4号-化学双语课件(最终版)

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➢Cu2+ + SO42- + Ba2+ + 2Cl- = Cu2+ +2Cl- + BaSO4↓
Step3. Delete the ions which not take part in the reaction on both sides of the equation.
➢Cu2+ + SO42- + Ba2+ + 2Cl- = Cu2+ +2Cl- + BaSO4↓
(C)
A. Ba(NO3)2 + H2SO4 = BaSO4↓ + 2HNO3 B. BaCl2 + Na2SO4 = BaSO4↓ + 2NaCl C. BaCO3 + H2SO4 = BaSO4↓ + H2O + CO2↑ D. BaCl2 + H2SO4 = BaSO4↓ + 2HCl
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Step2.Dismantle the dissoluble and dissociable substances into ionic form. But the indissoluble and indissociable substances and gases are still written in molecular formula.
Step4. Check the equation, both sides the number of atoms and charges are equal, the ionic equation is correct. SO42- + Ba2+ = BaSO4↓
Conditions of ionic reaction
How to write the ionic equation?
➢ We take CuSO₄ solution reaction with BaCl₂ solution as example to explain the steps of writing the ionic equation.
Step1. Write the chemical equation of reaction. ➢CuSO4 + BaCl2 = CuCl2 + BaSO4↓
Ionic equation
15化学1班 2015364119
Definition
➢ Using the symbols of ions which actually take part in the reaction to indicate the ionic reaction is called ionic equation.
indissoluble substances(难溶物质) (such as BaSO4,AgCl)
indissociable substances (不可分解物质) (such as H2O)
volatilizable substances(可挥发物质) (such as CO2)
Exercise: Which of the following reactions can not be indicated by the ionic equation: SO42- + Ba2+= BaSO4↓?
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