寒假作业开学检测
中学体育寒假作业：每天长跑2000米 开学测耐力
中学体育寒假作业：每天长跑2000米开学测耐力每天2000米长跑训练耐力；俯卧撑20×5组/次、引体向上(男)10个或哑铃训练(女)上肢力量；屈腿仰卧起坐30×4组/次和仰卧举腿30×4组/次锻炼腰腹力量……这不是健身房教练开出的课程表，而是成都七中今年寒假布置给所有学生的假期体育作业。
不要以为这些作业是学校布置起耍的。
昨日上午，成都七中通过官方微信公众号告知家长和学生，开学时学校将对每个学生进行测试，测试结果将纳入学期体育成绩评定，占比20%。
每日长跑2000米开学当堂测耐力这并不是成都七中给全校学生第一次布置体育作业。
“但今年和往年不一样：往年我们是要求学生在一个假期内完成20公里跑步，这次则是明确了每天跑2000米。
每日保持一定锻炼量，更能锻炼学生耐力素质。
”学校体育老师杜凯说。
学生会佩戴手环完成跑步，然后上传运动数据，方便老师监看吗？“不会。
”杜凯坦言，学生是否按规按量完成体育作业，一是靠学生自觉，二是靠家长督促。
“另外，我们开学后会对所有学生进行随堂测试，测试结果将按20%的比例纳入学期体育成绩评定。
”据了解，成都七中执行的是体育成绩和“评优”挂钩的政策，不管是评三好，还是优干，体育成绩都必须在良好及以上。
男生上肢力量差首次布置引体向上引体向上项目今年第一次进入成都七中的体育作业单，学校将及格线设定为10个。
杜凯告诉记者，引体向上是七中男生失分最严重的项目，“每年及格率只有50%左右”。
女生的上肢力量情况也不容乐观。
记者昨日从成都市教育局了解到，成都市每年都会对学生进行体能测试，引体向上为男生必测项目。
有意思的是，2013年，成都市中学生引体向上第一名就出自成都七中，官方登记成绩为33个。
这名学生名叫吕佩弦，去年考入了南京理工大学。
“他第一次参加校运会，就以48个引体向上的成绩，打破了学校纪录。
”杜凯对他印象十分深刻，他还有个双胞胎的哥哥，两兄弟并不是体育特长生，但体育成绩都好，主要是父母重视孩子体育锻炼。
高二数学下学期开学考试寒假作业检测试题 文
静海一中2021-2021第一学期高二数学〔文〕寒假作业检测试卷考生注意：1. 本套试卷分第一卷根底题〔108分〕和第二卷进步题〔12分〕两局部，一共150分。
2. 试卷书写标准工整，卷面整洁清楚，酌情减3-5分，并计入总分。
一、选择题〔每一小题3分，一共24分〕 1.“0x =〞是“(21)0x x -=〞( ) A ．充分不必要条件 B ．必要不充分条件 C ．充分必要条件 D ．既不充分也不必要条件 2. 命题“x R ∀∈,2x e x >〞 的否认是〔 〕 A ．不存在x R ∈，使2x e x > B ．R x ∈∃0，使200x e x <C ．0x R ∃∈，使200x ex ≤ D ．x R ∀∈,使2x e x ≤3.某学生记忆导数公式如下，其中错误的一个是〔 〕 A.()()'1nn x nx n N -*=∈ B.()'ln x xa ax =C.()'sin cos x x =D.()'1ln x x=4.“13m <<〞是“方程22113x y m m+=--表示椭圆〞的( )A.充分不必要条件B.必要不充分条件C.充要条件5.椭圆2214125x y +=的两个焦点为12,F F ,弦AB 过点1F ，那么2ABF ∆的周长为( )A ．10B ．20C ．241．416．抛物线23x =的准线过双曲线2221x y m-=-的焦点，那么双曲线的离心率为( )A.32431033r 的两个焦点分别为12,F F ,假设曲线r 上存在点P 满足1122::4:3:2PF F F PF =，那么曲线r 的离心率等于 〔 〕 A.1322或 B.23或者2 C.12或2 D.2332或 8.抛物线2:(0)C y ax a =>的焦点到准线的间隔 为14, 且C 上的两点1122(,),(,)A x y B x y ，关于直线y x m =+对称, 并且1212x x =-, 那么m =( )A.32B.52C.2D.3二、填空题〔每一小题4分，一共24分〕P 是函数ln y x =图象上的动点，那么点P 到直线y x =的间隔 的最小值为10．双曲线1y x=上任一点的切线与坐标轴围成的面积为_____ 11．设椭圆的两个焦点分别为12,F F ，过2F 作椭圆长轴的垂线与椭圆相交，其中的一个交点为P ，假设12F PF ∆为等腰直角三角形，那么椭圆的离心率是__. 12.某几何体的三视图如下图，其中正视图，侧视图均是由三角形与半圆构成，俯视图由圆与内接三角形构成，根据图中的数据可得此几何体的体积为____________．22122:1(0)x y C a b a b +=＞＞与双曲线222:14y C x -=有公一共的焦点，2C 的一条渐近线与以1C 的长轴为直径的圆相交于,A B 两点，假设1C 恰好将线段AB 三等分，那么b =_________.x y 82=，过点(2,0)A 作倾斜角为3π的直线l ，假设l 与抛物线交于B 、C 两点，弦BC 的中垂线交x 轴于点P ，那么线段AP 的长为___________.三、解答题(一共60分)15．〔14分〕直线1l 的方程为34120x y +-=，〔1〕求2l 的方程，使得：①2l 与1l 平行，且过点)3,1(-； ② 2l 与1l 垂直，且2l 与两坐标轴围成的三角形面积为4；〔2〕直线1l 与两坐标轴分别交于A 、B 两点，求三角形OAB 〔O 为坐标原点〕内切圆及外接圆的方程.〔3〕写出直线方程的五种形式并注明适用条件。
上海市奉贤区致远高级中学2021-2022学年高一下学期寒假作业反馈检测(开学考)英语试题
2021学年高一第二学期致远高级中学寒假作业反馈检测I. GrammarA ban on distracted walkingYou can’t walk down the street without passing so-called “smartphone zombies (僵尸).” They are too absorbed in their screen (1) _________ (watch) where they are going. Almost four in ten people admit having suffered a technology-related small accident (2) _________ they pay more attention to their electronic device than to the pavement.Now the city of Honolulu, Hawaii, has decided it’s time to take immediate action and make it illegal to cross the road while using a mobile phone. Those (3) ________ (catch) using phones, tablets or other electronic devices at crossing points could face a fine of up to $100.Honolulu is the first major U.S. city to ban (4) __________ is called “distracted w alking.” It comes after a study found there (5)___________(be) more than 11,000 injuries in the United States resulting from phone-related distraction while walking in the past few years.To explain the decision, mayor Kirk Caldwell said, “We hold the un fortunate honor of being a major city (6) ___________more pedestrians are hit in crosswalks than almost any other city in the country.”Under the fine systems, (7) _________ breaks this law for the first time will get a fine of $15 to $35. People breaking the law for a second or third time will get a $99 fine.The law, which is called the Distracted Walking Law, does permit an exception. Pedestrians (8) ___________ use such devices in the street to call emergency services and rescue workers, such as firefighters and police officers.If you still want to text while walking, you could avoid (9) _________ (fine) in Honolulu by using a voice-controlled digital assistant such as Siri or Google Assistant. Or you could just wait (10) __________ you are again, safely, off the street.How would you like to wear the same underwear for weeks? Owing to the work that has gone into developing intelligent materials, this may not be as __1__ as it sounds. Self-cleaning clothes have now been created, and these new materials provide __2__ resistance to dirt as well as water. As a result, they require much less cleaning than traditional materials.The creation of self-cleaning clothes provides an example of how nature helps scientists develop better products. This self-cleaning __3__ is known as the “lotus effect”. The name comes, of course, from the lotus leaves, which ar e famous for growing in muddy lakes and rivers while remaining almost __4__ clean. By observing nature, scientists are __5__ the qualities of the lotus leaves to the materials they have engineered. Because of this, some remarkable new products have been __6__. Among them are special windows that are resistant to dirt and water. A special __7__ on these windows not only prevents dirt from sticking to their surfaces, but also allows dust to be easily washed off by the rain. In fact, these new windows have already been __8__ to some cars. Even when traveling at high speed through rain, these cars never have to use their windshield wipers.Although we have already seen some practical applications, even more dramatic __9__ will be made in the future, and they will, perhaps, change our world completely. Undoubtedly, technology is an important development, and it will have an even bigger __10__ on our lives.III.ClozeGM(转基因)crops are debatable. On one hand, some farmers and scientists feel that GM crops can make the world a __1__ place. If bioengineers can create crops that are resistant to insects, __2__, then they won’t have to worry about insects destroying plants. In the __3__ of insect damage, crops can grow to feed the poor and hungry. Genetic engineering can create plants with other desirable properties as well. Plants that don’t require much water, that can live even in times of drought, can help prevent the widespread __4__ that would occur if people have nothing to eat. It’s easy to see why many people believe that GM crops will help the world meet the difficult __5__ that it will face as more and more people need to be fed.But not everyone thinks bioengineering is a good idea. Other people are __6__. They mistrust the claims made and don’t believe that bi otechnology is without __7__. The possible dangers include harming the ecosystem—the inter-related community of plants and animals and bacteria that __8__ the Earth. They __9__ that changing plants can harm our environment, and damage to our surroundings can hurt us. One danger is that GM crops can transfer their characteristics to other plants. Plants that reproduce by spreading their pollen(花粉) in the wind can possibly fertilize wild plants, making them more __10__ to control. Another problem is that GM plants might be a source of allergens(过敏源). This seems __11__, but in the process of making GM foods, genes are transferred that are known to cause problems for some people. Allergic reactions can __12__ from coughing and sneezing to death.Indeed, people hold very different opinions about __13__. While some people look forward to crops that will not rot during the trip to market, others claim that we will ruin our cropland and destroy what we are trying to save. While some people look forward to crops that can __14__ droughts, others claim that contact with GM plants can pollute other crops, making them __15__ for use. For some people, GM crops are the hope of the future; for others, they are a poison that will harm or destroy our farmland.1. A. worse B. better C. less healthy D. more peaceful2. A. in no way B. by all means C. for example D. by contrast3. A. absence B. appearance C. case D. effect4. A. war B. poverty C. starvation D. robbery5. A. challenge B. specification C. standard D. principle6. A. knowledgeable B. supportive C. ignorant D. suspicious7. A. control B. risks C. criteria D. doubts8. A. turn up B. make up C.give up D. take up9. A. ensure B. worry C. deny D. demand10. A. temperate B. difficult C. efficient D. enjoyable11. A. inevitable B. inaccessible C. unavoidable D. unlikely12. A. suffer B. arise C. start D. range13. A. bioengineering B. allergens C. drought D. future14. A. cause B. reduce C. stand D. change15. A. efficient B.expensive C. unfit D. possibleI. Reading Comprehension(A)The composing career of Albert Roussel got off to a disobedient start, and received one of its biggest boosts from a lie.Roussel was orphaned at the age of eight and went to live with his grandfather. He built on the music he had learned from his mother, entertaining himself by reading through the family music collection and playing operatic selections and popular songs on the piano.Three years later Rou ssel’s grandfather died, and his mother’s sister took him in. Her husband arranged for young Albert to take piano lessons. Summer vacations at a Belgian seaside resort added a second love to his life — the sea. He studied to be a naval cadet（军校学生）, but still made time to study music.In the French Navy, while he was sent to a warship based at Cherbourg, he and two friends found the time to play the piano trios of Beethoven and other composers. Roussel also began composing. At the Church of the Trinity in Cherbourg on Christmas Day 1892, he staged the performance of his Andante（行板乐曲）for the first time as a composer.That success encouraged Roussel to write a wedding march, and one of his fellow naval officers offered to show it to a prominent conductor, Edouard Colonne. When Roussel’s friend returned with the draft of the march, he reported that Colonne had advised Roussel to give up his naval career and devote his life to music.Not long afterward, at the age of 25, Roussel did just that. He applied the self-discipline, simplicity, and spirituality that he had developed in the navy to his composing and became a major force in twentieth century French music. As for Eduoard Colonne’s inspi ring advice that Roussel devote his life to music —Roussel’s navy friend later admitted that he had made it up and that he had never even shown Roussel’s draft to the world famous conductor.1. Which of the following is true of Roussel?A. Roussel was adopted by his aunt when he was 10 years old.B. Roussel applied what he had developed in the Navy to his composing.C. Roussel lived with his grandfather at 8 with his parents living in another city.D. Roussel spent his summer vacations at a seaside resort to be a naval soldier.2. On Dec.25th, 1892, at the church in Cherbourg, Roussel __________.A. played the piano trios of Beethoven and other composersB. made time to play music with his two friendsC. made his first performance as a composerD. took piano lessons and played popular songs on the piano3. The underlined word “prominent” in Paragraph 5 is similar in meaning to“__________”.A. graciousB. religiousC. generousD. well-known4. The passage mainly talks about __________.A. a composer’s professional training experienceB. a navy cadet’s dreamC. a well-intentioned trickD. the shortcut to become a composer( B )Which tablet computer should YOU be buying: They are this year's must have... and there's a style to suit everyone ？Best for young childrenLeapPad Explorer 2, £68Aimed at childrenbetween three and nine(though a nine-year-oldmight find it a little simple),it comes in pink or blue andwith five built-in educationgames (you can buy more).Besides, the LeapPad does not allow access to the internet — so it is impossible for your child to stumble across anything inappropriate.Pros: The education games are well-designed, the built-in video camera is a fun way to play at being a film director.Cons:Some of the games are shockingly expensive. And the power adaptor is not included. Best for teenagersiPad 4th generation, £399-£659The iPad is still themarket leader, and forgood reason. If theteenager in your houseenjoys playing computergames, the latest offeringfrom Apple is the one tochoose.Pros: No other tablet can compete with the near one million ‘apps’ (the name Apple created for specially-designed downloadable programs) available for the iPad. Simple to use, even for those who usually struggle with technology.Cons: Considerably more expensive than most competitors.Best for working parentsMicrosoft Surface, £399-£559Tablets arebrilliant for leisure —but what if you wantto do a bit of work?No tablet can yet compete with a full-size laptop computer, but this is the only tablet that allows you to use Microsoft Word, Excel and Powerpoint (they are all pre-installed and included in the price) and you can buy a pretty lovely mini- keyboard for typing letters and emails, which also doubles up as the cover.Pros:The Surface is good for watching movies —a bonus when stuck in the airport on a business trip —and surfing the internet.Con: The keyboard is an expensive add-on — costing up to £109. It might be cheaper to buy a laptop (though a tablet is much smaller and lighter). Best for bookwormsAmazon Kindle Paperwhite, £109Nearly all tablets letyou download books. It's agreat way to take amountainous pile ofhardbacks on holidaywithout stuffing yoursuitcase.But most tablets have a shiny screen —which can be very distracting when you're trying to read. The Paperwhite is different: its matt screen and crisp black lettering imitate the look of words on paper brilliantly. And yet you can still read the words in the dark.Pros:Easy on the eye, excellent battery life, 180,000 free books (if you subscribe to the Amazon Prime customer loyalty service) plus hundreds of thousands more to buy.Cons: No TV, films, games, internet or camera.5. The underlined phrase ‘stumble across’ most probably means ‘___________’.A. meet withB. quarrel withC. compare withD. competewith6. Which of the following about Surface is NOT TRUE?A. The keyboard will add to the cost.B. The keyboard can serve as a cover.C. You have to pay extra to install Microsoft Word.D. You can watch movies or surf the Internet with it.7. If you are a game lover, which tablet is least likely to be your choice?A. LeapPad Explorer 2.B. iPad 4th generation.C. Microsoft Surface.D. Amazon Kindle Paper( C )Happiness can be described as a positive mood and a pleasant state of mind. According to recent polls (民意调查), sixty to seventy percent of Americans consider themselves to be moderately happy and one in twenty persons feels very unhappy. Psychologists have been studying the factors that contribute to happiness. It is not predictable, nor is a person in an apparently ideal situation necessarily happy. The ideal situation may have little to do with his actual feelings.A good education and income are usually considered necessary for happiness. Though both may contribute, they are only chief factors if the person is seriously undereducated or actually suffering from lack of physical needs.The rich are not likely to be happier than the middle-income group or even those with very low incomes. People with college educations are somewhat happier than those who did not graduate from high school, and it is believed that this is mainly because they have more opportunities to control their lives. Yet people with a high income and a college education may be less happy than those with the same income and no college education.Poor health does not rule out happiness except for the severely disabled or those in pain. Learning to cope with a health problem can contribute to happiness. Those who have good relationship with other family members are happier than those who live alone. Love has a higher correlation with happiness than any other factors.It should be noted that people quickly get used to what they have, and they are happiest when they feel they are increasing their level no matter where it stands at a given time.Children whose parents were happily married have happier childhoods, but are not necessarily happier adults.The best formula(准则) for happiness is to be able to develop AQ (Adversity Quotient that can be of great benefit when running into trouble), to have a personal involvement and commitment, and to develop self-confidence and self-esteem.8. It can be inferred from the passage that _____.A. happiness is neither predictable nor apparentB. a person in an apparently ideal situation must be happyC. the rich are not likely to be happier than the middle-income groupD. happiness is n ot necessarily connected to one’s situation in society9. According to the article, happiness is greatly dependent upon _____.A. a happy childhood in which one can do whatever he likesB. great wealth with which one can buy anythingC. a feeling that conditions are becoming for the betterD. a college degree that can help one achieve great success10. The letters AQ in the last paragraph most probably mean _____.A. ambition to defeat others in a severe competitionB. ability to overcome difficulty and get out of embarrassing situationC. methods of solving difficult problems and challenges in lifeD. attitudes towards severe competition especially in trouble11. The best title of this passage may be _____.A. What Does Happiness Consist inB. Happiness and UnhappinessC. Different Kinds of HappinessD. Causes of Happiness and Unhappiness12. Which of the following does NOT increase your life span?A. Staying happy about lifeB. Exercising as much as possibleC. Exercising your brain frequentlyD. Enjoying your social life13. People who do not stay mentally active are more likely to _________.A. become ignorantB. lose their mindsC. shorten their livesD. become slow in movement14. The underlined phrase silver lining can be replaced with __________.A. something made of silverB. new informationC. good aspectsD. long life span15. Which of the following is correct about medication ?A. Appropriate medication is necessary.B. Medication is always helpful to you.C. Doctors suggest taking expensive medicines.D. Drugs are unnecessary because of side-effects.I.Grammar(10*2)1to watch 2. because 3. caught 4. what 5. had been 6.where 7. whoever 8. can/may 9. being fined 10. until II. V ocabulary (10*2=20分）BJHIC AFGKEIII. Cloze（15*2）BCACA DBBBB DDACCIV. Reading (16*2=30分）(A)1-4. BCDCACDDCBABCCA。
浙江省金华市义乌市绣湖中学2021-2022学年七年级下学期寒假作业监测（开学）英语试题
绣湖中学七年级英语学情调研卷2022.2.16一、听力（15分）第一节：听对话，回答问题。
(5分)（）1. What’s Dick’s favourite animal?A. dogsB. monkeysC. giraffes（）2. What does Lucy’s father do?A. doctorB. teacherC. worker（）3. What’s the wea ther like now?A. it’s rainy.B. it's sunny.C. it’s windy.（）4. How does Tom’s father usually go to work?A. by bikeB. on footC. by car（）5. Where will Jack go for the coming holiday?A. AmericaB. EnglandC. Japan第二节：听长对话，回答问题。
(5分)听下面一段较长的对话，回答6-7两小题。
（）6. Where are the speakers?A. In a shopB. In a libraryC. In the classroom（）7. What’s the woman’s favourite colour?A. redB. blueC. yellow听下面一段较长的对话，回答8-10三小题。
（）8. Where is Tom’s home?A. Behind his school.B. Next to his school.C. In front of his school.（）9. How does Jane usually go to school?A. By bike.B.On foot.C. By bus.（）10. What does Jane think of the school lunch?A. Bad.B. Just so-so.C. Delicious.第三节：听下面一段独白，从A、B、C三个选项中选择正确的选项, 回答问题。
辽宁省丹东市第六中学2023-2024学年九年级下学期寒假作业检测(开学考)数学试题
辽宁省丹东市第六中学2023-2024学年九年级下学期寒假作业检测（开学考）数学试题一、单选题1．2的平方根是（ ）．A ．2±B ．C ．2D 2．美琪在做数学作业时，不小心将式子中除号后边的代数式污染，即22432x x xy ⎛⎫-÷⎪-⎝⎭，通过查看答案，答案为232x x y+-，则被污染的代数式为（ ）A ．21x + B ．2x x- C ．2xx- D ．121x x +- 3．如图，正方形ABCD 的顶点A ，B 的坐标分别为()1,1，()3,1，若正方形ABCD 第1次沿x 轴翻折，第2次沿y 轴翻折，第3次沿x 轴翻折，第4次沿y 轴翻折，第5次沿x 轴翻折，…则第2021次翻折后点C 对应点的坐标为（ ）A ．()3,3-B ．()3,3C ．()3,3-D ．()3,3--4．如图，将四根木条用钉子钉成一个矩形框架ABCD ，然后向左扭动框架，观察所得四边形的变化，下面判断正确的是（ ）A ．四边形ABCD 由矩形变为菱形B ．对角线AC 的长度不变 C ．四边形ABCD 的面积不变D ．四边形ABCD 的周长不变5．如图，AB 是O e 的直径，点C 在O e 上，连接AC BC ，．若70A ∠=︒，则B ∠的度数是（ ）A ．50︒B ．40︒C ．35︒D ．20︒6．如图，在Rt ABC △中，90C ∠=︒，若6AC =，10AB =，则sin A 的值为（ ）A ．35B ．45C ．34D ．437．若反比例函数k y x =的图象经过点()3,2-，则反比例函数ky x=-的图象在（ ） A ．一、二象限B ．三、四象限C ．一、三象限D ．二、四象限8．若关于x 的一元二次方程()22240a x x a +++-=有一个根为0，则a 满足( )A ．a =2B ．2a =-C ．2a =±D ．a 为任意数9．如图，抛物线2=23y x x --与y 轴交于点C ，点D 的坐标为(0，－1)，在第四象限抛物线上有一点P ，若△PCD 是以CD 为底边的等腰三角形，则点P 的横坐标为（ ）A ．1B ．1C 1D ．1110．将含有30︒角的直角三角尺OAB 按如图所示的方式放置在平面直角坐标系中，OB 在x 轴上，若2OA =，将三角尺绕原点O 顺时针旋转75︒，则点A 的对应点A '的坐标为（ ）A ．1)-B ．(1,C ．D ．(二、填空题11．若2x =是一元二次方程230x x c -+=的一个根，则c 的值为．12．函数12y x =-的自变量x 的取值范围是． 13．如图，小明在距离地面30米的P 处测得A 处的俯角为15︒，B 处的俯角为60︒．若斜面AB 的坡角为30︒，则斜坡AB 的长是米．14．如图，ABC V 中，90A ∠=︒，1AB =，2AC =，射线CF AB ∥，点D 在射线CF 上运动，DE BC ⊥，垂足为点E ，若ABC V 与BDE V 相似，则CD 的长为．15．如图，在正方形ABCD 中，AB ＝4，E 为对角线AC 上与A ，C 不重合的一个动点，过点E 作EF ⊥AB 于点F ，EG ⊥BC 于点G ，连接DE ，FG ，下列结论：①DE ＝FG ；②DE ⊥FG ；③∠BFG ＝∠ADE ；④FG 的最小值为3．其中正确结论的序号为．三、解答题16．计算(1)计算：2︒-︒sin30cos45(2)解方程：24120+-=x x17．北京冬奥会的成功举办掀起了全民“冬奥热”，某校组织全校七、八年级学生举行了“冬奥知识”竞赛，现分别在七八两个年级中各随机抽取10名学生，统计这部分学生的竞赛成绩，相关数据统计整理如下：【收集数据】七年级10名同学测试成绩统计如下：85，78，86，79，72，91，79，72，69，89八年级10名同学测试成绩统计如下：85，80，76，84，80，72，92，74，75，82【整理数据】两组数据各分数段，如下表所示：【分析数据】两组数据的平均数、中位数、众数、方差如下表：【问题解决】根据以上信息，解答下列问题：(1)填空：a=______，b=______，c=______(2)求八年级同学成绩的方差，试估计哪个年级的竞赛成绩更整齐？(3)按照比赛规定90分及其以上为优秀，若该校七年级学生共1500人，八年级学生共1200人，请估计这两个年级竞赛成绩达到优秀学生的总人数．18．图1是某型号挖掘机，该挖掘机是由基座、主臂和伸展臂构成．图2是某种工作状态下的侧面结构示意图（MN 是基座的高，MP 是主臂，PQ 是伸展臂，EM QN ∥）．已知基座高度MN 为1m ，主臂MP 长为5m ，测得主臂伸展角37PME ∠=︒． （参考数据：3344sin 37tan 37sin 53tan 535453︒≈︒≈︒≈︒≈，，，）．(1)求点P 到地面的高度；(2)当挖掘机挖到地面上的点时，113MPQ ∠=︒，求QN ．19．如图，AB 是O e 的直径，C 为O e 上一点，AD 和过点C 的切线互相垂直，垂足为D ，AD 交O e 于点E ，3AE =，2CD =．(1)求证：AC 平分DAB ∠； (2)求O e 的半径．20．阅读与思考：下面是小亮同学的一篇数学日记，请仔细阅读并完成相应的任务． 某数学兴趣小组进行探究活动如下：如图，取一根长100cm 的匀质木杆，用细绳绑在木杆的中点O 并将其吊起来，在中点O 的左侧距离中点25cm O 处桂一个重9.8N 的物体，在中点O 右侧用一个弹簧秤向下拉，使木杆处于水平状态，改变弹簧秤与中点O 的距离L （单位：cm)，看弹簧秤的示数F （单位：)N 有什么变化．第一步，实验测量．改变弹簧秤与中点O 的距离L ，观察弹簧秤的示数F 的值，并做好记录，（共记录了7组数据）． 第二步，整理数据、第三步，描点连线．以L 的数值为横坐标，对应F 的数值为纵坐标在平面直角坐标系中描出以表中数对为坐标的各点，并用平滑的曲线顺次连接这些点．在数据分析时，一位同学发现一个数据有错误，重新测量计算后，证明了他的猜想正确，并修改了表中这个数据． 任务：(1)你认为表中第几组数据是错误的？请把这组数据改正过来； (2)在平面直角坐标系中，画出F 与L 的函数图象；(3)观察这条曲线所表达的就是关系，结合学习过的函数特点，直接写出F 关于L 的函数表达式；(4)点()50,4.9在这条曲线上吗？说明理由． 21．阅读材料，解答问题： 材料1 为了解方程()22213360x x -+=，如果我们把2x 看作一个整体，然后设2y x =，则原方程可化为213360y y -+=，经过运算，原方程的解为1,22x =±，3,43x =±．我们把以上这种解决问题的方法通常叫做换元法．材料2已知实数m ，n 满足210m m --=，210n n --=，且m n ≠，显然m ，n 是方程210x x --=的两个不相等的实数根，由韦达定理可知1m n +=，1mn =-． 根据上述材料，解决以下问题： (1)直接应用：方程42560x x -+=的解为_______________________； (2)间接应用：已知实数a ，b 满足：422710a a -+=，422710b b -+=且a b ≠，求44a b +的值； (3)拓展应用： 已知实数x ，y 满足：42117m m +=，27n n -=且0n >，求241n m+的值． 22．综合与实践 问题情境数学综合实践课上老师和同学们一起进行折纸，通过折叠探究其中的数学奥妙． 操作发现（1）实践小组按照如图1所示的方式，将矩形纸片ABCD 沿对角线AC 折叠，使点D 落在点D ¢处，AD '交BC 于点E ，则AEC △的形状是______，若2AB =，4BC =，则EC =______；继续探究（2）勤学小组按照如图2所示的方式，将矩形纸片ABCD 分别沿,AE CF 折叠，点B ，D 的对应点为点,B D ''，使,B D ''落在对角线AC 上，且,B D ''两点恰好重合． ①请判断四边形AECF 的形状，并说明理由； ②若10AB =，求EF 的长． 深入探究（3）博学小组按照如图3所示的方式，首先将矩形纸片ABCD 对折，使AD 与BC 重合，得到折痕MN ，然后把纸片展开；将纸片沿过点A 的直线折叠，使得点B 落在MN 上的点B '处，折痕交BC 于点E ，交MN 于点F ，延长AB '交DC 的延长线于点P ，然后展开纸片，若1MF =，8AD =，则PC =______．23．如图，抛物线212y x bx c =++与x 轴交于点A ，点B ，与y 轴交于点C ，直线122y x =-经过点B ，点C ．(1)试求抛物线的解析式；(2)点P 是直线BC 下方抛物线上一动点，当BCP V 的面积最大时，求点P 的坐标； (3)若M 是抛物线上一点，且MCB ABC ∠=∠，请直接写出点M 的坐标．。
浙江省杭州第二中学钱江学校2023-2024学年高一下学期寒假作业检测(开学考试)数学试卷
浙江省杭州第二中学钱江学校2023-2024学年高一下学期寒假作业检测（开学考试）数学试卷学校:___________姓名：___________班级：___________考号：___________一、单选题1．已知集合{}|02A x x =<<，集合{}|11B x x =-<<，集合{}|10C x mx =+>，若()A B C ⊆U ，则实数m 的取值范围为（ ）A ．{}|21m m -≤≤B ．1|12m m ⎧⎫-≤≤⎨⎬⎩⎭C ．1|12m m ⎧⎫-≤≤⎨⎬⎩⎭D ．11|24m m ⎧⎫-≤≤⎨⎬⎩⎭2．三角函数值1sin ，2sin ，3sin 的大小顺序是 A ．123sin sin sin >> B ．213sin sin sin >> C ．132sin sin sin >>D ．3 2 1sin sin sin >>3．设a ＝log 54，b ＝（log 53）2，c ＝log 45，则（ ） A ．a ＜c ＜bB ．b ＜c ＜aC ．a ＜b ＜cD ．b ＜a ＜c4．已知函数74sin 20,66ππ⎛⎫⎛⎫⎡⎤=+∈ ⎪⎪⎢⎥⎝⎭⎣⎦⎝⎭y x x 的图象与直线y m =有三个交点的横坐标分别为()123123,,x x x x x x <<，那么1232x x x ++的值是（ ） A ．34πB ．4π3C ．5π3D ．3π25．设(),0,παβ∈，()5sin 13αβ+=，1tan 22α=，则cos β的值是（ ） A ．1665-B ．1665C ．3365-D ．33656．设函数()2sin()f x x ωϕ=+，x R ∈，其中0ω>，||ϕπ<.若5()28f π=，()08f 11π=，且()f x 的最小正周期大于2π，则A ．23ω=，12πϕ=B ．23ω=，12ϕ11π=- C ．13ω=，24ϕ11π=- D ．13ω=，724πϕ= 7．设()|31|x f x =-,c b a <<且()()()f c f a f b >>,则下列关系中一定成立的是 A ．3c ＞3bB ．3b ＞3aC ．3c +3a ＞2D ．3c +3a ＜28．已知()f x 是偶函数，且()f x 在[0,)+∝上是增函数，若()()12f ax f x +≤-在1,12x ⎡⎤∈⎢⎥⎣⎦上恒成立，则实数a 的取值范围是（ ） A ．[﹣2，1]B ．[﹣5，0]C ．[﹣5，1]D ．[﹣2，0]二、多选题9．存在函数()f x 满足：对任意x ∈R 都有（ ） A ．()sin cos f x x = B ．()sin sin 2f x x = C ．()cos cos 2f x x =D ．()sin sin3f x x =10．下列不等式中，正确的是（ ）．A ．13π13πtan tan 45< B ．ππsin cos 57⎛⎫<- ⎪⎝⎭C ．ππsin 55> D ．ππtan 55> 11．关于函数()|ln |2||f x x =-，下列描述正确的有（ ）A ．()f x 在区间(1,2)上单调递增B ． ()y f x =的图象关于直线2x =对称C ．若1212,()(),x x f x f x ≠=则124x x +=D ．()f x 有且仅有两个零点12．设函数()f x 的定义域为R ，满足()()12f x f x +=，且当(]0,1x ∈时，()()1f x x x =-.若对任意(],x m ∈-∞，都有()89f x ≥-，则实数m 的值可以是（ ）A ．94B ．73C ．52D ．83三、填空题13．函数()()21256f x log x x =-+-的单调减区间是． 14．已知0a >，0b >，且111a b +=，则1411a b +--的最小值为.15．函数f （x ）＝log 2（kx 2+4kx +3）．①若f （x ）的定义域为R ，则k 的取值范围是；②若f （x ）的值域为R ，则k 的取值范围是．16．函数253sin cos 82y x a x a =+⋅+-在闭区间0,2π⎡⎤⎢⎥⎣⎦上的最大值是1，则=a ．四、解答题17．已知a ∈R ，集合{}2230A x x x =--≤，{}220B x x ax =--=．(1)若1a =，求A B ⋂；(2)若A B A ⋃=，求实数a 的取值范围．18．设集合{}12A x x =-≤≤，{}121B x m x m =-<<+． （1）若B A ⊆，求实数m 的取值范围；（2）若()R B A I ð中只有一个整数2-，求实数m 的取值范围． 19．设函数()sin ,f x x x =∈R .（1）已知[0,2),θ∈π函数()f x θ+是偶函数，求θ的值；（2）求函数22[()][()]124y f x f x ππ=+++ 的值域. 20．已知函数())2πcos 204f x x x ωωω⎛⎫=-+> ⎪⎝⎭的最小正周期是π．(1)求函数()y f x =的单调递增区间；(2)若对任意的π5π,1212x ⎡⎤∈-⎢⎥⎣⎦，都有()2f x m -≤，求m 的取值范围．21．已知函数()ln (0,e 2.71828ex af x x a =->=L 为自然对数的底数）.(1)当1a =时，判断函数()f x 的单调性和零点个数，并证明你的结论； (2)当[]1,e x ∈时，关于x 的不等式()2ln f x x a >-恒成立，求实数a 的取值范围. 22．已知函数2()|2|f x x x x a =+-，其中a 为实数． （Ⅰ）当1a =-时，求函数()f x 的最小值；（Ⅱ）若()f x 在[1,1]-上为增函数，求实数a 的取值范围；（Ⅲ）对于给定的负数a ，若存在两个不相等的实数12,x x （12x x < 且20x ≠ ）使得12()()f x f x =，求112x x x +的取值范围.。
重庆一中初级学度下期开学寒假作业检查语文试卷.doc
重庆一中初2014级13-14学年度下期第一次定时作业语文试卷2014.2（全卷共四个大题，满分150分，考试时间120分钟）一、语文知识及运用。
（30分） 1.下列加点字注音全部正确的一项是（ • • • • ）（3 分）A.毡帽 ■ (zh 召n) 袒露(lou) • 黄蓿佳（b©i ） ■ 故弄玄虚 ■ (xuan)B.嗤笑 (chi) 诘难(nan)舐犊(shi) 踉踉跄跄 (qiang) C.领略 ■ (nue) 蜃景(shen) ■ 骡马dud) ■ 前仆后继 • (pu) D.画缗 ■ (zeng) 少顷(shao) • 书斋(zhai) ■ 转瞬即逝 ■ (shun) 2.下列词语书写全部正确的一项是（• • • • ）（3 分） A.笑吟吟 斟酌 脚踝莫名其妙 B.天骄胡谄 端祥 窸窸窣窣 C.诀窍逻辑 恣睢 遍稽群藉 D.挈约 抽噎 喉咙矫揉造作 3. 卜-列句子中加点的成语使用有课的一•项是（ ）（3分）• • • • 入姥姥和面、拌馅、擀皮、包饺的一系列动作手势，都带着那么一股斩钉截铁的劲儿，一• • • •看就知道是个中好手。
三十的年夜饭桌上，一家人围坐举杯，爷爷高谈阔论，不禁感叹过去贫苦的H 子。
• • • •C. “年”的知识可以从浩瀚的书籍中去获知，所谓开卷冇益，古人诚不欺我！• • • •D. 冯小刚掌勺的马年春晚上，魔术师王亦丰将许多异想天开的情况变成了现实。
• • • •4. 下列文学常识表述有谋的一项是（ ）（3分）• • A. 《我的叔叔于勒》和《变色龙》冇许多相似Z 处：其作者都是19世纪批判现实主义作 家；情节构思突出“巧”；人物塑造突出“变”；艺术手法突岀“比”；所写人物事件突 出“小”；而所表现的主题却突出“大”。
B. 《战国策》是我国古代最早的一部国别体史书，主要记载了战国时期谋克策士纵横扌卑阖 的斗争，我们学过的《邹忌讽齐王纳谏》就选自本书。
浙江省义乌市稠州中学2023-2024学年九年级下学期开学考试(寒假作业)法治社会试题
九年级社会法治学科寒假作业检查一、选择题（本题有20小题，每小题2分，共40分。
）1．读图，A点地处（）A．东半球、北温带B．西半球、中纬度C．西半球、北温带D．东半球、高纬度2．下列关于秦岭—淮河一线的地理意义，说法正确的是（）①800mm等降水量分界线②季风区与非季风区的分界线③一月0℃等温线分界线④亚热带季风气候和温带季风气候分界线A．①②③B．②③④C．①②④D．①③④读下边等高线地形图，回答3-4题。
3．野外攀岩活动是指攀爬坡度很陡的天然岩石峭壁，图中__________处适合开展此活动。
A．甲B．乙C．丙D．丁4．若A处气温为26℃，那B处为（）A．21.8℃B．20.6℃C．31.4℃D．30.2℃5．《伤寒杂病论》中“辩证分析病情”的思想与下列哪位思想家看待问题的方法相似（）A．老子B．墨子C．孙武D．韩非子6．公元前5世纪中叶，罗马共和国颁布了适用于罗马公民的《十二铜表法》。
罗马帝国时期，法律体系进一步完善，以便实施于分散在帝国各处的各族人民。
由此可见，罗马法律不断发展的主要原因是（）A．统治区域不断扩大B．古希腊文化广泛传播C．民主制度达到鼎盛D．东西方文明交流互鉴7．这个帝国昙花一现后，便分裂并形成法兰西、德意志、意大利三个国家的雏形。
这个帝国是（）A．亚历山大帝国B．罗马帝国C．查理曼帝国D．拜占庭帝国8．历史事实是对历史的真实描述，历史观点是对历史事实的看法和结论。
下列表述中，属于历史观点的是（）A．欧洲殖民者从事黑奴贸易，赚取高额利润B．1588年，英国打败了西班牙“无敌舰队”C．印度民族大起义反映了印度民族意识的觉醒D．欧洲殖民者对美洲土著采取种族灭绝政策9．某同学撰写历史小论文的关键词：马克思、巴黎公社、彼得格勒武装起义。
据此可知，该小论文的标题是（）A．亚非民族民主运动的兴起B．社会主义革命的探索C．资本主义经济大危机爆发D．苏联模式的形成过程10．以下历史事件按照时间先后排序正确的是（）①《联合国家宣言》签署②联合国正式成立③《凡尔赛条约》的签署④中国加入WTOA．①②③④B．③②①④C．③①②④D．④②①③11．浙江省把山区海岛县（市、区）作为全省推进共同富裕示范区建设的突破口，不断加强公共服务供给，做优做强特色产业，推动山区海岛高质量发展，提高群众生活品质。
2020-2021学年江苏省南通市启秀中学八年级下学期开学摸底考英语试卷有答案
启秀中学初二英语寒假作业检测二、单项选择（本题共10 小题;每小题1分，满分10 分）从A、B、C、D四个选项中，选出可以填入空白处得最佳选项，并在答题卡上将该项涂黑。
21.It’s________pity that many wild animals are now in danger. Please have ________ pity on them since they are part of our big family.A.a; /B. a; aC. /; a D: /; /22. Amy looks pretty with a red scarf___________.A. onB. inC. byD. of23. Li Li can read the English article easily because there are only _______ new words in it.A. littleB. a littleC. a fewD. few24. Which has the same structure as "The reserve gives wildlife an ideal home."?A. The students are describing the birds.B. Birdwatching is interesting.C. The new film makes them happy.D. The hotel offers us free breakfast.25. Whenever we kids come over, Auntie Susan just stands there and watches us______sure we don’t break anything.A. makeB. madeC. to makeD.making26. —I hate my schoolwork. It's too hard. And I’m just not as smart as your mom.—_______, you have a higher IO. You just need to kick your laziness, Dan.A. First of allB. For exampleC. As a resultD. In fact27. The world __________ not be ready for me, but ready or not, I am here now.A. mayB. needC. shouldD. must28. All the villagers were sleeping in their houses________the earthquake happened.A .after B. when C. so D. while29.The price of petrol汽油）is not that __________ of last year, so more people are planning to buy cars.A.as expensive asB. so cheap asC. as low asD. so high as30.--I'm sorry that I was so impolite to you just now.--_____________.A.What a pity!B. No problem.C. Never mindD. That's right.三、完形填空（共 10小题;每小题1分，满分10分）请认真阅读下面短文，从短文后各题所给的A、B、C、D四个选项中，选出最佳选项。
浙江省金华市义乌市稠州中学教育集团2021-2022学年九年级下学期开学检测科学试题(含答案)
九年级寒假作业检测（2022.2）科学试卷相对原子质量：C-12;H-1;O-16;N-14;Fe-56;Cu-64;Ag-108;Cl-35.5;Ca-40;Na-23;Zn-65;g取10N/Kg一、单项选择题（每小题3分，共45分）1．新疆地区不仅棉花产量大，而且所产棉花品质好，特别是新疆长绒棉因其棉纤维长、柔软细腻、光泽度好，成为棉花界的明星。
决定棉纤维长短这一性状的是（ ）A．基因B．DNA C．染色体D．细胞核2、规范的操作是确保实验成功的关键，下列所示的操作正确的是（ ）3、比较HIV病毒、大肠杆菌、酵母菌三者之间的关系，下列说法错误的是()A. 三者体积大小：酵母菌>大肠杆菌>HIV病毒B.三者中大肠杆菌和酵母菌都有细胞核C. 三者中HIV病毒只能寄生在活细胞中D. 三者中只有HIV病毒没有细胞壁4. 在草原生态系统中，几种生物构成了如图所示的食物关系，下列说法正确的是()A. 该食物网中共有5条食物链B. 该食物网中，分解者是EC. 有毒物质在E体内积累最多D. 图中生物B与C的关系只有捕食关系5、以自然选择为中心的生物进化学说没能解决的问题是( )A. 生物进化的原因B. 说明物种是可变的C. 解释生物的适应性及多样性这一发现为未来改变ABO 血型系统中的血型成为一种可能。
下列关于ABO 血型的说法叙述正确的是（）A．人类血型是遗传的，而且ABO 血型系统是人类唯一的血型系统B．ABO 血系统中的血型是由血清中的凝集素决定C．O 型血的标准血清可以使ABO 血型系统中的其它三种血型的红细胞发生凝集D．根据血型“切除”理论，O 型血可以改造成A 型、B 型，甚至AB 型10、如图是空调遥控器，需要安装干电池才能使用。
使用时，摁下按键，就能遥控空调。
则干电池内具有的能、遥控空调时所利用的能，分别是（）A.电能电磁能B.化学能电磁能C.化学能电能D.电能电磁能11、如图所示装置中，甲、乙、丙三个完全相同的烧瓶中分别装有质量、初温都相同的液体，烧瓶中的液体分别是水、水、煤油，烧瓶中的电阻丝分别为R甲、R乙、R丙，烧瓶内都有相同的温度计。
高三数学下学期开学考试(寒假作业检测)试题 文-人教版高三全册数学试题
静海一中2015-2016第一学期高三数学（文）寒假作业检测试卷考生注意：1. 本试卷分第Ⅰ卷基础题（135分）和第Ⅱ卷提高题（15分）两部分，共120分。
2. 试卷书写规X 工整，卷面整洁清楚，酌情减3-5分，并计入总分。
知 识 技 能学习能力 习惯养成 总分内容 命题集合解析与三角立体几何与函数几何证明复数线性规划 转化化归推理证明卷面整洁分数 10505525103-5分第Ⅰ卷 基础题（共135分）一、选择题: （每小题5分，共40分） 1.设虚数单位为i ，复数2ii-为（） A.12i -- B.12i -+ C.12i + D.12i -2.一个几何体的三视图如图所示，其中俯视图是菱形，则该几何体的侧面积为( )A.3＋6B.3＋ 5C.2＋6D.2＋ 53.下列四种说法中，错误．．的个数是（） ①{0,1}A =的子集有3个；②“若22,am bm a b <<则”的逆命题为真；③“命题p q ∨为真”是“命题p q ∧为真”的必要不充分条件；④命题“x R ∀∈，均有2320x x --≥”的否定是：“,x R ∃∈使得2320x x --≤”A ．0个B ．1个C ．2个D ．3个4. 已知函数x x x f 23)(3+=，且)2(),31(log ),23(ln 3.02f c f b f a ===，则（A ）c a b >> (B) a c b >>(C)a b c >> (D) b a c >>5.若集合{}0,1,2,3,4M =，集合{}23N x x =-<，则下列判断正确的是（） A.x M ∉，是x N ∉的充分必要条件； B.x M ∉，是x N ∉的既不充分也不必要条件； C.x M ∉，是x N ∉的充分不必要条件； D.x M ∉，是x N ∉的必要不充分条件。
6.已知双曲线()222210,0y x a b a b -=>>的一条渐近线与1y =-平行，且它的一个焦点在抛物线224x y =的准线上，则双曲线的方程为（）A.22136108y x -= B.221927y x -= C.22110836y x -= D.221279y x -= 7.已知()()cos 2,04f x x x R πωω⎛⎫=+∈> ⎪⎝⎭的最小正周期为π，将()y f x =的图像上所有的点的横坐标缩短为原来的12倍，纵坐标不变；再把所得的图像向右平移ϕ个单位长度，所得的图像关于原点对称，则ϕ的一个值是（） A.316πB.516π C.34π D.38π 8.在ABC ∆中，O 为中线BD 上的一个动点，若6BD =，则()OB OA OC ⋅+的最小值是（） A.0 B.-9 C.-18 D.-24二、填空题：（共30分）9. 袋中有形状、大小都相同的4只球，其中1只白球，1只红球，2只黄球，从中一次随机摸出2只球，则这2只球颜色不同的概率为________.10．若数列{}n a 是首项为13a =，公比1q ≠-的等比数列，n S 是其前n 项和，且5a 是14a 与32a -的等差中项，则19S =.11. 如图，圆O 的割线PA 过圆心O 交圆于另一点B ,弦CD 交OB 于点E ，且OCE P ∠=∠，P11题2==OA PB 则PE 的长等于____________.12.已知圆C 过点（1,0），且圆心在x 轴的正半轴上，直线l ：1y x =-被圆C所截得的弦长为过圆心且与直线l 垂直的直线的方程为.13.（1） 设0,0x y >>，若2是x 2与y 4的等比中项，则①222y x +的最小值为.②11x y+的最小值为. (2) 根据以上两个小题的解答，总结说明含条件等式的求最值问题的解决方法（写出两个） ①_________________________②______________________14.若函数()2,02lg ,0xkx x f x x x x ⎧+≤⎪=-⎨⎪>⎩有且只有2个不同零点，则实数k 的取值X 围是.三、解答题（本大题共5题，共65分）15.（12分）某营养师要求为某个儿童预订午餐和晚餐.已知一个单位的午餐含12个单位的碳水化合物，6个单位的蛋白质和6个单位的维生素C,一个单位的晚餐含8个单位的碳水化合物，6个单位的蛋白质和10个单位的维生素C.另外，该儿童这两餐需要的营状中至少含64个单位的碳水化合物和42个单位的蛋白质和54个单位的维生素C.如果一个单位的午餐、晚餐的费用分别是2.5元和4元，那么要满足上述的营养要求，并且花费最少，应当为该儿童分别预订多少个单位的午餐和晚餐？16.（13分）已知向量,cos ),(sin ,cos ),4444x x x x==m n 函数()f x =⋅m n . （Ⅰ）求函数()f x 的最小正周期及单调递减区间；（Ⅱ）在锐角ABC ∆中，,,A B C 的对边分别是,,a b c ，且满足1cos ,2a C cb += 求(2)f B 的取值X 围.17.（14分）如图，正方形ACDE 所在的平面与平面ABC 垂直，M 是CE 和AD 的交点，BC AC ⊥，且BC AC =．（1）求证：⊥AM 平面EBC ；（2）求直线AB 与平面EBC 所成的角的大小； （3）求二面角C EB A --的大小．( 4 ) 你认为求二面角常用的方法有哪些？请按应用的重要程度写出3种，并就其中一种方法谈谈它的应用条件.18．（13分）已知函数()()1ln 0,f x a x a a R x=+≠∈ （1）当1a =时，求函数()f x 在2x =处的切线斜率及函数()f x 的单减区间； （2）若对于任意(]0,x e ∈，都有()0f x >，某某数a 的取值X 围。
一年级寒假开学测试题
一年级寒假开学测试题亲爱的同学们，经过一个月快乐的寒假生活，你的收获一定不少吧！接下来，让我们一起认真完成下面的练习，检查一下自己的寒假所得吧！第一部分语文一．看拼音，写词语。
（16 分）fēi niǎo bái yún shuǐ tián yuâ yá（）（）（）（）shàng shān mù tou mãn kǒu xià chē（）（）（）（）二.我会给下面的生字找朋友。
（ 4分）例：左－右东－（）雨－（）里－（）开－（）三．我会填。
（ 4分）1.“心”的第二笔是。
2. “山”的第一笔是，“出”的第一笔是。
3.给“她”换个偏旁可以变成。
四．我会把句子补充完整，并加上合适的标点符号。
（ 6分）1.你去吗（）2. ，操场上真热闹呀（）3. 从（）五．课外积累我最棒！（ 20分）1.我知道到了冬天冬眠的动物有、。
2.花生的果实长在（），（）的果实也长在土里。
荷花的果实长在（），苹果树的果实长在（）。
3.根据《弟子规》内容连线。
泛爱众，而亲仁问起对，势勿移身有伤，怡亲忧后有急，借不难近必趋，退必迟有余力，则学文借人物，及时还德有伤，贻亲羞4.在《书本里的蚂蚁》中，小女孩把那只蚂蚁当成了一个“会走路”的（）。
5.在《豆蔻镇的居民和强盗》一书中，有（）个强盗，他们虽然是强盗，但是却非常有（）。
6.寒假里，我们度过了一个快乐的节日是（），过这个节日的时候，家家户户都要往门上贴（），孩子们要穿（），吃（），还要放（）。
大家都非常（）。
第二部分数学一．我是计算小能手。
（16分）9－9 = 5＋9 = （）＋5 =15 4＋4＋7 = 9＋0 = 8＋7 = 8＋（）=18 5＋8－10 = 9－0 = 4＋8 = （）-5 =15 9-6＋8 = 0＋9 = 7＋5 = 18-（）=10 10-5-0 = 二．我能按要求分一分，画一画。
2023-2024学年高二下学期寒假检测(开学考试)英语试题
长郡中学2024年高二寒假作业检测英语得分：____________本试题卷共10页。
时量120分钟。
满分150分。
第一部分听力（共两节，满分30分）做题时，先将答案标在试卷上.录音内容结束后，你将有两分钟的时间将试卷上的答案转涂到答题卡上。
第一节（共5小题；每小题1.5分，满分7.5分）听下面5段对话。
每段对话后有一个小题，从题中所给的A、B、C三个选项中选出最佳选项，并标在试卷的相应位置。
听完每段对话后，你都有10秒钟的时间来回答有关小题和阅读下一小题。
每段对话仅读一遍。
例：How much is the shirt?A. £19.15.B. £9.18.C. £9.15.答案是C.1. When did the woman leave for the movie?A. 5 minutes ago.B. 15 minutes ago.C. 30 minutes ago.2. Which food does the man usually avoid?A. Cream.B. Biscuits.C. Chocolate.3. What is the probable relationship between the speakers?A. Relatives.B. Fellow students.C. Teacher and student.4. Who told Marie about the accident?A. Tom.B. Her father.C. Lucy.5. How many times has the man tried to wake Peter up?A. Once.B. Twice.C. Three times.第二节（共15小题；每小题1.5分，满分22.5分）听下面5段对话或独白。
每段对话或独白后有几个小题，从题中所给的A、B、C三个选项中选出最佳选项，并标在试卷的相应位置。
浙江省杭州市2023-2024学年高一下学期寒假作业检测(开学考试)数学试卷含答案
杭州钱江学校高一数学寒假作业检测（答案在最后）一、单选题：本题共8小题，每小题5分，共40分．每小题给出的选项中，只有一项是符合题目要求．1.已知集合{}|02A x x =<<，集合{}|11B x x =-<<，集合{}|10C x mx =+>，若()A B C ⊆ ，则实数m 的取值范围为（）A.{}|21m m -≤≤ B.1|12m m ⎧⎫-≤≤⎨⎬⎩⎭C.1|12m m ⎧⎫-≤≤⎨⎬⎩⎭D.11|24m m ⎧⎫-≤≤⎨⎬⎩⎭【答案】B 【解析】【分析】求出A ∪B ＝{x |﹣1＜x ＜2}，利用集合C ＝{x |mx +1＞0}，（A ∪B ）⊆C ，分类讨论，可得结论．【详解】由题意，A ∪B ＝{x |﹣1＜x ＜2}，∵集合C ＝{x |mx +1＞0}，（A ∪B ）⊆C ，①m ＜0，x 1m -＜，∴1m -≥2，∴m 12≥-，∴12-≤m ＜0；②m ＝0时，C ＝R,成立；③m ＞0，x 1m -＞，∴1m-≤-1，∴m ≤1，∴0＜m ≤1，综上所述，12-≤m ≤1，故选：B ．【点睛】此题考查了并集及其运算，以及集合间的包含关系，考查分类讨论的数学思想，属于中档题．2.三角函数值1sin ，2sin ，3sin 的大小顺序是A.123sin sin sin >> B.213sin sin sin >>C.132sin sin sin >> D.3 2 1sin sin sin >>【答案】B 【解析】【分析】先估计弧度角的大小，再借助诱导公式转化到090θ<< 上的正弦值，借助正弦函数在090θ<< 的单调性比较大小．【详解】解：∵1弧度≈57°，2弧度≈114°，3弧度≈171°．∴sin 1≈sin 57°，sin 2≈sin 114°＝sin 66°．sin 3≈171°＝sin 9°∵y ＝sin x 在090θ<< 上是增函数，∴sin 9°＜sin 57°＜sin 66°，即sin 2＞sin 1＞sin 3．故选B ．【点睛】本题考查了正弦函数的单调性及弧度角的大小估值，是基础题．3.设a ＝log 54，b ＝（log 53）2，c ＝log 45，则（）A.a ＜c ＜b B.b ＜c ＜aC.a ＜b ＜cD.b ＜a ＜c【答案】D 【解析】【详解】∵a ＝log 54＜log 55＝1，b ＝（log 53）2＜（log 55）2＝1，c ＝log 45＞log 44＝1，所以c 最大单调增，所以又因为所以b<a 所以b<a<c.故选D ．4.已知函数74sin 20,66ππ⎛⎫⎛⎫⎡⎤=+∈ ⎪ ⎪⎢⎥⎝⎭⎣⎦⎝⎭y x x 的图象与直线y m =有三个交点的横坐标分别为()123123,,x x x x x x <<，那么1232x x x ++的值是（）A.34πB.4π3 C.5π3D.3π2【答案】C 【解析】【分析】先作出74sin 20,66ππ⎛⎫⎛⎫⎡⎤=+∈ ⎪ ⎪⎢⎝⎭⎣⎦⎝⎭y x x 的图像，结合图像利用对称性即可求得结果.【详解】先作出函数74sin 20,66y x x ππ⎛⎫⎛⎫⎡⎤=+∈ ⎪⎪⎢⎥⎝⎭⎣⎦⎝⎭的图象，如图，令4sin 246y x π⎛⎫=+=± ⎪⎝⎭，可得6x π=和23x π=，所以由对称性可得1223242,26333x x x x ππππ+=⨯=+=⨯=，故123523x x x π++=，故选：C．5.设(),0,παβ∈，()5sin 13αβ+=，1tan 22α=，则cos β的值是（）A.1665-B.1665C.3365- D.3365【答案】A 【解析】【分析】根据半角公式得出α的正切值，继而得出其正弦值和余弦值，再根据α的取值范围和题意判断出π,π2αβ⎛⎫+∈ ⎪⎝⎭，并得出αβ+的余弦值，最后根据恒等变换公式计算[]cos cos ()βαβα=+-即可.【详解】22tan142tan tan 12231tan 2αααα=⇒==>- ，因为(),0,παβ∈，ππ,42α⎛⎫∴∈ ⎪⎝⎭，且4sin cos 3αα=，又223sin cos 1cos 5ααα+=⇒=，得4sin 5α=.因为()0,πβ∈，则π3π,42αβ⎛⎫+∈⎪⎝⎭，又5sin()132αβ+=<，所以π,π2αβ⎛⎫+∈ ⎪⎝⎭，12cos()13αβ∴+=-，[]16cos cos ()cos()cos sin()sin 65βαβααβααβα=+-=+++=-.故选：A.6.设函数()2sin()f x x ωϕ=+，x R ∈，其中0ω>，||ϕπ<.若5()28f π=，(08f 11π=，且()f x 的最小正周期大于2π，则A.23ω=，12πϕ= B.23ω=，12ϕ11π=-C.13ω=，24ϕ11π=- D.13ω=，724πϕ=【答案】A 【解析】【详解】由题意125282118k k ωππϕπωπϕπ⎧+=+⎪⎪⎨⎪+=⎪⎩，其中12,k k Z ∈，所以2142(2)33k k ω=--，又22T ππω=>，所以01ω<<，所以23ω=，11212k ϕ=π+π，由ϕπ<得12πϕ=，故选A．【考点】求三角函数的解析式【名师点睛】有关sin()y A x ωϕ=+问题，一种为提供函数图象求解析式或某参数的范围，一般先根据图象的最高点或最低点确定A ，再根据周期或12周期或14周期求出ω，最后再利用最高点或最低点坐标满足解析式，求出满足条件的ϕ值，另一种时根据题目用文字形容的函数图象特点，如对称轴或曲线经过的点的坐标，根据题意自己画出图象，再寻求待定的参变量，题型很活，求ω或ϕ的值或最值或范围等.7.设()|31|x f x =-,c b a <<且()()()f c f a f b >>,则下列关系中一定成立的是A .3c ＞3bB.3b ＞3aC.3c +3a ＞2D.3c +3a ＜2【答案】D 【解析】【分析】画出()|31|x f x =-的图象，利用数形结合，分析可得结果.【详解】作出()131xf x =-的图象，如图所示，要使c b a <<，且()()()f c f a f b >>成立，则有0c <且0a >，313c a ∴<<，()()13,31c a f c f a ∴=-=-，又()()f c f a >，1331c a ∴->-，即332a c +<，故选D.【点睛】通过数与形的相互转化来解决数学问题的一种重要思想方法，.函数图象是函数的一种表达形式，它形象地揭示了函数的性质，为研究函数的数量关系提供了“形”的直观性．归纳起来，图象的应用常见的命题探究角度有：1、确定方程根的个数；2、求参数的取值范围；3、求不等式的解集；4、研究函数性质．8.已知()f x 是偶函数，且()f x 在[0,)+∝上是增函数，若()()12f ax f x +≤-在1,12x ⎡⎤∈⎢⎥⎣⎦上恒成立，则实数a 的取值范围是（）A.[﹣2，1] B.[﹣5，0]C.[﹣5，1]D.[﹣2，0]【答案】D 【解析】【分析】利用函数的奇偶性和单调性，可得|ax +1|≤|x ﹣2|对112x ⎡⎤∈⎢⎥⎣⎦恒成立，再分离参数利用函数单调性求最值即可求解【详解】由题意可得|ax +1|≤|x ﹣2|对112x ⎡⎤∈⎢⎥⎣⎦，恒成立，得x ﹣2≤ax +1≤2﹣x 对112x ⎡⎤∈⎢⎥⎣⎦，恒成立，从而3x a x -≥且1x a x -≤对112x ⎡⎤∈⎢⎥⎣⎦，恒成立，又3x y x -=单调递增∴a ≥﹣21xy x-=；单调递减，所以a ≤0，即a ∈[﹣2，0]，故选D ．【点睛】本题考查的是不等式、函数性质以及恒成立有关的综合类问题．在解答的过程当中充分体现了函数的性质、恒成立的思想以及问题转化的能力，属于中档题．二、多选题：本题共4小题，共20分．每小题给出的选项中，有多项符合题目要求．9.存在函数()f x 满足：对任意x ∈R 都有（）A.()sin cos f x x =B.()sin sin 2f x x =C.()cos cos 2f x x =D.()sin sin 3f x x=【答案】CD 【解析】【分析】分别取0x =、x π=可得()01f =、()01f =-，A 错误；同理，取3x π=、23x π=可得(22f =、(22f =-，B 错误；利用三角恒等变换将cos 2x 整理为关于cos x 的二次函数可判断C ；同理可判断D.【详解】A ：取0x =时，sin 0,cos 1x x ==，()01f =，取x π=时，sin 0,cos 1x x ==-，()01f =-，故A 不正确；B ：取3x π=时，sin ,sin 222x x ==，(22f =，取23x π=时，sin ,sin 222x x ==-，(22f =-，故B 错误；C ：()2cos cos 22cos 1f x x x ==-，令cos ,[1,1]t x t =∈-，则()221f t t =-，C 正确；D ：()sin sin 3sin(2)sin 2cos cos 2sin f x x x x x x x x==+=+222sin (1sin )(12sin )sin x x x x=⨯-+-⨯3332sin 2sin sin 2sin 3sin 4sin x x x x x x=-+-=-令sin ,[1,1]t x t =∈-，则()334,[1,1]f t t t t =-∈-，D 正确.故选：CD10.下列不等式中，正确的是（）．A.13π13πtan tan 45< B.ππsincos 57⎛⎫<- ⎪⎝⎭C.ππsin 55> D.ππtan 55>【答案】BC 【解析】【分析】利用诱导公式及三角函数的单调性判断A 、B ，利用三角函数线证明当π02x <<时sin tan <<x x x ，即可判断C 、D.【详解】对于A ：13πππtantan 3πtan 1444⎛⎫=+== ⎪⎝⎭，13π2π2πtantan 3πtan 0555⎛⎫=-=-< ⎪⎝⎭，所以13π13πtan tan 45>，故A 错误；对于B ：因为ππππ7654<<<，且sin y x =在π0,2⎛⎫ ⎪⎝⎭上单调递增，cos y x =在π0,2⎛⎫⎪⎝⎭上单调递减，所以1πππ2sin sin sin 26542=<<=，又πππcos cos cos 7762⎛⎫-=>= ⎪⎝⎭，所以ππsincos 57⎛⎫<- ⎪⎝⎭，故B 正确；对于C 、D ：首先证明当π02x <<时sin tan <<x x x ，构造单位圆O ，如图所示：则()1,0A ，设π0,2POA x ⎛⎫∠=∈ ⎪⎝⎭，则()cos ,sin P x x ，过点A 作直线AT 垂直于x 轴，交OP 所在直线于点T ，由=tan ATx OA，得=tan AT x ，所以()1,tan T x ，由图可知OPA TOA OPA S S S << 扇形，即21111sin 11tan 222x x x ⨯⨯<⨯⨯<⨯⨯，即sin tan <<x x x π02x ⎛⎫<< ⎪⎝⎭，所以ππsin 55>，ππtan 55<，故C 正确，D 错误；故选：BC11.关于函数()|ln |2||f x x =-，下列描述正确的有（）A.()f x 在区间(1,2)上单调递增B.()y f x =的图象关于直线2x =对称C.若1212,()(),x x f x f x ≠=则124x x +=D.()f x 有且仅有两个零点【答案】ABD 【解析】【分析】作出函数()f x 的图象，由图象观察性质判断各选项．【详解】根据图象变换作出函数()f x 的图象（()ln 2f x x =-，作出ln y x =的图象，再作出其关于y 轴对称的图象，然后向右平移2个单位，最后把x 轴下方的部分关于x 轴翻折上去即可得），如图，由图象知()f x 在(1,2)是单调递增，A 正确，函数图象关于直线2x =对称，B 正确；12()()f x f x k ==，直线y k =与函数()f x 图象相交可能是4个交点，如图，如果最左边两个交点横坐标分别是12,x x ，则124x x +=不成立，C 错误，()f x 与x 轴仅有两个公共点，即函数仅有两个零点，D 正确．故选：ABD ．12.设函数()f x 的定义域为R ，满足()()12f x f x +=，且当(]0,1x ∈时，()()1f x x x =-.若对任意(],x m ∈-∞，都有()89f x ≥-，则实数m 的值可以是（）A.94B.73C.52D.83【答案】AB 【解析】【分析】因为(1)2()f x f x +=，可得()2(1)f x f x =-，分段求解析式，结合图象可得．【详解】解：因为(1)2()f x f x +=，()2(1)f x f x ∴=-，函数图象如下所示：(0x ∈ ，1]时，1()(1)[4f x x x =-∈-，0]，(1x ∴∈，2]时，1(0x -∈，1]，1()2(1)2(1)(2)[2f x f x x x =-=--∈-，0]；(2x ∴∈，3]时，1(1x -∈，2]，()2(1)4(2)(3)[1f x f x x x =-=--∈-，0]，当(2x ∈，3]时，由84(2)(3)9x x --=-解得73x =或83x =，若对任意(x ∈-∞，]m ，都有8()9f x - ，则73m ．故选：AB ．【点睛】本题考查分段函数的性质的应用，解答的关键是根据函数的性质画出函数图象，数形结合即可得解；三、填空题：本题共4小题，每小题5分，共20分．13.函数()()21256f x log x x =-+-的单调减区间是______．【答案】522，⎛⎫ ⎪⎝⎭【解析】【分析】根据对数函数的定义域及复合函数单调性的判断即可求得单调递减区间．【详解】因为()()21256f x log x x =-+-所以2560x x -+->解得()2,3x ∈因为()12f x log x =为单调递减函数，所以由复合函数单调性判断可知应该取()256f x x x =-+-的单调递增区间，即5,2x ⎛⎫∈-∞ ⎪⎝⎭结合定义域可得函数()()21256f x log x x =-+-的单调减区间是522，⎛⎫⎪⎝⎭【点睛】本题考查了复合函数单调区间的求法，注意对数函数的真数大于0，属于基础题．14.已知0a >，0b >，且111a b +=，则1411a b +--的最小值为___.【答案】4【解析】【分析】由等式111a b +=可得出1a >，1b >以及1a b a =-，代入1411a b +--可得出()14141111a ab a +=+----，利用基本不等式可求得结果.【详解】0a > ，0b >，且111a b +=，得1a >，1b >以及1ab a =-，()14141414111111a a ab a a a ∴+=+=+-≥=------，当且仅当32a =时，等号成立，因此，1411a b +--的最小值为4.故答案为：4.【点睛】本题考查利用基本不等式求最值，解题时注意对定值条件进行化简变形，考查计算能力，属于中等题.15.函数f （x ）＝log 2（kx 2+4kx +3）．①若f （x ）的定义域为R ，则k 的取值范围是_____；②若f （x ）的值域为R ，则k 的取值范围是_____．【答案】①.[0，34）②.k 34≥【解析】【分析】（1）根据()f x 的定义域为R ，对k 分成0,0,0k k k =><三种情况分类讨论，结合判别式，求得k 的取值范围.（2）当()f x 值域为R 时，由00k >⎧⎨∆≥⎩求得k 的取值范围.【详解】函数f （x ）＝log 2（kx 2+4kx +3）．①若f （x ）的定义域为R ，可得kx 2+4kx +3＞0恒成立，当k ＝0时，3＞0恒成立；当k ＞0，△＜0，即16k 2﹣12k ＜0，解得0＜k 34＜；当k ＜0不等式不恒成立，综上可得k 的范围是[0，34）；②若f （x ）的值域为R ，可得y ＝kx 2+4kx +3取得一切正数，则k ＞0，△≥0，即16k 2﹣12k ≥0，解得k 34≥．故答案为：(1).[0，34）(2).k 34≥【点睛】本小题主要考查根据对数型复合函数的定义和值域求参数的取值范围，属于中档题.16.函数253sin cos 82y x a x a =+⋅+-在闭区间0,2π⎡⎤⎢⎥⎣⎦上的最大值是1，则=a __________．【答案】32【解析】【分析】令[]cos ,0,1x t t =∈，即求25218y t at a =-++-在[]0,1上的最大值，需要根据对称轴的位置进行分类讨论即可求出结果.【详解】22535sin cos cos cos 82812y x a x a x a x a =+⋅+-=-+⋅+-，令[]cos ,0,1x t t =∈，则25218y t at a =-++-，对称轴2at =，若02a ≤，即0a ≤时，25218y t at a =-++-在0=t 处取得最大值，即51821a -=，解得125a =，与0a ≤矛盾，故不合题意，舍去；若012a <<，即12a <<时，25218y t at a =-++-在2a t =处取得最大值，即25122821a a a a ⎛⎫-+⋅+-= ⎪⎝⎭，即225120a a +-=，解得4a =-或32a =，因为12a <<，所以32a =；若12a ≥，即2a ≥时，25218y t at a =-++-在1t =处取得最大值，即251=1821a a -++-，解得2013a =，与2a ≥矛盾，故不合题意，舍去；综上：32a =.故答案为：32.四、解答题：本题共6小题，共70分．解答应写出文字说明，证明过程或演算步骤．17.已知a ∈R ，集合{}2230A x x x =--≤，{}220B x x ax =--=．（1）若1a =，求A B ⋂；（2）若A B A ⋃=，求实数a 的取值范围．【答案】（1）{}2,1-（2）71,3⎡⎤⎢⎥⎣⎦【解析】【分析】（1）首先解一元二次不等式求出集合A ，再根据条件求出集合B ，最后根据交集的定义计算可得；（2）依题意可得B A ⊆，则问题转化为关于x 的方程220x ax --=在区间[]1,3-上有两个不相等的实数根，结合二次函数的性质计算可得.【小问1详解】由2230x x --≤，即()()130x x +-≤，解得13x -≤≤，所以{}{}2230|13A x x x x x =--≤=-≤≤当1a =时{}{}2202,1B x x x =--==-，所以{}2,1A B =- 【小问2详解】因为A B A ⋃=，所以B A ⊆，关于x 的方程220x ax --=，因为280a ∆=+>，所以关于x 的方程220x ax --=必有两个不相等的实数根，依题意关于x 的方程220x ax --=在区间[]1,3-上有两个不相等的实数根，所以()()2213211203320a a a ⎧-<<⎪⎪⎪--⨯--≥⎨⎪--≥⎪⎪⎩，解得713a ≤≤，所以实数a 的取值范围为71,3⎡⎤⎢⎥⎣⎦.18.设集合{}12A x x =-≤≤，{}121B x m x m =-<<+．（1）若B A ⊆，求实数m 的取值范围；（2）若()R B A I ð中只有一个整数2-，求实数m 的取值范围．【答案】（1）(]1,20,2⎡⎤-∞-⎢⎥⎣⎦ ；（2）3,12⎛⎫-- ⎪⎝⎭.【解析】【分析】（1）分B =∅和B ≠∅两种情况讨论，结合B A ⊆列出关于实数m 的不等式（组），解出即可得出实数m 的取值范围；（2）求出集合R A ð，由题意得知B ≠∅，且有1213122213m m m m -<+⎧⎪-≤-<-⎨⎪-<+≤⎩，解该不等式组即可得出实数m 的取值范围.【详解】（1）集合{}12A x x =-≤≤，{}121B x m x m =-<<+.①当B =∅时，121m m -≥+，解得2m ≤-，符合要求；②当B ≠∅时，若B A ⊆，121m m -<+，则12111212m m m m -<+⎧⎪-≥-⎨⎪+≤⎩，解得102m ≤≤.综上，实数m 的取值范围是(]1,20,2⎡⎤-∞-⎢⎥⎣⎦；（2） 集合{}12A x x =-≤≤，{1R A x x ∴=<-ð或}2x >，若()B A R ð中只有一个整数2-，则必有B ≠∅，1213122213m m m m -<+⎧⎪∴-≤-<-⎨⎪-<+≤⎩，解得312m -<<-，因此，实数m 的取值范围是3,12⎛⎫-- ⎪⎝⎭．【点睛】本题考查利用集合的包含关系求参数的取值范围，同时也考查了利用交集与补集的混合运算求参数，解题时要结合题意列出不等式组进行求解，考查分析问题和解决问题的能力，属于中等题.19.设函数()sin ,f x x x =∈R .（1）已知[0,2),θ∈π函数()f x θ+是偶函数，求θ的值；（2）求函数22[()][()]124y f x f x ππ=+++的值域.【答案】（1）3,22ππ；（2）331,122⎡-+⎢⎣⎦.【解析】【分析】(1)由函数的解析式结合偶函数的性质即可确定θ的值；(2)首先整理函数的解析式为()sin y a x b ωϕ=++的形式，然后确定其值域即可.【详解】(1)由题意结合函数的解析式可得：()()sin f x x θθ+=+，函数为偶函数，则当0x =时，()02k k Z πθπ+=+∈，即()2k k Z πθπ=+∈，结合[)0,2θ∈π可取0,1k =，相应的θ值为3,22ππ.(2)由函数的解析式可得：22sin sin 124y x x ππ⎛⎫⎛⎫=+++ ⎪ ⎪⎝⎭⎝⎭1cos 21cos 26222x x ππ⎛⎫⎛⎫-+-+ ⎪ ⎪⎝⎭⎝⎭=+11cos 2cos 2226x x ππ⎡⎤⎛⎫⎛⎫=-+++ ⎪ ⎪⎢⎥⎝⎭⎝⎭⎣⎦111cos 2sin 2sin 2222x x x ⎛⎫=--- ⎪ ⎪⎝⎭1331cos 2sin 2222x x ⎛⎫=-- ⎪ ⎪⎝⎭31sin 226x π⎛⎫=+- ⎪⎝⎭.据此可得函数的值域为：1,122⎡-+⎢⎣⎦.【点睛】本题主要考查由三角函数的奇偶性确定参数值，三角函数值域的求解，三角函数式的整理变形等知识，意在考查学生的转化能力和计算求解能力.20.已知函数())2πcos 204f x x x ωωω⎛⎫=-++> ⎪⎝⎭的最小正周期是π．（1）求函数()y f x =的单调递增区间；（2）若对任意的π5π,1212x ⎡⎤∈-⎢⎥⎣⎦，都有()2f x m -≤，求m 的取值范围．【答案】（1）62ππ,π,Zπ3k k k ⎡⎤-+-+∈⎢⎥⎣⎦（2）2,0⎤-⎦【解析】【分析】（1）利用二倍角公式及两角和的余弦公式化简，再根据周期公式求出ω，即可得到函数解析式，最后根据余弦函数的性质求出单调递增区间；（2）由x 的取值范围求出π23x +的范围，即可求出()f x 的值域，由()22m f x m -≤≤+恒成立得到关于m 的不等式组，解得即可.【小问1详解】因为()2πcos 24f x x x ωω⎛⎫=-++ ⎪⎝⎭πcos 224x x ωω⎛⎫=+ ⎪⎝⎭πcos 222x x ωω⎛⎫=++ ⎪⎝⎭cos 22x xωω=132cos 2sin 222x x ωω⎛⎫=- ⎪ ⎪⎝⎭π2cos 23x ω⎛⎫=+ ⎪⎝⎭，又0ω>且函数的最小正周期是π，所以2ππ2T ω==，解得1ω=，所以()π2cos 23f x x ⎛⎫=+ ⎪⎝⎭，令Z ππ2π22π,3k x k k -+≤+≤∈，解得2ππππ,Z 36k x k k ≤--+≤+∈，所以函数()y f x =的单调递增区间为62ππ,π,Z π3k k k ⎡⎤-+-+∈⎢⎥⎣⎦.【小问2详解】当π5π,1212x ⎡⎤∈-⎢⎣⎦，则ππ7π2,366x ⎡⎤+∈⎢⎥⎣⎦，所以πcos 21,32x ⎡⎛⎫+∈-⎢ ⎪⎝⎭⎣⎦，则()f x ⎡∈-⎣，因为对任意的π5π,1212x ⎡⎤∈-⎢⎥⎣⎦，都有()2f x m -≤，即对任意的π5π,1212x ⎡⎤∈-⎢⎣⎦，都有()22f x m -≤-≤，即对任意的π5π,1212x ⎡⎤∈-⎢⎣⎦，都有()22m f x m -≤≤+，所以222m m ⎧+≥⎪⎨-≤-⎪⎩20m ≤≤，即m的取值范围为2,0⎤-⎦.21.已知函数()ln (0,e 2.71828e xaf x x a =->=L 为自然对数的底数）.（1）当1a =时，判断函数()f x 的单调性和零点个数，并证明你的结论；（2）当[]1,e x ∈时，关于x 的不等式()2ln f x x a >-恒成立，求实数a 的取值范围.【答案】（1）函数()f x 的零点个数为1个，证明见解析（2）()e 1e,∞++【解析】【分析】（1）利用函数单调性证明，再利用零点存在性定理即可知零点个数.（2）将()2ln f x x a >-转化为ln ln e ln e ln a x x a x x -+-+>，构造函数()e xg x x =+，转化为ln ln a x x ->，即ln ln a x x >+，即()max ln ln a x x >+，求解即可.【小问1详解】函数()f x 的定义域为()0,∞+.当1a =时，函数()e1ln x f x x =-在()0,∞+上单调递减，证明如下：任取()12,0,x x ∈+∞，且12x x <，()()12121212211111ln ln ln ln e e e ex x x x f x f x x x x x -=--+=--211221e e ln e e x x x x x x -=+⋅∵120x x <<，∴21211,e e 0x x x x >->，21ln 0xx ∴>∴()()120f x f x ->，即()()12f x f x >.所以函数()e1ln x f x x =-在()0,∞+上单词递减.又1111(1)ln10,(e)ln e 10e e e ex x f f =-=>=-=-<∴()e 1ln xf x x =-在区间()1,e 上存在零点，且为唯一的零点.∴函数()f x 的零点个数为1个【小问2详解】()2ln f x x a >-可化为ln 2ln e xaa x x +>+.可化为ln e ln ln a x a x x x -+->+.可化为ln ln e ln e ln a x x a x x -+-+>.令()e xg x x =+，可知()e x g x x =+在R 单调递增，所以有ln ln a x x ->，即ln ln a x x>+令()ln h x x x =+，可知()ln h x x x =+在(0,)+∞上单调递增.即()ln h x x x =+在[]1,e 上单调递增，max ()(e)ln e e 1eh x h ==+=+e 1max ln ()e 1ln e a h x +∴>=+=，e 1e a +∴>所以实数a 的取值范围是()e 1e,∞++.【点睛】方法点睛：本题考查不等式的恒成立问题，不等式恒成立问题常见方法：①分离参数()a f x ≥恒成立(()max a f x ≥即可)或()a f x ≤恒成立（()min a f x ≤即可）；②数形结合(()y f x =图像在()y g x =上方即可)；③讨论最值()min 0f x ≥或()max 0f x ≤恒成立.22.已知函数2()|2|f x x x x a =+-，其中a 为实数．（Ⅰ）当1a =-时，求函数()f x 的最小值；（Ⅱ）若()f x 在[1,1]-上为增函数，求实数a 的取值范围；（Ⅲ）对于给定的负数a ，若存在两个不相等的实数12,x x （12x x <且20x ≠）使得12()()f x f x =，求112x x x +的取值范围.【答案】（Ⅰ）12-（Ⅱ）2a ≤-或0a >；（Ⅲ）见解析【解析】【分析】（Ⅰ）由题可知2222,2()22,2x ax x af x x x x a ax x a⎧-≥=+-=⎨<⎩当1a =-时，222,2()2,2x x x f x x x ⎧+≥-=⎨-<-⎩，分别讨论该函数在各段上的最小值和区间端点值，进而求出在整个定义域上的最小值；（Ⅱ）因为()f x 在[1,1]-上为增函数，分0a >，0a =，0a =三种情况讨论即可（Ⅲ）因为a<0，则()f x 在(,)2a -∞上为减函数，在(,)2a +∞上为增函数，所以122ax x <<，令112x x M x +=，分122aa x ≤<，12x a <两种情况具体讨论即可．【详解】解：2222,2()22,2x ax x a f x x x x a ax x a⎧-≥=+-=⎨<⎩(Ⅰ)当1a =-时，222,2()2,2x x x f x x x ⎧+≥-=⎨-<-⎩所以当12x =-时()()2222f x x x x +=≥-有最小值为1122f ⎛⎫-=- ⎪⎝⎭；当2x =-时，由()()22f x x x =-<-得()1242f -=>-，所以当1a =-时，函数()f x 的最小值为12-（Ⅱ）因为()f x 在[1,1]-上为增函数，若0a >，则()f x 在R 上为增函数，符合题意；若0a =，不合题意；若a<0，则12a≤-，从而2a ≤-综上，实数a 的取值范围为2a ≤-或0a >．（Ⅲ）因为a<0，则()f x 在(,)2a -∞上为减函数，在(,)2a +∞上为增函数，所以122ax x <<，令112x x M x +=1、若122a a x ≤<，则12x x a +=，由20x ≠知22a x a <≤-且20x ≠所以121222221x a x a x a x x a x x x -+=+-=--+令()1ag x x a x=--+，则()g x 在，[上为增函数，在)+∞，(-∞上为减函数(1)当4a ≤-时，2a≤a ->,则()g x 在，[上为增函数，在]a -，[2a上为减函数从而当22ax a <<-且20x ≠所以2()1g x a ≥-+或2()1g x a≤--+(2)当41a -<<-时，2a>且a ->,则()g x 在，[,0)2a上为增函数，在]a -上为减函数从而当22ax a <<-且20x ≠所以2()12ag x >+或2()1g x a ≤-+(3)当10a -≤<时，2a >且a -<,则()g x 在(0,]a -，[,0)2a上为增函数，从而当22ax a <<-且20x ≠所以2()12ag x >+或2()22g x a <-2、若12x a <，则2122222ax x ax =-，2212x x x a=-且2x a>-第21页/共21页2222222211222(,22)(11)1x x x x a x a a x a x x x x a+=+=--∞-∈+---因为221a a-≤-+综上所述，当4a ≤-时，112x x x +的取值范围为(,1]1,)a a -∞--+-++∞ ；当41a -<<-时，112x x x +的取值范围为(,1](1,)2a a +-∞--++∞ ；当10a -≤<时，112x x x +的取值范围为(,22)(1,)2a a -∞-++∞ ．【点睛】本题考查函数的综合应用，包括求最值，单调性，分类讨论思想等，属于偏难题目．。
人教版初一上册寒假作业测试
人教版初一上册寒假作业测试很多同学因为假期贪玩而耽误了学习，以至于和别的同学落下了差距，因此，小编为大家准备了这篇人教版初一上册寒假作业测试，希望可以帮助到您!基础检测1、计算：(1)15+(-22) (2)(-13)+(-8) (3)(-0.9)+1.512、计算：(1)23+(-17)+6+(-22)(2)(-2)+3+1+(-3)+2+(-4)3、计算：(1)(2)拓展提高4.(1)绝对值小于4的所有整数的和是________;2)绝对值大于2且小于5的所有负整数的和是________。
5.若︱a︱=3，︱b︱=2，则︱a+b︱________。
6.已知︱a︱=1,︱b︱=2,︱c︱=3,且ac，求a+b+c的值。
7.若18.计算：9.计算：观察内容的选择，我本着先静后动，由近及远的原则，有目的、有计划的先安排与幼儿生活接近的，能理解的观察内容。
随机观察也是不可少的，是相当有趣的，如蜻蜓、蚯蚓、毛毛虫等，孩子一边观察，一边提问，兴趣很浓。
我提供的观察对象，注意形象逼真，色彩鲜明，大小适中，引导幼儿多角度多层面地进行观察，保证每个幼儿看得到，看得清。
看得清才能说得正确。
在观察过程中指导。
我注意帮助幼儿学习正确的观察方法，即按顺序观察和抓住事物的不同特征重点观察，观察与说话相结合，在观察中积累词汇，理解词汇，如一次我抓住时机，引导幼儿观察雷雨，雷雨前天空急剧变化，乌云密布，我问幼儿乌云是什么样子的，有的孩子说：乌云像大海的波浪。
有的孩子说“乌云跑得飞快。
”我加以肯定说“这是乌云滚滚。
”当幼儿看到闪电时，我告诉他“这叫电光闪闪。
”接着幼儿听到雷声惊叫起来，我抓住时机说：“这就是雷声隆隆。
”一会儿下起了大雨，我问：“雨下得怎样?”幼儿说大极了，我就舀一盆水往下一倒，作比较观察，让幼儿掌握“倾盆大雨”这个词。
雨后，我又带幼儿观察晴朗的天空，朗诵自编的一首儿歌：“蓝天高，白云飘，鸟儿飞，树儿摇，太阳公公咪咪笑。
2021年高一下学期寒假作业检测(期初开学)英语试题 含答案
吉林油田高中xx届高一下学期寒假作业检测考试英语组卷人： 2016-3-1第Ⅰ卷第一部分：阅读理解（共两节，满分30分）第一节（共10小题；每小题2分，满分20分）阅读下列短文，从每题所给的四个选项（A,B,C,和D）中，选出最佳选项，并在答题卡上将该项涂黑。
AMy parents moved from Mexico to South Texas in the early 90s with the hope for a brighter future for their family of nine---my parents, four boys and three girls. My parents have always wanted the best for us and they have done everything possible to encourage us to get a university degree. Never did they think that by pushing us that direction, it also meant encouraging us to move away and be distant from each other.Initially(起初), getting accustomed to the American culture and lifestyle was very difficult for my parents. They e from a culture where kids grow up together, go to school together and most of the time live in the same neighborhood. From our point, American family values were a bit different. Typically in the US, when you turn 18, you are expectedto graduate from high school, move out, find a university, possibly find a partner, get married and start a life together. Most of these decisions take you away from home; usually you have to follow opportunity and wherever that will take you.This is my family’s current situation. I graduated from Bethel College in Indiana in xx, and in order to fulfill my financial responsibilities of paying off student loans, I moved to Washington State for my job with Experience Mission. Ideally my parents wanted me to e home to South Texas, but that wasn’t where my opportunity took me.Currently, my sister Jennifer lives in Waco, Texas, about eight hours from my parents. My two younger brothers also decided to go to college at Bethel and are away from my parents. More than likely, when they graduate, they will probably not move back home to South Texas.My parent never imagined that their dream for a better future would separate our family this way.Facebook has played a crucial(决定性的) role in the way we municate while living in different places. Since we all use Facebook, we have found a place to connect and feel as if we were there together with each other.1．We can infer from the first paragraph that ________.A. the writer’s family are immigrants to AmericaB. the writer’ family came to America for a better futureC. the writer’ parents’ didn’t want their children t o get a university degreeD. the writer’ parents pushed their children away from each other 2．The writer’s parents found it hard to be used to American life because ________.A. they were strangers in AmericaB. they suffered from a culture shockC. the local people disliked their familyD. different countries have different lives3．The writer didn’t return to work in South Texas after graduation because ________.A. he owed a lot of money while studying at collegeB. he didn’t graduate from universityC. he found his opportunity in Washiongton StateD. his father couldn’t find him a job in South Texas4．What will probably be talked about in the paragraph after the last?A. The writer’s parents’ life in Texas.B. How the parents learn to use Facebook.C. Wha t the writer’s brothers’ and sisters’ lives are like.D. How the writer’s family municate through Facebook.2021年高一下学期寒假作业检测（期初开学）英语试题含答案Acorn BankGarden & water millA delightful walled garden with old varieties of fruit trees and flower borders, set against the backdrop of a 17th-century red sandstone house overlooking the Eden Valley. Herb garden planted with over 200 medicinal and culinary herbs. Dogs on leads are wele on woodland walks. Children’s activity sheet available.Temple Soverby, Near Penrich, CA 10 lsp Tel: 017683 61893Open:19 March—30 October, daily except Monday and Tuesday, 10 am—5pmTearoom open from 11am—4. 30 pm, Shop 10am—5pmPrice: Adult ￡3, Child ￡1.5, Family ￡7.5The Beatrix Potter GalleryOriginal sketches and watercolors by Beatrix Potter for her children’s tales. xx exhibition will feature. The Tale of Mrs Tiggy-Winkle and The Tale of the Pie and The Patty-Pan. Also on display in this atmospheric 17t h-century building is information on Beatrix Potter’s life. Children’s quiz sheets and goodie bag.Beatrix Potter Gallery, Hawkshead, LA22 ONS Tel: 015394 36355Open:19 March—30 October, 10am—4. 30 pm, daily except Thursday and Friday. Also open 12—20 February, 2 & 3 June and 27 & 28 October.Price: Adult ￡3.50, Child ￡1.70, Family ￡8.70Hill TopBeatrix Potter wrote and illustrated many of the famous children’s stories in this 17th-century farmhouse which she bought 100 years ago. Today you can view her personal treasures and step into the garden which is planted with flowers and vegetables, just as it would have been in Beatrix Potter’s time.Please note that this is a small and popular house, which gets verybusy especially in school holidays. At peak times there are queues and by the end of the day not all visitors may be able to visit the house (we apologize for this). Please collect a timed ticket (including NT members) from the ticket office in the car park on your arrival.Hill Top, Near Sawrey, La22 OLF Tel: 015394 36269Open:19 March—30 October, 10: 30 am—4. 30 pm, daily except Thursday and Friday. Also open Thursday in August and 2 & 3 June and 27 & 28 October. Shop and Garden open Thursday and Friday, 10:am—5 pm. Ring for winter opening.Price: Adult ￡5, Child ￡2, Family ￡125. From the ads mentioned above, we can learn _______.A．visitors can admire the scene of the Beatrix Potter’s time in Hill TopB．visitors can admire the beautiful natural in both the Beatrix Gallery and Hill TopC．the Beatrix Potter Gallery is more popular with children than Hill Top D．Beatrix Gallery neighbors Hill Top6. If the Smiths and their 2 children visit the 3 sites, they will have to pay _______.A．￡28.2 B．￡23.4 C．￡28 D．￡337. If you have the tickets, you must be able to _______.A．visit Hill Top at opening timeB．visit the Beatrix Potter Gallery on FridayC．visit Acorn Bank at opening timeD．visit the three sites at any time8. We can learn from the ads that _______.A．you can enjoy yourself with a dog as you like at Acorn BankB．it is convenient for you to get a timed ticket for Hill Top C．children who have passed a quiz will be admitted to the Beatrix Potter GalleryD．you can book the tickets for Hill Top through the telephone number 015394 36355CPsychiatrists (心理学家) at the Harvard Medical School say that getting angry at work may actually be helpful in climbing up a career ladder. Theyfound that staying calm and frustrated can be harmful for an individual’s professional and even personal life.The Harvard Study of Adult Development tracked the lives of more than 800 men and women for the last 44 years, and discovered that those people who were suppressing（压抑）their negative emotions and feelings were at least 3 times more likely to admit that they had unrealized opportunities, disappointing careers and unsatisfying personal life. On the contrary, men and women who were able to let their anger and frustration out in a tactful(得体的) way, had far more chances to bee professionally successful and well-established. In addition, they said that they enjoyed much more emotional connection with their loved ones.Prof. George Vaillant, a psychiatrist at Harvard Medical School, who has been a director of the Study of Adult Development since 1965, said that it has always been a mon to think of anger as of some bad and dangerous emotion which had to be suppressed and replaced by a ‘positive thinking.’ However, this kind of approach is being considered by scientists as pletely damaging for a person when encountering with hardships of reality.The new research ers after a similar study on this matter. In the previous findings it was revealed that more than 55percent of individuals had experienced positive results out of some angry episode in their lives. Almost one third of volunteers who took part in the study said that the episode helped them realize their own mistakes.Dr. Howard Kassinove, who was leading the previous study, explained that people who suddenly bee targets of someone’s angry emotions, start to realize those people much better. He said: “While assertive expression is always preferable to angry expression , anger may serve as an important alerting function that leads to deeper understanding of the other person and the problem.”9. We can infer from the passage that _________.A a worker can pour out his anger at his bossB only a boss or a leader can pour out his angerC we can only pour our anger at those who understand usD only a person who is misunderstood can pour out his anger10. What Dr. Howard Kassiove said suggests that ______.A he believes anger is a very harmful emotionB his idea about anger agrees with that of Prof.,George VaillantC he hold a quite different opinion on anger from Prof. George VaillantD he thinks anger-management is necessary at work第二节（共5小题；每小题2分，满分10分）根据短文内容，从短文后的选项中选出能填入空白处的最佳选项。