线，所以A 、B 、C 三点不共线，故选项B 错误；显然,BC CD 不共线，所以B 、C 、D 三点不共线，故选项C 错误；因为48AC AB BC a b =+=-+，所以,AC CD 不共线，从而A 、C 、D 三点不共线，故选项D 错误.故选：A.8．B【详解】由,R a b λλ→→∀∈≠可知，a 与b 不共线，所以两条不同的直线,m n 不平行，可能相交，也可能异面，所以“,R a b λλ→→∀∈≠”不是“直线,m n 相交”的充分条件；由两条不同的直线,m n 相交可知，a 与b 不共线，所以,R a b λλ→→∀∈≠，所以“,R a b λλ→→∀∈≠”是“直线,m n 相交”的必要条件，综上所述：“,R a b λλ→→∀∈≠”是“直线,m n 相交”的必要不充分条件.故选：B.9．CA 中，若0b =，则a 与c 不一定共线；B 中，共面向量的定义是平行于同一平面的向量，表示这些向量的有向线段所在的直线不一定共面；C 中，∵0AB CD +=，∴AB CD =-，∴AB 与CD 共线，故//C B D A 正确；D 中，若0b =，0a ≠，则不存在λ，使a b λ=.故选：C10．B【详解】若1x y z ++=，且OM xOA yOB zOC =++，则()1OM xOA yOB x y OC =++--，则()()OM OC x OA OC y OB OC -=-+-，即xCA yCB CM =+，所以，点M 、A 、B 、C 共面.对于A 选项，1111222++≠，A 选项中的点M 、A 、B 、C 不共面；对于B 选项，111133-+=，B 选项中的点M 、A 、B 、C 共面；对于C 选项，1111++≠，C 选项中的点M 、A 、B 、C 不共面；对于D 选项，2111--≠，D 选项中的点M 、A 、B 、C 不共面.故选：B.11．C【详解】A 选项，三个非零向量能构成空间的一个基底，则三个非零向量不共面，故A 正确；B 选项，三个非零向量不共面，则此三个向量可以构成空间的一个基底，若两个非零向量与任何一个向量都不能构成空间的一个基底，则这三个向量共面，则已知的两个向量共线，如图，故B 正确；C 选项，∵满足c a b λμ=+r r r ，∴a ，b ，c 共面，不能构成基底，故C 错误，D 选项，因为OA ､OB ､OC 共起点，若O ，A ，B ，C 四点不共面，则必能作为空间的一个基底，故D 正确，故选C .12．A【详解】平行向量就是共线向量，它们的方向相同或相反，未必在同一条直线上，故①错．两条异面直线的方向向量可通过平移使得它们在同一平面内，故②错.三个向量两两共面，这三个向量未必共面，如三棱锥P ABC -中，,,PA PB PC 两两共面，但它们不是共面向量，故③错．根据空间向量基本定理，,,a b c 需不共面才成立，故④错．故选:A ．13．D【详解】①：()111AB BC CC AC CC AC ++=+=，故①正确；②：()111111111AA A D D C AD D C AC ++=+=，故②正确；③：()1111111AB BB B C AB B C AC ++=+=，故③正确；④：()111111111AA A B B C AB B C AC ++=+=，故④正确.所以4个式子的运算结果都是1AC ，故选：D.14．C【详解】①中四点恰好围成一封闭图形，正确；②中当a ､b 同向时，应有a b a b +=+，故错误；③中a ､b 所在直线可能重合，故错误；④中需满足1x y z ++=，才有P ､A ､B ､C 四点共面，故错误.故选：C15．A【详解】因为m ＋n ＝1，所以m ＝1－n ，所以OP →＝(1－n )·OA →＋n OB →，即OP OA →→-＝n (OB OA →→-)，即AP n AB →→=，所以AP →与AB →共线．又AP →，AB →有公共起点A ，所以P ，A ，B 三点在同一直线上，即P ∈直线AB .故选：A16．D【详解】如下图，由正方体性质知：面11//B CD 面1BDA ，要使面//BDP 面11B CD，∴P 在面1BDA 上，即1,,P B A 共面，又113AP AB AA λ=+，[]0,1λ∈，∴113λ+=，可得23λ=.故选：D17．D【详解】由题意：A C A A AB BC AA AB AD c a b a b c→→→→→→→'''=++=-++=-++=+-故选：D.18．A【详解】在四面体OABC 中，M ，N 分别是OA ，BC 的中点，()()11112222111111222222MN MA AN OA AB AC OA OB OA OC OA OA OB OC OA OB OC OA ∴=+=++=+-+-=++-=+-故选：A ．19．C【详解】由向量的运算法则，可得CD CB BA AD CB AB AD a b c =++=-+=-++.故选：C.20．C【详解】①错误.两个空间向量相等，其模相等且方向相同，但与起点和终点的位置无关.②错误.向量的模可以比较大小，但向量不能比较大小.③正确.0AB CD →→→+=，得AB CD →→=-，且AB →，CD →为非零向量，所以AB →，CD →为相反向量.④错误.由AB CD →→=，知AB CD →→=，且AB →与CD →同向，但A 与C ，B 与D 不一定重合.故选：C21．A 【详解】()()31311314242242NM OM ON OB OA OC b a c a b c =-=-+=-+=-+-.故选：A22．B【详解】因为1:2:3A P PC =，可得1125A P A C =，根据空间向量的运算法则，可得111125AP AA A P AA A C =+=+112()5AA AC AA =+-1111323232322()()555555555AA AC AA AB BC AA AB AD AA AB BC =+=++=++==++，又由1AA a =，AB b =，AD c =uuu r r ，所以322555AP a b c =++.故选：B.23．B【详解】因为()AE AB BC CE AB BC EP AB BC AP AE=++=++=++-，所以2AE AB BC AP =++，所以111222AE AB BC AP =++，所以111,2,3222x y z ===，解得111,,246x y z ===，所以11111++24612x y z ++==，故选：B.24．D【详解】由空间向量的运算法则，可得11111111()44AE AA A E AA AC AA AB AD =+=+=++，因为1()AE x AA y AB AD =++，所以11,4x y ==.故选：D.25．A【详解】解：因为M 在AC 上，且12AM MC =，N 在1A D 上，且12A N ND =，所以13AM AC =，1123A N A D =，在平行六面体1111ABCD ABCD -中，AB a =，AD b =，1AA c =，所以AC a b =+u u u r r r ，1A D b c =-，所以11111233MN MA AA A N AC AA A D =++=-++12()()33a b c b c =-+++-111333a b c =-++，故选：A ．26．A因为M ，A ，B ，C 共面，则11146λ++=，得712λ=.故选：A【点睛】本题考查空间四点共面定理，属于基础题型.27．D【详解】如图，在正方体中，AM AB BC CM =++，BC AD =，()()111122CM CD CC AB AA =+=-+，所以()112AM AB AD AB AA =++-+11122AB AD AA =++,所以12x =，1y =-，12z =故选：D28．C 【详解】()12OP OA mOB nOC m n R =+-∈，，且P ，A ，B ，C 共面，∴11122m n m n +-=⇒-=，只有1 12m n =-=-，符合，故选：C.29．A【详解】因为1,,AB a AA c BC b ===，如图，依题意，有()11111111111122BM BA AA A M BA AA A C BA AA B C B A =++=++=++-()111111122222BA AA BC BA AB BC AA a b c =++-=-++=-++．故选：A30．C【详解】因为空间A 、B 、C 、D 四点共面，但任意三点不共线，则AB m AC n AD =+，又点P 为该平面外一点，则()PA PB m PC PA nAD -=-+，所以(1)m PA PB mPC nAD +=++，又5133PA PB xPC AD =--，由平面向量的基本定理得：513x -=，即23x =，故选：C ．31．A 如图，由空间向量的线性运算可得：()1111111111111222B M B B BM A A BD A A B D c A D A B =+=+=+=+-，()111222c b a a b c =+-=-++，故选：A32．B【详解】由题，在空间四边形OAB ，OA a =，OB b =，OC c =．点M 在OA 上，且2OM MA =，N 是BC 的中点，则1122ON c b =+．所以211322MN ON MO a b c =+=-++故选：B【点睛】本题主要考查空间向量加法与减法运算，需理解向量加法与减法的几何意义，属于基础题.33．BD【详解】由已知得，23AN ON OA OM OA =-=-211322OB OC OA ⎛⎫=+- ⎪⎝⎭1133OB OC OA =+-1133b c a =+-，分析各个选项：对于A ，利用向量的四边形法则，11112222OM OB OC b c =+=+，A 错；对于B ，利用向量的四边形法则和三角形法则，得23AN ON OA OM OA =-=-211322OB OC OA ⎛⎫=+- ⎪⎝⎭1133OB OC OA =+-1133b c a =+-，B 对；对于C ，因为点P 在线段AN 上，且3AP PN =，所以，411333AN AP b c a ==+-，所以，311114333444AP b c a b c a ⎛⎫=+-=+- ⎪⎝⎭，C 错；对于D ，113444OP OA AP a b c a =+=++-111444a b c =++，D 对故选：BD34．ACD∵O 为正方体的中心，∴1OA OC =-，1OD OB =-，故()11OA OD OB OC +=-+，同理可得()11OB OC OA OD +=-+，故()1111OA OB OC OD OA OB OC OD +++=-+++，∴A 、C 正确；∵OB OC CB -=uu u r uuu r uu r ，1111OA O A D D =-，∴OB OC -与11OA OD -是两个相等的向量，∴B 不正确；∵11OA OA AA =-，111OC OC C C AA -==-，∴()11OA OA OC OC -=--，∴D 正确.故选：ACD35．BCD【详解】A ．1A AB BC CD AD C ++=≠，故错误；B ．11111111111AA BC DC AA AD DC AC ++=++=，故正确；C ．1111111111AB C C BC AB CC BC AB BB BC AC -+=++=++=，故正确；D ．111111111AA DC BC AA AB BC AC ++=++=，故正确.故选：BCD.36．BD【详解】当MA m MB n MC =+时，可知点M 与点,,A B C 共面，所以()()MO OA m MO OB n MO OC +=+++，所以()1x y OM OA xOB yOC +-=-++，所以11111OA mOB nOC m n OM OA OB OC m n m n m n m n -++==-+++-+-+-+-，不妨令11x m n -=+-，1m y m n =+-，1n z m n =+-，且此时1x y z ++=，因为()()21101+-+-=≠，()1111++-=，111111236++=≠，1111236++=，由上可知：BD 满足要求.故选：BD.37．由空间向量共面定理可得，若向量,a b 不共线，则p 与,a b 共面的充要条件是存在实数对(),x y ，使p xa yb =+.故答案为：存在实数对(),x y ，使p xa yb =+.38．±1【详解】若12ke e +与12e ke +共线，则()1212ke e e ke λ+=+因为非零向量1e ，2e 不共线，所以1k k λλ=⎧⎨=⎩，即21k =，所以1k =±，故答案为：±139．0【详解】如图，取BC 的中点F ，连结DF ，则DF 必经过点E ，则32DF DE =，∴1322AB BC DE AD +--AB BF DF DA =+-+AF FD DA =++0=.故答案为：0.40．23-由题设，1133AM OM OA xOA OB OC =-=++，∴11(1)33OM x OA OB OC =+++，又,,,A B C M 共面，∴111133x +++=，可得23x =-.故答案为：23-41．111444OA OB OC ++【详解】由题意OP ()33132132=444434432OB OC OA AN OA ON OA OA OM OA ++=+-=+⨯=+⨯⨯=111444OA OB OC ++故答案为：111444OA OB OC ++42．0【详解】设E 为BC 的中点，则12BC BE =，又G 为BCD △的重心，则32DG DE =，所以()()130.22AB BC DG AD AB BE DE AD AB BE AD DE AE AE +--=+--=+-+=-=43．（1）11AB BA AA +=．（2）111111111AB B C C C A B B C C C AC ++=++=．（3）AM BM CB AM MB BC AC --=++=．（4）1102AA AB AM BM AB MA AB BM MA +-=++=++=．44．设1,,AB a AD b AA c ===，∵112A E ED =，123A F FC =，∴11123A E A D =，1125A F A C =，而11A D AD b ==∴123A E b =，111222()()()555A F AC AA AB AD AA a b c =-=+-=+-.∴1122()53EF A F A E a b c =-=--,又1123EB EA A A AB a b c =++=--,∴25EF EB =，即E ，F ，B 三点共线.45．证明：（1）,0AC AD m AB m =+≠，∴A 、B 、C 、D 四点共面．,0EG EH mEF m =+≠，∴E 、F 、G 、H 四点共面．（2）()()()EF OH OE OF OE OD OA OB OA EG EH m m k km =+=-+-=-+-(),//k AD km AB k AD m AB k AC AC EG =+=+=∴.（3）()OG OE EG kOA k AC k OA AC kOC =+=+=+=.。

人教版高中英语必修第一册同步训练UNIT3 Section Ⅱ 含答案

SectionⅡReading and Thinking课后·训练提升一、根据句意及首字母提示写出单词1.Tom loves sports very much,and he is a natural a.答案:athlete2.She won the gold medal,so she was the c.答案:champion3.I have the h to be invited to attend her wedding.答案:honour4.The old man was presented a m because of his great achievements to his country.答案:medal5.It is not easy to m a foreign language.You need to try your best.答案:master二、完成句子1.乒乓球现在很受欢迎;国内外都有人打。

Ping-pong is popular now;it is played .答案:at home and abroad2.切记:“永远别放弃!继续努力。

”Do remember,“Never !Keep trying.”答案:give up3.不要丧失信心。

你应该努力解决问题。

Don’t .You should try to solve the problem.答案:lose heart4.为了表达对来访客人的尊敬,我们举办了一个欢迎会。

We held a welcome party the visiting guests. 答案:in honour of三、单句语法填空1.The sports meeting was put off because the foggy weather.答案:of2.It’s honour to have the chance to attend the party.答案:an3.Please send the (injure) to the nearest hospital.答案:injured4.It may take a few weeks for you to build up your (strong) again. 答案:strength5.As you know,(fail) is the mother of success.答案:failure6.In fact,these old scientists brought glory our country when they were young.答案:to7.Thomas,my close friend,is a young man with great (determine).答案:determination四、阅读理解When school started on that warm August day,I threw myself into everything I did,including playing volleyball.I decided to become beautiful,or at the veryleast,skinny.I stopped eating completely.Soon I began losing weight,which thrilled me,and I even grew to love the tiredness and light headedness that came with my poor diet,for those feelings meant that I was winning.As the season progressed,things had become tense between my head volleyball coach,Coach Smith,and me.She felt that something was wrong with my health.She talked with me about my eating and was angry that I wouldn’t listen to her when she tried to make me eat.She tried to persuade me in a determined way and so we fought constantly.Then my hunger started to affect my performance.I was so tired that practice and games were becoming a struggle.One afternoon,with hurt in hereyes,Coach Smith asked me what I had eaten and I told her nothing yet,but I was going to.She looked at me,disappointment in her eyes,knowing she couldn’t make me stop,and walked away.A couple of weeks later I attended a formal dinner for our volleyball team.I stood there as my coach managed to say something nice about me.I realised then that I had ruined my senior year by being disrespectful,and I had probably ruined hers as well.So that evening I wrote her a letter apologising and thanking her.Then one Saturday,as I was reading in the library,I felt someone gently take my arm and say softly,“Lynn Jones,how are you doing?” I looked up and saw the familiar face.“Thanks for the letter,” she said.“It meant a lot.”When I think of a coach,I think of someone above me,someone who gives instructions—not a friend.But Coach Smith is different,and,like any other good friend,she dealt with my problem in a determined way even when I hated her for it at that time.I didn’t deserve her kindness,but she gave it anyway.I will forever be grateful for her help,and now for her friendship.1.How did the author feel when she had a sense of tiredness?A.Ashamed.B.Proud.C.Funny.D.Nervous.答案:B解析:推理判断题。

人教版高中地理必修1全册同步练习题含答案

宇宙中的地球一、单项选择题（60分）1、以下天体系统中，不包含火星的是（）Ａ、太阳系Ｂ、河外星系Ｃ、银河系Ｄ、总星系2、下列各组行星中距太阳由远及近排序正确的是（）Ａ、金星、木星、冥王星、天王星Ｂ、天王星、土星、火星、地球Ｃ、水星、小行星带、土星、海王星Ｄ、地球、小行星带、火星、木星3、对地球影响最激烈的太阳活动是（）Ａ、太阳辐射Ｂ、黑子Ｃ、耀斑Ｄ、太阳内部的核聚变反应4、下列现象属于太阳活动对地球产生影响的是（）A、地球两极地区出现极昼极夜现象B、无线电长波通讯受到干扰C、大气中二氧化碳增多，气温升高D、干扰地球磁场，产生“磁暴”现象5人类探索宇宙的目的是（）A、了解地球表面的变化规律B、研究、认识、开发和利用宇宙空间环境Ｃ、地球人口太多，向宇宙转移Ｄ、保护地外文明6、下列自然资源中只存在于宇宙中而地球上没有的是 ( )Ａ、太阳能资源Ｂ、空间资源Ｃ、2HeＤ、3He7.9月23日至次年3月21日，能形成物影，且正午物体的影子始终朝北的地区是( )A.赤道以南地区B.赤道以北地区C.北回归线以北地区D.赤道至北极圈之间地区8、下列现象与地球自转无关的是（）Ａ、二月，海南岛已进入春耕播种时节，而黑龙江仍是一片冰天雪地Ｂ、北半球河流右岸受冲刷，左岸泥沙淤积Ｃ、中国球迷在清晨观看美国当地晚间篮球赛的电视直播Ｄ、一日内学校操场旗杆影子长度要变化9、地球表面太阳光直射范围的大小是由（）Ａ、人为规定的Ｂ、黄赤交角的大小决定的Ｃ、地球的球体形状大小造成的Ｄ、地球自转造成的10、北京（北纬40度）某中学，要在楼高为H的楼房背面盖一座新教学楼，欲使新楼底层全年太阳光线不被遮挡，应考虑（）A、春分日的正午太阳高度B、夏至日的正午太阳高度C、秋分日的正午太阳高度D、冬至日的正午太阳高度11、某地正午时，北京时间为15点，则该地的经度为（）A、115°EB、130°WC、75°ED、165°E12、下列地理现象中，能说明地球自转的是（）A、昼夜现象B、昼夜更替C、昼夜长短变化D、四季变化13、关于地球自转一周的正确叙述是（）①转了360°②需要24小时③转了360°59′④需要23小时56分4秒A、①②B、②③C、①④D、③④14、天安门广场上的国旗与太阳同时升起，下列日期中升旗仪式最早的是（）A、5月1日B、7月1日C、8月1日D、10月1日15、下图是某条河流的剖面图，一般面对河流下游，左手方视为左岸，右手方视为右岸。

高中物理人教(新课标)必修1同步练习：第四章专题板块模型

高中物理人教（新课标）必修1同步练习：第四章专题板块模型姓名:________ 班级:________ 成绩:________一、单选题 (共6题；共12分)1. （2分） (2017高二下·黄山期末) 如图所示，质量为M的框架放在水平地面上，一轻弹簧上端固定一个质量为m的小球，小球上下振动时，框架始终没有跳起．当框架对地面压力为零瞬间，小球的加速度大小为（）A . gB . gC . 0D . g【考点】2. （2分）(2019·昆明模拟) 在光滑水平面上有一质点处于静止状态，现施加一水平力F，力F随时间t按如图所示的余弦函数变化，则下列说法正确的是（）A . 在0〜4s内，力F做功为零B . 第2s末，质点的加速度最大C . 第4s末，质点的速度最大D . 在2s〜4s内，质点做加速运动【考点】3. （2分）(2016·武昌模拟) 如图所示，质量为M=4kg的木板A长L=1m，静止放在光滑的水平地面上，其右端静置一质量为m=1kg的小滑块B（可视为质点），它与木板A之间的动摩擦因数μ=0.4．现用水平恒力F=28N 向右拉木板，使小滑块B能从木板A上滑下来．木板A和小滑块B的加速度大小分别为aA、aB ，速度大小分别为vA,vB ，重力加速度g取10m/s2 ，则从开始运动到小滑块B滑下木板的过程中，下列图像正确的是（）A .B .C .D .【考点】4. （2分） (2018高二上·黑龙江期末) 如图所示，图中实线是一簇未标明方向的由点电荷产生的电场线，虚线是某带电粒子通过该电场区域时的运动轨迹，a、b是轨迹上的两点，若带电粒子在运动过程中只受到电场力作用，根据此图可以作出的判断，错误的是（）A . 带电粒子所带电荷的正、负B . 带电粒子在a、b两点的受力方向C . 带电粒子在a、b两点的加速度何处较大D . 带电粒子在a、b两点的速度何处较大【考点】5. （2分） (2018高三上·武邑模拟) 一个质量可忽略不计的长轻质木板置于光滑水平地面上，木板上放质量分别为mA＝1 kg和mB＝2 kg的A、B两物块，A、B与木板之间的动摩擦因数都为μ＝0.2，水平恒力F作用在A 物块上，如图所示(重力加速度g取10 m/s2).则下列说法错误的是（）A . 若F＝1 N，则A，B都相对板静止不动B . 若F＝1.5 N，则A物块所受摩擦力大小为1.5 NC . 若F＝4 N，则B物块所受摩擦力大小为2 ND . 若F＝6 N，则B物块的加速度为1 m/s2【考点】6. （2分）水平地面上一个质量的物体，在水平向右拉力作用下，向右匀速运动，那么，在刚刚撤去F时，物体的加速度是（）A . 等于零B . ，水平向左C . ，水平向右D . ，水平向左【考点】二、多选题 (共6题；共18分)7. （3分） (2017高一下·营口开学考) 如图所示，某人正通过定滑轮将质量为m的货物提升到高处．滑轮的质量和摩擦均不计，货物获得的加速度a与绳子对货物竖直向上的拉力T之间的函数关系如图所示．以下判断正确的是（）A . 图线与纵轴的交点M的值aM=﹣gB . 图线与横轴的交点N的值TN=mgC . 图线的斜率等于物体的质量mD . 图线的斜率等于物体质量的倒数【考点】8. （3分） (2017高一上·肇庆期末) 质量为m的人站在升降机中，如果升降机运动时加速度的绝对值为a，升降机底板对人的支持力N=ma+mg，则可能的情况是（）A . 升降机以加速度a向下加速运动B . 升降机以加速度a向上加速运动C . 在向上运动中，以加速度a制动D . 在向下运动中，以加速度a制动【考点】9. （3分）(2019·南京模拟) 质量均为m的两个木块A、B用一轻弹簧拴接，静置于水平地面上，如图甲所示．现用一竖直向上的恒力F拉木块A，使木块A向上做直线运动，如图乙所示．从木块A开始运动到木块B刚要离开地面的过程中，设弹簧始终处于弹性限度内，重力加速度为g，下列说法中正确的有（）A . 要使B能离开地面，F的大小应大于mgB . A的加速度一定先减小后增大C . A的动能一定先增大后减小D . A、B和弹簧组成的系统机械能一定增大【考点】10. （3分） (2017高一下·合肥期末) 一质点在0～15s内竖直向上运动，其加速度﹣时间变化的图象如图所示，若取竖直向下为正，g取10m/s2 ，则下列说法正确的是（）A . 质点的机械能不断增加B . 在0～5s内质点的动能减小C . 在10～15s内质点的机械能一直增加D . 在t=15s时质点的机械能大于t=5s时质点的机械能【考点】11. （3分） (2018高三上·河北期末) 如图甲所示，倾角为θ的光滑斜面固定在水平面上，劲度系数为k 的轻弹簧，下端固定在斜面底端，上端与质量为m的物块A连接，A的右侧紧靠一质量为m的物块B，但B与A不粘连。

人教版高中英语必修第一册同步训练UNIT 1 Section Ⅱ 含答案

SectionⅡReading and Thinking课后·训练提升一、阅读理解Welcome to Teen Ink,a national teen magazine,book series,and website devoted to teenage writing,art and photos.Students must be ages 13-19 to take part,and submit(提交) works.Teen Ink magazine offers some of the most thoughtful and creative works finished by teens and has the largest distribution(分配) of any publication of its kind.We have no staff writers or artists;we depend completely on submissions from teenagers nationwide for our content.We offer teenagers the opportunity to publish their creative works and opinions on the problems that affect their lives.Hundreds of thousands of students have submitted their works to us and we have published the works of more than 55,000 teens since 1989.The Young Authors Foundation,Inc.is a non-profit organisation that supports all Teen Ink publications.The foundation is devoted to helping teens share their own voices,while developing reading,writing,creative and critical thinking skills.All proceeds from the printed magazine,website and Teen Ink books are used only for charitable(慈善的) and educational purposes.1.What’s the purpose of the passage?A.To introduce Teen Ink.B.To praise Teen Ink.C.To collect some works.D.To attract some readers.答案:A解析:写作意图题。

人教版高中英语选择性必修第一册同步训练UNIT1 Section Ⅰ 含答案

SectionⅠReading and Thinking课后·训练提升一、单词拼写.It is necessary to hold an o attitude towards ratings..Normally,water b at 100 degrees centigrade..As is known to all,most matter has three states:solid,l and gas..It is widely a that the film is instructive and full of emotion..Last month they were d again after so many defeats..At the meeting,he also i that they should give enough space for children..Laws have been passed in most countries to make it illegal to copy intellectual p.the overall score,add up the totals in each column.(science) research.naming his little brother Horace.’t say anything.(apparent),he was a man of few words.(teach),not research.(object) opinion on this.your survival on this island.(acknowledge) their timely help.conclusion,I would like to say the film is worth seeing.(analyse) the data.10.(boil) water is good for your health while some soft drinks will do harm to三、完成句子1.个体经营者要准确记录账目,这十分重要。

人教版高中英语必修第一册同步训练UNIT2 Section Ⅳ 含答案

SectionⅣListening and Talking&Reading for Writing课后·训练提升一、根据句意及首字母提示写出单词1.As a means of t,the high-speed rail is developing fast in China.答案:transport2.Going h is a good way to relax ourselves.答案:hiking3.Many s died for their country during the war.答案:soldiers4.More young people are paying by e-pay or by c card.答案:credit5.I want to know more about the plan,so please tell me about it in d. 答案:detail6.To save money,they often travel e class.答案:economy7.We finally got there and it looked quite grand at first s.答案:sight8.I enjoyed sitting close to the window and looking at the v of the park outside.答案:view二、完成句子1.工人们要求改善他们的工作条件。

The workers requested that their working conditions .答案:should be improved2.这个问题将在下一章详细论述。

This issue will be discussed in the next chapter.答案:in detail3.他们已经在机场办了登机手续,准备飞往重庆。

高中物理人教(新课标)必修1同步练习：4

高中物理人教（新课标）必修1同步练习：4.7用牛顿定律解决问题（二）物理考试注意事项：1、填写答题卡的内容用2B铅笔填写2、提前xx 分钟收取答题卡第Ⅰ卷客观题第Ⅰ卷的注释(共8题；共16分)1．（2分）放在水平地面上的一物体，受到方向不变的水平推力F的作用，力F与时间t的关系和物体速度v与时间t的关系如图所示，则下列说法正确的是（）A．物体与地面间的摩擦因数为0.2B．物体与地面间的摩擦因数为0.4C．9s内，力F做的功是18JD．3~6s和6~9s两段时间内摩擦力的平均功率相等2．（2分）一物块位于粗糙水平面上，用大小为F、方向如图所示的力作用在物体上，使它以加速度a向右加速运动。

保持拉力方向不变，当拉力大小变为2F时（物块未离开地面）（）A．物体的加速度小于2aB．物体的加速度等于2aC．物体的加速度大于2aD．因为物块的质量未知，故不能确定a的变化情况3．（2分）如图所示，在质量为M的小车中，用细线悬挂一个质量为m的小球，在水平牵引力的作用下，小车向右做匀加速运动，稳定时悬线向左偏离竖直方向的角度为α。

撤去牵引力后，小车继续向右运动，稳定时悬线向右偏离竖直方向的角度为β。

则牵引力的大小为()A．(M+m)gtanβB．(M-m)gtanαC．(M+m)g(tanα+tanβ)D．(M+m)g(tanα-tanβ)4．（2分）一物块在固定的粗糙斜面底端以初速度v0沿斜面向上运动，又返回底端。

能够描述物块速度v随时间t变化关系的图像是（）A．B．C．D．5．（2分）质量一定的某物体放在粗糙的水平面上处于静止状态，若用一个方向始终沿水平方向，大小从零开始缓慢增大的变力F作用在物体上，物体的加速度a与F的关系图像如图所示，取g=10m/s2，最大静摩擦力等于滑动摩擦力，则下列正确的是()A．物体的质量为4kgB．物体与水平面间的动摩擦因数为0.2C．物体与水平面间的最大静摩擦力为20ND．F为20N时物体的速度为8m/s6．（2分）如图所示，质量为10kg的物体，在水平地面上向左运动。

人教版高中英语选择性必修第一册同步训练UNIT2 Section Ⅰ 含答案

SectionⅠReading and Thinking课后·训练提升一、单词拼写.As the saying goes,c dripping wears away a stone..I tried to p Jim to give up smoking,but in vain..The farmhouse is r from any other buildings..The time we spent together at childhood is gradually becoming a d memory..All the information should be a so that people can reach their own conclusions..Learn these words and p through your listening and reading..Make exercise a part of your daily r to keep you healthy..The document is very important and it should be kept in a s place..Put all relevant materials on the topic together into the i whole.10.I honestly don’t know how I will react the next time I meet a p dangerous1.The shop assistant often persuaded me buying some unnecessary goods from(prefer) for the original plan.(distance) relative in this small town.English and chatted with the locals happily.her new job quickly.this sense,children and adults have equal rights.children’s use of social media.8.Doctors issued a (warn) against eating any fish caught in the river.9.He was an unfriendly and terrible creature in my eyes.He (constant) walked around10.But when he looked to the side,he saw (instant) that it wasn’t a dog at all,but a1.你可以劝说别人帮助你,或者被劝说去帮助别人。