安德森-商务与经济统计习题答案(第8版,中文版)
商务与经济统计作业(仅供参考)
第一章数据与统计资料P 1825. 表1-8是一个由25只影子股票组成的数据集，（表略）a 数据集中有几个变量？答：数据集中有5个变量。
b哪些变量是数量变量？哪些变量是品质变量？答：市场价值、市盈率和毛利率属于数量变量；交易所和股票代码是品质变量。
c对交易所变量，计算AMEX、NYSE 和OTC频数或百分数频数。
绘制类似于图1-5的交易所变量的条形图。
e 平均市盈率是多少？答：利用EXCEL的求平均值功能得出平均市盈率是20.2第二章表格法和图形法P 235按字母顺序，美国最常见的6个姓氏为：布朗、戴维斯、约翰逊、琼斯、史密斯和威廉姆斯。
假设根据一个由50个人组成的样本，得到如下的姓氏数据（图略）a相对频数分布和百分数频数分布。
mstotal 50 b构建条形图c 构建饼形图d根据这些数据，最常见的3个姓氏是哪些？答：最常见的3个姓氏分别是史密斯、约翰逊和威廉姆斯。
P5051 表2-17 给出了50家《财富》500强公司的所有者权益、市场价值和利润数据。
（图略）a．构建所有者权益和利润变量的交叉分组表。
对利润数据以0-200,200-400，…，1000-1200分组，对所有者权益数据以0-1200,1200-2400，…，4800-6000分组。
b. 计算（a）中交叉分组表的行百分数。
P 5153. 参考表2-17中的数据集a. 绘出显示利润和所有者权益变量之间关系的散点图。
b. 评价这两个变量之间的关系。
答：二者呈正相关的关系，即所有者权益增加，利润也增加。
但因为所有点并不在一条直线上，所以这种关系不是完全的。
案例2-1 Pelican 商店1. 主要变量的百分数频数分布2. 条形图或饼形图，以显示因促销活动而使顾客购买的百分数。
3. 顾客类型（常规性或奖励性）与销售额的交叉分组表，并评价其相似性与差异性。
动取得了显著成效。
使用折扣赠券购买的奖励性顾客占全体顾客总数的70%，分布于各个销售额区域，尤其在销售额100内的范围里做出了突出贡献，尽管未使用折扣赠券的常规性顾客也主要集中在该销售额区域，但比重明显低于奖励性顾客，且在200以上的销售额区域则无常规性顾客，奖励性顾客的消费金额也扩大到300。
商务统计选择答案.doc
Part One: Multiple Choices:1.The probability that a continuous random variable takes any specific valuea.is equal to zerob.is at least 0.5c.depends on the probability density functiond.is very close to 1.02. A normal distribution with a mean of 0 and a standard deviation of 1 is calleda. a probability density functionb.an ordinary normal curvec. a standard normal distributiond.none of these alternatives is correct3. A negative value of Z indicates thata.the number of standard deviations of an observation is to the right of the meanb.the number of standard deviations of an observation is to the left of the meanc. a mistake has been made in computations, since Z cannot be negatived.the data has a negative mean4.For a continuous random variable x, the probability density function f(x) representsa.the probability at a given value of xb.the area under the curve at xc.the area under the curve to the right of xd.the height of the function at x5.For the standard normal probability distribution, the area to the left of the mean isa.-0.5b.0.5c.any value between 0 to 1d. 1rger values of the standard deviation result in a normal curve that isa.shifted to the rightb.shifted to the leftc.narrower and more peakedd.wider and flatter7. A continuous probability distribution that is useful in describing the time, or space,between occurrences of an event is a(n)a.normal probability distributionb.uniform probability distributionc.exponential probability distributiond.Poisson probability distribution8.Consider a binomial probability experiment with n = 3 and p = 0.1. Then, the probabilityof x = 0 isa.0.0000b.0.0001c.0.001d.0.7299. A continuous random variable may assumea.all values in an interval or collection of intervalsb.only integer values in an interval or collection of intervalsc.only fractional values in an interval or collection of intervalsd.all the positive integer values in an interval10.The highest point of a normal curve occurs ata.one standard deviation to the right of the meanb.two standard deviations to the right of the meanc.approximately three standard deviations to the right of the meand.the meanExhibit 1The assembly time for a product is uniformly distributed between 6 to 10 minutes.11.Refer to Exhibit 1. The probability density function has what value in the interval between 6 and 10?a.0.25b. 4.00c. 5.00d.zero12.Refer to Exhibit 1. The probability of assembling the product between 7 to 9 minutes isa.zerob.0.50c.0.20d. 113.Refer to Exhibit 1. The probability of assembling the product in less than 6 minutes isa.zerob.0.50c.0.15d. 114.Refer to Exhibit 1. The probability of assembling the product in 7 minutes or more isa.0.25b.0.75c.zerod. 115.Refer to Exhibit 1. The expected assembly time (in minutes) isa.16b. 2c.8d. 416.Refer to Exhibit 1. The standard deviation of assembly time (in minutes) is approximatelya. 1.3333b. 1.1547c.0.1111d.0.577317.Center of a normal curve isa.always equal to zerob.is the mean of the distributionc.cannot be negatived.is the standard deviation18.The uniform, normal, and exponential distributions area.all continuous probability distributionsb.all discrete probability distributionsc.can be either continuous or discrete, depending on the datad.all the same distributions19.Which of the following is not a characteristic of the normal probability distribution?a.The mean, median, and the mode are equalb.The mean of the distribution can be negative, zero, or positivec.The distribution is symmetricald.The standard deviation must be 120.In a standard normal distribution, the range of values of z is froma.minus infinity to infinityb.-1 to 1c.0 to 1d.-3.09 to 3.0921.Parameters area.numerical characteristics of a sampleb.numerical characteristics of a populationc.the averages taken from a sampled.numerical characteristics of either a sample or a population22.How many simple random samples of size 3 can be selected from a population of size 7?a.7b.21c.35d.34323. A population consists of 500 elements. We want to draw a simple random sample of 50 elements from this population. On the first selection, the probability of an element being selected isa.0.100b.0.010c.0.001d.0.00224.The closer the sample mean is to the population mean,a.the larger the sampling errorb.the smaller the sampling errorc.the sampling error equals 1d.None of these alternatives is correct.25.Since the sample size is always smaller than the size of the population, the sample meana.must always be smaller than the population meanb.must be larger than the population meanc.must be equal to the population meand.can be smaller, larger, or equal to the population mean26.As the sample size increases, thea.standard deviation of the population decreasesb.population mean increasesc.standard error of the mean decreasesd.standard error of the mean increases27. A simple random sample from an infinite population is a sample selected such thata.each element is selected independently and from the same populationb.each element has a 0.5 probability of being selectedc.each element has a probability of at least 0.5 of being selectedd.the probability of being selected changes28.In point estimationa.data from the population is used to estimate the population parameterb.data from the sample is used to estimate the population parameterc.data from the sample is used to estimate the sample statisticd.the mean of the population equals the mean of the sample29.The sample mean is the point estimator ofa.pib.Gc.xd.-P30.The expected value of the random variable x isa.the standard errorb.the sample sizec.the size of the populationd.None of these alternatives is correct.31.The standard deviation of all possible x values is called thea.standard error of proportionb.standard error of the meanc.mean deviationd.central variation32.Whenever the population has a normal probability distribution, the sampling distribution of x is a normal probability distribution fora.only large sample sizesb.only small sample sizesc.any sample sized.only samples of size thirty or greater33.The sampling error is thea.same as the standard error of the meanb.difference between the value of the sample mean and the value of the population meanc.error caused by selecting a bad sampled.standard deviation multiplied by the sample size34.Which of the following is(are) point estimator(s)?a. ab.p,c.sd.a35. A population characteristic, such as a population mean, is calleda. a statisticb. a parameterc. a sampled.the mean deviation36. A single numerical value used as an estimate of a population parameter is known asa. a parameterb. a population parameterc. a mean estimatord. a point estimate37.The purpose of statistical inference is to provide information about thea.sample based upon information contained in the populationb.population based upon information contained in the samplec.population based upon information contained in the populationd.mean of the sample based upon the mean of the population38.The number of random samples (without replacement) of size 3 that can be drawn from a population of size 5 isa.15b.10c.20d.12539.For a population with any distribution, the form of the sampling distribution of the sample mean isa.sometimes normal for all sample sizesb.sometimes normal for large sample sizesc.always normal for all sample sizesd.always normal for large sample sizes40. A simple random sample of 28 observations was taken from a large population. The sample mean equaled 50. Fifty is aa.population parameterb.biased estimate of the population meanc.sample parameterd.point estimate41.When s is used to estimate G, the margin of error is computed by usinga.normal distributionb.t distributionc.the mean of the sampled.the mean of the population42.From a population with a variance of 900, a sample of 225 items is selected. At 95% confidence, the margin of error isa.15b. 2c. 3.92d. 443.In order to determine an interval for the mean of a population with unknown standard deviation a sample of 61 items is selected. The mean of the sample is determined to be 23. The number of degrees of freedom for reading the t value isa.22b.23c.60d.6144.If we want to provide a 95% confidence interval for the mean of a population, the confidence coefficient isa.0.485b. 1.96c.0.95d. 1.64545.As the number of degrees of freedom for a t distribution increases, the difference between the t distribution and the standard normal distributiona.becomes largerb.becomes smallerc.stays the samed.None of these alternatives is correct.46.For the interval estimation of p, when o is known and the sample is large, the proper distribution to use isa.the normal distributionb.the t distribution with n degrees of freedomc.the t distribution with n + 1 degrees of freedomd.the t distribution with n + 2 degrees of freedom47.An estimate of a population parameter that provides an interval of values believed to contain the value of the parameter is known as thea.confidence levelb.interval estimatec.parameter valued.population estimate48.The value added and subtracted from a point estimate in order to develop an interval estimate of the population parameter is known as thea.confidence levelb.margin of errorc.parameter estimated.interval estimate49.If an interval estimate is said to be constructed at the 90% confidence level, the confidence coefficient would bea.0.1b.0.95c.0.9d.0.0550.Whenever the population standard deviation is unknown and the population has a normal or near-normal distribution, which distribution is used in developing an interval estimation?a.standard distributionb.z distributionc.alpha distributiond.t distribution51.In interval estimation, the t distribution is applicable only whena.the population has a mean of less than 30b.the sample standard deviation is used to estimate the population standard deviationc.the variance of the population is knownd.the standard deviation of the population is known52.In developing an interval estimate, if the population standard deviation is unknowna.it is impossible to develop an interval estimateb.the standard deviation is arrived at using the rangec.the sample standard deviation can be usedd.it is assumed that the population standard deviation is 153.In order to use the normal distribution for interval estimation of)i when cr is known and the sample is very small, the populationa.must be very largeb.must have a normal distributionc.can have any distributiond.must have a mean of at least 154.From a population that is not normally distributed and whose standard deviation is not known, a sample of 6 items is selected to develop an interval estimate for the mean of the population (y).a.The normal distribution can be used.b.The t distribution with 5 degrees of freedom must be used.c.The t distribution with 6 degrees of freedom must be used.d.The sample size must be increased.55.From a population that is normally distributed, a sample of 25 elements is selected and the standard deviation of the sample is computed. For the interval estimation of pi, the proper distribution to use is thea.normal distributionb.t distribution with 25 degrees of freedomc.t distribution with 26 degrees of freedomd.t distribution with 24 degrees of freedom56.As the sample size increases, the margin of errora.increasesb.decreasesc.stays the samed.increases or decreases depending on the size of the mean57. A 95% confidence interval for a population mean is determined to be 100 to 120. If the confidence coefficient is reduced to 0.90, the interval for(ia.becomes narrowerb.becomes widerc.does not changed.becomes 0.158.The ability of an interval estimate to contain the value of the population parameter is described by thea.confidence levelb.degrees of freedomc.precise value of the population mean p,d.degrees of freedom minus 159.An interval estimate is a range of values used to estimatea.the shape of the population's distributionb.the sampling distributionc. a sample statisticd. a population parameter60.In determining the sample size necessary to estimate a population proportion, which of the following information is not needed?a.the maximum margin of error that can be toleratedb.the confidence level requiredc. a preliminary estimate of the true population proportion Pd.the mean of the population61.What type of error occurs if you fail to reject H o when, in fact, it is not true?a.Type IIb.Type Ic.either Type I or Type II, depending on the level of significanced.either Type I or Type II, depending on whether the test is one tail or two tail62.An assumption made about the value of a population parameter is called aa.hypothesisb.conclusionc.confidenced.significance63.The probability of committing a Type I error when the null hypothesis is true isa.the confidence levelb.卩c.greater than 1d.the Level of Significance64.The p-value is a probability that measures the support (or lack of support) for thea.null hypothesisb.alternative hypothesisc.either the null or the alternative hypothesisd.sample statistic65.The p-valuea.is the same as the Z statisticb.measures the number of standard deviations from the meanc.is a distanced.is a probability66.In hypothesis testing if the null hypothesis is rejected,a.no conclusions can be drawn from the testb.the alternative hypothesis is truec.the data must have been accumulated incorrectlyd.the sample size has been too small67.The level of significance is thea.maximum allowable probability of Type II errorb.maximum allowable probability of Type I errorc.same as the confidence coefficientd.same as the p-value68. A Type II error is committed whena. a true alternative hypothesis is mistakenly rejectedb. a true null hypothesis is mistakenly rejectedc.the sample size has been too smalld.not enough information has been available69.The level of significancea.can be any positive valueb.can be any valuec.is (1 - confidence level)d.can be any value between -1.96 to 1.9670.When the following hypotheses are being tested at a level of significance of aH o: pi > 500H a: ]i < 500the null hypothesis will be rejected if the p-value isa.< aH a : ]i > 10.0%H a : |i > 10.0%H a : ]i < 10.0%d. Ho ： pi > 10.0% H a : ]i < 10.0%a. Ho ： pi < 85 H a : pi > 85b. Ho ： pi < 85 H a : p, >c. Ho ： pi > 85 H a : p, < 85d. Ho ： pi > 85 H a : pi < 85 a. Ho ：pi < 12 H a : pi < 12b. Ho ： pi < 12 H a : p, >c. Ho： pi H 12H a : p, = 12b. > ac. > a/2d. < 1 - a/271. When the p-value is used for hypothesis testing, the null hypothesis is rejected if a. p-value < ab. a < p-valuec. p-value > ad. p-value = 1 - a72. In order to test the following hypotheses at an a level of significanceH o : pi < 800H a : ]i > 800the null hypothesis will be rejected if the test statistic Z isa. 巴 Z Qb. <Z ac. < -Z ad. = a73. Your investment executive claims that the average yearly rate of return on the stocks she recommends is more than 10.0%. You plan on taking a sample to test her claim. The correct setof hypotheses is a. H o : pi < 10.0% b. Ho ： pi < 10.0%c. Ho ： pi > 10.0%74. A weatherman stated that the average temperature during July in Chattanooga is less than 80 degrees. A sample of 32 Julys is taken. The correct set of hypotheses is a . H o : pi > 80 H a : p, <80 b . H o : pi < 80 H a : p, >80 c . H o : —80 H a : p, =80 d . H o : pi < 80 H a : p, >80 75. A student believes that the average grade on the final examination in statistics is at least85. She plans on taking a sample to test her belief. The correct set of hypotheses is76. A soft drink filling machine, when in perfect adjustment, fills the bottles with 12 ouncesof soft drink. Any over filling or under filling results in the shutdown and readjustment of the machine. To determine whether or not the machine is properly adjusted, the correct set ofhypotheses is d. Ho ： p = 1277. A two-tailed test is performed at 95% confidence. The p-value is determined to be 0.09. The null hypothesisa.must be rejectedb.should not be rejectedc . could be rejected, depending on the sample sized . has been designed incorrectly7 8Exhibit 2n = 49 x = 54.8 s = 28 H o: pi < 50H a: p, > 50Refer to Exhibit 2. The test statistic isa . 0.1714b . 0.3849c . -1.2d . 1.27 9Refer to Exhibit 2. The p-value is betweena . 0.01 to 0.025b . 0.025 to 0.05c . .05 to 0.1d . 0.1 to 0.28 0Refer to Exhibit 2. If the test is done at the 5% level of significance, the null hypothesisshoulda . not be rejectedb . be rejectedc . Not enough information given to answer this question.d . None of these alternatives is correct.8 1If we are interested in testing whether themeanof population 1 is significantly largerthanthe mean of population 2, thea . null hypothesis should state 内-应 > 0b . null hypothesis should state 内-应巴0c . alternative hypothesis should state p，i - |i2 > 0d . alternative hypothesis should state pii -112 < 08 2If we are interested in testing whether themeanof population 1 is significantlydifferentfrom the mean of population 2, thea . null hypothesis should state 山-应=0b . null hypothesis should state 山-应巴0c . alternative hypothesis should state p，i - |i2 > 0d . alternative hypothesis should state pii -112 < 08 3When developing an interval estimate for the difference between two sample means, withsample sizes of m and n2,a . Ni must be equal to n2b . Ni must be smaller than n2c . Ni must be larger than n2d . Ni and n2 can be of different sizes,84.Independent simple random samples are taken to test the difference between the means of two populations whose variances are not known, but are assumed to be equal. The samplesizes are m = 32 and n2 = 40. The correct distribution to use is thea.t distribution with 73 degrees of freedomb.t distribution with 72 degrees of freedomc.t distribution with 71 degrees of freedomd.t distribution with 70 degrees of freedom85.If two independent large samples are taken from two populations, the sampling distribution of the difference between the two sample meansa.can be approximated by a Poisson distributionb.will have a variance of onec.can be approximated by a normal distributiond.will have a mean of one86.The standard error of x -x2 is thea.--variance of x 严Qb.--variance of the sampling distribution of 区厂乂？c.- ~standard deviation of the sampling distribution of x 严？d.difference between the two means87.In the analysis of variance procedure (ANOVA), ''factor'' refers toa.the dependent variableb.the independent variablec.different levels of a treatmentd.the critical value of F88.The ANOVA procedure is a statistical approach for determining whether or nota.the means of two samples are equalb.the means of two or more samples are equalc.the means of more than two samples are equald.the means of two or more populations are equal89.An experimental design where the experimental units are randomly assigned to the treatments is known asa.factor block designb.random factor designpletely randomized designd.None of these alternatives is correct.90.In an analysis of variance problem involving 3 treatments and 10 observations per treatment, SSE = 399.6. The MSE for this situation isa.133.2b.199.8c.14.8d.30.04 4 4 191.The F ratio in a completely randomized ANOVA is the ratio ofa.MSTR/MSEb.MST/MSEc.MSE/MSTRd.MSE/MST92.The critical F value with 6 numerator and 60 denominator degrees of freedom at a = .05 isa. 3.74b. 2.25c. 2.37d. 1.9693.An ANOVA procedure is applied to data obtained from 6 samples where each sample contains 20 observations. The degrees of freedom for the critical value of F area. 6 numerator and 20 denominator degrees of freedomb. 5 numerator and 20 denominator degrees of freedomc. 5 numerator and 114 denominator degrees of freedomd. 6 numerator and 20 denominator degrees of freedom94.In an analysis of variance problem if SST = 120 and SSTR = 80, then SSE isa.200b.40c.80d.12095.An ANOVA procedure is used for data that was obtained from four sample groups each comprised of five observations. The degrees of freedom for the critical value of F area. 3 and 20b. 3 and 16c. 4 and 17d. 3 and 1996.In ANOVA, which of the following is not affected by whether or not the population means are equal?a.xb.between-samples estimate of c>2c.within-samples estimate of c>2d.None of these alternatives is correct.97. A term that means the same as the term "variable" in an ANOVA procedure isa.factorb.treatmentc.replicationd.variance withinExhibit 3Salary information regarding male and female employees of a large company is shown below.Male FemaleSample Size 64 36Sample Mean Salary (in $1,000)Population Variance (cr2) 128 7298.Refer to Exhibit 3. The point estimate of the difference between the means of the two populations isa.-28b. 3c. 4d.-499.Refer to Exhibit 3. The standard error for the difference between the two means isa. 4b.7.46c. 4.24d. 2.0100.Refer to Exhibit 3. At 95% confidence, the margin of error isa. 1.96b. 1.645c. 3.920d. 2.000101.The coefficient of determinationa.cannot be negativeb.is the square root of the coefficient of correlationc.is the same as the coefficient of correlationd.can be negative or positive102.If the coefficient of determination is a positive value, then the coefficient of correlationa.must also be positiveb.must be zeroc.can be either negative or positived.must be larger than 1103.The mathematical equation relating the independent variable to the expected value of the dependent variable; that is, E(y) = P0 + 卩lx, is known asa.regression equationb.correlation equationc.estimated regression equationd.regression model104.The model developed from sample data that has the form of y = + ijX is known asa.regression equationb.correlation equationc.estimated regression equationd.regression model105.The interval estimate of the mean value of y for a given value of x isa.prediction interval estimateb.confidence interval estimatec.average regressiond.x versus y correlation interval106.The interval estimate of an individual value of y for a given value of x isa.prediction interval estimateb.confidence interval estimatec.average regressiond.x versus y correlation interval107.In a regression analysis the standard error is determined to be 4. In this situation the MSEa.is 2b.is 16c.depends on the sample sized.depends on the degrees of freedom108.In regression analysis, which of the following is not a required assumption about the error term £?a.The expected value of the error term is one.b.The variance of the error term is the same for all values of X.c.The values of the error term are independent.d.The error term is normally distributed.109.In a regression analysis, the coefficient of determination is 0.4225. The coefficient of correlation in this situation isa.0.65b.0.1785c.any positive valued.any value110.In a regression analysis, the coefficient of correlation is 0.16. The coefficient of determination in this situation isa.0.4000b.0.0256c. 4d. 2.56111.In a regression and correlation analysis if r2 = 1, thena.SSE must also be equal to oneb.SSE must be equal to zeroc.SSE can be any positive valued.SSE must be negative112.In a regression and correlation analysis if r2 = 1, thena.SSE = SSTb.SSE= 1c.SSR = SSEd.SSR = SST113.If the coefficient of correlation is a positive value, then the regression equationa.must have a positive slopeb.must have a negative slopec.could have either a positive or a negative sloped.must have a positive y intercept114.If the coefficient of correlation is 0.& the percentage of variation in the dependent variable explained by the variation in the independent variable isa.0.80%b.80%c.0.64%d.64%115.In regression and correlation analysis, if SSE and SST are known, then with this information thea.coefficient of determination can be computedb.slope of the line can be computedc.Y intercept can be computedd.x intercept can be computed116.In regression analysis, if the independent variable is measured in pounds, the dependent variablea.must also be in poundsb.must be in some unit of weightc.cannot be in poundsd.can be any units117.If the coefficient of correlation is -0.4, then the slope of the regression linea.must also be -0.4b.can be either negative or positivec.must be negatived.must be 0.16118.If the coefficient of correlation is a negative value, then the coefficient of determinationa.must also be negativeb.must be zeroc.can be either negative or positived.must be positive119.If a data set has SSR = 400 and SSE = 100, then the coefficient of determination isa.0.10b.0.25c.0.40d.0.80pared to the confidence interval estimate for a particular value of y (in a linear regression model), the interval estimate for an average value of y will bea.narrowerb.widerc.the samed.None of these alternatives is correct.。
安德森-商务与经济统计公式汇总
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国际经济学第八版课后答案
国际经济学第八版课后答案国际经济学是当代世界上重要的一门学科，在全球经济不断发展的今天，在不同国家和地区间进行国际贸易和投资已成为一种常态，而这种现象的背后，正是国际经济学的基础理论支撑，因此学习国际经济学的重要性日益凸显。
而对于国际经济学这门学科来说，了解、掌握相关的知识点和要点，完成课后习题，是非常重要的。
国际经济学第八版通过对国际贸易、投资、汇率、国际收支等一系列问题进行系统讲述，对学生进行全方位的培养，涉及到的知识点也十分广泛，因此，在完成课后习题时，可能会遇到一定的问题，需要一定的帮助和指导才能完成。
因此，对于国际经济学第八版课后答案的研究也显得尤为重要。
在研究国际经济学第八版课后答案时，我们需要注意以下几点：1.仔细阅读教材，掌握理论基础课后习题的主要目的就是帮助学生巩固课堂上所学的知识点和理论基础，因此在完成课后习题时，学生需要仔细阅读教材，掌握理论基础。
只有对教材中所介绍的理论和分析方法有了充分的理解和把握，才能更好地完成课后习题，理解其中的思想和要点。
2.注重实践应用，锻炼思维能力国际经济学的学习需要注重实践应用，在完成课后习题时也应该如此，尤其是在解决实际问题的时候，需要更注重实践应用，并且要灵活运用学到的理论知识，通过对问题的分析、解答、讨论，锻炼自己的思维能力和创新意识。
3.积极参与交流讨论，锻炼合作能力课后习题的完成，不是个人的事情，而是需要学生之间相互交流、讨论、合作实现的，因此，在完成课后习题时，学生需要积极参与交流讨论，通过与同学之间的互动和交流，可以加深对问题的理解和认识，锻炼自己的合作能力。
4.注意答案的准确性和合理性在完成课后习题时，需要注意答案的准确性和合理性，只有在确认自己所得出的答案是准确的、合理的，才能对所学到的内容有充分的理解和掌握。
综上所述，国际经济学第八版课后答案对于学生的学习来说具有非常重要的作用，同时也需要注意一些问题。
最后，我们希望广大学生能够通过认真学习、积极思考、有效交流，掌握好国际经济学的相关知识点，为将来更好地服务国家和世界经济发展做出自己的贡献。
商务统计习题解答.doc
4.49 4.33 (a)H = husband watching W= wife watching P(H\W) =商务统计习题解答4.41 （7）（3）（3）= 63〃！ _ 7! _（7）（6）（5）X!（〃一 X ）! 4!（3!）（3）（2）（1）P(WIH)・P(H) P(W I H)・P(H) + F(W 1H')・P(H')0.4 • 0.6 0.24 2 八 y0.4 • 0.6 + 0.3 • 0.4 - 036 ~ 3 - *(b) P(IV) = 0.24+0.12 =0.36 5.11 If p-0.25 and n = 5,(a) RX= 5) =0.0010(b) I\X> 4) = RX=4) + RX=5) = 0.0146+0.0010 =0.0156(c) 0) = 0.2373(d) F\X < 2) = RX=0) + RX= 1) + RX=2)=0.2373 + 0.3955 + 0.2637 = 0.89655.21(a) 0) = 0.0907 (b) RX= 1)=0.2177(c) I\X> 2)=0.6916 (d) RXv 3) = 0.56976.11 (a) P(X v 180) = P(Z v — 1.50) = 0.0668(b) P(180 v X v 300) = P(— 1.50 v Z v 1.50) = 0.9332 - 0.0668 = 0.8664(c) P( 110 v X v 180) = P(— 3.25 v Z v — 1.50) = 0.0668 - 0.00058 =0.06622(d) P(X v A) = 0.01 P(Z v - 2.33) = 0.01A = 240 - 2.33(40) = 146.80 seconds6.19(a) mean = 678.85, median = 675.5, range = 54,6(Sx ) =88.5734, interquartile range = 20, 1.33(S X ) = 19.6338 Since the mean is approximately equal to the median and the interquartile range isvery close to 1.33 times the standard deviation, the data appear to be approximatelynormally distributed.(b)710X±Z- 350±1.96- 100V64 325.5 < 辱 374.50The normal probability plot suggests that the data appear to be approximately normally distributed. 7.9 (a)P(叉 < 0.75) = P(Z < -1.3693) = 0.0855 (b)P(0.70 <X < 0.90) = P(—2.7386 <Z<2.7386) = 0.9938 (c) P(A< X < B) = P(- L2816 < Z < 1.2816) = 0.80A =0.8-1.2816 (0.0365) = 0.7532 B= 0.8 +1.2816 (0.0365) = 0.8468(d) P(X <A) = P(Z< 1.2816) = 0.90 A = 0.8 +1.2816 (0.0365) = 0.8468Note: The above answers are obtained using PHStat. They may be slightly different whenTable E.2 is used.7.19 (a) P(0.15 vp v0.25) = P(- 1.25 <Z< 1.25)=0.7887(b) P(A<p<B) = P(- 1.6449 <Z< 1.6449) = 0.90A = 0.2 - 1.6449(0.04) = 0.1342B = 0.2 + 1.6449(0.04) = 0.2658(c) P(A v p v B) = P(- 1.960<Z< 1.960) = 0.95A =0.2 - 1.960(0.04) = 0.12160.2+ 1.96(0.04) = 0.27848.8 (a)(b) No. The manufacturer cannot support a claim that the bulbs last an average 400 hours.Based on the data from the sample, a mean of 400 hours would represent a distanceof 4 standard deviations above the sample mean of 350 hours.(c) No. Since is known and n = 64, from the Central Limit Theorem, we may assumethat the sampling distribution of X is approximately normal.(d) The confidence interval is narrower based on a process standard deviation of 80hours rather than the original assumption of 100 hours.Normal Probability Plot690 680670660700650 -2 -1.5 -1 -0.5 0 0.51 Z Value 1.5 2a loo sMp(a)8.18 (a) X±F・S “，c 八4.6024 -7= = 23 ±2.0739•― 4nV23 $21.01 <//< $24.99一cr80~F= = 350 ± 1.96 • —f=X ± Z ・4tr V64(b) Based on the smaller standard deviation, a mean of 400 hours would represent adistance of 5 standard deviations above the sample mean of 350 hours. No,the manufacturer cannot support a claim that the bulbs have a mean life of400 hours.(b) You can be 95% confident that the mean bounced check fee for the population issomewhere between $21.01 and $24.99.又◊又 (\n 77 . 7〔P(l ? P n77 . j QA /0.77(0.23)8.28 (a) p= 0.77 p ± Z • ------------------------- =().77 ±1.96」 ------------------------------\ n V 10000.74 <7t< 0.80(b)p = 0.77 p ± Z •、格王=0.77 ± 1,645/wWV n v 10000.75 <7T< 0.79(c)The 95% confidence interval is wider. The loss in precision reflected as a widerconfidence interval is the price you have to pay to achieve a higher level ofconfidence.Z2<T2 1.962 - 40028.38 (a) n =——=-------------- -—— =245.86 Use n = 246& 50~, Z2cr2 1.962 -4002八”八TT八睥(b) n = ——-— = --------------- ---- =983.41 Use n = 984& 2529.30 (a) Ho： " =375 hours. The mean life of the manufacturers light bulbs isequal to 375 hours.H\： // #375 hours. The mean life of the manufacturer9s light bulbs differs from375 hours.Decision rule: Reject 仇if Z v - 1.96 or Z > + 1.96.Test statistic: Z =与人笔尹=-2.00Decision: Since Z c^ = 一2.00 is below the critical bound of - 1.96, reject There isenough evidence to conclude that the mean life of the manufacturer's light bulbsdiffers from 375 hours.(b) ^-value = 2(0.0228) = 0.0456.Interpretation: The probability of getting a sample of 64 light bulbs that will yielda mean life that is farther away from the hypothesized population mean than thissample is 0.0456-(c)Test statistic: t = s 商 315.33/应y!n<64 (d) The results are the same. The confidence interval formed does not include thehypothesized value of 375 hours.9.58 (a) H Q : // < 400 The mean life of the batteries is not more than 400 hours. H 、： 〃> 400 The mean life of the batteries is more than 400 hours.X 一以 473.46-400 t “ --------------- 7= = 7= = 1 .230 / s/y/n 210.77/J13 Decision: Since t < 1.7823, do not reject H 。
《商务与经济统计课程》前三次作业参考答案
MS
F
兽医师间
0.03
4
0.0075 0.0065(ns)
奶牛间
0.65
4
0.1625
0.1404(ns)
试管间
0.19
4
0.0475
0.0410(ns)
Error
13.89
12
1.1575
Total
14.76
24
方差分析结果表明，兽医师间、奶牛间、试管间血色素的差异均不显著。
2.12 在下面变量中，哪些属于连续型变量？哪些属于离散型变量？ （1）屠宰生畜头数量；（2）零件尺寸偏差；（3）飞机耗汽油；（4）报废的汽车数；（5）存 款余额；（6）洪水涨落尺度；（7）选民投票数；（8）车轮转速；（9）森林覆盖面积；（10） 价格。
1600
计数 4 4 7 10 9 6
组距 100 100 200 400 800 800
频数密度 0.040 0.040 0.035 0.025 0.011 0.008
3.10 试根据下表资料绘制曲线图，并指出该曲线图属于什么类型？
表 3-13
1900-1978 世界人口变化资料
单位：百万人
年份
补充： （1） 标准拉丁方阵、一般拉丁方阵以及拉丁方阵的一个定理
拉丁方阵是一种 n×n 的方阵，方阵中恰有 n 种不同的元素，每种元素恰有 n 个，并 且每种元素在一行和一列中恰好出现一次。当一个拉丁方阵的第一行与第一列的元素按顺序 排列时，即为拉丁方阵的标准型，称为"reduced Latin square, normalized Latin square, 或 Latin square in standard form"。一般拉丁方阵也就是区别于标准拉丁方阵且符合拉丁方阵条件的
商务统计期末试题及答案
商务统计期末试题及答案【注意：以下为示例文章格式，实际内容与题目无关】一、选择题（每题2分，共30分）1. 下面哪个选项是正确的？A. 1+1=2B. 1+1=3C. 1+1=4D. 1+1=5答案：A2. 给定数据集的平均值为5，标准差为2，那么方差为多少？A. 1B. 2C. 4D. 8答案：C二、判断题（每题2分，共20分）1. 描述性统计是通过样本数据推断总体特征的方法。
答案：正确2. 概率分布函数可以描述随机变量的所有可能取值的概率。
答案：正确三、计算题1. 一个班级有30名学生，其中男生有20名，女生有10名。
请计算男生人数占总人数的比例，并将结果四舍五入到小数点后两位。
答案：20 / 30 = 0.67，四舍五入为 0.672. 有一个餐厅，星期一到星期五的销售额分别为1000、1500、1200、800、2000元，请计算平均销售额。
答案：(1000 + 1500 + 1200 + 800 + 2000) / 5 = 1100元3. 一家公司销售了3种产品，产品A的销售额占总销售额的30%，产品B的销售额占总销售额的40%，产品C的销售额为2000元，求总销售额。
答案：产品C的销售额占总销售额的30% + 40% = 70%，则总销售额为2000元 / 70% = 2857.14元四、应用题某公司进行了一次市场调研，调查了1000名顾客的购买行为。
以下是调查结果：- 500人购买了产品A- 300人购买了产品B- 200人购买了产品C- 100人购买了产品A和产品B- 50人购买了产品B和产品C- 20人购买了产品A和产品C- 10人购买了三种产品请回答以下问题：1. 购买了产品A但未购买产品B的顾客有多少人？答案：购买了产品A的人数减去购买了产品A和产品B的人数：500 - 100 = 400人2. 购买了产品B且同时购买了产品C的顾客有多少人？答案：购买了产品B和产品C的人数：50人3. 购买了至少一种产品的顾客有多少人？答案：购买了产品A、B或C的人数加上购买了三种产品的人数：500 + 300 + 200 - 10 = 990人五、简答题1. 请解释什么是样本调查？答：样本调查是从总体中选取一部分样本，并对这些样本进行调查和研究，通过对样本的观察和分析来推断总体的特征和规律。
商务与经济统计前6章笔记
商务与经济统计前6章笔记下载温馨提示：该文档是我店铺精心编制而成，希望大家下载以后，能够帮助大家解决实际的问题。
文档下载后可定制随意修改，请根据实际需要进行相应的调整和使用，谢谢!并且，本店铺为大家提供各种各样类型的实用资料，如教育随笔、日记赏析、句子摘抄、古诗大全、经典美文、话题作文、工作总结、词语解析、文案摘录、其他资料等等，如想了解不同资料格式和写法，敬请关注!Download tips: This document is carefully compiled by the editor. I hope that after you download them, they can help you solve practical problems. The document can be customized and modified after downloading, please adjust and use it according to actual needs, thank you!In addition, our shop provides you with various types of practical materials, such as educational essays, diary appreciation, sentence excerpts, ancient poems, classic articles, topic composition, work summary, word parsing, copy excerpts, other materials and so on, want to know different data formats and writing methods, please pay attention!商务与经济统计前6章笔记第一章：商务与经济统计概述在当今全球化的商业环境中，商务与经济统计扮演着至关重要的角色。
商务与经济统计选择题
商务与经济统计选择题选择题课堂练习第一章数据不统计学1. 样本容量 ba. 可以比总体容量大b. 总是比总体容量小c. 可以比总体容量大,也可以比总体容量小d. 总是和总体容量相同 2. 一个总体 ca. 不样本相同b. 是一个随机样本c. 特定研究中所有感兴趣的数据单位的集合d. 以上都不是3. 对数据进行相对简单的组织、概括和表述的统计方法称为 ba. 统计推断b. 描述性统计c. 抽样d. 以上都不是4. 根据样本信息对总体特征进行推测和估计的过程称为 ca. 描述性统计b. 随机样本c. 统计推断d. 抽样5. 收集数据时所依赖的对象称为 c a. 发量b. 数据集c. 数据单位d. 以上都不是6. 对数据单位感兴趣的某个特征量是 aa. 一个发量b. 一个数据单位c. 一个数据集d. 以上都不是7. 数学运算适合应用于 b a. 定性数据b. 定量数据c. 定性数据和定量数据d. 以上都不是8. 人的年龄是定量数据 aa. 是b. 否9. 在同一时刻收集以下的数据:同学的姓名,性别,年龄,成绩等数据,这些数据是aa. 横截面数据b. 时间序列数据第四章概率论介绍1. 所有样本点的集合称为 ca. 样本b. 事件c. 样本空间d. 试验2. 所有样本点概率相等的概率分配方法称为 b a. 主观方法b. 古典概率方法c. 相对频数方法d. 以上都不是3. 每个样本点，即试验结果，的概率必须是 d a. 任何大于零的数b. 小于零c. 大于1d. 在0和1之间4. 下面哪个条件成立时可以认为事件X和Y相亏独立？ Ba. P(Y|X) = P(X)b. P(Y|X) = P(Y)c. P(X|Y) = P(Y) 5. 从5个字母 (A, B, C, D, E)中取出两个字母,一共有多少种不同的取法？ Da. 20b. 7c. 5d. 106. P(A) = 0.6, P(B) = 0.5, 则 P(AuB) = Ea. 0.3b. 0.5c. 0.6d. 1.1e. 不能确定7. P(A) = 0.6, P(B) 0.5, P(AnB) = 0.3, 则 P(AuB) = c a. 0.5b. 0.6c. 0.8d. 1.1e. 不能确定8. P(A) = 0.6, P(B) = 0.5, P(AÇB) = 0.3, 则 P(A|B) = b a. 0.5b. 0.6c. 0.8d. 1.1e. 不能确定9. P(A) = 0.6, P(B) = 0.5, P(A n B) = 0.3, 则事件A和B为亏斥事件 ba. 正确b. 错误10. P(A) = 0.6, P(B) = 0.5, P(A n B) = 0.3, 则事件A和B亏为独立事件a a. 正确b. 错误11. P(A) = 0.2, P(B) = 0.5, 且事件A和B为亏斥事件,则 P(A n B) = a a.b. 0.3c. 0.7d. 112. P(A) = 0.2, P(B) = 0.5, 且事件A和B为亏斥事件,则 P(A u B) = c a.b. 0.3c. 0.7d. 113. P(A) = 0.2, P(B) = 0.5, 且事件A和B为亏斥事件,则 P(A|B) = a a.b. 0.3c. 0.7d. 114. 如果事件A和B为亏斥事件,则它们一定是相亏独立事件 b a. 正确b. 错误15. 一个学生在放假前认为,有 50% 的概率去于南度假,有30%的概率去西藏度假,有20%概率去新疆度假。
商务统计试题7参考答案及评分标准
《商务统计》试题7参考答案及评分标准一、判断题（每题1分，共10分）三、填空题（每题3四、简答题（每题5分，共15分）1.简述小概率事件原理及其在假设检验中的应用。
小概率事件指概率很小的事件（1分）。
小概率事件原理是指在一次实验中，发生概率很小的事件，可以认为是不可能事件（2分）。
在假设检验中，根据样本观测量计算检验统计量的值，如果在原假设正确的前提下，检验统计量的值的出现是小概率事件，则可以认为原假设错误（2分）。
2.列举描述一个变量的数值方法。
平均值、中位数、众数、极差、四分位距、方差、标准差（答对1个计1分）。
3.简述方差分析的基本原理。
方差分析是分析分类型自变量对数值型因变量影响的一种统计方法，可以检验多个总体均值是否相等（1分）。
方差分析通过分析数据的误差来检验自变量对因变量的影响效果是否显著（1分）。
具体地，它通过检验各总体均值是否相等来判断分类型自变量对数值型因变量是否具有显著影响。
如果总体均值相等，可以期望三个样本的均值会很接近。
因此，三个样本的均值的分散程度可以为原假设是否成立提供证据（3分）。
五、计算题（每题15分，共30分）1.（1）令μ1、μ2分别表示两家分行的经常性账户平均余额，则原假设为H0：μ1−μ2=0(2分)，备择假设为H a：μ1−μ2≠0（1分）。
（2）应该应用t统计量（1分）。
因为两家银行的账户余额都服从正态分布，两个总体的方差σ12与σ22未知。
在原假设成立的条件下，12√s1/n1+s2/n2t分布（2分）。
检验统计量t=12√s1/n1+s2/n2=√1502/28+1252/22=2.96（2分）。
（3）t分布自由度df=(s12n1+s22n2)21n1−1(s12n1)2+1n2−1(s22n2)2≈47，显著性水平是α=0.05，则拒绝域的临界值t0.025=2.01、−t0.025=−2.01 。
拒绝原假设的决策准则为：t≥2.01或者t≤−2.01时，拒绝原假设H0（2分）。
统计学第3、4章知识点与习题(含答案)
第三章数据资料的统计描述：统计表和统计图第一节定性资料的统计描述知识点：1、统计分组就是根据统计研究的需要，将统计总体按照一定的标志区分为若干组成部分的一种统计方法。
2、定性数据的频数、频率、百分数、累计频数、累积频率的概念及计算。
3、定性数据频数分布表示方法主要有条形图、扇形图。
第二节定量数据的统计描述知识点：1、定量数据频数分布表的编制：（1）整理原始资料；（2）确定变量数列的形式；（3）编制组距式变量数列。
应注意的问题：确定组距，确定组限。
考查的区间式分组数据按“上组限不在组内”的原则确定。
2、定量数据的频数、频率、百分数、累积频数、累计频率的概念及计算。
3、定量数据频数分布表示方法主要有直方图、折线图和曲线图三种。
第三节探索性数据分析——茎叶图知识点：1、基本茎叶图的理解及编制第四节相关表与相关图知识点：1、相关表，反映定性变量与定量变量之间的相关关系。
2、散点图，反映两个定量变量之间的相关关系。
根据散点图判断两个变量的相关关系。
第四章数据资料的统计描述：数值计算第一节集中趋势知识点：关于单值式分组和区间式分组数据的1、平均数的计算，包括算术平均数，几何平均数，调和平均数2、众数的计算3、中位数、四分位数的计算4、（补充知识点）平均数、众数、中位数三者之间的关系5、百分位数的计算6、截尾均值的计算第二节离散测度知识点：1、极差的计算2、关于单值式分组和区间式分组数据的四分位数差的计算3、关于单值式分组和区间式分组数据的方差、标准差的计算4、变异系数的计算5、（补充知识点）偏度、峰度的含义及计算第三节协方差与相关系数知识点：1、样本协方差的含义及计算2、相关系数的含义及计算第四节相对位置测度与奇异点知识点：1、数据的标准化处理2、奇异点的诊断：利用契比雪夫定理和经验规则第五节探索性分析——5点描述与箱线图知识点：1、5点描述法的理解2、箱线图的理解与运用第三章习题：一、填空题1、在对数据资料进行统计描述时，______反映了各个组中每一项目出现的次数，______反映了各个组中项目发生的比例。
商务与经济统计课后答案
商务与经济统计课后答案商务与经济统计课后答案【篇一：商务经济统计学复习题】．简答题1．简要谈谈你对统计与统计学的初步认识。
2.谈谈你对统计的三种含义的理解，并举出现实经济生活中你所了解到的运用统计学的一个例子3．试就统计数据的四种类型给出统计整理与显示的方法（统计图要求划出示意图）。
4．概述数据的离散程度的常用的测度方法(异众比率标准差离散系数)。
5．什么是个体指数? 什么是总指数？它们的作用分别是什么？6．试简要说明总量指标、平均指标和相对指标的在统计学中的作用。
7．只能用统计条形图和饼图来展示的是哪种类型的数据？画出这两种图形的示意图。
8.自己用一个实例画出统计条形图和饼图的示意图，它们通常可以用来展示哪种类型的数据？9．某高校毕业生就业指导中心想对2007届本校大学本科毕业生的毕业去向做一网上调查，请你为此设计一份半开放式（即：既含有封闭式问题又含有开放式问题）调查问卷。
（要求涉及学生的性别、专业、意向中的毕业去向：如出国、考研、自主创业、自主择业，以及意向中的就业领域、工薪待遇、单位性质、工作地区等等信息）。
二．填空题1.将下列指标按要求分类（只填写标号即可）（1）我国高等院校2006届本科毕业生就业率；（2）某贺岁片在国内上演第一周的票房收入；（3）2006年第3季度一汽大众销售的某品牌小汽车台数占其全部小汽车销售量的比率；,（5）进藏铁路开通后第一周，每天乘火车前往西藏的旅客的累计人数；（6）第3季度某商场的月平均销售额。
哪些是时点时标；哪些是时期指标；哪些是平均指标；哪些是相对指标。
2．统计调查方式除了重点调查，典型调查之外，另三种主要方式是 3．加权调和平均公式为4．异众比率公式是其含义是5．一组数据中非众数组所占的比率叫做，它可测度分类数据的趋势；离散系数测度的是总体的平均离散程度，它的计算公式是v?=。
6．将下列指标分类：（1）2005年我国人均占有粮食产量（2）我国第五次人口普查总人口数（3）股价指数（4）销售量指数（5）单位产品成本（6）某商店全年销售额(7)某企业在岗职工人数和下岗职工人数的比例 (8)我国高等院校“十五”期间年平均招生人数哪些是时期指标哪些是时点指标；哪些是一般平均数, 哪些是序时平均数；哪些是相对指标7．个体指数是反映项目或变量变动的相对数；反映多种项目或变量变动的相对数是。
商务与经济统计精要版答案
商务与经济统计精要版答案【篇一：经管类书单推荐】与管理学院 2016.10.17管理类推荐读物孙耀君，《西方管理学名著提要》，江西人民出版社1）管理学邢以群，《管理学》，浙江大学出版社周三多，《管理学》，复旦大学出版社2）管理信息系统kenneth udon/ jane udon ，《管理信息系统—网络化企业的组织与技术》（第六版，影印版），高等教育出版社薛华成，《管理信息系统》（第三版），清华大学出版社小威廉d.佩勒尔特 e.杰罗姆.麦卡锡，《市场营销学基础》：全球管理(英文版.第12版)--国际通用mba教材》，机械工业出版社郭毅等，《市场营销学原理》，电子工业出版社malhotra,n.k.著，《市场营销研究应用导向(第3版)》，电子工业出版社4）战略管理项保华，《战略管理——艺术与实务》，华夏出版社斯蒂文斯（英），《战略性思维》，机械工业出版社arthur a. thompson, jr. and a. j. strickland Ⅲ.crafting implementing strategy. 6th ed. richard d. irwin, inc., 1995中文版《战略管理学：概念与案例（英文版.第十版）-- 国际通用mba教材》，机械工业出版社david besanko, david dranove, mark shanley. the economics of strategy. john wiley sons, inc., 1996alan j. rowe; et al.. strategic management: a methodological approach. 4th ed. addison-wesley publishing company, inc., 19945）组织行为学卢盛忠等，《组织行为学：理论与实践》，浙江教育出版社英文版《human resource management: gaining a competitive advantage》，清华大学出版社约翰.m.伊万切维奇，《人力资源管理（英文版.原书第8版）-- 国际通用mba教材》，机械工业出版社luis r. gomez-mejia，david b.balkin，robert l. cardy，《管理人力资源 managing human resources 》（英文版第三版），北京大学出版社、培生教育出版集团7）财务管理8）管理统计david r.anderson dennis j.sweeney thomasa.william，《商务与经济统计（第七版）-- 经济教材译丛》，机械工业出版社david r.anderson;dennis j.sweeney;thomas a.william，《商务与经济统计（英文版.第8版）--21世纪经典原版经济管理教材文库》，机械工业出版9）会计学张启銮等，《会计学――工商管理硕士（mba）系列教材》，大连理工大学出版社cktde p.stickney roman l.weil，《财务会计(英文版第9版) --国际通用mba教材》，机械工业出版社ronald w.hilton，《管理会计（英文版.第三版）-- 国际通用mba教材》，机械工业出版10）西方经济学[美]平狄克等:《微观经济学》，中国人民大学出版社梁小民，《宏观经济学》，中国社会科学出版社梁小民，《西方经济学导论》，北京大学出版社宋承先，《现代西方经济学》（宏观经济学），复旦大学出版社[美] h.克雷格.彼得森等:《管理经济学》,中国人民大学出版社[美]s.charles maurice christopher r.thomas, managerial economics, 机械工业出社,2000年影印版11）运筹学胡运权，《运筹学教程（第二版）》，清华大学出版社蒋绍忠，《运筹学讲义》，浙江大学管理学院12）经济法高程德，《经济法》（第九版），上海人民出版社13）电子商务daniel amor，《电子商务:变革与演进--经济教材译丛》，机械工业出版社14）组织理论[美]达夫特著，李维安译．《组织理论与设计精要》，机械工业出版社[英]bernard burnes.《变革时代的管理》，云南大学出版社15）质量管理刘广第，《质量管理学（第二版）》，清华大学出版社16）生产管理陈荣秋、马士华，生产与运作管理，高等教育出版社，1999潘家轺等，现代生产管理学，北京：清华大学出版社，1994黄卫伟，生产与作业管理，北京：人民大学出版社，199717）项目管理毕星、翟丽，《项目管理》，复旦大学出版社，2000[美]杰克.吉多等著, 《成功的项目管理》，机械工业出版社，1999白思俊主编, 《现代项目管理》(上,中，下)，机械工业出版社，20022.认知心理学，robert j.sternberg，中国轻工业出版社3.人格理论，jess feist，gregory j.feist，人民卫生出版社4.社会心理学，elliott aronson等，中国轻工业出版社5.集合起来——群体理论与团队技巧，david w. johnson等，中国轻工业出版社8.招贤纳士自有道，lance a. berger等，清华大学出版社11. 内向者优势，martin olsen laney，华东师范大学出版社13. 超级冷静，铃木丈织，上海人民出版社31. 刘墉的书：我不是教你诈、你不可不知的人性、人生的真相补充书籍：经济类专业推荐读物 1、《摩根财团——美国一代银行王朝和现代金融业的崛起》第二版获得1990年美国国家图书奖推荐理由：摩根家族的发迹史和19-20世纪美国金融市场和银行业发展演变的全景图，前任财政部副部长、现任亚洲开发银行副行长金立群先生的翻译代表了中文相关专业译著的最高水平。