2010高二年级5月月考试卷

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上海中学高二年级五月份月考试题答案

上海中学高二年级五月份月考试题语文试题答案1.A。

B.打烊yànɡ狡黠（xiá） C.迂讷nè D.似的shì2.A。

A.服帖收讫置之度外 B. C. 睢为雎 D.慈祥绝不反（翻）悔3.B。

A 方兴未艾：事物正在发展，一直不会停止。

“方”与“正”重复C 空前绝后：以前没有过，以后也不会有。

多用来形容非凡的成就或盛况。

D 不绝如缕：形容声音细微悠长或形势危急。

4.C。

A “普通患者”与“文化程度不高的患者”不能并列。

B 确定缺宾语。

D “近年来”与“将”矛盾5．C 6．C 7．D8．A（归：出嫁）9．B（①仅是说教儿识字的严格要求，⑤是说督促丈夫判案要公正。

）10．A（“带着儿子寄食外祖父家”是为了便于丈夫在外游历，不是亲戚族称道的原因。

）11．（1）只有一个儿子，如果不好，妹妹靠谁呢?（2）母亲用什么游戏取乐，就当把画像作为娱乐。

（3）略。

12．与善人居∕如入芝兰之室∕久而不闻其香∕即与之化矣∕与不善人居∕如入鲍鱼之肆∕久而不闻其臭∕亦与之化矣13．（1）不同，《临江仙》上片写现时“春恨”，下片追忆当年初见小蘋及“当时”的情景，采用的是倒叙（2分）。

《鹧鸪天》采用的是顺叙，上片写当年佳会，过片写别后思念，结尾写别后重逢（2分）。

（2）《临江仙》表现的是词人苦恋之情、孤寂之感。

（2分）《鹧鸪天》上片表现当年欢聚时豪情欢畅，逸兴飞扬。

下片表现的是离别后的相思之苦以及重逢后的惊喜之情（2分）。

14．（每空1分，共6分）（1）古来万事东流水/ 一尊还酹江月（2）既窈窕以寻壑，亦崎岖而经丘（3）契阔谈月明星稀乌鹊南飞（4）王勃（5）醒世恒言（6）卢梭法15．深厚而奥博（深厚的历史和文化），朴素而宁静，慷慨而宽容。

（1点1分，3分）16．①成为异乡者，每有乡愁，回到故乡便得到安慰、踏实，便能沉睡。

②受到重压，在少陵原恢复了元气和尊严。

（1点2分，共4分。

）17．对原生态生存环境、对故乡的无限珍惜和依恋，对现代文明大潮中原生态生存环境面临丧失的伤感，对原生态环境保护的期待和执著。

江苏省淮海中学2010届高二上学期第一次月考英语试卷

江苏省淮海中学2010届高二上学期第一次月考英语第一部分听力（共两节；满分20分）第一节（共5小题；每小题1分，共5分）听下面5段对话。

每段对话后有1小题，从题中所给的A、B、C三个选项中选出最佳选项，并标在试卷的相应位置。

听完每段对话后，你都有10秒钟的时间回答有关小题和阅读下一小题，每段对话仅读一遍。

1.What’s the problem of the man’s daughter?A.She dresses like a boy.B.She likes noisy rock music best.C.She probably smokes.2.What does the man think of the woman’s work?A.He’s found some mistakes.B.He’s thinking highly of it.C.He isn’t satisfied of it.3. What’s the girl’s problem?A.She doesn’t know how to express it.B.She often argues with her mother.C.She can’t find her favorite music CD.4.Why has Mr. Lee been fired?A. He’s impatient with students.B.He knows too little.C.He broke the school rules.5.What does the man mean?A. He doesn’t know the details.B.He doesn’t agree with the woman.C.He thinks the same way as the woman.第二节{共15小题；每小题1分，满分15分}听下面五段对话或独白。

高二5月月考数学(文)试题Word版含答案

数学文科试题一、选择题(本大题共14小题，每小题5分，共70分．在每小题给出的四个选项中，只有一项是符合题目要求的。

)1．给出四个命题：①函数是其定义域到值域的映射；② f (x )＝x －3＋2－x 是函数；③函数y ＝2x (x ∈N)的图象是一条直线；④ f (x )＝x 2x与g (x )＝x 是同一个函数．其中正确的有( )A ．1个B ．2个C ．3个D ．4个2．下列四个函数中，在区间(0,1)上为减函数的是( ) A ．y ＝log 2x B ．y ＝1x C ．y ＝－(12)x D ．y ＝x 33.函数3yx x 的递增区间是（）A ．),0(+∞B ．)1,(-∞C ．),(+∞-∞D ．),1(+∞ 4.32()32f x ax x =++,若'(1)4f -=,则a 的值等于（） A ．319 B ．316 C ．313 D ．3105．若曲线y ＝x 2＋ax ＋b 在点(0，b )处的切线方程是x －y ＋1＝0，则( ) A ．a ＝－1，b ＝1 B ．a ＝－1，b ＝－1 C ．a ＝1，b ＝－1D ．a ＝1，b ＝16．已知a 是函数f (x )＝2x －log 12x 的零点，若0<x 0<a ，则f (x 0)的值满足( )A ．f (x 0)＝0B ．f (x 0)>0C ．f (x 0)<0D ．f (x 0)的符号不能确定7．若a >2，则函数 f (x )＝13x 3－ax 2＋1在区间(0,2)上恰好有( )A ．0个零点B ．1个零点C ．2个零点D ．3个零点 8．已知函数 f (x )＝ln a ＋ln xx在[1，＋∞)上为减函数，则实数a 的取值范围是 ( )A ．0<a <1eB ．0<a ≤eC ．a ≤eD ．a ≥e9．若0()ln 0xe x g x xx ⎧≤=⎨>⎩，则1(())2g g =（）A ．12B ．1C ．12e D ．ln 2-10．已知32()f x ax bx cx d =+++的图象如图所示，则有 ( ) A ．0b < B ．01b << C ．12b << D ．2b >11．已知函数 f (x )的导函数 f ′(x )＝a (x ＋1)(x －a )，若f (x )在x ＝a 处取到极大值，则a 的取值范围是( )A ．(－1,0)B ．(2，＋∞)C ．(0,1)D ．(－∞，－3)12．已知函数f (x )＝⎩⎨⎧|lg x |，0<x ≤10，－12x ＋6，x >10.若a ，b ，c 互不相等，且f (a )＝f (b )＝f (c )，则abc 的取值范围是( ) A ．(1,10) B ．(5,6) C ．(10,12) D ．(20,24)13. 设()f x 是连续的偶函数，且当x >0时()f x 是单调函数，则满足3()4x f x f x +⎛⎫= ⎪+⎝⎭的所有x 之和为（）A ．3-B ．3C ．8-D ．814．函数在定义域R 内可导，若，且当时，，设则（）A ．B ．C ．D ．二、填空题(本大题共6小题，每题7分，共42分．把答案填在题中横线上．) 15．f (x )＝log a x 的导函数为______________.16．定义非空集合A 的真子集的真子集为A 的“孙集”，则集合{}1,3,5,7,9的“孙集”的个数有__________个．17．设是定义在上且以3为周期的奇函数，若，，则实数的取值范围是 __________．)(x f )2()(x f x f -=)1,(-∞∈x 0)()1(<'-x f x ).3(),21(),0(f c f b f a ===c b a <<b a c <<a b c <<a c b <<()f x R (1)1f ≤23(2)1a f a -=+a yxo1218．已知函数，，的零点分别为，则的大小关系是__________．19．设函数 f (x )＝ax 3－3x ＋1(x ∈R )，若对于任意x ∈[－1,1]，都有f (x )≥0成立，则实数a 的值为________．20．定义在R 上的偶函数f (x )，满足f (x ＋1)＝－f (x )，且f (x )在[－1,0]上是增函数，下列五个关于f (x )的命题中：①f (x )是周期函数；②f (x )的图象关于x ＝1对称；③f (x )在[0,1]上是增函数；④f (x )在[1,2]上是减函数； ⑤f (2)＝f (0)．其中正确命题的序号是________．三、解答题(本大题共3小题，共38分，21，22题每题12分23题14分．解答应写出文字说明，证明过程或演算步骤．) 21．已知函数11()ln()xf x x x =+-+ （1）求()f x 的单调区间；（2）求曲线()y f x =在点（1，1()f ）处的切线方程；xx x f 2)(+=x x x g ln )(+=1)(--=x x x h ,,21x x 3x 321,,x x x22．已知函数32()23 3.f x x x =-+（1）求曲线()y f x =在点2x =处的切线方程；（2）若关于x 的方程()0f x m +=有三个不同的实根，求实数m 的取值范围.23．已知函数f (x )＝13x 3－ex 2＋mx ＋1(m ∈R )，g (x )＝ln x x.(1)求函数f (x )的单调区间；(2)对任意x 1，x 2∈R ＋，若g (x 1)<f ′(x 2)恒成立，求实数m 的取值范围．。

全南中学高二年级5月份历史月考试卷

全南中学高二年级5月份历史月考试卷一选择题1．王国维在《殷商制度论》中认为“周人制度大异于商者，一曰立子立嫡之制，由是而生宗法及丧服之制，并由是而有封建子弟之制，君天下臣诸侯之制”，实质上说明了A．商周政治制度存在差异性B．宗法制与分封制互为表里C．宗法制与礼制之间是因果关系 D．周文化的稳定性与延续性2.图1所示的中央机构创立于A.秦汉时期B.隋唐时期C.宋元时期D.明清时期3.19世纪中期，列强侵略激化了中国的社会矛盾，一场轰轰烈烈的农民运动在中国南方兴起。

这场运动是A.太平天国运动B.洋务运动C.维新变法运动D.义和团运动4.“西边的太阳就要落山了，……唱起那动人的歌谣。

”这首脍炙人口的《铁道游击队》主题曲反映的时代背景是A.甲午中日战争B.八国联军侵华战争C.抗日战争D.抗美援朝战争5、有人曾发出这样的感慨：“从前我国只是被西方大国打败过，现在竟被东方的小国打败了，而且是失败得那样惨，条约又订得那样苛刻，这是多么大的耻辱啊！”“被东方小国打败”是在下列那场战争中（）A．第一次鸦片战争 B．八国联军侵华战争C．甲午中日战争 D．第二次鸦片战争6、电影《建国大业》中有一个情节，建国前夕，毛泽东、周恩来联名写信给留居上海的宋庆龄：中山先生遗忘迄今实告实现。

至祁先生命驾北来，参加此一人民历史伟大的事业，并对于如何建设新中国给予指导。

"此信邀请宋庆龄参加的会议应该是：（）A、中国人民政治协商会议第一届全体会议B、内蒙古自治区成立大会C、第一届全国人民代表大会D、国共北平谈判7、新中国建立后美国长期实行孤立中国的政策，这一政策破产的标志是：（）A、中国与苏联等17国建交B、中美建交C、中国恢复在联合国的合法席位D、中国提出和平共处五项原则8．下图是近代中国人的著述或创办的报刊，其主张不能够反映当时人类社会政治文明前进方向的是9．澳大利亚人莫里循曾任《太晤士报》驻华首席记者，中华民国总统政治顾问，居住北京20余年（1897—1920）。

河南省伊川高中2010-2011学年高二上学期必修5第一次月考数学测试题

伊川高中II 部2009-2010学年第二学期第一次月考数学试题一、选择题(本大题共12个小题，每小题5分，共60分)1．2005是数列7,13,19,25,31,, 中的第（）项.A ．332B ．333C ．334D ．335 2．已知△ABC 中，a ＝4，b ＝43，∠A ＝30°，则∠B 等于( ) A ．30° B ．30°或150° C ．60°D ．60°或120°3．已知△ABC 中，AB ＝6，∠A ＝30°，∠B ＝120°，则△ABC 的面积为( ) A ．9B ．18C ．93D ．1834．在△ABC 中，sin A ：sin B ：sin C =3：2：4，则cos C 的值为（）A ．23 B ．－23 C ．14 D ．－145．一个等差数列的第5项等于10，前3项和等于3，那么它的首项与公差分别是( )A ．-2，3B ．2，- 3C ．-3，2D ．3，-26. 若{}n a 是等比数列，n a >0，且252645342=++a a a a a a ，那么53a a +的值为（）A ．5B ．-5C ． -5或5D ．25 7. 符合下列条件的三角形有且只有一个的是（） A ．a=1,b=2 ,c=3 B ．a=1,b=2 ,∠A=30° C ．a=1,b=2,∠A=100° D ．b=c=1, ∠B=458. 在ABC ∆中,若cos 4cos 3A bB a ==,则ABC ∆是( ) A ．直角三角形 B ．等腰三角形 C ．等腰或直角三角形D ．钝角三角形9．已知等差数列}{n a 中12497,1,16a a a a 则==+的值是( ) A ．15 B ．30 C ．31 D ．6410. 已知-1，1a ，2a ，-4成等差数列，且-1，b 1，b 2，b 3，-4成等比数列，则212b a a -的值为（） A ．—21 B ． 21 C ．21或—21 D ．41 11.设函数f (x )满足f (n +1)=2)(2nn f +(n ∈N *)且f (1)=2，则f (20)为（） A ．95B ．97C ．105D ．19212．在等差数列{}n a 中，10110,0a a <>，且1110||a a >，n S 是其前n 项和，则（）A ．125,S S S 都小于0，67,S S 都大于0B ．1210,S S S 都小于0，1112,S S 都大于0C ．1219,S S S 都小于0，2021,S S 都大于0D ．1220,S S S 都小于0，2122,S S 都大于0二、填空题(本大题共4个小题，每小题5分，共20分)13．已知数列 ,3219,1617,815,413试写出其一个通项公式：______ _____ ． 14．在△ABC 中，若AB ＝5，AC ＝5，且cos C ＝109，则BC ＝__________________．15. 船以每小时15km 的速度向东航行,船在A 处看到一个灯塔B 在北偏东60 ，行驶4h后，船到达C 处，看到这个灯塔在北偏东15 ，这时船与灯塔的距离为_______km ．16. 已知22()1x f x x =+，则111(1)(2)(3)(4)()()()234f f f f f f f ++++++_______．伊川高中II部2009-2010学年第二学期第一次月考数学试题一、选择题(本大题共12个小题，每小题5分，共60分)题号 1 2 3 4 5 6 7 8 9 10 11 12 答案二、填空题(本大题共4个小题，每小题5分，共20分)13．_________________________ 14．________________________15．_________________________ 16．________________________三、解答题(本大题共6个小题，共70分)17．(本小题满分10分)已知a＝33，c＝2，B＝150°，求边b的长及S△．18. (本小题满分12分)在∆ABC 中，设bbc B A -=2tan tan ，求A 的值.19．（本小题满分12分）在数列{a n }中，cn a a a n n +==+11,2（c 是常数，n=1,2,3,…）,且a 1,a 2,a 3成公比不为1的等比数列.(1)求c 的值；(2)求数列{a n }的通项公式.20．（本小题满分12分）数列{a n }中，18a =，42a =，且满足2120n n n a a a ++-+=.（1）求数列{a n }的通项公式；（2）设12||||||n n S a a a =+++ ，求n S .21．（本小题满分12分）已知数列{a n }满足： 333313221na a a a n n =+∙∙∙+++-， *N n ∈．（1）求数列{a n }的通项公式；（2）设nn a nb =，求数列{b n }的前n 项和S n .22．已知数列{}n a 的前n 项和为,n S 且11,a =142n n S a +=+（1）设12n n n b a a +=-，求证数列{}n b 是等比数列；（2）设n nn a c 2=，求证数列}{n c 是等差数列；（3）求数列{}n a 的通项公式及前n 项和公式.2009-2010学年必修5第一次月考数学测试题参考答案一、CDCDA ADAAB BC 二、13 ．*,21)12(1N n n a n n ∈++=+ 14． 4或5 15． 302 16．27三、17．解：b 2＝a 2＋c 2-2ac cos B ＝(33)2＋22-2·33·2·(-23)＝49． ∴ b ＝7， S △＝21ac sin B ＝21×33×2×21＝233．18. 解：tan 2,tan A c bB b-=根据正弦定理 sin sin 2sin sin sin cos sin A B C BB A B -∴= s i nc o s s i n c o s 2s i n A B B A C A ∴+= sin()2sin cos A B C A ∴+= 1s i n2s i n c o sc o s 602C C A A A ∴=⇒=⇒=︒ 19．解：（１）因为c a c a a 22,2,2321+=+==，且321,,a a a 成等比数列，所以)22(2)2(2c c +=+ 解得0=c 或2=c .当0=c 时，321a a a ==不符合题意，舍去，故2=c .（２）当n ≥2时，由于c a a =-12，c a a 223=-，…，c n a a n n )1(1-=--所以 c n n c n a a n 2)1()]1(21[1-=-+∙∙∙++=- 又21=a ，2=c 故2)1(22+-=-+=n n n n a n ，（n ≥2）当n=1时，上式也成立，所以 22+-=n n a n ，（*N n ∈）.20．（1）2120n n n a a a ++-+=∴211n n n n a a a a +++-=-∴1{}n n a a +-为常数列，∴{a n }是以1a 为首项的等差数列，设1(1)n a a n d =+-，413a a d =+,∴2823d -==-，∴102n a n =-。

华山中学2010-2011高二物理月考试卷(打印版)

华山中学2010-2011学年高二月考试卷物理一．不定项选择题（本题共11小题，每题6分，共66分。

每个小题的4个选项中至少有一项符合题意，选对的得6分，漏选的得3分，错选或不选的得0分）1. 振源A 带动细绳振动，某时刻形成的横波如图甲所示，则在波传播到细绳上一点P 时开始计时，下列图乙的四个图形中能表示P 点振动图象的是：2．如图为一列沿x 轴正方向传播的简谐横波在t=0时刻的波形图，波速为2 m/s，则下列说法正确的是：A ．质点Q开始振动的方向沿y 轴负方向B ．t=0.5s 时，质点P 的位置坐标为（4，-5）C ．t=1s 时，质点P 的速度最大，质点Q 的速度为零D ．t=1.5s 时，质点P 的回复力为零，质点Q 的回复力最大3．一列简谐横波在t=0时刻的波形如图所示，此时刻x=6m 处的质点正向y 轴负方向运动，波速为5m/s ，那么下列说法正确的是：A ．此波正向x 轴负方向传播B ．经过0.6s ，x=6m 处的质点向右平移了3mC ．质点P 将比质点Q 先回到平衡位置D ．图中质点Q （坐标为x=7.5m 的质点）的振动方程为y=55cos 3t πcm 4．如图所示，S1、S2是两个相干波源，它们振动同步且振幅相同。

实线和虚线分别表示在某一时刻它们所发出的波的波峰和波谷。

关于图中所标的a 、b 、c 、d 四点，下列说法中正确的是：A ．b 质点的振动始终是加强的，d 质点的振动既不加强也不减弱B ．b 质点的振动始终是加强的，c 质点的振动始终是减弱的C ．a 质点的振动始终是减弱的，b 、c 、d 质点的振动始终是加强的D ．再过T /4后的时刻b 、c 两个质点都将处于各自的平衡位置5．如图示为一单摆的共振曲线，取g=10m/s 2；π2=10。

则下列说法正确的是：A ．该单摆的摆长为1mB ．此单摆共振时的振幅等于8cmC ．该单摆的固有周期为2sD ．此单摆共振时摆球的最大摆角为0.086．一列简诸横波沿x轴负方向传播，波速v＝4 m/s，已知坐标原点（x＝0）处质点的振动图象如图甲方所示，在图乙的四幅图中能够正确表示t＝0.15s时的波形图是：7．如图为一半圆形玻璃砖的折射率n=1.5，一束光从玻璃射向空气，入射角为60°，以下光路图正确的是：8．如图所示，A、B两束不同的单色光以不同的角度从真空同时射入同一块半圆形玻璃砖，其透射光线都是由圆心O点沿OC方向射出．则下述结论正确的是：A．玻璃砖对光束A 的折射率较光束B的大B．若两光束从玻璃砖射入真空，光束A的临界角较光束B的临界角大C．A、B两光束射入玻璃砖时波长都变短D．在双缝干涉实验中，若仅将入射光由光束A变为光束B，则干涉亮条纹间距变小9．在双缝干涉实验中，以白光为光源，在屏幕上观察到了彩色干涉条纹，若在双缝中的一缝前放一红色滤光片（只能透过红光），另一缝前放一绿色滤光片（只能透过绿光），这时：A．只有红色和绿色的双缝干涉条纹，其它颜色的双缝干涉条纹消失B．红色和绿色的双缝干涉条纹消失，其它颜色的双缝干涉条纹依然存在C．任何颜色的双缝干涉条纹都不存在，但屏上仍有光亮D．屏上无任何光亮10．如图所示，人眼隔着起偏器B、A去看一只电灯泡S，一束透射光都看不到，则以下说法中正确的是：A．使A和B同时转过90°，仍然一束光都看不到B．单使B转过90°过程中，看到光先变亮再变暗C．单使B转过90°过程中，看到光逐渐变亮D．单使A转动时，始终看不到透射光11．如图所示，一个棱镜的顶角为θ=41.35°,一束白光以较大的入射角从棱镜的左侧面射入，在光屏上形成从红到紫排列的彩色光带，各色光在棱镜中的折射率和临界角见表.当入射角逐渐减小到0的过程中，彩色光带的变化情况是：A．紫光最先消失，最后只剩红光、橙光B．紫光最先消失，最后只剩红光C．红光最先消失，最后只剩紫光D．红光最先消失，最后只剩紫光、蓝光二．实验填空题（本题共5小题，12、14、15、16题3分，13题2分，共14分）12．如图所示，某同学用插针法测定玻璃砖的折射率，他的实验方法和操作步骤正确无误。

高二年级月考试卷试题(共17页)

土山(tǔ shān)高级中学高二年级月考试卷模块５第二单元一单项选择请认真阅读下面各题目，从题中所给的A、B、C、D四个选项里面，选出最正确选项，并写在答题卡上。

1. The country has ___________.A. the population of eighteen millionB. eighteen million peoplesC. a population of eighteen millionD. eighteen million population2. The old man is badly ill and he needs ___________ at once.A. to operateB. operatingingC. being operatedD. operated3. His failure in the driving test ___________ his carelessness.A. resulted fromB. led toC. brought aboutD. resulted in4. I ___________ to go to the lecture yesterday, but I had an unexpected visitor.A. meantB. would meanC. was to meanD. had meant5. There are still many people suffering a lot, and we are to do something to __________ poverty.A. keep outB. wipe outC. give outD. run out6. Whatever he promises, you can’t ___________ anything.A. rely on his doingB. depend on his doingC. rely on him to doD. advise him to do7. When he came back, his ___________ look on his face meaned that he failed in the interview.A. disappointedB. disappointingC. encouragedD. encouraging8. Nobody is think the film is ___________ worth ___________ again.A. very; to seeB. well; to be seenC. well; seeingD. very; being seen9. If there is anything wrong with the sentence, please ____________.A. pick it outB. pick it upC. pick itD. pick it on10. The one bedroom apartment ___________ its own bathroom and Internet access.A. is furnished forB. is supplied toC. is stocked withD. is offered with11. He is not a bit mean; instead he is always __________ to help anyone in trouble.A. possibleB. probableC. likelyD. willing12. Did you hear him ___________ the door when you passed by?A. lockingB. to lockC. having lockedD. lock13. Passengers are ___________ from using such electronic devices as mobile phones during take-off and landing.A. forbiddenB. encouragedC. prohibitedD. allowed14. When a discussion is under way, everybody is welcome to have the ___________ in class.A. floorB. timeC. chanceD. right15. What is ____________ is that try as they may, they can’t avoid the economic crisis.A. beneficialB. difficultC. effectiveD. obvious第二节：完形填空(一共(yīgòng)20小题；每一小题1.5分，满分是30分)A minister〔牧师(mù shi)〕went to the home of one of the rich members of the society. It was _16_ outside, so he was _17_ in his overcoat. He went into the living room and _18_his coat. They talked for a while and then the minister prepared to go _19_ . He put on his _20_ coat and asked the host to go with him to the outer _21_ as he wanted to say something to him _22_ secret. The host, _23_ that he would be coming back in a minute_24_ , did not _25_ to put on his own overcoat and went out into the _26_ hall with him.The minister kept himself _27_ with small talk, little to the _28_ of the host. He became so _29_ that his teeth began to strike together repeatedly. But the minister _30_ with his small talk. Several times the host asked the minister to _31_to the living room, but _32_time the minister replied that in another minute he would _33_ ._34_ , the rich man said, “ If you do not tell me what we have come here for, I’ll freeze to _35_ .〞“I’ll tell you what I have come for,〞 replied the minis ter. “I need a certain amount of money to buy some coal that will go to some poor people. But inside, you would not have realized what it means to be cold.〞16. A. cloudy B. sunny C. snowing D. raining17. A. wearing B. dressing C. dressed D. worn18. A. changed B. removed C. made D. took19. A. away B. around C. downstairs D. swimming20. A. warm B. cold C. new D. expensive21. A. building B. space C. world D. hall22. A. at B. with C. beyond D. in23. A. insisting B. thinking C. wondering D. knowing24. A. or so B. later C. time D. so soon25. A. like B. hate C. bother D. require26. A. vast B. hot C. heated D. unheated27. A. careful B. busy C. tired D. helpful28. A. pleasure B. surprise C. discomfort D. joy29. A. freezing B. impatient C. angry D. excited30. A. began B. helped C. ended D. continued31. A. stop B. rush C. return D. get32. A. any B. each C. some D. by33. A. finish B. pause C. warm up D. go on34. A. First B. Finally tely D. Meanwhile35. A. death B. dead C. end D. ice第三(dì sān)局部；阅读理解(一共20小题；每一小题２分，满分是４0分)ASome time ago, I discovered that one of my chairs had a broken leg. I didn’t think there would be any difficulty in getting it mended, as there was a lot of antique〔古董〕shops near my home. So I left home one morning, carrying the chair with me. I went into the first shop, expecting a friendly reception. I was quite wrong. The man didn't even look at my chair.The second shop, though slightly more polite, was just the same, and the third and the fourth ---so I decided that my approach(way) must be wrong.I went into the fifth shop with a plan in my mind. I placed the chair on the floor and said to the shopkeeper, “Would you like to buy a chair?〞 He looked it over carefully and said, “Yes, not a bad chair. How much do you want for it, sir?〞“Twenty pounds,〞 I said.“OK,〞he said, “I’ll give you twenty pounds.〞“It’s got a slightly broken leg,〞 I said. “Yes, I saw that. It's nothing.〞Everything was going according to the plan and I was getting excited. “Wha t will youdo with it?〞I asked. “Oh, it will be easy to sell once the repair is done.〞“I'll buy it,〞 I said. “What do you mean？You’ve just sold it to me,〞he said. “Yes, I know but I’ve changed my mind. I'm sorry. I'll give you twenty -seven pounds for it.〞“You must be crazy,〞 he said. Then, suddenly the penny dropped. “I know what you want. You want meto repair your chair.〞“You’re right,〞I said. “And what would you have done if I had walked in and said, ‘Would you mend this chair for me?’ 〞“I would n't have agreed to do it,〞he said. “We don’t do repairs, not enough money in it and too much trouble. But I’ll mend this for you, shall we say for a fiver(five dollars )?〞 He was a very nice man and was greatly amused by the whole thing.36. The expressio n “the penny dropped〞 in the last paragraph means the shopkeeper ______.A. changed his mindB. accepted the offerC. saw the writer’s purposeD. decided to help the writer37. How much did the writer pay for the repair?A. ￡ 5.B. ￡ 7.C. ￡ 20.D. ￡ 27.38. From the text, we can learn that the writer was ______.A. honestB. carefulC. smartD. funnyBScratchy throats, stuffy〔堵塞(dǔsè)〕noses and body aches all result in discomfort, but being able to tell if the cause is a cold or flu may make a difference in how long the discomfort lasts, because the drugs available for the flu need to be taken soon after the illnesssets in. As for colds, the sooner a person starts taking over the medications available, the sooner relief will come.The common cold and the flu are both caused by viruses. More than 200 viruses can cause cold symptoms, while the flu is caused by three viruses — flu A, B and C. There is no cure for either illness, but the flu can be prevented by the flu vaccine〔疫苗(yìmiáo)〕, which is, for most people, the best way to fight the flu, according to the ALA.But the flu does strike, quick action can help. Although the flu and common cold have many similarities, there are some obvious signs to look for.Cod symptoms such as stuffy nose, running nose and scratchy throat typically developed gradually, and adults and teens often do not get a fever. On the other hand, fever is one of the characteristic features of the flu for all ages. And in general, flu symptoms including fever and coldness, painful throat and body aches come on suddenly and are more worrying than cold symptoms.The ALA notes that it may be particularly difficult to tell when babies and preschool age children have the flu. It advises parents to call the doctor if their small children have flu-like symptoms.Both cold and flu symptoms can be eased with the medications as well. However, children and teens with a cold or flu should not take aspirin for pain relief because of the risk of Reye syndrome〔综合症〕.There is, of cause, no vaccine for the common cold. But frequent hand washing and avoiding close contact with people who have colds can reduce the probability catching one.39. According to the author, knowing the cause of the discomfort will help ____________.A. prevent people from catching colds and the fluB. the patient obtain cheaper drugsC. the patient buy medicineD. shorten the period of the illness40. We learn from the passage that ____________.A. the drugs available can be taken to ease the discomfort caused by a cold or the fluB. one doesn’t need to take any medicine if he has a cold or the flueC. aspirin should not be included in the medicines for the fluD. delayed treatment of the flu will harm the liver and central nervous systems41. According to the passage, to fight against the flu effectively, one should ____________.A. take medicine upon catching the diseaseB. identify the virus which causes itC. consult a doctor as soon as possibleD. remain watchful when the disease is spreading42. Which of the following symptoms will distinguish the flu from a cold?A. A painful throat.B. A stuffy nose.C. A dry cough.D. A high temperature.43. If children have flu-like symptoms, their parents ____________.A. are encouraged to take them to hospital for vaccinationB. are advised not to give them aspirinC. should watch out for signs of Reye syndromeD. should prevent themCHow could we possibly think that keeping animals in cages in unnatural environments－mostly for entertainment purposes－is fair and respectful?Zoo officials say they are concerned about animals. However, most zoos remain “collections〞of interesting “things〞 rather than protective habitats(栖息地). Zoos teach people that it is acceptable to keep animals bored, lonely, and far from their natural homes.Zoos claim(声称(shēngchēng)) to educate people and save endangered species(物种), but visitors leave zoos without having learned anything meaningful about the anim als’ natural behavior, intelligence, or beauty. Zoos keep animals in small spaces or cages, and most signs only mention the species’ name, diet, and natural range(分布区). The animals’ normal behavior is seldom noticed because zoos don’t usually take care of the animals’ natural needs.The animals are kept together in small spaces, with no privacy and little opportunity for mental and physical exercise. This results in unusually and self-destructive behavior called zoochosis. A worldwide study of zoos found that zoochosis is common among animals kept in small spaces or cages. Another study showed that elephants spend 22 percent of their time making repeated head movements or biting cage bars, and bears spend 30 percent of their time walking back and forth, a sign of unhappiness and pain.Furthermore, most animals in zoos are not endangered. Captive breeding(圈养繁殖) of endangered big cats. Asian elephants, and other species has not resulted in their being sent back to the wild. Zoos talk a lot about their captive breeding programs because they do not want people to worry about a species dying out. In fact, baby animals also attract a lot of paying customers. Haven’t we seen enough competitions to name baby animals?Actually, we will save endangered species only if we save their habitats and put an end to the reasons people kill them. Instead of supporting zoos, we should support groups that work to protect animals’ natural habitats.44．How would the author describe the animals’ life in zoos?A．Dangerous. B．Unhappy. C．Natural. D．Easy.45．In the state of zoochosis, animals _________.A．remain in cages B．behave strangelyC．attack other animals D．enjoy moving around46．What does the author try to argue in the passage?A．Zoos are not worth the public support.B．Zoos fail in their attempt to save animals.C．Zoos should treat animals as human beings.D．Zoos use animals as a means of making money.47．The author tries to persuade readers to accept his argument mainly by _________.A．pointing out the faults in what zoos doB．using pictures he has taken at zoosC．questioning the way animals are protectedD．discussing the advantages of natural habitatsDBeauty has always been regarded as something praiseworthy. Almost everyone thinks attractive people are happier and healthier, have better marriages and more respectable jobs. Personal advisor give them better advice for finding jobs. Even judges are softer on attractive defendants, but in the executive circle, beauty can become a liability.While attractiveness is a positive factor for a man on his way up the executive ladder, it is harmful to a woman.Handsome male executives were considered as having more honesty than plainer ones; their success was connected not with ability but with factors such as luck.All unattractive women executives were thought to have more honesty and to be more capable than the attractive female executives. Interestingly, though, the rise of the unattractive overnight successes was connected more to personal relationships and less to ability than that of the attractive overnight successes.Why are attractive women not thought to be able? An attractive woman is considered to be more womanly and an attractive man more manly than the less attractive ones. Thus, an attractive woman has an advantage in traditionally female jobs, but an attractive woman in a traditionally manly position appears to lack the "manly" qualities required.This is true even in politics. "When the only clue is how he or she looks, people treat men and women differently," says Anne Bowman, who recently published a study on the effects of attractiveness on political candidates. She asked 125 undergraduate students to rank two groups of photographs, one of men and one of women, in order of attractiveness. The students were told what the photographs were of. They were asked to rank them again, in the order they would vote for them.The results showed that attractive males completely defeated unattractive men, but the women who had ranked most attractive unchangeably received the fewest votes.48. According to the passage, attractive people are those who are ______.A. good-lookingB. humorousC. well-educatedD. capable49. The author of the passage intended to show us that people' s views on beauty are ______.A. out-of-dateB. practicalC. reasonableD. one-sided50. Which is TRUE according to the passage?A. Appearance is important in finding a good job.B. Attractiveness is of great advantage to his or her success.C. Attractiveness is more of a disadvantage than an advantage to women when it comes to politics.D. Attractiveness has more effect on men than on women.51. In traditional female jobs, attractiveness ______.A. strengthens the womanly qualities requiredB. always makes it easier for women to succeed quicklyC. makes women look more honest and capableD. can be a liabilityEWhen the population of the port town began to suffer from poisoning, the police came to find the cause of the poison. They thought someone was poisoning the people on purpose but no one knew how it was possible. Soon people took the position that the pork was poisoned. It was a popular food everyone ate and it could have possibly made everyone sick. Anyone who had possession of pork would throw it out. Even the poorest of the poor wouldn’t eat pork. Signs were posted on poles and letters were sent to everyone to warn people of the pork. Shortly afterwards, even policemen in high positions were also getting sick.Soon it became political and popular. Politicians rushed to the town to talk about politics and promised how they would find the solution if they were elected. Everyone was so sick that they didn’t care about politics. Everyone was in a position where he or she didn’t know what to do anymore. They went to the post office to mail posts out asking for help. The poor town didn’t know how to deal with the situation.One day, a well-known scientist from New York came to the town with a huge box containing many instruments and his possessions. He went to pools and the port and made measurements. He was quiet and polite. Then one day he made a speech at a newspaper meeting-room to announce his findings.“I am sorry to say your water supply is so heavily polluted; it is poisoned. I know who has been poisoning you all for such a long time. It is you who have been poisoning yourselves with pollution. A great deal of rubbish has been thrown into the water day after day. No one here has taken good care of the environment. It is no wonder all of you have been sick.〞 Shocked at the news, the people present were lost in thought.52. Which is the correct order of the facts described in the story?a. People suffered from poisoning.b. Politicians came to make promises.c. People began to realize the real cause.d. Pork was thrown away.e. The water there was polluted.f. A scientist came to check the water.A. e, a, d, b, f, cB. e, a, d, c, f, bC. a, e, b, d, c, fD. f, c, d, b, e, a53. What does the underlined phrase “ "took the position" mean in the passage?A. took the jobB. took the placeC. held the opinionD. made the suggestion54. Which of the following statements is correct?A. Everyone was so sick of politics that they didn’t care about those politicians.B. According to the scientist from New York, not all the population in the town have takengood care of the environment.C. The reason why the people in the town got sick was that they ate the pork poisoned bythe heavily polluted water.D. if the people in the town hadn’t polluted the water supply, they would not have sufferedfrom poisoning or sickness.55. After reading the passage, we can infer that ________A. politicians took every chance to make themselves electedB. pork was the main food of the people in the townC. people in the town were not well-educatedD. even some police officers were getting ill六对话(duìhuà)填空(一共10小题；每一小题1分，满分是10分)请认真阅读下面对话，并根据各题所给首字母的提示，在答题卡右栏中标有题号的横线上，写出一个英语单词的完好、正确形式，使对话通顺。

高二月考试卷及答案

高二月考试卷及答案一. 选择题：（本大题共12小题，每小题5分，共60分.在每小题给出的四个选项中，只有一项是符合题目要求的） 1．已知全集(}.7,5,3,1{},6,4,2{},7.6,5,4,3,2,1{ A B A U 则===B C U ）等于（A ）A ．{2，4，6}B ．{1，3，5}C ．{2，4，5}D ．{2，5}2.掷一枚骰子，则掷得奇数点的概率是（B ）A.61 B.21 C.`31 D.413. 从学号为0～54的高一某班55名学生中随机选取5名同学参加数学测试,采用系统抽样的方法,则所选5名学生的学号可能是（B ） A. 1,2,3,4,5 B. 5,16,27,38,49 C. 2,4,6,8,10 D.4,13,22,31,404.已知椭圆1162522=+yx上的一点P 到椭圆一个焦点的距离为3，则P 到另一焦点距离为（ D ）A 2B 3C 5D 75．已知等差数列{}n a 的公差为2,若431,,a a a 成等比数列, 则2a =（B ）A ． 4-B ． 6-C ． 8-D ． 10- 6. 如右图，一个空间几何体正视图与左视图为全等的等边三角形，俯视图为一个半径为1的圆及其圆心，那么这个几何体的表面积为（ B ）Ａ．πＢ．π3Ｃ．π2 Ｄ．3+π7．条件p ：1>x ，1>y ，条件q ：2>+y x ，1>xy ，则条件p 是条件q 的（ A ） A ．充分而不必要条件 B ．必要而不充分条件 C ．充要条件 D ．即不充分也不必要条件8．有金盒、银盒、铅盒各一个，只有一个盒子里有肖像．金盒上写有命题p ：肖像在这个盒子里；银盒上写有命题q ：肖像不在这个盒子里；铅盒上写有命题r ：肖像不在金盒里．p 、q 、r 中有且只有一个是真命题，则肖像在（ B ） A ．金盒里 B ．银盒里 C ．铅盒里 D ．在哪个盒子里不能确定 9.一只小蜜蜂在一个棱长为3的正方体内自由飞行，若蜜蜂在飞行过程中始终保持与正方体6个面的距离均大于1，称其为“安全飞行”，则蜜蜂“安全飞行”的概率为( C )(A)18 (B)116 (C)127 (D)3810. 如下图所示,程序执行后的输出结果为了 (B )A. -1B. 0C. 1D. 2 俯视图左视图正视图11．某家俱公司生产甲、乙两种型号的组合柜，每种组合柜的制造白坯时间、油漆时间如下表：设该公司安排甲、乙二种柜的日产量分别为y x ,，则y x 2420+的最大值为（A ）．A ． 272B ． 271C ． 270D ． 269 12．下列命题中，假命题的个数是( B ) ①∀x ∈R ，x 2＋1≥1； ②∃x 0∈R,2x 0＋1＝3；③∃x 0∈Z ，x 0能被2和3整除； ④∃x 0∈R ，x 20＋2x 0＋3＝0.A ．0B ．1C ．2D ．3第Ⅱ卷（非选择题共90分）二填空题（本大题共4小题，每小题4分，共16分，把正确答案填在横线上） 13．函数24++=x x y 的定义域为[)(]4,22,--⋃-+∞14. 已知a ＝（λ，2)，b ＝(－3，5)且a 与b 的夹角是钝角，则实数λ的取值范围是__10,3⎛⎫+∞⎪⎝⎭_____ 15．直线20x y +=被曲线2262150x y x y +---=所截得的弦长等于__________16．设α、β、r 是互不重合的平面，m ，n 是互不重合的直线，给出四个命题：①若m ⊥α，m ⊥β，则α∥β ②若α⊥r ，β⊥r ，则α∥β③若m ⊥α，m ∥β，则α⊥β ④若m ∥α，n ⊥α，则m ⊥n 其中正确命题的是 1,3.4 .三.解答题：（本大题共6小题，共74分，解答应写出文字说明，证明过程或演算步骤。

高二年级下学期五月考试

高二年级下学期五月考试物理试卷（全卷满分100分，考试时间120分钟；注意事项：1、本卷中g 取10m/s 2；2、本卷为试题卷，考生解题作答必须在答题卷(答题卡)上，答案书写在答题卷(答题卡)相应位置上，在试题卷、草稿纸上作答无效；3、考试结束后，请将答题卷(答题卡)交回。

）I 、选择题（46分）一、选择题（本题有10小题，每小题3分，共30分。

给出的四个选项中，只有一个选项正确。

）1、关于电路中感应电动势的大小，下列说法中正确的是： A 、穿过电路的磁通量越大，感应电动势就越大 B 、电路中磁通量的该变量越大，感应电动势就越大 C 、电路中磁通量变化越快，感应电动势越大D 、若电路中某时刻磁通量为零，则该时刻感应电流一定为零2、某线圈在匀强磁场中绕垂直于磁场的转轴匀速转动，产生交变电流的图像如图所示，由图中信息可以判断：A 、在A 和C 时刻线圈处于中性面位置B 、在B 和D 时刻穿过线圈的磁通量为零C 、从A-D 时刻线圈转过的角度为2πD 、若从O-D 时刻历时0.02s ，则在1s 内交变电流的方向改变100次3、如图所示，导线框abcd 与通电导线在同一平面内，直导线中通有恒定电流并通过ad 和bc 的中点，当线框向右运动的瞬间，则：A 、线框中有感应电流，且按顺时针方向B 、线框中有感应电流，且按逆时针方向C 、线框中有感应电流，但方向难以判断D 、由于穿过线框的磁通量为零，所以线框中没有感应电流4、闭合线圈与匀强磁场垂直，现将线圈拉出磁场，第一次拉出速度为v 1，第二次拉出速度为v 2，且v 2=2v 1，则：A 、两次拉力做的功一样多B 、两次所需拉力一样大abcdC 、两次拉力的功率一样大D 、两次通过线圈的电荷量一样多5、如图所示的电路为演示自感现象的实验电路，若闭合开关S ，电流达到稳定后通过线圈L 的电流为I 1，通过小灯泡L 2的电流为I 2，小灯泡L 2处于正常发光状态，则下列说法中正确的是： A 、S 闭合瞬间，L 2灯缓慢变亮，L 1灯立即变亮B 、S 闭合瞬间，通过线圈L 的电流由零逐渐增大到I 1C 、S 断开瞬间，小灯泡L 2中的电流由I 1逐渐键位零，方向与I 2相同D 、S 断开瞬间，小灯拍L 2中的电流由I 1逐渐减为零，方向不变6、如图所示，两根通电金属杆MN 和PQ 平行放置在匀强磁场中．关于各自所受安培力的方向，下列说法正确的是：A ．两者都向下B ．两者都向上C ．MN 的向下，PQ 的向上D ．MN 的向上，PQ 的向下7、正离子源发射出正离子经加速电压后,进入互相垂直的电场和磁场中,电场和磁场方向如图所示,发现离子向上偏转,要使离子沿直线通过混合场,需要: A 、增大电场强度E ,减小磁感应强度B B 、增大电场强度E ,减小加速电压U C 、适当增大加速电压U D 、适当增大电场强度E8、如图所示,abc 为三个同心圆环,且在同一平面内,垂直于此平面向里的磁场局限在b 环内部,当磁场减弱时,三个金属圆环中产生的感应电动势的大小关系是:A.E a >E b >E cB. E a <E b <E cC. E a <E b =E cD. E a =E b >E c9、一理想变压器给负载供电,变压器输入电压不变,如图所示.如果负载电阻的滑片向上移动则图中所有交流电表的读数及输入功率变化情况正确的是(均为理想电表): A.V 1、V 2不变，A 1增大，A 2减少，P 增大 B. V 1、V 2不变，A 1 、A 2增大，P 增大 C. V 1、V 2不变，A 1、A 2减少，P 减少 D. V 1不变、V 2增大，A 1、A 2减少，P 减少10、矩形线圈abcd,长ab=20cm,宽bc=10cm ，匝数n=200匝，线圈回路总电阻R=5Ω,整个线圈平面内均有垂直于线圈平面的匀强磁场穿过.若匀强磁场的磁感应强度B 随时间t 的变化规律如图所示，则：A.线圈回路中感应电动势随时间均匀变化B.线圈回路中产生的感应电流为0.4AC.当t=0.3s 时，线圈的ab 边所受的安培力大小为0.016ND.在1min 内线圈回路产生的焦耳热为48J二、选择题（本题4小题，每小题4分，共16分。

高级中学09-10(二).5月考试2010.5.30doc

t /s 高级中学09-10年（二）5月考试高二年级物理学科试卷2010.5.30一.选择题（题目中有一个或几个答案，全部选对得4分，漏选得2分，错选不得分，答案必须添在答题栏中，否则不得分）1、某消防队员从一平台上跳下,下落2m 后双脚触地,接着他用双腿弯屈的方法缓冲,使自身重心又下降了0.5m.在着地过程中地面对他双脚的平均作用力估计为(g=10m/s 2)(A)自身所受重力的2倍 (B)自身所受重力的5倍(C)自身所受重力的8倍 (D)自身所受重力的10倍2、一粒钢珠从静止状态开始自由下落,然后陷入泥潭中.若把在空中下落的过程称为过程Ⅰ,进入泥潭直到停住的过程称为过程Ⅱ,则（A ）过程Ⅰ中钢珠动量的改变量等于重力的冲量（B ）过程Ⅱ中阻力的冲量的大小等于过程Ⅰ中重力冲量的大小（C ）过程Ⅱ中钢珠克服阻力所做的功等于过程Ⅰ与过程Ⅱ中钢珠所减少的重力势能之和;（D ）过程Ⅱ中损失的机械能等于过程Ⅰ中钢珠所增加的动能.3、两个质量不同的物体，以相同的初动量开始沿同一水平面滑动，设它们与水平面间的滑动摩擦系数相同，则它们滑行的距离大小关系是：A 、质量大的物体滑行距离较大；B 、质量小的物体滑行距离较大；C 、两物体滑行距离一样大；D 、条件不足，无法比较。

4. 两个小木块B 、C 中间夹着一根轻弹簧，将弹簧压缩后用细线将两个木块绑在一起，使它们一起在光滑水平面上沿直线运动，这时它们的运动图线如图中a 线段所示，在t =4s 末，细线突然断了，B 、C 都和弹簧分离后，运动图线分别如图中b 、c 线段所示。

从图中的信息可知A.B 、C 都和弹簧分离后的运动方向相反 B.B 、C 都和弹簧分离后，系统的总动量增大C.B 、C 分离过程中B 木块的动量变化较大D.B 木块的质量是C 木块质量的四分之一 5、一个质量为M ，长为L 的小车静止在光滑水平路面上，一个质量为m 的人站在小车的一端，当人从车的一端走到另一端时，小车移动的距离为：(A)L ； (B)mL/(M+m)； (C)mL/M ； (D)mL/(M －m)。

05—06学年高二上学期数学月考试卷

05—06学年高二上学期数学月考试卷第Ⅰ卷选择题（共60分）一、选择题（每小题5分，共60分） 1，不等式“a +b>2c ”成立的一个充分条件是（）Ａ．c b c a >>或Ｂ．c b c a <>且Ｃ．c b c a >>且Ｄ．c b c a <>或 2，若关于x 的不等式2043x ax x +>++的解为31x -<<-或2x >，则a 的取值为（） A ．2B ．12C ．－12D ．－23,若a b R +∈，且11k k k k a b P a b Q ab a b ++≠=+=+，，，其中k N *∈，则（） A. P>Q B 、P Q = C.不能确定 D. P<Q 4，不等式|a +b|<|a |+|b|成立的充要条件是（）A ．a ·b>0B ．a ·b ≥0C ．a ·b<0D ．a ·b ≤0５,（文科）直线l 与两直线07,1=--=y x y 分别交于P 、Q 两点, 线段P Q 的中点恰为 ),1,1(-则直线l 的斜率为（） A.23 B.32 C.32- D. 23- （理科）如直线l 1、l 2的斜率是二次方程x 2-4x+1=0的两根，那么l 1和l 2的夹角是( )A.3π B. 4π C. 6π D. 8π6，若点P(x o ，y o )在直线2x+3y+1=0的上方，则有2x o +3y o +1（）A ．大于0B ．等于0C ．小于0D ．不能确定 7，下列函数中，最小值为22的是（）A ．xx y 2+=B ．)0(sin 2sin π<<+=x xx yC ．x x e e y -+=2D ．2log 2log 2x x y +=8,无论a 为何实数, 直线01)2()13(=----y a x a 必须经过的象限是 ( )A. 第一象限B. 第二象限C. 第二象限D. 第四象限9,已知a 、b 、m 为正实数，则不等式bam b m a >++（） A ．当a < b 时成立 B ．当a > b 时成立 C ．是否成立与m 有关D ．一定成立10,设10<<a ，a b 、为常数，则221a b x x+-的最小值为（） A.()2a b + B.当0ab ≥时，为()2a b +；当ab<0时，为()2a b - C.()2a b - D.当0ab ≥时，为()2a b -；当ab<0时，为()2a b +11,若动点),(),(2211y x B y x A 、分别在直线1l ：07=-+y x 和2l ：05=-+y x 上移动，则AB 中点M 到原点距离的最小值为（）A ．23B ．32C ．33D ．2412, （文科）a>1是曲线y=a|x|和直线y-x-a=0有且仅有两个不同交点的 ( )A. 充分不必要条件B. 必要不充分条件C. 充要条件D. 既不充分也不必要条件（理科）已知f （x ）=（x －a ）（x －b ）－2，(a<b)并且βα,(βα<)是方程f （x ）=0的两根，实数a 、b 、α、β 的大小关系可能是（）A ．α＜a ＜b ＜βB ．a ＜α＜β＜bC ．a ＜α＜b ＜βD ．α＜a ＜β＜b05—06学年高二上学期数学月考试卷答案二、填空题（每小题4分，共16分）13，（文科）直线4ax+y=1与直线（1－a ）x+y=－1互相垂直，则a= 221±（理科）写出直线7x+5y-10=0的一个方向向量（1，57-） 14，不等式01272322≥+-+-x x x x 的解集为_),4()3,2[]1,(+∞-∞∈ x15，（文科）已知0<a<1，且111A B a C a ==+=-，，则A B C ，，中最大者为a-11（理科）若8a b R a b ab +∈++=、，，则a b +的最小值是_816，（文科）.将直线y(2,0)按顺时针方向旋转60°所得的直线l 在y 轴上的截距是 32-（理科）对于每一个实数x ，设f （x ）取4x+1，x+2，－2x+4中的最小值，那么f （x ）的最大值是 38三、解答题（共74分）17，（本小题满分12分）已知等腰直角三角形的斜边所在直线方程是：023=+-y x ，直角顶点C （52,514）,求两条直角边所在的直线方程和此三角形面积. 解：∵直线AB 方程为3x －y +2=0 ∴K AB =3 设与直线AB 成45°角的直线斜率为k ，则|1tg45|313=︒=+-kk 4分解之得：k =21或k =－2 6分故两直角边所在直线方程为：x －2y －2=0和2x +y －6=0 8分由于点C 到AB 的距离d =1031|2525143|2=++-⋅10分而|AB |=2d =210 ∴所求三角形面积为S =10||412=AB 12分 18，（本小题满分12分）已知正常数a 、b 和正变数x 、y ，满足a+b=10，1ybx a =+，x+y 的最小值为18，求a ，b 的值。

山西省大同市高二5月月考数学(文)试题Word版含答案

2016—2017—2高二年级5月阶段性试题数学（文科）试卷第Ⅰ卷（选择题）一、选择题：本大题共12小题，每小题5分，共60分.在每个小题给出的四个选项中，有且只有一项符合题目要求.1.下列四个命题中，与命题A B ⊆等价的共有①A B A = ②A B B = ③()U A C B =∅ ④A B B =A. 1个B. 2个C. 3个D. 4个2.在同一平面直角坐标系中，经过伸缩变换53x x y y'=⎧⎨'=⎩后，曲线C 变为曲线22280x y ''+=，则曲线C 的方程为A. 2225360x y +=B. 2291000x y +=C.10240x y +=D.22280259x y += 3.已知函数()1f x x =-，则下列函数与()f x 表示同一函数的是 A. ()211x g x x -=+ B. ()21,112,1x x g x x x ⎧-≠-⎪=+⎨⎪=-⎩ C. ()1,01,0x x g x x x ->⎧=⎨-≤⎩D.()1g x x =- 4.定义集合运算：{}|,,A B z z xy x A y B ⋅==∈∈，设{}{}1,2,0,2A B ==，则集合A B ⋅的所有元素之和为A. 0B. 2C. 3D. 65.已知函数()y f x =的定义域为()()0,,83f +∞=-，对任意正数12,x x ，都有()()()1212f x x f x f x =+，猜想()y f x =的表达式为A. ()2x f x =B.()38f x x = C. ()2log f x x = D.()3f x = 6.已知i 是虚数单位，若()17,2i a bi a b R i+=+∈-，则乘积ab = A. -15 B. -3 C. 3 D. 157.设有一个回归直线方程ˆ32yx =-，则变量增加一个单位时， A. y 平均增加2个单位 B. y 平均增加3个单位C. y 平均减少2个单位D. y 平均减少3个单位8.下列命题中，真命题是A.,sin cos 1.5x R x x ∃∈+=B. ()0,,sin cos x x x π∀∈>C. 2,1x R x x ∃∈+=-D.()0,,1xx e x ∀∈+∞>+ 9.极坐标方程()2,033ππθθρ==>和4ρ=所表示的曲线围成的图形的面积是 A. 163π B. 83π C. 43π D.23π 10.若函数()()22log 3f x x ax a =-+在区间[)2,+∞上是增函数，则实数a 的取值范围是 A.(],4-∞ B. (]4,4- C. (]4,2- D. (][),42,-∞-+∞11.已知221111x x f x x --⎛⎫= ⎪++⎝⎭，则()f x 的解析式为 A. 21x x + B. 221x x -+ C. 221x x + D. 21x x-+ 12.对于函数①()()lg 21f x x =-+；②()()22f x x =-；③()()cos 2f x x =+，给出下列三个命题：命题甲：()2f x +是偶函数；命题乙：()f x 在(),2-∞上是减函数，在()2,+∞上是增函数；命题丙：()()2f x f x +-在R 上是增函数，能使命题甲、乙、丙均为真命题的所有函数的序号是A. ①③B. ①②C. ③D. ②二、填空题：本大题共4小题，每小题5分，共20分.13.设{}{}20,1,2,3,|0U A x U x mx ==∈+=，若{}1,2U C A =，则实数m = .14.已知函数()y f x =定义域为[]0,2，则函数()()()21lg 1f x g x x =++的定义域为 .15.若复数()(23z a a i =--+为纯虚数，则2011= . 16.程序框图如图所示，其输出结果是 .17.设函数()()()12211log 1x x f x x x -⎧≤⎪=⎨->⎪⎩，则满足()2f x ≤的x 取值范围是 .18.设ABC ∆的三边长分布为,,,a b c ABC ∆的面积为S ，则ABC ∆的内切圆半径为2S r a b c=++，将此此结论类比到空间四面体：设四面体S ABC -的四个面的面积分别为1234,,,S S S S ，体积为V '，则四面体的内切球半径r = .三、解答题：本大题共6小题，共70分.解答应写出必要的文字说明或推理、验算过程.19.（本题满分10分）设p ：实数x 满足22430x ax a -+<，其中0a >，命题:q 实数x满足2260280x x x x ⎧--≤⎪⎨+->⎪⎩. （1）若1a =，且p q ∧为真，求实数x 的取值范围；（2）若p 是q 的必要不充分条件，求实数a 的取值范围.20.（本题满分10分）已知椭圆C 的极坐标方程为222123cos 4sin ρθθ=+，点12,F F 为其左右焦点，直线l的参数方程为222x y ⎧=+⎪⎪⎨⎪=⎪⎩（t为参数）. （1）求直线l 和曲线C 的普通方程；（2）求点12,F F 到直线l 的距离之和.21.（本题满分10分）已知函数()32f x ax x bx =++（其中常数,a b R ∈），()()()g x f x f x '=+是奇函数（1）求()f x 的解析表达式；（2）求()g x 在区间[]1,2上的最大值和最小值.22.（本题满分10分）在平面直角坐标系xoy 中，直线l 的参数方程为1cos 2sin x t x y t x =+⎧⎨=+⎩（t 为参数），以坐标原点O 为极点，x 轴的正半轴为极轴建立极坐标系中，圆C 的极坐标方程为6sin .ρθ=（1）求圆C 的直角坐标方程；（2）设圆C 与l 交于A,B 两点，若点P 的坐标为()1,2，求PA PB +的最小值.。

高二年级5月份月考计算机试卷(word)

高二年级5月份计算机月考试卷一、是非选择题：（15小题，每小题1分，共15分，对的选A，错的选B）1．如果需要对文本格式化，则必须先选择被格式化的文本，然后再对其进行操作（A B）2．文档的页码只能是数字，而不能是其他符号。

（A B）3．如果要使文档编排的页码从“2”开始，只需在“起始页码”右侧的框中输入即可。

（A B）4．如要将所选文本复制到文档另一位置，只需按复制按钮即可。

（A B）5．如要合并上、下两个表格，只要删除两个表格之间的任何内容就可以了（A B）6．打印预览窗口只能显示文档的打印效果，不能进行文档的编辑操作。

（A B）7．两个单元格合并后，仍然是两个单元格，只是去掉了表格线而已。

（A B）8．页眉与页脚在任何视图模式下均可显示。

（A B）9．在Word2003中，默认的汉字字体为黑体，默认西文字体为Times New Roman（A B）10．使字符间距扩大的方法是在字符之间添加空格。

（A B）11．Word对话框中的样例框可以显示被选项的结果。

（A B）12．单击“新建”按钮与选择“文件”菜单中的“新建”命令创建新文件的操作是一样的。

（A B）13．要设置段落格式，必先选取整个段落。

（A B）14．Office2003的“剪贴板”最多只能保存12个剪贴对象。

（A B）15.项目符号不会像项目编号一样自动增减号码。

（A B）二、单项选择题：（20小题，每小题1.5分，共30分）16．在文档中插入特殊符号，则应选择（）A．“插入”→“分隔符”B．“视图”→“粘贴”C．“工具”→“自定义”D．“插入”→“符号”17．在Word编辑状态，单击“粘贴”按钮后（）A．将文档中被选择的内容复制到当前插入点处；B．将文档被选择的内容复制到剪贴板；C．将剪贴板中的内容复制到当前插入点处；D．将剪贴板中的内容移到到当前插入点处18．在文档中，打开“查找”对话框的快捷键是（）A．Ctrl+G B．Ctrl+H C．Ctrl+A D．Ctrl+F19．下列可设定打印纸张大小的命令是（）A．“文件”菜单中的“打印预览”B．“文件”菜单中的“页面设置”C．“视图”菜单中的“工具栏”命令D．“视图”菜单中的“页面”命令20．在文档打印时，若“打印页码范围”中的内容是4-10,16,20，则表示能够打印（）A．第4页，第10页，第16页，第20页；B．第4页至第10页，第16页至第20页；C．第4页至第10页，第16页，第20页；D．第4页，第10页，第16页至第20页；21．如果已有页眉，再次进入页眉区只需双击（）A．文本区B．菜单栏C．页眉页脚区D．工具栏22．需要多次复制格式段落时，将鼠标移动到“常用”工具栏的“格式刷”按钮上，然后（）A．双击鼠标左键B．单击鼠标左键C．双击鼠标右键D．单击鼠标右键23．下列关于文档窗口说法中正确的是（）A．只能打开一个文档窗口；B．可以同时打开多个文档窗口，被打开的窗口都是活动窗口C．可以同时打开多个文档窗口，但其中只有一个是活动窗口；D．可能同时打开多个文档窗口，但在屏幕上只能见到一个文档窗口。

人教B版高中数学必修五第一次月考答案.docx

东北育才学校高中部2010－2011学年度上学期高二年级数学第一次月考试卷一、选择题：本大题共12小题，每小题5分，共60分. 在每小题给出的四个选项中，只有一项是符合题目要求的.1. B2.C3.B4.C5.A6.A7.D8.D9.D 10.C 11.A 12.C二、填空题：本大题共4小题，每小题5分，共20分.13. 充分 14. 3227+ 15. 20 16.（63，53）三、解答题：本大题共6小题，共70分. 解答应写出文字说明、证明过程或演算步骤. 17.（Ⅰ）依题意，－2和6是方程02322=-++a b x a ax 的两根 ……………………1分故⎪⎩⎪⎨⎧-=⨯--=+-a a b a 326262 解得 ⎩⎨⎧-=-=84b a ……………………3分 (Ⅱ)∵ 48164)(2++-=x x x f ∴()()4(1)2(61)4k F x f x k x k =-+++- 2(41648)4(1)2(61)4k x x k x k =--+++++- ……………………4分欲使()F x ＜0恒成立，只要使0242<-+x kx 恒成立①当0=k 时，原不等式化为024<-x ，不合题意，舍去；……………………6分 ②当0≠k 时，要使0242<-+x kx 的解集为R ，则须满足： ⎩⎨⎧<-⨯-=∆<0)2(4402k k ，解得2-<k ……………………9分综合①②得k 的取值范围为)2,(--∞. ……………………10分18.(1)命题的否定：末位数字是0或5的整数，不能被5整除．否命题：末位数字不是0也不是5的整数，不能被5整除． ……………………4分（2）不是全称命题，补充条件：1a b <-<（答案不惟一）当1a b <-<时, 0a b +>，10b +>11)(1)(2++≠++-=++b b a b b a b b a……………………8分(3)由22430x ax a -+<得(3)()0x a x a --<,又0a >,所以3a x a <<,由2260280x x x x ⎧--≤⎪⎨+->⎪⎩,得23x <≤，p ⌝是q ⌝的充分不必要条件，即p ⌝⇒q ⌝,且q ⌝⇒/p ⌝,设A={|}x p ⌝,B={|}x q ⌝,则A B Ø,又A={|}x p ⌝={|3}x x a x a ≤≥或, B={|}x q ⌝={23x x ≤>或}，则0<2a ≤,且33a >.所以实数a 的取值范围是12a <≤.……………………12分19解：（1）当2≥n 时，1--=n n n S S a ，∴11--⋅=-n n n n S S S S ，…………3分 ∴()21111≥-=--n S S n n ，∴数列⎭⎬⎫⎩⎨⎧n S 1为等差数列.………………5分（2）由（1）知，2211)1()1(111n n S S n -=-⨯-+=， ∴nS n 2112-=.…………………………………………7分当2≥n 时，)213)(211(4213221121n n n n S S a n n n --=---=-=-，9分 ∴⎪⎪⎩⎪⎪⎨⎧≥--==)2(,)213)(211(4),1(,92n n n n a n ……………………12分 20.解:).,2(12,1212211)(1*-∈≥-=-=++--=N n n a a x x x f n n 则 (1),11,111211111111-=-=--=-=-----n n n n n n n a b a a a a b 则),1(11111111*----∈≥=---=-N n n a a a b b n n n n n ,所以数列;}{是等差数列n b --5分(2)由(1)知,数列,27,1,251111-=-=-=n b a b n 则其通项公式公差为, 由.7221,271111,11-+=-+=+=-=n a n b a a b n n n n n 故得构造函数.0)72(4)(,7221)(2'<--=-+=x x f x x f 则函数.),27(),27,(,7221)(上均为减函数在+∞-∞-+=x x f 1,3,)27,(,17221,273-==-∞<-+=<∴a a n x y x n 取得最小值时故当上递减且在时当3,4,),27(,17221,274==+∞>-+=>∴a a n x y x n 取得最大值时故当上递减且在时当.故存在最大项和最小项. …………12分 21.解:（1）由题意得(1)(2)(3)(9)(10)1f f f f f ======L L ∴(10)1(10)81(1)(9)90==+++L L f g f f . …………2分（2）当120x ≤≤时，(1)(2)(1)()1f f f x f x ===-==L L ∴()11()81(1)(1)81180===+++-+-+L L f x g x f f x x x .…………4分当2160x ≤≤时，2()()81(1)(20)(21)(1)1108120(21)(1)1210(21)(20)160010120f x g x f f f f x x f f x x x x x x x =++++++-=++++-==-+-++L L L L L L …………7分 ∴当第x 个月的当月利润率为**21 (120,)80()2 (2160,1600⎧≤≤∈⎪⎪+=⎨⎪≤≤∈⎪-+⎩）x x N x g x x x x N x x …………8分（3）当120x ≤≤时，1()80g x x =+是减函数，此时()g x 的最大值为1(1)81g = 当2160x ≤≤时，2222()16001600791x g x x x x x==≤=-++- 当且仅当1600x x =时，即40x =时，max 2()79g x =，又217981>Q ， ∴当40x =时，max 2()79g x = 答：该企业经销此产品期间，第40个月的当月利润率最大，最大值为279…12分 22解：（Ⅰ）由条件得1221(1)2n n a a n n +=⋅+，又1n =时，21n a n =，故数列2{}n a n 构成首项为1，公式为12的等比数列．从而2112n n a n -=，即212n n n a -=.…4分（Ⅱ）由22(1)21222n n n n n n n b ++=-=得23521222n n n S +=+++L ， 231135212122222n n n n n S +-+⇒=++++L ，两式相减得： 23113111212()222222n n n n S ++=++++-L ，所以 2552n n n S +=-.8分（Ⅲ）由231121()()2n n n S a a a a a a +=+++-+++L L 得 1112n n n n T a a T S +-+-= 所以11222n n n T S a a +=+-2146122n n n -++=-． …12分。