金具强度计算
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金具强度计算目录
一、计算说明
二、计算过程
三、结论
四、应力表
1/2
1×=1×=1×=1×=1×γ1s =1×××=×1×=1×γ3S =1×××=1×g 5=1×γ5S =1×××=×=N 2
1×1××=N 00
×2
001/2
×2×P h l h cos(ψ/2)+P is +2Fsin (ψ/2))最大弧垂控制工况:高温500 — 金具允许机械荷载,N/m ;
P V 、P H 式中:
9.81×(1、计算参数
1.1 工程名称:
1.2 电压等级:1.3 kV G is = 5.00P is =9.81A I =-( — 分别为一相导线覆冰、最大风速或最低气温时垂直荷载及风荷载,N/m ;(1-σc P v Gis }+l h 2]-σc {[W ic 2)σo P c σo P c
2、计算公式(手册P 606)
l Vc =N/m N/mm 2N/mm 2
100.88100.885.63
2.2 大风工况:
V 217.27N/m
10-3P H =100.88 3.16
N/m W ic =T R =K I
P V =g 340103
=2.59.849
16000249.0-(σ覆冰P c =55.79210.78)710-3 — 一相导线最大弧垂时单位荷载,N/m ;— 分别为一相导线最大弧垂时及覆冰、最低气温或最大风速时的应力,N/mm 2
;
F σ0=1.4 σc 、σo P c W ic — 一相导线覆冰、最大风速或最低气温时张力,N ;ψ — 线路转角,(°)。
2.1 覆冰工况:
σc =σm l Vc — 导线最大弧垂时允许垂直档距,m ;l h — 水平档距,m ;
G is 、P is 69.8969.89N
1616
将上述参数代入公式可得:
×30100.8821263.49N
171.230.02+0.0331.33 3.16×650=93.80810-3210.78×F =σ覆冰S=210.78[16000l Vc =69.89×{210.78 5.63+93.81
+2×21263.49×sin )2
=
919.73
m
1+650×(]-)
210.78 5.63-
69.8917.27×cos }一、计算说明
— 分别为金具或金具与绝缘子串覆冰时的垂直荷载及水平荷载,N ;
二、计算过程
1×=1×=1×=1×=1×γ1s =1×××=×1×=1×γ1S =1×××=1×g 4(30)=1×γ4(30)S =1×××=×=N 2
1×1××=N 00
×2
001/2
×2×1×=1×=1×=1×=1×γ1s =1×××=×1×=1×γ1S =1×××=×=N 2
1×1××=N 00
×2
001/2
×2×1×=1×=1×=1×=1×γ1s =1×××=×1×=1×γ1S =1×××=×=N 2
1×1××=N 00
×2
001/2
×2×N/mm 2
N/mm 2cos )0.00××3014N/m N/m 69.89100.8810-310-355.79 5.63
10000100.88N/mm 210-3100.8896.68N/mm 2
5.63
171.063072.795.63
N/m 100.88 5.63
N/m N
=×49.0(10-3100.88 5.63
10-3100.887343.06}0.02P is =16
0.03)×××+V 2l Vc =69.89σ0=σ年平G is = 5.00P V =0.00
N/m g 1P H =P c =69.8955.79103
=W ic =K I
4T R =402.4 年平工况:
σc =σm 5.63)
5.63=
2747.00
m
(1-
69.89σc =P V =σ0=96.68P c =W ic =T R =40103
σm 69.8955.79σ大风N/m 0.00
10-3100.8810-3N
55.79G is = 5.009.8P H = 2.50.00=g 1K I
49
=171.06N
(0.02K I
2.5=9.81×16
0.03)×302.3 低温工况:
72.79P c =55.79]-×-16000N
167343.06将上述参数代入公式可得:
++0.03σ0=σ低温+2×16000P is =9.81A I V 25.63[16000sin ) 5.63
171.06N
16
σc =σm 69.8969.89171.06
+650N/mm 2N/m 100.88169.8172.7972.7955.79×49
103
=0.00
N/m 2P V =g 1P H = 5.009.8将上述参数代入公式可得:
×W ic =T R =10000=4069.8971.389.8A I =9.8114162
×sin 71.38[)7200.81N
(0.00l Vc =69.89×{72.799.81+2×F =σ大风S=96.68100.88+171.06
(0.00×650cos ×{[160002-+2×9753.08l Vc =69.8969.89 5.63)
96.68 5.6396.68 5.63×sin ×=
2228.82
m
F =σ低温S=P is =9.81A I V 2
G is =)
71.38 5.63(1-
69.89 5.635.63+171.06×650××=
1744.50
m
F =σ年平S=将上述参数代入公式可得:
×{71.38)2
}+49.0cos }+650N/m 100.887200.81×(1-×14650]+2--49.0]N/mm 2
0.0249
(71.38(2
6509753.08-
×=