中国邮递员问题matlab实现

中国邮递员问题的matlabchengxu

clear;

clc;

M=inf;

a(1,1)=0;a(1,36)=10.3;a(1,37)=5.9;a(1,38)=11.2; a(1,50)=6.0;

a(2,2)=0;a(2,50)=9.2; a(2,5)=8.3;a(2,3)=4.8;

a(3,3)=0;a(3,39)=8.2; a(3,38)=7.9;

a(4,4)=0;a(4,39)=12.7; a(4,8)=20.4;

a(5,5)=0;a(5,6)=9.7; a(5,39)=11.3; a(5,48)=11.4;

a(6,6)=0;a(6,7)=7.3;a(6,47)=11.8; a(6,48)=9.5;

a(7,7)=0;a(7,47)=14.5; a(7,40)=7.2; a(7,39)=15.1;

a(8,8)=0;a(8,40)=8.0;

a(9,9)=0;a(9,40)=7.8; a(9,41)=5.6;

a(10,10)=0;a(10,41)=10.8;

a(11,11)=0;a(11,42)=6.8; a(11,45)=13.2; a(11,40)=14.2;

a(12,12)=0;a(12,43)=10.2; a(12,42)=7.8;a(12,41)=12.2;

a(13,13)=0;a(13,45)=9.8;a(13,44)=16.4;a(13,42)=8.6; a(13,14)=8.6; a(14,14)=0;a(14,43)=9.9; a(14,15)=15.0;

a(15,15)=0;a(15,44)=8.8;

a(16,16)=0;a(16,17)=6.8;a(16,44)=11.8;

a(17,17)=0;a(17,22)=6.7; a(17,46)=9.8;

a(18,18)=0;a(18,46)=9.2; a(18,45)=8.2; a(18,44)=8.2;

a(19,19)=0;a(19,20)=9.3; a(19,45)=8.1; a(19,47)=7.2;

a(20,20)=0;a(20,21)=7.9;a(20,25)=6.5; a(20,47)=5.5;

a(21,21)=0;a(21,23)=9.1;a(21,25)=7.8; a(21,46)=4.1;

a(22,22)=0;a(22,23)=10.0; a(22,46)=10.1;

a(23,23)=0;a(23,24)=8.9; a(23,49)=7.9;

a(24,24)=0;a(24,27)=18.8; a(24,49)=13.2;

a(25,25)=0;a(25,49)=8.8; a(25,48)=12.0;

a(26,26)=0;a(26,27)=7.8; a(26,49)=10.5; a(26,51)=10.5;

a(27,27)=0;a(27,28)=7.9;

a(28,28)=0;a(28,52)=8.3; a(28,51)=12.1;

a(29,29)=0;a(29,52)=7.2; a(29,51)=15.2; a(29,53)=7.9;

a(30,30)=0;a(30,32)=10.3; a(30,52)=7.7;

a(31,31)=0;a(31,33)=7.3;a(31,32)=8.1; a(31,53)=9.2;

a(32,32)=0;a(32,33)=19;a(32,35)=14.9;

a(33,33)=0;a(33,35)=20.3; a(33,36)=7.4;

a(34,34)=0;a(34,35)=8.2; a(34,36)=11.5; a(34,37)=17.6;

a(35,35)=0;

a(36,36)=0;a(36,53)=8.8;a(36,37)=12.2;

a(37,37)=0;a(37,38)=11.0;

a(38,38)=0;a(38,50)=11.5;

a(39,39)=0;

a(41,41)=0;

a(42,42)=0;

a(43,43)=0;

a(44,44)=0;a(44,45)=15.8;

a(45,45)=0;

a(46,46)=0;

a(47,47)=0;

a(48,48)=0;a(48,49)=14.2; a(48,50)=19.8;

a(49,49)=0;

a(50,50)=0;a(50,53)=12.9;a(50,51)=10.1;

a(51,51)=0;

a(52,52)=0;

a(53,53)=0;

% 用1、2 、3……35表示35个村：用36、37……53表示各乡镇。其中50表示的是县政府。

b=a+a';b(find(b==0))=M;

for i=1:53

b(i,i)=0;

end

[m n]=size(b);

k=1;

for i=1:m

for j=1:n

if (b(i,j)==0)||(b(i,j)==inf)

else

x1(k)=i;

y(k)=j;

z(k)=b(i,j);

k=k+1;

end

end

end

Q=[x1;y;z]';

k=0;

d=zeros(1,n);

for i=1:m

for j=1:n

if (b(i,j)==0)||(b(i,j)==inf)

else

d(i)=d(i)+1;

x2(i)=i;

end

end

end